sin²A-cos²A=2sin²A-1​

Answer:

36 monkeys where sleeping

wheres the question?

Answer:

It will be the first option

Step-by-step explanation:

Answer:

1/3

with indices, the brackets mean you multiply the powers - so you need to multiply 1/4 by something to get 1/12, which is 1/3

:)

Answer:

g(x) = 20x + 12

Step-by-step explanation:

can i plz have the brainleist

For the pdf f(x; θ) = 0.5(1 + θx) ; − 1 ≤ x ≤ 1 where −1 ≤ θ ≤ 1, of random sample the unbiased estimator of θ is equals to the \(\hat \theta = 3 \bar X \).

An estimator is said to be unbiased if its bias is equal to zero for all values of parameter θ. We have a random sample of variables, X₁, . . . , Xₙ with probability density function, pdf f(x; θ) = 0.5(1 + θx) ; − 1 ≤ x ≤ 1 where −1 ≤ θ ≤ 1. We have to show that \(\hat \theta = 3 \bar X \) is an unbiased estimator of θ. Now, first we determine value of expected value, μ = E(X). So, using the following formula, \( E( X) = \int_{-1}^{1}x f(x, θ)dx \)

\( = \int_{-1}^{1} 0.5x( 1 + θx)dx \)

\( =0.5 [\frac{x²}{2} + \frac{θx³}{3}]_{-1}^{1}\)

\(= 0.5 [\frac{1}{2} + \frac{θ}{3} - \frac{1}{2} + \frac{θ}{3} ]\)

= 0.5\(( \frac{2θ}{3})\)

μ = \( \frac{θ}{3}\), so θ = 3μ. Also, from unbiased estimator of θ, \(\hat \theta = 3 \bar X \), so

E( \(\hat \theta \)) = E( \( 3 \bar X \)

= 3E( \( \bar X \) )

= 3μ = θ

Hence, the required results occurred.

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Answer:

n = 3200

Step-by-step explanation:

200 = 1000 - \(\frac{n}{4}\) ( subtract 1000 from both sides )

- 800 = - \(\frac{n}{4}\) ( multiply both sides by 4 to clear the fraction )

- 3200 = - n ( multiply both sides by - 1 )

n = 3200

Answer:

A=B*H

Step-by-step explanation:

multiply B (base) by H (height)

Answer:

Hard to tell based on what you posted

Step-by-step explanation:

a slope is positive if it is going up from left to right

a slope is negative if it is going down left to right

There are six equilateral triangles in a regular hexagon.

A triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

A regular hexagon has six equal sides and six equal angles.

It can be divided into six equilateral triangles by drawing lines connecting the center of the hexagon to each vertex.

Each of these triangles has the same side length and angle measures.

A square has four sides and four right angles, but it is not a regular polygon because it does not have equal side lengths.

A polygon is a general term for a shape with three or more straight sides, but it does not refer to any specific shape or properties.

An octagon has eight sides and eight angles, but it cannot be divided into equilateral triangles because the angle measures are not all equal.

Thus,

There are six equilateral triangles in a regular hexagon.

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Given :

Calculators cost $12.99 each, rulers cost $0.49 each, pencils cost $0.10 each, and erasers  cost $0.05 each.

To Find :

How much would Mrs. Algebra's single order be.

Solution :

Total price paid by Mrs. Algebra = Price of pencil + price of ruler + price of calculator + price of eraser.

T = $(0.10 + 0.49 + 12.99 + 0.05)

T = $13.63

Therefore, Mrs. Algebra's single order cost is $13.63 .

Hence, this is the required solution.

The shooting method is a numerical technique used to solve differential equations with specified boundary conditions. In this case, we will apply the shooting method to solve the second-order differential equation \(7d^2y/dx^2 - 2dy/dx - yx = 0\) with the boundary conditions y(0) = 5 and y(20) = 8.

To solve the given differential equation using the shooting method, we will convert the second-order equation into a system of first-order equations. Let's introduce a new variable, u, such that u = dy/dx. Now we have two first-order equations:

dy/dx = u

du/dx = (2u + yx)/7

We will solve these equations numerically using an initial value solver. We start by assuming a value for u(0) and integrate the equations from x = 0 to x = 20. To satisfy the boundary condition y(0) = 5, we need to choose an appropriate initial condition for u(0).

We can use a root-finding method, such as the bisection method or Newton's method, to adjust the initial condition for u(0) until we obtain y(20) = 8. By iteratively refining the initial guess for u(0), we can find the correct value that satisfies the second boundary condition.

Once the correct value for u(0) is found, we can integrate the equations from x = 0 to x = 20 again to obtain the solution y(x) that satisfies both boundary conditions y(0) = 5 and y(20) = 8.

The shooting method involves converting the given second-order differential equation into a system of first-order equations, assuming an initial condition for the derivative, and iteratively adjusting it until the desired boundary condition is satisfied.

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1. 215.10

2. 57.60

3. 16.11

4. 8.24

5. 89.40

6. 149.10

7. 476

8. 48

9. 59.50

10. 13.49

Answer:

51

Step-by-step explanation:

Geometric Relationships

Figure d in the diagram shows two similar triangles. They are formed when two parallel lines cut two of the sides.

In similar triangles, the ratio between corresponding sides must be identical.

The two corresponding sides are the base and the slanted side.

The length of the base of the longer triangle is 5 + 8 = 13

The length of the base of the shorter triangle is 8.

The length of the slanted side of the longer triangle is 16

The length of the slanted side of the smaller triangle is x

The ratios must be equal, thus:

Solving for x:

equation A

we have that

Its a vertical line

x=-4

equation B

Its a vertical line

x=4

equation C

Its a horizontal line

y=4

equation D

Its a horizontal line

y=-2

equation E

we need tow points to calculate the slope

we have the points (-4,4) and (4,-2)

the slope is equal to

m=(-2-4)/(4+4)

m=-6/8

m=-3/4

Find the equation of the line in slope intercept form

y=mx+b

we have

m=-3/4

point (4,-2)

substitute

-2=(-3/4)*(4)+b

solve for b

-2=-3+b

b=1

the equation is

y=(-3/4)x+1

Answer:

The mean increased, but the median stayed the same

Step-by-step explanation:

hope it help luvs

The mean increased, but the median remained constant If new dogs' weights are added to the data set.

The mean of a data set is defined as the ratio of the sum of observations to the total number of observations. It can be referred to as the average of a specific set of data or the arithmetic mean.

The formula for the mean of a given set of data is as follows:

Mean = Sum of Observations/Total number of observations

Given the set of observations as :

16, 34, 44, 20, 50, 19, 30, 54

Arrange the data in ascending order, we get

16, 19, 20, 30, 34, 44, 50, 54

The median of the given data would be (30+34)/2 = 32.

Here, n = 8

⇒ ∑x = Sum of Observations

⇒ ∑x = 267

Mean = ∑x/n

Mean = 267/8

Mean = 33.375

If two more dogs weighing 25 pounds and 45 pounds come to the kennel.

Arrange the given data in ascending order, we get

16, 19, 20, 25, 30, 34, 44, 45, 50, 54

The new median of the data would be (30+34)/2 = 32.

New mean = 337/10 = 33.7

Therefore, the mean increased, but the median remained constant If new dogs' weights are added to the data set.

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Answer:

15:16 boys to girls

Step-by-step explanation:

The total length of cable needed for the zip line, considering the required 5% slack and 7 extra feet of cable at each end, is approximately 302.75 feet.

To determine the total length of cable needed for the zip line, we need to consider the distances between the trees and add the required slack and extra cable for wrapping around the trees.

Given the distances between the trees:

Tree 1 is 130 feet from Tree 2.

Tree 2 is 145 feet from Tree 3.

Tree 1 is 160 feet from Tree 3.

Let's calculate the total length of cable needed step by step:

1. Distance between Tree 1 and Tree 2: 130 feet.

2. Distance between Tree 2 and Tree 3: 145 feet.

3. Total distance from Tree 1 to Tree 3 (via Tree 2): 130 + 145 = 275 feet.

Now, we need to add the required slack in the line. The required 5% slack means we need to increase the total distance by 5%. To calculate this, we can multiply the total distance by 1.05 (1 + 0.05):

Total distance with 5% slack: 275 * 1.05 = 288.75 feet.

Next, we need to add 7 extra feet of cable at each end to wrap around each tree:

Total distance with 5% slack and extra cable for wrapping: 288.75 + 7 + 7 = 302.75 feet.

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The Probable question may be:
You and your friend Rhonda work at the community center. You will be counselors at a summer camp for middle school students. The camp director has asked you and Rhonda to design a zip line for students to ride while at camp. A zip line is a cable stretched between two points at different heights with an attached pulley and harness to carry a rider. Gravity moves the rider down the cable.

The zip line will be secured to two trees. The camp has a level field with three suitable trees to choose from. All three trees are on level ground

Tree 1 is 130 feet from Tree 2.

Tree 2 is 145 feet from Tree 3.

Tree 1 is 160 feet from Tree 3.

The camp director is ready to purchase the cable for the zip line. Use the distance between the trees and the change in height you found in question to determine the length of cable needed.

Be sure to include:

the required 5% slack in the line, and

7 extra feet of cable at each end to wrap around each tree

Enter the total length, in feet, of cable needed for the zip line..

Answer: The correct is 114

Step-by-step explanation: Hope this helps

An example of an adjusting journal entry for an increase in an expense and a decrease in an asset is recording the depreciation expense.

When an asset is depreciated, it results in an increase in the expense account (typically called "Depreciation Expense") and a decrease in the corresponding asset account (such as "Accumulated Depreciation" or the specific asset account being depreciated).

For instance, let's consider a machine with an initial value of $10,000 and an estimated useful life of 5 years. At the end of the first year, if the annual straight-line depreciation method is used, the adjusting entry would be:

Debit: Depreciation Expense $2,000

Credit: Accumulated Depreciation - Machine $2,000

This entry reflects the increase in the expense (Depreciation Expense) and the decrease in the asset value (Accumulated Depreciation - Machine).

An adjusting journal entry for an increase in an expense and a decrease in an asset can be exemplified by recording depreciation expense, where the expense account is increased and the asset account is decreased to account for the depreciation of the asset over time.

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Answer:

BC = 30.73

Here,

\(\sf \frac{AB}{BQ} = \frac{CD}{DQ}\)

so first solve for QD

\(\sf \hookrightarrow \frac{32}{15} = \frac{19.2}{DQ}\)

\(\sf \hookrightarrow 32(DQ)} =19.2(15)\)

\(\sf \hookrightarrow 32(DQ)} =288\)

\(\sf \hookrightarrow DQ =9\)

Now! using Pythagoras theorem,

Answer:

BC = 30.7 units (nearest tenth)

Step-by-step explanation:

As ∠AQR = ∠CQR  then ∠AQB = ∠CQD

This means that ΔABQ ~ ΔCDQ

Therefore, the side lengths of two similar triangles are proportional.

\(\begin{aligned} \sf \dfrac{AB}{CD} & =\sf \dfrac{BQ}{QD}\\\sf \implies \dfrac{32}{19.2} & =\sf \dfrac{15.0}{QD}\\\sf \implies QD & = \sf 9 \end{aligned}\)

Pythagoras' Theorem:  \(\sf a^2+b^2=c^2\)

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Given:

Substituting values into the formula:

\(\begin{aligned}\sf 24^2+19.2^2 & = \sf BC^2\\\sf BC^2 & = \sf 944.64\\\sf BC & = \sf \pm\sqrt{944.64}\\\sf BC & = \sf 30.7 \ (nearest \ tenth)\end{aligned}\)

(since distance is positive only)

So the probability, rounded to the nearest thousandth, of getting at least 2 fours in 5 rolls of a fair die is 0.194.

A probability is a number that expresses the possibility or likelihood that a specific event will take place. Probabilities can be stated as proportions with a range of 0 to 1, or as percentages with a range of 0% to 100%.

The probability of getting at least 2 fours is the sum of the probabilities of getting exactly 2, 3, 4, or 5 fours:

P(X ≥ 2) = P(X=2) + P(X=3) + P(X=4) + P(X=5)

Using the binomial formula, we can calculate each of these probabilities:

P(X=k) = (n choose k) p^k (1-p)^(n-k)

where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items from n distinct items.

P(X=2) = (5 choose 2) (1/6)² (5/6)³ = 0.1608

P(X=3) = (5 choose 3) (1/6)³ (5/6)² = 0.0322

P(X=4) = (5 choose 4) (1/6)⁴ (5/6)¹ = 0.0013

P(X=5) = (5 choose 5) (1/6)⁵ (5/6)⁰ = 0.00003

Therefore,

P(X ≥ 2) = 0.1608 + 0.0322 + 0.0013 + 0.00003 = 0.1943

So the probability, rounded to the nearest thousandth, of getting at least 2 fours in 5 rolls of a fair die is 0.194.

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If all attributes of r are prime, then the group of answer choices a, b, and d are true.

Option a states that r cannot be factored. This is true because prime attributes cannot be further decomposed into smaller attributes. Option b states that r has no common keys. This is also true because prime attributes are unique and cannot have any duplicates. Option d states that r is at least in 3NF. This is true because if all attributes of r are prime, then r must have a candidate key composed of only prime attributes. This means that there are no transitive dependencies and r is in at least 3NF. Option c, which states that r is at least in BCNF, is not necessarily true. BCNF requires that for any functional dependency X → Y, X must be a superkey. It is possible for a relation with all prime attributes to have a non-trivial functional dependency where the determinant is not a superkey, violating BCNF.
If all attributes of R are prime, then R is at least in 3NF. In 3NF, every non-prime attribute is fully functionally dependent on a candidate key. Since all attributes are prime, they are part of a candidate key, ensuring the relation meets the conditions of 3NF.

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Therefore, the equation that can be used to find the number of pretzels in each group is 23.

Kumani made 8 dozen pretzels, which is equivalent to 8 x 12 = 96 pretzels. She discarded 4 of the pretzels, so the number of pretzels left is 96 - 4 = 92. She divided the remaining pretzels into 4 equal groups, so the number of pretzels in each group can be found by dividing 92 by 4:

p = 92 ÷ 4

Simplifying this expression gives:

p = 23

Therefore, the equation that can be used to find the number of pretzels in each group is:

p = (8 x 12 - 4) ÷ 4

or

p = 23

The correct answer is A.

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Answer:

(-2,-8)

Step-by-step explanation:

First, we have to make these linear equations into standard form:

-3x+y=-2

and

9x-y=-10

Now we tell my using elimination method, we can cross out the y variables because when added(y+(-y)) is just 0, so we just cross them out

Add liked terms

6x=-12

Solve for X:

X=-2

Plug 2 for X in any equation (lets do -3x+y=-2)

Plug in -2 for X:

-3(-2)+y=-2

Thus we get 6+y=-2

Solve for Y:

y=-8

Now that we have both our variables, we know that the answer is (-2,-8)

(D) the floor of a classroom is a perfect example of a line segment.

Therefore, (D) the floor of a classroom is a perfect example of a line segment.

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The correct form of the question is given below;
Which is an example of a line segment?

(A) the edge of a book

(B) the corner of a box

(C) a beam of light

(D) the floor of a classroom

Answer:

12

Step-by-step explanation:

Answer:

the percentage change on the drone is 42.86%

Step-by-step explanation:

The computation of the percentage change is shown below:

Since the helicopter was sold for $179.99

But amazon would be selling it for $125.99

So, the percentage change would be

= (Sale value -  sale value by amazon) ÷ ( sale value by amazon) × 100

= ($179.99 - $125.99) ÷ ($125.99) × 100

= 42.86%

Hence, the percentage change on the drone is 42.86%

To find a value of c such that P(z ≥ c) = 0.55, we need to use a standard normal distribution table or calculator.From the standard normal distribution table, we find that the z-score corresponding to a right-tailed area of 0.55 is approximately 0.126.

Therefore, we have:

P(z ≥ c) = 0.55

P(z ≤ c) = 1 - P(z ≥ c) = 1 - 0.55 = 0.45

Using the standard normal distribution table, we find that the z-score corresponding to a left-tailed area of 0.45 is approximately -0.126.

So, c = -0.126.

Therefore, the value of c that satisfies P(z ≥ c) = 0.55 is approximately -0.126.

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