Solve for g.
9 - g = 2g

Answer:

Total lost yards = 10 yards  

Step-by-step explanation:

Given:

First match = lost 3 yards

Second match = lost 5 yards

Third match = lost 2 yards

Find:

Total lost yards

Computation:

Total lost yards = First match + Second match + Third match

Total lost yards = 3 yards + 5 yards + 2 yards

Total lost yards = 10 yards  

Answer:

x = \(\frac{t(a+p)}{4}\)

Step-by-step explanation:

Given

a = \(\frac{4x}{t}\) - p ( isolate term in x by adding p to both sides )

a + p = \(\frac{4x}{t}\) ( multiply both sides by t )

t(a + p) = 4x ( divide both sides by 4 )

\(\frac{t(a+p)}{4}\) = x

Answer:

Step-by-step explanation:

-10

By BODMAS Method

8 + 3*4 ÷ -2*3

8 + 3* \(\frac{4}{-2}\) *3

8 + 3*-2*3

8 +(-18)

-10

The order of operations (BODMAS) in mathematics and computer programming refers to a set of rules that represent standards for which operations to carry out first in order to evaluate a specific mathematical expression.

For instance, since the advent of contemporary algebraic notation, multiplication has been given a higher priority than addition in mathematics and most computer languages.

As a result, 1 + (2 × 3) = 7, rather than (1 + 2) × 3 = 9. is the value assigned to the expression 1 + 2 × 3. BODMAS was first used in the 16th and 17th centuries when addition and multiplication were given priority. BODMAS could only is used as a superscript to the right of their base.

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Answer:

Please send full question. What to find in this question?

Answer:

XY = 5.4cm,angle X = 30 degree,angle Y = 75 degree.it is your answer.

The number of cups of sugar that you will need to make lemonade would be = 2 cups of sugar.

A recipe is defined as the list of condiments that are used for the preparation of a food and it's guidelines.

In the recipe to make lemonade,

6 cups of water = 1/2 cup of sugar

24 cups of water = X cup of sugar.

Make X the subject of formula;

X cup of sugar = 24 × 1/2 ÷ 6

= 12/6 = 2 cups of sugar.

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Eight people skiing downhill in a race can finish in 40,320 different orders.

Calculating probabilities for a set of possibilities keeping in account the order they are in is called permutation (\({n}_P_{r}\)).

If we overlook the order, it becomes a problem of combination (\({n}_C_{r}\)).

Permutation plays an important role in probability problems where the order of the possible outcomes is concerned. It does not allow repetition of outcomes.

Mathematically, permutation can be represented as:

\({n}_P_{r}=\frac{n!}{(n-r)!}\)

where 'n' represents the total objects/values/instances and 'r' represents our selected number of objects/values/instances.

In this case, we have total 8 drivers (n=8) and 8 positions we are selecting i.e. the order skiing people finish in (r=8);

\({n}_P_{r}=\frac{8!}{(8-8)!}=\frac{8!}{0!}=\frac{40320}{1}\)

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Answer:

i say b. because 300+4 is 304

Step-by-step explanation:

Answer: A

Step-by-step explanation: Domain means the x values. Since Miguel works between 15 and 25 hours, the appropriate x values (independent variable) are between 15 and 25.

B is wrong because between 100 and 300 would be the range (y values). C is wrong because a specific domain (between 15 and 25) is specified in the problem, and all real numbers would also include negatives, which isn’t realistic for this scenario. D is wrong because a specific domain is specified. Therefore, it couldn’t be all numbers greater than 0.

The length of the diameter of a circle with endpoints at points (-2, 87) and (18, 91) is  20.4 units

The length of line in an ordered pair is calculated using the formula

d = √{(x₂ - x₁)² + (y₂ - y₁)²}

where

d = distance between the points

x₂ and x₁ = points in x coordinates

y₂ and y₁ = points in y coordinates

distance between points  (-2, 87) and (18, 91) is calculated as follows

d = √{(x₂ - x₁)² + (y₂ - y₁)²}

d =√{(-2 - 18)² + (87 - 91)²}

d =√{400 + 16}

d = √416

d = 20.4 units

The diameter has length 20.4 units

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Answer:

PDR= 127

Step-by-step explanation:

Answer: D

Step-by-step explanation:

\(3x^2-x+2=0\)

\(\text{Solve \ with \ the \ quadratic \ formula \mathrm{for\:}\quad a=3,\:b=-1,\:c=2}\)

\(x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:3\cdot \:2}}{2\cdot \:3}\) \(\rightarrow \sqrt{\left(-1\right)^2-4\cdot \:3\cdot \:2} =\sqrt{1-24} =\sqrt{-23} =\sqrt{-1}\sqrt{23} =\sqrt{23}i\)

\(x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{23}i}{2\cdot \:3}\)

\(x_1=\frac{-\left(-1\right)+\sqrt{23}i}{2\cdot \:3},\:x_2=\frac{-\left(-1\right)-\sqrt{23}i}{2\cdot \:3}\)

\(x_1=\frac{1+\sqrt{23}i}{6},\:x_2=\frac{1-\sqrt{23}i}{6}\)

After 2 generations, the fraction of the population that is wild type is approximately 0.8462, or 84.62%.

To calculate the fraction of the population that is wild type after 2 generations, we need to consider the probabilities of different outcomes for each generation.

Let's denote the fraction of the population that is wild type after the n-th generation as Wₙ and the fraction that is mutant as Mₙ. We are given that initially W₀ = 0.9 and M₀ = 0.1.

In each generation, a wild type individual has a probability of 0.03 of having a mutant offspring, so the fraction of mutant offspring from wild type individuals is 0.03 * Wₙ. Similarly, a mutant individual has a probability of 0.005 of having a wild type offspring, so the fraction of wild type offspring from mutant individuals is 0.005 * Mₙ.

We can calculate the fractions for the first generation as follows:

W₁ = W₀ - 0.03 * W₀ + 0.005 * M₀ = 0.9 - 0.03 * 0.9 + 0.005 * 0.1 = 0.8725

M₁ = M₀ + 0.03 * W₀ - 0.005 * M₀ = 0.1 + 0.03 * 0.9 - 0.005 * 0.1 = 0.1275

Now, we can calculate the fractions for the second generation:

W₂ = W₁ - 0.03 * W₁ + 0.005 * M₁ = 0.8725 - 0.03 * 0.8725 + 0.005 * 0.1275 = 0.84622125

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The genotype of an organism can be either normal (wild type) or mutant. Each generation, a wild type individual has probability 0.03 of having a mutant offspring, and a mutant has probability 0.005 of having a wild type offspring. Suppose that initially 0.9 of the population is wild type and 0.1 is mutant. What fraction of the population is wild type after 2 generations? (enter two digits after decimal, if any)

Answer: 2

Step-by-step explanation:

Answer:

x = a²

Step-by-step explanation:

To undo the square root, you have to square both sides of the equation so it becomes...

(√x )² = a²

That undoes the square soot so it is

x = a²

The GCF of 45 and 315 is 45. So before conformation of my answer refer to your math teacher .

You need to show the question i cant see it anywhere?

The first derivative of the function `g(u) = u(2u - 3)^3` is `g'(u) = 6u(2u - 3)^2 + (2u - 3)^3`. The second derivative of the function is `g''(u) = 12(u - 1)(2u - 3)^2`.

Given function: `g(u)

= u(2u - 3)^3`

To find the first derivative of the given function, we use the product rule of differentiation.`g(u)

= u(2u - 3)^3`

Differentiating both sides with respect to u, we get:

`g'(u)

= u * d/dx[(2u - 3)^3] + (2u - 3)^3 * d/dx[u]`

Using the chain rule of differentiation, we have:

`g'(u)

= u * 3(2u - 3)^2 * 2 + (2u - 3)^3 * 1`

Simplifying:

`g'(u)

= 6u(2u - 3)^2 + (2u - 3)^3`

To find the second derivative, we differentiate the obtained expression for

`g'(u)`:`g'(u)

= 6u(2u - 3)^2 + (2u - 3)^3`

Differentiating both sides with respect to u, we get:

`g''(u)

= d/dx[6u(2u - 3)^2] + d/dx[(2u - 3)^3]`

Using the product rule and chain rule of differentiation, we have:

`g''(u)

= 6[(2u - 3)^2] + 12u(2u - 3)(2) + 3[(2u - 3)^2]`

Simplifying:

`g''(u)

= 12(u - 1)(2u - 3)^2`.

The first derivative of the function `g(u)

= u(2u - 3)^3` is `g'(u)

= 6u(2u - 3)^2 + (2u - 3)^3`. The second derivative of the function is `g''(u)

= 12(u - 1)(2u - 3)^2`.

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The first derivative of g(u) is g'(u) = (2u - 3)³ + 6u(2u - 3)², and the second derivative is g''(u) = 12(2u - 3)² + 12u(2u - 3).

First, let's find the first derivative:

g'(u) = (2u - 3)³ * d(u)/du + u * d/dx[(2u - 3)³]

Using the chain rule, we can differentiate (2u - 3)³ and u as follows:

d(u)/du = 1

d/dx[(2u - 3)³] = 3(2u - 3)² * d(2u - 3)/du

= 3(2u - 3)² * 2

Plugging these values back into the equation for g'(u), we have:

g'(u) = (2u - 3)² + u * 3(2u - 3)² * 2

= (2u - 3)³ + 6u(2u - 3)²

Simplifying the expression, we have:

g'(u) = (2u - 3)³ + 6u(2u - 3)²

Now, let's find the second derivative:

g''(u) = d/dx[(2u - 3)³ + 6u(2u - 3)²]

Using the chain rule and product rule, we can differentiate each term:

d/dx[(2u - 3)³] = 3(2u - 3)² * d(2u - 3)/du

= 3(2u - 3)² * 2

d/dx[6u(2u - 3)²] = 6(2u - 3)² + 6u * d/dx[(2u - 3)²]

= 6(2u - 3)² + 6u * 2(2u - 3)

Plugging these values back into the equation for g''(u), we have:

g''(u) = 3(2u - 3)² * 2 + 6(2u - 3)² + 6u * 2(2u - 3)

= 6(2u - 3)² + 6(2u - 3)² + 12u(2u - 3)

= 12(2u - 3)² + 12u(2u - 3)

Simplifying the expression further, we have:

g''(u) = 12(2u - 3)² + 12u(2u - 3)

Therefore, the first derivative of g(u) is g'(u) = (2u - 3)³ + 6u(2u - 3)², and the second derivative is g''(u) = 12(2u - 3)² + 12u(2u - 3).

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Sorry I don't know how to answer number 3

This is for number 4

x  <  3

Explanation:

5 x  −  2 x  <  7  −  1

3 x  <  6

x  <  2

Answer:

3. x = 4

4. undefined (anything divided by 0 is undefined)

Step-by-step explanation:

3. You can do anything here:

2(4x - 5) + 3 = 5x + 5

Expand

8x - 10 + 3 = 5x + 5

8x - 5x = 5 + 10 - 3

3x = 12

x = 4

4. 5x - 7 = 2x + 1 + 3x

5x - 2x - 3x = 1 + 7

0x = 8

undefined (anything divided by 0 is undefined)

Answer:

the answer is 7/20

Step-by-step explanation:

7/8×2/5

7/4×1/5

7/20

The speed of the cyclist during the first portion is 13 mph and during the cooldown period is 10 mph.

To find the speed of the cyclist during each of the portions covered:

Let x be the speed of the cyclist.

We know that, speed=distance/time or time=distance/speed.

Applying this in the given situation,

First portion:

time = 26/x

Cooldown portion:

time = 20/x-3 as the speed is reduced by 3

Since each portion of the workout took the same time,

26/x = 20/x-3

26x - 78 = 20x

6x = 78

x = 13

Hence, the speed during the first portion is 13 mph.

As the speed was reduced by 3 during the cooldown portion,

speed during this portion = 13 - 3 = 10 mph.

Therefore, the speed of the cyclist during the first portion is 13 mph and during the cooldown period is 10 mph.

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Answer: True.

By definition, a stochastic matrix is a square matrix where each entry is a non-negative real number and the sum of each row is 1.

If A is a stochastic matrix and v is a vector in its 1-eigenspace, then we have:

Av = λv

where λ = 1 is the corresponding eigenvalue.

Multiplying both sides by 1/λ = 1, we get:

v = A v

This means that the vector v is also in the range of A, which is a subspace of the vector space R^n.

Since A is a stochastic matrix, the rows of A sum to 1, and therefore the columns of A also sum to 1. This implies that the vector of all 1's, which we denote by u, is also in the range of A.

Since v is a nonzero vector in the 1-eigenspace and u is a nonzero vector in the range of A, the span of v and u is a two-dimensional subspace of R^n.

Moreover, since A is a stochastic matrix, we have:

Au = u

This means that the vector u is also in the 1-eigenspace.

Therefore, the 1-eigenspace of A is a line spanned by the vector u, which is a nonzero vector in the range of A.

if a is a stochastic matrix, then its 1-eigenspace must be a line: True.


A stochastic matrix is a square matrix with non-negative entries where each row sums to one. The 1-eigenspace of a matrix is the set of all eigenvectors with eigenvalue 1.

Let v be an eigenvector of a stochastic matrix A with eigenvalue 1. Then we have Av = 1v.

Multiplying both sides by the transpose of v, we get v^T Av = v^T v.

Since A is a stochastic matrix, its columns sum to 1 and therefore, its transpose has rows that sum to 1. Thus, v^T Av = 1 and v^T v = 1.

This implies that v^T (A-I) = 0, where I is the identity matrix. Since A is stochastic, I is also stochastic and has a unique 1-eigenspace, which is a line spanned by the vector (1,1,....1)^T.

Therefore, v must be a scalar multiple of (1,1,....1)^T, which implies that the 1-eigenspace of A is a line.

Therefore, the statement "if a is a stochastic matrix, then its 1-eigenspace must be a line" is true.

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We are given the relationship:

a. It's required to find a relationship where r is a function of t. To do that, we need to solve the equation for r.

Subtract 4t:

Divide by 7:

b. We use the function found in part a and evaluate it for t=-7:

Thus, f(-7) = 6

c. Solve f(t) = 18

Again, we use the function from part a and solve the equation:

Multiplying by 7:

Subtract 14 and then divide by -4:

t = -28

The reason why some data mining algorithms require that variables are standardized to zero mean and standard deviation of 1.0 is because it helps to normalize the data and make it more comparable across different variables.

Standardizing the data helps to remove the impact of the scale of the variables on the analysis, allowing for more accurate comparisons and correlations between variables. By doing this, it ensures that no one variable has an undue influence on the results of the analysis. Standard deviation is a statistical measure that is used to measure the amount of variability or dispersion in a dataset. When data is standardized, it allows for a more accurate assessment of the relationship between variables and can improve the accuracy of the analysis. Overall, standardizing variables is a crucial step in the data mining process, as it helps to ensure that the results of the analysis are reliable and accurate.

The reason some data mining algorithms require variables to be standardized (or normalized) to a zero mean and a standard deviation of 1.0 is to ensure consistent and comparable scales for all variables involved. Standardizing variables helps in improving the performance and accuracy of the algorithms.

When variables have different scales or units, it can be challenging for algorithms to interpret their relative importance accurately. By transforming variables to have a zero mean and a standard deviation of 1.0, the algorithms can more effectively process and analyze the data. This standardization process is particularly important for distance-based and gradient-based algorithms, where scale differences can significantly impact the results.

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the answer is: 1/12

simple explanation is :50/100*1/6

The probability that a randomly chosen college student exercises in the morning or afternoon is 0.76

We have given that the M be the event that the student exercises in the morning and A be the event that the student exercises in the afternoon.

To find : The probability that a randomly chosen college student exercises in the morning or afternoon

P(M) = 0.25+0.37 = 0.62

P(A) = 0.14+0.37 = 0.51

P(M and A) = 0.37

Now,

P(M or A) = P(M) + P(A) - P(M and A)

                = 0.62 + 0.51 - 0.37

                = 0.76

Hence, Option last 0.76 is the correct choice.

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A differential equation (2xy² − 5) dx + (2x²y + 7) dy = 0  is an exact differential equation

We know that a differential equation M dx + N dy = 0 is an exact differential equation when \(\partial N/\partial x=\partial M/\partial y\)

Consider a differential equation (2xy² − 5) dx + (2x²y + 7) dy = 0

Comparing this equation with M dx + N dy = 0 we get,

M =  (2xy² − 5)

and N = (2x²y + 7)

The partial derivative of M with respect to y is:

\(\frac{\partial M}{\partial y} \\\\=\frac{\partial}{\partial y}(2xy^2 -5)\)

= 4xy           ...........(1)

The partial derivative of N with respect to x is:

\(\frac{\partial N}{\partial x} \\\\=\frac{\partial}{\partial x}(2x^2y+7)\)

= 4xy          ...........(2)

From (1) and (2),

\(\partial N/\partial x=\partial M/\partial y\)

Therefore, the differential equation is an exact differential equation

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In order to find the values of the sides of the triangle you take into account the relation between sides and hypotenuse.

h: hypotenuse

c1: shorter leg

c2: longer leg

Longer leg c2 is 3 inches longer than c1:

c2 = c1 + 3

hypotenuse h is 6 inches longer than c1:

h = c1 + 6

The formula for the calculation of the hypotenuse is:

h² = c1² + c2²

you replace for h and c2 in terms of c1:

(c1 + 6)² = c1² + (c1 + 3)²

You solve the previous equation for c1:

c1² + 12c1 + 36 = c1² + c1² + 6c1 + 9

c1² - 6c1 - 27 = 0

the roots of the previous equation are:

(c1 - 9 )(c1 + 3) = 0

c1 = 9

c1 = -3

You take the positive number because there is no length of sides with negative values.

Then, c2 and h are:

c2 = c1 + 3 = 9 + 3 = 12

h = c1 + 6 = 9 + 6 = 15

Hence, shorter leg is 9 inches, longer leg 12 inches and hypotenuse 15 inches

The probability that the operator will choose a unit that is not a multiple of 8 is 22/25.

Given that storage units are numbered 1 through 50.

We have to find the probability that the operator will choose a unit that is not a multiple of 8.

Storage units are numbered through 1,2,3,....48,49,50.

So, the total number of possible units are 50.

The numbers that are multiples of 8 which lies between 1 to 50 are 8,16, 24, 32, 40, 48.

So, the multiples of 8 are 6.

And the number of units that are not multiple of 8 are 50-6=44.

Thus, favourable number of units are 44.

So, the probability that the operator will choose a unit that is not a multiple of 8 will be given by

Required probability=(Number of favourable units)/(Total possible units)

Required probability=44/50

Required probability=22/25

Hence, the probability that the operator will choose a unit that is not a multiple of 8 when storage units are numbered 1 through 50 is 22/25.

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The length of BP is 14.4 meters.

To find the length of BP, we can use the property that states that when two chords intersect inside a circle, the product of the segment lengths on one chord is equal to the product of the segment lengths on the other chord.

Using this property, we can set up the equation:

AP * PC = BP * DP

Substituting the given values:

12 m * 6 m = BP * 5 m

Simplifying:

72 m^2 = BP * 5 m

To solve for BP, divide both sides of the equation by 5 m:

72 m^2 / 5 m = BP

Simplifying:

14.4 m = BP

Therefore, the length of BP is 14.4 meters.

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