So I have this question I cannot figure out 3w+w2+1=10−w

Answer:

1124

Step-by-step explanation:

1323

The area of the triangle △ABC is 12 square units.

The question is incomplete. The actual question is

Triangle ABC is symmetric about the y-axis. Point A is located at (-3,0), and AB is the longest side of ABC. If the perimeter of ABC is 16, what is the area?

Symmetrical forms or figures are things that can have a line drawn through them so that the representations on both sides of the line mirror each other.

As could be seen in the figure the triangle  △ABC is symmetric along the y-axis. Hence, the side AC and BC must be of the same length let us call it 'a'. Also, the coordinate of B must be (3,0) because (3,0) is the reflection of (-3,0) corresponding to the y-axis.

And, the length of AB=6 units because the distance between (-3,0) and (3,0) is 6 units.

Now, the perimeter of the triangle is 16 units. Therefore,

2a+6=16

⇒a=(16-6)/2

⇒a=5 units.

Hence, we have an isosceles triangle △ABC we can find the height 'h' of the triangle using the Pythagoras theorem. Consider the triangle  △ACE
then we have that

the height of the right triangle  △ACE= h

the base of the right triangle  △ACE= 3 units

the hypotenuse of the right triangle  △ACE= a = 5 units.

Hence, by Pythagoras' theorem

h²+3²=5²

⇒h²=25-9=16

⇒h=4 (we choose the positive value of h because length is always positive)

Hence, the area of the triangle △ABC is

(1/2)×base×height

=(1/2)×AB×CE

=(1/2)×6×4 unit²

=12 unit²

Hence, the area of the triangle △ABC is 12 square units.

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Answer:

Step-by-step explanation:

( x + y ^)2 finds the area of the outer square by squaring its side length.

z²  + 4( 1/2xy )  finds the area of the outer square by adding the area of the inner square and the four triangles.

Answer:

1) (x+y)^2

2) z^2+4(1/2xy)

Step-by-step explanation:

( x + y )^2 finds the area of the outer square by squaring its side length.

z²  + 4( 1/2xy )  finds the area of the outer square by adding the area of the inner square and the four triangles.

Answer:

2 is the answer

Step-by-step explanation:

The answer will probably be:

20-(-2)^2 = 16

6-(-2)= 8

So 16/8 =2

And therefore 2 is the answer

Energy consumption is the amount of power used over time, measured in watt-hours (Wh) or kilowatt-hours (kWh). It is calculated by multiplying the power (measured in watts) by the time for which it is used.

To calculate energy consumption, you will need to know the amount of power being used and the time over which it is being used. Power is typically measured in watts (W), and energy is the product of power and time, so energy consumption is the number of watts used multiplied by the number of hours for which they are used.

For example, let's say you want to calculate the energy consumption of a light bulb that uses 60 W of power and is left on for 4 hours. The energy consumption would be:

Energy consumption = 60 W * 4 hours = 240 Wh (watt-hours)

This is the amount of energy that the light bulb used over the 4-hour period.

You can also convert watt-hours to other units of energy, such as kilowatt-hours (kWh). To do this, you would divide the watt-hours by 1,000. In the example above, the energy consumption would be 0.240 kWh.

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The solution set can be written in parametric vector form as: \(X = x3 [-1 0 1]^T + x2 [-2 1 0]^T\)

We can rewrite the system of equations in matrix form as AX = 0, where \(A =[2 2 4]\\[-4 -4 -8]\\[0 -3 -9]\)

\(X = [x1 x2 x3]^T\)

To solve for the solution set, we can row reduce the augmented matrix \([A|0].\\[2 2 4|0]\\[-4 -4 -8|0]\\[0 -3 -9|0]\)

\([2 2 4|0]\\[0 0 0|0]\\[0 -3 -9|0]\)

\([2 2 4|0]\\[0 0 0|0]\\[0 1 3|0]\)

\([2 2 4|0]\\[0 0 0|0]\\[0 1 3|0]\)

\([1 1 2|0]\\[0 0 0|0]\\[0 1 3|0]\)

Therefore, the system has two free variables, x2 and x3, while x1 is a pivot variable. where x2 and x3 are arbitrary constants.

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The average value of f over the rectangle [0,6] x [0,1] is approximately 3.427.

The average value of a function f over a rectangle R is given by:

avg(f) = (1/Area(R)) * double integral of f over R

Here, f(x,y) = 5e^(yx) + e^y and R = [0,6] x [0,1]

The area of R is given by:

Area(R) = (6 - 0) * (1 - 0) = 6

So, the average value of f over R is:

avg(f) = (1/6) * double integral of f over R

We can evaluate the double integral using iterated integration. First, we integrate f with respect to y from 0 to 1, and then integrate the result with respect to x from 0 to 6:

integral of f(x,y) dy = integral of (5e^(yx) + e^y) dy

= (5x/2)e^(yx) + e^y + C

where C is the constant of integration.

Now, we integrate this result with respect to x from 0 to 6:

integral of [(5x/2)e^(yx) + e^y] dx = [(5/2) * integral of xe^(yx) dx] + integral of e^y dx

= [(5/2) * (1/y)e^(yx) - (5/2)(1/y^2)(e^(yx) - 1)] + ey + C

where C is another constant of integration.

Therefore, the average value of f over R is:

avg(f) = (1/6) * [(5/2) * (1/y)e^(yx) - (5/2)(1/y^2)(e^(yx) - 1) + ey] evaluated from y=0 to y=1 and x=0 to x=6

avg(f) = (1/6) * [(5/2) * (1/e^6 - 1) - (5/2)(1/e - 1/e^6) + e - 1]

avg(f) = (1/6) * [(5/2) * (1 - e^-6) - (5/2)(e^-1 - e^-6) + e - 1]

avg(f) = (1/6) * [(5/2) * (1 - e^-6 - e^-1 + e^-6) + e - 1]

avg(f) = (1/6) * [(5/2) * (1 - e^-1) + e - 1]

avg(f) ≈ 3.427

Therefore, the average value of f over the rectangle [0,6] x [0,1] is approximately 3.427.

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The missing information for q2 is the mean squares for treatment, which can be calculated by dividing the sum of squares for treatment. The missing information for q3 is the sum of squares for error.The missing information for q4 is the mean squares for error, which can be calculated by dividing the sum of squares for error.To find the p-value for the above ANOVA table, we need to use the F-distribution with degrees of freedom for treatment  and degrees of freedom for error.

Using the given mean squares for treatment (25.25) and mean squares for error (2.95), we can calculate the F-statistic as follows:

F = mean squares for treatment / mean squares for error
F = 25.25 / 2.95
F = 8.5593

The p-value can then be calculated using a one-tailed F-test with alpha level of 0.05:

p-value = pf(F, degrees of freedom for treatment, degrees of freedom for error)
p-value = pf(8.5593, 3, 16)
p-value = 0.0006

Therefore, the answer is A.
Q2: Mean squares (treatment) = Sum of squares (treatment) / Degree of freedom (treatment)
Mean squares (treatment) = 75.75 / 3
Mean squares (treatment) = 25.25
So, the answer for q2 is: a. 25.25

Q3: Mean squares (error) = Sum of squares (error) / Degree of freedom (error)
Mean squares (error) = 47.2 / 16
Mean squares (error) = 2.95
So, the answer for q3 is: b. 2.95

Q4: F-value = Mean squares (treatment) / Mean squares (error)
F-value = 25.25 / 2.95
F-value ≈ 8.5593
So, the answer for q4 is: c. 8.5593

Q5:P-value = 1 - pf(F-value, Degree of freedom (treatment), Degree of freedom (error))
P-value = 1 - pf(8.5593, 3, 16)

So, the answer for question 5 is: c. 1- pf(8.5593, 3, 16)

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Answer:

\(y=-52x+480\)

Step-by-step explanation:

Linear Modeling

Some events can be modeled as linear functions. If there is a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

\(y=mx+b\)

The event into consideration is the number of pages of a book left to read by Shyryia.

We know that for x=1.5 hours, she had y=402 out of the total 480 pages left to read. This is the point ( 1.5, 402 ). The other point is not obvious but can be inferred by context. If she hasn't used any time to read (x=0), then she would have y=480 pages left to read. This is the point (0,480).

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\(\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\)

Substituting the given points:

\(\displaystyle y-402=\frac{402-480}{1.5-0}(x-1.5)\)

\(\displaystyle y-402=\frac{-78}{1.5}(x-1.5)\)

Operating:

\(y-402=-52(x-1.5)\)

\(\mathbf{y=-52x+480}\)

Answer:

-52x+480.

Step-by-step explanation:

I took the test, definitely correct

An ogive is used to plot cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class when displaying quantitative data. Option B.

An ogive is a graph that represents a cumulative distribution function (CDF) of a frequency distribution. It shows the cumulative relative frequency or cumulative frequency of each class plotted against the upper limit of the corresponding class. In other words, an ogive can be used to represent data through graphs by plotting the upper limit of each class interval on the x-axis and the cumulative frequency or cumulative relative frequency on the y-axis.

An ogive is used to display the distribution of quantitative data, such as weight, height, or time. It is also useful when analyzing data that is not easily represented by a histogram or a frequency polygon, and when we want to determine the percentile or median of a given set of data. Based on the information given above, option B: "Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class" is the correct answer.

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Answer: 4  1/2 ounces

Step-by-step explanation:

Since there are 6 coins that weigh 3/4 ounces each

we should multiply 3/4 by 6

6 becomes 6/1

then you multiply straight across

6/1 x 3/4 = 18/4

the mixed number of that fraction is 4 and 2/4,

but you can simplify it more to make it 4 and 1/2

the answer is 4  1/2 ounces

Answer:

7 7/8 cups of flour

Step-by-step explanation:

2.25 times 3.5 equals 7.875

according to the transitive property of congruence, AB and ST are equal to each other, which implies that AB is congruent to ST.

The transitive property is a postulate that can be utilized to determine whether or not a pair of segments are equal to one another. The transitive property of congruence is a term that is frequently utilized in geometry.

This concept may be used to determine whether or not a given segment is equivalent to another segment. If two segments are equal to a third segment, the transitive property states that they are equal to one another.

Let us consider that,AB is congruent to JK, JK is congruent to ST. Therefore, we can say that the transitive property of congruence is being used in this scenario.

Since AB is congruent to JK, it implies that segment AB and segment JK have identical length. Furthermore, since JK and ST are congruent, JK and ST have the same length, which means that the length of JK is the same as that of ST.

Since AB and JK are equal and JK and ST are equal, it implies that AB and ST are equal, according to the transitive property. This implies that segment AB is congruent to segment ST.

The transitive property of congruence is just one of many theorems that can be used to prove that a given segment is congruent to another segment.  

This theorem, on the other hand, is often used since it is simple to comprehend and use. In geometry, the transitive property is used to describe the relationship between several congruent parts of a triangle, polygon, or another figure.

Using the transitive property, geometric principles can be proved, and several facets of a problem can be comprehended.

the transitive property of congruence is an important concept in geometry. It helps to determine whether or not two segments are equal to each other.

In this given scenario, AB is congruent to JK, and JK is congruent to ST. Therefore, according to the transitive property of congruence, AB and ST are equal to each other, which implies that AB is congruent to ST.

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The area of the puddle is 1810 cm^2.

Area is defined as the total space taken up by a flat (2-D) surface or shape of an object. Take a pencil and draw a square on a piece of paper. It is a 2-D figure. The space the shape takes up on the paper is called its Area.

Area is a measure of how much space there is inside a shape. Calculating the area of a shape or surface can be useful in everyday life, for example you may need to know how much paint to buy to cover a wall or how much grass seed you need to sow a lawn.

It had rained for 4 hours with the hole in the roof (from 3am to 7am).

4 hours = 4×60 = 240 minutes.

Thus the radius of the puddle grew to

240×0.1 = 24 cm

therefore the area of the puddle was

pi×r² = pi×24² = 576pi = 1,809.557368... cm² ≈

≈ 1,810 cm²

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Answer:

Your answer is: 6 wpm

Step-by-step explanation:

If Tyler types twice as fast as Kyla, you multiply the amount of wpm Kyla writes by 2. 3 multiplied by 2 equals 6. Therefore, Tyler writes 6 wpm.

If a business had sales of $4,000,000, and a margin of safety of 25%, the break-even point was is c. $1,000,000.

The margin of safety is the difference between the actual or expected sales and the break-even point. In this case, if the margin of safety is 25%, it means that the business is generating sales that are 25% higher than the break-even point.

To calculate the break-even point, we can use the following formula:

Break-even point = Fixed costs / Contribution margin ratio

The contribution margin ratio is the difference between the sales price and variable costs, divided by the sales price. We don't have enough information to calculate it directly, but we can use the margin of safety to estimate it.

If the margin of safety is 25%, it means that the contribution margin ratio is 25% of the sales price. So, the variable costs must be 75% of the sales price, and the contribution margin ratio is 25%/100% = 0.25.

We know that the sales are $4,000,000, but we don't know the fixed costs. However, we can use the break-even formula to solve for it:

$1,000,000 = Fixed costs / 0.25

Fixed costs = $250,000

Therefore, the break-even point is $250,000 / 0.25 = $1,000,000.

Based on the given information, the break-even point for the business with sales of $4,000,000 and a margin of safety of 25% is $1,000,000.

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The probability that Adam and Betty meet at some point is $1-\frac{1}{16}=\boxed{\frac{15}{16}}$.

To find the probability that Adam and Betty meet while walking on the grid, we can consider their paths. Adam will always move up or right, while Betty will always move down or left. This means that their paths will always be perpendicular, and they will only meet if they intersect at some point.

Let's consider the first minute. Adam can either move up or right, and Betty can either move down or left. There are four possible outcomes: Adam moves up and Betty moves down, Adam moves up and Betty moves left, Adam moves right and Betty moves down, or Adam moves right and Betty moves left.

Out of these four outcomes, only one leads to Adam and Betty meeting: if Adam moves right and Betty moves down, they will meet at the point $(1,3)$. So the probability of them meeting in the first minute is $\frac{1}{4}$.

Now let's consider the second minute. Adam will be one unit away from $(1,3)$, and Betty will be one unit away from $(1,3)$. There are four possible outcomes again, but only one leads to them meeting: if Adam moves up and Betty moves down, they will meet at the point $(1,2)$. So the probability of them meeting in the second minute is $\frac{1}{4}$.

We can continue this process for each minute. At each step, there is only one outcome that leads to them meeting, and the probability of that outcome is $\frac{1}{4}$. So the probability of them meeting after $n$ minutes is $\left(\frac{1}{4}\right)^n$.

Now we need to find the probability that they meet at any point in time. We can do this by taking the complement of the probability that they never meet. The only way they will never meet is if their paths never intersect, which means that Adam always stays to the right of Betty or always stays above Betty.

The probability of this happening is the same as the probability that Adam flips tails $4$ times in a row, or Betty flips heads $2$ times in a row. This probability is $\left(\frac{1}{2}\right)^4=\frac{1}{16}$, since there are $2^4$ possible outcomes for Adam and $2^2$ possible outcomes for Betty.

So the probability that Adam and Betty meet at some point is $1-\frac{1}{16}=\boxed{\frac{15}{16}}$.

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The money is in the account immediately after the final deposit of r30 000 is 107573.

Arista opens a savings account with a deposit of r50 000

principal = 50000

rate of interest = 3.5% componded months

Amount = CI = P(1 + (r/12) )¹²

50000(1 + 0.035/12)¹²

The amount after 1 year is 51778.34

He deposits 25000 now the amount is 51778.34+ 25000 = 76778.34

after 2 years the amount will be

CI = P(1 + (r/12) )²ˣ¹²

76778.34(1 + 0.035)²ˣ¹²

the amount is 82336.64

Now, she withdraws 10000, the amount will be 72336.64

After two years the amount is

CI = P(1 + (r/12) )²ˣ¹²

72336(1 + (0.035/12))²ˣ¹²

77573.04

Now she makes a final deposit of 30000

the amount will be 77573 + 30000 = 107573

Therefore, the money is in the account immediately after the final deposit of r30 000 is 107573.

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We find that the proportion of her laps that fall between 127 and 130 seconds is about 0.139. Any lap time under 135.25 seconds would be considered one of the fastest 2% of her laps. The middle 70% of her laps are between 119 and 131 seconds.

To answer your questions, we first need to have some context on what we're dealing with. You mentioned "her laps," so I assume we're talking about a person who is running or swimming laps. We also need to know the distribution of her lap times (i.e., are they normally distributed, skewed, etc.) in order to answer these questions accurately. For now, let's assume that her lap times are normally distributed.
To find the proportion of her laps that are completed between 127 and 130 seconds, we need to calculate the area under the normal distribution curve between those two values. We can do this using a calculator or a statistical software program, but we need to know the mean and standard deviation of her lap times first.

Let's say the mean is 125 seconds and the standard deviation is 5 seconds. Using a standard normal distribution table or calculator, we find that the proportion of her laps that fall between 127 and 130 seconds is about 0.139.
To find the fastest 2% of laps, we need to look at the upper tail of the distribution. Again, we need to know the mean and standard deviation of her lap times to do this accurately. Let's say the mean is still 125 seconds and the standard deviation is 5 seconds. Using a standard normal distribution table or calculator, we find that the z-score corresponding to the 98th percentile (i.e., the fastest 2% of laps) is about 2.05. We can then use the formula z = (x - mu) / sigma to find that x = z * sigma + mu, where x is the lap time we're looking for. Plugging in the numbers, we get x = 2.05 * 5 + 125 = 135.25 seconds.

Therefore, any lap time under 135.25 seconds would be considered one of the fastest 2% of her laps.
Finally, to find the middle 70% of her laps, we need to look at the area under the normal distribution curve between two values, just like in part However, we need to find the values that correspond to the 15th and 85th percentiles, since those are the cutoffs for the middle 70%. Using the same mean and standard deviation as before, we can use a standard normal distribution table or calculator to find that the z-scores corresponding to the 15th and 85th percentiles are -1.04 and 1.04, respectively.

We can find that the lap times corresponding to those z-scores are 119 seconds and 131 seconds, respectively. Therefore, the middle 70% of her laps are between 119 and 131 seconds.

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Answer:

No solutions (Maybe)

Step-by-step explanation:

If you input 0 into the equation you get -3=-4, which means it has no solutions.

Answer:

10 km/h

Step-by-step explanation:

First, convert 150 minutes to hours:

150/60

= 2.5 hours

Then, to find his speed, divide the km by the number of hours:

25/2.5

= 10 km/h

Answer:

10 km / hr

Step-by-step explanation:

We want to find the average speed in kilometers per hour.

We know that Andre cycled 25 kilometers in 150 minutes.

First, we have the convert 150 minutes to hours.

There are 60 minutes in 1 hour, so we can divide 150 by 60.

150/60= 2.5

Next, find the average speed in kilometers per hour.

Divide the kilometers traveled by the hours.

speed = kilometers / hours

Andre cycled 25 kilometers in 2.5 hours.

speed= 25 km /2.5 hrs

speed = 10 km/hr

Andre’s average speed was 10 kilometers per hour.

Answer:

36

Step-by-step explanation:

9 × 4 = 36

Answer:

4 quarts

Step-by-step explanation:

1 quart = 2 pints

2 quart = 4 pints

3 quart = 6 pints

4 quarts = 8 pints,

therefore Michelle has 4 quarts of milk

hope i helped you!

The fixed cost for suit is $125 and for every additional day, the cost can be calculated as 30*x.

Therefore, the total cost is the sum of the fixed cost ($125) and the additional cost per additional day ($30x). So, the total cost y is:

y = 125 + 30x

To calculate the total cost after 3 days, we need to replace x by 3 on the initial equation as:

y = 125 + 30*3

y = 125 + 90

y = 215

Answers: 21. y = 125 + 30x

22. $215

The assumption that is NOT underlying independent samples t-tests is: c. Normality of the independent lines  variable.

An independent samples t-test is a hypothesis test that compares the means of two unrelated groups to see if there is a significant difference between them. This test is used when we have two separate groups of individuals or objects, and we want to compare their means on a continuous variable. It is also referred to as a two-sample t-test.The underlying assumptions of independent samples t-tests are as follows:1. Independence of observations: The observations in each group must be independent of each other. This means that the scores of one group should not influence the scores of the other group.2.

Homogeneity of the population variance: The variance of scores in each group should be equal. This means that the spread of scores in one group should be the same as the spread of scores in the other group.3. Normality of the dependent variable: The distribution of scores in each group should be normal. This means that the scores in each group should be distributed symmetrically around the mean, with most of the scores falling close to the mean value. The assumption that is NOT underlying independent samples t-tests is normality of the independent variable.

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The area of a plane shape is the measurement on a  2-dimensional plane. The area of the triangle is 110.124 \(cm^{2}\).

A triangle is a  plane shape that has not more than three sides and three angles. The sum of the internal angle of a triangle is \(180^{o}\).

In the given question, the area of the given triangle can be determined by;

Area = \(\frac{1}{2}\) ac SinB

Where: a = 12 cm, c = 19 cm and B = 105°.

Therefore,

Area of the triangle =  \(\frac{1}{2}\) x 12 x 19 x Sin 105°

                                = 6 x 19 x 0.9660

Area of the triangle =  110.124 \(cm^{2}\)

The area of the given triangle is 110.124 \(cm^{2}\).

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The three main examples of parallel lines are railway track, sidewalk edges and ladder rails

Given,

Parallel lines;-

Lines that are parallel to one another on a plane do not intersect or meet at any point. They are always equidistant from one another and parallel. Non-intersecting lines are parallel lines. Parallel lines can also be said to meet at infinity.

We have to the examples of parallel lines;

Here,

Examples of parallel lines in real life are railroad tracks, sidewalk edges, ladder rails, endless rail tracks, opposing sides of a ruler, opposite edges of a pen, and eraser

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Since the events are not mutually exclusive, there is a possibility that they occur simultaneously. Therefore, we need to consider this possibility in calculating the probability of event a occurring before event b.

Answer:

Let P(a) and P(b) be the probabilities of event a and event b, respectively. Then, the probability that event a occurs before event b is given by the formula:

P(a before b) = P(a) + P(a and b)/[1 - P(b)]

Here, P(a and b) represents the probability that events a and b occur simultaneously. Since the events are independent, we can calculate this probability as:

P(a and b) = P(a) x P(b)

Substituting this value in the formula, we get:

P(a before b) = P(a) + P(a) x P(b)/[1 - P(b)]

Simplifying this expression, we get:

P(a before b) = P(a) / [1 - P(b)]

This formula gives us the probability that event a occurs before event b, given that a and b are independent events (and not mutually exclusive). We can use this formula to calculate the probability of event a occurring before event b for any given values of P(a) and P(b).

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The greatest common factor of all the coefficients is of 8.

The greatest common factor between multiple terms is the largest value for which all terms are divisible.

In this problem, the equation is:

\(h(x) = -16x^2 + 56x + 96\)

The terms are 16, 56 and 96. Hence, to find the gcf, we have to keep factoring them by prime factors while all can be factored by the same value, hence:

16 - 56 - 96|2

8 - 28 - 48|2

4 - 14 - 24|2

1 - 7 - 12

There are no terms by which both 7 and 12 are divisible, hence the procedure is stopped and:

gcf(16, 56, 96) = 2³ = 8.

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The maximum cycle time is 4.6 minutes.

The rate of output in a 420 minutes workday is 323 units

The daily output is 182 units

Cycle time is a software statistic used in software engineering to gauge the speed of development in agile software projects. When processing a job, whether it be a client request, an order, or a specific production process stage, the cycle time measures how long it takes.

How to find the idle time %

Idle time/task time * number of WS = 0.6/1.3 * 4 = 0.1154

Multiply by 100

= 11.54%.

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