Answer:
x=-28
Step-by-step explanation:
-x+4=32
-x=32-4
-x=28
x= -28
refer to information in the above question. if it takes 6 days for the order placed to arrive, at what level of inventory should the product be reordered, assuming a 30-day month (i.e what's the reorder point)? group of answer choices 83 gallons 100 gallons 500 gallons 537 gallons none of the above
To calculate the reorder point, we need to consider the lead time (6 days) and the average daily usage of the product. Assuming a 30-day month, the average daily usage can be calculated as:
Product used per day = Total product used in a month / Number of days in a month
Product used per day = Inventory / 30
To determine the reorder point, we need to know the daily consumption rate of the product and the lead time (number of days it takes for the order to arrive).
1. Calculate the daily consumption rate: Since we have a 30-day month, we will divide the monthly consumption by 30.
Total consumption in a month = X gallons (Information not provided)
Daily consumption rate = X gallons / 30 days
2. Calculate the lead time demand: Since it takes 6 days for the order to arrive, we need to find out how many gallons are consumed during this time.
Lead time demand = Daily consumption rate * Lead time
Lead time demand = (X gallons / 30 days) * 6 days
3. Determine the reorder point: The reorder point is the level of inventory at which the product should be reordered to ensure that there is enough stock to cover the lead time demand.
Reorder point = Lead time demand
Reorder point = (X gallons / 30 days) * 6 days
Let's assume that the reorder point is the level of inventory at which we need to place a new order to avoid running out of stock. So, the reorder point can be calculated as:
Reorder point = Lead time demand + Safety stock
Here, the lead time demand is the product used during the lead time (6 days) and the safety stock is the buffer inventory kept to avoid stockouts. Let's assume a safety stock of 50 gallons.
Lead time demand = Product used per day * Lead time
Lead time demand = (Inventory / 30) * 6
Lead time demand = Inventory / 5
Reorder point = (Inventory / 5) + 50
We need to solve for the inventory level at which we should reorder. Let's assume the answer is X.
X / 5 + 50 = X
X - X/5 = 50
4X/5 = 50
X = (5/4) * 50
X = 62.5
So, the reorder point is 62.5 gallon. Therefore, the correct answer is "none of the above".
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I need help on this question for math please!
Answer:
no
Step-by-step explanation:
using the values of the ordered pair in the first equating we get :
2 = 3×5 - 13 = 15 - 13 = 2
that fits.
but when using them in the second equation we get :
4×5 - 3×2 = 17
20 - 6 = 17
14 = 17
and that is wrong.
that means the point (5, 2) is not on the second line, so the point cannot be the crossing point (= solution, where both equations deliver the same result) of both lines.
FYI
we would solve the system by using the first equality directly in the second equation :
4x - 3(3x - 13) = 17
4x - 9x + 39 = 17
-5x = - 22
5x = 22
x = 22/5 = 4.4
and y is then
y = 3×4.4 - 13 = 13.2 - 13 = 0.2
the actual solution of the system is therefore
(4.4, 0.2)
refer to the following distribution. cost of textbooks frequency $25 up to $35 7 35 up to 45 20 45 up to 55 18 55 up to 65 14 65 up to 75 11 what are the class limits for the class with the highest frequency? group of answer choices 35 up to 44 34 up to 44 35 up to 44.5 35 up to 45
The class limits for the class with the highest Frequency are 35 up to 45.
The given distribution table is related to cost of textbooks, frequency, and class limits. To find out the class limits for the class with the highest frequency, we need to determine the class interval with the highest frequency. From the given distribution table, it can be observed that the class interval with the highest frequency is 35 up to 45. The frequency of this interval is 20.
The class limit for this interval will be 35 up to 45, which is Option D. The class limit is the lowest and the highest possible value that can be included in a class interval. For example, if we take the class interval 35 up to 45, the lower class limit is 35 and the upper class limit is 45.
The steps to find the class limits for the class with the highest frequency are given below:
Step 1: Determine the class interval with the highest frequency from the given distribution table, we can determine the class interval with the highest frequency, which is 35 up to 45. This class interval has a frequency of 20.
Step 2: Find the class limits for this intervalThe class limits for the class interval 35 up to 45 will be 35 up to 45, which is Option D. The class limits refer to the smallest and largest values that can be included in a class interval.
Thus, the class limits for the class with the highest frequency are 35 up to 45.
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What is the inverse function of
Answer:
is a function that reverse another function if de function apply to an input x gives a result of a y den applying its inverse function g to y gives de result of x nd opposite eg f (x )=y nd if g (y )=x
Answer:
21
Step-by-step explanation:
12. SHORT RESPONSE Describe how you can fold a sheet of paper to create two parallel lines that are perpendicular to the same line.
The description of how you can fold a sheet of paper to create two parallel lines that are perpendicular to the same line is as follows,
Take a paper.
Horizontally fold 1/3rd part of it.
Again fold the 1/3rd part of it (Horizontally).
Open the paper, you will find two parallel lines.
Now, fold the paper in half vertically.
Open the paper.
You will find a line that is perpendicular to both parallel lines.
This is how you can fold a sheet of paper to create two parallel lines that are perpendicular to the same line.
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what geometric shape forms the hole that fits an allen wrench
Answer:
A hexagon
Step-by-step explanation:
A hexagon - - - the allen wrench has 2 hexagonal heads. See attached pic.
The geometric shape that forms the hole that fits an allen wrench is a hexagon, which is a six-sided polygon with straight sides and angles.
The geometric shape hexagon-shaped hole in an allen wrench, also known as a hex key, is designed to fit tightly over the hexagonal socket of a screw or bolt head. A hexagon is a six-sided polygon, meaning it has six straight sides and angles. In the case of an allen wrench, the hexagon has internal angles of 120 degrees and opposite sides that are parallel.
The hexagonal shape of the hole in the wrench allows for a tight and secure fit onto the corresponding hexagonal socket of the screw or bolt head. This design ensures that the wrench can apply a significant amount of torque to the fastener without slipping, which is essential for many applications in construction, mechanics, and other industries.
The use of a hexagonal shape also allows for greater precision and control when turning the screw or bolt, making it easier to achieve the desired level of tightness. Overall, the hexagon is an ideal shape for the hole in an allen wrench due to its strength, stability, and precision.
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What is debris flow? What are the characteristics of flow and
deposition of a debris flow? How to monitor and reduce the risk of
a stream with potential debris flow?
Debris flow refers to a type of fast-moving landslide or mass movement that involves a mixture of water, soil, rocks, and other debris. It typically occurs in mountainous or hilly regions, especially after heavy rainfall or during periods of intense snowmelt.
The characteristics of debris flow include high velocity, thick consistency, and destructive power. They often exhibit a turbulent, surging flow pattern and can transport large volumes of material downstream. Debris flows have the ability to erode and carry away sediment, rocks, and vegetation, causing significant damage to infrastructure, property, and natural environments.
To monitor and reduce the risk of a stream with potential debris flow, various measures can be implemented. Monitoring techniques may include the installation of gauges and sensors to measure rainfall, water levels, and ground movement. Early warning systems can be established to alert residents and authorities of potential debris flow events.
To reduce the risk, structural measures such as the construction of debris flow barriers or channels can be implemented to divert or contain the flow. Land-use planning and zoning regulations can help restrict development in high-risk areas.
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A catering service offers 7 appetizers, 11 main courses, and 9 desserts. A banquet committee is to select 6 appetizers, 8 main courses, and 3 desserts. How many ways can this be done? There are possible ways this can be done.
Total number of ways to select 6 appetizers, 8 main courses, and 3 desserts from the given menu are 962,280.
A catering service offers 7 appetizers, 11 main courses, and 9 desserts.
A banquet committee is to select 6 appetizers, 8 main courses, and 3 desserts.
There are several ways to solve this problem, but one of the simplest methods is to use the multiplication rule of counting, which states that the number of ways to perform a sequence of independent actions is the product of the number of ways to perform each action.
Using this rule, we can find the number of ways to select appetizers, main courses, and desserts separately and then multiply the results to obtain the total number of ways to select the entire menu.
The formula for the multiplication rule of counting is: N = n1 × n2 × ... × nk,
where N is the total number of ways, and n1, n2, ..., nk are the numbers of ways to perform each action.
Using this formula, we have:
Number of ways to select 6 appetizers from 7 = C(7,6) = 7
Number of ways to select 8 main courses from 11
= C(11,8)
= 165
Number of ways to select 3 desserts from 9
= C(9,3)
= 84
Therefore, the total number of ways to select 6 appetizers, 8 main courses, and 3 desserts from the given menu is:
N = 7 × 165 × 84
= 962,280
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Chris has a bucket with paper clips. It has 9 green paper clips and 21 orange paper clips. Chris randomly draws a paper clip, records the color, and returns the paper clip to the bucket. After doing 10 experiments, he found that he drew an orange paper clip 70% of the time. What kind of comparison can be made?
The percentage is likely to decrease with more trials. Or, the percentage is likely to remain the same with more lanes. Or the percentage will likely increase with more experiences.
Answer:
likely remain the same
Step-by-step explanation:
as their ratio from green to orange paper clips is 9:21 meaning it is very likely to draw a orange. If calculated 9/30 is 30 percent meaning there is a 30 percent chance of drawing green. We can conclude there is a 70 percent chance of drawing green mathematically
Last year Geri’s council tax bill was £1815
This year she has to pay £1906 for her council tax.
Work out the percentage increase in her council tax bill.
Give your answer to 1 decimal place.
Answer:
5%
Step-by-step explanation:
To find the increase, we must do 1906 - 1815 = 91
To find the percentage increase, we need to do 91/1815.
91/1815 to the nearest ten-thousandth is 0.0501
Percent = 100 * decimal
0.0501*100 = 5.01%
Rounded to one decimal place = 5.0 = 5
Hope this helps :)
Select all expressions that represent the total area of the large rectangle.
Answer:
a. 5(x + y)
c. 5x + 5y
Step-by-step explanation:
The area = length * width.
Find the volume of radius 7 cm in diameter of 12 cm in 3.14
The volume of a sphere with a radius of 7 cm (or diameter of 12 cm) is 904.32 cubic centimeters.
To find the volume of a sphere with a radius of 7 cm, we can use the formula:
V = (4/3) * π * r^3
where V represents the volume and r represents the radius. However, you mentioned that the diameter of the sphere is 12 cm, so we need to adjust the radius accordingly.
The diameter of a sphere is twice the radius, so the radius of this sphere is 12 cm / 2 = 6 cm. Now we can calculate the volume using the formula:
V = (4/3) * π * (6 cm)^3
V = (4/3) * 3.14 * (6 cm)^3
V = (4/3) * 3.14 * 216 cm^3
V = 904.32 cm^3
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E. How do you use linear regression and
multiple regression to create causal forecasting models?
F. How do you calculate measures of forecasting
accuracy and interpret their results?
E. Linear regression and multiple regression are used to create causal forecasting models.
F. Measures of forecasting accuracy, such as MAE, MSE, RMSE, and MAPE, are used to assess the performance of forecasting models.
E. Linear regression and multiple regression can be used to create causal forecasting models by examining the relationship between independent variables and a dependent variable. Linear regression focuses on predicting a dependent variable based on a single independent variable, while multiple regression considers multiple independent variables.
To create a causal forecasting model using linear regression, follow these steps:
1. Collect data: Gather data on the dependent variable and the independent variable(s) of interest.
2. Plot the data: Create a scatter plot to visualize the relationship between the independent and dependent variables.
3. Fit the regression line: Use the least squares method to estimate the coefficients of the regression line that best fits the data.
4. Assess the model: Evaluate the significance of the coefficients and the goodness of fit of the regression model.
5. Make forecasts: Once the model is validated, use it to predict the values of the dependent variable for future time periods.
Multiple regression extends this process to include multiple independent variables. It allows for the examination of the combined effect of multiple factors on the dependent variable.
F. Measures of forecasting accuracy help assess the performance of a forecasting model. Some common measures include:
1. Mean Absolute Error (MAE): It measures the average magnitude of errors without considering their direction.
2. Mean Squared Error (MSE): It measures the average squared differences between the forecasted and actual values, giving more weight to large errors.
3. Root Mean Squared Error (RMSE): It is the square root of MSE and provides an interpretable measure in the same unit as the dependent variable.
4. Mean Absolute Percentage Error (MAPE): It calculates the average percentage difference between the forecasted and actual values, making it useful for comparing accuracy across different datasets.
To interpret the results, lower values of MAE, MSE, RMSE, and MAPE indicate better forecast accuracy. However, the interpretation of these measures depends on the context and the nature of the data being forecasted. It is also important to consider the magnitude of the variables involved to understand the practical significance of the forecast errors.
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Question 7 Evaluate 2y + 3(y - 5) when y = 10 57 35
Answer:
Sustitute the y-values into the equation.
For y=10,
2(10) + 3 (10 - 5)
20 + 3(5)
20+15
35
For y=57,
2(57) + 3 (57 - 5)
114 + 156
270
For y=35
2(35) + 3 (35 - 5)
70 + 3(30)
70 + 90
160
:)
Answer:
Step-by-step explanation:
monert
A polar vortex causes the temperature to decrease from 3°C at 3 PM to -2°C at 4 PM the temperature continues to change by the same amount each hour until 8 PM find the total change in temperature for 3 PM to 8 PM
The total change in temperature from 3 PM to 8 PM is 25°C.
The first step is to calculate the temperature difference.
Temperature at 3 PM = 3°C
The temperature at 4 The period2°C
The difference = 3 - (-2) = 3 + 2 =5°C
The second step is to calculate the difference time.
Period from 3 PM to 8 PM:
To find the difference between two numbers, subtract the number with the smallest value from the number with the largest value.
So,
8-3 = 5 hours
The third step is to calculate the total temperature change.
5°C × 5 hours = 25°C.
The total change in temperature from 3 PM to 8 PM is 25°C.
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Find fx and fy, and evaluate each at the given point. f(x, y) = exy2, (ln 2, 2)
The partial derivative with respect to x at the given point is 2e^4, and the partial derivative with respect to y at the given point is 8e^4.
To find the partial derivatives of f(x,y) = exy^2, we differentiate f with respect to x and y, treating the other variable as a constant. So,
fx(x,y) = y^2exy^2
fy(x,y) = 2xyexy^2
At the point (ln 2, 2), we have:
fx(ln 2, 2) = 2e^4
fy(ln 2, 2) = 8e^4
Therefore, the partial derivative with respect to x at the given point is 2e^4, and the partial derivative with respect to y at the given point is 8e^4.
These partial derivatives give us information about how the function changes in each direction at the given point.
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X is normally distributed with mean 50 and stan- dard deviation 8. What value of X is such that only 8% of values are below it
The value of X is normally distributed such that only 8% of values are below it is approximately 38.76.
To find the value of X such that only 8% of values are below it, we need to find the z-score associated with the 8th percentile and then convert it back to the X value using the mean and standard deviation.
Step 1: Find the z-score associated with the 8th percentile.
Using a standard normal distribution table or calculator, we find that the z-score associated with the 8th percentile is approximately -1.4051.
Step 2: Convert the z-score back to the X value.
We can use the formula for z-score:
z = (X - mean) / standard deviation
Rearranging the formula to solve for X, we have:
X = z * standard deviation + mean
Plugging in the values:
X = -1.4051 * 8 + 50
X ≈ 38.76
Therefore, the value of X such that only 8% of values are below it is approximately 38.76.
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The product of 8 and n decreased by 5 is _________________ 25. Less than
The product of 8 and any number n decreased by 5 can be expressed as 8n-5 and calculated by multiplying 8 by the number n and then subtracting 5 from the result.
The product of 8 and n decreased by 5 can be expressed as 8n-5. This can be calculated as 8 multiplied by any number n and then subtracting 5 from the result. To illustrate, if n=2, then 8n-5 would be 8 multiplied by 2 (which is 16) and then subtracting 5 from 16 (which is 11). Therefore, the product of 8 and n decreased by 5 is 11. To summarize, 8n-5 is an expression that represents the product of 8 and any number n decreased by 5 and can be calculated by multiplying 8 by the number n and then subtracting 5 from the result.
The product of 8 and any number n decreased by 5 can be expressed as 8n-5 and calculated by multiplying 8 by the number n and then subtracting 5 from the result.
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You would like to add freshly made mint ice cream to your restaurant's menu, and
have decided to grow your own mint. Last month, your mint plant was 2 feet, 7
inches tall. You took care of the mint plant properly, and that care has paid off.
This month, it is 4 feet, 1 inch tall. How much did it grow?
Jackie earned a total of $9 by selling 3 cups of lemonade. How many cups of lemonade does Jackie need to sell in all to earn $18? Assume the relationship is directly proportional
Answer:
6 cups
Step-by-step explanation:
When two things are directly proportional (e.g. y and x), we can model the relationship with the direct variation equation, which is
y = kx, where
k is the constant of proportionalityStep 1: To find k, we can allow y to represent Jackie's total revenue from selling lemonade ($9) and x to represent the quantity of cups of lemonade sold ($3):
9 = 3k
k = 3
Step 2: Now that we've found the constant of proportionality, we can plug in 18 for y and 3 for k, allowing us to solve for x:
18 = 3x
6 = x
Thus, in order for Jackie to earn $18, she must sell 6 cups in all.
Please Help me - You will get 60 points for the rapid reply- Use isosceles trapezoid ABCD to determine the following measurements-
Answer:
1) AD = 9 in
2) DE = 9.25 in
3) ∠EDC = 36°
4) ∠AEB = 108°
5) 11.5 in
Step-by-step explanation:
1) AD = BC = 9in
2) AC = BD (diagonals are equal)
⇒ BD = 14.25
⇒ BE + DE = 14.25
⇒ 5 + DE = 14.25
DE = 9.25
3) Since AB ║CD,
∠ABE = ∠EDC = 36°
4) ∠ABE = ∠BAE = 36°
Also ∠ABE + ∠BAE + ∠AEB = 180 (traingle ABE)
⇒ 36 + 36 + ∠AEB = 180
∠AEB = 108
5) midsegment = (AB + CD)/2
= (8 + 15)/2
11.5
A 5 5 meter rope is lying on the floor and has has a weight of 40 40 N in total. How much work is required to lift up one end of the rope to a height of 3 3 meters
It would require 60 Joules of work to lift up one end of the rope to a height of 3 meters.
The amount of work required to lift up one end of a 5-meter rope to a height of 3 meters can be calculated using the formula:
Work = Force x Distance
Here, the force required to lift the rope is equal to half its weight since we are only lifting one end. Hence, the force required is:
Force = Weight/2
= 40/2
= 20 N
The distance moved is equal to the height to which the rope is lifted, which is 3 meters.
So, the amount of work required is:
Work = Force x Distance
= 20 x 3
= 60 Joules
Therefore, it would require 60 Joules of work to lift up one end of the rope to a height of 3 meters.
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The diameterof circle is 8 cm. Find the circumference to the nearest tenth
Answer:
25.1 cm
Step-by-step explanation:
the other person answered first but have a great day!
Hi can someone fully answer the question down below
Answer:
x= -10
Step-by-step explanation:
since its > not ≥, your only answer would be -10.
at the point -6, it would be =
when x= -10,
\(\frac{-10+3}{6}\)>\(\frac{-10}{4}\)+1
-7/6>-3/2
which is correct
Evaluate the expression when
a= -2; b= -1; c= -3
a - bc?
(Answer/Solve)
Answer:
the answer that i found out was -5
Step-by-step explanation:
a - bc
= -2 - [ -1×(-3) ]
= -2 - 3
= -5
the u.s. bureau of labor statistics reports that 11.3% of u.s. workers belonged to unions in 2013. suppose a sample of 400 u.s. workers is collected in 2018 to determine whether union efforts to organize have increased union membership. if the sample results show that 58 of the workers belonged to unions, what is the p-value for your hypothesis test?
Since the p-value is greater than the commonly used significance level of 0.05, we fail to reject the null hypothesis. Therefore, we do not have sufficient evidence to conclude that union efforts to organize have increased union membership.
We can use a one-sample proportion test to determine if the proportion of union members in the sample is significantly different from the population proportion of 11.3%.
The null hypothesis is that the population proportion is equal to 11.3%:
H0: p = 0.113
The alternative hypothesis is that the population proportion is greater than 11.3%:
Ha: p > 0.113
The sample proportion is P = 58/400
= 0.145
The standard error of the sample proportion is:
SE = √(p*(1-p)/n)
= √(0.113*(1-0.113)/400)
= 0.0197
The test statistic is:
z = (P - p) / SE
= (0.145 - 0.113) / 0.0197
= 1.6244
The p-value for this test is the probability of getting a z-score of 1.6244 or greater, assuming the null hypothesis is true:
p-value = P(Z > 1.6244)
= 0.0515 (using a standard normal distribution table)
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factor 147a^2b-675b^3
Answer:Factor the polynomial
3(a−4b)2
Franco wants to prove that the base angles of any isosceles triangle are congruent. He draws ∆ABC, as shown, and then draws the angle bisector of ∠A. Use the drop-down menus below to complete Franco’s proof that base angles of an isosceles triangles are congruent.
1. Angles BAP and CAP are congruent by the definition of the angle bisector theorem.
2. Segment AP is congruent to itself by the reflexive property.
What is the angle bisector theorem?The angle bisector of a triangle divides a triangle into two parts, from an angle, and the angle is divided into two equal parts.
The bisected angle in this problem is given as follows:
Angle A.
The two new angles are given as follows:
<BAP and <CAP.
Hence they are congruent by the definition of the angle bisector theorem, and congruent is the word that completes the blank for item 1.
For item 2, the reflexive property is the property that states that a segment is always congruent to itself. Hence the reflexive property is the work that completes the blank for item 2.
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A quarter back completes 23% of his passes. We want to observe this quarterback during one game to see how many pass attempts he makes before completing one pass. What is the probability that the quarterback throws exactly 6 incomplete passes before he has a completion
Answer:
\(Pr = 0.0479\)
Step-by-step explanation:
Given
\(p =23\%\) --- proportion of completed passes
Required
The probability that he has 6 incomplete before he has 1 completion
Let:
\(q \to\) proportion of back passes not completed
Using complement rule:
\(q = 1 - p\)
\(q = 1 - 23\%\)
\(q = 1 - 0.23\)
\(q = 0.77\)
The event that he has 6 incomplete passes before he completed one is:
q q q q q q p
And the probability is:
\(Pr = q * q * q * q * q * q * p\)
\(Pr = q^6* p\)
\(Pr = 0.77^6* 0.23\)
\(Pr = 0.0479\)
I need to know the rate of change of the area of a rectangle based off the information in the provided image.
The answer of the given question based on the rate of change of the area of a rectangle the answer is is decreasing at a rate of 8 units²/second.
What is a Rectangle?A rectangle is geometric shape that has four straight sides and four right angles. It is two-dimensional figure that can be described as parallelogram with four right angles. A rectangle has two pairs of parallel sides and opposite sides of equal length..
we are given that the length of the rectangle is increasing at a rate of 4 units/second and the width of the rectangle is decreasing at a rate of 3 units/second.
To find the rate of change of the area of the rectangle, we can use the chain rule of differentiation:
dA/dt = (dA/dl) * (dl/dt) + (dA/dw) * (dw/dt)
We can find dA/dl and dA/dw by taking the partial derivatives of the area formula with respect to l and w, respectively:
dA/dl = w
dA/dw = l
Substituting these values and the given rates of change into the chain rule formula, we get:
dA/dt = (w) * (4) + (l) * (-3)
Substituting l = 10 and w = 8 (from the given image), we get:
dA/dt = (8) * (4) + (10) * (-3) = 8 units²/second
Therefore, the rate of change of the area of the rectangle is decreasing at a rate of 8 units²/second.
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