Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?

Answers

Answer 1

Answer:

The answer is 0.54 g/cm³

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question we have

\(density = \frac{10.5}{19.3} \\ = 0.54404145...\)

We have the final answer as

0.54 g/cm³

Hope this helps you


Related Questions

An airplane flies with a velocity of 750. kilometers
per hour, 30.0° south of east. What is the
magnitude of the eastward component of the
plane's velocity?
A. 866 km/h
B. 650. km/h
D. 375 km/h
C. 433 km/h

Answers

B. 650 km/h is the correct answer

The magnitude of velocity in east direction will be 650 N approximately.

What is velocity ?

velocity is given by the change in distance by the object with respect to change in time. It is a vector quantity and having S.I unit as m/s.

Here it is given that magnitude of velocity is 750 N and making an angle of 30 degree with x axis in counterclockwise direction as shown in figure below :

Now resolving and writing magnitude of velocity V in x and y direction respectively :

\(\begin{aligned}Vcos\theta&= 750 cos30^{o}=650 \:m/s\\Vsin\theta&= 750sin30^{o}= 375 m/s\end{aligned}\)

It should be noted that \(vsin\theta\) is acting in negative y direction.

Therefore, the magnitude of velocity in east direction is 650 m/s

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An airplane flies with a velocity of 750. kilometersper hour, 30.0 south of east. What is themagnitude

When a magnetic field is first turned on, the flux through a 20-turn loop varies with time according to Φm=5.0t2−2.0t, where Φm is in milliwebers, t is in seconds, and the loop is in the plane of the page with the unit normal pointing outward. (a) What is the emf induced in the loop as a function of time? What is the direction of the induced current at (b) t = 0, (c) 0.10, (d) 1.0, and (e) 2.0 s?

Answers

Answer:

A) ( - 200t + 40 ) volts

B)  b) anticlockwise ,  c) anticlockwise , d) clockwise ,  e) clockwise

Explanation:

Given data:

magnetic flux (Φm) = 5.0t^2 − 2.0t

number of turns = 20

a) determine induced emf

E = - N \(\frac{d\beta }{dt}\)

  =  - N ( 10t - 2 ) = - 20 ( 10t - 2 )

  =  - 200t + 40  volts

b) Determine direction of induced current

i) at t = 0

 E = - 0 + 40  ( anticlockwise direction )

ii) at t = 0.10

E = -20 + 40 =  20 ( anticlockwise direction )

iii) at t = 1

E = - 200 + 40 = - 160 ( clockwise direction)

iv) at t = 2

E = -400 + 40 =  - 360 ( clockwise direction )

Assume an AC circuit with parallel RLC elements operating in a steady state. If each
branch is carrying 10 A then find out total current? If the voltage source is 230 V and 50
Hz then find values of R, L and C.

Answers

To find the total current in the AC circuit with parallel RLC elements, we need to calculate the impedance of each branch and then apply the rules for combining parallel impedances.

The impedance of each branch in a parallel RLC circuit can be calculated as follows:

1. For the resistor (R): The impedance (Z_R) of a resistor in an AC circuit is equal to its resistance (R). Therefore, Z_R = R.

2. For the inductor (L): The impedance (Z_L) of an inductor in an AC circuit is given by Z_L = jωL, where j is the imaginary unit, ω is the angular frequency (2πf), and L is the inductance.

3. For the capacitor (C): The impedance (Z_C) of a capacitor in an AC circuit is given by Z_C = 1/(jωC), where C is the capacitance.

The total current (I_total) can be calculated by summing the currents in each branch: I_total = I + I + I (three branches in parallel)

Now, By performing the necessary calculations using the given values, we can determine the specific values of R, L, and C for the parallel RLC circuit.

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Astronomers observe a spectral analysis of a distant star where a particular element has a spectral line with a wavelength of 663 nm. In the laboratory, the same element has a spectral line with a wavelength of 645 nm.
a. How fast is the star moving, and in what direction is it moving?

b. The same element on Earth’s surface is observed from a space shuttle orbiting at 7800 m/s,
350 km above Earth. Is the same shift in the spectral line seen from the space shuttle? Why or why not?

Answers

Answer:

(a). The velocity of star is \(8.1\times10^{6}\ m/s\) and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

Explanation:

Given that,

Wavelength of spectral line = 663 nm

Wavelength of spectral line in lab = 645 nm

(a). We need to calculate the velocity

Using doppler's effect

\(\Delta \lambda=\dfrac{v}{c}\lambda\)

Where, \(\Delta\lambda\)= change in wavelength

v = velocity

c = speed of light

Put the value into the formula

\(663-645=\dfrac{v}{3\times10^{8}}\times663\)

\(v=\dfrac{3\times10^{8}(663-645)}{663}\)

\(v=8144796.38\ m/s\)

\(v=8.1\times10^{6}\ m/s\)

The direction of star toward the earth.

(b). Speed = 7800 m/s

We need to calculate the shift

Using formula of shift

\(\Delta \lambda=\lambda(\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}-1)\)

Put the value into the formula

\(\Delta \lambda=645\times(\sqrt{\dfrac{1+\dfrac{7800}{3\times10^{8}}}{1-\dfrac{7800}{3\times10^{8}}}}-1)\)

\(\Delta\lambda=0.0168\ nm\)

This shift is small compare to the the movement of Earth around the sun.

Hence, (a). The velocity of star is \(8.1\times10^{6}\ m/s\) and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

A student is testing a 1.0 m length of 4.0-mm-diameter steel wire Part A How much force is required to stretch this wire by 1.0 mm? Young's modulus for steel is 10 N/m2 Express your answer to two significant figures and include the appropriate units. F 2500 N Submit My Answers Give Up Correct Part B What length of 8.0-mm-diameter wire would be stretched by 1.0 mm by this force? Express your answer to two significant figures and include the appropriate units

Answers

The force required to stretch the wire by 1.0 mm is approximately 0.00013 N. Length of approximately 0.0039 m or 3.9 mm of the 8.0-mm-diameter wire would be stretched by 1.0 mm with a force of 0.00013 N.

Part A:

To calculate the force required to stretch the wire by 1.0 mm, we can use Hooke's Law, which states that the force required to stretch or compress a material is directly proportional to the displacement or change in length.

The formula to calculate the force is:

F = (Y * A * ΔL) / L

F is the force

Y is Young's modulus

A is the cross-sectional area of the wire

ΔL is the change in length of the wire

L is the original length of the wire

First, we need to calculate the cross-sectional area of the wire:

A = π * (r²)

r is the radius of the wire, which is half of the diameter.

r = 4.0 mm / 2 = 2.0 mm = 0.002 m

A = π * (0.002 m)²

A ≈ 0.000012566 m²

ΔL = 1.0 mm = 0.001 m

L = 1.0 m

Y = 10 N/m²

Plugging the values into the formula:

F = (10 N/m² * 0.000012566 m² * 0.001 m) / 1.0 m

F ≈ 0.00012566 N

Rounded to two significant figures:

F ≈ 0.00013 N

Therefore, the force required to stretch the wire by 1.0 mm is approximately 0.00013 N.

Part B:

To calculate the length of the 8.0-mm-diameter wire that would be stretched by 1.0 mm with this force, we can rearrange the formula used in Part A to solve for L.

L = (Y * A * ΔL) / F

r = 8.0 mm / 2 = 4.0 mm = 0.004 m

A = π * (0.004 m)² = 0.000050265 m²

ΔL = 1.0 mm = 0.001 m

F = 0.00013 N (from Part A)

Plugging the values into the formula:

L = (10 N/m² * 0.000050265 m² * 0.001 m) / 0.00013 N

L ≈ 0.00386 m

Rounded to two significant figures:

L ≈ 0.0039 m

Therefore, a length of approximately 0.0039 m or 3.9 mm of the 8.0-mm-diameter wire would be stretched by 1.0 mm with a force of 0.00013 N.

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whats the difference between transverse and longitudinal waves?

Answers

Answer:

longitudianl particles are dispelled parrell

Explanation:

transverse perpendicular

An object has a weight of 755 Newtons. Determine what the mass of this
object is. Weight (N) = mass (kg) xg (9.8 m/s/s) *
=
0 7400 kg
O 77 kg
O 765 kg
04530 kg
O 75,5 kg

Answers

Answer:

75.5 kg

Explanation:

w=mg

755= m × 10

m = 75.5

PLS ANSWER CORRECTLY ASAP. What moon phase is 1 WEEK BEFORE first quarter moon? And what moon phase is 1 WEEK AFTER first quarter moon?

I have attached a picture below as well..

PLS ANSWER CORRECTLY ASAP. What moon phase is 1 WEEK BEFORE first quarter moon? And what moon phase is

Answers

Answer:

waxing cresent and waxing gibbous

Answer:

i think it is the full moon

Explanation:

tell me if am wrong

10)
The population of humans living on the Earth has increased tremendously due to scientific discoveries and technology. Which
statement BEST summarizes how science and technology have contributed to human population growth?
A)
Science and technology have increased the human birth rate.
B)
Science and technology have been crucial in opening up new areas for
human development.
Science and technology have allowed for an increased emphasis on
education and the arts.
C)
D)
Science and technology have increased food and reduced death rates due
to illness and malnutrition.

Answers

The correct answer would be

D. Science and technology have increased food and reduced death rates due to illness and malnutrition.

I took this on USATestPrep, it's 100% right

weathering can be either chemical or physical process that action of water causes physical weathering rocks which examples

Answers

Frost wedging is a type of physical weathering of rock.

Explanation:

Physical or mechanical weathering affects the rock structurally but does not change the chemical composition. Mechanical forces will rub, break or shatter the rock surfaces. Wedging, abrasion, exfoliation are different types of physical weathering.

Water is one of the main sources which alter the structure of the rocks physically.

Frost wedging occurring due to flow of freezing water over the rocks. This frozen water enters the rock through the cracks and crevices on the rock surface,  and will expand inside and makes the rocks to crack further and breaks it apart.

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(T/F) Time series data can exhibit seasonal patterns of less than one month in duration

Answers

True, Time series data can exhibit seasonal patterns of less than one month in duration is True

Seasonal patterns refer to a predictable and repeated pattern that occurs within a specific time frame. Time series data can exhibit these patterns, and they can have durations of less than one month. For instance, a sales data set may show a predictable increase in sales every week due to a specific event or promotion.

Time series data can exhibit seasonal patterns of less than one month in duration. Seasonality refers to the recurring patterns observed in the data over time. These patterns can be of any duration, not limited to monthly or yearly occurrences. For instance, weekly or daily patterns are also considered seasonal patterns.

Time series data can indeed exhibit seasonal patterns of less than one month in duration, as seasonal patterns are not limited to monthly or yearly occurrences.

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Urgent! Two people are biking towards each other. Biker A is moving at 2 m/s east, and Biker B is 10 m east of Biker A, biking towards them at 3 m/s west. How long does it take the two to pass by each other?

Answers

Answer:

see below

Explanation:

I will assume you made  a typo error and use 10 km rather than 10 m  

Closing speed is  2 + 3 = 5 m/s

  they will cover the 10 km (?) in    10 km / 5 m/s = 10000m /5 m/s =

                   2000 seconds =   33 min and 20 sec

Electricity is defined by the following: energy made through the use of heat through a window. energy made by burning material energy made by the flow of electrical current through a conductor

Answers

Electricity is defined as the flow of electrical current through a conductor.

A fundamental type of energy that is produced by the presence and movement of electric charge is electricity. The passage of electrons or other charged particles across a conductor, like a wire, is what defines the phenomena. It includes the creation, transmission, and use of electric energy, as well as the full field of electric phenomena.

Therefore,

Electricity is defined as the flow of electrical current through a conductor.

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Thunder is caused by the compression of free photons in the lightning bolt O high temperatures of lightning heat the surrounding air, causing it to expand explosively. o the combustion of flammable atmospheric gasses by the lightning bolt. o the compression of free neutrons in the lightning bolt the compression of free electrons in the lighting bolt

Answers

Thunder is caused by the rapid expansion of air surrounding a lightning bolt due to high temperatures of the lightning.

The correct statement is: Thunder is caused by the rapid expansion of air surrounding a lightning bolt due to high temperatures of the lightning, which leads to an explosive compression and subsequent release of sound waves.

When a lightning bolt occurs, it generates an immense amount of heat, reaching temperatures hotter than the surface of the Sun. This intense heat rapidly heats the surrounding air, causing it to expand explosively. The sudden expansion of air creates a shock wave that propagates through the atmosphere, resulting in the characteristic booming sound we hear as thunder.

It is important to note that thunder is not directly caused by the lightning itself. Rather, it is a byproduct of the rapid heating and subsequent expansion of the air molecules in the lightning's path. The sound waves generated by the expanding air travel through the atmosphere, reaching our ears as the familiar rumble of thunder.

The other options mentioned - compression of free photons, combustion of flammable atmospheric gases, and compression of free neutrons or electrons - are not accurate explanations for the cause of thunder. Thunder primarily arises from the rapid expansion and contraction of air due to the intense heat produced by a lightning discharge.

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Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.

Answers

Answer:

Velocidad final, V = 8 m/s

Explanation:

Dados los siguientes datos;

Velocidad inicial, u = 4 m/s

Aceleración, a = 2 m/s²

Tiempo, t = 2 segundos

Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;

V = u + at

Sustituyendo en la fórmula, tenemos;

V = 4 + 2*2

V = 4 + 4

Velocidad final, V = 8 m/s

I n it in 20 minutes
JL.61 A producer of refrigerator compressors wants to implement
a just-in-time production line to support demand from a neighboring
appliance manufacturer. Demand from the applian

Answers

The producer of refrigerator compressors needs to determine the number of kanbans required for implementing a just-in-time production line to meet the demand for 150 compressors per day from a neighboring appliance manufacturer.

To calculate the number of kanbans required, we need to consider the production lead time, safety stock factor, and optimal production quantity. The production lead time is 5 days, which means that it takes 5 days to produce a batch of compressors once the production process starts.

The safety stock factor is 17%, indicating that the producer wants to maintain an additional 17% of the daily demand as safety stock to mitigate any unforeseen fluctuations. The optimal production quantity is 95 units, which is the batch size that minimizes setup costs.

To determine the number of kanbans, we first need to calculate the total demand during the production lead time. Since the demand is 150 compressors per day and the lead time is 5 days, the total demand during the lead time is 150 compressors/day * 5 days = 750 compressors. Adding the safety stock, the total demand becomes 750 compressors + (17% * 150 compressors) = 750 compressors + 25.5 compressors = 775.5 compressors.

Next, we divide the total demand by the optimal production quantity to get the number of kanbans required. The number of kanbans is calculated as 775.5 compressors / 95 compressors per kanban = 8.16 kanbans. Since we cannot have a fraction of a kanban, we round up to the nearest whole number. Therefore, the producer of compressors requires 9 kanbans to meet the demand of 150 compressors per day from the neighboring appliance manufacturer.

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The complete question is:

A producer of refrigerator compressors wants to implement a just-in-time production line to support demand from a neighboring appliance manufacturer. Demand from the appliance manufacturer is for 150 compressors a day. The production lead time is 5 days and the producer wants to have a 17% safety stock factor. This producer has also cut setup costs such that the optimal production quantity is 95 units. How many kanbans does this producer of compressors require?

PLEASE HELP ME, IM STUCK ON THIS QUESTION

PLEASE HELP ME, IM STUCK ON THIS QUESTION

Answers

Answer:

the correxct adnswer is d

Explanation:

lol

Which of the following is a characteristic of a mechanical wave but not a characteristic of an electromagnetic wave?

Answers

Mechanical waves have a crest but no trough is a characteristic of a mechanical wave but not a characteristic of an electromagnetic wave.

What is an electromagnetic wave?

The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.

Mechanical waves have a peak but no dip, which is a mechanical wave characteristic but not an electromagnetic wave characteristic.

Hence, mechanical waves have a crest but no trough is a characteristic of a mechanical wave but not a characteristic of an electromagnetic wave.

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Hw2b. 8. Position from polar velocity a particle starts at time at the position the velocity of the particle is written in the polar basis associated with its current position, and is: what is the position of at ?

Answers

The particle's location vector at time t is given by: r(t) = t³ + t² + 1

As per the question, we have the velocity of the particle in polar coordinates, but we need to find the position of the particle at time t. To do this, we need to integrate the velocity vector to obtain the position vector.

Let's consider the given velocity vector:

v(t) = (3t² + 2t)i + (2t² + 3t)j

To integrate this velocity vector, we need to find the corresponding position vector. Since the velocity vector is given in polar coordinates, we can express it in terms of polar variables:

v(t) = r'(t) + r(t)θ'(t)

where r'(t) and θ'(t) are the radial and angular components of the velocity vector, respectively.

By comparing the given velocity vector with the above equation, we can write:

r'(t) = 3t² + 2t

θ'(t) = (2t²+ 3t)/r(t)

Integrating r'(t) with respect to t, we get:

r(t) = t³ + t² + C

where C is the constant of integration.

To determine the value of C, we need to use the initial condition given in the problem. The particle starts at the position r = 1 and θ = π/4 at time t = 0. This implies:

r(0) = 1

θ(0) = π/4

Substituting these values in the equation for r(t), we get:

1 = 0 + 0 + C

C = 1

Therefore, the position vector of the particle at time t is given by:

r(t) = t³ + t² + 1

To find the value of θ at time t, we integrate θ'(t) with respect to t:

θ(t) = ∫(2t² + 3t)/r(t) dt

= ∫(2t² + 3t)/(t³ + t² + 1) dt

This integral is not trivial to solve analytically. Therefore, the position of the particle at time t can be expressed as:

r(t) = (t³ + t² + 1)i + f(t)j

where f(t) is the solution of the above integral for θ(t).

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If the altitude of the North Star is 30º above the horizon, then what is the highest altitude that the Sun will reach during the Autumnal Equinox:
__________degrees

Answers

If the altitude of the North Star is 30º above the horizon, then the highest altitude that the Sun will reach during the Autumnal Equinox: is 60 degrees

What is the  Autumnal Equinox?

The sun shines squarely on the equator at the autumnal equinox, giving both the northern and southern hemispheres an equal quantity of sunlight.

The start of the fall season is signaled by the autumnal equinox, a natural occurrence that takes place in late September every year. The celestial equator coincides with the equator of Earth, such that day and night are of equal length.

It would be 30 degrees north latitude if you could see Polaris at 30 degrees above the horizon. Now, if a star reaches its highest point at a place below the observer's zenith, its latitude is equal to 90 - star altitude.

90 - 30 = 60 degrees

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A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origin and thereafter has an acceleration given by a = (4.0 m/s2)i-(3.0 m/s2)j. The torque, relative to the origin, acting on it at the end of 2.0 s is: (Torque as a Vector) a. 0 b. (-18N m)k c. (+24 N m)k d. (-144 N m)k e. (+144 N m)k

Answers

The angular momentum is constant in this case (no external torque is acting on the block), the torque is zero.

If the acceleration of the block was given by a = (3.0 m/s²)i + (4.0 m/s²)j, what would be the torque acting on it at the end of 2.0 seconds?

To find the torque acting on the block, we first need to find the angular momentum of the block relative to the origin at the end of 2.0 seconds.

The angular momentum of an object is given by the cross product of its position vector and its momentum vector, which can be expressed as:

L = r x p

where L is the angular momentum, r is the position vector, and p is the momentum vector.

In this case, the block starts from rest, so its initial momentum is zero.

We only need to consider the momentum of the block after it has accelerated for 2.0 seconds.

The velocity of the block after 2.0 seconds can be found using the kinematic equation:

v = v0 + at

where v0 is the initial velocity (zero), a is the acceleration, and t is the time elapsed.

Substituting the given values, we get:

v = (4.0 m/s2)(2.0 s)i - (3.0 m/s2)(2.0 s)j

v = 8.0 m/s i - 6.0 m/s j

The momentum of the block can then be calculated as:

p = mv

p = (2.0 kg)(8.0 m/s)i - (2.0 kg)(6.0 m/s)j

p = 16.0 kg m/s i - 12.0 kg m/s j

Next, we need to find the position vector of the block relative to the origin. Since the block starts 3.0 m from the origin on the positive x-axis, its position vector after 2.0 seconds can be expressed as:

r = (3.0 m + 8.0 m/s(2.0 s))i

r = 19.0 m i

Finally, we can calculate the angular momentum of the block relative to the origin:

L = r x p

L = (19.0 m i) x (16.0 kg m/s i - 12.0 kg m/s j)

L = (19.0 m)(-12.0 kg m/s) k

L = -228.0 N m k

Since torque is defined as the time derivative of angular momentum, we can find the torque acting on the block as:

τ = dL/dt

The angular momentum is constant in this case (no external torque is acting on the block), the torque is zero.

The answer is (a) 0.

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Please someone help!!!

Please someone help!!!

Answers

I know it’s the Coulomb’s law and that I’m pretty sure the answer would be C.Inverse Square.

imagine a visual scene of a landscape. in the sky, you see big, soft clouds darkening as a storm approaches. these clouds represent ______________ spatial frequencies.

Answers

The big, soft clouds darkening as a storm approaches in the visual scene represent low spatial frequencies.

Spatial frequency refers to the rate of change of intensity or color in an image across space. It is commonly associated with the level of detail or fine-grained texture in a visual scene. In this case, the description of big, soft clouds darkening as a storm approaches suggests a decrease in fine details and a more uniform appearance, indicating a dominance of low spatial frequencies.

Low spatial frequencies correspond to large-scale variations in an image. They represent smooth and slowly changing features such as broad contours, large objects, and overall patterns. In the context of clouds, low spatial frequencies would capture the overall shape, size, and general structure of the cloud masses as they darken before a storm.

The darkening of the clouds may result from increased cloud thickness or the presence of rain or other atmospheric conditions associated with a storm. These factors can reduce the amount of light scattering through the cloud, resulting in decreased brightness and contrast, which further emphasizes the low-frequency content in the visual scene.

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Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, and E, in a straight line across the path of flow. A and E are closest to the edges of the glacier. C is in the center of the glacier. B and D are between A and C and C and E respectively. How would the scientists predict the motion of each of the markers relative to the edges of the valley down which the glacier flows? What pattern would they predict in the markers over time?

Answers

Answer: c a d b

Explanation:

Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers thus, The pattern they predict in the markers over time would be C D A B.

How would the scientists predict the moving glacier of the markers relative to the edges of the valley down which the glacier flows?

In some parts of the world, glaciers are an important natural resource because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.

Due to this, Glaciologists monitor and try to predict the movement and morphology of glaciers.

One of the techniques used by "Glaciologists" in the monitoring and prediction of glaciers in the use of markers.

The movement of markers is measured relative to the edges of the valley down which the glacier flows.

Thus, The movement of the markers are then predicted using the GlenNye Flow Law.

The pattern they predict in the markers over time would be C D A B.

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The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?

Answers

Answer:

43.83 nC

Explanation:

We know Q = ε₀Ψ where Q = charge enclosed by the cubic box,  ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C

So, substituting the values of the variables into the equation, we have

Q = ε₀Ψ

= 8.854 × 10⁻¹² F/m × 4950 Nm²/C

= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C

= 43.8273 × 10⁻⁹ C

= 43.8273 nC

≅ 43.83 nC

what is the mass of an object that experiences an acceleration of 15m/s/s when a force of 45 n is applied to it?

A- 3kg
B- 675 N
C- .33m/s/s
D- 60kg​

Answers

Explanation:

Force= mass × acceleration

45 N = mass × 15 m/s/s

45/15 kg = mass

3kg = mass

A box having a mass of 1.5 kg is accelerated across a table at 1.5 m/s2. The coefficient of friction on the box is 0.3. What is the force being applied to the box? If this force were applied by a spring, what would the spring constant have to be in order for the spring to be stretched to only 0.08 m while pulling the box?

Answers

To determine the force being applied to the box, we can use Newton's second law of motion:

Force = mass x acceleration

Plugging in the given values, we get:

Force = 1.5 kg x 1.5 m/s²

Force = 2.25 N

Therefore, the force being applied to the box is 2.25 N.

To find the spring constant required to stretch the spring only 0.08 m while pulling the box, we can use Hooke's law:

Force = spring constant x displacement

Plugging in the given values, we get:

2.25 N = k * 0.08 m

Solving for the spring constant, we get:

k = 2.25 N / 0.08 m

k = 28.125 N/m

Therefore, the spring constant would have to be 28.125 N/m in order for the spring to be stretched to only 0.08 m while pulling the box with a force of 2.25 N.

Las turbinas que funcionan en la empresa tarjeta ¿Que tipo de energía se utiliza para hacerlas girar?

Answers

Answer:

Energía cinética.

Explicación:

La energía cinética es un tipo de energía que se utiliza para hacer girar la turbina. La energía cinética que está presente en el fluido o el viento obliga a girar la turbina que convierte esta energía y conduce a la generación de energía eléctrica. Cuando el viento o el fluido en movimiento toca las palas de la turbina, provoca la rotación de la turbina y, debido a esta rotación, los generadores conectados a la turbina también inician un movimiento que produce energía eléctrica.

Protons and electrons are ejected from the sun in large quantities. These charge particles, that travel to the earth from the sun along with electromagnetic radiation, are called the solar wind. The solar wind penetrates the atmosphere of the earth much more at the geopmagnetic north and south poles than anywhere else on the earth. Why

Answers

The solar wind penetrates the Earth's atmosphere much more at the geomagnetic north and south poles due to the configuration of Earth's magnetic field lines.

Earth's magnetic field is generated by its core and creates a protective shield called the magnetosphere. This shield is important because it deflects harmful solar wind particles away from Earth's atmosphere. The magnetic field lines are shaped like loops that extend from the geomagnetic north and south poles. The field lines are more concentrated and closer to the Earth's surface at the poles, which allows solar wind particles to follow these lines and penetrate deeper into the atmosphere at the poles compared to other regions. This increased penetration at the poles is what causes phenomena such as auroras, where charged particles interact with the Earth's atmosphere to create beautiful light displays.

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A 50. -kilogram woman wearing a seat belt is traveling in a car that is moving with a velocity of +10. Meters per second. In an emergency, the car is brought to a stop in 0. 50 second. What force does the seat belt exert on the woman so that she remains in her seat?.

Answers

The force exerted on the woman by the seat belt is equal to 50 kg x 20 m/s2 = 1000 N.

What is force?

Force is a push or pull that acts upon an object, causing it to accelerate or change direction. It is an influence that can cause an object to change its motion, direction, shape, or even energy. Force can be generated through direct physical contact, or it can be generated from a distance, such as when a magnet pulls on a piece of metal. Forces are measured in newtons, and the SI unit for force is the Newton (N).

The force exerted on the woman by the seat belt is equal to her mass times the acceleration experienced by the car. The acceleration of the car is equal to the change in velocity (10 m/s) divided by the time it took for the car to stop (0.50 s), which is equal to 20 m/s2. Therefore, the force exerted on the woman by the seat belt is equal to 50 kg x 20 m/s2 = 1000 N.

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