Solve for x if 6x - 7 = 5x - 1

A) x = 7
B) x = -6
C) x = 13
D) x = 6

Answer: False

Step-by-step explanation:

Answer:

B. False

Step-by-step explanation:

Got it right in a-p-e-x.

Will you please mark as brainliest? =D

Answer:

c.

Step-by-step explanation:

From the last row in the matrix z = 1.

From the second row:

y + 5z = -4

y = -4 -5(1) = -9.

From the first row:

x + -1 = -3

x = - 3 + 1

x = -2.

Answer:

x = 1.5 when y = 3

Step-by-step explanation:

You can put this in a ratio:

x    :    y

5    :   10

1.5  :    3

x is 1.5 when y is 3.

For Pearson correlation the most common purpose to examine is given by option a. The relationship between 2 variables.

The Pearson correlation is a statistical measure that indicates the extent to which two continuous variables are linearly related.

It measures the strength and direction of the relationship between two variables.

Ranging from -1 perfect negative correlation to 1 perfect positive correlation.

And with 0 indicating no correlation.

It is commonly used in research to examine the association between two variables.

Such as the relationship between height and weight, or between income and education level.

Therefore, the most common purpose of a Pearson correlation is to examine the relationship between 2 variables.

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The above question is incomplete, the complete question is:

The most common purpose for a Pearson correlation is to examine,

a. The relationship between 2 variables

b. Relationships among groups

c. Differences between variables

d. Differences between two or more groups

The angle, a, between the Vectors u and W is  2.0 radians (rounded to the nearest tenth).

The angle, a, between the vectors u = <-4, -3> and W = <-1, 5>, we can use the dot product formula:

u · W = |u| |W| cos(a)

Where u · W is the dot product of u and W, |u| is the magnitude of u, |W| is the magnitude of W, and a is the angle between the vectors.

First, let's calculate the dot product:

u · W = (-4)(-1) + (-3)(5)

      = 4 - 15

      = -11

Next, let's calculate the magnitudes of the vectors:

\(|u| = \sqrt{((-4)^2 + (-3)^2)}\\= \sqrt{(16 + 9)}\\= \sqrt{(25)}\\= 5\)

\(|W| = \sqrt{((-1)^2 + 5^2)}\\= \sqrt{(1 + 25)}\\= \sqrt{(26)\)

Now, we can substitute the values into the dot product formula:

\(-11 = (5)(\sqrt{(26)}) cos(a)\)

To find cos(a), we can rearrange the equation:

cos(a) = \(-11 / (5 \times \sqrt{(26))\)

Now, let's calculate the value of cos(a):

cos(a) ≈ -11 / (5 * 5.099)

      ≈ -11 / 25.495

      ≈ -0.431

To find the angle a, we can take the inverse cosine (arccos) of cos(a):

a ≈ arccos(-0.431)

 ≈ 1.994 radians (rounded to the nearest tenth)

Therefore, the angle, a, between the vectors u and W is approximately 2.0 radians (rounded to the nearest tenth).

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In this problem, descriptive statistics is used because the survey percentage is used to make inference for all business owners.

Descriptive statistics is used when data from a sample, which is a sub-set of a population, is used to make inferences about the entire population.

In this problem, the data 979 business owners sampled is used to make inference about the population, which is composed by all business owners, hence descriptive statistics is used.

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Martin bought 8 notebooks and 4 pens for a total of 56000 pesos, while in the same store Camila bought 3 notebooks and 5 pencils for 28000.So the price of a notebook is 5000 pesos and the price of a pen is 7000 pesos.

Let's assume the price of a notebook is N pesos and the price of a pen is P pesos. According to the given information, Martin bought 8 notebooks and 4 pens for a total of 56,000 pesos, which can be expressed as 8N + 4P = 56,000. Similarly, Camila bought 3 notebooks and 5 pencils for 28,000 pesos, which can be expressed as 3N + 5P = 28,000. By solving these two equations simultaneously, we can find the values of N and P. Solving the equations yields N = 5,000 pesos and P = 7,000 pesos.

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#Complete/Translate Question:- Martin bought 8 notebooks and 4 pens for a total of 56,000 pesos, while in the same store Camila bought 3 notebooks and 5 pencils for 28,000. What is the price of the notebook and the pen?

Answer:

I was doing that this year but I for got how.

Step-by-step explanation:

Answer:

------------------------

Set up ratios and solve for the unknown:

So, Harper is at 200 yards from home.

Answer:

See Explanation

Step-by-step explanation:

\(15 = 3 \times \bold{ \red{ \boxed5}} \\ \\ 40 = 2 \times 2 \times 2 \times \bold{ \purple{ \boxed5}} \\ \\ common \: factor \: of \: 15 \: and \: 40= 5 \\ \\ \therefore \: gcf \: of \: 15 \: and \: 40 = 5\)

Answer:

2πrh+2πr2

Step-by-step explanation:

I'm a genius...

Answer:

Closed= 2πrh+2πr²

Open= 2πrh+πr²

a) y(0) = 2

b) y'(0) = -1

values of y(0) and y'(0) for an implicitly defined function using the given equation \(e^x + 3xy - 2 = 0.\)

To find y(0), we substitute x = 0 into the given equation \(e^x + 3xy - 2 = 0.\)Plugging in x = 0, we have \(e^0 + 3(0)y - 2 = 0\), which simplifies to 1 - 2 = -1. Therefore, y(0) = 2.

To find y'(0), we differentiate the given equation implicitly with respect to x. Taking the derivative of \(e^x\) gives us \(e^x\), and applying the product rule to the term 3xy, we have 3y + 3xy'. The derivative of -2 with respect to x is 0. So the derivative of the equation e^x + 3xy - 2 = 0 becomes e^x + 3y + 3xy' = 0.

To find y'(0), we substitute x = 0 into the derived equation. Plugging in x = 0, we get e^0 + 3y + 3(0)y' = 0, which simplifies to 1 + 3y = 0. Solving for y, we find y = -1/3. Therefore, y'(0) = -1.

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Answer:

A.CBA

hope this helps you

(a-1) The value of the population mean is unknown.

(a-2) The best estimate of the population mean is the sample mean, which is 20 eggs.

(c) The value of t for a 95% confidence interval with 17 degrees of freedom is approximately 2.110.

(d) the 95% confidence interval for the population mean is approximately (17.902, 22.098).

(e-1) It would not be reasonable to conclude that the population mean is 17 eggs.

(e-2) It would be reasonable to conclude that the population mean is 18 eggs.

(a-1) The given information provides the sample mean (20 eggs) and the sample standard deviation (5 eggs), but it does not directly provide the population mean.

(a-2) In the absence of other information, the sample mean is a reasonable estimate of the population mean.

(c) For a 95% confidence interval, the value of t can be determined using the t-distribution with n-1 degrees of freedom, where n is the sample size. In this case, the sample size is 18, so the degrees of freedom is 18 - 1 = 17.

Using a t-distribution table or a statistical software, the value of t for a 95% confidence interval with 17 degrees of freedom is approximately 2.110.

(d) To determine the 95% confidence interval for the population mean, we can use the formula: Confidence interval = sample mean ± (t * standard error), where the standard error is the sample standard deviation divided by the square root of the sample size.

In this case, the sample mean is 20, the standard deviation is 5, the sample size is 18, and the value of t is 2.110. Plugging in these values, the confidence interval is 20 ± (2.110 * (5 / √18)), which evaluates to approximately 20 ± 2.098.

(e-1) The 95% confidence interval calculated in part (d) does not include 17 eggs, indicating that it is unlikely for the population mean to be 17 eggs.

(e-2) The 95% confidence interval calculated in part (d) includes 18 eggs, suggesting that it is plausible for the population mean to be 18 eggs.

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Answer:

Yooooooo my man Thanks

Step-by-step explanation:

:)

Answer:

-4 1/9

Step-by-step explanation:

The price for 5 pounds of honey is $13.32.

Unitary method is a mathematical technique used to solve problems related to proportions and ratios.

To find the price for 5 pounds of honey, we can use a proportion:

Price of 3 pounds of honey / 3 = Price of 1 pound of honey

We can use this equation to find the price of 1 pound of honey, and then multiply by 5 to find the price of 5 pounds of honey.

Price of 3 pounds of honey / 3 = 7.99 / 3

Price of 1 pound of honey = 2.6633 (rounded to 4 decimal places)

Price of 5 pounds of honey = 2.6633 x 5 = $13.32 (rounded to 2 decimal places)

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The correct radius of the cylinder is given by: Option B: 3.04 cm

The formula for the volume of a cylinder is given by the formula:

V = πr²h

where:

V is volume

r is radius

h is height

We are given the parameters as:

Height: h = 12.25 cm

Volume: V = 355 cm³

Thus:

355 = π * r² * 12.25

r² = (355)/(12.25π)

r² = 9.2245

r = √9.2245

r = 3.04 cm

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The C.P is Rs.120

Here we can use the formula,

CP=Rs. {100÷100+gain%*S. P}

    =Rs. {100÷100+10*132}

    =Rs. {100÷110*132}

    =Rs.13200÷110

    =Rs.120

Hence the CP is Rs.120

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Answer:

a) 130m    b)1.3m/s²

Step-by-step explanation:

area under graph = distance

area of trapezium = a+b/2 x h

6+20/2 x 10

13 x 10 = 130m

acceleration = gradient

gradient = change in y/ change in x

4/3 = 1.3 m/s²

Answer:

(4x+5)(x-3)

Step-by-step explanation:

You factor this by grouping together the numbers you get from multiplying/subtracting the numbers in the equation.

Answer:

The total amount of tickets sold was 198 tickets.

Step-by-step explanation:

To get this answer, all we have to do is simply divide the amount of money total by the price of the tickets.

So we get 1584 ÷ 8

Which will equal to 198

Hope this helps:) Goodluck!

Answer:

Club 1: 16 would be 120

Club 2: 15 would be 120

none of the possible cases for y satisfy the conditions of the pumping lemma. This means that L cannot be a regular language, and we have a contradiction. Therefore, the language L = {w | w ∈ {0,1}* and w has 1 except as third character} is not regular.

We can prove that the language L = {w | w ∈ {0,1}* and w has 1 except as third character} is not regular by using the pumping lemma for regular languages.

Suppose that L is a regular language, and let n be the pumping length given by the pumping lemma. Consider the string \(s = 0^n1(0+1)^n\). Since s is in L and |s| = 2n+1 > n, we can apply the pumping lemma to s.

By the pumping lemma, we can write s as s = xyz, where |y| > 0, |xy| ≤ n, and for all\(i ≥ 0, xy^iz ∈ L\). Let's consider the possible cases for the string y:

y consists only of 0's: in this case,\(xy^iz\) still has 1 as its third character, so it cannot be in L.

y consists of both 0's and 1's: in this case, \(xy^iz\)has 1 as its third character when i is odd, but not when i is even. Therefore, \(xy^iz\) cannot be in L for all i.

y consists only of 1's: in this case, we can write y = 1^k, where 1 ≤ k ≤ n. Then, \(xy^iz = 0^n1^(k+i)(0+1)^(n-k)\)for all i ≥ 0. If we choose i = 0, then \(xy^0z = 0^(n+k)(0+1)^(n-k) ∈ L\). However, this contradicts the definition of L, since the second character in\(xy^0z\) is a 0, not a 1.

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The linear independence of vector sets forms the basis of the space of polynomials of third degree.

In vector space theory, a collection of matrices is said to be heavily dependent if there is a nontrivial concatenation of the vectors that equal the zero vector. If no such linear combination exists, the vectors are said to be linearly independent. These concepts are crucial to the concept of dimension.

The maximum number of nonzero vectors determines whether the dimensions of a vector space are finite or infinite. The capacity to recognize whether a subset of columns in a vector space is dependent, as well as the concept of linear dependence, are crucial for determining a vector space's dimensionality.

If the same vector appears twice in a vector sequence, it must be dependent. The linear dependency of a vector series is independent of the order of the terms. A restricted collection of vectors can have linear independence if the sequence obtained by sorting a finite number of lines is linearly independent. In other words, the following outcome is frequently useful.

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To find Edmond's weight after he gains g(x) kilograms, we need to add the weight gained g(x) to his initial weight f(x).

f(x) = 5x^2 + 5x + 3 (Edmond's initial weight)

g(x) = 2x^2 - 2x + 1 (Weight gained)

To calculate his new weight, we add f(x) and g(x):

New weight = f(x) + g(x)

= (5x^2 + 5x + 3) + (2x^2 - 2x + 1)

= 5x^2 + 5x + 3 + 2x^2 - 2x + 1

= 7x^2 + 3x + 4

Therefore, Edmond's weight after gaining g(x) kilograms can be represented by the function:

New weight = 7x^2 + 3x + 4 (in kilograms)

Please note that the function represents Edmond's weight in terms of the variable x, so the actual weight in kilograms would depend on the specific value of x chosen.

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