Simplify the following expression.

5+((2*5) -7)^2 -9

Your answer:

1


5


-4


16

(HELP PLEASE!!!)

A B E are the answers

The Composite Trapezoidal rule is used to approximate the given integrals. In part (a), the integral \(\( \int_{1}^{2} x \ln x \, dx \)\) is approximated using \(\( n = 4 \)\)subintervals. In part (b), the integral\(\( \int_{2}^{2} x^{3} e^{x} \, dx \)\) is given with incorrect limits, so it cannot be evaluated.

To approximate \(\( \int_{1}^{2} x \ln x \, dx \)\) using the Composite Trapezoidal rule, we divide the interval \(\([1, 2]\) into \( n = 4 \)\) subintervals. The step size, \(\( h \)\), is calculated as\(\( h = \frac{b-a}{n} = \frac{2-1}{4} = \frac{1}{4} \)\). Then, we evaluate the function \(\( x \ln x \)\)at the endpoints of each subinterval and sum the areas of the trapezoids formed. The approximation formula for the Composite Trapezoidal rule is: \(\[\int_{a}^{b} f(x) \, dx \approx \frac{h}{2} \left[ f(a) + 2\sum_{i=1}^{n-1} f(x_i) + f(b) \right]\]\)

Using this formula, we can calculate the approximation for the given integral. The limits of the integral \(\( \int_{2}^{2} x^{3} e^{x} \, dx \)\) are given as \(\( 2 \)\) to 2 which indicates an interval of zero length. In this case, the integral cannot be evaluated since there is no interval over which to integrate.

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These standardization methods are crucial in chromatography to ensure accurate quantification and comparability of results.

In chromatography, standardization methods are used to ensure accurate and reliable results by establishing reference points or calibration standards. Here are three common methods of standardization in chromatography: External Standardization: In this method, a set of known standard samples with known concentrations or properties is prepared separately from the sample being analyzed. These standards are then analyzed using the same chromatographic conditions as the sample. By comparing the response of the sample to that of the standards, the concentration or properties of the sample can be determined. Internal Standardization: This method involves the addition of a known compound (internal standard) to both the standard solutions and the sample. The internal standard should ideally have similar properties to the analyte of interest but be different enough to be easily distinguished. The response of the internal standard is used as a reference to correct for variations in sample preparation, injection volume, and instrumental response. Internal standardization helps improve the accuracy and precision of the analysis. Standard Addition: This method is useful when the matrix of the sample interferes with the analysis or when the analyte concentration is unknown. It involves adding known amounts of the analyte of interest to different aliquots of the sample. The response of the analyte is then measured, and the concentration is determined by comparing the response with that of the standards. The difference in response between the sample and the standards allows for the determination of the analyte concentration in the original sample.

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x^2 +3x = x ( x + 3 )

2x^2+9x+5 = − ( 2 x + 1 ) ( x − 5 )

Hope this helps you!

Hope you have a good day, Loves!

Also if I'm right can you let me know, please?

Also Also if I am right can I please have Brainliest??

You don't need to, I'm just glad I could help. ^^

Answer:

13

Step-by-step explanation:

a + b = 6 and a - b = 4

Add the two equations together

a + b = 6

a - b = 4

----------------

2a = 10

Subtract the two equations

a + b = 6

- a + b = -4

----------------

2b = 2

b =1

Multiply by 3

3b =3

2a +3b

we know 2a = 10 and 3b = 3

10+3

13

Step-by-step explanation:

Given the expression

\(-3m - [2m + (5 - m)] + 7\)

Step one

Firstly we have to open the inner bracket we have

\(-3m - [2m + 5 - m] + 7\)

Step two

we proceed further by opening up the next bracket we have

\(-3m - 2m -5 +m+ 7\)

Step three

we then have to collect like terms of m and rearrange.

\(=-3m - 2m+m -5+ 7\\=-4m+2\\=2-4m\)

Answer:

I don't know but I will advise you to use microsoft maths solver

Area = 19.25in²

Area of a triangle

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry.

A triangle with vertices A, B, and C is denoted △ABC.

The area of a triangle is given as

1/2 x b x h

where b is the length of the base of the triangle, and h is the height/altitude of the triangle.

Assuming it is a right angled triangle.

Given the measure of the sides of the triangle, we can take the longest side to be the Hypotenuse (7in) and the shortest side to be the Opposite (2in)

This will leave us with a base of 5.5in

given the area of a triangle as 1/2 x b x h

1/2 x 7 x 5.5

= 19.25in²

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In a competitive market, we need to graph the market demand and supply curves and determine the equilibrium quantity. The equilibrium quantity represents the quantity at which the demand and supply curves intersect.

To sketch the supply and demand curves, we first need to gather information on the market demand and supply. The demand curve represents the quantity of ventilators that the four hospitals are willing to purchase at different prices, while the supply curve represents the quantity of ventilators that the four producers are willing to sell at different prices.

Using the multipoint drawing tool, we can plot the market demand curve based on the data provided for the hospitals. Label this line as 'Demand'. Next, using the same tool, we can plot the market supply curve based on the data provided for the producers. Label this line as 'Supply'.

The equilibrium quantity is determined at the point where the demand and supply curves intersect. It represents the quantity of ventilators that will be sold in the market. To find this point, we identify the quantity at which the demand and supply curves meet on the graph.

By following the instructions and accurately plotting the demand and supply curves, we can determine the equilibrium quantity of ventilators sold in the market.

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He will break even on the 25th month.

The cost to start the business is $20,000 and the monthly costs are $8,000.

He has been earning $8,800 every month in revenue.

Profit = Selling Price - Cost Price

Therefore,

let

x = number of month

Hence,

selling price = 8800x

cost price = 20000 + 8000(x) = 20,000 + 8000x

Therefore,

profit =  8800x - (20,000 + 8000x)

profit = 8800x - 20000 - 8000x

profit = 8800x - 8000x - 20000

profit = 800x - 20000

Hence,

The month when they will break even is as follows:

8800x = 20,000 + 8000x

20000 = 8800x - 8000x

20000 = 800x

x = 20000 / 800

x = 25

Therefore, he will break even on the 25th month.

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The electric force experienced by a charge Q1 due to the presence of another charge Q2 located at a distance r from Q1 is given by the Coulomb’s Law as:

F = (1/4πε0) (Q1Q2/r²)

where ε0 is the permittivity of free space and is equal to 8.854 x 10⁻¹² C²/Nm²

Given : Charge Q1 = 4 uCCharge Q2 = 8 uC - (-8 uC) = 16 uC

Distance between Q1 and Q2 = (6² + 2²)¹/²

= (40)¹/² cm

= 6.3246 cm

Substituting the given values in the Coulomb’s Law equation : F = (1/4πε0) (Q1Q2/r²)

F = (1/4π x 8.98755 x 10⁹ Nm²/C²) (4 x 10⁻⁶ C x 16 x 10⁻⁶ C)/(6.3246 x 10⁻² m)²

F = 6.21 x 10⁻⁵ N

Answer: The force experienced by a charge of 4 uC on the x-axis at x = 6 cm is 6.21 x 10⁻⁵ N.

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RESPUESTA: no es un triangulo

EXPRICACION

The sum of any two sides must be greater than the other to be it triangle thus it will not be a triangle so option (D) is correct.

A triangle is a 3-sided shape that is occasionally referred to as a triangle. There are three sides and three angles in every triangle, some of which may be the same.

The sum of all three angles inside a triangle will be 180°.

For any triangle, the sum of any two sides must be greater than the then third side.

As per the given sides,  11, 13, 25

11 + 13 < 25

24 < 25 so it will not a triangle.

Hence "The sum of any two sides must be greater than the other to be it triangle thus it will not be a triangle".

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The 90% confidence interval obtained from examining 653 customers in one fast food chain's drive-through has a lower bound of 178.2 seconds and an upper bound of 181.6 seconds. This means that based on the sample data collected from the 653 customers, we can be 90% confident that the true average drive-through service time for this fast food chain falls within the range of 178.2 seconds to 181.6 seconds.

In other words, if we were to repeatedly sample 653 customers from the same fast food chain's drive-through and calculate confidence intervals, approximately 90% of those intervals would contain the true average service time of the entire population of customers.

The range between the lower and upper bounds of the confidence interval provides an estimate of the precision or uncertainty associated with our sample mean.

The narrower the interval, the more precise our estimate of the true population mean becomes. In this case, the interval is relatively narrow, indicating a relatively precise estimate of the average drive-through service time for this fast food chain based on the sample data.

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Answer:

2 bus

Step-by-step explanation:

The expected value of y is larger than the expected value of x. This is because y takes into account the number of students on all 4 buses, while x only takes into account the students on the bus with the randomly selected student.

The expected value of a random variable represents the average value of that variable over multiple trials. In this case, x is a random variable representing the number of students on the bus carrying the randomly selected student, and y is a random variable representing the number of students on the randomly selected bus.

The expected value of x can be calculated as follows:

E[x] = (10/100)×10 + (20/100)×20 + (30/100)×30 + (40/100)×40

= 16 + 12 + 9 + 16

= 53/4

= 13.25

This means that, on average, the bus carrying the randomly selected student would have 13.25 students.

The expected value of y can be calculated as follows:

E[y] = (1/4)×10 + (1/4)×20 + (1/4)×30 + (1/4)×40

= 25

This means that, on average, the randomly selected bus would have 25 students.

As expected, the expected value of y is larger than the expected value of x. This is because y takes into account the number of students on all 4 buses, while x only takes into account the students on the bus with the randomly selected student. Since the number of students on the other 3 buses can vary widely, y has a higher expected value than x.

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Answer:

(2,7) x=2 y=7

Step-by-step explanation:

An expression for the sequence of operations described "Subtract three from the product of seven and eight." is (7 × 8) - 3.

In order to evaluate and solve this expression, we would have to apply the PEMDAS rule, where mathematical operations within the parenthesis (grouping symbols) are first of all evaluated, followed by exponent, and then multiplication or division from the left side of the equation to the right. Lastly, the mathematical operations of addition or subtraction would be performed from left to right.

Based on the information provided, we have the following mathematical expression:

Expression: (7 × 8) - 3

56 - 3

53

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Answer:

12(a) 4(x+19)=752 (b) 169

Step-by-step explanation:

12(a) 4(x+19)=752

   (b) 4(x+19)=752

        4x+76=752

               4x=676

                 x=169

a. The equation representing the situation is 4(x+19)=752

b. The price of one ticket is $169

It is important to note that algebraic expressions are defined as expressions consisting of terms, coefficients, constants, factors and variables

They are also made up of mathematical operations are;

From the information given, we have that;

Let x be the price ticket

This is then represented as;

4(x+19)=752

expand

4x + 76 = 752

collect the like terms

4x = 676

Divide by the coefficient

x = $169

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I do not have any information about you or your beliefs, experiences, or actions.. I do not have the ability to make judgments or assumptions about you or any other individual, you should provide more context as well as fix the category your question is listed under, you might have better results.

The equation 3x² - 12x - 15 = 0 when solved by factoring has the solutions x = 5 and x = -1

The equation 3x² - 12x - 15 = 0, is a representation of the equation in the question.

The aforementioned problem is a quadratic equation, and factoring is one way to solve this kind of issue.

Divide 3 from the equation.

As a result, we have the following

x² - 4x - 5 = 0.

Expanding the equation, we get

x² + x - 5x - 5 = 0.

Factoring the equation, we get

x(x + 1) - 5(x + 1) = 0

The result is

(x - 5)(x + 1) = 0.

We can solve for x by getting

x = 5 and x = -1.

Thus, the equation's answers are 5 and -1.

And it means that there are actually two solutions to the equation.

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The minimum wage set by the government at $7.50 per hour does not result in a pay cut for unskilled workers, as it is below the equilibrium wage of $8.00 per hour.

The wage rate remains unchanged, and the labor market remains in balance.

The statement is false.

False.

The equilibrium wage in the market for unskilled labor is $8.00 per hour, which means that the market naturally sets the wage rate at this level, based on the forces of supply and demand.

The government then sets a minimum wage at $7.50 per hour.

Since the minimum wage is below the equilibrium wage, it does not directly impact the wage rate for unskilled workers.
The equilibrium wage represents the point at which the supply of labor (the number of workers willing to work at a given wage) equals the demand for labor (the number of workers that employers are willing to hire at a given wage).

In this case, both workers and employers are satisfied with the $8.00 per hour wage, and the labor market is balanced.
The government sets a minimum wage below the equilibrium wage, it essentially sets a wage floor that is not binding. Employers are still willing to pay the equilibrium wage of $8.00 per hour, and workers are still willing to accept this wage.

The wage for unskilled workers remains at $8.00 per hour, and there is no pay cut of 50 cents per hour.

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The polygon PQRS satisfies the conditions of being an equilateral polygon, where all sides and angles are equal.

Based on the given information, we can make the following observations about the polygon PQRS:

1. All sides are equal: pq = qr = rs = sp = 12.

2. All angles are equal: ∠p = ∠q = ∠r = ∠s = m.

Therefore, the polygon PQRS satisfies the conditions of being an equilateral polygon, where all sides and angles are equal.

A polygon is a closed geometric shape with straight sides. It is formed by connecting line segments called edges or sides. The sides do not intersect except at their endpoints. The endpoints of the sides are called vertices. Polygons can have different numbers of sides and angles, and they are named based on the number of sides they possess.

Some common examples of polygons include triangles (3 sides), quadrilaterals (4 sides), pentagons (5 sides), hexagons (6 sides), and so on. Polygons can be regular, where all sides and angles are equal, or they can be irregular, where sides and angles may vary.

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Answer:

17x24=248

248+32=280

280-13=267

Step-by-step explanation:

Highest possible whole number is 3.

A triangle has three sides, three angles, and three vertices, which are its characteristics. A triangle's total internal angles are always equal to 180 degrees. This is referred to as the triangle's angle sum property. Any two triangle sides can add up to a length that is longer than the third side.

Given Data

Sum of length of any two sides of a triangle is always equal to the third side.

For sides a, b and c

We must have, a + b > c

Sides of triangle are x, x +3 and 10cm

So,

x + x+ 3 > 10

2x > 10 - 3

2x> 7

x > \(\frac{7}{2}\)

Possible values of x are 3.5, 3, and so on.

Highest possible whole number is 3.

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Using the linear approximation scheme with Li(x) defined in this section gives the trapezoid rule:

N∫f(x)dx≈(Δx/2) [f(x0)+2f(x1)+2f(x2)+...+2f(xN-1)+f(xN)]

where Δx = (b-a)/N and xi = a + iΔx.

Start with the definition of Li(x): Li(x) = f(xi-1) + ((f(xi) - f(xi-1))/(xi-xi-1))(x-xi-1).

Plug in xi = a + iΔx and xi-1 = a + (i-1)Δx, and simplify the expression for Li(x): Li(x) = (1-((x-xi-1)/Δx))f(xi-1) + ((x-xi-1)/Δx)f(xi).

Rewrite the trapezoid rule using the values of xi and Δx from step 2:N∫f(x)dx≈(Δx/2) [f(x0)+2f(x1)+2f(x2)+...+2f(xN-1)+f(xN)].

Substitute Li(x) into the trapezoid rule expression from step 3, using xi-1 and xi for x0 and x1, xi and xi+1 for x2 and x3, and so on, up to xi-1 and xi for xN-1 and

xN: N∫f(x)dx≈(Δx/2) [(1-((xi-xi-1)/Δx))f(xi-1) + ((xi-xi-1)/Δx)f(xi) + 2((1-((xi+1-xi)/Δx))f(xi) + ((xi+1-xi)/Δx)f(xi+1)) + ... + 2((1-((xN-xN-1)/Δx))f(xN-1) + ((xN-xN-1)/Δx)f(xN))].

Simplify the expression from step 4 by factoring out f(xi-1) and f(xN), and combining the coefficients of f(xi), f(xi+1), and so on:

N∫f(x)dx≈(Δx/2) [f(x0) + 2f(x1) + 2f(x2) + ... + 2f(xN-1) + f(xN)].

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Answer:

see explanation

Step-by-step explanation:

(a)

calculate the lengths using the distance formula

d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\)

with (x₁, y₁ ) = J (- 3, - 7 ) and (x₂, y₂ ) = K (3, - 8 )

JK = \(\sqrt{(3-(-3))^2+(-8-(-7))^2}\)

    = \(\sqrt{(3+3)^2+(-8+7)^2}\)

    = \(\sqrt{6^2+(-1)^2}\)

    = \(\sqrt{36+1}\)

    = \(\sqrt{37}\)

repeat with (x₁, y₁ ) = M (8, 3 ) and (x₂, y₂ ) = N (7, - 3 )

MN = \(\sqrt{(7-8)^2+(-3-3)^2}\)

      = \(\sqrt{(-1)^2+(-6)^2}\)

     = \(\sqrt{1+36}\)

     = \(\sqrt{37}\)

repeat with (x₁, y₁ ) = P (- 8, 1 ) and (x₂, y₂ ) = Q (- 2, 2 )

PQ = \(\sqrt{-2-(-8))^2+(2-1)^2}\)

      = \(\sqrt{(-2+8)^2+1^2}\)

      = \(\sqrt{6^2+1}\)

      = \(\sqrt{36+1}\)

      = \(\sqrt{37}\)

(b)

JK ≅ MN ← true

JK ≅ PQ ← true

MN ≅ PQ ← true

Answer:

14.006

Step-by-step explanation:

π + 3.14 × π + 3.14 ÷ 3.14

14.00619358

Rounded -

14.006

Let's see

\(\\ \rm\rightarrowtail \dfrac{\pi\pi(3.14)(3.14)}{3.14}\)

\(\\ \rm\rightarrowtail \pi\pi(3.14)\)

\(\\ \rm\rightarrowtail \pi^2(\pi)\)

\(\\ \rm\rightarrowtail \pi^3\)