Starting with acetylene, show reagents that you would use to prepare each of the following compounds: (a) 1-Butyne (b) 2-Butyne (c) 3-Hexyne (d) 2-Hexyne (f) 2-Heptyne (g) 3-Heptyne (h) 2-Octyne ) 2-Pentyne (e) 1-Hexyne C)

2H₂ (g)  + O₂ (g) ↔ 2H₂O (g) + heat, The system will move towards the products of the reaction for H₂O and O₂, The system will tend to move towards the reactants for last two options in the question.

Changes to the reactant components or the environment or conditions in which the reaction is occurring can significantly alter the course of the entire reaction process in an equilibrium reaction. As a result, both the removal of H2O and the addition of O2 will alter the equation of the reaction system in the direction of the product. The equation shifts toward the reaction's reactants with a decrease in pressure and an increase in temperature. An equilibrium reaction, also known as a reaction in thermodynamic equilibrium, is a chemical reaction between the reactants that maintains a stable state both before and after the reaction is complete.

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Answer:

Explanation:

From the information given:

The unknown contained salt, salicylic acid, and sand.

It is okay for the student to believe that the sand is present in the unknown, but if we carry how a scientific experiment, we will confirm such a hypothesis if it is right or wrong.

For a test containing salt, salicylic acid, and sand.

We know that the salt is soluble in water, but salicylic acid is sparingly soluble i.e., lightly soluble, and sand is insoluble in water.

So, we will add the unknown mixture into the water. The salt will eventually dissolve first, and then the salicylic acid will dissolve lightly.

Afterward, we will heat the mixture to evaporate the salicylic acid to evaporate, leaving us with the salt.

If there is a positive result of her claim that there is some presence of sand in the evaporated salt sample, that might result from impurities.

This scientific project aims to analyze and implement strategies to rejuvenate a dying lawn, ensuring its vitality and health.

If you notice that a lawn looks unhealthy and the grass is dying, you can undertake a scientific project to save it by following these steps:

Step 1: Identify the problemThe first step is to identify the problem. Observe the lawn and try to determine what is causing the grass to die. Common causes include poor soil quality, lack of water, too much sun or shade, pests, or disease.

Step 2: ResearchOnce you have identified the problem, conduct research to find out more about it. Look for information about how to treat the specific problem that is causing the grass to die. You can consult gardening books or online resources.

Step 3: Develop a hypothesisBased on your research, develop a hypothesis about what is causing the problem. For example, if you think the soil quality is poor, your hypothesis might be that adding fertilizer will improve the health of the grass.

Step 4: Design an experimentDesign an experiment to test your hypothesis. For example, if your hypothesis is that adding fertilizer will improve the health of the grass, you could divide the lawn into two sections. Apply fertilizer to one section and not the other. Record your observations over time to see if the grass in the fertilized section is healthier.

Step 5: Conduct the experiment , Carry out your experiment, making sure to record your observations.

Step 6: Analyze the data Analyze your data and determine whether your hypothesis was correct. If the grass in the fertilized section is healthier than the grass in the section without fertilizer, your hypothesis was correct.

Step 7: Draw a conclusion Based on your analysis, draw a conclusion about what is causing the problem and how it can be fixed. For example, if your experiment showed that adding fertilizer improved the health of the grass, you could conclude that the soil quality is poor and that fertilizing the lawn will help to improve it.

Step 8: Take action Based on your conclusion, take action to fix the problem. In this case, you would apply fertilizer to the entire lawn to improve its health.

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Answer:

0.1gram

Explanation:

mass = no of moles × molar mass

Answer:

B. Only potential energy C. Both kinetic and potential energy D. Neither potential nor kinetic 1 See answer All molecules move and therefore have kinetic energy. They also hold bond energies which I believe count as potential energy. Advertisement Advertisement

Explanation:

Answer:

I believe its c

Explanation:

i'm doing it on edge, let me know if i'm wrong

Answer:

The answer is C.)Protons have an electrical charge, but neutrons have no charge.

Explanation:

I got it right on edge

C = Ca

A = 20

B = 42

₁₉⁴²K →   ⁴²₂₀Ca  +  ⁰₋₁e

There is an addition of one electron. The atomic number increases by one.

Positrons or electrons make up beta particles (electrons with positive electric charge, or antielectrons). In a nucleus with an excessive number of protons or neutrons, beta decay happens when one of the protons or neutrons is converted into the other. A neutron degrades into a proton, electron, and antineutrino in beta minus decay. A proton degrades into a neutron, a positron, and a neutrino in beta plus decay.

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The correct answer is:Only statements 1 and 2 are correct.

1) The bond is planar.

2) There is free rotation about the carbonyl carbon and nitrogen bond.

The bond is planar: True, Peptide bond is a planar bond because it is composed of a double bond between the carbonyl carbon and nitrogen, and the atoms on either side of the double bond are sp2 hybridized. There is free rotation about the carbonyl carbon and nitrogen bond: True, the peptide bond between amino acids in a protein is a single bond, which allows for rotation about the bond, this is one reason proteins can adopt many different conformations.There is substantial double-bond character to this bond: False, the peptide bond is actually a single bond, although it has some double-bond character, it is not a double bond.There is a net negative charge on nitrogen and net positive charge on oxygen: False, both nitrogen and oxygen atoms in a peptide bond are neutral, as there is no charge separation in the bond.

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The solubility of methyl bromide in water at 25°C and a partial pressure of 300 mm Hg can be calculated using Henry's Law. The Henry's Law constant for methyl bromide is given as 0.159 mol/(L atm) at 25°C. By applying the equation for Henry's Law, the solubility of methyl bromide in water can be determined.

Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's Law is written as:

S = k * P

Where S is the solubility of the gas in the liquid, k is the Henry's Law constant, and P is the partial pressure of the gas. In this case, we are given the Henry's Law constant for methyl bromide as 0.159 mol/(L atm) at 25°C. The partial pressure of methyl bromide is given as 300 mm Hg.

Substituting the values into the equation, we have:

S = 0.159 mol/(L atm) * (300 mm Hg)

To convert mm Hg to atm, we divide by the conversion factor of 760 mm Hg/atm:

S = 0.159 mol/(L atm) * (300 mm Hg / 760 mm Hg/atm)

Simplifying the equation, we find:

S ≈ 0.0628 mol/L

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The mass of nitrogen gas in the sample is 0.001355 g and the number of molecules of nitrogen gas in the sample is 2.91 x 10¹⁹ molecules.

At STP (Standard Temperature and Pressure), the temperature is 0°C (273.15 K) and the pressure is 1 atm (101.325 kPa).

Ideal gas law is: PV = nRT

Where P will be the pressure, V will be the volume, n is number of moles, R is the ideal gas constant, and T will be the temperature.

At STP, the value of R is 0.0821 L·atm/mol·K.

The volume of the nitrogen gas sample is 1120 cm³, which is equivalent to 0.00112 m³.

Using the ideal gas law;

n = PV/RT

n = (1 atm) x (0.00112 m³) / (0.0821 L·atm/mol·K x 273.15 K)

n = 0.0000483 moles of nitrogen gas

To calculate the mass of nitrogen gas, we use the molar mass of nitrogen, which is 28.02 g/mol.

Mass of nitrogen gas = n x molar mass

Mass of nitrogen gas = 0.0000483 moles x 28.02 g/mol

Mass of nitrogen gas = 0.001355 g

To calculate the number of molecules of nitrogen gas in the sample, we use Avogadro's number, which is 6.022 x 10²³ molecules/mol.

Number of molecules of nitrogen gas = n x Avogadro's number

Number of molecules of nitrogen gas = 0.0000483 moles x 6.022 x 10²³ molecules/mol

Number of molecules of nitrogen gas = 2.91 x 10¹⁹ molecules

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Answer:

Your lungs are part of the respiratory system, a group of organs and tissues that work together to help you breathe. The respiratory system's main job is to move fresh air into your body while removing waste gases.

Answer:

Supply the body with Oxygen

Explanation:

The respiratory system helps remove waste gases and help you breath

(Your respiratory system consists of your lungs, mouth, and windpipe)

We can start by using the equilibrium concentrations of A, B, and C to calculate the equilibrium constant (Kc) for the reaction:

Kc = [C]^2 / ([A] x [B])

Substituting the given concentrations, we get:

Kc = (0.500 M)^2 / (0.200 M x 3.00 M) = 0.4167

Next, we can use the equilibrium concentrations to write an ICE table (Initial, Change, Equilibrium) to determine how the concentrations will change when we add more A to the system:

       A(g)   +   B(g)   =   2C(g)

I 0.200 M 3.00 M 0 M

C -x -x 2x

E 0.200 M - x 3.00 M - x 0.500 M + 2x

We know that we want the concentration of C to be 0.700 M, so we can set up an equation to solve for x:

0.700 M = 0.500 M + 2x

0.200 M = 2x

x = 0.100 M

This tells us that we need to add 0.100 moles of A to the system to increase the concentration of C from 0.500 M to 0.700 M at 200°C. To calculate the number of moles of A required, we can use the initial volume of the system, which is 1.00 L, and the concentration of A:

moles of A = volume x concentration = 1.00 L x 0.200 M = 0.200 moles

Therefore, we need to add 0.100 moles of A to the system, which is half the amount of A present initially.

It can take hundreds of years for a plastic bag to decompose.

Plastic bags are made from synthetic polymers, which are materials that do not biodegrade easily. In the environment, plastic bags can break down into smaller and smaller pieces, but they never completely disappear. In ideal conditions, a plastic bag can take anywhere from 10 to 1000 years to decompose, but the exact amount of time depends on a number of factors such as the type of plastic, exposure to sunlight and heat, and presence of other decomposers like bacteria and fungi.

Because plastic bags do not decompose quickly, they can persist in the environment for a long time and cause problems for wildlife, ecosystems, and human health. For this reason, many communities have implemented plastic bag reduction and recycling programs to help reduce their impact on the environment.

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Answer:

1.Physical change

2. Chemical change

3. Heat

4.photosynthesis

5. composition

BEcause

Explanation:

Sulfur (or sulphur in BrE) is a chemical element with the symbol S and atomic number 16. It is abundant, multivalent and nonmetallic.

The reaction between 2-methyl-2-pentanol and sulfuric acid to yield 2-methyl-2-pentene goes via an elimination reaction

Elimination reactions are those that proceed by the removal of one or more atoms or functional groups from the reactants, resulting in the formation of a new double bond or π bond in a product. An example of an elimination reaction is the dehydration of alcohols.In this particular reaction, 2-methyl-2-pentanol (an alcohol) reacts with sulfuric acid to produce 2-methyl-2-pentene, which is an alkene.

The reaction mechanism proceeds via an elimination reaction, where the OH group and a hydrogen ion (H+) are removed from the reactant, resulting in the formation of a double bond between the adjacent carbon atoms in the product.The reaction can be represented as follows:CH3C(CH3)2CH(OH)CH3 + H2SO4 → CH3C(CH3)2C=CH2 + H2O + H2SO4In conclusion, the reaction between 2-methyl-2-pentanol and sulfuric acid to yield 2-methyl-2-pentene goes via an elimination reaction.

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Answer:

D [polymers]

Explanation:

The joining of monomers (small molecules) is polymerization.

Answer:

This took forever T-T

Explanation:

1. The condition of the soil has a big impact on the environment. Good soil helps plants grow, supports different kinds of life, and prevents erosion. It also keeps nutrients in balance and affects the quality of water and air. If the soil is unhealthy or polluted, it can harm plants, animals, and the overall ecosystem.

2. The dodo bird is an example of a species that no longer exists. It used to live on an island called Mauritius. Sadly, people hunted the dodo bird for food and destroyed its habitat. They also introduced other animals that harmed the dodo bird's population. Because of these reasons, the dodo bird became extinct. This affected the environment because the dodo bird played a role in spreading seeds and helping plants grow.

3. The Sumatran orangutan is a species in danger of disappearing. Its biggest threats are losing its home due to forests being cut down for palm oil, illegal hunting, and being taken as pets. People are working to protect the orangutans by preserving their habitat, rescuing and rehabilitating them, and educating communities about their importance.

4. Central Park in New York City is a natural area created in 1857. It was made for people to enjoy nature in the middle of the city. People can do many outdoor activities there like walking, picnicking, and playing sports. The park is also home to various birds and animals, which adds to the city's biodiversity.

5. When a certain environment, like a forest or a desert, is damaged or in danger, it has a big impact on the whole ecosystem. Many different plants and animals depend on each other in these environments. If something harms or destroys their homes, it can lead to the loss of species, disruption of food chains, and less diversity. It can also affect important processes like water and carbon cycles, and even influence the climate. People who rely on these environments for resources and livelihoods are also affected. That's why it's important to protect and take care of these natural areas.

When some of the vapor is allowed to escape, the pressure of the vapor will decrease, resulting in a decrease in the rate of condensation.

This is because the vapor pressure is directly proportional to the rate of condensation. Since the pressure of the vapor is lower, it is less likely for the molecules to collide and condense.

Furthermore, the rate of vaporization will increase since the pressure inside the container is lower. This is because when the pressure is lower, the molecules require less energy to escape the liquid, thus increasing the rate of vaporization.

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The condensation rate will initially be higher than the vaporization rate.

When a liquid is in equilibrium with its vapor and some of the vapor is allowed to escape, the condensation rate will initially be higher than the vaporization rate. This is because the vapor pressure in the system has decreased due to the escape of some vapor.

To re-establish equilibrium, the liquid will increase its vaporization rate to produce more vapor. As the vaporization rate increases, it will eventually match the condensation rate again, and the system will return to equilibrium. So, initially, there is an effect on the condensation and vaporization rates, but the system will adjust to restore the equilibrium between the two rates.

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The final volume of the reconstituted cefazolin solution is 4 mL.  The volume of the cefazolin powder is 0.6 mL. The final volume of the 100 mg/mL cefazolin solution is 10 mL.

The packaging insert instructs to add 3.4 mL of sterile water without bacteriostat to the 1-g vial of cefazolin. This results in a reconstituted solution with a concentration of 250 mg/mL.

To find the final volume, we can set up the equation:

Concentration of reconstituted solution = Amount of drug / Final volume

Using the given concentration (250 mg/mL) and the amount of drug (1 g = 1000 mg), we can rearrange the equation to find the final volume:

250 mg/mL = 1000 mg / Final volume

Solving for the final volume:

Final volume = 1000 mg / 250 mg/mL = 4 mL

Therefore, the final volume of the reconstituted cefazolin solution is 4 mL.

To find the volume of the cefazolin powder, we need to subtract the volume of sterile water added from the final volume of the reconstituted solution.

Given that 3.4 mL of sterile water is added to the vial, and the final volume of the reconstituted solution is 4 mL, we can calculate the volume of the cefazolin powder as follows:

Volume of cefazolin powder = Final volume - Volume of sterile water added

Volume of cefazolin powder = 4 mL - 3.4 mL = 0.6 mL

Therefore, the volume of the cefazolin powder is 0.6 mL.

To determine the final volume of the 100 mg/mL cefazolin solution, we can use the concentration and the amount of drug.

We are given that the resulting concentration after reconstitution should be 100 mg/mL. Considering the amount of drug is 1 g (1000 mg), we can set up the following equation:

Concentration of reconstituted solution = Amount of drug / Final volume

Using the given concentration (100 mg/mL) and the amount of drug (1000 mg), we can rearrange the equation to find the final volume:

100 mg/mL = 1000 mg / Final volume

Solving for the final volume:

Final volume = 1000 mg / 100 mg/mL

Final volume = 10 mL

Therefore, the final volume of the 100 mg/mL cefazolin solution is 10 mL.

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When the electron, proton, and neutron move at the same speed, the electron will have the lowest matter wave wavelength of the trio.

The de Broglie wavelength of a particle is given by the equation λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle. Since the speed of the electron, proton, and neutron is the same, their momentum will be directly proportional to their mass.

Comparing the masses of the three particles, we find that the electron has the smallest mass, followed by the proton, and the neutron has the largest mass.

Therefore, for the same speed, the electron will have the largest momentum, and consequently, the smallest matter wave wavelength.

In summary, the electron will have the smallest matter wave wavelength among the electron, proton, and neutron when they have the same speed.

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The most appropriate definition for NH3 in the given equation is Bronsted-Lowry base, as it accepts a proton from water to form NH4+ and OH-.

The definition that applies to the compound NH3 in the given chemical equation is Bronsted-Lowry base. The Bronsted-Lowry acid-base theory defines an acid as a substance that donates a proton (H+) and a base as a substance that accepts a proton.

In the equation NH3(aq) + H2O(l) → NH4(aq) + OH-(aq), NH3 (ammonia) acts as a base because it accepts a proton (H+) from water, which acts as an acid. The water molecule donates a proton to ammonia, resulting in the formation of the ammonium ion (NH4+) and the hydroxide ion (OH-).

This reaction exemplifies the concept of proton transfer between species in a chemical reaction. According to the Bronsted-Lowry theory, the ammonia molecule (NH3) accepts a proton, making it a base. Meanwhile, water (H2O) donates a proton, making it an acid.

The Arrhenius acid-base theory defines an acid as a substance that releases hydrogen ions (H+) in an aqueous solution, and a base as a substance that releases hydroxide ions (OH-) in an aqueous solution. In the given equation, NH3 does not release H+ ions, so it does not fit the definition of an Arrhenius acid. Similarly, the hydroxide ion (OH-) in the product side does not fit the definition of an Arrhenius base.

Therefore, the most appropriate definition for NH3 in the given equation is Bronsted-Lowry base, as it accepts a proton from water to form NH4+ and OH-.

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Answer:

D. Bronsted-Lowry base

Explanation:

Answer:

There are several strategies that a local council could use to increase the percentage of used steel cans that are recycled:

Explanation:

Answer:

provide steels-specific bins to families and provide people to collect the cans

Explanation:

The recycling process plays an important role in the saving of the environment. Recyling of steel cans uses less energy than manufacturing something from the scratch. In addition, the process creates jobs for the people. There are number of recycling usints that are making a living. In order to make the process faster and easier, the coucile can encourage each househild to have a can bin. This will be dedicated to the alumininium cans. This makes iyt easuetr to dispose the bins abs tha vcans. In addition, the council can employ more people who move from house to house collecting the cans.

Answer:

its  Hypothalamus

Explanation:

To generate 48.0 L of H2 gas at 0.888 atm and 32°C, approximately 30.3 grams of CaH2 are needed according to the given conditions and calculations using the Ideal Gas Law and stoichiometry.

To determine the grams of calcium hydride (CaH2) required to produce 48.0 L of hydrogen gas at a pressure of 0.888 atm and a temperature of 32°C, we employ the Ideal Gas Law. Firstly, converting the temperature from Celsius to Kelvin yields 305.15 K. Using the equation PV = nRT, where P represents pressure, V signifies volume, n denotes moles, R represents the ideal gas constant (0.0821 L*atm/(mol*K)), and T signifies temperature in Kelvin.

Rearranging the equation to solve for n, we find n ≈ 1.44 moles. By employing the balanced chemical equation, we determine that 0.72 moles of CaH2 are required, as 1 mole of CaH2 produces 2 moles of H2. Finally, using the molar mass of CaH2 (approximately 42.1 g/mol), we find that the quantity of CaH2 needed is roughly 30.3 grams.

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The semi-crystalline polymer of the same composition, a completely amorphous polymer is expected to the crystallites scatter light.

Crystallization of polymers is a manner associated with the partial alignment of their molecular chains. these chains fold together and shape ordered areas called lamellae, which compose larger spheroidal systems named spherulites.

Semi-crystalline plastics can be taken into consideration for a selection of applications. choosing a plastic material for use in excessive temperature surroundings calls for a cautious assessment of fabric residence information. View our interactive Thermoplastics Triangle to evaluate substances.

Polyethylene is a partially crystalline solid whose residences are exceedingly dependent on the relative content of the crystalline section and amorphous section, i.e., crystallinity. Polyethylene is a polymer polymerized from monomeric ethylene.

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Answer:

Metals

Explanation: