Study the graph of the relation.
What is the domain of the relation in the graph?

Answer: 53.5 seconds

Step-by-step explanation:

Answer:

x = 21

Step-by-step explanation:

ABF is a right angle and m∠EBA + m∠EBF = m∠ABF

3x - 1 + x + 7 = 90 add like terms

4x + 6 = 90 subtract 6 from both sides

4x = 84 divide both sides by 4

x = 21

Answer:

answer :J LOOK THE DIAGRAM CAREFULLY AND UNDERSTAND

Answer:

A <c - <b = 10

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

Another notation for same function is

1. Is the function increasing or decreasing?

2. What is the y-intercept?

3. What is the slope?

4. What is f(-2)?

5. If f(x) = 0, what is x?

Answer:

Solving step

\(f(x) = 5x - 7\)

Substitute x=0

\(f(0) = 5 \times 0 - 7\)

Calculate the product

\(f(0) = (0) - 7\)

When adding or Subtracting 0 the quantity does not change

\(f(0) = - 7\)

\(f(x) = 0\)

\(0 = 5x - 7\)

\(5x = 0\)

\(x = \frac{7}{5} \)

OR

\(x = 1.4\)

Answer:

2,4,6

3,6,9

Step-by-step explanation:

hope this helps

Answer:

$287.68

Step-by-step explanation:

The five thousand three hundred mexican pesos is worth $287.68 (USD) today or two hundred eighty-seven us dollars 68 cents as of 10:00AM UTC.

Answer:

$288.59 american dollars

Answer:

Step-by-step explanation:

divide 40 by 4 and you get 10. divide 24 by 4 and you get 6. meaning that 6 is 10%. multipy by 10. you get 60. so 60 points

Step-by-step explanation:

40/100=24 =40/4=10

or

40/100=24=4/10=24

=4/10=24/1

24×10= 4×1

240=4

60

either which

The calculated length of the segment MN in the triangle is 20

From the question, we have the following parameters that can be used in our computation:

The triangle

The third angle in the triangle is calculated as

Third angle = 180 - 50 - 50

Evaluate

Third angle = 80

The length of the segment MN is then calculated as

MN/sin(50) = 20/sin(50)

This gives

MN = sin(50) * 20/sin(50)

Evaluate

MN = 20

Hence, the length of the segment MN in the triangle is 20

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Answer:

4+m

Step-by-step explanation:

You can't put them together 'cause they aren't like terms, so you just keep the sign that put them together in the first place.

The missing values are numerator: 3,5 Denominators: 10,20, 30

For the numerators:

The numbers are increasing by 1.

Hence, the missing values are 3 and 5

The values of the numerators are 1,2,3,4,5,6,7

For the denominators:

The missing values are:

5 x2 = 10

5 x 4 = 20

5 x 6 = 30

Hence, the missing values are 10, 20 and 30

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Let's begin by listing out the information given to us:

Principal (P) = $2,200, Interest rate (r) = 3.4% = 0.034, Time (t) = 5.5 years

The bond will be worth the sum of the Principal and the Interest:

Answer:

19397 difference of elevation between the mountain and valley

Answer:

The time interval between 1.08 PM and 2.24 PM is 1 hour and 16 minutes.

Step-by-step explanation:

To determine the time interval between 1.08pm and 2.24pm, the following calculation must be performed:

PM - PM = 0

2 - 1 = 1

24 - 8 = 16

0 + 1 = 1

Thus, the time interval between 1.08 PM and 2.24 PM is 1 hour and 16 minutes.

Step-by-step explanation:

let

(-7,-8) =(x1, y1)

and (-6,7)=(x2, y2)

by the formula

d=√(y2-y1) ²+(x2-x1) ²

=√(7+8)²+(-6+7)²

=√15²+1²

= √225+1

= √226

Answer:

\(\textsf{1.(a)} \quad x^2-14x+\boxed{49}=\left(x-\boxed{7}\right)^2\)

\(\textsf{1.(b)} \quad 9x^2 + 30x +\boxed{25}= \left(3x +\boxed{5}\right)^2\)

\(\begin{aligned}\textsf{2.(a)}\quad3x^2-24x+48&=3\left(x^2-\boxed{8}\:x+\boxed{16}\right)\\&=3\left(x-\boxed{4}\right)^2\end{aligned}\)

\(\begin{aligned}\textsf{2.(b)}\quad \dfrac{1}{2}x^2+8x+32&=\dfrac{1}{2}\left(x^2+\boxed{16}\:x+\boxed{64}\right)\\&=\dfrac{1}{2}\left(x+\boxed{8}\right)^2\end{aligned}\)

Step-by-step explanation:

(a) When completing the square for a quadratic equation in the form ax² + bx + c where the leading coefficient is one, we need to add the square of half the coefficient of the x-term:

\(x^2-14x+\left(\dfrac{-14}{2}\right)^2\)

\(x^2-14x+\left(-7\right)^2\)

\(x^2-14x+49\)

We have now created a perfect square trinomial in the form a² - 2ab + b². To factor a perfect square trinomial, use the following formula:

\(\boxed{a^2 -2ab + b^2 = (a -b)^2}\)

Therefore:

\(a^2=x^2 \implies a=1\)

\(b^2=49=7^2\implies b = 7\)

Therefore, the perfect square trinomial rewritten as a binomial squared is:

\(x^2-14x+\boxed{49}=\left(x-\boxed{7}\right)^2\)

(b) When completing the square for a quadratic equation where the leading coefficient is not one, we need to add the square of the coefficient of the x-term once it is halved and divided by the leading coefficient, and then multiply it by the leading coefficient:

\(9x^2 + 30x +9\left(\dfrac{30}{2 \cdot 9}\right)^2\)

\(9x^2 + 30x +9\left(\dfrac{5}{3}\right)^2\)

\(9x^2 + 30x +9 \cdot \dfrac{25}{9}\)

\(9x^2 + 30x +25\)

We have now created a perfect square trinomial in the form a² + 2ab + b². To factor a perfect square trinomial, use the following formula:

\(\boxed{a^2 +2ab + b^2 = (a +b)^2}\)

Therefore:

\(a^2=9x^2 = (3x)^2 \implies a = 3x\)

\(b^2=25 = 5^2 \implies b = 5\)

Therefore, the perfect square trinomial rewritten as a binomial squared is:

\(9x^2 + 30x +\boxed{25}= \left(3x +\boxed{5}\right)^2\)

\(\hrulefill\)

(a) Factor out the leading coefficient 3 from the given expression:

\(3x^2-24x+48=3\left(x^2-\boxed{8}\:x+\boxed{16}\right)\)

We have now created a perfect square trinomial in the form a² - 2ab + b² inside the parentheses. To factor a perfect square trinomial, use the following formula:

\(\boxed{a^2 -2ab + b^2 = (a -b)^2}\)

Factor the perfect square trinomial inside the parentheses:

                        \(=3\left(x-\boxed{4}\right)^2\)

(a) Factor out the leading coefficient 1/2 from the given expression:

\(\dfrac{1}{2}x^2+8x+32=\dfrac{1}{2}\left(x^2+\boxed{16}\:x+\boxed{64}\right)\)

We have now created a perfect square trinomial in the form a² + 2ab + b² inside the parentheses. To factor a perfect square trinomial, use the following formula:

\(\boxed{a^2+2ab + b^2 = (a +b)^2}\)

Factor the perfect square trinomial inside the parentheses:

                        \(=\dfrac{1}{2}\left(x+\boxed{8}\right)^2\)

Step-by-step explanation:

Since ABCD is a rectangle

⇒ AB = CD and BC = AD

x + y = 30 …………….. (i)

x – y = 14 ……………. (ii)

(i) + (ii) ⇒ 2x = 44

⇒ x = 22

Plug in x = 22 in (i)

⇒ 22 + y = 30

⇒ y = 8

Answer:

a. 8.7

Explanation:

We use the trigonometric ratio to find the value of AB.

Therefore:

The correct choice is A.

The number of different frames you can create, if There are 4 different styles, each available in 5 different colors, there are 3 different shades of blue to choose from, is 12.

A combination is a choice of items from a group of different items, where the order of the choices is irrelevant.

Given:

There are 4 different styles, each available in 5 different colors, there are 3 different shades of blue to choose from,

Calculate the total number of frames, we can create as shown below,

The number of frames = different styles available for blue color × shades of blue

The number of frames = 4 × 3

The number of frames = 12

Thus, the number of frames you can create is 12.

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\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 50000\\ P=\textit{original amount deposited}\dotfill &\$23000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &7 \end{cases}\)

\(50000 = 23000\left(1+\frac{ ~~ \frac{r}{100} ~~ }{4}\right)^{4\cdot 7} \implies \cfrac{50000}{23000}=\left( 1+\cfrac{r}{400} \right)^{28} \\\\\\ \cfrac{50}{23}=\left( \cfrac{400+r}{400} \right)^{28}\implies \sqrt[28]{\cfrac{50}{23}}=\cfrac{400+r}{400} \\\\\\ 400\sqrt[28]{\cfrac{50}{23}}=400+r\implies 400\sqrt[28]{\cfrac{50}{23}}-400=r\implies \stackrel{ \% }{11.25}\approx r\)

A. The distributions of the periods is that using the five number summary is that

B. The box and whisker plot of the periods is attached

From the question, we have the following parameters that can be used in our computation:

7th Period

66, 72, 77, 78, 78, 80, 82, 84, 84, 87, 88, 88, 89, 89, 90 92, 92, 93, 94, 94 96, 96

3rd Period

52, 60, 62, 64, 64, 65, 68, 71, 72, 74, 75, 76, 78, 79, 83, 84, 85, 88, 89, 93, 94, 97

The distributions of the periods will be compared using the five-number summaries

Using a graphing tool, the five-number summaries are:

7th Period

3rd Period

The box and whisker plot of the periods is added as an attachment

From the box and whisker plot attached, we can see the five-number summaries of the periods

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Answer:

1 Using the given zero, find one other zero of f(x). 4 - 5i is a zero of f(x).= x4 - 8x3 + 42x2 - 8x + 41. -4 - 5i 1 1 - i 4 + 5i #2 Find a cubic function

Step-by-step explanation:

The sentence

"Distance of 5 units from the number 7"

The part "From the number 7" indicates that you have to start counting from 7 on. Then the left bound of the interval is number 7.

To determine the right bound of the interval you have to count 5 units starting from 7, so add 5 to 7

The right bound of the interval is 12.

So, the values of x within the distance described by the sentence are: (7,12)

Answer:

\(20(x - y)² - 45y² = 5(2(x - y) + 3y)(2(x - y) - 3y)\)

Step-by-step explanation:

We can start by factoring out the common factor of 5 from both terms:

\(20(x - y)² - 45y² = 5(4(x - y)² - 9y²)\)

Now, we can see that we have a difference of squares in the second set of parentheses:

\(= 5(2(x - y) + 3y)(2(x - y) - 3y)\)

Therefore, the fully factorized expression is:

\(20(x - y)² - 45y² = 5(2(x - y) + 3y)(2(x - y) - 3y)\)

Answer:

negative twelve

Step-by-step explanation:

the slope is -1, so one must go down as the other goes up. since the x value has increased by 3, the y value must decrease by three

Answer:

5 1/2- 1 2/7

11/2-9/7

(11×7-9×2)/14

59/14

4 3/14

Answer:

9.52 x 1

4.26 x 2

4 x 2.38

Hope that helps

Answer:

150.72

Step-by-step explanation:

8 x 6 x 3.14 = 150.72

Answer:

150.72

radius times pi

then you have the value of the inside

times it by the height

and you have the volume

Answer: A side of a square for the area given 100/9 square meters, then length = 3.33 meters .

Step-by-step explanation:

The area of a square is (100/9) cm.

So, find out the length of the square?

Then,

Define Square:

A square is closed, two-dimensional shape with 4 equal sides. A square is a quadrilateral. We can find the shape of a square in a game board or chess board, a wall clock and in a slice of bread, around us.

The area of any rectangle is length times width. The area of a square is a special case where length equals width, so side times side or side squared is used for area.

Define Area of Square:

Area of a square is defined as the number of square units needed to fill a square. In general, the area is defined as the region occupied inside the boundary of a flat object or 2d figure. The measurement is done in square units with the standard unit being square meters (m²).                    

The area of any rectangle is length times width. The area of a square is a special case where length equals width, so side times side or side squared is used for area.    

Area of a Square = Side ×  Side

Therefore, the area of square = side²  square units                          

                                              A = s²

Means,       A= area of square

You have the area so you need to find the side length that when multiplied by itself equals that area. If you don’t know what number squared is (100/9) you can plug and chug or use a calculator with square roots.

Replace with A=(100/9) values,

We can write,

                        A = s²

               (100/9) = s²

Then we can solve it,

               \(\sqrt{100/9}\) = s

                 \(\sqrt{\frac{(10^{2}) }{3^{2} } }\) = s

We can write, \(\sqrt{10^{2} }\) = 10 , and \(\sqrt{3^{2} }\) = 3

Then,  

                    (10/3) = s

Therefore,   s = (10/3)

                    s = 3.33 meters

So, length = 3.33 meters

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Answer: Angle VUW and QRP are alternate exterior angles.

They are both exterior and are on alternate sides of the transversal.

Hope this helps!