Store Trash manufactures trash cans that are open at the top and do not have lids. The company’s engineers are designing a trash can that has a total volume of 7.85/cubedft. They are deciding between a rectangular prism-shaped trash can with base dimensions of 1.5 ft X 2.0 ft and a cylindrical trash can with a base area of 3.14/squaredft. The material used to manufacture the trash cans costs $3.60 per square foot. Which trash can design will cost the company less to manufacture and by approximately how much?

a) cylindrical trash can by $2.47.
b) cylindrical trash can by $8.89.
c)rectangular prism trash can by $0.50.
d) rectangular prism trash can by $3.96.

Answer:

-12z⁴ - 48z³ + 4z²

Explanation:

The given expression is

-4z²(3z² + 12z - 1)

To multiply it, we need to apply the distributive property, so

-4z²(3z²) - 4z²(12z) - 4z²(-1)

-12z⁴ - 48z³ + 4z²

So, the answer is

-12z⁴ - 48z³ + 4z²

Answer:

7k+6 is your answer to the question

Yes, the deviation is greater than it was in tossing them 40 times.

A standard deviation (or σ) is a measure of how widely distributed the data is in reference to the mean. A low standard deviation suggests that data is grouped around the mean, whereas a large standard deviation shows that data is more spread out.

Given:

n= 400 trials

Tossing 2 coins 400 times gives 800 trials

so, \(\sigma_1\)² = np(1- p)

        = 800 x 1/2 x 1/2

      \(\sigma_1\)  = √200

      \(\sigma_1\) = 10√2

Now, n=40

and,  \(\sigma_2\)² = np(1- p)

        = 80 x 1/2 x 1/2

      \(\sigma_2\)  = √20

      \(\sigma_2\) = 2√5

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Answer:

One.  The point at which the parabola and the line intersect.

Answer:

e-5=2f

take '-5' to the other side where '2f' is

e=2f+5

Answer: You have the correct answer. It's choice B

Domain = \(\left(-\infty, \frac{2}{5}\right)\)

Nice work.

=========================================================

Explanation:

The domain of g(x) is found by setting 2-5x greater than or equal to 0 and solving for x. We're doing this to ensure that 2-5x is not negative.

\(2-5x \ge 0\\\\2 \ge 5x\\\\5x \le 2\\\\x \le \frac{2}{5}\)

So we can plug in any number smaller than 2/5, or we can plug in 2/5 itself, into the g(x) function to get some output.

However, notice that if x = 2/5, then g(x) = 0. This then would feed into the f(x) function and lead to a division by zero error. Therefore, x = 2/5 must be kicked out of the domain of (f o g)(x). We keep everything else that we found earlier.

In short, the domain as an inequality is \(x < \frac{2}{5}\), which is the same as saying \(-\infty < x < \frac{2}{5}\) and that converts to the interval notation \(\left(-\infty, \frac{2}{5}\right)\)

We don't use a square bracket because we don't want to include the endpoint 2/5.

1. Jada's data set has a mean of 5, Diego's data set has a mean of 6, and Lin's data set has a mean of 4.

2. The data set that has the greatest variability is Lin's data set because it has the highest standard deviation of 3.6.

In Mathematics and Geometry, the mean for this set of data can be calculated by using the following formula:

Mean = [F(x)]/n

Question 1.

In this scenario and exercise, we would determine the mean of the three data sets based on the number of text messages sent by Jada, and Diego, and Lin over 6 days as follows;

Mean number of text for Jada = (4 + 4 + 4 + 6 + 6 + 6)/6

Mean number of text for Jada = 30/6

Mean number of text for Jada = 5.

Mean number of text for Diego = (4 + 5 + 5 + 6 + 8 + 8)/6

Mean number of text for Diego = 36/6

Mean number of text for Diego = 6.

Mean number of text for Lin = (1 + 1 + 2 + 2 + 9 + 9)/6

Mean number of text for Lin = 24/6

Mean number of text for Lin = 4.

Question 2.

In Statistics, variability is a measure of the spread of a data set. Also, we would use standard deviation to determine the variability in each data set as follows;

Standard deviation = √(1/n × ∑(xi - u₁)²)

Standard deviation for Jada = √(1/6 × [(4 - 5)² + (4 - 5)² + (4 - 5)² + (6 - 5)² + (6 - 5)² + (6 - 5)²]

Standard deviation for Jada = √(6/6) = 1

Standard deviation for Diego = √(1/6 × [(4 - 6)² + (5 - 6)² + (5 - 6)² + (6 - 6)² + (8 - 6)² + (8 - 6)²]

Standard deviation for Diego = √(14/6) = 1.53

Standard deviation for Lin = √(1/6 × [(1 - 4)² + (1 - 4)² + (2 - 4)² + (2 - 4)² + (9 - 4)² + (9 - 4)²]

Standard deviation for Lin = √(76/6) = 3.6

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

AB =  4.9cm

Step-by-step explanation:

We know

AC is 9.1 centimeters, and BC is 4.2 centimeters.

Find AB

We take

9.1 - 4.2 = 4.9cm

So, AB = 4.9cm

As a result, the answer to the given angle problem can be found by comparing the position, measurement, and congruence of two or more angles.

When two lines come together at a common point, an angle is created. They are expressed as a number of degrees, denoted by the symbol °. Acute, right, obtuse, and reflex angles are the other three significant types of angles. 360 degrees make up a circle. A 720° angle indicates that the object has completed two full rotations.

Here,

You can compare angles and take into account their relationships to other angles in addition to calculating degrees or radians.

Since we are comparing the position, measurement, and congruence of two or more angles, we refer to them as having "angle relationships."

For instance, two lines or line segments that cross each other create two pairs of vertical angles.

When a transversal intersects two parallel lines, complex angle relationships, such as alternating interior angles, matching angles, and so forth, result.

As a result, the answer to the given angle problem can be found by comparing the position, measurement, and congruence of two or more angles.

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Answer:

Area = 324ft²

Perimeter = 72ft

Step-by-step explanation:

Area of a square = length²

Area of a square = (18ft)² = 324ft²

Perimeter of a square = 4*length

Perimeter of a square = 4ft*18 = 72ft

Answer:

Step-by-step explanation:

c 0,4 .01

The system of equations is.

\(\begin{cases}\text{x}+\text{y}=60 \\15\text{x}+10\text{y}=800 \end{cases}\)

And the solutions are y = 50 and x = 10.

Let's define the two variables:

With the given information we can write two equations, then the system will be:

\(\begin{cases}\text{x}+\text{y}=60 \\15\text{x}+10\text{y}=800 \end{cases}\)

Now let's solve it.

We can isolate x on the first  to get:

\(\text{x} = 60 - \text{y}\)

Replace that in the other equation to get:

\(15\times(60 - \text{y}) + 10\text{y} = 800\)

\(-2\bold{y} = 900 - 800\)

\(-2\bold{y} = 100\)

\(\text{y} = \dfrac{100}{-2} = \bold{50}\)

Then \(\bold{x=10}\).

Therefore, the solutions are y = 50 and x = 10.

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Answer:

48

Step-by-step explanation:

u • w

= (i + 6j ) • (9i - 2j )

= (1 × 9 ) + (6 × - 2 )

= 9 + (- 12)

= 9 - 12

= - 3

v • w

= (5i - 3j ) • (9i - 2j )

= (5 × 9) + (- 3 × - 2)

= 45 + 6

= 51

Then

u • w + v • w

= - 3 + 51

= 48

ln(5y) = 4xy

Differentiate both sides with respect to x, taking y = y(x) :

d/dx [ln(5y)] = d/dx [4xy]

1/(5y) d/dx [5y] = 4y + 4x dy/dx

5/(5y) dy/dx = 4y + 4x dy/dx

1/y dy/dx = 4y + 4x dy/dx

(1/y - 4x) dy/dx = 4y

dy/dx = 4y / (1/y - 4x)

Since y = 0 is outside the domain (ln(0) is undefined), we can multiply the right side by y/y :

dy/dx = 4y ² / (1 - 4xy)

To compute the second derivative, differentiate both sides again:

d/dx [dy/dx] = d/dx [4y ² / (1 - 4xy)]

d²y/dx ² = ((1 - 4xy) d/dx [4y ²] - 4y ² d/dx [1 - 4xy]) / (1 - 4xy)²

d²y/dx ² = ((1 - 4xy) 8y dy/dx - 4y ² (0 - 4y - 4x dy/dx)) / (1 - 4xy)²

d²y/dx ² = ((8y - 32xy ²) dy/dx + 16y ³ + 16xy ² dy/dx) / (1 - 4xy)²

d²y/dx ² = ((8y - 16xy ²) dy/dx + 16y ³) / (1 - 4xy)²

Substitute the first derivative founder earlier:

d²y/dx ² = ((8y - 16xy ²) (4y ² / (1 - 4xy)) + 16y ³) / (1 - 4xy)²

d²y/dx ² = ((8y - 16xy ²) 4y ² + 16y ³ (1 - 4xy)) / (1 - 4xy)³

d²y/dx ² = (16y ³ (3 - 8xy)) / (1 - 4xy)³

The second derivative vanishes wherever the numerator vanishes (so long as 4xy ≠ 1) :

16y ³ (3 - 8xy) = 0

16y ³ = 0   or   3 - 8xy = 0

y = 0   or   8xy = 3

As pointed out earlier, y = 0 is outside this function's domain, so we're left with points on the curve

y = 3/(8x)

Substituting this into the original function gives

ln(5 (3/(8x))) = 4x (3/(8x))

ln(15 / (8x)) = 12/8

ln(15) - ln(8x) = 3/2

ln(8x) = ln(15) - 3/2

8x = exp(ln(15) - 3/2)

8x = 15 exp(-3/2)

x = 15/8 exp(-3/2)   →   y = 1/5 exp(3/2)

or approximately (0.4184, 0.8963).

(where exp(x) = e ˣ)

Answer:

The variable Y represents the number of meters of string in the third yoyo

Step-by-step explanation:

In this equation y stands for the unknown variable. The equation tell you that hope made 3 different yo-yos so the number of yo-yos hope made isn't unknown, meaning, it cant be the first answer. The problem also tells you that hope used a total of 4 meters of string which means that the total number of string used isn't the unknown variable. The number of meters of string in the third yo-yo is the only number that isn't. This makes the number of sting used in the third yo-yo the unknown variable, making it y.

(f/g)(-5) is equal to 1/4, and the value -1 is not in the domain of f/g.

To find (f/g)(-5), we need to substitute -5 into the functions f(x) and g(x) and then divide f(-5) by g(-5).

Given:

f(x) = (4+x)(6+x)

g(x) = 1+x

Substituting -5 into the functions:

f(-5) = (4+(-5))(6+(-5)) = (-1)(1) = -1

g(-5) = 1+(-5) = -4

Now, we can calculate (f/g)(-5):

(f/g)(-5) = f(-5) / g(-5) = -1 / -4 = 1/4

Therefore, (f/g)(-5) equals 1/4.

Now let's determine the values that are not in the domain of f/g. The values that are not in the domain of f/g are the values that make the denominator g(x) equal to zero. In this case, the denominator is g(x) = 1+x.

To find the values that make the denominator zero, we solve the equation:

1 + x = 0

Subtracting 1 from both sides, we get:

x = -1

So, the value x = -1 is not in the domain of f/g because it would make the denominator equal to zero.

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Answer:

1:2

Step-by-step explanation:

The table is completed as follows using the double-declining-balance method of depreciation:

Year Cost   Accumulated  Book Value  Depreciation Accumulated  Book

                   Depreciation        B.O.Y         Expense     Depreciation  Value

                        B.O.Y                                                               E.O.Y       E.O.Y

1    $30,000          $0           $30,000         $12,000         $12,000  $18,000

2   $30,000    $12,000          $18,000         $7,200           $19,200  $10,800

3   $30,000   $19,200          $10,800           $4,320          $23,520   $6,480

The double-declining-balance approach is what?

The double-declining-balance method is one of the depreciation techniques in use, however it adds additional costs in the first years of an asset's life.

In this depreciation method, the straight-line rate, which is computed as the product of 100/estimated useful life multiplied by 2, is twice.

At the conclusion of each year, the leftover balance for the depreciation charge is adjusted using the double rate.

The difference between the closing balance from the previous year and the residual value is used to determine the depreciation charge for the most recent year.

Auto  = $30,000

Estimated useful life = 5 years

Residual = $800

Depreciable amount = $30,000 - $800 = 29,200

Straight-line depreciation rate = 100/5 = 20%

Double-declining depreciation rate =20% x 2 = 40%

Depreciation Expense:

1st year = 30,000 x 40/100 = 12,000

2nd year = 18,000 x 40/100 = 7,200

3rd year = 10,800 x 40/100 = 4,320

4th year = 6,480 x 40/100 = 2,592

5th year = 3,888 x 40/100 = 1,555

Year Cost   Accumulated  Book Value  Depreciation Accumulated Book

                   Depreciation        B.O.Y         Expense      Depreciation   Value

                        B.O.Y                                                               E.O.Y       E.O.Y

1    $30,000          $0           $30,000         $12,000         $12,000  $18,000

2   $30,000    $12,000          $18,000         $7,200           $19,200  $10,800

3   $30,000   $19,200          $10,800           $4,320          $23,520   $6,480

4   $30,000  $23,520          $6,480           $2,592           $26,112   $3,888

5  $30,000  $26,112            $3,888          $1555           $27,667     $2,332

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Answer:

sorry wanted pionts

Step-by-step explanation:

umm sorry

Answer: :Given : points G and I have coordinates (6,4) and (3,2)

To Find : Use  Pythagorean theorem  to calculate the straight line distance between points G and I

Solution:

points G and I have coordinates (6,4) and (3,2)

Draw a line parallel to y axis passing through G

Draw a line parallel to x axis passing through I

Intersection point K ( 6 , 2)

IK = 6 - 3 = 3

GK = 4 -2  = 2

ΔIKG right angled triangle

Pythagoras' theorem: square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.  

GI² = IK² + GK²

=>  GI²  = 3² + 2²

=>  GI²  = 13

=> GI = √13

using distance formula

G (6,4) and I (3,2)

= √(6 - 3)² + (4 - 2)²

= √3² + 2²

= √9 + 4

= √13

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13. In Fig. 16.10, BCDE is a rectangle , ED = 3.88 cm,AD= 10 cm ...

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Answer:

The answer is 3

Step-by-step explanation:

B/c 8+2=10 just add one more and 2+1=3

Answer:

3

Step-by-step explanation:

first you subtract 11 to 8 and when you count it youll get 3 so 8+3=11

hope this helps :)))))

Carlos needs to earn at least 16 points on the final quiz to earn at least a 90% average.

We have,

Let's start by finding the total number of points that Carlos can earn in the class:

Total points

= 5 quizzes x 20 points per quiz

= 100 points

If Carlos needs an average of 90% or greater, that means he needs to earn at least 90 points out of 100.

Total points earned.

= 18 + 19 + 17 + 20

= 74 points

To find the minimum score Carlos needs on the final quiz, we can set up an inequality:

(74 + x) / 5 ≥ 0.9

where x is the score on the final quiz.

Simplifying this inequality.

74 + x ≥ 90

x ≥ 16

Therefore,

Carlos needs to earn at least 16 points on the final quiz to earn at least a 90% average.

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If circle with center N with m∠MNP=124 ∘ and MN=13,  the area of sector MNP is approximately equal to 194.86 square units.

To find the area of a sector of a circle, we need to use the formula:

Area of sector = (central angle/360°) x πr²

Where r is the radius of the circle.

In this problem, we know that the central angle m∠MNP is 124° and MN, which is also the radius of the circle, is 13. So we can substitute these values into the formula:

Area of sector = (124/360) x π(13)²

Area of sector ≈ 194.86

Therefore, the area of sector MNP is approximately equal to 194.86 square units.

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I assume you meant to say "a differentiable function f has the values ..." and not g.

Since f is differentiable, the mean value theorem holds, so you can approximate

f ' (2.5) ≈ (f (2.6) - f (2.4)) / (2.6 - 2.4) = (24 - 18) / (0.2) = 30

Answer:

El chapo so that your mean

Im sure it's -3    Because well thats what  i got

The expression is simplified to 2

It is important to note that the table of exact values for trigonometric identity differ with the particular identity in study.

From the table of exact values, we have that;

sin 15 = 0. 25

sin 30 = 0. 5000

sin 45 = 0. 7071

sin 60 = 0. 8600

sin 75 = 0. 9659

sin 90 = 1

To determine the value of the expression, we have to substitute the value of sin 30 as 0. 5000

4 sin 30°

⇒ 4 × 0. 5000

multiply through

⇒ 2

The value determined is 2

Thus, the expression is simplified to 2

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Answer:

That is a child mom with triplets.

Step-by-step explanation: