Answers
Answer:
Step-by-step explanation:
Related Questions
Consider the function given below: (defun things (x) (if (null x ) '() (if (>(carx) 10) (cons(+(carx) 1) (things (cdrx))) (cons (- (car x) 1) (things (codr x)) ) 1 ) 1 Show the evolution resulting from the following call: USP> (things '(11-2 31))
Answers
The evolution of the function call (things '(11 -2 31)) is as follows:
(things '(11 -2 31)) -> (things '(-2 31)) -> (things '(31)) -> (things '()) -> '() the final result of the given call is '().
The given function is a recursive function called "things" that takes a list as input. It checks if the list is empty (null), and if so, it returns an empty list. Otherwise, it checks if the first element of the list (car x) is greater than 10. If it is, it adds 1 to the first element and recursively calls the "things" function on the rest of the list (cdr x). If the first element is not greater than 10, it subtracts 1 from the first element and recursively calls the "things" function on the rest of the list. The function then returns the result.
Now, let's see the evolution resulting from the call (things '(11 -2 31)):
1. (things '(11 -2 31))
Since the list is not empty, we move to the next if statement.
The first element (car x) is 11, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.
The recursive call is (things '(-2 31)).
2. (things '(-2 31))
Again, the list is not empty.
The first element (car x) is -2, which is not greater than 10, so we subtract 1 from it and recursively call the "things" function on the rest of the list.
The recursive call is (things '(31)).
3. (things '(31))
The list is still not empty.
The first element (car x) is 31, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.
The recursive call is (things '()).
4. (things '())
The list is now empty, so the function returns an empty list.
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find the volume of the cylinder.
either enter an exact answer in terms of pi or the use of 3.14
radius 3
height 6
Answers
Answer:
Volume, \(V=169.56\ \text{units}^3\)
Step-by-step explanation:
We have,
Radius of cylinder is 3 units
Height of the cylinder is 6 units
It is assumed to find the volume of the cylinder. The formula of the volume of cylinder is given by :
\(V=\pi r^2 h \\\\V=3.14\times 3^2 \times 6\\\\V=169.56\ \text{units}^3\)
So, the volume of the cylinder is \(169.56\ \text{units}^3\).
What is the 7th term of the geometric sequence below? 7, -14,28, -56, А -448 b b -896 с 448 D 896
Answers
Given the sequence:
7, -14, 28, -56,
To find the 7th term of the geometric sequence, use the formula below:
\(a_n=ar^{(n-1)}\)where,
a is the first term = 7
n is the number of terms = 7
r = common ratio =
\(r\text{ = }\frac{\sec ond\text{ term}}{\text{first term}}\text{ = }\frac{-14}{7}=\text{ -2}\)Thus, we have:
\(\begin{gathered} a_7=\text{ 7(}-2^{(7-1)}) \\ \\ \text{ = 7 }(-2^6) \\ \\ \text{ = }7(-64) \\ \\ \text{ = }-448 \end{gathered}\)The 7th term is -448
ANSWER:
A) -448
all the formulas of area
Answers
Answer:
Area of rectangle=l×b×h
Area of square=4l
Answer:
Area = l × w
Area = a2
Area = 1/2 b×h
Area = πr2
Area = 1/2 (a + b)h
Area = πab
Step-by-step explanation:
Area of Rectangle = Area = l × w
Area of square = Area = a2
Area of a Triangle = Area = 1/2 b×h
Area of a Circle = Area = πr2
Area of a Trapezoid = Area = 1/2 (a + b)h
Area of Ellipse = Area = πab
Given the following estimates of zonal productions and attractions of many trips would be produced from zone 3 after balancing productions and attractions? HBW trips, how Zone Productions Attractions 1 240 100 2 400 200 3 160 300 Total 800 600
Answers
A negative value indicates that more people would be attracted to Zone 3 than would be produced from it. Therefore, we cannot calculate the number of HBW trips that would be produced from Zone 3 after balancing productions and attractions.
Given the following estimates of zonal productions and attractions, it is possible to calculate the number of HBW (home-based work) trips that would be produced from Zone 3 after balancing the productions and attractions.
To balance the productions and attractions, we need to use the following formula:
Total productions - Zone 3 production = Total attractions - Zone 3 attraction
In this case, the total productions are 800 (240+400+160), and the total attractions are 600 (100+200+300). So, we can plug in the values we have:
800 - 160 = 600 - Zone 3 attraction
Simplifying this equation, we get:
Zone 3 attraction = 240
Now that we know the attraction from Zone 3 is 240, we can calculate the number of HBW trips that would be produced from Zone 3 using the formula:
HBW trips from Zone 3 = Zone 3 production - Zone 3 attraction
Plugging in the values we have:
HBW trips from Zone 3 = 160 - 240 = -80
A negative value indicates that more people would be attracted to Zone 3 than would be produced from it. Therefore, we cannot calculate the number of HBW trips that would be produced from Zone 3 after balancing productions and attractions.
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my correlation coefficient for the linear model i created is 0.8. What does this mean?
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Elizabeth is a nurse, and she just administered 1. 8 milliliters of medication to one of her patients. Elizabeth knows that the amount of medication remaining in the patient's body will decrease by a factor of 1 3 each hour
Answers
If the amount of medication in the body decrease by a factor of 1/3 each hour , then the exponential function is y = 1.8(2/3)ˣ .
Let M = the initial amount of medication administered = 1.8 milliliters , and
Let y = the amount of medication remaining in the patient's body after x hours.
We know that the medication amount will decrease by a factor of 1/3 each hour, which means that after 1 hour, only (1-1/3) = 2/3 of the medication will remain, after 2 hours, only (2/3)² will remain, and so on.
So we can write the equation in exponential form as :
⇒ y = M × (1-1/3)ˣ
⇒ y = M × (2/3)ˣ ;
substituting the initial value as 1.8 ,
we get ;
⇒ y = 1.8 × (2/3)ˣ ;
where x = number of hours that have passed since the medication was administered.
Therefore , the exponential function for the situation is y = 1.8 × (2/3)ˣ .
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The given question is incomplete , the complete question is
Elizabeth is a nurse, and she just administered 1.8 milliliters of medication to one of her patients. Elizabeth knows that the amount of medication remaining in the patient's body will decrease by a factor of 1/3 each hour .
Write an exponential equation in the form y = a(b)ˣ that can model the amount of medication (y) , remaining in the patient's body after x hours .
Tim takes a sheet of paper and makes a diagonal cut from one corner to the opposite corner, making two triangles. The cut he makes is 10 inches long and the width of the paper is 9 inches. What is the paper's length?
Answers
In a diagram, this is the information we have
Notice that, after cutting the sheet of paper, we get 2 right triangles.
We can use the Pythagorean theorem to find the length of the paper as follows:
\(\begin{gathered} (10in)^2=(9in)^2+(length)^2 \\ \Rightarrow\text{length}=\sqrt[]{(10in)^2-(9in)^2}^{} \\ \Rightarrow\text{length}=\sqrt[]{19in^2} \\ \Rightarrow\text{length}=\sqrt[]{19}in \end{gathered}\)The answer is sqrt(19) in, which is, approximately, 4.36 in
What’s this answer ?
Answers
Answer:
12
Step-by-step explanation:
The average rate of change for f(x) in the closed interval [ a, b ] is
\(\frac{f(b)-f(a)}{b-a}\)
Here [ a, b ] = [ 1, 3 ] , then
f(b) = f(3) = 27 ← value of y from table for x = 3
f(a) = f(1) = 3 ← value of y from table for x = 1
average rate of change = \(\frac{27-3}{3-1}\) = \(\frac{24}{2}\) = 12
A case of wood screws weights LaTeX: 18\frac{2}{3}\:18 2 3 pounds. Each individual box of wood screws weighs LaTeX: 1\frac{1}{3}1 1 3 pounds. How many boxes are in the case?
Answers
Answer:
5
Step-by-step explanation:
Cause you have to divide 113 by 23 and you get 4.91304347836 and cause a bigger number you have to round up and u will get at least 5 boxes.I hope I helped :)
A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel—emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition Display Panel 1 2 3 4 A 17 25 31 14 14 24 35 13 B 15 22 28 9 12 19 31 10 C 21 29 32 15 24 28 37 19 Least Squares Means Estimates Panel Estimate Condition Estimate A 21. 500000 1 17. 166670 B 18. 375000 2 24. 666670 C 25. 625000 3 32. 166670 4 13. 333300 Analysis of Variance Source DF Sum of Squares Mean Square F Ratio Model 11 1,480. 3333 134. 576 30. 4700 Error 12 53. 2000 4. 417 Prob > F C. Total 23 1,533. 3333 <. 0001* Effect Tests Source Nparm DF Sum of Squares F Ratio Prob > F Panel 2 2 211. 5833 23. 9528 <. 0001* Condition 3 3 1,253. 0000 94. 5660 <. 0001* Panel* Condition 6 6 15. 7500 0. 5943 0. 7298 Tukey HSD All Pairwise Comparisons Quantile = 2. 66776, Adjusted DF = 12. 0, Adjustment = Tukey Panel -Panel Difference Std Error t Ratio Prob>|t| Lower 95% Upper 95% A B 3. 12500 1. 050793 2. 97 0. 0290* 0. 3217 5. 92826 A C −4. 12500 1. 050793 −3. 93 0. 0053* −6. 9283 −1. 32174 B C −7. 25000 1. 050793 −6. 90 <. 0001* −10. 0533 −4. 44674 Tukey HSD All Pairwise Comparisons Quantile = 2. 9688, Adjusted DF = 12. 0, Adjustment = Tukey Condition -Condition Difference Std Error t Ratio Prob>|t| Lower 95% Upper 95% 1 2 −7. 5000 1. 213352 −6. 18 0. 0002* −11. 1022 −3. 8978 1 3 −15. 2000 1. 213352 −12. 36 <. 0001* −18. 6022 −11. 3978 1 4 3. 8333 1. 213352 3. 16 0. 0359* 0. 2311 7. 4355 2 3 −7. 5000 1. 213352 −6. 18 0. 0002* −11. 1022 −3. 8978 2 4 11. 3333 1. 213352 9. 34 <. 0001* 7. 7311 14. 9355 3 4 18. 8333 1. 213352 15. 52 <. 0001* 15. 2311 22. 4355 Click here for the Excel Data File.
a. Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places. )
Answers
Without the standard deviation, we cannot calculate the standard error or the 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B.
To calculate a 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B, we can use the least squares means estimates provided in the JMP output.
According to the JMP output, the estimate for the mean time required to stabilize emergency condition 4 using display panel B is 10.375000.
To calculate the confidence interval, we need to find the margin of error. The margin of error can be calculated using the formula:
Margin of Error = Critical Value * Standard Error
In this case, we need to find the critical value for a 95 percent confidence interval. Since we have a sample size of 24 (as mentioned in the question), we can use the t-distribution with (24-1) degrees of freedom to find the critical value.
Looking up the critical value in the t-distribution table, with (24-1) degrees of freedom and a confidence level of 95 percent, we find that the critical value is approximately 2.064.
The standard error can be calculated using the formula:
Standard Error = Standard Deviation / √(sample size)
The standard deviation is not provided in the given information. Therefore, we cannot calculate the standard error or the confidence interval without this information.
In summary, without the standard deviation, we cannot calculate the standard error or the 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B.
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Pete's Plainting charges $25 per room to paint, plus an additional $0.50 per square foot that they paint. If they charges me $201 to paint my kitchen, how many square feet did they paint?
Answers
Answer:
352 square feet
Step-by-step explanation:
thats the answer ( i dont know how to explain it sorry )
A group of 200 adults were asked whether they exercise and what they are vegetarian
Answers
Step-by-step explanation:
(a) What percentage of the adults exercise?
₹
(b) What percentage of the adults are vegetarian?
€
(c) What percentage of the adults who are vegetarian exercise? [ (d) Is there evidence that adults who are vegetarian tend to be exercisers more often than average?
Yes, because the percentage found in part (c) is much greater than the percentage found in part (a).
Yes, because the percentage found in part (c) is much greater than the percentage found in part ((b).
No, because the percentage found in part (c) is about the same as the percentage found in part ((a).
No, because the percentage found in part (c) is about the same as the percentage found in part ((b).
for what values of x does 5x^2+4x-4=0
Answers
Answer: See explanation
Step-by-step explanation:
x=-(2-2*the square root of 6)/5, about 0.58
or
x=-(2+2*the square root of 6)/5, about -1.38
The values of the x from equation \(5x^2+4x-4=0\) are x = 0.5798 and -1.38.
Given that:
Equation: \(5x^2+4x-4=0\)
To find the values of x that satisfy the equation \(5x^2+4x-4=0\), use the quadratic formula:
\(x = \dfrac{ -b \± \sqrt{b^2 - 4ac}}{ 2a}\)
Compare the equation with \(ax^2 + bx + c = 0\).
Here, a = 5, b = 4, and c = -4.
Plugging in the values to get,
\(x = \dfrac{-4 \± \sqrt{4^2 - 4 \times 5 \times (-4)}}{2 \times 5} \\x = \dfrac{-4 \± \sqrt{16 +80}}{10} \\x = \dfrac{-4 \± \sqrt{96}}{10}\\x = \dfrac{-4 \± {4\sqrt6}}{10}\)
So the solutions for x are calculates as:
Taking positive sign,
\(x = \dfrac{-4 + {4\sqrt6}}{10}\\x = \dfrac{-4 + {9.798}}{10}\\\)
x = 5.798/10
x = 0.5798
Taking negative sign,
\(x = \dfrac{-4 - {4\sqrt6}}{10}\\x = \dfrac{-4 - {9.798}}{10}\\\)
x = -13.798/10
x = -1.38
Hence, the exact solutions for the equation \(5x^2 + 4x - 4 = 0\) are x = 0.5798 and -1.38.
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A delivery drone approaches a customer's porch, flying 14.1 m above the porch at 22.6 km/h. Calculate the speed the package hits the porch if it's released by the drone. Please report your speed in meters per second to 1 decimal place. Hint: speed is the magnitude of velocity and is thus always positive
Answers
The speed the package hits the porch when it is released by the drone is 16.9 m/s (approx)
Given data: Height of drone, h = 14.1 m
Velocity of drone, v = 22.6 km/h
The speed the package hits the porch when it is released by the drone.
It is given that the drone is flying at a height of 14.1 m above the porch and it releases the package. The package falls freely under gravity.
We can use the formula for the velocity of a freely falling body to calculate the speed the package hits the porch.
v² = u² + 2gh
Here, g is the acceleration due to gravity and u = 0 as the package is initially at rest.
Therefore, the above formula becomes,
v² = 2ghv = √(2gh)
We know that the height of the drone above the porch is h = 14.1 m.
We can convert the velocity of the drone,
v = 22.6 km/h, into m/s.
1 km/h = 1000 m/3600 s = 0.27778 m/sv = 22.6 km/h = 22.6 × 0.27778 m/s = 6.27708 m/s
Substituting the given values in the above formula, we get,
v = √(2gh)= √(2 × 9.81 m/s² × 14.1 m)≈ 16.91 m/s
Therefore, the speed the package hits the porch when it is released by the drone is 16.9 m/s (approx)
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Determine whether the statement is true or false. Explain your reasoning. If itis false, provide a counterexample.Statement: Two triangles that have congruent angles are congruent.
Answers
Answer:
The statement is False
Explanation:
Statement: Two triangles that have congruent angles are congruent.
The statement is False.
As a counterexample, consider the two triangles below:
The two triangles above have congruent angles 45°-45°-90.°
However, the side lengths are not the same, thus, the triangles are not congruent, hence supporting our claim that the given statement is False.
State the transformation from the parent function (y=log2 X) to f(x)=4-log2(x+2)
Answers
Answer:
Step-by-step explanation:
Just like a lot of our other curve transformations
The number with x => (x+2) is the shift in x direction and you take opposite sign so it's been shifted -2 or left 2
bring the 4 to the back of teh equation and it will be +4, that controls the y direction which is +4 or up 4
That would leave a - in the front which means the graph wil be reflected.
The graph of y=3x is shown. What is the value of x when y=27?
A. 2
B. 3
C. 9
D. 24
It said c was wrong
Answers
Answer:
x = 3
Step-by-step explanation:
Is x an exponent?
\( y = 3^x \)
\( 27 = 3^x \)
\( 3^3 = 3^x \)
\( x = 3 \)
The fence around Stan's rectangular backyard is 48 feet. His yard is 3 feet longer than twice its width. What is the length of Stan's yard?
Answers
Answer: Length = 17 ft
Concept:
Here, we need to know how to find the perimeter of a rectangle.
Perimeter (rectangle) = 2 (l + w)
l = length
w = width
If you are still confused, you may refer to the attachment below for a graphical explanation or tell me.
Solve:
**Disclaimer** I assume that the length is [3 feet longer than twice its width] because a [yard] would not use length to measure it. If it was, then you may refer to my answer. If it was not, then you may tell me and I will redo it.
Let x be the width
Let 2x + 3 be the length
Given information
Perimeter = 48 ft
width = x
length = 2x + 3
Given expression deducted from the question
Perimeter = 2 (l + w)
Substitute values into the expression
48 = 2 (2x + 3 + x)
Combine like terms in the parentheses
48 = 2 (2x + x + 3)
48 = 2 (3x + 3)
Expand parentheses and apply the distributive property
48 = 2 · 3x + 2 · 3
48 = 6x + 6
Subtract 6 on both sides
48 - 6 = 6x + 6 - 6
42 = 6x
Divide 6 on both sides
42 / 6 = 6x / 6
x = 7
Find the value of length
Length = 2x + 3 = 2(7) + 3 = 14 + 3 = \(\boxed{17}\)
Hope this helps!! :)
Please let me know if you have any questions
A cell phone company uses the equation C=$0.15t+$35.00 to determine the total cost, C, for a month of service based on the number of text messages, t. Identify the slope.
Answers
Slope is $0.15 of the equation of cost C=$0.15t+$35.00.
What is Slope of Line?The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.
The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is
m=y₂-y₁/x₂-x₁
Given that A cell phone company uses the equation C=$0.15t+$35.00
C is the total cost for a month of service.
t is the number of text messages.
We have to find the slope of the equation.
slope is 0.15 and 35.00 is the y intercept of the equation given.
Hence, slope is $0.15 of the equation of cost C=$0.15t+$35.00.
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2.) Let's consider a Stackelberg version of monopolistic competition. Suppose market demand is given by P = 30 – Q and there are ""n"" firms in the market with the first firm denoted as the leader
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The specific numerical solution will depend on the number of firms in the market and their behavior.
In a Stackelberg version of monopolistic competition, there is a leader firm that sets its output first, and all the other firms in the market act as followers and choose their outputs simultaneously.
Suppose there are "n" firms in the market, with the first firm denoted as the leader. Let's assume that each firm has a constant marginal cost of $10 per unit. Then, the leader firm's profit-maximizing output level can be found by solving the following problem:
max (30-Q1-Q2-...-Qn)Q1 - 10Q1
subject to Q1 >= 0
where Q1 is the output level of the leader firm, and Q2, Q3, ..., Qn are the output levels of the follower firms.
Taking the first-order condition by differentiating with respect to Q1 and setting it equal to zero, we get:
d/dQ1 [(30-Q1-Q2-...-Qn)Q1 - 10Q1] = 0
Simplifying this expression, we get:
30 - Q1 - Q2 - ... - Qn - 2Q1 = 0
Solving for Q1, we get:
Q1 = (30 - Q2 - ... - Qn)/3
This equation gives us the leader firm's profit-maximizing output level as a function of the follower firms' output levels.
Now, let's consider the follower firms' profit-maximizing output levels. Since each follower firm is a price-taker, its profit-maximizing output level can be found by equating marginal cost to market price, which is equal to the market demand curve divided by the total quantity produced by all firms in the market. Therefore, the profit-maximizing output level of the jth follower firm can be expressed as:
Qj* = (1/n) * (30 - Q1 - Q2 - ... - Qj-1 - Qj+1 - ... - Qn - 10)
where Qj* is the follower firm's profit-maximizing output level, and j = 2, 3, ..., n.
Using these expressions for the leader and follower firms' profit-maximizing output levels, we can solve for the equilibrium outputs and profits in the Stackelberg version of monopolistic competition. However, the specific numerical solution will depend on the number of firms in the market and their behavior.
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Could someone plz help me on this math problem
Answers
Answer:
√7/22
Step-by-step explanation:
p=√7
b=22 ( R as reference)
tanR= p/b
√7/22
You can round yourself if necessary.
Can someone please help me with my homework !
Answers
Answer:
Nah ;)
Step-by-step explanation:
You bought a magazine for $5 and 20 erasers. If you spent a total of $11, how much did each eraser cost
Answers
Answer:
.30 cents
Step-by-step explanation:
11-5=6
6 divided by 20
Which of the following integrals represents the area of the region bounded in the first quadrant by x = pi/ 4 and the functions f(x) = sec^2(x) and g(x) = sin(x)? O π/4 (sec²(x)+sin(x))dx
O π/4 (sec²(x)-sin(x))dx
O π/4 (sin(x)-sec² (x))dx
O (sec²(x)-sin(x))dx
Answers
The integral that represents the area of the region bounded in the first quadrant by x = π/4 and the functions f(x) = sec^2(x) and g(x) = sin(x) is π/4 (sec^2(x) - sin(x))dx.
To find the area of the region bounded by the curves, we need to subtract the integral of the lower curve from the integral of the upper curve. In this case, the upper curve is f(x) = sec^2(x) and the lower curve is g(x) = sin(x).
The integral representing the area is given by:
Area = ∫[a,b] (f(x) - g(x))dx
Substituting the given functions, we have:
Area = ∫[0,π/4] (sec^2(x) - sin(x))dx
This integral represents the area bounded by the x-axis, the curve y = sec^2(x), the curve y = sin(x), and the vertical line x = π/4. The integral of (sec^2(x) - sin(x))dx over the interval [0,π/4] calculates the area between the two curves within the specified region.
Therefore, the correct integral that represents the area of the region in the first quadrant is π/4 (sec^2(x) - sin(x))dx.
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Write an expression for the total number of cruise ships in the harbor on all 5 days.
I'll give brainiest to whoever answers it first!!!
And you get 100 points
Answers
Solution:
Note that:
Total number of cruise ships = M + T + W + Th + FriSubstitute the values in the expression:
Total number of cruise ships = M + T + W + Th + Fri=> Total number of cruise ships = x - 4 + x + 9 + 2x + 3x - 7 + 4Combine Like terms:
=> Total number of cruise ships = x(1 + 1 + 2 + 3) - 4 + 9 - 7 + 4Further Simplify:
=> Total number of cruise ships = x(7) + 2=> Total number of cruise ships = 7x + 2Anybody help plsssss
Answers
Answer:
1200 you minus the 6900 from the 8100
Consider this story problem: "Priscilla bought cheese that weighs ¾ pounds. If she divides it into portions that are each 1/8 pound, how many portions can she make?" The value 3/4 is which part of the equation?
Answers
Answer:
4
Step-by-step explanation:
Find the length of the third side. If necessary, round to the nearest tenth. 8 17
Answers
Answer:
definitely 20
Step-by-step explanation:
only if it has to be a tenth tho if not then 25?=)
Answer:
15
Step-by-step explanation:
Se calcula que inhalamos alrededor de 15 veces por minuto y, en ese tiempo, respiramos 7.5 litros de oxígeno. Cuando exhalamos, nuestros pulmones no se vacían; siempre queda alrededor de un litro de oxígeno adentro de ellos.
Answers
Es CIERTO afirmar que se estima que inhalamos unas 15 veces por minuto y, en ese tiempo, respiramos 7,5 litros de oxígeno. Cuando exhalamos, nuestros pulmones no se vacían; siempre queda alrededor de un litro de oxígeno en su interior.
¿Por qué nuestro pulmón retiene algo de aire después de la exhalación?Los pulmones nunca están completamente vacíos; siempre queda algo de aire en los pulmones después de una exhalación máxima. El aire que queda en los pulmones es necesario para ayudar a evitar que los pulmones colapsen.
Es el volumen de aire que queda en los pulmones después de una exhalación máxima. El valor normal para adultos tiene un promedio de 1200 ml (20-25 ml/kg).
La respiración excesiva puede conducir a niveles bajos de dióxido de carbono en la sangre, lo que causa muchos de los síntomas que puede sentir si hiperventila.
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Full Question:
Se calcula que inhalamos alrededor de 15 veces por minuto y, en ese tiempo, respiramos 7.5 litros de oxígeno. Cuando exhalamos, nuestros pulmones no se vacían; siempre queda alrededor de un litro de oxígeno adentro de ellos.
¿Verdad de Falso?