The statement "short-wave (visible and ultraviolet) radiation that reflects off the Earth's surface is absorbed by the lower atmosphere and heats it up, a process otherwise known as the greenhouse effect" is true.
How does the greenhouse effect work?Solаr energy аbsorbed аt Eаrth’s surfаce is rаdiаted bаck into the аtmosphere аs heаt. Аs the heаt mаkes its wаy through the аtmosphere аnd bаck out to spаce, greenhouse gаses аbsorb much of it. Greenhouse gаses аre more complex thаn other gаs molecules in the аtmosphere, with а structure thаt cаn аbsorb heаt. They rаdiаte the heаt bаck to the Eаrth's surfаce, to аnother greenhouse gаs molecule, or out to spаce.
Eаrth is constаntly bombаrded with enormous аmounts of rаdiаtion, primаrily from the sun. This solаr rаdiаtion strikes the Eаrth's аtmosphere in the form of visible light, plus ultrаviolet (UV), infrаred (IR) аnd other types of rаdiаtion thаt аre invisible to the humаn eye. UV rаdiаtion hаs а shorter wаvelength аnd а higher energy level thаn visible light, while IR rаdiаtion hаs а longer wаvelength аnd а weаker energy level.
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A student mixed two clear liquids together in a beaker. A solid and a new liquid formed. The student forgot to write down the mass of one of the reactants. The
rest of the data are shown in the table below.
What is the mass of liquid reactant A?
A 1.0 g
B 8.0 g
C 9.0 g
D 11.0 g
E 20.0 g
How far will you have traveled on a bus driving 31 m/s for 3 hours.
Elements are organized on the periodic table based on their properties. Which statement correctly predicts and explains the chemical reactivity of two metals?
Rubidium (Rb) is more reactive than strontium (Sr) because strontium atoms must lose more electrons.
Sodium (Na) is more reactive than magnesium (Mg) because sodium atoms must gain more electrons.
Calcium (Ca) is less reactive than potassium (K) because potassium atoms must lose more electrons.
Beryllium (Be) is less reactive than lithium (Li) because beryllium atoms must gain more electrons.
Answer:Rubidium or answer 1
Explanation:took quiz
Answer: Rubidium (Rb) is more reactive than strontium (Sr) because strontium atoms must lose more electrons.
Explanation: Look at the elements they are organized on the periodic table based on their properties. (A) correctly predicts and explains the chemical reactivity of two metals.
Most meteorites that enter the Earth's atmosphere burn up before they reach the Earth itself. When this happens, lots of energy is transferred from the meteorites' __________ energy stores very quickly. What one word completes the sentence
Most meteorites that enter the Earth's atmosphere burn up before they reach the Earth itself. When this happens, lots of energy is transferred from the meteorites' kinetic energy stores very quickly.
The kinetic energy storage of meteorites are communicated to the surrounding environment as heat, sound, and light energy.
A meteorite penetrates the atmosphere of the Earth. Friction acts on the meteorite when it reaches the Earth's atmosphere. When a meteorite enters the Earth's atmosphere, it gains kinetic energy. The meteorite catches fire due to friction. At this time, the meteorite's kinetic energy will be transformed into heat energy, sound energy, and light energy.
Hence kinetic word word completes the sentence.
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'what does the scale read (in n ) when the elevator is ascending at a constant speed of 2.1 m/s ?
When the elevator is ascending at a constant speed of 2.1 m/s the scale will read 696.51 N.
What do you mean by speed?
Speed is a measure of how fast an object is moving, and is defined as the distance traveled per unit time. It is a scalar quantity, which means that it has only magnitude and no direction. The standard unit of speed in the International System of Units (SI) is meters per second (m/s).
Speed can be calculated using the following formula:
Speed = Distance / Time
When the elevator is ascending at a constant speed of 2.1 m/s, the scale will read the person's normal weight, which is the force exerted on the scale by the person's mass due to gravity.
This is because at a constant speed, the person and the scale are not experiencing any net acceleration, and so the force experienced by the person is the same as their weight.
The weight of the person is given by the formula:
Weight = mass x gravitational acceleration
where mass = 71.0 kg and gravitational acceleration = 9.81 m/s^2 (assuming the elevator is on Earth).
So the weight of the person is:
Weight = 71.0 kg x 9.81 m/s^2 = 696.51 N
Therefore, the scale will read 696.51 N.
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Two equal masses are floating in space. The distance between their centers is X. How would the gravitational force between them change if the mass of one of the objects was cut in half?
Group of answer choices
The force would be one-half as much.
The force would be one-fourth as much.
The force would be twice as much.
The force would be the same.
The force would be one-fourth as much.
What is force?
Force is a push upon an object resulting from its interaction with another object. It is a vector quantity that is described by both magnitude and direction. Forces cause an object to accelerate.
Therefore, The force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. So if one of the objects has its mass halved, the gravitational force between them will decrease by a factor of (1/2)^2 = 1/4.
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If a projectile hits a stationary target, and the projectile continues to travel in the same direction, the mass of the projectile is less than the mass of the target. the mass of the projectile is equal to the mass of the target. the mass of the projectile is greater than the mass of the target. nothing can be said about the masses of the projectile and target without further information. this is an unphysical situation and will not actually happen.
The correct arrangement of the question is;
If a projectile hits a stationary target, and the projectile continues to travel in the same direction,
A) the mass of the projectile is less than the mass of the target.
B) the mass of the projectile is equal to the mass of the target.
C) the mass of the projectile is greater than the mass of the target.
D) nothing can be said about the masses of the projectile and target without further information.
E) this is an unphysical situation and will not actually happen.
Answer:
Option C: The mass of the projectile is greater than the mass of the target.
Explanation:
We want to find what will happen when a projectile continues in motion after it hits a target.
Now, for the projectile to keep moving in that direction after it hits the target, it means it had a force bigger than the force of the target to overpower it and force it to move with it.
Now, from law of inertia, Force = ma.
But in this case acceleration is 0 because the speed of the projectile is constant.
Thus, the force depends on the mass. So for a higher force, the mass of the projectile has to be more than that of the stationary object.
Thus, option C is correct
Looking at the position of the house and the tree, if the man ran starting from the house going
to
the tree in 8 seconds, the average velocity would be?
Average velocity of man is 2 m/s
Given that;
Distance between tree and house = 16 m
Time taken = 8 seconds
Find:
Average velocity
Computation:
Average velocity = Total distance cover / Time taken
Average velocity = Distance between tree and house / Time taken
Average velocity = 16 / 8
Average velocity = 2 m/s
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The law of Conservation of energy states that energy can be transformed from one form to another, but it cannot be _______ or ________.
A. radiated, conducted
B. created, changed
C. changed, destroyed
D. created, destroyed
Answer:
D
Explanation:
A force of 80.0 N is applied by a janitor on the handle of a mop held at 40° angle with the floor. What force is pushing the mop (a) across the floor and (b) downward to the floor?
can someone answer this, thank youuu!
Answer:
Explanation:
Answer:
Explanation:
If we ASSUME that the mop has no acceleration, then the applied force must be acting parallel to the length of the handle.
a) 80.0cos40 = 61.3 N
b) 80.0sin40 = 51.4 N
a healthy person has a body temperature of 37 degree celsius. if they jump into an ice bath after sports training their temperature only decreases slowly. how can you explain this when a lump of metal at 37 celsius degree placed in the same ice bath cools down to 0 celsius degree in only a couple of minutes
Blue light with a wavelength of 4.57 E-7 m is used in Young's experiment with the slits separated by a distance of 2.42 E-4Y
m. The screen is located at a distance from the slits of 4.5 m. Calculate the distance on the screen between the central
bright fringe and the first bright fringe. Show all work for full credit.
The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.
In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:
y = (m * λ * L) / d
where:
y is the distance between the fringes on the screen,
m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),
λ is the wavelength of the light,
L is the distance from the slits to the screen, and
d is the distance between the slits.
Given the values:
λ = 4.57E-7 m (blue light wavelength)
d = 2.42E-4 m (distance between the slits)
L = 4.5 m (distance from the slits to the screen)
For the central bright fringe (m = 0), the distance (y) is:
y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y = 0
Therefore, the central bright fringe coincides with the point where the two beams of light overlap.
For the first bright fringe (m = 1), the distance (y) is:
y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y ≈ 8.52E-3 m
This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.
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Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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Wavelength of blue photons 495 nm, what is the frequency? and what is the energy?
Answer:
1.F: About 6*10^14 Hz
2.E: About 4*10^ -19 J
Explanation:
Frequency: We knew that the speed of a wave is its wavelength(λ)* frequency(f, in Hz). By the wave-particle duality we know we can calculate the frequency of light in the same way. So, c=495nm *f, f=c/495nm=> (299,792,458 m/s) / (4.95*10^-7 m)
=6.05*10^14 /s
Energy: The energy photon contains can be calculate by this formula-- E=hf
f is the frequency and h is Planck's constant which is about 6.62 ×10^-34 *m^2*kg/s (after dimensional analysis ) =6.62*10^ -34 J*s.
So, the energy of a blue photon is (6.05*10^14)*(6.62*10^-34)=40.051*10^-20= 4.051*10^-19 J
A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.
(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---
(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---
(c) Find the initial velocity of the ball.
____ m/s upward
(d) Find the maximum height it reaches.
____ m
(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.
Using the equation, we can solve for the acceleration:
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s
Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.
(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.
(c) To find the initial velocity of the ball, we can use the equation:
v = u + at
At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s upward
Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.
(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:
s = ut + (1/2)at^2
At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.
0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2
0 = 47.864 + (-5.5294)
5.5294 = 47.864
Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.
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Please help me
Explain why driver age 16-18 are most likely to be involved in traffic accidents
Answer:Lack of experience.
Explanation:
Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
Closer to a perfect circle then a straight line
Almost rectangular
A very elongated ellipse
Almost parabolic
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
a very elongated ellipse.What is eccentricity?Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.
The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).
An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.
Therefore, the correct answer is - A very elongated ellipse.
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¿Cuál es el trabajo neto en J que se necesita para acelerar un auto de 1500 kg de 55 m/s a 65 m/s?
What is the net work in J required to accelerate a 1500 kg car from 55 m/s to 65 m/s?
The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J
How do i determine the net work done?First, we shall obtain the initial kinetic energy. Details below:
Mass (m) = 1500 Kginitial velocity (u) = 55 m/sInitial kinetic energy (KE₁) =?KE₁ = ½mu²
= ½ × 1500 × 55²
= 41250 J
Next, we shall final kinetic energy. Details below:
Mass (m) = 1500 KgFinal velocity (v) = 65 m/sFinal kinetic energy (KE₂) =?KE₂ = ½mv²
= ½ × 1500 × 65²
= 3168750 J
Finally, we shall determine the net work done. Details below:
Initial kinetic energy (KE₁) = 41250 JFinal kinetic energy (KE₂) = 3168750 JNet work done (W) =?W = KE₂ - KE₁
= 3168750 - 41250
= 3127500 J
Thus, the net work done is 3127500 J
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What is the change in potential energy in moving a 10kg box from the floor to a table 1 m high?
Explanation:
potential energy formula is 1/2 mv2(this 2 is square).m means mass and v means velocity.
now, you can calculate
The change in potential energy in moving a 10kg box from the floor to a table 1 m high is 98 Joules.
To find the potential energy, the given values are,
Mass of the box = 10Kg
Height h = 1 m
What is Potential energy?The potential energy can be defined as the energy that is stored and that can be determined through various parts in a particular system.
Also, the energy will gets stored when the object is not moving.
For example: Spring. Even when the spring is not stretched or contracted it stores energy.
The formula for Potential energy PE= mgh joules.
m is the Mass,
g is the acceleration due to gravity = 9.8 m/s²,
h is the height.
Substituting all the given values,
Potential Energy= 10 (9.8)(1)
PE= 98 J
Thus the potential energy of the box= 98 J.
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No matter how far you stand from a mirror, your image appears erect. The mirror
may be:
a) plane
b) concave
c) convex
d) both a) and c).
Answer:
The answer to this question is option “d” that is either plane or convex.
Explanation:
The mirror can be either a plane mirror or a convex mirror, it cannot be concave.
In a convex mirror, one will always get the virtual size and smaller erect images of the objects seen reflected on it.
In a plain mirror, one can see the real size.
Answer:
d
Explanation:
plan and convex mirrors make ur image to be erect but concave is based on the object distance but the image will erect focal length and pole, have a great day!!!
An object A is placed 12cm in front of a concave mirror M₁ of focal length 8cm and a plane mirror M₂ is placed 30cm in front of the concave mirror as shown in Figure 1 The object A is first reflected by M₁and then reflected by M₂ to get an image 1₂. What is the distance between 1₂ and the object A?
According to the question the distance between the object A and the image 1₂ is 6 cm.
What is distance?Distance is the measure of how far apart two objects, points, or locations are from one another. Distance can be measured in linear units such as feet, meters, or kilometers, or angular units such as degrees. The concept of distance is a fundamental concept in mathematics, physics, and other sciences. Distance is used to calculate the speed and velocity of objects, as well as the force of gravity between two objects.
The distance between the object A and the image 1₂ can be calculated using the mirror equation.
Mirror equation: 1/d₁ + 1/d₂ = 1/f
Where d₁ is the object distance, d₂ is the image distance, and f is the focal length of the mirror.
In this case, d₁ = 12 cm, d₂ = ? and f = 8 cm.
Substituting these values into the equation gives us:
1/12 + 1/d₂ = 1/8
Rearranging the equation gives us:
1/d₂ = 1/8 – 1/12
Plugging in the values gives us:
1/d₂ = 1/8 – 1/12 = 1/6
Solving for d₂ gives us:
d₂ = 6 cm
Therefore, the distance between the object A and the image 1₂ is 6 cm.
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A scientist makes a model of Earth's water by drawing 100 drops of water, all the same size. How many of the 100 drops represent ocean water?
A.3
B.50
C.75
D.97
Answer:
D
Explanation:
If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)
Two objects have a gravitational force of attraction to each other, equal to 10 Newtons. What is their gravitational force if the distance between them is halved?
I have the answer, however I do not know how to get to it. Please explain.
The gravitational force when the distance between them is halved is 40 N
How to determine the gravitational force?Newton's law of universal gravity states as follow:
F = GM₁M₂ / r²
Where
F is the force of attraction K is the electrical constant M₁ and M₂ are the masses of the objects r is the distance apartFinding a relationship between force and distance, the following were obtained:
F = GM₁M₂ / r²
Cross multiply
Fr² = GM₁M₂
GM₁M₂ = constant
F₁r₁² = F₂r₂²
Now, we can obtain the new gravitational force of as illustrated below:
Initial gravitational force (F₁) = 10Initial distance (r₁) = rNew distance (r₂) = 1/2r = 0.5rNew gravitational force (F₂) =?F₁r₁² = F₂r₂²
10 × r² = F₂ × (0.5r)²
10r² = F₂ × 0.25r²
Divide both side by 0.25r²
F₂ = 10r² / 0.25r²
F₂ = 10 / 0.25
F₂ = 40 N
Thus, the gravitaional force is 40 N
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Which layer of the atmosphere is most likely to protect life on Earth from ultraviolet radiation
Answer:
ozone layer
Explanation:
The ozone layer forms a thin shield in the upper atmosphere protecting life on earth from UV rays. Ozone is a naturally occurring gas that is found in two layers of the atmosphere
A wave is traveling through a 40.0-meter-long cable strung with a tension of 35,000 newtons. The mass of this length of cable is 10.2 kilograms. What is the speed of a wave that is traveling in the cable?
Answer:7678
Explanation:
Two point charges have a total electric potential energy of -24 J, and are separated by 29 cm.
If the total charge of the two charges is 45 μC, what is the charge, in μC, on the positive one?
What is the charge, in μC, on the negative one?
Answer:
The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.
Explanation:
Electric potential energy between two point charges is derived from concept of Work, Work-Energy Theorem and Coulomb's Law and described by the following formula:
\(U_{e} = \frac{k\cdot q_{A}\cdot q_{B}}{r}\) (1)
Where:
\(U_{e}\) - Electric potential energy, measured in joules.
\(q_{A}\), \(q_{B}\) - Electric charges, measured in coulombs.
\(r\) - Distance between charges, measured in meters.
\(k\) - Coulomb's constant, measured in kilogram-cubic meters per square second-square coulomb.
If we know that \(U_{e} = -24\,J\), \(q_{A} = 45\times 10^{-6}\,C+ q_{B}\), \(k = 9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}}\) and \(r = 0.29\,m\), then the electric charge is:
\(-24\,J = -\frac{\left(9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}} \right)\cdot (45\times 10^{-6}\,C+q_{B})\cdot q_{B}}{0.29\,m}\)
\(-6.96 = -405000\cdot q_{B}-9\times 10^{9}\cdot q_{B}^{2}\)
\(9\times 10^{9}\cdot q_{B}^{2}+405000\cdot q_{B} -6.96 = 0\) (2)
Roots of the polynomial are found by Quadratic Formula:
\(q_{B,1} = 1.327\times 10^{-5}\,C\), \(q_{B,2} \approx -5.827\times 10^{-5}\,C\)
Only the first roots offer a solution that is physically reasonable. The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.
Simulate a blackbody spectrum of temperature 1700 Kelvin. Determine the peak wavelength in 3.22 nanometers of an object of that temperature nanometers What is the emissive intensity of the object
a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².
The relationship between the temperature,T and the peak wavelength, \(\lambda\) emitted by a black body is given by wien's displacement law:
\(\lambda\) = b / T
Where, b is a constant and it's value is 2.898 * 10-3 m-K
Given: T = 8400 K
So, \(\lambda\) = (2.898 * 10-3 )/8400
\lambda = 3.45 * 10-7
\lambda = 345 nm
Hence, the peak wavelength of the object at this temperature is 345 nanometre.
The amount of power emitted per unit area, P is given by Stefan Boltzmann law:
P =\(\sigma\)T⁴
Where,
Absolute temperature, T = 8400 K
Stefan Boltzmann constant, \(\sigma\) = 5.67 * 10-8 W/m²K⁴
So, P = 5.67 * 10-8 * (8400)⁴
P = 2.82 * 10⁸ W/m²
Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².
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What is the current in the 60.0 Q resistor? 120.0 V O A. 80.0 A B. 2.00 A O C. 1.50 A OD. 12.0 A 60.002 20.0 Q A
2A
Given ,
Resistance=60
V=12
V=IR
I=V/R
I=120/60=2A
The pace at which electrons flow past a location in a complete electrical circuit is defined as current. At its most fundamental, current Means flow.
An ampere (AM-pir), sometimes known as an amp, is the international unit for measuring current. It denotes the number of electrons (also known as "electrical charge") that pass across a location in a circuit over a specific time period.
A current of one ampere indicates that one coulomb of electrons—that is, 6.24 billion billion (6.24 x 1018) electrons—moves across a circuit in one second. The method is comparable to determining how many gallons move through a single spot in a pipe in one minute (gallons per minute, or GPM).
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HELP! IDENTIFY AND DRAW A CONCLUSION FOR THIS PROBLEM PLS! ASAP.
Answer:
the conclusion is that the plant that had been given fertilizer B grew more than the plant with fertilizer A and the plant without fertilizer. so in conclusion fertilizer B is better for growing plants fastly.
the problem is that you noticed your tomatoes were not growing properly.
Hope this helps!❤
feather is dropped from 13 m high after it has fallen 3 m what is its acceleration
Answer:
Explanation:
The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:
\(s(t)=-4.9t^2+13\) which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:
\(v(t)=-9.8t\). We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:
a(t) = -9.8
It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.