Select the correct answer from each drop-down menu. Choose the correct words.To complete the statements about career planning. Throughout your job search, you'll find that is closely related to the career of your choosing. It's important to take the time to find out what to expect now, so you can start developing the you need to excel in that career. Reset Next

During troubleshooting a network incident, the first step is to identify the problem.

Go to Settings > Network & Internet > Status by clicking the Start button. Choose Network troubleshooter from the list under Modify your network settings. By according to the troubleshooter's recommendations, see if the problem has been fixed.

The following are the steps in the troubleshooting process:

To know more about Troubleshooting a Network visit:

https://brainly.com/question/14102193

#SPJ4

Answer:

A

Explanation:

All cars have rear steering to a percent it is very little and hard to notice but they turn slightly.

Cars can't rely on rear steering, it's to hard to engineer the rear diff.

Answer:

transmission bandwidth required is very large.

Explanation:

Answer: border-radius

Explanation:

In a 5G Non-Standalone (NSA) network architecture, which combines both 4G and 5G technologies, the 4G and 5G parts of a 5G NSA bearer can be handed over independently from each other. This capability is achieved through the concept of dual connectivity, which allows devices to simultaneously connect to both 4G and 5G networks.

The independence of handover between the 4G and 5G parts is enabled by the network's ability to handle dual connectivity. When a device is connected to both 4G and 5G networks, it can maintain an active bearer on each network simultaneously. During a handover process, the device can transition its connection from one network to another without interrupting the ongoing data transmission.

This independent handover is made possible by the coordination between the 4G and 5G radio access networks (RANs) and the core network. The network architecture allows the 4G part of the bearer to be handed over to a different 4G base station or cell, while the 5G part can be handed over to a different 5G base station or cell. This enables seamless and efficient handover between the two technologies, ensuring continuous connectivity and improved user experience.

By allowing independent handover, 5G NSA networks provide flexibility and optimization in terms of network resources and coverage. It allows operators to leverage both 4G and 5G networks efficiently, maximizing the benefits of 5G technology while maintaining compatibility with existing 4G infrastructure.

Learn more about radio access networks here:

https://brainly.com/question/29807528

#SPJ11

Answer:

If you are driving below 40 mph, you should leave at least one second for every 10 feet of vehicle length.

Answer:

i) Heat rejection =  1.0288 KJ

  Network production = 1.212 kJ

ii) Thermal efficiency = 54.08%

   mean effective pressure = 353.5 kPa

Explanation:

Given data :

Compression ratio ( r )  = 7

P1 ( initial pressure ) = 90 kPa,

T1 ( initial temperature ) = 27°C + 273 = 300 K

V1 = 0.004 m^3

Max cycle Temperature = 1127°C for each repetition of the cycle

i) Determine the heat rejection and net work production

considering that process 1-2 is an Isentropic compression

Find ; T2 = T1 ( r )^1.4-1

      T2 = 300 ( 7 )^0.4  = 653.371 K

    P2 = P1( r )^k

          = 90 ( 7 )^1.4  = 1372.081 kPa

considering that process 3-4 is an Isentropic expansion

T4 = T3 / r^k-1

    = 1400 / 7^(1.4 -1 ) = 642.82 K

Next ; Calculate the value of m

m = P1V1 / RT1   = 90(0.004) / 0.287 ( 300 )

                      m = 4.18 * 10^-3 kg

Finally :

amount of heat rejected = mCv ( T4 - T1 )

                                          = 4.18 * 10^-3 ( 0.718 ) ( 642.82 - 300 )

                                    Qout  = 1.0288 KJ

amount of heat added ( Qin ) =  mCv ( T3 - T2 )

                                                = 4.18 * 10^-3 ( 0.718 ) ( 1400 - 653.371 )

                   hence           Qin  = 2.2408 kJ

Network production( Wnet) = Qin - Qout

                                  = 2.2408 - 1.0288 ) KJ

                                  = 1.212 kJ

ii) Determine the thermal efficiency and mean effective pressure of the cycle

Thermal efficiency = 1 - Qout / Qin

                               = 1 - ( 1.0288 / 2.2408 )  = 54.08%

mean effective pressure = Wnet / V1 ( 1 - 1/r )

                                         = 1.212 / 0.004 ( 1 - 1/7 )

                                         = 353.5 kPa

a) The rating of the transformer bank (KVA) to supply the given loads can be calculated using the formula given below:

KVA = (V x I x √3) / 1000

Where, V is the voltage

I is the current√3 is the square root of 3

For load 1, P = 100 kVA and p.f. = 0.85 lagging.

S = P / p.f.

= 100 / 0.85

= 117.65

KVAI = S / V

= 117650 / 2400

= 49.02 A

For load 2, P = 80 kW and p.f. = 0.9 leading.

S = P / p.f.

= 80 / 0.9

= 88.88

KVAI = S / V

= 88.88 x 1000 / (2400 x √3)

= 24.87 A

Therefore, the total current drawn from the transformer bank is

I1 + I2 = 49.02 + 24.87

= 73.89 A

So, the rating of the transformer bank

= (2400 x 73.89 x √3) / 1000

= 119.63 KVA

b) The voltage and current of the sending end of the transmission line can be calculated as follows:

Zeq = ZTL + (Z1 + Z2) / 3

= j2 + [(0.6 + j0) + (0.15 + jXX)] / 3

= j2 + (0.75 + jXX/3)Ohm

∴ Zeq = √(2^2 + (0.75 + jXX/3)^2)

= 2.03 ∠20.47⁰ Ohm

Zeq I = Vp - I

Zeq⇒ I = Vp / (Zeq + Zeq )

= 2400 / [2 x (2.03 ∠20.47⁰)]

= 588.69 ∠-20.47⁰ A

Therefore, the voltage and current of the sending end of the transmission line are 2400 V and 588.69 ∠-20.47⁰ A, respectively.

c) The power factor at the sending end of the transmission line can be calculated using the formula given below:

p.f. = cos φ

= P / (V x I)

= (100000 + 80000) / (2400 x 588.69 x 0.94)

= 0.9841

d) We know that,

p.f. = cos φ

= P / (V x I)

⇒ P = V x I x cos φ

So, the apparent power drawn by the load is given by:

S = V x I

= 2400 x 588.69

= 1413254.22 VA

The real power drawn by the load is given by:

P = S x p.f.

= 1413254.22 x 0.94

= 1327329.68 W

Now, the real power that needs to be drawn by the load to improve the power factor to 0.95 lagging can be calculated as follows:

Q = P x tan (cos⁻¹ 0.95 - cos⁻¹ 0.94)

= 1327329.68 x tan (18.19⁰)

= 46277.21 VAR

KVAR rating of the three-phase capacitive load to be connected to the secondary side of the transformer to improve the p.f. to 0.95 lagging = 46277.21 / 3

= 15425.74 VAR

To know more about capacitive visit:

https://brainly.com/question/31871398

#SPJ11

Without specific information or equations, the values of Ib and Z cannot be determined.

The given question asks to find the value of Ib and Z. However, without specific information or equations provided, it is not possible to determine the values or the context in which they are being calculated.

To find Ib, we would need additional information such as the equation or circuit involved. Similarly, to find Z, we would need information about the specific problem or system in which Z is relevant.

Without such details, it is not possible to provide an explanation or solve the problem.

Learn more about Ib

brainly.com/question/12145534

#SPJ11

The set of all functions x (t) = a1 sin wt + a2 coswt is a vector space.

Vector space is a mathematical concept that describes a set of vectors in which operations such as vector addition, scalar multiplication, and vector scalar multiplication can be performed. Vector spaces are usually equipped with an inner product, which allows for the definition of the length of a vector and the angle between two vectors. Vector spaces are commonly used to model problems in linear algebra, geometry, and engineering. Examples of vector spaces include Euclidean and affine spaces, as well as Hilbert and Banach spaces. Vector spaces are typically associated with a field, such as the real numbers or complex numbers, which allows for the definition of a vector space over the field.

A vector space is a set of elements that is closed under addition and scalar multiplication. This means that if two elements in the set, x1 (t) and x2 (t), are added together and the result is also in the set, and if any element in the set is multiplied by a scalar and the result is also in the set.

In this mass-spring system, we have a set of functions x (t) = a1 sin wt + a2 coswt.
We can see that the set is closed under addition because if we add two functions x1 (t) = a1 sin wt + a2 coswt and x2 (t) = b1 sin wt + b2 coswt, we get x3 (t) = (a1+b1) sin wt + (a2+b2) coswt which is also an element of the set. We can also see that the set is closed under scalar multiplication because if we multiply any function x (t) = a1 sin wt + a2 coswt by a scalar c, we get c x (t) = ca1 sin wt + ca2 coswt which is also an element of the set.

Therefore, the set of all functions x (t) = a1 sin wt + a2 coswt is a vector space.

To learn more about vector space
https://brainly.com/question/29757201
#SPJ4

According to the HST data, very distant (and early) galaxies tend to be smaller, bluer, and more irregular than modern ones.

The Hubble Space Telescope (HST) has allowed astronomers to observe galaxies at great distances and thus look back in time to see what galaxies were like in the early universe. The observations show that distant galaxies tend to be smaller, bluer, and more irregular than modern galaxies. This is because galaxies have evolved over time, with smaller galaxies merging to form larger ones and the formation of new stars slowing down over time. The blue color of distant galaxies is due to the fact that they are forming new stars at a much higher rate than modern galaxies. The irregular shape of distant galaxies is due to the fact that they have not yet formed into the well-defined spiral and elliptical shapes that are more common in modern galaxies.

Learn more about Hubble Space Telescope here:

brainly.com/question/30246219

#SPJ11

Answer:

Explanation:

Given that:

diameter = 100 mm

initial temperature = 500 ° C

Conventional coefficient = 500 W/m^2 K

length  = 1 m

We obtain the following data from the tables A-1;

For the stainless steel of the rod \(\overline T = 548 \ K\)

\(\rho = 7900 \ kg/m^3\)

\(K = 19.0 \ W/mk \\ \\ C_p = 545 \ J/kg.K\)

\(\alpha = 4.40 \times 10^{-6} \ m^2/s \\ \\ B_i = \dfrac{h(\rho/4)}{K} \\ \\ =0.657\)

Here, we can't apply the lumped capacitance method, since Bi > 0.1

\(\theta_o = \dfrac{T_o-T_{\infty}}{T_i -T_\infty}} \\ \\ \theta_o = \dfrac{50-30}{500 -30}} \\ \\ \theta_o = 0.0426\\\)

\(0.0426 = c_1 \ exp (- E^2_1 F_o_)\\ \\ \\ 0.0426 = 1.1382 \ exp (-10.9287)^2 \ f_o \\ \\ = f_o = \dfrac{In(0.0374)}{0.863} \\ \\ f_o = 3.81\)

\(t_f = \dfrac{f_o r^2}{\alpha} \\ \\ t_f = \dfrac{3.81 \times (0.05)^2}{4.40 \times 10^{-6}} \\ \\ t_f= 2162.5 \\ \\ t_f = 36 mins\)

However, on a single rod, the energy extracted is:

\(\theta = pcv (T_i - T_{\infty} )(1 - \dfrac{2 \theta}{c} J_1 (\zeta) ) \\ \\ = 7900 \\times 546 \times 0.007854 \times (500 -300) (1 - \dfrac{2 \times 0.0426}{1.3643}) \\ \\ \theta = 1.54 \times 10^7 \ J\)

Hence, for centerline temperature at 50 °C;

The surface temperature is:

\(T(r_o,t) = T_{\infty} +(T_1 -T_{\infty}) \theta_o \ J_o(\zeta_1) \\ \\ = 30 + (500-30) \times 0.0426 \times 0.5386 \\ \\ \mathbf{T(r_o,t) = 41.69 ^0 \ C}\)

The only statement that can be checked as true based on the given information is: gamma = 45 degrees which is the first option as if the projection angle is found to be 45 degrees, then gamma (γ) would also be 45 degrees.

Gamma = 45 degrees: The statement says that if the projection angle is found to be 45 degrees, then gamma (γ) would also be 45 degrees. In geometry, gamma represents one of the angles in a triangle. If the projection angle is 45 degrees, it implies that one of the angles in the triangle is also 45 degrees, which is represented by gamma.

Learn more about gamma angle here

https://brainly.com/question/32196087

#SPJ1

Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.

The grade of 12.9 bolt is known to be 1220 (176,000 psi). The alloy carbon steel is said to be one that is often used to make Metric 12.9 Hex Cap Screws that is heat-treated, quenched, as well as tempered.

Their strength is one that is comparable to alloy sockets, and with a proof load of 970 MPa and a minimum tensile strength of 1220 MPa.

Therefore, Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.

Learn more about bolt grade from

https://brainly.com/question/28629241
#SPJ1

See full question below

Tech A says that a standard grade 5 bolt is stronger than a standard grade 8 bolt. Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. Who is correct?

a. Tech A

b. Tech B

c. both

d. neither

Answer:

Cómo forzar a Steam a reconocer los juegos instalados.

1) Vuelva a instalar los juegos sin descargar.

2) Agregue la carpeta Steam Library manualmente.

3) Reconocer juegos de una nueva unidad

4) Utilizar .acf Cache para forzar el reconocimiento de juegos de Steam .acf Cache para forzar el reconocimiento de juegos de Steam.

Explanation:

1) Vuelva a instalar los juegos sin descargar.

- Inicia Steam y ve a Juegos.

- Seleccione y haga clic en instalar para el juego que Steam no pudo reconocer.

- Steam comenzará a descubrir los archivos existentes para el juego.

2) Agregue la carpeta Steam Library manualmente.

- Lanzar Steam.

- Haga clic en Steam y seleccione Configuración.

- Haz clic en la pestaña Descargas.

- Haga clic en las carpetas de la biblioteca de Steam.

- En la ventana emergente, haz clic en Agregar carpeta de biblioteca y selecciona la ubicación donde se guardan todos los datos de tu juego Steam.

- Haga clic en Seleccionar y cerrar la configuración de Steam.

- Salga de la aplicación Steam y reinicie Steam.

- Steam ahora debería reconocer los juegos instalados nuevamente y enumerarlos en la carpeta de juegos.

3) Reconocer juegos de una nueva unidad

- Inicie la aplicación Steam desde el escritorio.

- Haz clic en Steam y selecciona Configuración.

- Haz clic en la pestaña Descargas.

- Haga clic en la carpeta de la biblioteca de Steam en la sección Bibliotecas de contenido.

- Haga clic en Agregar carpeta de biblioteca y navegue a la ubicación donde se mueven sus juegos (nuevo directorio) que es D: / games / your_subdirectory.

- Haga clic en Seleccionar y cerrar para guardar la carpeta de la biblioteca.

- Salga de Steam y reinícielo.

Steam escaneará la carpeta Biblioteca recientemente seleccionada y mostrará todos los juegos instalados.

4) Utilizar .acf Cache para forzar el reconocimiento de juegos de Steam .acf Cache para forzar el reconocimiento de juegos de Steam.

- Asegúrese de haber reinstalado Steam o tener la instalación existente.

- Mueva los datos del juego a C: >> Archivos de programa (x86) >> Steam >> carpeta Steamapps.

- Lanzar Steam.

- En este punto, Steam puede mostrar algunos juegos que están instalados correctamente.

- Para los juegos que se muestran como no instalados, seleccione y haga clic en el botón Instalar.

- Steam comenzará a descubrir todos los archivos existentes.

- Sin embargo, si Steam no reconoce los archivos existentes, comenzará a descargar los archivos y el progreso leerá 0%.

- Pausa la actualización de los juegos y sal de Steam. Vaya a C: >> Archivos de programa (x86) >> Steam >> Steamapps y encuentre todos los archivos .acf actuales.

¡¡¡Espero que esto ayude!!!

True. Carbide tools come in a variety of grades, which are based on carbide wear resistance and toughness.

Cemented carbides are of great importance in the manufacturing industry, and have long been used in applications such as cutting, grinding, and drilling. Cemented carbide is a class of composite materials, which comprises of hard and wear-resistant carbide, a tough and ductile metal binder, and owns a unique combination of hardness and toughness. Nano, Ultrafine, and Submicron grades of carbide are what is usually used for end mills. They have a binder in the range of 3-12% by weight. Sizes measures below 1μm having the highest hardness and compressive strengths, combined with high wear resistance and high reliability against breakage.

Learn more about carbide here: https://brainly.com/question/4499981

#SPJ11

The three types of irony are Verbal Irony, Situational Irony, and Dramatic Irony.

Example of Verbal Irony:

Example of Situational Irony:

Example of Dramatic Irony:

What is Irony?

When something unexpected occurs, it is ironic. The thing opposite to what we anticipate usually occurs, and this is either humorous or dramatic.

To learn more about Irony:

https://brainly.com/question/24267033

#SPJ4

The tool that has a revolving vertical shaft and a cutter is a router. The correct option is b.

There are many different kinds of power tools, including portable power tools like a circular saw, heat guns, and wall chasers as well as electrical power tools like impact wrenches, lathes, power drills, power ratchet sets, and power saws.

Power tools including circular saws, jigsaws, drills, hammer drills, sanders, grinders, routers, and many others reduce labor and time requirements. The requirement for knowledge of the risks that power tools provide if used improperly is raised due to their rising use.

A power tool called a router has a flat base and a spinning blade that protrudes beyond the base. An electric motor or a pneumatic motor can drive the spindle.

Therefore, the correct option is b) router.

To learn more about power tools, refer to the link:

https://brainly.com/question/30115428

#SPJ6

Answer:

Explanation:

Tech Social Media giant FB is one of those companies. Not long ago the ceo was brought to court to accusations that his company was selling user data. Turns out this is true and they are selling their users private data to companies all over the word. Once the news turned to something else, people focused on something new but the company still continues to sell it's users data the same as before. This is completely unethical as the information belongs to the user and they are not getting anything while the corporation is profiting.

Answer:

a pair of safety goggles, that fit.

Gloves that also fit

A type of clothing you are willing to get dirty depending on what you are doing for the lab.

Don’t where a watch if you don’t want it getting ruined.

Make sure you take notes.

Explanation:

if you mean this for science, I think I have some I can list. These are also ones I know because I had to do science labs this year and I needed to use these.

Sorry I'm new and need points ty

Answer:

first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.

Answer:

a) The ductility = -30.12%

the negative sign means reduction

Therefore, there is 30.12% reduction

b) the true stress at fracture is 658.26 Mpa

Explanation:

Given that;

Original diameter \(d_{o}\) = 12.8 mm

Final diameter \(d_{f}\) = 10.7

Engineering stress  \(\alpha _{E}\) = 460 Mpa

a) determine The ductility in terms of percent reduction in area;

Ai = π/4(\(d_{o}\) )²  ; Ag = π/4(\(d_{f}\) )²

% = π/4 [ ( (\(d_{f}\) )² - (\(d_{o}\) )²) / ( π/4  (\(d_{o}\) )²) ]

= ( (\(d_{f}\) )² - (\(d_{o}\) )²) / (\(d_{o}\) )² × 100

we substitute

= [( (10.7)² - (12.8)²) / (12.8)² ] × 100

= [(114.49 - 163.84) / 163.84 ] × 100

= - 0.3012 × 100

= -30.12%

the negative sign means reduction

Therefore, there is 30.12% reduction

b) The true stress at fracture;

True stress  \(\alpha _{T}\) = \(\alpha _{E}\) ( 1 +  \(E_{E}\) )

\(E_{E}\)  is engineering strain

\(E_{E}\)  = dL / Lo

= (do² - df²) / df² = (12.8² - 10.7²) / 10.7² = (163.84 - 114.49) / 114.49

= 49.35 / 114.49  

\(E_{E}\) = 0.431

so we substitute the value of \(E_{E}\)  into our initial equation;

True stress  \(\alpha _{T}\) = 460 ( 1 +  0.431)

True stress  \(\alpha _{T}\) = 460 (1.431)

True stress  \(\alpha _{T}\) = 658.26 Mpa

Therefore, the true stress at fracture is 658.26 Mpa

Answer:

20368.917N

Explanation:

Frictional force (F) is the product of the Coefficient of friction and the normal reaction.

F = μN

Coefficient of friction, μ = 0.2

Normal reaction = MgCosθ

Mass, m = 12 tonnes = 12 * 1000 = 12000 kg

N = 12000 * 9.8 * cos30

N = 101844.58

F = 0.2 * 101844.58

F = 20368.917N

Answer:

Vehicle manufacturers specify various reference points on the frame, body, fender, bumper or suspension. On some applications, ride height may even be specified as a distance between two points on the vehicle's suspension, such as the distance from the frame rail to the axle or a suspension control arm.

Answer:

1. All engines  exhibit wear over time ⇒ Synthetic Improves engine protection by resisting oil breakdown.

Synthetic oil does not breakdown so easily which means that it protects the engine more and protects it from wearing.

2. Engines are cold at start-up and not while running ⇒ Synthetic provides maximum protection in extreme hot and cold temperature conditions.

By providing protection for the engine during cold and hot conditions, the engine will not be too cold when the car is started up.

3.  If oil is thicker, engines lose power and efficiency ⇒ Synthetic has greater resistance to oil thickening to maintain engine efficiency.

Part of the characteristics of synthetic oil is that it does not get as thick as regular oil which means that the adverse effects of thick oil are spared on the engine.

Answer:

Explanation:

Hi sorry I'm new and need points ty

The fuel reduction zone, "Reduced Fuel Zone", is the remaining 30 feet (or to property line) and will depend on the steepness of your property and the vegetation. The correct answer is option d. 30 feet (or to property line).

Reduced Fuel Zones (RFZs) are areas of vegetation and fuel that have been managed or modified to reduce their flammability and to create fuel breaks. The objective is to remove or minimize the fuel load, as well as the continuity and distribution of fuel throughout the landscape.RFZs assist firefighters in controlling fires, particularly those that are moving rapidly, because they allow for a reduction in the fire's intensity, speed, and potential to spread. In fire suppression operations, RFZs are frequently used as safety zones for firefighters and as areas where strategic fire control operations, such as burning operations, can be conducted to bring the fire under control.In conclusion, the Reduced Fuel Zone (RFZ) is the remaining 30 feet (or to property line) and will depend on the steepness of your property and the vegetation.

Learn more about vegetation here :-

https://brainly.com/question/1981135

#SPJ11