Answer:
Faucet
Explanation:
Probably the leaky faucet....it leaks 24/7 even when she is not home and completely wastes the water....but it really depends on how fast it is leaking vs. how many flushes of the toilet per day Sara does.
Suppose a space vehicle with a rest mass of 150 000 kg travels past the International Space Station at a constant speed of 2.6 x 108 m/s with respect to the I.S.S. When an observer on the I.S.S. measures the moving vehicle, her measurement of the space vehicle length is 25.0 m. Determine the relativistic mass of the space vehicle. Determine the length of the space vehicle as measured by an astronaut on the space vehicle.
Answer:
m = 300668.9 kg
L₀ = 12.47 m
Explanation:
The relativistic mass of the space vehicle is given by the following formula:
\(m = \frac{m_{0}}{\sqrt{1-\frac{v^{2} }{c^{2}} } }\)
where,
m = relativistic mass = ?
m₀ = rest mass = 150000 kg
v = relative speed = 2.6 x 10⁸ m/s
c = speed of light = 3 x 10⁸ m/s
Therefore
\(m = \frac{150000kg}{\sqrt{1-\frac{(2.6 x 10^{8}m/s)^{2} }{(3 x 10^{8}m/s)^{2}} } }\)
m = 300668.9 kg
Now, for rest length of vehicle:
L = L₀√(1 - v²/c²)
where,
L = Relative Length of Vehicle = 25 m
L₀ = Rest Length of Vehicle = ?
Therefore,
25 m = L₀√[1 - (2.6 x 10⁸ m/s)²/(3 x 10⁸ m/s)²]
L₀ = (25 m)(0.499)
L₀ = 12.47 m
Your go-cart breaks down right before the end of a race, so you have to push it over the finish line. The go-cart has a mass of 85 kg.
a. What is the weight of your go-cart?
(I need to show my work)
Explanation:
Weight =mass x force of gravity
Weight = 85kg x 9.8m/s²
Weight = 833N
How far apart are two electrons if they exert an electrostatic force of repulsion of 2.00 x 10 ^-2 on each other?
I think the answer is 1.07x10^-13m, but I don’t know if I’m right
Answer:
Your correct i did the work on my paper and got the same answer
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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An iron meteorite melts when it enters the Earth's atmosphere.
If its initial temperature was -105°C outside of Earth's atmosphere, calculate the minimum velocity the meteorite must have had before it entered Earth's atmosphere.
The minimum velocity for the meteorite before entrance into earth's atmosphere is 36.8 m/s.
How to find minimum velocity?To calculate the minimum velocity the meteorite must have had before it entered Earth's atmosphere, the equation for heat transfer is:
Q = mcΔT
Where Q = the heat transferred,
m = the mass of the meteorite,
c = the specific heat capacity of iron, and
ΔT = the change in temperature.
The specific heat capacity of iron is approximately = 0.45 J/g°C.
Temperature of the meteorite changes from -105°C to the melting point of iron, which is approximately = 1535°C.
So: Q = mc(1535 - (-105))
Mass of the meteorite unknown, but we know it is made of iron, so assume a value for the mass, such as 100 g.
Q = 100 x 0.45(1535 - (-105))
Solving for Q:
Q = 67875 J
To calculate the kinetic energy of the meteorite, which is given by the equation: Ek = 1/2mv²
where Ek is kinetic energy,
m = the mass of the meteorite and
v = the velocity of the meteorite.
Therefore, the velocity of the meteorite is given by the following equation: v = √(2Ek/m)
Substituting the values of Ek and m, we get
v = √(2 x 67875/100)
Solving for v:
v = √1357.5
The minimum velocity the meteorite must have had before it entered Earth's atmosphere is approximately 36.8 m/s.
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A compact car can climb a hill in 10 s. The top of the hill is 30 m higher than the
bottom, and the car's mass is 1,000 kg What is the power output of the car?
Answer:
29.4 kW
Explanation:
time t = 10 s, height h = 30 m, mass m = 1,000 kg
power output = work done/time
work done = increase in potential energy = mgh = 1,000 * 9.8 * 30 = 294,000 J = 294 kJ
power output = 294/10 = 29.4 kW
Which situation does NOT show kinetic energy? *
PLS ANSWER ASAPPPP
Answer options:
A. a hockey puck sliding on the ice
B. a baseball in a catcher's glove
C. a lady walking slowly across the street
D. a man running around a track
"Kinetic" energy is the energy of motion.
The ball in the glove is not moving. It's just laying there. (B)
So it has no kinetic energy.
All the other choices describe something moving, so they all have some.
I NEED THE ANSWER QUICK PLEASEE
01*. A 45kg woman stands on a spring scale inside an elevator. (The scale reads th with which it pushes upward on the woman). What does the scale read when the elew accelerating (a) upward at 3.65m/s², (b) downward at 3.65m/s² ? [605.25N, 276.75N]
Explanation:
There are two forces on the woman: weight force pulling down, and normal force pushing up. The scale reading is the normal force.
Use Newton's second law.
∑F = ma
N − mg = ma
Solve for N.
N = mg + ma
N = m (g + a)
(a) a = +3.65 m/s²
N = (45 kg) (9.8 m/s² + 3.65 m/s²)
N = 605.25 N
(b) a = -3.65 m/s²
N = (45 kg) (9.8 m/s² − 3.65 m/s²)
N = 276.75 N
(a)A 45kg woman stands on a spring scale inside an elevator. The scale reading when the elevator accelerates upward at 3.65m/s² is 605.25N.
(b) A 45kg woman stands on a spring scale inside an elevator, the scale reading when it accelerates downward at 3.65m/s² it is 276.75N.
When a 45kg woman stands on a spring scale inside an elevator, the scale measures the force with which it pushes upward on the woman, which is equal to her weight. The weight of an object can be calculated using the formula weight = mass × acceleration due to gravity (W = m × g), where the acceleration due to gravity is approximately 9.8m/s².
(a) When the elevator accelerates upward at 3.65m/s², the net force acting on the woman is the sum of her weight and the force due to acceleration. The scale reading will be the magnitude of this net force. Using Newton's second law (F = m × a), the net force can be calculated as F = m × (g + a). Substituting the given values, we have
F = 45kg × (9.8m/s² + 3.65m/s²) = 45kg × 13.45m/s² = 605.25N.
(b) When the elevator accelerates downward at 3.65m/s², the net force acting on the woman is her weight minus the force due to acceleration. Applying the same formula, we have
F = 45kg × (9.8m/s² - 3.65m/s²) = 45kg × 6.15m/s² = 276.75N.
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A bat emits a sound with a frequency of 134 kHz in a cave where the temperature is 28°C. Assume that air behaves like an ideal monatomic gas and use the fact that the speed of sound in air at 20.0°C is 343 m/s to determine the wavelength of the sound emitted by the bat.
The wavelength of the sound is 2.6 x 10⁻³ m.
What is the wavelength of the sound?The wavelength of the sound or distance travelled by the sound wave is calculated by applying the following formula.
v = fλ
λ = v / f
where;
v is the speed of the sound wave = 343 m/sf is the frequency of the sound wave = 134 kHzλ is the wavelength of the sound wave = ?The wavelength of the sound is calculated as follows;
λ = v / f
λ = ( 343 m/s ) / ( 134,000 Hz )
λ = 2.6 x 10⁻³ m
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A metal ring 5.00 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpendicular to the magnetic field. These magnets produce an initial uniform field of 1.12 T between them but are gradually pulled apart, causing this field to remain uniform but decrease steadily at 0.220 T/s.
Required:
What is the magnitude of the electric field induced in the ring?
Answer:
Ein: 2.75*10^-3 N/C
Explanation:
The induced electric field can be calculated by using the following path integral:
\(\int E_{in} dl=-\frac{\Phi_B}{dt}\)
Where:
dl: diferencial of circumference of the ring
circumference of the ring = 2πr = 2π(5.00/2)=15.70cm = 0.157 m
ФB: magnetic flux = AB (A: area of the loop = πr^2 = 1.96*10^-3 m^2)
The electric field is always parallel to the dl vector. Then you have:
\(E_{in}\int dl=E_{in}(2\pi r)=E_{in}(0.157m)\)
Next, you take into account that the area of the ring is constant and that dB/dt = - 0.220T/s. Thus, you obtain:
\(E_{in}(0.157m)=-A\frac{dB}{dt}=-(1.96*10^{-3}m^2)(-0.220T/s)=4.31*10^{-4}m^2T/s\\\\E_{in}=\frac{4.31*10^{-4}m^2T/s}{0.157m}=2.75*10^{-3}\frac{N}{C}\)
hence, the induced electric field is 2.75*10^-3 N/C
please help i’m stuck
What are two benefits of scientists using a diagram to model the water cycle?
A. It can be used to show how the parts of the cycle relate to one
another.
B. It can be used to show as much detail ahis present in the actual
water cycle.
c. Only a few factors in the water cycle can be shown on the
diagram
D. It can show changes that occur in many different parts of Earth at
the same time.
Answer:
Options A. and D. are correct.
Explanation:
The water cycle shows the continuous movement of water within the Earth and atmosphere.
The two benefits of scientists using a diagram to model the water cycle are as follows:
It can be used to show how the parts of the cycle relate to one another.
It can show changes that occur in many different parts of Earth at the same time.
Options A. and D. are correct.
A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force has a magnitude of 5 N and acts vertically upward. When the ball is released from rest, what is it's acceleration and direction? [2 pts] for a Free Body Diagram correctly labeled.
Answer:
The acceleration is 2.448 meters per square second and is vertically upward.
Explanation:
The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:
\(\Sigma F = F - m\cdot g = m\cdot a\) (1)
Where:
\(F\) - Buoyant force, measured in newtons.
\(m\) - Mass of the plastic ball, measured in kilograms.
\(g\) - Gravitational acceleration, measured in meters per square second.
\(a\) - Net acceleration, measured in meters per square second.
If we know that \(F = 5\,N\), \(m = 0.408\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the net acceleration of the plastic ball is:
\(a = \frac{F}{m} - g\)
\(a= 2.448\,\frac{m}{s^{2}}\)
The acceleration is 2.448 meters per square second and is vertically upward.
what are ionic charges
Answer:
Ionic charges refer to the electrical charges of ions, which are atoms or molecules that have gained or lost electrons. These charges result from the loss or gain of electrons during chemical reactions.
When an atom loses one or more electrons, it becomes a positively charged ion known as a cation. The cation carries a positive charge equal to the number of electrons lost.
Conversely, when an atom gains one or more electrons, it becomes a negatively charged ion known as an anion. The anion carries a negative charge equal to the number of electrons gained.
The magnitude of the ionic charge depends on the number of electrons gained or lost, which is determined by the element's position in the periodic table and its electron configuration. For example, sodium (Na) loses one electron to become a +1 charged cation (Na+), while chlorine (Cl) gains one electron to become a -1 charged anion (Cl-).
Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?
Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time
solve for average torque for each objects
τ(average) = ΔL / Δt
Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4
Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2
Relates τy and τx
2τx = τy
Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.
The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.
To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:
L = I * ω
Differentiating this equation with an appreciation of time, we get:
dL/dt = d(I * ω)/dt
Using the product rule of differentiation, we've got:
dL/dt = I * dω/dt + ω * dI/dt
Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:
τ = dL/dt
Substituting the expression for dL/dt in terms of angular velocity and second of inertia:
τ = I * dω/dt + ω * dI/dt
Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:
torquex = I0 * dω/dt + ω * dI0/dt
Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:
torquey = (2I0) * dω/dt + ω * d(2I0)/dt
torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)
torquey = 2I0 * dω/dt + 2ω * dI0/dt
Comparing the expressions for torquex and torquey, we will see that:
torquey = 2 * torquex
Therefore, the precise relation between torquey and torquex is;
torquey = 2 * torquex.
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The correct question is;
"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"
Need help with my homework assignment. Thank you!
According to research, development is always towards complexity.
What is the meaning of research?The term research has to do with the process that we have to go through to obtain new knowledge or to confirm a piece of information. Let us say that we have some disconnected pieces of evidence that tend to point towards a particular fact, we would need to use the process of research to establish the truth in the research.
Now we can see that there is a movement towards the complexity of organisms at each particular level in the developmental process. We can then conclude that according to research, development is always towards complexity.
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how big is the solar system
Answer:
287.46 billion km. (kilometers)
Answer:
very Very very Very Very very very Very very very large.
A 0.41 kg particle moves in an xy plane according to x(t) = - 16 + 1 t - 3 t3 and y(t) = 22 + 3 t - 10 t2, with x and y in meters and t in seconds. At t = 1.8 s,
what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
a) The magnitude of the net force is = 15.610 N
b). The angle of the net force relative to the positive direction of the x axis is -147.48°
c) the particle's direction of travel at t = 1.8 s is at an angle of -128.08° relative to the positive direction of the x axis.
How The answers were obtainedTo find the net force on the particle, we need to compute the particle's acceleration at t = 1.8 s and then use Newton's second law, F = ma, to calculate the net force.
The particle's position at t = 1.8 s is:
x(1.8) = -16 + 1(1.8) - 3(1.8)^3 = -53.8848 m
y(1.8) = 22 + 3(1.8) - 10(1.8)^2 = -3.24 m
To find the velocity and acceleration vectors, we need to differentiate the position equations with respect to time:
vx(t) = dx/dt = 1 - 9t^2
vy(t) = dy/dt = 3 - 20t
ax(t) = d^2x/dt^2 = -18t
ay(t) = d^2y/dt^2 = -20
At t = 1.8 s, we have:
vx(1.8) = 1 - 9(1.8)^2 = -28.52 m/s
vy(1.8) = 3 - 20(1.8) = -33.6 m/s
ax(1.8) = -18(1.8) = -32.4 m/s^2
ay(1.8) = -20 m/s^2
The net force on the particle is given by:
Fnet = ma = m(ax i + ay j) = (0.41 kg)(-32.4 i - 20 j) = (-13.284 kg m/s^2 i - 8.2 kg m/s^2 j)
The magnitude of the net force is:
|Fnet| = √[(-13.284)^2 + (-8.2)^2]
= 15.610 N
The angle of the net force relative to the positive direction of the x axis is:
theta = atan2(-8.2, -13.284)
= -147.48°
Note that we use atan2 to get the correct quadrant for the angle.
To find the particle's direction of travel at t = 1.8 s, we need to compute the velocity vector and then find its angle relative to the positive direction of the x axis:v = vx i + vy j = (-28.52 i - 33.6 j)
The angle of the velocity vector relative to the positive direction of the x axis is:
theta_v = atan2(-33.6, -28.52) = -128.08°
Therefore, the particle's direction of travel at t = 1.8 s is at an angle of -128.08° relative to the positive direction of the x axis.
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Answer:
positive direction o
Explanation:
The more exercise a person takes the fewer medical problems they report. This is an example of:
O A. statistical independence.
B. a positive correlation.
O C. a negative correlation.
D. a curvilinear relationship
Answer:
The best answer seems to be B because there is a strong positive correlation that the more exercise a person does, the fewer medical problems they have
Explanation:
Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!
The more exercise a person takes the fewer medical problems they report. This is an example of a positive correlation. The correct option is B.
What is positive correlation?When two variables rise or decrease simultaneously, there is a positive correlation; when there is a negative correlation, one variable increases as the other falls.
When two variables behave in unison, rising or falling in lockstep with one another, there is a positive correlation.
When two variables move in opposition to one another—that is, when one rises, the other falls—this is known as a negative correlation.
A person reports fewer medical issues the more activity they get. An illustration of a positive correlation would be this.
Thus, the correct option is B.
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1. Using the graph, calculate the displacement for the section labeled A.
А
B
D
The Send
Aaron ran 500 meter in 100 Seconds. Find the speed in km per hour.
Answer:
50km
cuz he ran so fast in 100 seconds
I need the answer for this question
Answer:
Since impedance = omega * L we can use the equation for resistance:
20 + 12 + 10 in parallel with 7 we have
J1 = 42 * 7 / 49 = 6 H for the combination on the right
4 H + 6 H + 8 H = 18 H for the entire combination
HI! I need help, this is the complete question but I'm only uncertain about the second part, which formula should I use to solve it?an aircraft is descending with a constant velocity of 133.3m/s at an angle of 2.0 to the horizontal. 1. what is the vertical component of the plane's velocity?2. how long will it take to descend 500m on this flight's path?
Draw a diagram to visualize the situation:
Notice that the vertical component of the velocity can be found using the sine trigonometric function:
\(v_y=v\cdot\sin (2º)\)Substitute v=133.3m/s to find the vertical component of the velocity:
\(v_y=133.3\frac{m}{s}\times\sin (2º)=4.65\frac{m}{s}\)Use the formula v=d/t to find the time that it takes for the plane to descend 500m. Isolate t:
\(\begin{gathered} t=\frac{d}{v} \\ \Rightarrow t=\frac{500m}{4.65\frac{m}{s}}=107.5s \end{gathered}\)Then, the vertical component of the velocity is 4.65m/s (downwards) and it takes 107.5s to descend 500m.
If 1 kg of each substance in the table changes temperature by 15°C, which
substance absorbed the greatest amount of thermal energy?
Substance
Specific Heat Capacity
(kJ/(kg;°C))
Air
1.01
Plastic
2.60
Water
4.18
Wood
1.68
Answer:
Water.
Explanation:
To know which of the substance that will absorbed the greatest amount of thermal energy, we'll simply determine the amount of energy absorbed by each substance.
This is illustrated below:
For Air:
Mass (M) = 1 kg
Change in temperature (ΔT) = 15 °C
Specific heat capacity (C) = 1.01 KJ/Kg°C
Heat Absorbed (Q) =..?
Q = MCΔT
Q = 1 x 1.01 x 15
Q = 15.15 KJ
Therefore, the heat absorbed by air is 15.15 KJ.
For Plastic:
Mass (M) = 1 kg
Change in temperature (ΔT) = 15 °C
Specific heat capacity (C) = 2.60 KJ/Kg°C
Heat Absorbed (Q) =..?
Q = MCΔT
Q = 1 x 2.60 x 15
Q = 39 KJ
Therefore, the heat absorbed by plastic is 39 KJ.
For Water:
Mass (M) = 1 kg
Change in temperature (ΔT) = 15 °C
Specific heat capacity (C) = 4.18 KJ/Kg°C
Heat Absorbed (Q) =..?
Q = MCΔT
Q = 1 x 4.18 x 15
Q = 62.7 KJ
Therefore, the heat absorbed by water is 62.7 KJ.
For Wood:
Mass (M) = 1 kg
Change in temperature (ΔT) = 15 °C
Specific heat capacity (C) = 1.68 KJ/Kg°C
Heat Absorbed (Q) =..?
Q = MCΔT
Q = 1 x 1.68 x 15
Q = 25.2 KJ
Therefore, the heat absorbed by Wood is 25.2 KJ.
Summary:
Substance >>>>> Heat Absorbed
Air >>>>>>>>>>>> 15.15 KJ.
Plastic >>>>>>>>> 39 KJ
Water >>>>>>>>>> 62.7 KJ
Wood >>>>>>>>>> 25.2 KJ.
From the above calculations, we can see that water will absorb the greatest amount of thermal energy.
Write two or three sentences to describe the conductivity of a conductor. Explain its conductivity in terms of the electrons in it.
The conductivity of a conductor refers to its ability to conduct electrical current.
A material that has high conductivity allows electrical charges to flow through it easily and with little resistance, while a material with low conductivity does not allow electrical charges to flow as easily and has more resistance.
The conductivity of a conductor is determined by the number of free electrons in the material, as well as how easily these electrons can move through the material.
In a conductor, the atoms are closely packed together and the electrons are not tightly bound to the atoms, allowing them to move freely through the material and carry an electrical charge. This facilitates the flow of electrical current through the material, resulting in high conductivity.
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Two students are debating about the nature of light:a.Student 1: Looking at the chart, I see that light with a shorter wavelength has the highest frequency. But all light has the same speed.b.Student 2: I disagree with your Student 1. If light has a higher frequency, then it will have a faster speed than light with a lower energy.
Answer:
student 1 is right and student 2 is wrong
Explanation:
In the graph that the two students are observing is a graph of energy and frequency vs. wavelength, this graph is constructed using the relationship between a wave and its wavelength and frequency.
c = λ f
therefore for all waves we have the speed salami.
Therefore student 1 is right and student 2 is wrong
Angle of incidence is 70 degrees what is the relection and refraction ray
The angle of incidence = 35°.
The normal divides the angle between the incident and reflected rays into two equal angles. The angle between the incident ray and the normal is called the angle of incidence. The angle between the reflected ray and the normal is called the reflection angle. When a ray of light approaches a smooth and polished surface and bounces off it, it is called a light reflection.
An incident ray striking a surface is reflected by the surface. A reflected ray is called a reflected ray. The difference between light reflection and refraction is simple. In reflection, a ray hitting a plane returns to its original source/medium as the wave bounces off the surface. However, when refracted, the wave passes through the surface, changing its speed and direction.
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A man walks 30 m to the west than 5 m to the east in 45 seconds.
A). what is his total distance walked?
B). What is his average velocity?
Answer:
35 m
0.56 m/s west
Explanation:
A) Total distance is the length of the path taken.
30 m + 5 m = 35 m
B) Velocity is displacement over time. Displacement is the difference between the final position and the initial position.
If west is -x, and east is +x, then:
Δx = -30 m + 5 m
Δx = -25 m
v = Δx / t
v = -25 m / 45 s
v = -0.56 m/s
v = 0.56 m/s west
The total distance travelled = 35 m and average velocity = 0.55 \(m/s^{2}\)
We have a man who walked 30 m to the west than 5 m to the east in 45 seconds.
We have to find out his total distance walked and his average velocity?
Define Average velocity of a body?The average velocity is defined as the rate of change of displacement per unit time.
\(v_{avg} = \frac{x_{2} -x_{1} }{t_{2} -t_{1} }\)
According to the question -
A). The total distance travelled will be equal to = \(X_{W} +X_{E}\) = 30 + 5 = 35m
Since, the distance travelled is a scalar quantity, we have used simple addition method.
B). In order to calculate the average velocity, first we will calculate the displacement -
Consider the direction to the west as the + x axis, then -
displacement = \(30\overrightarrow{a_{x} } - 5\overrightarrow{a_{x} } = 25\overrightarrow{a_{x} }\)
Magnitude of displacement = 25 x | \(\overrightarrow{a_{x} }\)| = 25 x 1 = 25 m
\(v_{avg} = \frac{25}{45 } = 0.55\) \(m/s^{2}\)
Hence, the total distance travelled = 35 m and average velocity = 0.55\(m/s^{2}\)
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EXPLAIN HOW MAGNETIC MATERIALS ARE SEPARATED FROM COAL
A procedure known as magnetic separation can be used to extract magnetic elements from coal.
This method makes use of the magnetic characteristics of some materials to distinguish them from non-magnetic materials like coal. A description of how magnetic separation can be used to remove magnetic components from coal is given below:
Putting a magnetic field around the coal and magnetic material mixture is the first step in the magnetization process. This can be achieved by creating an electromagnetic field or by putting the mixture close to a powerful magnet.
Magnetism: Magnetic materials, such as iron atoms or magnetite that are frequently found in coal, will be drawn to the magnetic field and become magnetized. They line up their magnetic moments with the magnetic field's direction.
Separation: The magnetic coal components can be physically separated from the non-magnetic coal once they have been magnetized. To create this separation, there are numerous techniques:
Magnetic Drum Separator: Using this technique, the mixture is run through a spinning, magnetized drum. The non-magnetic coal can now go along the conveyor belt without being interfered with by the magnetic materials, which adhere to the surface of the drum and are removed from the coal. Magnetic Pulley Separator: This method involves mounting a magnetic pulley at the discharge end of a conveyor belt that is transporting the mixture. The magnetic pulley draws in and gathers the magnetic elements as the belt moves, sending them to a different location for collecting.Magnetic fluid separation includes floating the mixture in a liquid medium and using a magnetic field to draw and separate the magnetic particles. By using filtration or decantation, the magnetic materials can be separated from one another.Learn more about coal from the given link:
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