Answer:
42m/s
6.06s
Explanation:
To find the initial velocity and time in which the ball is fling over the ground you use the following formulas:
\(x_{max}=\frac{v_o^2sin(2\theta)}{g}\\\\x_{max}=vt_{max}\)
θ: angle = 45°
vo: initial velocity
g: gravitational constant = 9.8m/s^2
x_max: max distance = 180 m
t_max: max time
by replacing the values of the parameters and do vo the subject of the first formula you obtain:
\(v_o=\sqrt{\frac{gx_{max}}{sin(2\theta)}}\\\\v_o=\sqrt{\frac{(9.8m/s^2)(180m)}{sin(2(45\°))}}=42\frac{m}{s}\)
with this value of vo you calculate the max time:
\(t_{max}=\frac{x_{max}}{v}=\frac{x_{max}}{v_ocos(45\°)}\\\\t_{max}=\frac{180m}{(42m/s)cos(45\°)}=6.06s\)
hence, the initial velocity of the ball is 42m/s and the time in which the ball is in the air is 6.06s
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TRANSLATION:
Para encontrar la velocidad inicial y el tiempo en el que la pelota está volando sobre el suelo, use las siguientes fórmulas:
θ: ángulo = 45 °
vo: velocidad inicial
g: constante gravitacional = 9.8m / s ^ 2
x_max: distancia máxima = 180 m
t_max: tiempo máximo
reemplazando los valores de los parámetros y haciendo el tema de la primera fórmula que obtiene:
con este valor de vo usted calcula el tiempo máximo:
por lo tanto, la velocidad inicial de la pelota es de 42 m / sy el tiempo en que la pelota está en el aire es de 6.06 s
What phase of matter are the particles least energetic, most dense, and best organized?
A. Plasma
B. Gas
C. Liquid
D. Solid
Conservation of Momentum
No one likes you little trolls please send an actual answer
Hello!
This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).
We can write out the conservation of momentum formula:
m1vi + m2vi = m1vf + m2vf
Let:
m1 = mass of puck
m2 = mass of the goalkeeper
We know that the initial velocity of the goalkeeper is 0, so:
m1vi + m2(0) = m1vf + m2vf
m1vi = m1vf + m2vf
The final velocities will be the same, so:
m1vi = (m1 + m2)vf
Plug in the given values:
(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s
Using the equation for momentum:
p = mv
The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of
p = (120)(0.0533) = 6.396 kgm/s.
determine the henry's law constant for ammonia in water at 25°c if an ammonia pressure of 0.022 atm produces a solution with a concentration of 0.77 m.
Therefore, the Henry's Law constant for ammonia in water at 25°C is 5.6 x 10^-4 M/atm.
The Henry's Law constant relates the vapor pressure of a gas to its concentration in the solution. The concentration of ammonia in a solution of 0.77 molarity is produced by an ammonia pressure of 0.022 atm. We will use this information to determine the Henry's Law constant for ammonia in water at 25°C.
Henry's Law states that:
P = K * C
Where P is the partial pressure of the gas, K is the Henry's Law constant, and C is the molar concentration of the gas in the solution.
At 25°C, the Henry's Law constant for ammonia is calculated to be 5.6 x 10^-4 M/atm.
To determine this constant, we first need to convert the pressure into molarity.
We can use the ideal gas law,
PV = nRT,
to find the moles of ammonia gas in the solution:
PV = nRTn = PV/RTn = (0.022 atm) * (1 L) / (0.08206 L*atm/mol*K) * (298 K)n = 0.000902 mol
Next, we can divide the moles of ammonia by the volume of the solution to get the molarity:
C = n/V = 0.000902 mol / 1.17 L = 0.77 M
Now we can use Henry's Law to find the Henry's Law constant K:
P = K * CP = 0.022 atm
K = P/C = 0.022 atm / 0.77 M
K = 2.857 x 10^-2 atm/M = 5.6 x 10^-4 M/atm.
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What is the length a of the semimajor axis of a planet whose period is 214 days
0.7 AU is the length a of the semimajor axis of a planet whose period is 214 days.
The given orbital period is T = 214 days
Now, let's convert the orbital period into years :
T = (214 days) (1 year / 365 days)
T = 0.586 years eq.....1
As we know that, constant proportionality is the same for all the planets.
Therefore, as per the Kepler's third law of planetary motion :
T^2 = R^3
Now, put the value of T from eq....1
(0.586)^2 = R^3
0.343 = R^3
R = 0.7 AU
Thus, the length a of the semimajor axis of a planet whose period is 214 days is 0.7 AU
What is Kepler's Third Law of Planetary Motion ?
According to Kepler's third law of planetary motion, the square of a planet's orbital period is directly proportional to the cube of the length of its semimajor axis.
T^2 ∝ R^3
Where T is the planet's orbital period in years and R is the length of the semimajor axis or average distance from the sun in AU (Astronomical Units). For all planets, the constant proportionality k is the same.
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What is meant by the “right to redress”?
Answer:it can be putting right a wrong by compensation or compensation for injuries sustained; recovery or restitution for harm or injury; damages or equitable relief. Right to redress refers to the right to a relief or remedy.The right of redress is a capability that anyone should be able to exercise if they consider they are not being treated in ways that are congruent with their status as an individual person worthy of respect.
Explanation: I hope this helps I tried my best<33
Answer:
d.
The consumer has the right to fair settlement of disputes
Explanation:
Two dimensions. In Figure 13-34, three point particles are fixed in place in an xy plane. Particle A has mass mA = 3 g, particle B has mass 2.00mA, and particle C has mass 3.00mA. A fourth particle D, with mass 4.00mA, is to be placed near the other three particles. What (a) x coordinate and (b) y coordinate should particle D be placed so that the net gravitational force on particle A from particles B, C, and D is zero (d = 22 cm)?
To make the net gravitational force on particle A from particles B, C, and D zero, particle D should be placed at the x coordinate of -11 cm and the y coordinate of 0 cm.
The net gravitational force on particle A from particles B, C, and D can be calculated using the formula for gravitational force:
F = G * (m₁ * m₂) / r²
Where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the two particles, and r is the distance between them.
Since the net gravitational force on particle A should be zero, we can set up an equation:
FAB + FAC + FAD = 0
Using the given information that the distance d is 22 cm and the masses of particles B, C, and D are known in terms of mA, we can calculate the x and y coordinates for particle D.
By applying the principle of superposition, we can calculate the net gravitational force on particle A from particles B, C, and D at the x coordinate and y coordinate of particle D. By adjusting the position of particle D, we can find the coordinates that result in a net gravitational force of zero on particle A.
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[PLEASE ANSWER WITH 6TH GRAMMAR) Although people usually only hear about the benefits of exercise, there can be risk factors as well. Some of these risks are inherent in different types of exercises or sports, but other risks can be associated with the environment where someone chooses to exercise. What are some environmental risk factors that should be considered and avoided when exercising?
Answer:
heat, light, pollution, hypoxia
Explanation:
Answer:
I'm in 8th grade but oh whatever
Explanation:
Some Enviromental risk factors that should be avoided when exercising would be Dehydration. Dehydration would be considered a risk because if you're exercising nonstop outside in the heat and not drinking plenty of water, there could be serious health issues such as your blood volume going down. Another risk factor would be a heat stroke. A heat stroke is when your body temperature is over the original temperature. So, if you exercise long enough outside, then your body temperature will increase causing a heat stroke. Therefore, you should manage how long you exercise outside.
a circuit is connected to 8 volt battery and it has 2 amperes of current flowing through the wires.What is the resistance of the circuit
Answer:
4 ohms
Explanation:
Current = Voltage/resistance
2 = 8/R
2R = 8
R = 4
The following figure shows a Ferris wheel that rotates 6 times each minute and has a diameter of 17.8. What is the centripetal acceleration of a rider?
Answer:
106.8
Explanation:
If you multiply 6 and 17.8, you'll get 106.8.
If that's wrong, my apology's !
uotuN
CER: Momentum and Collisions - Preventing Concussions in Football Players and
Woodpeckers
Using the question below, develop a claim-evidence-reasoning to fully answer and explain
every part of the phenomenon we looked at in this part of the Unit.
Question: Why do football players get concussions, but woodpeckers don't?
Claim (your answer to the question; 1 sentence):
Evidence (values, descriptions, and observations that support your claim; 2-3
sentences):
Reasoning (explanation of the evidence to further support your claim; 3-4 sentences):
Even the most powerful woodpeckers could not penetrate a bird's brain with more than 60% of the force required to cause a concussion in a human.
How do concussions affect football players?One of the most frequent causes of concussions in football is helmet-to-helmet contact, but any collision that causes the head to rapidly snap back or to the side can cause the brain to collide with the skull. The brain striking the skull during this impact is what creates a concussion.
What physics governs the woodpecker?He uses his potential energy to maintain the swing by lowering a stick and hard-beating it with its beak.
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A plane mirror moves towards the object with a velocity of 2m/s and the object itself moves towards the mirror with a velocity of 5m/s. What is the velocity of the image approaching towards the object?
We have that the velocity of the image approaching towards the object is
\(x=3.33m/s\)
From the question we are told
A plane mirror moves towards the object with a velocity of 2m/s and the object itself moves towards the mirror with a velocity of 5m/s. What is the velocity of the image approaching towards the object?
Generally the equation for the velocity of the image is mathematically given as
\(\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\Therefore\\\\\frac{1}{2}=\frac{1}{x}+\frac{1}{5}\\\\\frac{1}{x}=\frac{1}{2}-+\frac{1}{5}\\\\\frac{1}{x}=0.3\)
\(x=3.33m/s\)
Therefore
the velocity of the image approaching towards the object is
\(x=3.33m/s\)
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The constructor equation of the geometric optics allows to find the result for the speed of the image is 7 m/s
Geometric optics analyzes the formation of images with different objects, for this it uses the constructor equation
\(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)
Where f is the focal length, p the distance a to the object and q the distance to the image
In this case we have a plane mirror, a plane object has its radius of curvature at infinity (f = ∞), consequently
p = q
If we derive this expression with respect to time
\(\frac{dp}{dt} = \frac{dq}{dt}\)
The speed of the object and the image is the same.
In all these equation is the mirror or lens are considered fixed in space
In this case we have that the object moves towards the mirror at v₀ = 2 m / s and the mirror moves towards the object at \(v_m\) = 5 m / s
To consider the mirror fixed in space, we must find the relative velocity of the object with respect to the mirror; the body approaches the speeds add
\(v_{om} = v_o +v_m\)
Where \(v_{om}\) speed of the object with respect to the mirror, v₀ and \(v_m\) are the velocities of the object and the mirror, respectively
\(v_{om}\) = 5 + 2
v_{om} = 7 m / s
The speed of the image and the object are equal, therefore the image speed is:
v = 7 m / s
In conclusion using the constructor equation allow to find the result for the image speed is 7 m / s
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Which mineral has a blue color and will scratch the garnet?
Topaz
Pyrite
Magnetite
Garnet
Augite
Talc
Answer:
Topaz
Explanation:
It's harder than garnet and comes in various colors
Answer:
garnet
Explanation:
let assume a hypothetical planet was discovered orbiting around the star. its orbital distance was measured to be 300 million kilometers. what is the orbital period
The hypothetical planet discovered orbiting the star has an orbital period of 4.44 Earth years.
When a hypothetical planet is discovered orbiting a star, its orbital distance is measured to be 300 million kilometers. The orbital period of the planet is determined by its distance from the star and the mass of the star.
The time taken by an object to complete a single orbit around another object is known as the orbital period. It is calculated based on the distance between the two objects and the mass of the central object. The formula for calculating the orbital period of a planet is:
Orbital period = 2π √(r³/GM)
Where r is the distance between the planet and the star, G is the gravitational constant, and M is the mass of the star.π is the mathematical constant pi whose value is 3.14.So, in the case of the hypothetical planet, the orbital period can be calculated as:
Orbital period\(= 2π √(r³/GM) = 2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x M)]\)
Where the value of the gravitational constant is\(6.67 x 10^-11 Nm^2/kg^2\).
Assuming the mass of the star is one solar mass or \(1.989 x 10^30\)kg,
the orbital period can be calculated as:
Orbital period = \(2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x 1.989 x 10^30)] = 4.44\) Earth years
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By referring to Standard Method of Measurement 2 (SMM2), explain the following clauses:
i. D.10
ii. D.12.4
iii. D.12.6
iv. D.12.8
SMM2 refers to the Standard Method of Measurement 2. It is a document that specifies the method and processes used in measuring buildings and civil engineering works. SMM2 is commonly used in the construction industry.
The following are explanations of the clauses under Standard Method of Measurement 2 (SMM2):
i. D.10: This clause under SMM2 relates to the painting of metal and timber surfaces. It stipulates that when painting the surfaces of timber or metal, the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.
ii. D.12.4: This clause under SMM2 refers to the construction of walls using concrete blocks. It states that the concrete blocks used should have a minimum density of 1500 kg/m3. It also outlines specific measurements for the thickness of the mortar to be used for bonding the blocks together. The clause further specifies the measurement of the joint thickness between blocks.
iii. D.12.6: This clause under SMM2 refers to the rendering of walls with a cement mortar mix. It specifies that before rendering, the surface of the wall must be clean, dry, and free of debris. It also outlines specific measurements for the thickness of the rendering to be applied to the wall. The clause then stipulates that the rendering should be finished with a smooth surface that conforms to the architect's specifications.
iv. D.12.8: This clause under SMM2 refers to the painting of interior plastered walls. It stipulates that the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.
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A baseball pitcher throws a ball across home plate. The ball travels 13.40m in 0.357s Determine the
speed of the ball in
m/s
Please Help!!
Answer: I'm not sure what it needs to be rounded to, but I got 37.53501401 m/s
Explanation: The formula for speed is speed = distance/time. You plug in the distance (13.40) and the time (0.357), then divide 13.40 by 0.357
I hope this helps! :)
Please can someone answer, I need help!!
Explain what role does capitalism and patriarchy play in American beauty? What images
projected in today's media are a result of gender inequality, what message do the images
send to young people? Explain in at least two paragraphs.
Answer:
Both beauty standards and the feminine beauty ideal are moving targets. Psychologists have argued that it may be all but impossible to separate what we inherently and individually find beautiful from what society tells us is beautiful. In my opinion, beauty standards are the gnarled and rotten roots of all that’s wrong with the industry and perhaps the world. They are tools of oppression that reinforce sexism, racism, colorism, classism, ableism, ageism, and gender norms. They are built into our societies and embedded into our brains.
According to scientists' recent research, women are well represented in media and entertainment companies. But even with corporate America’s increased focus on ensuring gender parity. Scientist observed that women’s day-to-day workplace experiences in media and entertainment are worse than men’s. Almost half of all respondents said they believe women in their fields are judged by different standards than men, which they say makes it difficult to achieve parity in senior management in their workplaces. So the media influence on pre-teens and teenagers can be deliberate and direct. For example, advertising is often directed at children of all ages. This means that children, pre-teens and teenagers are increasingly conscious of brands and images.
A car accelerates from 5m/s to 20m/s in 2.5 seconds
Acceleration of the car is 6 m / s ².
a = ( v - u ) / t
a stands for acceleration
u stands for initial velocity
v stands for final velocity
Given ,
u = 5 m / s
v = 20 m / s
t = 2.5 s
a = ( v - u ) / t
a = ( 20 - 5 ) / 2.5
= 15 / 2.5
a = 6 m / s ²
Hence , Acceleration of car is 6 m / s ² .
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The given question is incomplete kindly refer below for complete question :
A car accelerates from 5m/s to 20m/s in 2.5 seconds . Find the acceleration of the car .
Part II – Measuring distant objects [24 points] Parallax as
explained in the pre-lab activity, is an interesting way of
measuring the distance of an object by how much it appears to move
when viewed
wZAnswer:d
Explanation:
efwdx
Parallax is a valuable technique used in astronomy to measure the distances of nearby celestial objects accurately. It relies on the apparent shift in an object's position when viewed from different locations on Earth's orbit and utilizes trigonometry to calculate the distance to the object.
Parallax is the apparent shift or change in the position of an object when viewed from different perspectives. This effect occurs when an observer changes their viewing angle. In astronomy, parallax is used to measure the distances of stars, planets, and other celestial objects.
The principle behind parallax is simple: Observers on Earth have slightly different views of a nearby object compared to a distant one, due to the difference in the observer's location on the planet. By measuring the apparent shift in the position of an object when viewed from two different points (such as two different locations on Earth), astronomers can calculate the object's distance.
The baseline used for measuring the parallax is the distance between the two observing points. In the case of celestial objects, the baseline is the distance between two points on the Earth's orbit, which are six months apart. This is because the Earth's position is significantly different after half a year due to its revolution around the Sun.
To measure parallax accurately, astronomers use specialized instruments like telescopes and cameras to observe the position of stars or other celestial objects at different times of the year. By comparing the apparent shifts in the object's position, they can determine the parallax angle. Using trigonometry, they can then calculate the distance to the object.
The formula used to calculate the distance to the object is:
Distance (in parsecs) = 1 / Parallax (in arcseconds)
That 1 parsec is approximately equal to 3.26 light-years.
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WDYK? Can you remember how ionic bonds were defined from your physical science class?
(Level 5-6) 3. An object accelerates 15.0 m/s2 when a force of 8.ON is applied to it. What is the mass of the
object in g and Kg?
Answer:
0.53 kg
Explanation:
Mass = \(\frac{Force}{acceleration}\)
Force (also weight) = 8.0N
Acceleration = 15.0 \(m/s^{2}\)
= \(\frac{8.0}{15}\)
= 0.53 kg ( to 2 decimal place )
The light beam shown in the figure below makes an angle of? = 15.5° with the normal line NN' in the linseedoil. Determine the angles θ and θ'.(The refractive index for linseed oil is 1.48.)
θ = 1
°
θ' = 2
°
The angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.
To determine the angles θ and θ' in the given scenario, we can use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the media involved. Snell's Law can be stated as follows:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
Where:
n₁ is the refractive index of the medium of incidence (in this case, air with a refractive index close to 1),
θ₁ is the angle of incidence,
n₂ is the refractive index of the medium of refraction (in this case, linseed oil with a refractive index of 1.48), and
θ₂ is the angle of refraction.
Let's solve for the unknown angles θ and θ' using the given information.
Given:
Angle of incidence θ = 1°
Refractive index of linseed oil n₂ = 1.48
We need to find the angle of refraction θ₂.
Using Snell's Law, we have:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:
sin(θ₁) = n₂ * sin(θ₂)
Plugging in the values:
sin(1°) = 1.48 * sin(θ₂)
We can now solve for θ₂:
θ₂ = arcsin(sin(1°) / 1.48)
Calculating this value, we find:
θ₂ ≈ 0.688°
Now, let's determine the angle θ'.
Given:
Angle of refraction θ₂ = 0.688°
Refractive index of linseed oil n₂ = 1.48
We need to find the angle of incidence θ'.
Using Snell's Law, we have:
n₂ * sin(θ₂) = n₁ * sin(θ')
Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:
n₂ * sin(θ₂) = sin(θ')
Plugging in the values:
1.48 * sin(0.688°) = sin(θ')
Solving for θ', we find:
θ' = arcsin(1.48 * sin(0.688°))
Calculating this value, we get:
θ' ≈ 1.988°
Therefore, the angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.
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If the refractive index of water is 1.33, then its critical angle is...
Calculate the reading on voltmeter v²
The reading of the voltmeter can be determined by finding the potential difference across the 2Ω resistance by using the value of current in the circuit. V=IR, here V is the potential difference across a resistance R through which a current I is flowing.
The table shows data for four planetary bodies. If your mass is 68. 05 kg, how
much gravitational force would you experience on the surface of the Moon?
Newton's law of gravitation is F, Gm me. The gravitational constant
Gis 6. 67 * 10-11 Nm2/C2. (For the purposes of calculating the gravitational
force between a planet and an object on its surface, the distance ris the
radius of the planet. )
gravity
14
You would experience a gravitational force of C.92.1 N on the surface of Mercury.
To calculate the gravitational force experienced on the surface of Mercury, we can use Newton's law of gravitation. The formula for gravitational force is given by:
F = (G * m1 * m2) / \(r^{2}\)
Where:
F is the gravitational force,
G is the gravitational constant (6.67 x \(10^{-11}\) N·m²/kg²),
m1 is the mass of the object (your mass),
m2 is the mass of the planetary body (Mass of Mercury), and
r is the radius of the planetary body (Radius of Mercury).
Given that your mass is 68.05 kg and the mass and radius of Mercury are 3.30 x \(10^{23}\) kg and 2.44 x \(10^{6}\) m respectively, we can calculate the gravitational force:
F = (6.67 x \(10^{-11}\) N·m²/kg²) * (68.05 kg) * (3.30 x \(10^{23}\) kg) / (2.44 x \(10^{6}\) m)\(^{2}\)
After calculating this equation, we find that the gravitational force experienced on the surface of Mercury would be approximately 92.1 N.
Therefore, the correct answer is option C. You would experience a gravitational force of approximately 92.1 N on the surface of Mercury. Therefore, Option C is correct.
The question was incomplete. find the full content below:
The table shows data for four planetary bodies. If your mass is 68.05 kg, how
much gravitational force would you experience on the surface of Mercury?
Newton's law of gravitation is F gravity Gmima The gravitational constant
Gis 6.67 x 10-11 N·m²/c2. (For the purposes of calculating the gravitational
force between a planet and an object on its surface, the distance ris the
radius of the planet.)
Planetary body
Mass, kg
Radius, m
Earth
5.97 X 1024
6.37 x 106
Moon
7.35 x 1022
1.74 x 106
Mars
6.42 x 1023
3.39 x 106
Mercury
3.30 x 1023
2.44 x 106
A. 110 N
B. 252 N
C. 92.1 N
D. 254 N
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If you running a mile for time, which is the best method to maximize your outcome in completing your jog in a good time?
The maximize your outcome when running a mile for time, there are several methods that you can use. The first is to establish a good pace from the beginning. You don't want to start off too fast and burn out before the end, but you also don't want to start too slow and waste precious seconds trying to catch up.
The best to find a pace that feels challenging but sustainable and stick with it throughout the mile. Another method is to focus on your form. This means keeping your shoulders relaxed, your arms at your sides, and your strides short and quick. Good form not only helps you move more efficiently, but it can also prevent injury and fatigue. Breathing is also important when running a mile for time. You want to take deep breaths in through your nose and exhale through your mouth. It's also helpful to focus on your breathing and try to match it with your stride pattern. Finally, mental preparation can be key to maximizing your outcome when running a mile for time. This means visualizing yourself completing the mile in a good time, staying focused, and pushing through any discomfort or fatigue. With these methods, you can set yourself up for success and achieve your best possible time when running a mile.
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An electron moving along the +x-axis enters a magnetic field. Ifthe electron experiences a magnetic deflection in the -y direction, what is the direction of the magnetic field in this region?A) along the +z-axisB) along the -z-axisC) along the -x-axisD) along the +y-axisE) along the -y-axis
The direction of the magnetic field in this region is along the -z-axis (option B).
To determine the direction of the magnetic field when an electron moving along the +x-axis experiences a magnetic deflection in the -y direction, we can use the right-hand rule.
1: Point your thumb in the direction of the electron's motion, which is along the +x-axis.
2: Point your index finger in the direction of the magnetic force experienced by the electron, which is in the -y direction.
3: Your middle finger will point in the direction of the magnetic field.
Following these steps, your middle finger will point along the -z-axis.
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A car traveled 1 hour at a contanst velocity of 65 mph west with cruise control. The acceleration is
a subway train starts from rest at a station and accelerates at a rate of 1.60 m/s2 for 14.0 s . it runs at constant speed for 70.0 s and slows down at a rate of 3.50 m/s2 until it stops at the next station.
The subway train has a constant acceleration of 1.60 m/s^2 for 14.0 s
And then runs at constant speed for 70.0 s
Before slowing down at a rate of 3.50 m/s^2 until it stops.
The final velocity, distance traveled, and time taken can be calculated using kinematic equations.
A branch of physics called kinematics, which originated in classical mechanics, defines how points, bodies, and systems of bodies move without taking into account the forces that are responsible for their motion.
When an object has either a constant velocity or constant acceleration, kinematic equations can be used to aid in problem-solving.
Kinematics is the area of classical mechanics that studies the motion of points, objects, and groups of things without taking into account the causes of motion. The Greek term "kinesis," which means motion, is where the name "kinematics" originates.
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6th grade science please help
A 1.30 kg ball is attached to a ceiling by a
1.93 m long string. The height of the room is
3.41 m.
The acceleration of gravity is 9.81 m/s^2.
What is the gravitational potential energy
associated with the ball relative to
a) the ceiling?
b.)the floor?
c.)a point at the same elevation as the ball?
(answer in J)
Answer:
A
Explanation:
Put A, It will help you.