Solve, to two decimal places, the equation

Answer:

D.

Step-by-step explanation:

1) the domain is x∈[0;+∞);

2) the solution is:

\(\sqrt{x}\leq 10; \ => \ x\leq 100;\)

3) finally, the solution with the domain is:

x∈[0;100].

Answer:

64

Step-by-step explanation:

24 / (3/8) = 64 meals. Hope this helps!

The Value of x is 2/3.

The value of x, we need to determine the mean of the given values and set it equal to the expression for the mean.

The mean (average) is calculated by adding up all the values and dividing by the number of values. In this case, we have five values: x, x+3, x-5, 2x, and 3x.

Mean = (x + x+3 + x-5 + 2x + 3x) / 5

Next, we simplify the expression:

Mean = (5x - 2 + 3x) / 5

Mean = (8x - 2) / 5

We are given that the mean is also equal to x:

Mean = x

Setting these two expressions equal to each other, we have:

(x) = (8x - 2) / 5

To solve for x, we can cross-multiply:

5x = 8x - 2

Bringing all the x terms to one side of the equation and the constant terms to the other side:

5x - 8x = -2

-3x = -2

Dividing both sides by -3:

x = -2 / -3

Simplifying, we get:

x = 2/3

Therefore, the value of x is 2/3.

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             - - - -- - - - - - - - - - - - - - - - - - - - - - - - - -- - -  - - -- - -

\(\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\)

How do we write 8x-2y=10 in slope intercept form?

\(\blue\textsf{\textbf{\underline{\underline{Answer and Solution:-}}}}\)

First subtract 8x on both sides:-

-2y=10-8x

or

-2y=-8x+10

Now divide by -2 on both sides:-

y=2x-5

This is our equation in slope intercept form.

                    - - - -- - - - - - - - - - - - - - - - - - - -- - - - - - - - - - - - - - - - - - - - - - -

Surface area is calculated as 48 + 120 = 168 square units (area of triangular faces + area of rectangular faces).

A polyhedron with two triangular sides and three rectangles sides is referred to as a triangular prism. It is a three-dimensional shape with two base faces, three side faces, and connections between them at the edges.

Given :

We must calculate the area of each face of the triangular prism and put them together to determine its surface area.

The areas of the triangular faces are equal, so we may calculate one of their areas and multiply it by two:

One triangular face's area is equal to (1/2) the sum of its base and height, or (1/2) 6 x 8 x 6, or 24 square units.

Both triangular faces' surface area is 2 x 24 or 48 square units.

Finding the area of the rectangular faces is now necessary:

One rectangular face's area is given by length x breadth (10 x 6) = 60 square units.

120 square units are the area of both rectangular faces or 2 by 60.

Hence, the triangular prism's total surface area is:

Surface area is calculated as 48 + 120 = 168 square units (area of triangular faces + area of rectangular faces).

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we can interpret the value of   \(m'(12) = -15\) as the instantaneous rate of change of the amount of milk in the tanker truck, which is decreasing by 15 gallons per minute at time  \(t = 12\) minutes.

The expression "m'(12)" represents the derivative of the function m(t) with respect to time t, evaluated at t=12. Geometrically, the derivative represents the instantaneous rate of change of the function at the point t=12.

In this case, m'(12) = -15 means that at the time t=12 minutes, the rate of change of the number of gallons of milk in the tanker truck is -15 gallons per minute. This indicates that the amount of milk in the truck is decreasing at a rate of 15 gallons per minute at time t=12.

To calculate m'(12), you need to take the derivative of the function m(t) with respect to t and then evaluate the result at t=12. Assuming you have the expression for m(t), the steps are as follows:

Differentiate m(t) with respect to t:

\(m'(t) = d/dt [m(t)]\)

Evaluate  \(m'(t) at t=12:\)

\(m'(12) = m'(t=12)\)

Therefore, we can interpret the value of   \(m'(12) = -15\) as the instantaneous rate of change of the amount of milk in the tanker truck, which is decreasing by \(15\) gallons per minute at time t = 12 minutes.

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Answer:

2 students play both

Step-by-step explanation:n(u)=28

n(b)=7,n(b)=5,n(who play neither sport)=18

HERE,

n(u)=n(b)+n(b)-n(BnB)+n(who play neither sport)

28=7+5-n(BnB)+18

28=30-n(BnB)

n(BnB)=30-28

 =2 answer

Answer:

18

Step-by-step explanation:

This is venn diagram with 4 elements

Fish = n(F)

Bird = n(B)

Dog = n(D)

Cat = n(C)

The formula is given as

n (F ∪ B ∪ C ∪ D) - n(pet owners that have not fish, bird, cat or dogs) = n(F ) + n ( B ) + n (C) + n(D) - n ( F ∩ B) - n ( F ∩ C) - n ( F ∩ D) - n ( D ∩ B) - n ( D ∩ C) - n ( C ∩ B) + n(F ∩ D ∩ C) + n(F ∩ D ∩ B) + n(F ∩ C ∩ B) + n(D ∩ B ∩ C)- n (A ∩ B ∩ C ∩ D)

= 140 - n(pet owners that have not fish, bird, cat or dogs) = 47 + 53 + 50 + 68 - 21 -26 - 29- 10 - 2

140 - n = 218 - 88

140 - 218 - 88 +[(9 + 4 + 10) -(11 + 14)] = n

140 - 218 - 88 + (33 - 25)= n

140 - 130 + 8 = n

10 + 8 = n

( a ) The null hypothesis, represented by \(H_{0}\), should be equivalent to 0.6 pounds per square inch, considering it normally is predicted to be equivalent to the population parameter, which, in this case, is 0.6 psi ( pounds per square inch. ) The alternative hypothesis on the other hand contradicts the null hypothesis, and as the manager feels the pressure has been reduced, the alternative hypothesis points that the pressure is less than 0.6 psi -

\(H_0: stigma = 0.7,\\H_a: stigma < 0.7\)

stigma is represented by the sign ( σ )

( b ) Now if you were to reject the null hypothesis when true, that would lead to a type I error. That would mean that to reject the fact that σ = 0.7, and accept that σ < 0.7, even though σ = 0.7 is true, would make a type I error.

_______

( c ) A type II error is quite the opposite. Accepting the null hypothesis while rejecting the alternative hypothesis would make a type II error.

From the information given and using error concepts, it is found that:

a)

The null hypothesis is \(H_0: \sigma = 0.6\)

The alternative hypothesis is \(H_1: \sigma < 0.6\)

b) It would mean a conclusion that the standard deviation is of less than 0.6 psi when in fact it is not.

c) It would mean a conclusion that the standard deviation not significantly less than 0.6 psi when in fact it is.

At the null hypothesis, we test if the standard deviation is of 0.6 psi, that is:

\(H_0: \sigma = 0.6\)

At the alternative hypothesis, we test if variability has been reduced, that is, if the standard deviation is of less than 0.6 psi, hence:

\(H_1: \sigma < 0.6\)

Item b:

A Type I error happens when a true null hypothesis is rejected, hence, it would mean a conclusion that the standard deviation is of less than 0.6 psi when in fact it is not.

Item c:

A Type II error happens when a false null hypothesis is not rejected, hence, it would mean a conclusion that the standard deviation not significantly less than 0.6 psi when in fact it is.

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Answer:

D. -3 + 2i and E. 3+2i are the zeroes for the equation.

Step-by-step explanation:

The interval where function f(x) is negative and greater than 0 is (-∞, -3) U (-1.1, 0)

We have,

The function f(x) crosses the x-axis at (-3, 0), (-1.1, 0), and (0.9, 0), it means that f(x) is negative for x values less than -3, between -1.1 and 0.9, and greater than 0.

Therefore, we can say that:

f(x) < 0 for x < -3 and -1.1 < x < 0.9

And,

The function f(x) has a minimum value of (0, -3) and a maximum value of (-2.4, 17).

This means that f(x) is positive for x values greater than -2.4. Therefore, we can say that:

f(x) > 0 for x > -2.4

Now,

Combining these inequalities, we can say that f(x) is negative over the intervals (-∞, -3) and (-1.1, 0.9), and positive over the interval (-2.4, ∞).

So,

The interval where f(x) is negative and greater than 0 is:

(-∞, -3) U (-1.1, 0)

Thus,

The interval where f(x) is negative and greater than 0 is (-∞, -3) U (-1.1, 0)

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According to the Empirical Rule, 99.7% of the measures fall within 3 standard deviations of the mean in the normal distribution.

The Empirical Rule states that, for a normally distributed random variable, the symmetric distribution of scores is presented as follows:

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Answer:

Step-by-step explanation:

Assuming x(t) to be the number of salt

The maximum bottom of deposits =300 Litre

Initial Concentration of the saturated salt solution = 1 kg of salt for 3 liters of water

\(x_ic_i= \dfrac{1}3\)

⇒x = 0

The  differential equation is :

\(\dfrac{dx(t)}{dt}\) \(={x_ic_i}-{x_oc_o}\)

       \(= \dfrac{1}{3} - \dfrac{x(t)}{300}\)

\(\dfrac{dx(t)}{dt} + \dfrac{x(t)}{300} = \dfrac{1}{3}\)

Using the first order differential equation of the form :

x' + p(t) x = q(t)

where

\(p(t) = \dfrac{1}{300}\)   ;   \(q(t) = \dfrac{1}{3}\)

By integrating the factor:

\(\mu = e^{\int\limitsP(t)dt } \\ \\ =e^{\int\limits \dfrac{1}{300}dt } \\ \\ = e^{\frac{t}{300} }\)

\(x(t) = \dfrac{1}{\mu(t) }\int\limits \mu (t) * q(t) dt \\ \\ = e ^{- t/300} \ \ [\int\limits e ^{+ t/300} * \dfrac{1}{3}dt ]\)

\(= e ^{- t/300} \ \ [\dfrac{1}{3} * \dfrac{e^{t/300}}{1/300} + C ]\)

\(x(t) = 100 + Ce ^{-t/300\)

Thus the differential equation solution  is : \(x(t) = 100 + Ce ^{-t/300\)

However; we have initial concentration   x(0) = 0

SO;

\(0 = 100 + Ce^{-0/300}\)

C = -100

\(x(t) = 100 -100e ^{-t/300\)

when x → ±[infinity]

\(\infty = 100 + Ce^{- \infty /300}\)

\(x(t) = 100 -100e ^{-t/300\)

Now;  the amount of salt after an hour is as follows:

1 hour = 60  minutes

t = 60 min

\(x(60) = 100 -100e ^{-60/300\)

= 100 -100 (0.818)

= 100 - 81.8

= 18.2

x(60) = 18.2 kg

Answer:

75%

Step-by-step explanation:

75% of 3/4 of 48 is 36

Hope this helps :D

AnsWER

Step-by-step explanation:

is  %## because ## happens ## be #### we #### to ###### so ## divided ## 36 ## %13

The value of x is 24 and different angles of hexagon will be -

A = 160

B = 142

C = 120

D = 156

E = 31

F = 111

An angle is a geometric shape that is defined as the amount of rotation that occurs between two straight lines or planes. Angles are measured in degrees, with 360° representing a full circle.

We need to apply the inverse tangent function to determine the angle at which the sun strikes the flagpole. We are aware that the triangle's adjacent side is 42 feet long and its opposite side is 25 feet tall (the height of the flagpole) (the length of the shadow).

Given the figure is hexagon,

the sum of angles of a hexagon is 720,

Upon adding the given angles,

mA = (7x-8)°

mB (4x+46)°

mC = (5x)

mD = (6x+12)°

mE = (x+7)°

mF = (5x-9)°

⇒ 7x - 8 + 4x + 46 + 5x + 6x + 12 + x + 7 + 5x - 9 = 720

⇒ 28x + 48 = 720

⇒ 28x = 672

⇒ x = 24

Therefore, the angles will be -

A = 160

B = 142

C = 120

D = 156

E = 31

F = 111

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The number 842 is the number whose digit 4 is ten times larger than in the number 384

To solve the problem, we need to find a number in which the digit 4 is ten times larger than in the number 384.

In the number 384, the digit 4 is in the ones place, which means that its value is 4.

To find a number in which the digit 4 is ten times larger, we need to find a number in which the digit 4 is in the tens place and its value is 10 times larger than 4, which is 40.

The only answer option that fits this description is 842. In this number, the digit 4 is in the tens place and its value is 40, which is ten times larger than its value in the number 384.

Therefore, the correct answer is 842.

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Answer:

there is a thing called you can use that

Step-by-step explanation:

Respuesta: 28 billetes de 100 y 11 billetes de 200

Explicación paso a paso:

X=39-y

200(39-y)+100y=5000

7800-200x+100y=5000

-100y=2800

Y=2800/100

Y=28 billetes de 100

X=39-28

X=11 billetes de 200

The expression becomes: p^(1/2) = p^(1/2 * 1) = p^(1/2) Now we can simplify p^(1/2) as p^1/2 which equals the square root of p.

The property of exponents that must be applied to the expression p^(1/2) to derive p as the result is the Power of a Power Property.

The Power of a Power Property states that when a power is raised to another power, the exponents are multiplied.

For instance, consider the expression p^(1/2). We can apply the Power of a Power Property to this expression as follows: p^(1/2) = (p^(1/2))^1 By applying the Power of a Power Property, the exponent (1/2) is multiplied by the exponent 1, giving a result of 1/2.

Therefore, the expression becomes: p^(1/2) = p^(1/2 * 1) = p^(1/2)Now we can simplify p^(1/2) as p^1/2 which equals the square root of p.

So we have derived p as the result using the Power of a Power Property.

In summary, we must apply the Power of a Power Property to the expression p^(1/2) to derive p as the result.

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The Vales of x in the equations are : 1) 3 (2) 1  (3) 5  (4) 14  (5) 10 respectively

A linear equation in one variable is that in which the highest power of its variable is 1

The given equations and their solutions are

2x +1 = 7

By collecting like terms we have

2x = 3

x = 3

2) The given equation is 4x +7 = 11

By collecting like terms we have

4x = 4

Making x the subject we have

x = 1

3) 2x -3 = 7

By collecting like terms we have

2x = 10

Making x the subject we have

x = 5

4) 1/2 x - 3 = 7

By collecting like terms we have

1/2x = 7

x= 14

5) The given equation is 3x - 11 = 19

By collecting like terms we have

3x= 30

Therefore x= 10

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Answer:

I dont but want to.

Hope this helps! :) ;-;

Step-by-step explanation:

The percentage of male goat is 56%

We have given that  14 of the goats are male,and 11 of the goats are female.

We have to calculate what percentage of these goat are male:

Total number of goat

14+11=25 goats

The goats are male=14

The goats are female=11

What is the formula for percentage?

\(\frac{number of goats}{total number of goats}*100\)

percentage of male goats is,

\(=\frac{no of male goats}{total no of goats}*100\)

\(=\frac{14}{25} *100\)

\(=14*4\)

\(=56\)

Therefore we get the percentage of male goat is 56%

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Answer:

The answer is in the link

Step-by-step explanation:

Brainliest pls

Answer:

How heavy is a full grown black bear?

2-3 feet at the shoulders and weights average 150 -300 pounds, with females smaller than males; some male bears weighing 700-800 pounds have been documented.

Step-by-step explanation:

HOPE THIS HELPED ✨

The weight difference between a female black bear and a female key deer is 80 or lower.

a female black bear can weight up to 180 pounds while a female key deer can weight up to 100 pounds.

the weight difference between a male black bear and a male key deer is 510 pounds.

a male black bear can weigh up to 660 punds while a male key deer can weigh up to 150 pounds.

Answer:

The {(1, 3), (-4, 0), (3, 1), (0, 4), (2, 3)} is a function. A relation will be a function if each domain value corresponds to one and only value in the range.

Step-by-step explanation:

Start Cheatin more But Thanks for the coins

Step-by-step explanation:

Improper fractions have a numerator that is larger than the denominator

1 = 6/6

 so  1  1/6  = 7/6

Answer:

9x^2 - 12x + 6 =0

work is pictured and shown

The missing coordinates of given vectors a, b, c, d, and e are 0,0,0, -0.8, and 0. Then, the vectors are \(\vec{u}=\left[\begin{array}{ccc}-0.6\\0.8\\0\end{array}\right]\), \(\vec{v}=\left[\begin{array}{ccc}0\\0\\1\end{array}\right]\), and \(\vec{w}=\left[\begin{array}{ccc}-0.8\\-0.6\\0\end{array}\right]\)

We refer to two vectors as being orthogonal if they are perpendicular to one another. So these vectors' dot product will be zero. Let the given three vectors be \(\vec{u}\), \(\vec{v}\), and \(\vec{w}\). And the unknowns be a, b, c, d, and e.

Then, the vectors are written as

\(\vec{u}=\left[\begin{array}{ccc}-0.6\\0.8\\a\end{array}\right]\), \(\vec{v}=\left[\begin{array}{ccc}b\\c\\1\end{array}\right]\), and \(\vec{w}=\left[\begin{array}{ccc}d\\-0.6\\e\end{array}\right]\)

First, take \(\vec{u}\) and consider unit length, we get,

\(1=\sqrt{(-0.6)^2+(0.8)^2+a^2}\\1=1+a^2\\a=0\)

For \(\vec{v}\), we get,

\(1=\sqrt{(b)^2+(c)^2+1^2}\\1=1+b^2+c^2\\b=0\;\text{and}\;c=0\)

We know that \(\vec{w}\) is orthogonal to both vectors, then,\(\vect{w}\cdot{\vec{v}=0\). Substituting, the values of \(\vec{v}\) and \(\vec{w}\), we get,

\(\begin{aligned}\langle d, -0.6, e\rangle \;\cdot\;\langle 0, 0, 1\rangle&=0\\e&=0\end{aligned}\)

Also, \(\vect{u}\cdot{\vec{w}=0\),  Substituting, the values of \(\vec{u}\) and \(\vec{w}\), we get,

\(\begin{aligned}\langle -0.6, 0.8, 0\rangle \;\cdot\;\langle d, -0.6, e\rangle&=0\\-0.6d-0.48+0&=0\\-0.6d&=0.48\\d&=-0.8\end{aligned}\)

Therefore, the required answers for a, b, c, d, and e are 0,0,0, -0.8, and 0.

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