solution to a solution of D gives a white precipitate, F.
a State the names of D, E and F.
D is a green crystalline solid that dissolves in water to give a very pale
green solution. Addition of sodium hydroxide solution to a solution of D
produces a green precipitate, E, which turns orange-brown around the top
after standing in air. Addition of dilute hydrochloric acid and barium chloride​

Answer:

2.09 grams

Explanation:

From this equation, for every 4 moles of water produced, we need 1 mole of propane.

The molar mass of water is 18.015 g/mol, and the molar mass of propane is 44.1 g/mol.

First, we need to calculate the number of moles of water produced:

moles of water = mass of water / molar mass of water

moles of water = 3.43 g / 18.015 g/mol

moles of water = 0.1906 mol

From the balanced chemical equation, we know that 4 moles of water are produced for every 1 mole of propane. Therefore, the number of moles of propane required to produce 0.1906 mol of water is:

moles of propane = 0.1906 mol / 4

moles of propane = 0.04765 mol

Finally, we can calculate the mass of propane required:

mass of propane = moles of propane x molar mass of propane

mass of propane = 0.04765 mol x 44.1 g/mol

mass of propane = 2.10 g

Therefore, the mass of propane reacting to produce 3.43 grams of water is 2.10 grams.

The amount of NH₃ that would be produced from H₂ is less than the amount that would be produced from N₂, H₂ is the limiting reagent. Then, the theoretical yield of NH₃ is 6.98 g.

The balanced chemical equation for the reaction between H₂ and N₂ to form NH₃ is;

N₂ + 3H₂ → 2NH₃

To calculate the theoretical yield of NH₃, we need to determine the limiting reagent in the reaction. We can do this by calculating the amount of NH₃ that would be produced from each reactant, assuming that the other reactant is in excess.

For H₂; 1 mole of H₂ (2.02 g) reacts with 0.5 moles of NH₃ (17.03 g)

Therefore, 1.40 g of H₂ would produce: (0.5 mol NH₃ / 1 mol H₂) x (17.03 g NH₃ / 1 mol NH₃) x (1.40 g H₂ / 2.02 g H₂)

= 6.98 g NH₃

For N₂ 1 mole of N₂ (28.02 g) reacts with 2 moles of NH₃ (34.06 g)

Therefore, 9.66 g of N₂ would produce; (2 mol NH₃ / 1 mol N₂) x (34.06 g NH₃ / 1 mol NH₃) x (9.66 g N₂ / 28.02 g N₂) = 23.5 g NH₃

Therefore, the theoretical yield of NH₃ is 6.98 g.

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\(8.83\)cents

Explanation:

\((25 \times 4) + (5 \times 10) + (9 \times 1)\)

\( = > 159\) cents

Now,

\( \frac{159}{(4 + 5 + 9)}\)

\( = > \frac{159}{18} \)

\( = > 8.83\)

Hence, the average value of coins is \(8.83\)cents

Answer:

x/2

Explanation:

X = 2 molecules of H2

For 2 molecules of H2, there's only 1 molecule of O2. Meaning, there's twice the amount of H2, so O2 = x/2 molecules.

I hope I'm understanding this question right.

Answer:

O Each orbit has a specific energy level.

Explanation:

Neils Bohr put forward his own model of the atom based on the quantum mechanics originally developed by Planck.

He assumed the Rutherford's model and suggested that the extranuclear part consists of electrons in specific spherical orbits around the nucleus.

The orbits/energy level are the permissible through which the electrons can move through.

His concept is based the concept that the electron can move round the nucleus in certain permissible orbitss

The correct answer is C. Living things are composed of cells.

Explanation:

A conclusion is an idea derived from information, this idea or statement often summarizes the information or indicates the result of this. In the case of the studies by Schwann and Schleiden, these two focused on living organisms. Moreover, in both studies, the researchers found different living organisms were composed of basic life units known as cells.

In this context, one idea that derives from the findings of the two studies is "Living things are composed of cells". Also, this conclusion is now part of modern cell theory because the basic unit of life is the cell and cells can be found in all living organisms despite the type of organism (animal, plant, fungi,etc.)

Answer:

C(Living things are composed of cells.)

Explanation:

Answer:

Writing a balanced Equation for the reaction

Br₂ + 3Cl₂ ==> 2BrCl₃

Kc = [BrCl₃]² / [Br₂][Cl₂]³

Each Concentration (n) = moles/volume of container.

(nBrCl₃)= 1/6 = 0.167moldm-³

(nBr₂) = 2/6 = 0.333moldm-³

(nCl₂) = 6/6 = 1moldm-³

Kc = (0.167)² / (0.333)(1)³

Kc = 0.0838.

Answer: Shown below

Explanation:

CaCl2=calcium chloride

Mg(NO3)2=Magnesium nitrate

ZaCl2=Zinc Chloride

NH2Cl=Chloramine

AgNO2=Silver nitrate

NaCl= Sodium chloride

KI=Potassium iodide

PbSO4=Lead(II) Sulfate

n82CO3=Sodium carbonate

KNO3=Potassium nitrate

N82SO4=Sodium Sulfate.

I hope this helped please give Brainliest!

The name of the compounds and the involved ion are as follows;

Ionic compound is any of a large group of chemical compounds consisting of oppositely charged ions, wherein electron transfer, or ionic bonding, holds the atoms together.

Ionic compounds, when in an aqueous solution, dissociates into its respective ions. This question gives the chemical formula of certain compounds. For example, the sodium ions attract chloride ions and the chloride ion attracts sodium ions. The result is a three-dimensional structure of alternate Na⁺ and Cl⁻ ions.

The names of the chemical compound and the ionic elements that make them up are given in the main answer part.

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1201.6 grams of \(HNO_{3}\) is produced which is the minimum amount of reactant requires to complete the reaction.

The minimum amount of \(O_{2}\) is 915.2 grams

Step 1: Provided data

\(N_{2}\) mass = 400 grams

\(N_{2}\) molar mass = 28.0 g/mol

Step 2: Calculate the balanced equation

\(N2 (g) + 2O2 (g)\) → \(2NO2 (g)\)

\(3NO_{2} (g)+ H_{2} O (g)\) → \(NO + 2HNO_{3} (aq) (g)\)

Step 3: Determine the moles of \(N_{2}\).

\(N_{2}\) moles =\(N_{2}\) mass / \(N_{2}\) molar mass

\(N_{2}\)moles = 400 g / 28.0 g/mol

\(N_{2}\) moles = 14.3 moles

Step 4: Determine the moles of \(O_{2}\)

To produce 2 moles \(NO_{2}\), we need 2 moles O2 for 1 mol \(N_{2}\).

To produce 14.3 moles \(N_{2}\), we need 28.6 moles \(O_{2}\) and 28.6 moles \(NO_{2}\)

Step 5: Determine the mass  

\(O_{2}\) Mass\(O_{2}\) = moles\(O_{2}\) * molar mass of \(O_{2}\) Mass\(O_{2}\)= 28.6 moles * 32.0 g/mol Mass \(O_{2}\) = 915.2 grams

Step 6: Determine the moles of \(NO_{2}\)

To produce 14.3 moles \(N_{2}\), we need 28.6 moles \(O_{2}\) and 28.6 moles \(NO_{2}\)

Step 7: Determine the moles of \(HNO_{3}\)

1 mole H2O is required to produce 2 moles \(HNO_{3}\) and 1 mol \(NO_{2}\) for 3 moles \(NO_{2}\).

2/3 * 28.6 = 19.07 moles \(HNO_{3}\) is required for 28.6 moles \(NO_{2}\)

Step 8: Determine the mass of \(HNO_{3}\).

\(HNO_{3}\) mass = mole \(HNO_{3}\) * molar mass \(HNO_{3}\)

\(HNO_{3}\)mass = 19.07 g/mol * 63.01 g/mol

\(HNO_{3}\)mass = 1201.6 g

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Complete question

\(N2 (g) + 2O2 (g)\) → \(2NO2 (g)\)

\(3NO_{2} (g)+ H_{2} O (g)\) → \(NO + 2HNO_{3} (aq) (g)\)

a. a car burns \(4.00 * 10^2\) g of \(N_{2}\). How many grams of \(HNO_{3}\) will be produced?

b. what is the minimum amount of \(O_{2}\) needed in grams?

Four Hydrogen atoms are present in the molecule (Furan) shown below.

Furan is a heterocyclic organic compound with a five-membered ring containing four carbon atoms and one oxygen atom. It has the chemical formula C4H4O. Furan is a colorless, volatile liquid with a distinctive aromatic odor. Coal tar and organic material burning make it.

Furan is utilised in resins, polymers, and solvents. Furan is poisonous and carcinogenic, hence its use and exposure must be carefully controlled.

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Answer:

The body temperatures in degrees Fahrenheit of a sample of adults in onle small town are 96.6 99.6 96. 3 97.3 99.8 97.7 97,6 97.9 99.2 Assume body temperatures of adults are normally distributed Based on this data find the 9900 confidence Interval of the mean body temperature of adults in the town Enter Your answer as an Open-interval (i.e. parentheses) accurate to 3 decimal places. Assume the data is from normally distributed population_ 9900 CI = Previewv Tp Enter 4euleie er using intewval notation. Example: [2,5) Uge U fcr unicr to combine interval:, Example: (-00,2] U [4,00} Entet each Faluce nunber (like 33,2.2172) Or 33 calculztion (like 5/3,243 5-4) Enter DNE for ar empty set, Use 00 to enter Infinity. Enter each valze accurate to decial place: Get Help: Points possible: 10 This attempt of 3 Me ye ingtmctor absutthis questin Poelis quesivto 6 EpIC e 6 DeA

Explanation:

(Unsure if this helped but hope it did!)

460 grams of Potassium periodate contains 128 grams of Oxygen and 253.9 grams of Iodine.

A compound is composed of atoms from two or more different elements chemically bonded together in fixed small whole number ratios to each other.

Mass of potassium= 17.0 grams

Mass of Oxygen= 27.8 grams

Mass of Iodine= 55.2 grams.

Mass of Potassium periodate= Mass of Potassium+Mass of Oxygen+Mass of Iodine

Mass of Potassium periodate= 17g+27.8g+55.2g

Mass of Potassium periodate= 100 grams

Therefore, 100 grams of Potassium periodate contains 27.8 grams of Oxygen

1 gram Potassium periodate contains 27.8/100= 0.278 grams of Oxygen

So, 1×460= 460 grams Potassium periodate contains 0.278×460

=128 grams Oxygen

Now,

100 grams of Potassium periodate contains 55.2 grams of Iodine

1 gram of Potassium periodate contains 55.2/100=0.552 grams of Iodine

1×460=460 grams Potassium periodate contains 0.552×460

=253.9 grams of Iodine.

So,  460 grams of Potassium periodate contains 128 grams of Oxygen and 253.9 grams of Iodine.

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Answer:

B.Handling the crucible directly with your hands.

D.Taking the mass of the empty crucible without the lid, but including the lid in all other mass measurements.

E.Taking the mass of all samples with the lid included.

Explanation:

When observed critically , the measures associated with the errors which could cause your percent yield to be falsely high, or even over 100% are those which increase the weight of the substance with the individual neglecting.

Handling the crucible directly with your hands,Taking the mass of the empty crucible without the lid, but including the lid in all other mass measurements and taking the mass of all samples with the lid included will all increase the weight of the substance. Instead the substance should be placed alone without any form of support or contamination.

Answer:

Q = -22.9 kJ

Explanation:

Given that,

Mass of water, m = 150.3 g

Water gets cool from 25.60°C to -10.70°C.

The specific heat of water, c = 4.2 J/g°C

The formula for heat needed is given by :

\(Q=mc\Delta T\\\\Q=150.3\times 4.2 \times (-10.7-25.6)\\\\Q=-22914.738\\\\or\\\\Q=22.9\ kJ\)

So, 22.9 kJ of heat is needed to be removed to cool.

2.84 g is the molar mass for oxygen gas. 2 moles or HgO are needed to produce 1 mole or oxygen gas. This means that x grammes of HgO result in x322216.6 g=0.074x grammes of oxygen gas.

1. To determine how many moles more NaCl you need, multiply its concentrations (0.5 mols/Liters) even by desired volume of solution (0.5 Liters). 2. To determine how many grammes of solute are required, multiply all moles of NaCl by their molar mass (58.44 g/mol).

Response and justification When determining the quantity of reactants and byproducts in a chemical process, the balanced version of the reaction must first be written if it is given inside the unbalanced form.

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The usual enthalpy change for the 200g/7.68 mol of ethyne reaction is C2H6g C2H2g Plus 2H2g - 2,388.5kJ.

The quantity of heat released or absorbed during a reaction occurring at constant pressure is known as the enthalpy change.

H stands for "enthalpy change," Hf for "system final enthalpy" (i.e., the enthalpy of the byproducts of the system in equilibrium in a chemical reaction), and Hi for "system initial enthalpy" (i.e., the entropy for the reactants in a chemical reaction).

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Answer:

(a)

Explanation:

Hello,

In this case, the temperature required to boil argon, it means, transform it from liquid to gas is -197 °C. In such a way, since the temperature inside the steel sphere is -190 °C, which is greater than the boiling point, we realize argon is gaseous, therefore, the molecules will be spread inside the sphere as they will be moving based on the kinetic theory of gases.

For that reason, answer is scheme (a).

Best regards.

Answer:

166.56g of NH3 are produced

Explanation:

The reaction of N2 with H2 to produce NH3 is:

N2 + 3H2 → 2NH3

Where 1 mole of N2 produce 2 moles of NH3

4.89 moles of N2 with excess of H2 produce:

4.89 moles N2 * (2 moles NH3 / 1 mole N2) = 9.78 moles NH3

As molar mass of NH3 is 17.031g/mol, mass of NH3 produced is:

9.78 moles * (17.031g / mol) =

Answer:

Physical and chemical methods can be used to monitor the rate of a chemical reaction. Physical methods measure changes in properties like temperature, pressure, or volume. Chemical methods track reactant consumption or product formation using techniques like titration or spectrophotometry. The choice of method depends on the reaction being studied, and scientists use these methods to gain insight into reaction kinetics and optimize conditions for better efficiency and selectivity.

A gas with a volume of 3.5m³ is at 0.275 bar. The volume is reduced to 1.25 m³ while the temperature is held constant .The new gas pressure is

0.77 bar. This is based on Boyle's law.

Boyle's law, also known as the Boyle-Mariotte law or Mariotte's law (particularly in France), is an experimental gas law that explains how the volume and pressure of a confined gas relate to one another. Boyle's law is defined as follows:

If the temperature and amount of gas remain constant in a closed system, the absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies.

the law can be expressed as:

P₁×V₁=P₂×V₂

Given

P₁= 0.275 bar

V₁= 3.5 m³

V₂=1.25 m³

substituting the values and solving for P₂

P₂= 0.77 bar

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Answer:

1.  2.28 g

2. 0.82 g

3. 1.35 g

4. 36 %

5. 59 %

6. 2.17 g

7. 95 %

Explanation:

Hello,

1. In this case, the mass of the unknown mixture is obtained by subtracting the mass of the dish plus sample and the mass of the dish:

m = 26.57 g- 24.29 g = 2.28 g

2. In this case, the mass of the NaCl recovered is obtained by subtracting the mass of the dish plus NaCl and the mass of the dish:

m = 68.66 g- 67.84 g = 0.82 g

3. In this case, the mass of the sand recovered is obtained by subtracting the mass of the filter paper plus sand and the mass of the filter paper:

m = 37.69 g- 36.34 g = 1.35 g

4. The percentage of NaCl is computed by considering its mass and the mass of the unknown mixture:

% NaCl = 0.82 g / 2.28 g * 100 % = 36 %

5. The percentage of sand is computed by considering its mass and the mass of the unknown mixture:

% sand = 1.35 g / 2.28 g * 100 % = 59 %

6. Here,we have to add the mass of NaCl and sand:

m = 0.82 g + 1.35 g = 2.17 g

7. Finally, the percent recovery is obtained by diving the total recovered mass by the total obtained mass of the mixture:

% recovery = 2.17 g / 2.28 g * 100 % = 95 %

Best regards.

The heat released by each molecule, in joules, when ethanol undergoes complete  combustion is 2.28 × \(10^-18\) J.

The number of moles in 1.00 g  of ethanol is obtained from;

Mass of ethanol/molar mass of ethanol

Molar mass of ethanol = 46.07 g/mol

Number of moles =  1.00 g/46.07 g/mol = 0.022 moles of ethanol

1 mole of ethanol contains 6.022 × \(10^23\) molecules

0.022 moles of ethanol contains  0.022 moles ×  6.022 × \(10^23\) molecules/1 mole

=  1.32 × \(10^22\) molecules of ethanol

If 1.32 × \(10^22\) molecules of ethanol release  29.8 × \(10^3\) J of heat

1 molecule of ethanol will release 1 molecule × 29.8 × 10^3 J / 1.32 × \(10^22\)

=  2.28 × \(10^-18\) J

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The equation is balanced since the number of atoms of the elements on each side of the reaction is equal. So we can continue with the calculations.

We have that the Al to O2 ratio is 4/3, we know this from the stoichiometry of the reaction by seeing the coefficients that accompany the Al and O2 molecules.

So the moles of Al will be:

If you have 99 moles of O2 you need 132 moles of Al to use it all.

Answer: 132mol Al

Answer:

A) atomic size

Explanation:

Answer:

See explanation

Explanation:

A reducing agent in chemistry is any substance that accepts electrons and its oxidation number is decreased in a redox reaction.

Manganese occurs in a variety of oxidation states; +7, +6, +5, +4, +3, +2. This makes it an exceptionally good reducing agent since it can accept different number of electrons and change from one oxidation state to another.

The commonest compound of manganese used as a strong oxidizing agent is KMnO4 in which manganese has an oxidation number of +7.

Answer:

Na3N

Explanation:

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