Statement: In the Integer division block, the width of the quotient register cannot be the same size as that of the divisor or the dividend, Select the best answer that correctly gives the reason if the above statement is true or false a. False: The quotient registers needs to be the same size as that of the dividend, as this number could be equal to the dividend b. False: The quotient width needs to be equal to the sum of the widths of the divisor and the dividend, else there will be an overflow c. True: The width of the quotient has to be 32 bits no matter the size of the divisor or dividend d. True: The width of the quotient register is always going to be smaller than the dividend or divisor, since we are dividing. So the quotient register always needs to be smaller in width

Answer:

A reason why MVC may reject your road test vehicle is that there is a lack of examiner access to the emergency brake or foot brake. The examiner must be able to reach the brake pedal from the passenger seat in case of an emergency.

The tari's total standard machine-hours allowed for last year's output 600,000 hours

Budgeted at start of year:  $100,000 fixed manufacturing overhead  for 500,000 machine hours

Standard = $100,000 / 500,000 hours = $0.2 fixed overhead / maching hour

At end of year, manufacturing overhead volume was $20,000 favorable which means

$20000 / $1=0.2 = 100000 additional hours.

Total Standard Machine Allowance Allowed for output = 500,000 + 100,000 = 600,000 hours.

the use of one machine running for an hour as a basis for cost estimation and operating effectiveness evaluation. In order to determine the contribution margin per machine hour for a specific product: a. Total cost per unit divided by the quantity of machine hours required to produce each unit of the target product. The manufacturing overhead cost divided by the activity driver yields the predetermined overhead rate. For instance, if machine hours were the activity driver, you would divide overhead costs by the anticipated number of machine hours.

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The correct answer is Specific weight: w = [weight ÷ volume] = [9N ÷ 0.001m³] = 9000N/m³Density: w = [ × g] Where, g = acceleration due to gravity = 9.81m/sec². Specific gravity: G = [density of liquid ÷ density of water] As you know, The density of water = 1000kg/m³.

The density of a substance is divided by the density of water at 4 degrees Celsius to determine its specific gravity. The density of the substance and the density of the water must be represented in the same units for the calculation.distinguishes  While specific weight has dimensions, specific gravity is a dimensionless number. The gravitational field has no effect on a material's specific gravity, but it does have an effect on a material's specific weight. A substance's "Specific Gravity" is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.

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Answer:

Lack of fall protection and Scaffold is overloaded

Answer:

A. 1 J = 1 kg.m²/s²

Explanation:

Energy is defined as the ability to do work. The most basic equation or formula to find the magnitude of energy is given in terms of work. That formula is written as follows:

Energy = Work

Energy = Force * Displacement

Replacing these variables, with their S.I units:

Joule = Newton*m

where,

Force (Newton) = mass (kg) * acceleration (m/s²)

Newton = kg.m/s²

Therefore,

Joule = (kg.m/s²)(m)

A. 1 J = 1 kg.m²/s²

Answer:

the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Explanation:

Given:

Diameter of the pipe = 100mm = 0.1m

Contraction ratio = 0.5

thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m

The formula for discharge through a venturimeter is given as:

Where,

is the coefficient of discharge = 0.97 (given)

A₁ = Area of the pipe

A₁ =  

A₂ = Area at the throat

A₂ =  

g = acceleration due to gravity = 9.8m/s²

Now,

The gauge pressure at throat = Absolute pressure - The atmospheric pressure

⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)

Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m

Substituting the values in the discharge formula we get

or

or

Q = 29.28 ×10⁻³ m³/s

Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Hope This Helps :D

Answer:

true

Explanation:

The crystallinity of cellulose as well as its polar qualities makes it less difficult to dissolve. It has a three-dimensional hydrogen bond (H-bond) arrangement with the hydroxyl group connected to each polymer chain. On the other hand, Hydrocarbon polymers are nonpolar, and nonpolar solvents are used to dissolve them.

Cellulose is an organic molecule with the formula n that is a polysaccharide made up of a linear chain of hundreds to thousands of β  linked D-glucose units. Cellulose is a structural component of the major cell wall of green plants, many algae, and oomycetes.

Cellulose is the principal component present in plant cell walls and aids in the plant's stiffness and strength. Although cellulose cannot be digested by humans, it is an essential source of fiber in the diet. Cellulose is utilized in the production of clothing and paper.

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A bend is defined as a change in the shape of the part between the damaged and undamaged area that is smooth and continuous.

What is a kink?

A kink can be defined as a sharp bend with a small radius over a short distance.

So when any part is kinked it must be replaced without any doubt. A part is kinked if it just doesn't work on the repair.

What is a bend?

Unlike a kink, a bend can be restored. That is after a bend also  a part can be bought back to its original position.

When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation.

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The Pitot tube measures air velocity directly by means of a pressure transducer which generates an electrical signal which is proportional to the difference between the pressure generated by the total pressure and the still air (static pressure).

Fluid flow velocity is measured using a pitot tube (pitot probe; /pito/ PEE-toh). It was developed in the early 18th century by a French engineer named Henri Pitot. and changed into its current form by a French scientist named Henry Darcy in the middle of the 19th century. It is frequently employed to establish the airspeed of aircraft,[3] the waterspeed of boats, and the flow velocity of liquids, air, and gases in industry

P0 = P2 + 12 V2z = 8.77 x 104 + 12 (1.23)(147)2 = 1.01 x 103 N/m2 p1 - P2 = w H = 1.33 x 104 N/m2 (1.33 x 105)(0.1) = 1.33 x 104 N/m2 p2 = P1 - P1 - 1.33 x 104 = 1.01 x 105

Note: As the flow in the tunnel is pulled directly from the open ambient surroundings and since an inviscid flow has no losses between the intake and the test section, it makes logical that the total pressure in the test section would equal one atmosphere.

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The statement does not provide information on the amount of additional boost contributed by the supercharger for superior performance.

The statement does not provide information on the exact amount of additional boost contributed by the supercharger for superior performance. However, it does suggest that the supercharger plays a crucial role in maximizing the powerband of the 6.2L V8 engine by improving both low-end torque and high-rpm performance. Typically, a supercharger can provide up to 50% or more additional boost, which means that it can significantly increase the engine's horsepower and torque output. The amount of boost generated by a supercharger depends on various factors such as the engine size, type of supercharger, and the desired performance level.

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Answer:

The final velocity of the rocket is 450 m/s.

Explanation:

Given;

initial velocity of the rocket, u = 0

constant upward acceleration of the rocket, a = 18 m/s²

time of motion of the rocket, t = 25 s

The final velocity of the rocket is calculated with the following kinematic equation;

v = u + at

where;

v is the final velocity of the rocket after 25 s

Substitute the given values in the equation above;

v = 0 + 18 x 25

v = 450 m/s

Therefore, the final velocity of the rocket is 450 m/s.

To calculate the total wellbore storage coefficient and the dimensionless wellbore storage coefficient,  it is necessary to obtain more details about the compressibility of the fluid and the fluctuations in fluid level observed during the drawdown experiment.

The wellbore's storage coefficient reflects the variation in fluid quantity resulting from a unit of pressure change in the same area. The subsequent equation can be utilized to compute it:

Wellbore Storage Coefficient (C) = (Change in Fluid Volume) / (Change in Pressure)

To estimate the wellbore storage coefficient without having the specific values of the oil formation volume factor (Bo) for a particular reservoir, we divide the wellbore storage coefficient by Bo.

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the quantities for a trial mix consisting of two strength cylinders are: Cement: 12.9 kg or 4.1 L, Water: 7.1 kg or 0.0071 m3, Coarse aggregate: 10.3 kg or 0.0038 m3

To determine the quantities for a trial mix using the water/cement ratio method, we need to know the weight of the cement, the weight of water, and the weight of aggregate required to produce two 150 mm x 300 mm (6 in. x 12 in.) strength cylinders.

Here are the steps to calculate the quantities:

Determine the weight of cement required:

The water/cement ratio is 0.55, so the weight of water is 0.55 times the weight of cement.

Assume that we want to produce two cylinders with a total weight of 20 kg (10 kg each), and we want to use a Type I Portland cement with a specific gravity of 3.15.

Using the formula: Weight of cement = Total weight / (1 + W/C ratio), we get:

Weight of cement = 20 / (1 + 0.55) = 12.9 kg

Convert the weight of cement to volume using the specific gravity:

Volume of cement = Weight of cement / Specific gravity = 12.9 / 3.15 = 4.1 L

Determine the weight of water required:

The water/cement ratio is 0.55, so the weight of water is 0.55 times the weight of cement.

Weight of water = 0.55 x 12.9 = 7.1 kg

Convert the weight of water to volume:

Volume of water = Weight of water / Density of water = 7.1 / 1000 = 0.0071 m3

Determine the weight of aggregate required:

Assume that the maximum aggregate size is 37.5 mm (1 1/2 in.) and the specific gravity of the coarse aggregate is 2.7.

We can use the ACI 211 method to calculate the volume of coarse aggregate required:

Volume of coarse aggregate = 0.62 x (Maximum size of aggregate / 1000) x (Volume of concrete / (1 + W/C ratio))

Plugging in the numbers, we get:

Volume of coarse aggregate = 0.62 x (37.5 / 1000) x (0.107 / 1.55) = 0.0038 m3

Convert the volume of aggregate to weight using the specific gravity:

Weight of coarse aggregate = Volume of coarse aggregate x Density of coarse aggregate = 0.0038 x 2.7 x 1000 = 10.3 kg

Therefore, the quantities for a trial mix consisting of two strength cylinders are:

Cement: 12.9 kg or 4.1 L

Water: 7.1 kg or 0.0071 m3

Coarse aggregate: 10.3 kg or 0.0038 m3

Note: It is important to adjust the mix proportions based on trial batches and testing to achieve the desired properties and strength.

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Answer:

molar flow at the bottom streams = 30 moles

composition of the bottom streams exiting the second separation unit

= 0.20 ( methanol )

= 0.80 ( water )

Explanation:

The molar flow and the composition of the bottom streams is calculated as follows below

First we have to balance the overall material across the Mixer unit

= F1 + F2 = A

= 100 + 10 = 110 mole

next we calculate Methanol balance

= Xe1 * F1 + Xe2 * F2  = AXea

= (0.5 * 100) + ( 0.4 * 10 ) = 110 Xea

= 50 + 4 = 110Xea

Xea = 0.491   therefore: Xaw = 1 - Xea = 1 - 0.491 = 0.509

Next we calculate the material balance of separator 1

A = B + C

where: A = 110 moles , B = ? , C = 70 moles

Therefore B= A - C = ( 110 - 70 ) = 40 moles

From here we will find the value of Xec using the Methanol balance relationship

Xea * A = Xeb*B + Xec * C

where: A = 110 moles , B = 40 moles , C = 70 moles

           Xea = 0.491, Xeb = 0.7 ,

Input these values into the equation above : Xec = 0.372

note: at the exit top stream both the separators have the same flow rate

i.e : B = D = 40 mole

Material Balance over the separator 2 can hence be calculated as

C = D + E

E = c - d = 70 - 40

E = 30 moles ( mole flow rate at the 2nd separator unit )

calculate the value of XeE

methanol balance : Xec * c = Xed * D + XeE * E

hence : XeE = [ ( 70 * 0.372 ) -  ( 0.5 * 40 ) ] /  30

             XeE  =  0.20

attached below is the flow sheet of the problem

The tank with a volume of 2000 Gallons would be considered "full" according to the given conditional statement. This expression is useful in situations where we need to determine the status of a tank based on its volume. We can substitute different values of V into the expression to determine the tank's status for different volumes.

The expression Tank(V):=if(V>_1000gal,"full","empty") is a conditional statement that checks if the value of V is greater than 1000 gallons. If it is, then the tank is considered "full", otherwise, it is considered "empty".
When we evaluate the expression Tank(2000gal), we are essentially asking the question, "Is a tank with a volume of 2000 gallons considered full or empty according to this statement?" Since 2000 is greater than 1000, the answer would be "full". The tank with a volume of 2000 gallons would be considered "full" according to the given conditional statement. This expression is useful in situations where we need to determine the status of a tank based on its volume. We can substitute different values of V into the expression to determine the tank's status for different volumes.

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Answer:

Car Payments. Making payments on your car is the biggest, most obvious expense of your vehicle. ...

Insurance. Insurance is another primary expense to consider when budgeting for a new car. ...

Gas. ...

Maintenance. ...

Fees & Taxes.

Explanation:

Answer:

Owning a car is expensive. Between the price of the vehicle, financing costs, insurance, taxes, and maintenance, owning one —let alone two — cars can drain your bank account quickly.

Explanation:

The following are violations of the CAA venting prohibition:A) Release of refrigerants because appliances were not recovered.B) Releasing isobutane while servicing equipment.C) Releasing HFC refrigerant because of catastrophic equipment failure.D) Refrigerants released when disconnecting non low-loss hoses to service an appliance.

The Clean Air Act (CAA) is a United States federal law passed in 1963 that aimed to reduce air pollution in the United States. It was established to protect and improve air quality and to avoid risks to human health and the environment.What is the Venting Prohibition in CAA?Section 608 of the CAA prohibits the release of ozone-depleting substances (ODS) and substitute refrigerants (like HFCs) into the atmosphere during the maintenance, service, repair, or disposal of refrigeration and air-conditioning equipment, as well as during the disposal of appliances and vehicles, that contain ODS or substitute refrigerants.

It is also prohibited to release these substances when disposing of air conditioning and refrigeration equipment, including refrigerant, which is prohibited by law.So, A, B, C and D are violations of the CAA venting prohibition because they release refrigerants.

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Answer:

F = 3 N + 2 N = 5 N

Explanation:

Resultant force F = 3 N + 2 N = 5 N to the right. The resultant force is 5 N to the right. Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force.

The magnitude of σ1 that will cause yielding according to the maximum-shear-stress theory is 9.94 ksi.

Yield stress for the zirconium-magnesium alloy, σY = 15.3 ksi

In-plane principal stresses are σ1 and σ2 = −0.54σ1

To find the maximum shear stress theory, the equation used is τ_max=1/2(σ1-σ2)

The maximum shear stress theory states that yielding begins when the maximum shear stress in a part equals or exceeds the shear strength of the material. It is represented as τ_max = τ_yield

Where τ_max is the maximum shear stress in a part and τ_yield is the shear strength of the material. In-plane principal stresses are σ1 and σ2 = −0.54σ1

Let us replace the value of σ2 in terms of σ1σ2 = −0.54σ1,σ1 = 1.85σ2

Substitute the values in the τ_max=1/2(σ1-σ2)

τ_max=1/2(σ1-(-0.54σ1))

τ_max=0.77σ1

Now, τ_yield= σY/2 = 7.65 ksi

Therefore, 0.77σ1 = 7.65

σ1 = 9.94 ksi

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Answer:

The development of homosapiens

Explanation:

People adapted to the harsh weather by creating tools and used land bridges to spread to new regions

If you have a 22-pallet load, and assuming each pallet is the same weight, the maximum weight each pallet can weigh would be around 2,000 pounds

To find out the maximum each pallet can weigh in a 22-pallet load, you need to know the total weight limit for the load. The answer will depend on what type of truck or transportation vehicle you are using to transport the pallets, as each has different weight limits.

To illustrate, for a standard 53-foot trailer, the maximum weight allowed is typically around 44,000 pounds.  

44,000 pounds / 22 pallets = 2000.

However, if you know the specific weight limit for the truck or transportation vehicle you are using, you can calculate the maximum weight for each pallet accordingly.

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If a 22 pallet load is to be carried, then the maximum each pallet can weigh in the load will depend on the capacity of the truck, the weight limit per axle, and the total weight of the load.

The weight limit varies for different types of trucks, and other factors like the size and weight of the cargo, the type of load, and the distance to be traveled affect the weight distribution. Therefore, the maximum weight limit that each pallet can carry in a 22 pallet load is 11,250 pounds assuming an even distribution, a maximum weight capacity of 80,000 pounds.A truck can carry a maximum of 22 pallets of different weight capacities, the truck's total weight limit will be reached before 22 pallets are loaded. However, if the load is light and does not occupy much space, more pallets can be loaded. Therefore, it is essential to understand the maximum weight limit that each pallet can carry to prevent exceeding the truck's weight limit, which can cause accidents and damage to the goods.

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Using APA reference style, the references is attached below from Feldman, R. S. (2013) to American Psychology Association (2020)

APA reference style is a style of citing sources used by the American Psychological Association. It is primarily used in the social sciences and includes guidelines for citing sources both within the text of a document and in the reference list at the end of the document. The guidelines provide a consistent way of citing sources to make it easier for readers to identify and locate the sources cited in a document.

In the given problem, if we need to write the reference using APA style, it will take this format below

Reference Page:

Feldman, R. S. (2013). Psychology and your life (2nd ed.). New York, NY: McGraw Hill Companies.

Frontline. (n.d.). League of denial. Retrieved from https://www.pbs.org/wgbh/frontline/film/league-of-denial/

Friends. (2004). The one after Joey and Rachel kiss [Television series episode]. In D. Crane, & M. Kauffman (Executive producers), Friends. Burbank, CA: Warner Bros. Television.

Silver Linings Playbook. (2012). [Motion Picture]. United States: The Weinstein Company.

U.S. Energy Information Administration. (2013). Annual energy outlook 2013 with projections to 2040. Retrieved from http://www.eia.gov/forecasts/aeo/er/pdf/0383er(2013).pdf

Snickers. (2013, April 2). You’re not you when you’re hungry [Video file]. Retrieved from https://youtu.be/2rF_FRCd_LA

American Psychological Association. (2020). Publication manual of the American Psychological Association (7th ed.). doi:10.1037/0000165-000

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Answer:

10.80 mm

Explanation:

Given that the reading of the fixed scale is : 10.5 mm

The thimble scale specifies : 0.30 mm

The micrometer reading will be : 10.5 + 0.30 =10.80 mm

Based on the image attached, the reading of micrometer is= 15.20.

You will see a line of numbers running down the barrel of your micrometer, starting with the barrel scale. On the barrel scale, each number corresponds to 0.100. Looking at the barrel, 1 equals 0.100, 2 equals 0.200, 3 equals 300, and so on. The distance between each tick mark and the larger numbers on the barrel is 0.025, or 25 thousandths. 

Note that micrometer is one that is also referred to as a micrometer screw gauge—is a tool with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, and others.

Looking at the image, you will see the stop ends at 15 and  and 20 so adding them together will be option A. 15.20.

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One common feature of Byzantine architecture that was unusual in the West was the use of pendentives. Pendentives were concave, triangular sections of a dome that made it possible to transition the dome's circular shape to the square base of the structure it was placed on.

This feature allowed Byzantine architects to create large, centralized domes with considerable weight, which were a hallmark of their architecture.

In contrast, Western architects preferred to use round arches and groin vaults, which limited the size of their domes.

Byzantine architecture refers to the architecture of the Byzantine Empire, which was a medieval empire based in Constantinople (modern-day Istanbul) from the 5th century until 1453.

The architecture of the Byzantine Empire spanned from the 4th century to the end of the Middle Ages, and it was primarily defined by the construction of churches, palaces, fortifications, and public buildings.

Byzantine architecture evolved over time, with influences from Roman, Greek, and Persian styles, and it was known for its lavish use of decoration and intricate mosaics.

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