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Answer:

Step-by-step explanation:

Candice = 25mph for 4 hours.

Candice has driven= 25 * 4= 100miles.

Liz =50mph

Liz time to catch up to candice= 50 * 2= 100miles.

Therefore, It would have taken Liz two hours to catch up with Candice

Answer:

base=×

hypotenuse=6

prependicular=90

we know that

90÷6

×=15

The probability that a student who can drive is a college student is 0.2771 or 27.7%

It will be sooved using Baye's theorem -

P(college) = P(C) / 1/5 = 0.2

P(high school students) = P(H) = 4/5 = 0.8

P(college drives) = 0.23

P(high school drives) = 0.15

We have to find, probability that a student who drives is a college student.

That is, we have to find P(C/D).

P(C/D) = P(C ∩ S)/P(S)

Since P(C ∩ S) is an independent event.

P(C ∩ S) = P(C) × P(S)

P(C ∩ S) = 0.2 × 0.23

= 0.046

Using bayes's theorem, we will get

P(C/D) = 0.2771 or 27.7%

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Gerard concluded that triangle with given sides cannot be used as  building-frame support because it is not right triangle, he come to this conclusion because the Pythagoras-theorem is not satisfied.

In order to check if a triangle is "right-triangle", Gerard used the Pythagorean theorem. According to this theorem, in right triangle, the square of length of hypotenuse (the side opposite the right angle) is equal to sum of squares of other two sides,

So, the squares of the given sides are :

Square of √95 feet = (√95)² = 95 feet

Square of 8 feet = 8² = 64 feet

Square of √150 feet = (√150)² = 150 feet

We see that, 95 feet + 64 feet = 159 feet ≠ 150 feet,

Since the square of the longest side (√150) is not equal to the sum of the squares of the other two sides (√95 and 8), the Pythagorean-theorem is not satisfied.

Therefore, Gerard concluded that the triangle with sides √95 feet, 8 feet, and √150 feet is not a right triangle.

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The given question is incomplete, the complete question is

Gerard concluded that the triangle with sides √95 feet, 8 feet, and √150 cannot be used as a building frame support on the house because it is not a right triangle. How did Gerard come to that conclusion? explain.

4÷1.84 means 4 over 1.84 (4/1.84) = 2.17

if u calculate 1.84 ÷ 4 (using calculator) the ans will be different bcauz it means 1.84 over 4 (1.84/4)

Answer:

25+22

Step-by-step explanation:

When you subtract 27 to 22

Answer:

31 and 26

Step-by-step explanation:

31 + 26 = 57

31 - 26 = 5

Therefore, your answer is 31 and 26

Answer:

just do the assignments get help when neccesary ask the teacers if they have any extra credit materials

Step-by-step explanation:

The surface area of the cuboid is 3.286 cm²

A cuboid is a solid shape or a three-dimensional shape.

Surface area is the amount of space covering the outside of a three-dimensional shape.

The surface area of a cuboid is expressed as;

SA = 2( lb + lh + bh)

length = 1 2/5 = 7/5

breadth = 5/8

height = 3/8

lb = 7/5 × 5/8 = 7/8

bh = 5/8 × 3/8 = 15/64

lh = 7/5 × 3/8 = 21/40

surface area =2( 7/8 + 15/64+21/40)

= 2( 0.875 + 0.234 + 0.525)

= 2( 1.634)

= 3.268 cm²

The surface area of the cuboid is 3.268 cm²

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Answer:

0, 1, 1/2

Step-by-step explanation:

First you would have to make them have the same denominators.

The lowest one they share is 24.

What ever you do to the bottom you have to do to the bottom.

1/6, times each by 4.

1 * 4 = 4

6 * 4 = 24

4/24.

Now you have to do the same thnig for 5/8.

But times it by 3, since 8 times 3 is 24.

5 * 3 = 15

8 * 3 = 24

15/24

Now subtract.

15 - 4 = 11/24

the difference is close to one half.

4/24 = 1/6 is close to 0.

15/24 = 5/8 is close to 1.

Answer:

i need the points

Step-by-step explanation:

a) A symbol with a frequency of at least 0.4 will never be encoded with two or more bits. - True

b) A symbol with a frequency of at least 0.5 will never be encoded with two or more bits. - False

c) If all symbol frequencies are less than 0.33, all symbols will be encoded with at least two bits. - False

d) If all symbol frequencies are less than 0.5, all symbols will be encoded with at least two bits. - True

a) The Huffman greedy algorithm assigns shorter codes to symbols with higher frequencies. Therefore, a symbol with a frequency of at least 0.4 will never be encoded with two or more bits because it has a higher frequency and will be assigned a shorter code.

b) This statement is false. The Huffman greedy algorithm does not guarantee that a symbol with a frequency of at least 0.5 will always be encoded with a single bit. The encoding depends on the distribution of frequencies and the construction of the Huffman tree.

c) This statement is false. If all symbol frequencies are less than 0.33, it is possible that some symbols will be encoded with a single bit if they have a high frequency, while others may be encoded with more than two bits depending on their frequencies.

d) This statement is true. If all symbol frequencies are less than 0.5, the Huffman greedy algorithm guarantees that all symbols will be encoded with at least two bits. This is because the algorithm assigns shorter codes to symbols with higher frequencies, and since all frequencies are less than 0.5, none of the symbols will have a high enough frequency to be encoded with a single bit.

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Answer: 0.84375

Step-by-step explanation:

1. x = 5.4n

2. 5.4n + n = 5.4

3. n(6.4) = 5.4

4. n = 0.84375

DOUBLE CHECK

x = 5.4(0.84375)

x = 4.55625

4.55625 + 0.84375 = 5.4

0.84375 = 5.4 - 4.55625

0.84375 = 0.84375

The solution is, : for 0.84375 = N such that x+N=5.4 and x/n=5.4 are equivalent equations.

An equation is a  mathematical statement that is made up of two expressions connected by an equal sign.  In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here, we have,

the given equations are:

1. x = 5.4n

2. 5.4n + n = 5.4

3. n(6.4) = 5.4

4. n = 0.84375

DOUBLE CHECK

x = 5.4(0.84375)

x = 4.55625

4.55625 + 0.84375 = 5.4

0.84375 = 5.4 - 4.55625

0.84375 = 0.84375

Hence, The solution is, : for 0.84375 = N such that x+N=5.4 and x/n=5.4 are equivalent equations.

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Therefore, the MLE of θ is θ = -(1/n) ∑ln(x_i). Therefore, θ is an unbiased estimator of θ.

(a) To find the maximum likelihood estimator (MLE) of θ, we first write the likelihood function as follows:

L(θ|x_1, x_2, ..., x_n) = ∏(i=1 to n) f(x_i; θ)

= ∏(i=1 to n) [(1/θ)x_i(1-θ)/θ]

= (1/θ^n) ∏(i=1 to n) x_i(1-θ)

Taking the natural logarithm of L(θ|x_1, x_2, ..., x_n), we have:

ln(L(θ|x_1, x_2, ..., x_n)) = -n ln(θ) + (1-θ) ∑ln(x_i)

To find the MLE of θ, we differentiate ln(L(θ|x_1, x_2, ..., x_n)) with respect to θ and set the derivative to zero:

d/dθ ln(L(θ|x_1, x_2, ..., x_n)) = -n/θ + ∑ln(x_i) = 0

Solving for θ, we get:

θ = -(1/n) ∑ln(x_i)

(b) To show that θ is an unbiased estimator of θ, we need to find its expected value:

E(θ) = E[-(1/n) ∑ln(x_i)]

= -(1/n) ∑E[ln(x_i)]

= -(1/n) ∑[∫0^1 ln(x_i) (1/θ)x_i(1-θ)/θ dx_i]

= -(1/n) ∑[∫0^1 (1/θ)ln(x_i)x_i(1-θ) d(x_i)]

= -(1/n) ∑[θ(-1/(θ^2))(1/2)ln(x_i)^2|0^1 + (1/θ)(1/2)x_i^2(1-θ)|0^1]

= -(1/n) ∑[(1/2θ)ln(x_i)^2 - (1/2θ)x_i^2(θ-1)]

= -(1/n) [(1/2θ)∑ln(x_i)^2 - (1/2θ)(θ-1)∑x_i^2]

Note that ∑ln(x_i)^2 and ∑x_i^2 are constants with respect to θ. Therefore, we have:

E(θ) = -(1/n) [(1/2θ)∑ln(x_i)^2 - (1/2θ)(θ-1)∑x_i^2]

= (1/2) - (1/2nθ)

Since E(θ) = θ, we have:

θ = (1/2) - (1/2nθ)

Solving for θ, we get:

θ = 1/(n+2)

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The price of each pair of skates is given as follows:

$8.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

For which the parameters are given as follows:

A skating rink charges a rate of $4, hence the intercept b is given as follows:

b = 4.

Hence:

y = mx + 4.

A family rents 2 pairs of skates and pays a total of $20, meaning that when x = 2, y = 20, then the slope m, representing the cost of each pair, is obtained as follows:

20 = 2m + 4

2m = 16

m = 16/2

m = 8.

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The answer is y = 1(x + 3)^2 - 81.

area=l×w

l=area/w

l=105/5

l=15

perimater=l+w

perimater=15+7

perimeter=22

Answer:

a) ⅖+⅓ = 6/15 + 5/15 = 11/15

b) 5/9 - 1/2 = 10/18 - 9/18 = 1/18

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

x+4y+68

The number of nonempty sets of letters that can be formed from four a's and eight b's is 4096.

A set is a collection of distinct objects, called elements or members, that have some property or characteristics in common. Sets are used in mathematics to model and study the properties of objects and the relations between objects.

In set theory, sets are defined as unordered collections of elements that are well-defined and have certain properties.

We have,

The number of letters.

4 a's and 8 b's

This means,

a, a, a, a, b, b, b, b, b, b, b, b

Now,

The number of non-empty sets we can form is given by the formula.

= \(2^{n}\)

Where n is the number of letters.

For example,

S = {1, 2, 3}

The number of nonempty sets.

\(2^{3}\\ =8\)

= { {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}, Ф }

Similarly,

The number of nonempty sets from 4 a's and 8 b's.

= \(2^{12}\)

= 4096

Therefore, The number of nonempty sets that can be formed from 4 a's and 8 b's is 4096.

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Answer:

x = 0.5

Step-by-step explanation:

The given expression is :

4(x+2) = 10

Using commutative property at LHS.

4x+8 = 10

Subtract 8 from both sides.

4x+8-8 = 10-8

4x = 2

x = (1/2) = 0.5

So, the value of x is equal to 0.5 instead of 0. Hence, the given expression cannot be equal to 0.

The reciprocal (inverse or indirect quote) for the given exchange rates is as follows:

USO/DKK: The reciprocal exchange rate is 0.1557 DKK/USO.

GBP/NZD: The reciprocal exchange rate is 0.4898 NZD/GBP.

USO/INR: The reciprocal exchange rate is 0.0226 INR/USO.

To calculate the reciprocal quote, we take the reciprocal of the given exchange rate. For example, for USO/DKK with an exchange rate of 6.4270 DKK per USO, the reciprocal is 1 divided by 6.4270, which equals 0.1557 DKK per USO.

Similarly, for GBP/NZD with an exchange rate of 2.0397 NZD per GBP, the reciprocal is 1 divided by 2.0397, which equals 0.4898 NZD per GBP.

Finally, for USO/INR with an exchange rate of 44.333 INR per USO, the reciprocal is 1 divided by 44.333, which equals 0.0226 INR per USO.

These reciprocal quotes represent the inverse of the original exchange rates.

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Complete question: Calculate the reciprocal (inverse or indirect quote) for the following currency pairs:
1. USO/DKK: 1/6.4270 or DKK/USO: 1/350
2. GBP/NZD: 1/2.0397 or NZD/GBP: 1/0.7000
3. USO/INR: 1/44.333 or INR/USO: 1/44.333

Answer:

angle NKP = 60 degrees

Step-by-step explanation:

A line will always equal 180 degrees

If angle JKM and angle MKN are complentary, that means they will add up to 90. Since angle JKM is 40 degrees, angle MKN must be 50 degrees

Angle LKP is 30 degrees

Form an equation:

180 = 40 + 50 + 30 + angle NKP

Combine like terms

180 = 120 + angle NKP

Subtract 120 from both sides to isolate the unknown angle

60 = angle NKP

Answer:

umm so i belive you will mulltiply all of thoes together

Step-by-step explanation:

chicken nuggies are good :0

Answer:

number 3

Step-by-step explanation:

p represents amount of tickets sold at the pre-sale and d represents the amount of tickets sold at the door. If you add p + d, that equals the total amount of tickets sold which is 345 tickets.

So:

p + d = 345

Pre-sale tickets (p) cost $7 while tickets at the door (d) cost $10, and the total amount of money mad is $2550.

So:

7p + 10d = 2550

Answer should be the equations in number 3.

The number of trees more than 10m tall but not more than 20m tall is 18 trees.

0 < h ≤ 5 = 5

height greater than 0m less than or equal to 5m

5 < h ≤ 10 = 9

height greater than 5m less than or equal to 10m

10 < h ≤ 15 = 13

height greater than 10m less than or equal to 15m

15 < h ≤ 20 = 5

height greater than 15m less than or equal to 20m

20 < h ≤ 25 = 1

height greater than 20m less than or equal to 25m

The number of trees that are more than 10m tall but not more than 20m tall are;

10 < h ≤ 15 = 13

15 < h ≤ 20 = 5

So,

13 + 5 = 18 trees

Therefore, the total number of trees which are 10m tall but not more than 20m tall is 18 trees.

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The statement "If y is the solution of the initial-value problem dy dt = 2y 1 − y 5 , y(0) = 1 then lim t→[infinity] y = 5" is false.

To explain why the statement is false, we can analyze the behavior of the solution y as t approaches infinity.

Given the initial-value problem dy/dt = (2y)/(1 - y^5), y(0) = 1, we want to determine the limit of y as t approaches infinity, i.e., lim t→∞ y.

We can rewrite the differential equation as:

dy/(2y) = dt/(1 - y^5)

Integrating both sides of the equation gives:

(1/2) ln|y| = t + C

Where C is the constant of integration.

Solving for y, we have:

ln|y| = 2t + 2C

Taking the exponential of both sides:

|y| = e^(2t+2C)

Since we are interested in the limit of y as t approaches infinity, we can ignore the absolute value sign and focus on the behavior of the exponential term.

As t approaches infinity, the term e^(2t+2C) grows without bound if 2t + 2C is positive. On the other hand, if 2t + 2C is negative, the exponential term approaches zero.

Since y(0) = 1, we can substitute this value into the equation to find the value of the constant C:

ln|1| = 2(0) + 2C

0 = 2C

C = 0

So the equation becomes:

|y| = e^(2t)

Since the exponential term e^(2t) is always positive and approaches infinity as t approaches infinity, we can conclude that the limit of y as t approaches infinity is also positive infinity, i.e., lim t→∞ y = ∞.

Therefore, the statement lim t→∞ y = 5 is false. The correct statement is lim t→∞ y = ∞.

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Answer: 42/21 or 2

Step-by-step explanation:

you first convert them to improper fractions, which is 14/3 and 7/3. Then, you multiply the reciprocal and get 14/3x3/7, and get 42/21. Simplify, and you get 2.

Answer:

9 cups of lemonade

Step-by-step explanation:

First, calculate the amount of money Pablo earns every week:

$5 + $7 + $18 = $30

Calculate how much money Pablo gets each week by selling lemonade:

$30 - $12 = £18

Calculate how many cups of lemonade are being sold each week:

18 ÷ 2 = 9

Pablo needs to sell 9 cups of lemonade each week to reach his goal

Answer: A: 4

Step-by-step explanation:

This is the number we will start the line, if we were to graph this example. We would then go up 1 page for every hour (1 y for every x), on the graph.

The Number of small and large boxes shipped are 10 and 5 respectively.

Large boxes :

Volume = 18 cubic feets

Let number of large boxes = b

Small boxes :

Volume = 10 cubic feets

Number of small boxes = 2b

Total volume shipped = 190 cubic feet

To obtain total volume shipped :

(Number of small boxes × volume of small boxes) + (Number of large boxes × volume of large boxes

Writing as a system of equation :

(10 × 2b) + (18 × b)

20b + 18b = 190 cubic feets

38b = 190

b = 190 ÷ 38

b = 5

Hence,

Number of large boxes = 5

Number of small boxes = 2(5) = 10

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A statement that creates a list is my_nums= [5,10,15]. This is also known as array.

An array is a grouping of identically typed elements that are stored in adjacent memory locations and may each be separately referred to using an index to a special identifier. There is no need to declare five distinct variables when declaring an array of five integer values (each with its own identifier).

The three types of arrays are index, multidimensional and associative array.

my_nums= [5,10,15] is an array that stores multiples of 5.

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A statement that creates a list is my_nums= [5,10,15]. This is also known as array.

What is an array?

An array is a data structure consisting of a collection of elements (values or variables), each identified by at least one array index or key. An array is a combination of a set of elements which are all of the same data type, organized in a particular way. Arrays are used to store multiple values in a single variable, structure data, and access data more efficiently. Arrays are generally used to represent data in a structured way, and they can be used to perform various mathematical operations and other calculations. Arrays are also useful for sorting and searching data in a predetermined order.

What are three types of array?
The three types of array are index, multidimensional and associative array.
my_nums= [5,10,15] is an array that stores multiples of 5.

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