Answer:
Select all the expressions which have 3 as the greatest common factor of the terms.
b + 3 + 6c
27n + 66p
38 – 9j + 6k
12x + 75y + 21
–32 – 24z
-5x -10 >30 help Hehehehehe.
Answer:
x<-8
Step-by-step explanation:
-5x-10>30
(add 10 to both sides)
-5x-10+10>30+10
-5x>40
\(\frac{-5x}{-1}\)<\(\frac{40}{-1}\)
(dividing through by -1 changes the sign of the inequality from "<" to ">")
5x<-40
(dividing through by 5)
\(\frac{5x}{5}\)<\(\frac{-40}{5\\}\)
x<-8
Write and equation a solve!
Marry had $115 to spend on clothes. She found a pair of shoes fo $55 and then pants for $15 each. how many pairs of pants can she buy?
(1,5), (9,85), (2,10),(6,38),(4,3),(12,107),(7,64), (12,86) ,(7,47), (9,64), (4,27) The line is in the form y=mx+b.y=mx+b. What is the value of m?m? Enter your answer as a number with two decimal places, like this: 3.14
Answer:
y=10x-5
Step-by-step explanation:
should be the right answer since I used a calculator :p
plz help me solve
The locus of a point which moves in a plane such that it is equidistant from
two fixed points X and Y is
A. the perpendicular bisector of the line segment X Y
B. a line parallel to the line segment XY C. a circle with XY as diameter
D. the line perpendicular to the lin
Answer:
A. the perpendicular bisector of the line segment XY
Step-by-step explanation:
You know that one point equidistant from X and Y is the midpoint of segment XY. The third vertex of an isosceles triangle with XY as its base will also be equidistant from X and Y. That vertex will be located on the perpendicular bisector of XY.
The locus of points of interest is the perpendicular bisector of XY.
_____
For many geometry problems, it can be helpful to draw a diagram.
A 6.5-foot ladder is leaning against the side of a house. If the ladder is resting 6 feet off
the ground, how far is the ladder from the house?
O A. 7.5 feet
OB. 5 feet
C.
2.5 feet
D. 1 foot
Answer: C. 2.5 ft
Step-by-step explanation:
Use the Pythagorean Theorem a² + b² = c² where c is the hypotenuse.
In the given problem, the height = 6 and the hypotenuse = 6.5
6² + b² = 6.5²
36 + b² = 42.25
b² = 6.25
b = 2.5
The base (distance from the house) is 2.5 feet
A candy store uses 10. 3 grams of sugar each hour. How many grams of sugar will the store use in 10 hours?
The candy store will use 103 grams of sugar in 10 hours.
To find out how many grams of sugar the store will use in 10 hours, we can simply multiply the amount of sugar used in one hour (10.3 grams) by the number of hours (10).
To solve the problem, we use a simple multiplication formula: the amount used per hour (10.3 grams) multiplied by the number of hours (10) to find the total amount of sugar used in 10 hours.
We can interpret this problem using a rate equation: the rate of sugar usage is 10.3 grams/hour, and the time period is 10 hours. Multiplying the rate by the time gives the total amount of sugar used.
So the calculation would be:
10.3 grams/hour x 10 hours = 103 grams
Therefore, the candy store will use 103 grams of sugar in 10 hours.
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please help I would really Appreciate it so much
Answer:
I think it is b
Step-by-step explanation:
it is 3a times all of the numbers in parenthases
hope you pass your test
HAPPY NEW YEAR
Answer:
the answer is 15a+12ac+6ab
Step-by-step explanation:
3a(5+4c+2b)
(3a)(5+4c+2b)
(3a)(5)+(3a)(4c)+(3a)(2b)
15a+12ac+6ab
6ab+12ac+15a
hope this helps!
The payment to a clown for a children's party is directly proportional to the number of
children under 12 at the birthday party. The clown earns $140 at a party that has 10 children attending,
.
How much will the clown earn when 22 children under the age of 12 attend?
If the clown uses 46% of the money earned on his props for the party, and the rest is
profit. What is the profit if only 10 children under the age of 12 attend the party?
Answer:
Step-by-step explanation:
We know he earns $14 per child under 12
So he'll earn 22 times 14 which is $308 earned.
46% of 308 is basically 0.46 X 308=$141.68 spent on props.
He profits $166.32
If only 10 children attend.
He earns 10 times 14= $140
46% of these earnings is for props and 54% is profit so
0.54 X 140=$75.60.
Thus he profits $75.60 if 10 children attended.
The profit will amount to $75.60 when only 10 children under the age of 12 attend the party.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
We are aware that he receives $14 for each child under the age of 12.
Thus, he will make $308 after multiplying 22 by 14.
In other words, 46% of 308 is 0.46 × 308 or $141.68 spent on props.
He earns $166.32.
If just 10 kids show up.
He makes $10 multiplied by 14 for a total of $140.
Props account for 46% of these revenues, while profits make up 54%, therefore
0.54 × 140=$75.60.
So, if 10 kids showed up, he makes $75.60.
Thus, the profit will amount to $75.60 when only 10 children under the age of 12 attend the party.
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The two cones below are similar. What is the height of the larger cone?
Answer: B 35/4
Step-by-step explanation:
What is the volume of this sphere?
Use a 3.14 and round your answer to the nearest hundredth.
9 cm
cubic centimeters
Answer:
3052.08
Step-by-step explanation:
We use the volume formula for spheres
\(\frac{4}{3}\)πr³
Plug in 9cm for radius and evaluate
\(\frac{4}{3}\)π(9)³
\(\frac{4}{3}\)π*729
3052.08
Mrs. Hanger is painting the following picture of an H to hang in the entryway of her home. She has made the following scale drawing as her model. The scale used on the drawing is 1:6.
As you can see, the "H" is going to be painted brick red in the center of a rectangular beige background. This means the distance from the "H" to the top of the picture will be the same as the distance from the "H" to the bottom of the picture. Similarly, the distance from the "H" to the left side of the picture will be the same as the distance from the "H" to the right side of the picture. Finally, each segment of the "H" will have the same width.
Mrs. Hanger decides to change the scale of her drawing from 1:6 to 1:4.
Is the new scale drawing larger or smaller than the original scale drawing? Use complete sentences to explain your reasoning.
What are the dimensions of the painting on the new scale drawing?
The percentage of the rectangle that will be beige is 15.5 percent
What is a rectangle?
A rectangle is a quadrilateral having the four sides and the sum of the angles is 180 in the rectangle the opposite two sides are equal and parallel and the two sides are at 90-degree angles.
The width of the "H" is 1/2 the distance form the top to the bottom of the "H" is 1/2
1/2 + 1/2 =
the side length of the "H" is 4
4 x 1/2 = 2
The demensions of the other 1/2 by 4 are the same, therefore,
2 + 2 = 4
The middle section is 1 by 1/2
1 x 1/2 = 1/2
The equation is 2 + 1/2 = 2 1/2
and converted to decimal form it is 4.5
The rectangle is 4 by 5
So 4 x 5 = 20
20 - 4.5 = 15.5 percent
Hence the percentage of the rectangle that will be beige is 15.5 percent.
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what is the equation of the line in slope intercept form that passes through the points (1,7) and (2,11)
Answer:
slope = y^2 - y^1 / x^2 - x^1 = 4
your slope would be 4
Step-by-step explanation:
You are on a ship and you notice that it took exactly 10 hours to sail from exactly 10 degrees north latitude to exactly 12 degrees north latitude. What was your ship's speed during that time
The ship's speed during that time was approximately 22.2 kilometers per hour.
We have,
To calculate the ship's speed, we need to determine the distance traveled between 10 degrees north latitude and 12 degrees north latitude, and then divide it by the time taken.
The distance between two degrees of latitude is approximately 111 kilometers (or 69 miles).
Since the ship traveled from 10 degrees north latitude to 12 degrees north latitude, it covered a distance of:
Distance = (12 - 10) x 111 kilometers
Distance = 2 x 111 kilometers
Distance = 222 kilometers
Given that it took 10 hours to cover this distance, we can calculate the ship's speed as:
Speed = Distance / Time
Speed = 222 kilometers / 10 hours
Speed = 22.2 kilometers per hour
Therefore,
The ship's speed during that time was approximately 22.2 kilometers per hour.
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There is a line through the origin that divides the region bounded by the parabola y=5x−3x^2 and the x-axis into two regions with equal area. What is the slope of that line?
The slope of the line that divides the region bounded by the parabola \(y=5x-3x^2\)and the x-axis into two regions with equal area is 5.
To find the slope of the line that divides the region into two equal areas, we need to determine the point of intersection between the parabola and the x-axis. Since the line passes through the origin, its equation will be y = mx, where m represents the slope.
Setting the equation of the parabola equal to zero, we find the x-values where the parabola intersects the x-axis. By solving the equation\(5x - 3x^2 = 0\), we get x = 0 and x = 5/3.
To divide the region into two equal areas, the line must pass through the midpoint between these x-values, which is x = 5/6. Plugging this value into the equation of the line, we have y = (5/6)m.
Since the areas on both sides of the line need to be equal, we can set up an equation using definite integrals. By integrating the equation of the parabola from 0 to 5/6 and setting it equal to the integral of the line from 0 to 5/6, we can solve for m. After performing the integration, we find that m = 5.
Therefore, the slope of the line that divides the region into two equal areas is 5.
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Mehmer has a stillity function (x,y) = 2x² + y Answer the following questions. Consider that the price of x is 100 TL, the price of y is 25 TL and monthly income is "M" TL Mehmet uses all of his income each month to purchase x and y. Solve the constraint optimization problem and find the expressions for x'.y' and 2". Confirm the second order condition for part (a) using bordered Hessian Matrix. Deive the value function. Suppose his income increased by one unit. How does the optimal value of u(x, y) i Answer by using the value function. Answer by using Envelope Theorem. (e) Suppose the price of y increased by one unit. How does the optimal value of u(x, y) change? Answer by using Envelope Theorem. (Hint: replace 25 with p, and proceed)
The constraint optimization problem can be solved by determining the expressions for x' and y' and confirming the second-order condition using the bordered Hessian Matrix. The value function and the Envelope Theorem can be used to analyze the effects of changes in income and prices on the optimal value of u(x, y).
To find the expressions for x' and y', we set up the Lagrangian function:
\(L(x, y, \lambda) = 2x^2 + y - \lambda (p_x * x + p_y * y - M)\)
Taking partial derivatives with respect to x, y, and λ, we get:
\(\partial L/\partial x = 4x - \lambda p_x = 0\\\partial L/\partial y = 1 - \lambda p_y = 0\\p_x * x + p_y * y = M\)
Solving these equations simultaneously, we find the optimal values of x and y. Differentiating the first-order conditions, we obtain the second derivative expressions, denoted as 2". The bordered Hessian matrix can be used to confirm the second-order condition for part (a).
To derive the value function, we substitute the optimal values of x and y into the utility function: u(x, y) = 2(x')² + y'.
Suppose the income increases by one unit. We can determine the effect on the optimal value of u(x, y) by using the value function and considering the change in the optimal values of x and y.
Applying the Envelope Theorem, we can evaluate the change in the optimal value of u(x, y) by taking the derivative of the value function with respect to income, while keeping the prices constant.
Similarly, if the price of y increases by one unit, we can analyze the impact on the optimal value of u(x, y) using the Envelope Theorem and considering the change in the optimal values of x and y, with the price of y denoted as p.
These steps will help us understand the changes in the optimal values of u(x, y) under different scenarios based on the given utility function, prices, and income.
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value of 8 , and using the foliowing equations for the equibbrium enern. r0=(n0A)t1,E0=−v01+n1n Comaute the values of A and B in these equations. A. A=3.332cV. นm, B=2.335×10−4eV.nm∗ B. A=2.332eV, num, B=3.335×10−4eV⋅nm∗ C. A=2.332eV⋅nm,B=3.335×103eV⋅nm3 D. A=0.332eV rm, B=3.335×10−1eV. rim* E.
The values of A and B in the given equations of Equilibrium energy and calculations. are A = 2.332 eV·nm and B = 3.335 × 10^−4 eV·nm.
How do we compute the values of A and B?To compute the values of A and B, we need to use the given equations and the given value of 8.
Equation 1: r0 = (n0A)t1
Equation 2: E0 = -v01 + (n1n)
First, let's consider Equation 1. We are given r0 = 8 and we need to find the value of A. Rearranging the equation, we have:
8 = (n0A)t1
To find A, we need to know the values of n0 and t1. However, these values are not provided in the question. Therefore, we cannot determine the exact value of A.
Moving on to Equation 2, we are given E0 = -v01 + (n1n) and we need to find the value of B. Rearranging the equation, we have:
B = (-v01 + E0) / (n1n)
Again, we need the values of v01, E0, n1, and n to compute B. Unfortunately, these values are not given in the question, so we cannot determine the exact value of B either.
Therefore, none of the given options (A, B, C, D, E) accurately represent the values of A and B.
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Easy geometry question please help
Answer:
Y-8
Step-by-step explanation:
Any point on the upper triangle ABC, for example point B, is translated 8 units down the y axis, appearing on the lower triangle A'B'C'
Find the next positive coterminal
angle to 147º
Answer:
5 + 5 = 10
Step-by-step explanation: ok
wich of the following numbers are greater than -185/100 -1.08190/100-35/20
-185/100 = -1.85
a) -1.08 this number id greater than -1.85
b) 190/100 = 1.9 this number is greater than -1.85
c) -35/20 = -1.75 this number is greater than -1.85
All these numbers are greater than -185/100
please help! i will give brainliest if you answer all and correctly
Answer: a is 21 b is 45 and c is yes more people are going above because the median is above the speed limit
Step-by-step explanation:
The sides of the triangle shown increase in such a way that dz/dt=1, and dx/dt=3 dy/dt At the instant when x = 12 and y= 5, what is the value of dx/dt?
The value of is dx/dt = 0.95, when x = 12 and y =5.
What is Pythagoras theorem?Pythagoras' Theorem states that the square of the hypotenuse side in a right-angled triangle is equal to the sum of the squares of the other two sides. The Perpendicular, Base, and Hypotenuse are the names of the three sides of this triangle.
Given:
dz/dt = 1,
dx/dt = 3(dy/dt)
So, dy/dt = 1/3 (dx/dt)
According to the Pythagoras theorem -
z² = x² + y²
Differentiating both sides we get
d/dt (z²) = d/dt (x² + y²)
2z dz/dt = 2x dx/dt + 2y dy/dt
z dz/dt = x dx/dt + y dy/dt
Substituting the value of dy/dt -
z dz/dt = x dx/dt + y/3 (dx/dt)
z dz/dt = dx/dt (x + y/3)
dx/dt = (z dz/dt)/(x + y/3).....(1)
So, when x = 12 and y = 5, the value of z -
z = √[(12)² + (5)²]
z = √(144+25)
z = √169
z = 13
Substituting the value of x, y, z and dz/dt in equation (1), we get
dx/dt = (13 × 1)/(12 + 5/3)
dx/dt = 13 / 41/3
dx/dt = (13 × 3)/41
dx/dt = 39/41
Hence, the value of dx/dt = 0.95.
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how do i solve this trigonometry question?
Answer:
2.07 cm
Step-by-step explanation:
Hypotenuse = 2 cm
Adjacent side = a
Formula
cos θ = Hypotenuse/Adjacent side
cos 15 = 2/a
Note
The value of cos 15 is approximately 0.965.
0.965 = 2/a
a = 2/0.965
a = 2.07 cm ( approximately )
PLEASE HELP ASAP - ILL GIVE BRAINIEST
Answer:
We know that:
A = lwFactorize the expression for the area and find the missing side
< 10 >Given:
A = x² + 10x + 21w = x + 3Find l:
l = A/w
l = (x² + 10x + 21)/(x + 3) =
(x + 3)(x + 7)/(x + 3 =
x + 7
------------------------------
< 11 >Given:
A = x² + 2x - 8l = x + 4Find w:
w = A/l
w = (x² + 2x - 8)/(x + 4) =
(x + 4)(x - 2)/(x + 4) =
x - 2
Simplify 10√3x +4√3x +5√3x
Add the like terms :
10√3x + 4√3x + 5√3x(10 + 4 + 5)√3x19√3xcalculate the surface area and then the volume
Answer:
46
Step-by-step explanation:
length x width x height
7 x 5 x 3
Answer: surface area = 142
Volume = 105
* make sure to add labels (units^2, etc.)
Step-by-step explanation:
Area = length x height
Volume = length x width x height
If 1 litre = 1000ml, then 2/10 a litre = ____.
Answer:
→100ml.
Step-by-step explanation:
If 1 litre = 1000ml, then
\(\small\sf{\quad\dfrac{2}{10} \: of \: 500 \: ml}\)
\(: \implies\small\sf{\dfrac{2}{10} \: of \: 500 \: ml}\)
\(: \implies\small\sf{\dfrac{2}{10} \times 500 \: ml}\)
\(: \implies\small\sf{\dfrac{2 \times 500 \: ml}{10}}\)
\(: \implies\small\sf{\dfrac{1000 \: ml}{10}}\)
\(: \implies\small\sf{\cancel{\dfrac{1000 \: ml}{10}}}\)
\(: \implies\small{\sf{100 \:ml}}\)
∴ The answer is 100 ml.
Which of the following statements about degrees of freedom is TRUE? a) It always equals N - 2. b) It is the number of scores in a sample that are free to vary. c) It is used in effect size calculations. d) It increases the bias inherent in a statistical estimate.
The statement that is true about degrees of freedom is b) it is the number of scores in a sample that are free to vary.
Degrees of freedom (df) refers to the number of values in a calculation that are free to vary without changing the result. In statistics, degrees of freedom are used in various calculations, such as t-tests, ANOVA, and regression. The concept of degrees of freedom is important because it affects the accuracy and precision of statistical estimates.
The formula for degrees of freedom varies depending on the specific calculation being performed. For example, in a t-test, the degrees of freedom is calculated as n - 1, where n is the sample size. This means that in a sample of n scores, only n - 1 scores are free to vary because the sample mean is fixed. In ANOVA, degrees of freedom are calculated differently depending on the number of groups and the sample sizes within each group.
Degrees of freedom are not always equal to N - 2, as stated in option a. Option c is partially correct as degrees of freedom are used in some effect size calculations, but it is not the primary purpose of degrees of freedom. Option d is incorrect as degrees of freedom do not increase bias; in fact, they can help reduce bias by providing a more accurate estimate of variability.
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URGENT!!!!!!
Dan's car depreciates at a rate of 17% per year.
By what percentage has Dan's car depreciated after 4 years?
Give your answer to the nearest percent.
Answer:
an=yearn−year−0.17n+0.34
Step-by-step explanation:
Answer:
68%
Step-by-step explanation:
17% × 4
68%
solve the given initial value problem for y = f(x). dy 37. = (3 – 2x)2 where y = 0 when x = 0 dx
The solution to the initial value problem is y = -3 / \((3x-x^{2} )^{3}\) , where y = 0 when x = 0.
We can solve this initial value problem using separation of variables. First, we write the differential equation as:
dy/dx = \((3-2x)^{2}\)
Next, we separate the variables by moving all the y terms to one side and all the x terms to the other side:
1/\(y^{2}\) dy = \((3-2x)^{2}\) dx
We integrate both sides with respect to their respective variables:
∫1/\(y^{2}\) dy = ∫ \((3-2x)^{2}\) dx
Applying the power rule of integration on the left-hand side and simplifying the right-hand side by expanding the square, we get:
-1/y = \((3x-x^{2} )^{3}\) /3 + C
where C is the constant of integration. We can solve for C using the initial condition y(0) = 0:
-1/0 = \((3(0)-0^{2} )^{3}\)/3 + C
C = 0
Therefore, the solution to the initial value problem is:
-1/y = \((3x-x^{2} )^{3}\)/3
Multiplying both sides by -1 and taking the reciprocal, we get:
y = -3/ \((3x-x^{2} )^{3}\)
Correct Question :
Solve the given initial value problem for y = f(x). dy/dx = \((3-2x)^{2}\) where y = 0 when x = 0.
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Hello! When using compelting the square, arent you just technically putting the standard form equation you have into vertex form?
Answer:
Hello! Yes, when completing the square, you are essentially transforming a quadratic equation from standard form to vertex form. The vertex form of a quadratic equation is given by:
y = a(x - h)^2 + k
where (h, k) represents the vertex of the parabola and 'a' is a constant that determines the shape and direction of the parabola.
To convert a quadratic equation from standard form (ax^2 + bx + c) to vertex form, we follow these steps:
1. Divide both sides of the equation by 'a' to make the coefficient of x^2 equal to 1.
2. Move the constant term (c/a) to the right-hand side of the equation.
3. Complete the square by adding and subtracting (b/2a)^2 on the left-hand side of the equation.
4. Factor the left-hand side of the equation as a perfect square trinomial.
5. Write the equation in vertex form by identifying the values of 'a', 'h', and 'k'.