where are the options???
The second term of an arithmetic sequence is –39. The rule a, - a-1 +12 can be used to find the next term of the
sequence. What is the explicit rule for the arithmetic sequence?
Answer:
a 2 = -39
a 2 = a 1 + 12
- 39 = a 1 + 12
a 1 = - 39 - 12
a 1 = - 51 ( first term )
The common difference is : d = 12
The explicit rule for the arithmetic sequence:
a n = a1 + ( n - 1 ) d
a n = -51 + ( n - 1 ) · 12
Step-by-step explanation:
n a given year, there are 10 million unemployed workers and 120 million employed workers in an economy.
In a given year, an economy has 10 million unemployed workers and 120 million employed workers. This information provides a snapshot of the labor market and indicates the number of individuals who are currently without jobs and those who are employed.
The information states that in the given year, there are 10 million unemployed workers and 120 million employed workers in the economy. This data provides a measure of the labor market situation at a specific point in time.
Unemployed workers refer to individuals who are actively seeking employment but currently do not have a job. The number of unemployed workers can be an important indicator of the health of an economy and its ability to provide job opportunities.
Employed workers, on the other hand, represent individuals who have jobs and are currently working. The number of employed workers indicates the size of the workforce that is actively contributing to the economy through productive activities.
By knowing the number of unemployed and employed workers, policymakers, economists, and analysts can assess factors such as labor market conditions, unemployment rates, and workforce participation rates. This information is crucial for formulating policies, understanding economic dynamics, and monitoring the overall health and functioning of the economy.
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sin−1(sin/6)
cos−1(cos5/4)
tan−1(tan5/6) compute without using a calculator
Without using a calculator, the trigonometric expressions simplify to:
1. sin^(-1)(sin(θ/6)) = θ/6
2. cos^(-1)(cos(5/4)) = 5/4
3. tan^(-1)(tan(5/6)) = 5/6.
To compute the trigonometric expressions without using a calculator, we can make use of the properties and relationships between trigonometric functions.
1. sin^(-1)(sin(θ/6)):
Since sin^(-1)(sin(x)) = x for -π/2 ≤ x ≤ π/2, we have sin^(-1)(sin(θ/6)) = θ/6.
2. cos^(-1)(cos(5/4)):
Similarly, cos^(-1)(cos(x)) = x for 0 ≤ x ≤ π. Therefore, cos^(-1)(cos(5/4)) = 5/4.
3. tan^(-1)(tan(5/6)):
tan^(-1)(tan(x)) = x for -π/2 < x < π/2. Thus, tan^(-1)(tan(5/6)) = 5/6.
Hence, without using a calculator, we find that:
sin^(-1)(sin(θ/6)) = θ/6,
cos^(-1)(cos(5/4)) = 5/4,
tan^(-1)(tan(5/6)) = 5/6.
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If the nth term of a sequence is
7n + 2 what is the 10th term?
Answer:
72
Step-by-step explanation:
7(10) + 2
70 + 2
72
What is the value of k?
Answer:
10°
Step-by-step explanation:
According remote interior angles, 4k + 5 + 6k + 10 = 115.
10k + 15 = 115
10k = 100
k = 10
Hope this helps :)
Have a nice day!
Answer:
k = 10°
Step-by-step explanation:
According to the exterior angle theorem, the exterior angle will be equal to the two opposite inside angles added together. It will look like the following, and we solve for k from there.
115° = (4k + 5)° + (6k + 10)°
115° = 4k° + 5° + 6k° + 10°
115° = 6k° + 4k° + 10° + 5°
115° = 10k° + 15°
100° = 10k°
10° = k
k = 10°
a class has 30 students. what is the probability that at least two people in this class share the same birthday?
To calculate the probability that at least two people in a class of 30 share the same birthday, we can use the complement rule, which states that the probability of an event happening is equal to one minus the probability of the event not happening.
If we assume that birthdays are uniformly distributed throughout the year (i.e., each day is equally likely to be someone's birthday), then the probability that no two people in the class share the same birthday is:
365/365 * 364/365 * 363/365 * ... * 336/365
This is because the first person can have any birthday (probability of 365/365), the second person must have a different birthday (probability of 364/365), the third person must have a different birthday than the first two (probability of 363/365), and so on, up to the 30th person, who must have a different birthday than the first 29 (probability of 336/365).
Calculating this probability gives us:
(365/365) * (364/365) * (363/365) * ... * (336/365) ≈ 0.2937
So the probability that no two people in the class share the same birthday is approximately 0.2937.
Using the complement rule, the probability that at least two people in the class share the same birthday is:
1 - 0.2937 = 0.7063
Therefore, the probability that at least two people in a class of 30 share the same birthday is approximately 0.7063, or 70.63%.
Prove Power of a Point I Theorem o Let and be chords of a circle meeting at a point X inside the circle. Then, • Let v represent the y-axis and let h represent the x-axis. • Find the image of (2, 3) under the reflection . Find the image of (2, 3) under the reflection. • Find the image of (2, 3) under the composition mapping • What is the image of an arbitrary point under ? . Give a simple geometric description of the composition 6.6 Power of a Point I Theorem Let and be chords of a circle meeting at a point inside the circle. Then, 6.7 Power of a Point II Theorem Let be a point outside a given circle. Suppose we draw two rays from the point: one ray intersects the circle at the points and in that order), and the other intersects the circle at the points and in that order). Then
The Power of a Point Theorem I states that if two chords of a circle intersect at a point inside the circle, then the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
The Power of a Point Theorem II states that if a point is located outside a circle and two rays are drawn from that point intersecting the circle, then the product of the lengths of the segments of one ray is equal to the product of the lengths of the segments of the other ray. These theorems provide useful relationships between the lengths of segments formed by chords and rays intersecting a circle.
Power of a Point Theorem I: Consider two chords of a circle, AB and CD, intersecting at a point X inside the circle. According to the theorem, the product of the lengths of AX and BX is equal to the product of the lengths of CX and DX: AX * BX = CX * DX. This relationship holds true for any pair of intersecting chords inside a circle.
Power of a Point Theorem II: Suppose there is a point P located outside a given circle. Draw two rays, PA and PB, from point P intersecting the circle at points A and B, and PC and PD intersecting the circle at points C and D, respectively. The theorem states that the product of the lengths of PA and PB is equal to the product of the lengths of PC and PD: PA * PB = PC * PD. This relationship applies to any pair of rays drawn from a point outside a circle and intersecting the circle.
These theorems provide geometric relationships that can be utilized in various geometric proofs and problem-solving involving circles. They help establish connections between the lengths of segments formed by chords and rays intersecting a circle, enabling the calculation of unknown segment lengths based on known ones.
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Find the value of x.
(5x +13)
(4x+ 2)°
(2x -9)
Answer:
x = 20
Step-by-step explanation:
By exterior angle theorem, we have:
\((4x + 2) \degree + (2x - 9) \degree = (5x + 13) \degree \\ \\(4x + 2 + 2x - 9) \degree = (5x + 13) \degree\\ \\(6x - 7) \degree = (5x + 13) \degree \\ \\ 6x - 7 = 5x + 13 \\ \\ 6x - 5x = 13 + 7 \\ \\ x = 20\)
true or false: prior probability is the initial probability based on the present level of information.
Prior probability is the initial probability based on the present level of information. The given statement is true.
Prior probability, also known as prior belief or prior distribution, is the initial probability assigned to an event or hypothesis based on the available information before new data or evidence is observed or collected. It represents the degree of belief or probability of an event before considering any new evidence or information.
The prior probability is updated using Bayes' theorem after considering new evidence or data, resulting in a posterior probability that represents the revised probability of the event or hypothesis.
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The Environmental Protection Agency sets limits on the maximum allowable concentration of certain chemicals in drinking water. For the substance PCB, the limit was been set at 5 ppm (parts per million). The PCB level is unsafe if it is greater than 5 ppm. A random sample of 36 water specimens from the same well results in a mean PCB concentration of 5. 2 ppm with standard deviation of 0. 6 ppm. Does the data substantiate that the water is unsafe? Write the hypothesis and conclusion, p-value and test statistic
To determine if the water is unsafe based on the given data, we can conduct a hypothesis test using the sample mean and the provided information.
Null Hypothesis (H₀): The mean PCB concentration in the water is equal to or less than 5 ppm.
Alternative Hypothesis (H₁): The mean PCB concentration in the water is greater than 5 ppm.
We will use a one-sample t-test to assess the evidence.
Test statistic and p-value calculation:
The test statistic for a one-sample t-test is calculated as:
t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))
In this case:
Sample mean (x) = 5.2 ppm
Hypothesized mean (μ₀) = 5 ppm
Sample standard deviation (s) = 0.6 ppm
Sample size (n) = 36
t = (5.2 - 5) / (0.6 / sqrt(36))
= 0.2 / (0.6 / 6)
= 0.2 / 0.1
= 2
To find the p-value associated with this test statistic, we need to consult the t-distribution table or use statistical software. Assuming a one-tailed test (since we're testing if the mean is greater than 5 ppm), the p-value is the probability of observing a t-value greater than or equal to 2.
With the calculated test statistic of t = 2 and the associated p-value, we can compare the p-value to a significance level (α) to make a decision. Common significance levels include 0.05 or 0.01.
Suppose we choose a significance level of α = 0.05. If the p-value is less than 0.05, we reject the null hypothesis in favor of the alternative hypothesis. If the p-value is greater than or equal to 0.05, we fail to reject the null hypothesis.
Since the p-value was not provided, please consult a t-distribution table or use statistical software to determine the exact p-value for t = 2. Once you have the p-value, compare it to the chosen significance level (e.g., α = 0.05) to draw a conclusion about whether the data substantiates that the water is unsafe.
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PLEASE HELP ASAP, ITS DUE TONIGHT
Tony is 6 years older than his brother Zack. The sum of their ages is 42. Write an equation for
this situation and use it to determine the age of each brother.(**Define your variable)
Answer:
Zack = x
Tony = x + 6
x + x + 6 = 42
2x + 6 = 42
2x = 36
x = 18
So,
Zack = x = 18
Tony = x + 6 = 18 + 6 = 24
I need help! I don’t know this problem can you figure this out?
Ms. Alonzo was hired to build a scale model of a submarine for a naval history exhibit. She has the
measurements shown in the table.
Submarine
Scale Model
Width: 42 feet
Width: ?
Length: 560 feet
Length: 72 inches
If the model of the submarine will have a length of 72 inches, what will be the width of the model?
A. 1.7 inches
B. 5.4 inches
C. 7.8 inches
D. 13.3 inches
Answer:
13.3
Step-by-step explanation:
What is the solution set of the equation
3X=-6/1-X
for x # 1?
The solution set of the equation 3X=-6/1-X for x # 1 is {-2,1)
3x = -6/(1-x)
3x(1-x) = -6
3x – 3x2 = -6
Taking 3 as common from both sides
x –x2 = -2
x2 – x +2 =0
Using factorisation method we will get two factors
Factoring quadratics is a method of expressing the quadratic equation ax2 + bx + c = 0 as a product of its linear factors as (x - k)(x - h), where h, k are the roots of the quadratic equation ax2 + bx + c = 0. This method is also is called the method of factorization of quadratic equations. Factorization of quadratic equations can be done using different methods such as splitting the middle term, using the quadratic formula, completing the squares, etc.
( x – 2)(x+1)=0
So, x = 2 , -1
Now, when x ≠ 1
The solution of the equation will vary from {-2,1) .
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help help help help
Answer:
abc is a triangle so ,
a is ( 9,6 )
b is ( 9,3 )
and c is ( 3,3 )
simplify 1+4/x / 1-16 x^2
1+4/x x + 4
------------ = -------------
1-16 x^2 x(-4x + 1) (4x + 1)
hope this helps, it probs won't but-
Answer: \(\frac{x+{4} }{x - 16x^{3} }\)
Steps:
\(\frac{1+\frac{4}{x} }{1-16x^{2} }\)\(\frac{\frac{x}{x} +\frac{4}{x} }{(1-4x)(1+4x) }\) (get common denominator (x) for top and factor bottom)\(\frac{x+{4} }{x(1-4x)(1+4x) }\) (add numberator, then move x to denominator)\(\frac{x+{4} }{(x-4x^{2} )(1+4x) }\) (multiply x and (1-4x) )\(\frac{x+{4} }{x+4x^{2} - 4x^{2} - 16x^{3} }\) (FOIL denominator)\(\frac{x+{4} }{x - 16x^{3} }\) (simplify)Sorry about the delay. Hope this helps!
When displaying quantitative data, what is an ogive used to plot? Multiple Choice Frequency or relative frequency of each class against the midpoint of the corresponding class Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class Frequency or relative frequency of each class against the midpoint of the corresponding class and cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class None of the above
An ogive is used to plot cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class when displaying quantitative data. Option B.
An ogive is a graph that represents a cumulative distribution function (CDF) of a frequency distribution. It shows the cumulative relative frequency or cumulative frequency of each class plotted against the upper limit of the corresponding class. In other words, an ogive can be used to represent data through graphs by plotting the upper limit of each class interval on the x-axis and the cumulative frequency or cumulative relative frequency on the y-axis.
An ogive is used to display the distribution of quantitative data, such as weight, height, or time. It is also useful when analyzing data that is not easily represented by a histogram or a frequency polygon, and when we want to determine the percentile or median of a given set of data. Based on the information given above, option B: "Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class" is the correct answer.
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simplifiy the equations and show ur work
The simplest form is (-2 ±√12)/2.
What is simplification?
To simplify simply means to make anything easier. In mathematics, simplifying an equation, fraction, or problem means taking it and making it simpler. Calculations and problem-solving techniques simplify the issue. Simplifying procedures is one way to achieve uniformity in work efforts, expenses, and time. It reduces diversity and variety that is pointless, harmful, or unnecessary.
Here, we have
Given: x = (-4 ±√48)/4
We have to simplify the given term.
x = (-4 ±√48)/4
x = (-4 ±√12×4)/4
x =(-4 ±2√12)/4
Now, we take 2 as common and get
x = (-2 ±√12)/2
Hence, the simplest form is (-2 ±√12)/2.
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the mode of the values?
Answer:
letter D.
Step-by-step explanation:
im not sure but I try it
What is the least number to be multiplied with 'm' to make it perfect cube?
-----------------------------
Solve the following problem using the principle of inclusion and exclusion:
Among a bank’s 250 customers with checking or savings accounts, 168 have
checking accounts, 75 have regular savings accounts, 120 have money market savings accounts,
and 70 have both checking and regular savings accounts. No customer is allowed to have both
regular savings and money market savings accounts.
a) How many customers have both checking and money market savings accounts?
b) How many customers have a checking account but no savings account?
a) To find the number of customers who have both checking and money market savings accounts, we need to use the principle of inclusion and exclusion.
Let A be the set of customers with checking accounts, B be the set of customers with money market savings accounts, and C be the set of customers with both checking and money market savings accounts. Then we have:
|A ∪ B| = |A| + |B| - |A ∩ B|
We know that |A| = 168, |B| = 120, and |A ∩ B| = ? (what we need to find)
We can also use the fact that the total number of customers is 250, so:
|A ∪ B| = 250 - |A' ∩ B'|
where A' and B' are the complements of A and B, respectively. Since no customer is allowed to have both regular savings and money market savings accounts, we know that:
|B ∩ C| = 0
So we can use the principle of inclusion and exclusion again to find:
|A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |B ∩ C| - |C ∩ A| + |A ∩ B ∩ C|
We know that |A ∪ B ∪ C| = 250 and |A|, |B|, and |C| are given. We also know that |B ∩ C| = 0 and we can use the fact that:
|A' ∩ B' ∩ C'| = |(A ∪ B)' ∩ (B ∪ C)' ∩ (C ∪ A)'|
= |(A' ∩ B') ∪ (B' ∩ C') ∪ (C' ∩ A')|
= |A' ∩ B'| + |B' ∩ C'| + |C' ∩ A'| - |A' ∩ B' ∩ C'|
We know that |A' ∩ B'| = |(A ∪ B)'| = 250 - |A ∪ B| and |C' ∩ A'| = |(C ∪ A)'| = 250 - |C ∪ A|. Since we already know |A ∪ B| and |C ∪ A| from the previous calculations, we can find |A' ∩ B' ∩ C'|. Then we can use the principle of inclusion and exclusion to find |A ∩ B|:
|A ∩ B| = |A| + |B| + |C| - |A ∪ B ∪ C| + |A' ∩ B' ∩ C'|
Substituting the given values, we get:
|A ∩ B| = 168 + 120 + 0 - 250 + (250 - 168 - 75 - 120 + |A ∩ B|)
Solving for |A ∩ B|, we get:
|A ∩ B| = 26
Therefore, there are 26 customers who have both checking and money market savings accounts.
b) To find the number of customers who have a checking account but no savings account, we can use the same principle of inclusion and exclusion. Let D be the set of customers with no savings account. Then we have:
|A ∩ D| = |A| - |A ∩ B ∪ A ∩ C|
We know that |A| = 168 and we just found |A ∩ B| = 26. To find |A ∩ C
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A hiker is climbing down a valley. He stops for a water break 4 times. Between each break, he descends 15 meters. How many meters did he descend?
Ju Chan answered the question by writing the following:
4(−15) meters = −60 meters.
Which word in the problem indicates that a negative number should be used?
The word in the problem that indicates that a negative sign should be used is "descend"
How many meters did he descend?We know that he stops for water breaks four times, and between each water break, he descends 15 meters.
The written equation is:
4*(-15)m = -60m
Why the negative sign is used?
The negative sign is used because the hiker is descending, so its height is decreasing. The word in the problem that indicates that a negative sign should be used is "descend"
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If two lines intersect, then the vertical angles formed must be? both equal in measure both acute angles complementary angles
If two lines intersect, then the vertical angles formed must be both equal in measure.
What is intersection of a line?The intersection of a line can be described as when two or more lines cross each other in a plane as a result of this they are been referred to as intersecting lines.
Therefore, intersecting lines share a common point, hence , If two lines intersect, then the vertical angles formed must be both equal in measure.
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The sales tax rate is 7 1/2%. What is the sales tax rate on a 164.00$ purchase?
Answer:
$176.30
Step-by-step explanation:
7 1/2% can be simplified to 7.5%
7.5% of 164.00 is 12.30
12.30+164.00=176.30
$176.30
A and B are whole numbers, and A/11 + B/3 = 31/33. find the value of A and the value of B.
The value of A is 3 and the value of B is 2.
Whole NumbersThey are the numbers represented by positive real numbers where the fractions and decimal numbers are not included.
The question gives:
A and B are whole numbers;\(\frac{A}{11}+\frac{B}{3} =\frac{31}{33}\)Thus, you need to find A and B for these conditions.
When we calculated the Least Common Multiple ( LCM ) between 3 and 11, we can rewrite the equation as:
\(\frac{A}{11}+\frac{B}{3} =\frac{31}{33}\\ \\ \frac{3A+11B}{33}=\frac{31}{33}\)
Thus, we have:
\(3A+11B=31\\ \\ 3A=31-11B\\ \\ A=\frac{31-11B}{3}\) (1)
From this condition, for that A is a whole number, then 31-11B >0.
Then,
\(31-11B > 0\\ \\ -11B > -31\\ \\ 11B < 31\\ \\ B < 2.8\)
In this case, for that B should be a whole number, B can be 0,1 and 2.
Now, you should replace probable numbers for B in equation (1). The value of B will be the number from that you will find the whole number for A. See below.
For B=0, you have \(A=\frac{31-11*0}{3}=\frac{31}{3}=10.33\) . In this case, A is not a whole number. Then, B can't be 0 (zero).
For B=1, you have \(A=\frac{31-11*1}{3}=\frac{31-11}{3}=\frac{20}{3}=6.67\) . In this case, A is not a whole number. Then, B can't be 1 (one).
For B=2, you have \(A=\frac{31-11*2}{3}=\frac{31-22}{3}=\frac{9}{3}=3\) . In this case, A is a whole number (3). Then, B can be 2 (two).
Let's replace this information in the given equation in your question.
\(\frac{A}{11}+\frac{B}{3} =\frac{31}{33}\\ \\ \frac{3}{11}+\frac{2}{3} =\frac{31}{33}\\ \\ \frac{9+22}{33}= \frac{31}{33}\\ \\ \frac{31}{33}=\frac{31}{33}\)
Hence, A=3 and B=2.
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-3x-y=-24
convert to slope intercept form
Answer:
y = - 3x + 24
Step-by-step explanation:
Step 1:
y = mx + b Slope Intercept Form
Step 2:
- 3x - y = - 24 Equation
Step 3:
- 3x = y - 24 Add y on both sides
Step 4:
- 3x + 24 = y Add 24 on both sides
Answer:
y = - 3x + 24
Hope This Helps :)
Mike an experienced bricklayer can build a wall in 5 hours while his son, who is learning can do the job in 20 hours. How long does it take for them to build a wall together.
Answer:
4 hours
Explanation:
Mike can build a wall in 5 hours. His work rate is:
\(\frac{1}{5}\)His son can do the job in 20 hours. The son's work rate is:
\(\frac{1}{20}\)Let the time it takes both of them = x hours. Then, their joint rate is:
\(\frac{1}{x}\)Therefore:
\(\frac{1}{5}+\frac{1}{20}=\frac{1}{x}\)We solve the equation for x:
\(\begin{gathered} \frac{4+1}{20}=\frac{1}{x} \\ \frac{5}{20}=\frac{1}{x} \\ \text{ Cross multiply} \\ 5x=20 \\ \text{ Divide both sides by 5} \\ \frac{5x}{5}=\frac{20}{5} \\ x=4\text{ hours} \end{gathered}\)It takes them 4 hours to build a wall together.
If a rectangle has a height of 5 feet length of 10 feet and the width of 5 feet what is the surface area
HELP please, will give brainliest
As we know that
Diagonal of square = √2 ( side of square )So , we need to find side of square first
Using area of square = Side²
➩ 144 = S²
➩ S = √144
➩ Side = 12 cm
Now ,
➨ Diagonal = √2 ( 12 )
➨ Diagonal of square = 12√2
Select the correct answer.
A baker uses square prisms for her cake boxes. Due to the number of layers in her cakes, she needs the height of each box to be 5.5 inches. In order to have enough space around the cake for icing and decorations, the volume of each box must be 352 cubic inches. The baker found that the equation below can be used to find the side length, x, of the box to fit her cakes.
Which statement best describes the solutions to this equation?
The solutions are -16 and 16 which are both reasonable side lengths.
The solutions are -16 and 16, but only 16 is a reasonable side length.
The solutions are -8 and 8 which are both reasonable side lengths.
The solutions are -8 and 8, but only 8 is a reasonable side length.
The only reasonable side length is x = 8 is "The solutions are -8 and 8, but only 8 is a reasonable side length."
The equation provided and evaluate the solutions in the context of the problem.
The equation mentioned in the problem is not explicitly provided, so we'll proceed with the given information.
Let's assume the side length of the square prism cake box is x.
The volume of a square prism can be calculated using the formula:
Volume = Length × Width × Height
Since the cake box is a square prism, the length and width are the same, so we can write:
Volume = x × x × 5.5
Given that the volume of each box must be 352 cubic inches, we can set up the equation:
x^2 × 5.5 = 352
Now, let's solve this equation to find the possible solutions for x:
x^2 = 352 / 5.5
x^2 ≈ 64
Taking the square root of both sides, we have:
x ≈ ±8
The solutions to the equation are -8 and 8.
Since we are dealing with a physical length, a negative side length doesn't make sense in this context.
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