Subtract
7
x
2
−
x
−
1
7x
2
−x−1 from
x
2
+
3
x
+
3
x
2
+3x+3.

Answer:

C. 19

Step-by-step explanation:

Answer:

-34

Step-by-step explanation:

r^2 - 8r - 22  ( R = 6)

6^2 =36   (8r = 8*6=48)

36 - 48 =  -12

-12 - 22 = -34

Answer:

114 pies

Step-by-step explanation:

If the pie get together only had 20 people with 15 pies, then each person had a portion of 3/4 (divide them). The pie party has 152 people with 3/4 portions each, which means there has to be 114 pies at the party (multiply them).

:)

Answer:

152÷20=7.6

7.6×15=114

114 pies

49 inches in feet is 4.08333.

You can easily convert 49 inches into feet using each unit definition:

Inches

inch = 2.54 cm = 0.0254 m

Feet

foot = 12 inch = 0.3048 m

Performing the inverse calculation of the relationship between units, we obtain that 1 foot is 0.24489796 times 49 inches.

A foot is zero times forty-nine inches.

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Answer:

10x-24

Step-by-step explanation:

8(2x-3)-6x

8 time's 2x = 16

8 time's -3 = -24

then that would give you 16x-24-6x

then combine like terms 16x-6x= 10x

10x-24

The minimum is 29 cm and it represents the sensor's minimum height above the ground.

In Mathematics and Geometry, the standard form of a cosine function can be represented or modeled by the following mathematical equation (formula):

y = Acos(Bx - C) + D

Where:

By critically observing the graph which models the sensor's height above the ground (in centimeters) shown in the image attached below, we can reasonably infer and logically deduce that it has a minimum height of 29 centimeters.

In conclusion, the sensor's minimum height above the ground cannot exceed 29 centimeters.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The probability of x taking on a value between 75 to 90 is 0.25.

Given that x is a continuous random variable uniformly distributed between 65 and 85.To find the probability that x lies between 75 and 90, we need to find the area under the curve between the values 75 and 85, and add to that the area under the curve between 85 and 90.

The curve represents a rectangular shape, the height of which is the maximum probability. So, the height is given by the formula height of the curve = 1/ (b-a) = 1/ (85-65) = 1/20.Area under the curve between 75 and 85 is = (85-75) * (1/20) = (10/20) = 0.5Area under the curve between 85 and 90 is = (90-85) * (1/20) = (5/20) = 0.25.

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The ATI Capstone Comprehensive Assessment evaluation normally comprises of multiple-choice questions, with 90 to 130 possible answers. Certain versions may also include extra alternative questions kinds, such as fill-in-the-blank or select-all-that-apply

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(a) For the equation r(t) = e^(-t), 2t^2, 3tan(t), the first derivative is r'(t) = -e^(-t), 4t, 3sec^2(t). (b) The second derivative is r''(t) = e^(-t), 4, 6tan(t)sec^2(t). (c) The dot product of r'(t) and r''(t) is (-e^(-t))(e^(-t)) + (4t)(4) + (3sec^2(t))(6tan(t)sec^2(t)) = -e^(-2t) + 16t + 18tan(t)sec^4(t).

(a) For the equation r(t) = 3cos(t)i + 3sin(t)j, the first derivative is r'(t) = -3sin(t)i + 3cos(t)j.

(b) The second derivative is r''(t) = -3cos(t)i - 3sin(t)j.

(c) The dot product of r'(t) and r''(t) is (-3sin(t))(-3cos(t)) + (3cos(t))(3sin(t)) = 0, which means that the vectors r'(t) and r''(t) are orthogonal or perpendicular to each other.

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To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v), where u and v are defined as

\(u = \frac{x}{{\sqrt{x^2 + y^2}}}\)  and \(v = \frac{y}{{\sqrt{x^2 + y^2}}}\), is given by:

\(f_{U,V}(u,v) = \frac{1}{{2\pi}} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v):

\(J = \frac{{du}}{{dx}} \frac{{du}}{{dy}}\)

\(\frac{{dv}}{{dx}} \frac{{dv}}{{dy}}\)

Substituting u and v in terms of x and y, we can evaluate the partial derivatives:

\(\frac{{du}}{{dx}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}} \\\frac{{du}}{{dy}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dx}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dy}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}}\)

Therefore, the Jacobian determinant is:

\(J &= \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} - \frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} \\&= -\frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} + \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} \\J &= \frac{1}{{(x^2 + y^2)^{\frac{1}{2}}}}\)

Now, we can find the joint density function of (u, v) as follows:

\(f_{U,V}(u,v) &= f_{X,Y}(x,y) \cdot \left|\frac{{dx,dy}}{{du,dv}}\right| \\&= f_{X,Y}(x,y) / J \\&= f_{X,Y}(x,y) \cdot (x^2 + y^2)^{\frac{1}{2}}\)

Substituting the standard normal density function

\(f_{X,Y}(x,y) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \\f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \cdot (x^2 + y^2)^{\frac{1}{2}} \\&= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

Therefore, the joint distribution of (u, v) is given by:

\(f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot \exp\left(-\frac{1}{2}(u^2 + v^2)\right)\)

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To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

The joint distribution of (u, v) can be found by transforming the independent random variables x and y using the following formulas:

\( u = x + y\)
\( v = x - y \)

To find the joint distribution of (u, v), we need to find the joint probability density function (pdf) of u and v.

Let's start by finding the Jacobian determinant of the transformation:

\(J = \frac{{\partial (x, y)}}{{\partial (u, v)}}\)

\(= \frac{{\partial x}}{{\partial u}} \cdot \frac{{\partial y}}{{\partial v}} - \frac{{\partial x}}{{\partial v}} \cdot \frac{{\partial y}}{{\partial u}}\)

\(= \left(\frac{1}{2}\right) \cdot \left(-\frac{1}{2}\right) - \left(\frac{1}{2}\right) \cdot \left(\frac{1}{2}\right)\)

\(J = -\frac{1}{2}\)

Next, we need to express x and y in terms of u and v:

\(x = \frac{u + v}{2}\)

\(y = \frac{u - v}{2}\)

Now, we can find the joint pdf of u and v by substituting the expressions for x and y into the joint pdf of x and y:

\(f(u, v) = f(x, y) \cdot |J|\)

\(f(u, v) = \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{x^2}{2}\right) \cdot \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{y^2}{2}\right) \cdot \left|-\frac{1}{2}\right|\)

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{u^2 + v^2}{8}\right)\)

Therefore, the joint distribution of (u, v) is given by:

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{{u^2 + v^2}}{8}\right)\)

In summary, the joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

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Answer:

I'm very sorry, but there is no questions 21-23, if you give me the picture, I'll do it.

Step-by-step explanation:

To determine Bob's expected utility for each option, we calculate the utility for each outcome and weigh them by their respective probabilities.

Option A:

Expected utility = 0.5v(316 - 30) + 0.5v(4 - 0)

= 0.5v(48) + 0.5v(4) = 0.548 + 0.54 = 26.

Option B: Expected utility = v(8) = 8.  

Bob would choose Option A as it has a higher expected utility.

ii. Option A: Expected utility = 0.5v(-16) + 0.5v(-4) = 0.5*(-32) + 0.5*(-8)

= -20.

Option B: Expected utility = v(-12) = -24. Bob would choose Option B as it has a higher expected utility.

iii. Option A: Expected utility = 0.5v(8) + 0.5v(-4) = 0.58 + 0.5(-8) = 0. Option B: Expected utility = v(1) = 1.  Bob would choose Option B as it has a higher expected utility.

 (b) If Bob buys the hammer for $2, his utility would be v(-2) = -4. If he does not buy the hammer, his utility would be v(0) = 0. Bob would prefer not to buy the hammer since the utility is higher at 0.

(c) If Bob sells the hammer for $2, his utility would be v(2) = 2. If he does not sell the hammer, his utility would be v(0) = 0. Bob would prefer to sell the hammer since the utility is higher at 2. (d) Bob's buying price is not the same as his selling price.

This concept is known as loss aversion, where individuals tend to value losses more than equivalent gains. One study that demonstrates a similar concept is the "Prospect Theory" by Daniel Kahneman and Amos Tversky, which shows how people's decision-making is influenced by the potential for gains and losses and how they weigh them differently.

The study revealed that individuals are generally more averse to losses and are willing to take greater risks to avoid losses compared to the risks they are willing to take for potential gains of equal value.

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Answer:

1) y = 5, x = 2

2) y = 5, x = 8

3) y = -2, x= -2

Step-by-step explanation:

1)

Use elimination to solve this problem. In this case, one can just add up the two equations, simplify, use inverse operations, and then substitute back in to find the answer.

y = -x + 7

y = x + 3

_______

2y = 10

/2     /2

y = 5, x = 2

2)

Use elimination, in this case, one will have to multiply the second equation by -2, then add, in order to eliminate one of the variables. Finally one will have to simplify, use inverse operations and then substitute back in to solve.

y = x - 3

y = (1/2)x + 1 (*-2)

y = x - 3

-2y = -x - 2

-y = -5

y = 5,   x = 8

3)

Use elimination, in this case, one will have to multiply the second equation by 2, then add, in order to eliminate a variable. Then one will have to simplify, use inverse operations and then substitute back in to solve.

y = 2x + 2

y = -x - 4     *(2)

y = 2x + 2

2y = -2x - 8

3y = -6

/3      /3

y = -2, x = -2

The 14 distinct 3-dimensional configurations in that atoms can be organized in crystals are known as the Bravais Lattice.

By using this formula 1/d(hkl)^2 = (h^2/a^2 + k^2/b^2 + (l^2/c^2) calculate d for each peak and then select the particular index in which only one index having a value and other two are zero to calculate the lattice parameters (a,b,c).

A unit cell is the smallest collection of symmetrically aligned atoms that may be repeated in an array to form the whole crystal.A lattice can be explained in a variety of ways. The Bravais lattice is considered to be the most basic explanation. A Bravais lattice is, in other words, a collection of discrete points that, from any discrete point, have the same arrangement and orientation, making the points of the lattice identical.

Thus, one of the 14 various kinds of unit cells that might make up a crystal structure can be referred to as a Bravais lattice.

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The coefficient of x^3 in the Taylor series for f(x) is 0, since there is no term involving x^3.

To find the Taylor series of the function f(x) = 1/(2x) about x = 0, we can use the formula:

\(f(x) = f(0) + f'(0)x + (1/2!)f''(0)x^2 + (1/3!)f'''(0)x^3 + ...\)

where f'(x), f''(x), f'''(x), etc. denote the derivatives of f(x).

First, we need to find the derivatives of f(x):

f'(x) = -1/(2x^2)

f''(x) = 2/(x^3)

f'''(x) = -6/(x^4)

f''''(x) = 24/(x^5)

Next, we evaluate these derivatives at x = 0 to get:

f(0) = 1/(2(0)) = undefined

f'(0) = -1/(2(0)^2) = undefined

f''(0) = 2/(0)^3 = undefined

f'''(0) = -6/(0)^4 = undefined

f''''(0) = 24/(0)^5 = undefined

Since the derivatives are undefined at x = 0, we need to use a different method to find the Taylor series. We can use the identity:

1/(1 - t) = 1 + t + t^2 + t^3 + ...

where |t| < 1.

Substituting t = -x^2/a^2, we get:

1/(1 + x^2/a^2) = 1 - x^2/a^2 + x^4/a^4 - x^6/a^6 + ...

This is the Taylor series for 1/(1 + x^2/a^2) about x = 0. To get the Taylor series for f(x) = 1/(2x), we need to replace x with ax^2:

f(x) = 1/(2(ax^2)) = 1/(2a) * 1/(1 + x^2/a^2)

Substituting the Taylor series for 1/(1 + x^2/a^2), we get:

f(x) = 1/(2a) - x^2/(2a^3) + x^4/(2a^5) - x^6/(2a^7) + ...

Therefore, the coefficient of x^3 in the Taylor series for f(x) is 0, since there is no term involving x^3.

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Answer:

The formula to find the mid-point of a line segment give the two end points is:

M

=

(

x

1

+

x

2

2

,

y

1

+

y

2

2

)

Where

M

is the midpoint and the given points are:

(

x

1

y

1

)

and

(

x

2

y

2

)

Substituting the information we have gives:

(

1.5

,

4.5

)

=

(

−

3.5

+

x

2

2

,

−

6

+

y

2

2

)

To find

x

2

we need to solve this equation:

1.5

=

−

3.5

+

x

2

2

2

×

1.5

=

2

×

−

3.5

+

x

2

2

3

=

2

×

−

3.5

+

x

2

2

3

=

−

3.5

+

x

2

3.5

+

3

=

3.5

−

3.5

+

x

2

6.5

=

0

+

x

2

6.5

=

x

2

x

2

=

6.5

To find

y

2

we need to solve this equation:

4.5

=

−

6

+

y

2

2

2

×

4.5

=

2

×

−

6

+

y

2

2

9

=

2

×

−

6

+

y

2

2

9

=

−

6

+

y

2

9

+

6

=

6

−

6

+

y

2

15

=

0

+

y

2

15

=

y

2

y

2

=

15

The other end point of the segment is:

(

6.5

,

15

)

Step-by-step explanation:

(zw)² – 2 (z/w)^(-1 )= z²w² – 2 w/z

w²z³ – 2w

= —————

z

w (z³w – 2)

= ——————

z

Follow my account^^

Answer:

2.76 x 10⁹

Explanation:

Particles of dust per square foot = 2.3 x 10⁷

The size of Vic's bedroom = 1.2 x 10²

Therefore, the number of particles of dust present in the bedroom is:

We simplify our result below.

There are 2.76 x 10⁹ dust particles.

Answer:

20.97$

Step-by-step explanation:

7/3=2.33

2.33*9 = 20.97

Answer:

i tink im doing this complete wrong but 1.380649×10−23 J

Step-by-step explanation:

Answer:

180 degrees

Step-by-step explanation:

-100 + 180 = 80

Answer:

40m

Step-by-step explanation:

Complete question

The equations h = 60 - 4m gives the height h (in inches) of the water in a tank m minutes after it starts to drain. How high is the water after 5 minutes.

To get the height of the water after 5minutes, we will find h at when m = 5

h = 60 -4 (5)

h = 60 - 20

h = 40m

Hence the water is 40m high after 5minutes

The slope of a plot of ln k versus 1/t equal to: −E_a/R

The Arrhenius equation is one that describes the relation between the rate of reaction and temperature for many physical and chemical reactions.

Arrhenius equation is expressed as:

k = \(Ae^{-E_{a}/RT }\)

Taking natural log on both sides,

ln k = ln \(Ae^{-E_{a}/RT }\)

In k = In A - E_a/RT

In k = In A - (E_a/R * (1/T))

This equation is in the form of y = mx + c

The plot of ln k vs 1/T gives a straight line with negative slope.

Slope = −E_a/R

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Gabriela will claim $54550 as her taxable income.

The correct option is A.

Subtraction is a mathematic operation. Which is used to remove terms or objects in the expression.

Given:

Gabriela made $58,750 last year.

She paid $1200 in student loan interest and made a $3000 contribution to her IRA.

That means,

58750 - 1200 - 3000

= 54550

$54550 is the taxable income.

Hence, the taxable income is $54550.

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Answer:

Step-by-step explanation:

x-y=7

-3x+9y=-39

Divide the second equation by 3

-x +3y = -13

Add this to the first equation

x-y=7

-x +3y = -13

----------------------

0x +2y = -6

Divide by 2

2y/2 = -6/2

y = -3

Now find x

x-y = 7

x -(-3) = 7

x+3 = 7

Subtract 3 from each side

x = 4

(4,-3)

Or by substitution

x-y=7  

solve for x

x = 7+y

-3x+9y=-39

Substitute y+7 in for x

-3(7+y) +9y = -39

Distribute

-21 -3y +9y = -39

Combine like terms

-21 +6y = -39

Add 21 to each side

6y = -18

Answer:

The system has no real  solutions.

Step-by-step explanation:

\( \bf \implies{\angle{JND} = 57 \degree}\)

\( \bf \longrightarrow{\angle{BNL} = 33 \degree}\)

\( \bf \longrightarrow{\angle{JND} = \: ?}\)

\( \bf \longrightarrow \: \: \: \angle{BNL} = \angle{DNS} \: \\ \: \: \: \bf [Verically \: Opposite \: Angle]\)

\( \bf \therefore\angle{DNS } = 33 \degree\)

\( \bf \longrightarrow \angle{JND} + \angle{ DNS} = 90 \degree \\ \bf \: \: \: \: \: \: \: \: \: [form \: a \: right \: angle]\)

\( \bf \longrightarrow \angle{JND} +33 \degree= 90 \degree\)

\( \bf \longrightarrow \angle{JND}= 90 \degree - 33 \degree\)

\( \bf \longrightarrow \angle{JND}= 57 \degree \)

Answer:

Step-by-step explanation:

We start by developing an equation for Line 1, and then use that to find the equation for Line 2.  We'll use the form of an equation for a straight line:

 y = mx + b,

where m is the slope and b the y-intercept (the value of y when x=0).

Line 1

Determine the slope, m, by calculating the "Rise/Run" between the two points (-3,-7) and (5,3).

Line up the two points from left to right (based on x) and then calculate:

  Rise:  (3 - (-7)) = 10

   Run:  (5 -(-3) = 8

The slope, m, is Rise/Run or (10/8)

The equation becomes y = (5/4)x + b

We could calculate b, the y-intercept, by entering one of the two given points and solving for b, but the only thing we need from this line is it's slope, m.  Slope is (5/4), which we'll use in the next step:  Line 2.

[Note:  Out of curiosity, here is the calculation for b:  Use point (5,3) in y = (5/4)x + b and solve for b.   3 = (5/4)*5 + b.  3 = (25/4) + b  b = -13/4.  This means that Line 1 is y = (5/4)x -(13/4)]

Line 2

The slope of a line perpendicular to the first is the "negative inverse" of the first line.  In this case, line 1's slope of (13/8) would become a slope of -(8/13) for line 2.

    Line 2:  y = -(8/13)x + b

We'll calculate b for this line by enetering the single point provided,  (-4,-2), and solving for b:

          y = -(8/13)x + b

        -2 = -(8/13)*(-4) + b

          -2 = (32/13) + b

          -2 - (32/13) =  b

b = -(26/13) - (32/13)

b = -(58/13)

The new line perpendicular to Line 1 and passing through (-4,-2) is:

          y = -(8/13)x -(58/13)

See attached graph.

Answer:

6 days

Step-by-step explanation:

The weight for mom's boxes is obtained as 41.41 pounds.

What is weight?

Weight gauges how much gravity is pulling on a body.

The weight formula is provided by -

w = mg

Since weight is a force, it has the same SI unit as a force, which is the Newton (N).

Use a proportion to solve this problem.

Since the weight of the art projects is directly proportional to the number of art projects, we can set up the following proportion -

weight of 11 art projects / 11 = total weight / 24

Solving for the total weight -

total weight = (weight of 11 art projects / 11) x 24

total weight = 2.18 x 24

total weight = 52.32 pounds

So the total weight of the 11 art projects is 24 pounds, and if mom gets 7 of them, 4 art projects will be left weighing a total of -

weight of 4 art projects = (weight of 11 art projects - weight of 7 art projects)

weight of 4 art projects = (24 - (7/11) x 24)

weight of 4 art projects = 10.91 pounds

So, mom would be receiving 7 art projects weighing a total of -

weight of 7 art projects = (total weight - weight of 4 art projects)

weight of 7 art projects = (52.32 - 10.91)

weight of 7 art projects = 41.41 pounds

Therefore, mom's box would weigh 41.41 pounds.

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Answer:right angles, two sets of parallel sides, and opposite sides equal.

Step-by-step explanation: