The step(s) that compose rationale for the cation Ag+ being absent in an unknown (but Pb+2 is present) are:
A lack of dark blue colored solution after the addition of 15 M NH3 (step 2-B)A yellow precipitate did not form when K2CrO4 was added in step 1-CA reddish-brown precipitate did not form after adding KFe(CN)6The white solid did not turn black upon the addition of NaOH and SnCl2The white precipitate from step 1-A dissolved in hot water, indicating it is not AgCl, which is insoluble in water.The white precipitate from step 1-A dissolved in 6M NH3 and then reformed when 6M HNO3 was added, indicating it is not AgCl, which would not dissolve in NH3.No white precipitate formed when 6 M HCl was added to the unknown solution in step 1-A, indicating it is not AgCl, which would precipitate with HCl.The presence of a light blue decantate in step 1-B is consistent with the presence of Pb2+ but not Ag+.Step 1 involves adding KCl and HCl to the unknown solution, which should result in the formation of white precipitates of AgCl and PbCl2 if Ag+ and Pb+2 are present.
The absence of a white precipitate in step 1-A suggests that Ag+ may not be present, and this is supported by the fact that the precipitate dissolves in hot water, indicating it is not AgCl, which is insoluble in water.
In step 1-B, the addition of H2S produces a black precipitate of PbS, indicating the presence of Pb+2. The absence of a black precipitate in step 1-B also suggests that Ag+ may not be present.
Step 1-C involves adding K2CrO4 to the unknown solution to test for the presence of Pb+2, which should result in the formation of a yellow precipitate of PbCrO4. The absence of a yellow precipitate indicates that Pb+2 may not be present.
Step 2-B involves adding NH3 to the unknown solution, which should result in the formation of a dark blue solution if Ag+ is present. The absence of a dark blue color suggests that Ag+ may not be present.
The remaining steps (4, 5, 6, 7) involve the use of additional reagents to further differentiate between Ag+ and Pb+2. For example, the addition of KFe(CN)6 to the unknown solution should result in the formation of a reddish-brown precipitate if Ag+ is present, but not if Pb+2 is present.
Overall, by observing the results of these specific reactions with various reagents, it is possible to determine the presence or absence of specific cations in the unknown solution. In this case, the results suggest that Pb+2 is present, but Ag+ is not.
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amines are multiple choice organic bases that react with water to produce ammonia. organic acids that react with water to produce ammonia. organic bases that react with acids to form ammonium salts. organic acids that react with bases to form ammonium salts.
Amines are the organic bases that react with acids and form ammonium salts.
Amines are Lewis bases. according to Lewis acid are the electron pair acceptor and bases are the electron pair donor. Amines are that contains a nitrogen atom connected to other groups with the single bond. Amine group has as lone pair of electrons. so. amines can donate the lone pair of electrons to the other molecules. so. amines are the bases or the Lewis bases. Amines are the weak bases. Amines are the derivative of ammonia.
Thus, Amines are the organic bases that react with acids and form ammonium salts.
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5.52×1020 so3 molecules express your answer in grams to three significant figures.
5.52×10^20 SO3 molecules have a mass of 7.41 g.
The molar mass of SO3 can be calculated as follows:
Sulfur (S) atomic mass = 32.06 g/mol
Oxygen (O) atomic mass = 16.00 g/mol (there are 3 oxygen atoms in SO3)
Molar mass of SO3 = (32.06 g/mol) + (3 × 16.00 g/mol) = 80.06 g/mol
The molar mass of SO3 is 80.06 g/mol.
The number of moles of SO3 in 5.52×10^20 molecules is:n = 5.52×1020 molecules / 6.022×10^23 molecules/mol = 0.092 mol
The mass of 0.092 mol of SO3 is:moles = mass/molar mass
=> mass = moles * molar mass
m = 0.092 mol * 80.06 g/mol = 7.41 g
Therefore, 5.52×10^20 SO3 molecules have a mass of 7.41 g.
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To convert the number of SO3 molecules to grams, you need to multiply by the formula mass of SO3 and convert using conversion factors.
Explanation:To convert the number of SO3 molecules to grams, you need to first find the formula mass of SO3 and then use the given number of molecules to calculate the mass. The formula mass of SO3 is 80.06 g/mol, which means that one mole of SO3 weighs 80.06 grams. Since there are 6.02 x 1023 molecules in one mole, you can use this conversion factor to convert the given number of molecules to grams:
(5.52 x 1020 SO3 molecules) x (1 mole/6.02 x 1023 molecules) x (80.06 g/1 mole) = 7.28 x 10-3 grams
Therefore, the answer is 7.28 x 10-3 grams, rounded to three significant figures.
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What is the∆S° of 0₂
Answer:0
Explanation: zero because it is the most stable form of oxygen in its standard state
In the chemical equation, H202-H2O + O2, the H2O2 is a
reactant
catalyst
product
solid
Answer:
product
Explanation:
what is the electronic configuration of the co(ii) center found in vitamin b12?
The Co(II) center in vitamin B12 has an electronic configuration of d^7.
This means that there are seven electrons in the d orbitals of the cobalt ion.
The electron configuration of an element describes how electrons are distributed in its atomic orbitals
The electronic configuration of the cobalt ion can be determined by considering its atomic number (27) and the fact that it has lost two electrons to form the Co(II) ion. The electronic configuration of neutral cobalt (Co) is [Ar] 3d^7 4s^2. When two electrons are removed to form the Co(II) ion, the 4s^2 electrons are lost, leaving a d^7 electronic configuration.
In vitamin B12, the Co(II) ion is coordinated to a corrin ring and a nucleotide. The d^7 electronic configuration of the Co(II) center plays an important role in the function of vitamin B12 as a cofactor in several enzymatic reactions.
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why is it more effective to perform an extraction with several small portions of solvent as opposed to one large portion of solvent of equal volume? byu
It is more effective to perform an extraction with several small portions of solvent as opposed to one large portion of solvent of equal volume because the amount of the material left in the trash will be less.
The extraction of certain ratio of the solute is able to the distribute among the phases during each extraction. The various extractions with the lesser amounts of the solvent are more efficient than the single extraction with the huge amount of solvent.
The extraction is about to maximize the outside field of the communication between the two solvents, we can easily get the more surface area in the contact with the fewer amounts.
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What is the law of fossil succession?:
(8th Grade Science)
(Earth History)
(Layers & Layers of Rocks)
Different Fossil organisms succeed one another to go up through the different rock layers in a definite and determinable order. Therefore, any time period can be recognized by its fossil content
Explanation:
Different Fossil organisms succeed one another to go up through the different rock layers in a definite and determinable order. Therefore, any time period can be recognized by its fossil content
9. What is the mass of one mole of sodium?
a. 32. 06 g
b. 16 g
c. 22. 99 g
d. 11 g
The mass of one mole of sodium is determined to be c. 22.99 g
In chemistry, the atomic mass of an element can be described as the average mass of the atoms of an element measured in the atomic mass unit.
Sodium is a soft, silvery-white, highly reactive metal with an atomic mass of 22.989amu or 22.99 amu
The atomic mass of a compound or element, measured in amu, is the same as the mass in grams of one mole of that element.
As the atomic mass of sodium is found to be 22.99 amu, therefore, one mole of sodium atom would weigh or in other words, will have a mass of 22.99 grams.
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Which of the following is not a molecular formula?
N₂020
N₂08
N₂04
NO₂
Answer:
N2020
Explanation:
I’m not fully sure but I’m pretty sure it’s wrong
what is an atom
plz help
Answer:
the smallest thing in the world
Explanation:
Answer:
It is the smallest particle of the elements that exists ob the earth
Convert a density of 55.3 lbs/ft3 into g/mL.
The density of 55.3 lbs/ft³ is 0.884 g/mL.
To convert density from pounds per cubic foot (lbs/ft³) to grams per milliliter (g/mL), we can use the following conversion factors:
1 pound = 453.59237 grams
1 foot = 30.48 centimeters (cm)
1 inch = 2.54 centimeters (cm)
1 milliliter (mL) = 1 cubic centimeter (cm³)
First, we convert pounds to grams:
55.3 lbs = 55.3 lbs * 453.59237 g/lb = 25050.364 grams
Next, we convert cubic feet to milliliters:
1 ft³ = (30.48 cm)³ = 28316.8466 cm³
1 cm³ = 1 mL
Finally, we calculate the density in g/mL:
Density = (25050.364 g) / (28316.8466 mL) ≈ 0.884 g/mL
Therefore, the density of 55.3 lbs/ft³ is approximately 0.884 g/mL.
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15.00 ml of 0.500 m h2so4 is titrated with 17.70 ml of potassium hydroxide. what is the concentration of the koh solution?
The concentration of the koh solution content loaded when 15.00 ml of 0.500 m h2so4 is titrated with 17.70 ml of potassium hydroxide is 0.848 M (Approx.)
To determine the concentration of the KOH solution when 15.00 mL of 0.500 M H2SO4 is titrated with 17.70 mL of potassium hydroxide, follow these steps:
1. Write the balanced chemical equation: H2SO4 + 2KOH -> K2SO4 + 2H2O
2. Calculate the moles of H2SO4: moles = Molarity × Volume (in liters)
moles_H2SO4 = 0.500 M × 15.00 mL × (1 L / 1000 mL) = 0.0075 moles
3. Determine the moles of KOH: From the balanced equation, 1 mole of H2SO4 reacts with 2 moles of KOH, so
moles_KOH = 2 × moles_H2SO4 = 2 × 0.0075 moles = 0.015 moles
4. Calculate the concentration of KOH: Molarity = moles / Volume (in liters)
M_KOH = 0.015 moles / (17.70 mL × (1 L / 1000 mL)) ≈ 0.848 M
So, by calculating, the concentration of the solution results in approximately 0.848 M.
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If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol
Answer:
\(V_{2} = 29.28\,L\)
Explanation:
Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:
\(\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\)
\(V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)\)
\(V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)\)
\(V_{2} = 29.28\,L\)
If 0.0025 mol of NaNO3 forms during the reaction, what is the concentration of NaNO3 in the final solution?
Answer:Hi! I hope this will help you with your question, whether this is an assignment or not. The answer that I get is 0.033 concentration.
If 0.0025 mol NaNo3 forms during the reaction, the concentration of NaNO3 in the final solution should be 0.033.
Explanation:
Why doesn't fluorine show exceptional electronic configuration due to attaining stability??
Fluorine does not show exceptional electronic configuration because it does not have any d orbitals to move electrons to. It achieves stability by forming covalent bonds with other atoms.
Fluorine, with an atomic number of 9, has a configuration of 1s2 2s2 2p5. It is one electron short of having a full outer shell, which would make it highly stable. However, fluorine does not show exceptional electronic configuration despite this fact. This is because the exceptional electronic configuration occurs when an electron from the s orbital moves to the d orbital to achieve greater stability. However, fluorine does not have any d orbitals. Its highest energy level is the p orbital, which already has 3 electrons. Therefore, fluorine cannot attain a greater degree of stability by moving an electron to the d orbital. Instead, fluorine achieves stability by forming a covalent bond with another atom, such as hydrogen or another fluorine atom. This sharing of electrons allows fluorine to achieve a full outer shell and become highly stable.
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How many moles of NaF are contained in 258.6 mL of 0.0296 M NaF solution?
Answer:
Approximately 7.65
Explanation:
math.
skillz.
consider the hypothetical atom, with a mass number of 85 and an atomic number of 44, what would be the number of protons (p), neutrons (n), and electrons (e), if the atom was real?
For the hypothetical atom with a mass number of 85 and an atomic number of 44, a real atom of this isotope (Ruthenium) would have:
Protons (p) = 44
Neutrons (n) = 41
Electrons (e) = 44
The hypothetical atom with a mass number of 85 and an atomic number of 44 represents an isotope of the element Ruthenium (Ru). To determine the number of protons, neutrons, and electrons in a real atom of this isotope, we need to understand the atomic structure.
The atomic number (Z) represents the number of protons in an atom. Since the atomic number is given as 44, the number of protons (p) in the atom is 44.
The mass number (A) represents the total number of protons and neutrons in the nucleus of an atom. In this case, the mass number is given as 85. Therefore, the number of neutrons (n) can be calculated by subtracting the atomic number (protons) from the mass number:
Neutrons (n) = Mass number (A) - Atomic number (Z)
Neutrons (n) = 85 - 44
Neutrons (n) = 41
To determine the number of electrons (e), we assume that the atom is neutral, meaning it has an equal number of protons and electrons. Therefore, the number of electrons is also 44.
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Explain why Ra is larger than Be. With 2 points.
Explanation:
Radium(Ra)=>atomic number=88
BERYLLIUM (Be)=>atomic number =4
why is Ra larger than Be
1. since the atomic number of Ra is greater than Be, the number of electrons is more, which means there are more number of shells present in Ra than Be. (atomic Radius)2. the more the valence electron (excluding fully filled ones) the less is the nuclear attraction forcesince Ra has more valence electron in its outermost shell, the nuclear attraction force is less which means that Ra 's size is greater than Be.hope it helps:)
How do you think the -OH on the end of the pentanol molecule will affect the surface tension? Will pentanol have greater surface tension, less surface tension, or about the same surface tension as pentane or hexane? Write a prediction in the space below, and then submit your answer to move to the next section.
The -OH on the end of the pentanol molecule will affect the surface tension as it will be higher as that of as pentane or hexane.
What is Surface tension?This is referred to as the tension of the surface film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid.
It minimizes the surface area and the higher strength of the intermolecular force is present in the pentanol therefore the surface tension of the pentanol is more than surface tension of the pentane and hexane.
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1. How many moles of Fe₂O, can be formed by reacting 3.2 moles of iron?
Answer:
Explanation:
To determine the number of moles of Fe2O3 that can be formed by reacting 3.2 moles of iron (Fe), we need to first write and balance the chemical equation for the reaction between iron and oxygen (O2) to form Fe2O3:
4Fe + 3O2 → 2Fe2O3
From the balanced equation, we see that 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe2O3. This means that the mole ratio of Fe to Fe2O3 is 4:2, or simply 2:1.
To find the number of moles of Fe2O3 formed from 3.2 moles of Fe, we can use the mole ratio from the balanced equation:
moles of Fe2O3 = 2/4 x 3.2 moles
moles of Fe2O3 = 1.6 moles
Therefore, 1.6 moles of Fe2O3 can be formed by reacting 3.2 moles of iron.
gallium-67 is used medically in tumor-seeking agents. the half-life of gallium-67 is 78.2 hours. if you begin with 46.4 mg of this isotope, what mass remains after 93.8 hours have passed?
After 93.8 hours have passed, 11.6 mg of gallium-67 remains from 46.4 mg of this gallium-67.
The half-life of gallium-67 is 78.2 hours, which means that every 78.2 hours, half of the original amount of the isotope will decay. Using this information, we can determine how much gallium-67 will remain after 93.8 hours have passed.
First, we need to determine how many half-lives have passed in 93.8 hours. We can do this by dividing 93.8 hours by the half-life of gallium-67:
93.8 hours ÷ 78.2 hours/half-life = 1.2 half-lives
This means that 1.2 half-lives have passed, and we can calculate how much gallium-67 remains using the formula:
Amount remaining = (Initial amount) x (1/2)^(number of half-lives)
Plugging in the values we have:
Amount remaining = (46.4 mg) x (1/2)^(1.2) = 11.6 mg
Therefore, after 93.8 hours have passed, 11.6 mg of gallium-67 remains.
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Which SQL query below retrieves all the data in the PRODUCT table?
Question options:
SELECT all
FROM PRODUCT;
SELECT *
FROM PRODUCT;
SELECT *
FROM PRODUCT
WHERE ProdCode IS NOT NULL;
SELECT
FROM PRODUCT;
The SQL query below retrieves all the data in the PRODUCT table.SELECT * FROM PRODUCT;
What is SQL?SQL stands for Structured Query Language and is a programming language used to manage relational databases. SQL is used to execute a variety of operations on a database, such as inserting data, updating existing data, and deleting data.
SQL is used to communicate with a database and is the standard language for managing databases. SQL is used to interact with databases such as MySQL, Oracle, MS SQL Server, SQLite, etc.
PRODUCT is the name of a table in a database that stores product information. The PRODUCT table contains information about a company's products, such as product codes, names, descriptions, and prices. SQL is used to perform operations on the PRODUCT table such as SELECT, INSERT, UPDATE, and DELETE.SQL QueryThe SQL query to select all data in the PRODUCT table is:SELECT * FROM PRODUCT; the
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Heating Curve Question
How much energy is required to raise the temperature of 88 grams of water at 48°C to steam at 138°
Answer:
Q = 33105.6 J
Explanation:
Given that,
Mass of water, m = 88 grams
The temperature raised from 48°C to steam at 138°.
We need to find the energy required to raise the temperature. The formula for the energy required is given by :
\(Q=mc\Delta T\)
Where
c is specific heat of water, c = 4.18J/g °C
So,
\(Q=88\times 4.18\times (138-48)\\\\Q=33105.6\ J\)
So, the required energy is 33105.6 J.
why is it important to heat the melting point apparatus or block slowly (~1ºc per minute) when the temperature gets close to the mp?
It is important to heat the melting point apparatus or the block slowly, when the temperature gets close to the melting point is
The melting point of the substance is the temperature at which the substance changes the state from the solid to liquid. When heat energy is provided to substance it will changes from the solid phase to the liquid phase. So, it is important to add the heat energy slowly because when the substance changes a phase then it will absorb the much energy till it reaches up to the melting.
Therefore the heat will be provided slowly. The slow heating will provide the more accurate reading of the melting point.
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Boron has an average atomic mass of 10.81. One isotope of boron has a mass of 10.012938 and a relative abundance of 19.80 percent. The other isotope has a relative abundance of 80.20 percent.
What is the mass of that isotope? Report to two decimal places.
amu
Answer:
11.01
Explanation:
because yes :)
calculate the amount of parent isotope that remaining after 1, 2, 3, and 4 half-lives. include 4 decimal places in your answers. parent present: 1.0000 unit (i.e., all of the parent isotope is still present) after 1 half-life: 0.5000 units
For each half-life, the total amount of the isotope is divided by 2.
Therefore, the amount of parent isotope that remains after:
1 half-life is ½= 0.5
2 half-lives= 2/4= 0.5
3 half-lives= 3/6= 0.5
What is an isotope?
Isotopes are two or more atoms sharing the same atomic number and chemical element but have distinct nucleon numbers (mass numbers) as a result of having a different number of neutrons in their nuclei. The word "isotope" is derived from the Greek words "isos" and "topos," both of which imply "the same location." As a result, the name refers to the fact that various isotopes of a given element occupy the same spot on the periodic table. Scottish physician and author Margaret Todd first used it in a recommendation in 1913.To know more about isotopes, click the link given below:
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Q2. Name, constituent of petroleum (Petrochemicals) which is used for following purposes.
(i) To make candles.
(ii) A solvent for dry cleaning
(iii) For surfacing roads.
(iii) Jet engine fuel.
(v) For lubrication.
The constituents of petroleum that are used for the following purposes are as follows:
To make candles ----- Paraffin waxA solvent for dry cleaning ----- PetrolFor surfacing roads ----- BitumenJet engine fuel ----- KeroseneFor lubrication ----- Lubricating oil.What are the constituents of petroleum?The constituents of petroleum are LPG, bitumen, paraffin wax, lubricating oil, kerosene, diesel, etc. These compounds are a mixture of hydrocarbons.
Therefore, each constituent of petroleum that is used for the following purposes is mentioned above with proper names.
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8. Some people practice brining their turkey. This means they let it soak in a solution overnight. The solution diffuses into the turkey. This means that the turkey is placed into a ___________________ solution.
Some people practice brining their turkey. This means they let it soak in a solution overnight. The solution diffuses into the turkey. This means that the turkey is placed into a hypertonic solution.
What is a hypertonic solution?A hypotonic solution is described as a solution that has lower osmotic pressure than another solution to which it is compared.
The concept of tonicity helps us understand that the saltwater we use to brine the turkey is typically considered hypertonic solution because it has a greater concentration of solutes than the liquid found inside the cells.
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an electronic interaction that stabilizes alkenes and carbocations and results from overlap of a vacant p orbital on one atom with the neighboring c-h sigma bond is known as
an electronic interaction that stabilizes alkenes and carbocations and results from overlap of a vacant p orbital on one atom with the neighboring c-h sigma bond is known as Hyperconjugation.
The delocalization of the sigma electrons in the C-H bond of an alkyl group coupled to an atom in an unsaturated system or to an atom with an unshared p orbital is known as hyperconjugation, which is a general stabilizing interaction. When a suitable attacking reagent is present in an organic molecule, electron displacement happens.
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CH4 + 2O + CO2 + 2 H2O
If 9.65 mole of methane reacts with oxygen to produce carbon dioxide and water, what mass of water is produced?
Answer:
347.4 (19.3 mole)
Explanation:
CH4 + 2O2 = CO2 + 2H2O
1(mole) - 9.65(mole)
2(mole) - x ⇒x = 9.65*2=19.3
m=n*M ⇒ m= 19.3*(1*2+16)= 19.3*18=347.4(g)