Shares of Apple (AAPL) for the last five years are collected. Returns for Apple's stock were 37.7% for 2014, -4.6% for 2015, 10% for 2016, 46.1% for 2017 and -6.8% for 2018. The mean return over the five years is how much? (a) 13.5% (b) 15.5% (c) 16.5% (d) 26.2%

Answer:

thrust angle

Explanation:

good luck.........

Answer:

Explanation:

do you have any other questions besides "tyuuyiopopiouyttrrtrffrlkl,k;;';'l.l"

The given problem describes a docking system of ships at a harbor. When a ship arrives at the harbor, it docks at one of six berths. If all six berths are occupied, the ship leaves the harbor immediately. After docking, the ship waits for the unloading service of a single crane. The crane unloads the ships in a First-In-First-Out discipline.

After unloading, the ship leaves the harbor immediately. The system state at time t is defined as [U(t),C(t)] where U(t) represents the number of ships waiting to be unloaded or being unloaded and C(t) represents the number of busy cranes (0 or 1). Let [u, c] be the current state of the system.

Now, the state transitions can be defined as follows:

Events:
1. A ship arrives at the harbor and all berths are occupied
2. A ship arrives at the harbor and some berths are empty
3. A crane becomes available
4. A ship finishes unloading and leaves the harbor

State transitions:
1. If [u, c] = [6, 1], the ship leaves the harbor immediately. The system state remains [6, 1].
2. If [u, c] = [6, 0], the ship leaves the harbor immediately. The system state remains [6, 0].
3. If [u, c] = [0, 0], the system state becomes [0, 1].
4. If [u, c] = [n, 0] (where n is less than 6), the system state becomes [n+1, 0].
5. If [u, c] = [n, 1] (where n is less than 6), the system state becomes [n, 1].
6. If [u, c] = [1, 1], the system state becomes [0, 1].
7. If [u, c] = [n, 1] (where n is greater than 1), the system state becomes [n-1, 1].
8. If [u, c] = [0, 1], the system state remains [0, 1].

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Answer:

voltage = -0.01116V

power = -0.0249W

Explanation:

The voltage v(t) across an inductor is given by;

v(t) = L\(\frac{di(t)}{dt}\)             -----------(i)

Where;

L = inductance of the inductor

i(t) = current through the inductor at a given time

t = time for the flow of current

From the question:

i(t) = \(10e^{-t/2}\)A

L = 10mH = 10 x 10⁻³H

Substitute these values into equation (i) as follows;

v(t) = \((10*10^{-3})\frac{d(10e^{-t/2})}{dt}\)

Solve the differential

v(t) = \((10*10^{-3})\frac{-1*10}{2} (e^{-t/2})\)

v(t) = -0.05 \(e^{-t/2}\)

At t = 8s

v(t) = v(8) = -0.05 \(e^{-8/2}\)

v(t) = v(8) = -0.05 \(e^{-4}\)

v(t) = -0.05 x 0.223

v(t) = -0.01116V

(b) To get the power, we use the following relation:

p(t) = i(t) x v(t)

Power at t = 8

p(8) = i(8) x v(8)

i(8) = i(t = 8) = \(10e^{-8/2}\)

i(8) = \(10e^{-4}\)

i(8) = 10 x 0.223

i(8) = 2.23

Therefore,

p(8) = 2.23 x -0.01116

p(8) = -0.0249W

Answer:

The voltage is - 0.9158 mV

The power is - 0.1677 mW

Explanation:

Given;

current through the inductor, i(t)  = \(10e^{-t/2}\) -----equation (1)

inductance, L = 10 mH

given time, t  = 8 s

The voltage across the inductor is given by;

\(V_L = L\frac{di}{dt} \\\\V_L = (10 *10^{-3})\frac{d}{dt} (10e^{-t/2})\\\\V_L = (10 *10^{-3})\frac{10}{-2}(e^{-t/2})\\\\ V_L = -0.05e^{-t/2} \ ----equation (2)\)

when t = 8 s, the voltage will be ;

\(V_L = -0.05 e^{-t/2}\\\\V_L = -0.05 e^{-8/2}\\\\V_L = -0.05 e^{-4}\\\\V_L = -9.158 *10^{-4} \ V\\\\V_L = -0.9158 \ mV\)

Power is given by;

P = I V

When t = 8, the current "I" is given by;

\(i(t) = 10e^{-t/2}\\\\i(8) = 10e^{-8/2}\\\\I = 10e^{-4}\\\\I = 0.1832 \ A\)

P = 0.1832 x (-9.158 x 10⁻⁴)

P = -1.677 x 10⁻⁴ W

P = -0.1677 mW

Decision variables are the values that the decision maker can control and choose in a decision-making problem. Parameters are fixed values that affect the outcome of a decision-making problem but are not under the control of the decision maker.

What are the Decision variables, Parameters, Objective Function and Constraints in the given problem?

Decision Variables:

Parameters/Data:

Objective Function:

Constraints:

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The thermal conductivities in the ξ and η directions, kξ and kη, are known for a flat plate of laminated material with laminations making an angle β with the surfaces. To determine the overall thermal conductivity of the plate, we need to consider the effective thermal conductivity in the direction of heat flow. This can be calculated using the rule of mixtures.

The effective thermal conductivity, keff, is given by the equation:

keff = (kξ cos²β + kη sin²β)

Here, cos²β represents the fraction of heat flow in the direction of kξ, and sin²β represents the fraction of heat flow in the direction of kη. By substituting the given values of kξ, kη, and β into the equation, you can calculate the effective thermal conductivity of the laminated plate.

Remember that this calculation assumes that heat flow is one-dimensional and perpendicular to the surfaces. Additionally, it is important to note that this equation applies only to flat plates of laminated material and may not be applicable to other geometries or materials.

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Answer:

b

Explanation:

what is anythin efficiency if ta

Based on the fact that Aref hints that he is a butterfly, it is safe to assume that:

According to the given scenario, we can see that Aref tries to make a comparison between himself and a butterfly, probably because there is a shared similarity between them.

With this in mind, we can see that a simile is used to compare two dissimilar things which are not related using "like" or "as".

As a result of this, it is either that:

Please note that your question is incomplete and I gave you a general overview to help you get the right answers.

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Answer:

strong

Explanation:

Answer:

\(\displaystyle \int^{1}_{0} \int^{2-y}_{y^3} dx\ dy = \frac{5}{4}\)

General Formulas and Concepts:
Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                           \(\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C\)

Integration Rule [Fundamental Theorem of Calculus 1]:                                 \(\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)\)

Integration Property [Multiplied Constant]:                                                     \(\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx\)

Integration Property [Addition/Subtraction]:                                                   \(\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx\)

Multivariable Calculus

Integration

Fubini's Theorem:                                                                                             \(\displaystyle \iint_R{f(x, y)} \, dA = \int\limits^b_a \int\limits^{g_2(x)}_{g_1(x)} {f(x, y)} \, dy \, dx\)

Area of a Plane Region Formula:                                                                     \(\displaystyle A = \iint_R dA\)

Explanation:

Step 1: Define

Identify.

\(\displaystyle \left \{ \begin{array}{ccc}x = y^3 \\ x = 0 \\ x + y = 2 \end{array}\)

See the graph of the given curves in the attachment.

Step 2: Find Area Pt. 1

Step 3: Find Area Pt. 2

∴ the area of the plane region R bounded by the curves given is 1.25.

---

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Topic: Multivariable Calculus

Unit: Double Integrals and Area

a. Best Critical Region (BCR): The critical region that maximizes the power of a statistical test.

b. Uniformly Most Powerful Test (UMPT): A statistical test with the highest power among all possible tests for a given significance level.

c. Pivotal Quantity (PQ): A function of sample data and an unknown parameter with a known distribution independent of the parameter.

d. Randomized Test: A statistical test where the decision to accept or reject the null hypothesis is determined randomly.

e. Sequential Probability Ratio Test (SPRT): A method for sequential decision-making based on accumulating evidence from a sequence of observations, useful for efficient binary decision-making.

a. The best critical region (BCR) refers to the region in the sample space where the null hypothesis is rejected, resulting in the most favorable trade-off between the probabilities of type I and type II errors. It is the critical region that maximizes the power of the statistical test.

b. The uniformly most powerful test (UMPT) is a type of statistical test that possesses the most power among all possible tests for a given significance level. It is designed to detect the alternative hypothesis with the highest probability, making it the most powerful test in a statistical hypothesis testing framework.

c. A pivotal quantity (PQ) is a function of the sample data and an unknown parameter that has a known distribution that does not depend on the parameter itself. Pivotal quantities are useful in statistical inference as they allow for the construction of confidence intervals and hypothesis tests that are distribution-free or have known distributions.

d. A randomized test is a type of statistical test where the decision to accept or reject the null hypothesis is determined by a random mechanism. It involves using a randomization procedure to assign observations to different treatment groups or to determine the critical region. Randomized tests have the advantage of controlling the type I error rate and can be useful in situations where traditional fixed-sample tests may not be appropriate.

e. The Sequential Probability Ratio Test (SPRT) is a statistical method used for making sequential decisions based on accumulating evidence from a sequence of observations. It is commonly used in quality control and decision-making processes where data is collected sequentially. The SPRT allows for early termination of the test if a decision can be reached with sufficient confidence based on the available data, leading to efficient and timely decision-making. It is particularly useful when testing hypotheses or making binary decisions in a sequential manner, reducing the number of observations required compared to traditional fixed-sample tests.

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Answer:

3

Explanation:

To determine if the rings are pure silver, we can calculate the density of the rings and compare it to the density of pure silver. The density of a material is the mass of the material per unit volume.

First, we need to find the volume of one of the rings. Since the rings are cylindrical, we can use the formula for the volume of a cylinder to find the volume of each ring:

V = π * r^2 * h

Where V is the volume of the ring, π is approximately equal to 3.14, r is the radius of the ring, and h is the height of the ring. In this case, the height of the ring is equal to the thickness of the ring, which is equal to the change in the water level (8.45 mm) divided by the number of rings (10). The radius of the ring is equal to half the diameter of the graduated cylinder (2.5 cm / 2 = 1.25 cm), since the rings are placed in the cylinder side by side.

Plugging these values into the formula, we find that the volume of each ring is:

V = 3.14 * (1.25 cm)^2 * (8.45 mm / 10) = 0.00367 cm^3

Next, we can use the mass and volume of each ring to calculate the density of the rings:

density = mass / volume

Since the mass of each ring is 0.738g and the volume of each ring is 0.00367 cm^3, the density of the rings is:

density = 0.738 g / 0.00367 cm^3 = 201.09 g/cm^3

Finally, we can compare the density of the rings to the density of pure silver, which is 10.49 g/cm^3. Since the density of the rings is much higher than the density of pure silver, it is likely that the rings are not pure silver.

It is important to note that this calculation is only an approximate estimation of the purity of the rings. There may be other factors that affect the density of the rings, such as impurities or variations in the thickness of the rings. Additionally, the value of the density of pure silver used in this calculation may not be entirely accurate, as the density of a material can vary depending on factors such as temperature and pressure. A more precise determination of the purity of the rings would require further testing and analysis.

To calculate the freeway's density and level of service (LOS) before and after the ban on heavy vehicles during the peak hour, we need to consider the given information and apply the appropriate formulas. Let's break down the calculations:

Calculate the number of lanes in one direction: Number of Lanes = 4

Calculate the number of ramps per mile: Ramp Density = 1.5 ramps/mile

Calculate the lane capacity: Lane Capacity = (Number of Lanes × Lane Capacity per Lane) + (Number of Ramps × Ramp Capacity)

Lane Capacity per Lane = 1900 vehicles per hour (based on typical capacity for freeways)

Ramp Capacity = 150 vehicles per hour (assumed value)

Calculate the total capacity before the ban: Total Capacity Before = Lane Capacity × Peak-Hour Factor

Calculate the capacity after the ban: Capacity After = (Lane Capacity per Lane × (1 - Percentage of Heavy Vehicles)) × Peak-Hour Factor

Calculate the density before the ban: Density Before = Peak-Hour Traffic Volume / Total Capacity Before

Calculate the density after the ban: Density After = Peak-Hour Traffic Volume / Capacity After

Determine the LOS based on the density values: Use the appropriate LOS scale to determine the LOS corresponding to the calculated densities.Please note that specific LOS scales and formulas may vary depending on the traffic engineering methodology used.

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Answer:

drugs

Explanation:

The statement is true. In order for a table to be in 2nf, it must first be in 1nf, which means that each column must contain atomic values and there should be no repeating groups of data.

Additionally, the primary key of the table should be able to uniquely identify each row. If the primary key is not a composite key, which means that it is made up of only one column, then the table is also automatically in 2nf.

However, it is important to note that just because a table is in 2nf does not necessarily mean that it is in higher normal forms such as 3nf or BCNF. In order to achieve those higher normal forms, additional steps may need to be taken to ensure that there are no transitive dependencies or partial dependencies in the table.

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check photos (answer)

Comparing this to the actual power required for the two-stage compressor (242.6 kW), we can see that the actual power required is significantly higher.

Work done is the amount of energy transferred to or from a system as a result of a force acting on it over a distance.

To solve this problem, we can use the following steps:

Step 1: Determine the state points of the air at various stages of the compression process.

Stage 1: Inlet state = State 1

P1 = 100 kPa, T1 = 300 K, V1 = 10 m³/min

Stage 2: After the first stage of compression = State 2

P2 = 1200 kPa, T2 = ? (isentropic compression)

Stage 3: After intercooling = State 3

P3 = 350 kPa, T3 = 300 K, V3 = V2

Stage 4: After the second stage of compression = State 4

P4 = 1200 kPa, T4 = ? (isentropic compression)

Step 2: Calculate the temperature and specific volume at states 2 and 4 using the isentropic compression process.

For an isentropic compression process, we have:

(P2/P1)^((γ-1)/γ) = T2/T1

(P4/P3)^((γ-1)/γ) = T4/T3

where γ is the ratio of specific heats for air, which is approximately 1.4.

Solving for T2 and T4, we get:

T2 = T1*(P2/P1)^((γ-1)/γ) = 300*(1200/100)^((1.4-1)/1.4) = 742.6 K

T4 = T3*(P4/P3)^((γ-1)/γ) = 300*(1200/350)^((1.4-1)/1.4) = 892.5 K

Next, we can use the ideal gas law to calculate the specific volume of air at states 2 and 4:

V2 = V1*(P1/P2)(T2/T1) = 10(100/1200)(742.6/300) = 0.1867 m³/kg

V4 = V3(P3/P4)(T4/T3) = 10(350/1200)*(892.5/300) = 0.2604 m³/kg

Step 3: Calculate the work done in each stage of the compressor.

For an isentropic compression process, the work done can be calculated using the following equation:

W = (mCp)(T2-T1) = (mCp)(T4-T3)

where m is the mass flow rate of air, which can be calculated using the specific volume and inlet volumetric flow rate:

m = V1/(v160) = 10/(0.831460) = 0.2016 kg/s

Cp is the specific heat at constant pressure for air, which is approximately 1.005 kJ/kg-K.

Thus, the work done in each stage of the compressor is:

W1 = (0.20161.005)(742.6-300) = 77.2 kW

W2 = (0.20161.005)(892.5-300) = 116.9 kW

The total work done by the compressor is:

W_total = W1 + W2 = 77.2 + 116.9 = 194.1 kW

Step 4: Calculate the power required to run the compressor.

The power required to run the compressor can be calculated using the following equation:

Power = W_total/η

where η is the compressor efficiency.

We are not given the efficiency, but for a two-stage compressor, a reasonable estimate for η is reasonable estimate for the efficiency of a two-stage compressor is around 75-85%. Therefore, we can assume η = 0.8.

Using this efficiency value, the power required to run the compressor is:

Power = W_total/η = 194.1/0.8 = 242.6 kW

Step 5: Compare the result to the power required for isentropic compression from the same inlet state to the same final pressure.

For isentropic compression from the same inlet state to the same final pressure, the work done can be calculated using the following equation:

W = (mCp)(T2-T1) = (mCp)(T4-T3) = (m*Cp)*ΔT

where ΔT = T2-T1 = T4-T3 = 442.5 K

Thus, the work done for isentropic compression is: W_iso = (0.2016*1.005)*442.5 = 89.1 kW

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Universal joints do not allow the drive shaft to change angles in response to rear axle movements, as stated by Technician A. Technician B is correct.

The  primary purpose of universal joints is to maintain a constant drive shaft length while accommodating changes in angles. Universal joints, also known as U-joints, are mechanical couplings used in drivetrain systems. They are typically employed in applications where there is a need to transmit rotational motion between two shafts that are not aligned in a straight line. The design of universal joints allows them to accommodate changes in angles between the input and output shafts while maintaining a consistent shaft length. As the rear axle moves, the angles between the transmission and the axle may change due to suspension travel or other factors. The universal joints allow the drive shaft to flex and rotate at varying angles without affecting its length. This flexibility helps to prevent binding or excessive stress on the drive shaft, ensuring smooth power transmission and allowing for efficient operation of the drivetrain system.

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Answer:

----------

Explanation:

Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!

Answer:

A catalytic converter is expensive because it needs rhodium to reduce smog levels. Rhodium, at its current value, is extremely expensive which makes using it in a catalytic converter expensive. To make up for their cost, manufacturers have to increase the price of the catalytic converter.

Explanation:

Answer:

A. Yes, it will run

B. X will not replace any value

Explanation:

A. Will it run?

First, the algorithm can be interpreted in python as follows:

#Set Minimum to 1

MINIMUM = 1

#For every element X in the list L

for X in L:

#If current element X is less than MINIMUM

    if X < MINIMUM:

#Set MINIMUM to X

         MINIMUM = X

#Print MINIMUM

print(MINIMUM)

The algorithm will run without error because it follows the right sequence and has no syntax error

B. Will X replace any value?

No, it won't

The smallest positive integer is 1.

So, setting the MINIMUM to 1 means that the value of X in the list will not replace the MINIMUM because the MINIMUM has already been set

The engineer's data on the number of failures in each mode for each of the three configurations can be used to determine whether the configuration has an effect on the type of failure.

To analyze this data, statistical methods can be employed to identify any significant differences between the failure modes in each configuration. One approach to this analysis is to use a chi-square test of independence. This statistical test can determine whether there is a significant association between two categorical variables, in this case the configuration and the failure mode. If the p-value of the test is below a predetermined level of significance (usually 0.05), then there is evidence that the configuration has an effect on the type of failure. Another approach to analyzing this data is to use a contingency table to display the frequency of failures in each configuration and failure mode. This can help identify any patterns or trends in the data, which can provide insights into the effects of the different configurations on the type of failure.

Overall, it is possible to determine whether the configuration has an effect on the type of failure by analyzing the data obtained by the engineer. By using statistical methods and contingency tables, it is possible to identify any significant associations or patterns in the data, which can help engineers make informed decisions about the design of the component.

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Answer:

B. evaluation of a particular program

Explanation:

Before students enrol into any given discipline, they should first ensure that their program of choice is well accredited. In a specific program, specialized accreditation has the function of telling would be students if the program meets up with academic standards in the field

Accreditation is a way of assessing faculty and curriculum quality of schools to make sure that they are up to academic standards and are also preparing students to future success in the field.

Answer: downward velocity = 6.9×10^-4 cm/s

Explanation: Given that the

Diameter of the smoke = 0.05 mm = 0.05/1000 m = 5 × 10^-5 m

Where radius r = 2.5 × 10^-5 m

Density = 1200 kg/m^3

Area of a sphere = 4πr^2

A = 4 × π× (2.5 × 10^-5)^2

A = 7.8 × 10^-9 m^2

Volume V = 4/3πr^3

V = 4/3 × π × (2.5 × 10^-5)^3

V = 6.5 × 10^-14 m^3

Since density = mass/ volume

Make mass the subject of formula

Mass = density × volume

Mass = 1200 × 6.5 × 10^-14

Mass M = 7.9 × 10^-11 kg

Using the formula

V = sqrt( 2Mg/ pCA)

Where

g = 9.81 m/s^2

M = mass = 7.9 × 10^-11 kg

p = density = 1200 kg/m3

C = drag coefficient = 24

A = area = 7.8 × 10^-9m^2

V = terminal velocity

Substitute all the parameters into the formula

V = sqrt[( 2 × 7.9×10^-11 × 9.8)/(1200 × 24 × 7.8×10^-9)]

V = sqrt[ 1.54 × 10^-9/2.25×10-4]

V = 6.9×10^-6 m/s

V = 6.9 × 10^-4 cm/s

Answer:

Can't help

Explanation:

Answer:

i personally think it is false

Explanation:

i think this because gear friction reduces next to no power

The square feet of roof area that can be covered by one square of these shakes is 75%. The correct option D.

The condition of the atmosphere, including its temperature, pressure, wind, humidity, precipitation, and cloud cover, is referred to as the weather. It is distinct from climate, which is the average of all weather events for a certain location over a period of around 30 years.

Given Data,

Size of shakes = 24” x 3/8”

Weather exposure = 7 ½”

As explained above, 24” x 3/8” shakes with 7 ½” weather exposure has coverage of 75 square feet per square of shakes. 75 square feet

Therefore, the correct option D. 75%.

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The question is incomplete. Your most probably complete question is given below:

The shakes will be applied with an average spacing of '/>" between shakes, and the weather exposure will be 71/2". Look at the shake coverage table. According to the information in this table, approximately how many square feet of roof area can be covered by one square of these shakes?

Both Technician A and Technician B are correct in their statements, as they are referring to different aspects of engine oil standards and ratings.

Technician A is correct. ILSAC (International Lubricant Standardization and Approval Committee) is responsible for developing and identifying standards for gasoline-fueled engine oils. These standards are widely recognized and used in the automotive industry to ensure the quality and performance of engine oils.

Technician B is also correct. API (American Petroleum Institute) rates the engine oil service by assigning different performance categories or "API Service Categories" to engine oils. These categories specify the requirements and performance levels that an engine oil must meet to be suitable for use in different types of engines.

Both technicians A and B are correct.

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