Sunspots are darker than the regions of the Sun around them because A. they are the shadows of the planets and asteroids seen on the bright surface of the Sun B. they consist of different elements than the rest of the Sun C. they are cooler than the material around them (although still very hot compared to Earth temperatures) D. they are located in the corona and not on the photosphere E. they move much faster around the Sun than other material and thus heat up

(a) The initial temperature is 373.95 K.

(b) The final temperature is 546.15 K.

(c) The total internal energy change of the fluid during this process is 515.4 kJ.

(d) The process can be represented as an isochoric heating process on the P-v diagram and as an isobaric expansion process on the T-v diagram.

(a) To find the initial temperature, we can use the saturated steam tables. At a pressure of 200 kPa, the corresponding saturation temperature is 373.95 K.

(b) Since the volume doubles, the process is an isochoric (constant volume) heating process. Using the ideal gas law, we can determine the final temperature. The initial and final volumes are related by the equation V_final = 2V_initial. Since the mass remains constant, the specific volume (v) is inversely proportional to the density (ρ). Therefore, ρ_final = ρ_initial/2. Using the ideal gas law, we can calculate the final temperature to be 546.15 K.

(c) The total internal energy change can be calculated using the equation ΔU = mC_vΔT, where m is the mass of the fluid and C_v is the specific heat at constant volume. Given the mass as 0.5 kg, the specific heat of water at constant volume, and the temperature change, we can find that the total internal energy change is 515.4 kJ.

(d) On the P-v diagram, the process is represented as a vertical line at 200 kPa, indicating constant pressure. On the T-v diagram, the process is shown as an upward-sloping line, indicating an isobaric expansion process. The initial state is represented as a point on the left, and the final state is represented as a point on the right. The path between the initial and final states is a straight line connecting these two points.

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When wind energy is transferred to the water, waves form and particles of water move in a nearly circular orbit.

Wind energy is converted into water energy by the wind, which can cause waves to form on the surface of the ocean. As wind energy is transferred to water, particles of water move in a nearly circular orbit.

A wave is a form of water movement that occurs in the ocean. A wave is produced when energy is transferred from the wind to the water. As a result, a wave is a form of energy that travels through the water. The particles of water transfer energy, not the water itself.

Water waves can be grouped into two categories: deep-water waves and shallow-water waves. Deep-water waves are waves that travel through deep water. They are distinguished by the fact that the water is deep enough that the entire wave is affected by the water's depth.

Shallow-water waves are waves that travel in shallow water. They are distinguishable because the wave's depth is less than one-half of the wavelength. Water waves are very important to surfers and others who enjoy water sports, and understanding the science behind them can help us appreciate them even more.

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Many students leaving a crowded room and entering a vacant hallway could serve as a model of diffusion (option D).

The transfer of molecules from a location of higher concentration to a region of lower concentration is referred to as diffusion. Many students leaving a crowded room and entering a vacant hallway could serve as a model of diffusion (option D). A specific event or circumstance is described or shown using a model. The area with higher concentration in this instance is the packed room. The area with lower concentration is the unoccupied hallway. The students are the molecules. Diffusion is also implied by their transition from the busy room to the empty hallway.

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Answer:

B: The colors of light emitted from heated atoms had very specific energies.

Explanation:

B: The colors of light emitted from heated atoms had very specific energies.

Answer:

C.

Explanation:

For every action there is a opposite negative reaction. So what ever the positive action is there is the negative reaction for it.

For example: +10 action and -10 reaction. It will always equal 0. If it doesn't then you probably might have done something wrong.

Answer:

always equal to zero

Answer: average annual rainfall, average annual temperatures, types of plants and animals native to the area

Explanation: the best way you can identify a biome is by telling which animal or species are native to the certain area

Answer:

a wire carrying a currents creates a magnetic field this can interact with another magnetic field causing a force that pushes the wire at right angles. This is called the motor effect

Answer:

The work done on the block by the force of gravity is 392.4 J. The work done by the normal force is zero. The work done by the net force is equal to the change in kinetic energy of the block. At the end of the slide, the block has a kinetic energy of (1/2)mv^2, where v is the speed of the block.

Explanation:

Answer:

The heat necessary to warm 500g of water from 20°C to 65°C is 37,620 J.

Explanation:

GIVEN: m = 500 gm, T₂ = 65°C AND T₁  = 20°C, we know that c (specific heat capacity) = 4180

TO FIND: The heat necessary to warm 500g of water from 20°C to 65°C.

SOLUTION:

By using the heat equation,

              Q=m c ΔT  

             ΔT = T₂ - T1

             ΔT = 65 - 20 = 45°C

In this case,

Q = 0.2 × 4180 × 45 = 37,620 J

The final speeds of the spheres are 3.47 m/s and 3.08 m/s.

We can use conservation of momentum to solve this problem since there are no external forces acting on the system.

The initial momentum of the system is:

p_initial = m₁ * v₁ + m₂ * v₂

where m₁ and m₂ are the masses of the spheres, and v₁ and v₂ are their initial velocities (4.00 m/s and 0 m/s, respectively).

After the collision, the momentum of the system is:

p_final = m₁ * v1' + m₂ * v₂'

where v₁' and v₂' are the final velocities of the spheres. We also know that the angle between the first sphere's final path and its initial path is 60 degrees, which means that the angle between the two spheres after the collision is 150 degrees (90 + 60).

Using conservation of momentum, we can set the initial and final momenta equal to each other:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' + m₂ * v₂'

We can also break down the final velocities into their x and y components using trigonometry. Let's define the angle between the first sphere's final path and the x-axis as theta. Now we can use conservation of momentum to solve for the final velocities:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' * cos(theta) + m₂ * v₂' * cos(150 degrees)

0 = m₁ * v₁' * sin(theta) + m₂ * v₂' * sin(150 degrees)

Solving the first equation for v₂', we get:

v₂' = (m₁ * v₁ + m₂ * v₂ - m₁ * v₁' * cos(theta)) / (m₂ * cos(150 degrees))

Substituting this expression into the second equation and solving for v₁', we get:

v₁' = (m₂ * sin(150 degrees) * v₁ + m₂ * sin(150 degrees) * v₂ + m₁ * sin(theta) * v₁' - m₁ * sin(theta) * m₂ * v₁ * cos(theta) / cos(150 degrees)) / (m₁ * sin(theta))

Plugging in the given values and solving, we get:

v₁' = 3.47 m/s

v₂' = 3.08 m/s

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Answer:

Erosion of Mountains

Explanation:

Answer:

c gimme brainliest I'm right

Answer:

We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The coordinate origin is at the release point (the initial position for the ball as it begins projectile motion in the sense of §4-5), and we let θ

0

be the angle of throw (shown in the figure). Since the horizontal component of the velocity of the ball is v

x

=v

0

cos40.0°, the time it takes for the ball to hit the wall is

t=

v

x

Δx

=

(25.0m/s)cos40.0

o

22.0m

=1.15s.

(a) The vertical distance is

Δy=(v

0

sinθ

0

)t−

2

1

gt

2

=(25.0m/s)sin40.0

o

(1.15s)−

2

1

(9.80m/s

2

)(1.15s)

2

=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: v

x

=v

0

cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

v

y

=v

0

sinθ

0

−gt=(25.0m/s)sin40.0

o

−(9.80m/s

2

)(1.15s)=4.80m/s.

(d) Since v

y

>0 when the ball hits the wall, it has not reached the highest point yet.

Answer:

horizontal component of the velocity of the ball is vx​=v0​cos40.0°, the time it takes for the ball to hit the wall is

t=Δx/vx​=(25.0m/s)cos40.0o22.0m​=1.15s.

(a) The vertical distance is

Δy=(v0​sinθ0​)t−21​gt2=(25.0m/s)sin40.0o(1.15s)−21​(9.80m/s2)(1.15s)2=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: vx​=v0​cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

vy​=v0​sinθ0​−gt=(25.0m/s)sin40.0o−(9.80m/s2)(1.15s)=4.80m/s.

(d) Since vy​>0 when the ball hits the wall, it has not reached the highest point yet.

Explanation:

Radius of disk, `R`= `r`Charge of electron, `q`= `-e`Surface charge density of disk, `σ`= `4 µC/m²`= `4×10⁻⁶ C/m²`Using the formula for electric field at a point on the axis of a uniformly charged disk, we have:$$E=\frac{\sigma R}{2\epsilon_0}\left(1-\frac{z}{\sqrt{R^2+z^2}}\right)$$where,`z` is the distance from the center of the disk to the point where electric field is to be calculated.`ε₀` is the permittivity of free space.`

σ` is the surface charge density of disk.`R` is the radius of the disk.Substituting the given values, we get:$$E=\frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{z}{\sqrt{R^2+z^2}}\right)$$On substituting `z=r`, where `r` is the distance from the center of the disk at which the electron is released, we have:$$E=\frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$The electric field is the force per unit charge acting on the electron.

So, the force `F` acting on the electron is given by:$$F=qE=-e\cdot \frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$The acceleration `a` of the electron is given by:$$a=\frac{F}{m}$$$$a=\frac{qE}{m}=-\frac{e}{m}\cdot \frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$The negative sign indicates that the acceleration is opposite to the direction of electric field.The mass of electron, `m`= `9.11×10⁻³¹ kg`Substituting the given values, we have:$$a=-\frac{(1.60\times 10^{-19})}{(9.11\times 10^{-31})}\cdot\frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$On substituting the given values of `R` and `e`, we get the main answer of the given problem as:$$a=\frac{8\times 10^4}{\sqrt{r^2+4\times 10^8}}\left(1-\frac{r}{\sqrt{r^2+4\times 10^8}}\right)$$Hence, the magnitude of the electron's initial acceleration if it is released at a distance `r` from the center of the disk is `a = (8 × 10⁴)/√(r² + 4 × 10⁸)} × (1 - r/√(r² + 4 × 10⁸))`.

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Answer:

A higher amplitude means a higher frequency which means a higher energy the higher the wavelength means lower energy because its not as precise and cant reach levels small wavelengths can the sound waves that usually damage our ears are small wavelengths because of the energy applied to them

Explanation:

The amount of coal burnt to operate the mini fridge is 0.81 metric tons.

The term energy cost refers to the monetary cost of operating a particular electrical appliance. Let us now answer the questions one after the other.

a) Power consumption per hour = 100 watt or 0.1kW. To operate it for an hour we have  0.1kWhr × $0.10/kWh = 0.01$ Since it operates for twelve hours a day 12(0.01$)= 0.12$ per day. In five years; 0.12$× 5 × 365 = 219 $.

b) Electricity used for the five years = 5 × 365 × 12 × 0.1kWhr = 2190 kWhr

Since 1 metric ton of coal produces 2713 kWh(considering energy losses)

x metric tons of coal produces 2190 kWhr

x = 1 metric ton × 2190 kWhr/2713 kWh

x = 0.81 metric tons

c) In part 1 we did not include the cost of the environmental damage caused by the mining of coal and the social inconveniences caused by the sound of the mini fridge.

d) The college student could reduce the electricity use associated with having a mini fridge in his or her dorm room by turning it off for some hours within the day.

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The strength of the electric field at (2.0m, 3.0m) is 880 V/m and the direction of the electric field is 116.6 degrees counterclockwise from the positive x-axis.

To find the electric field strength and direction, we need to take the negative gradient of the electric potential. Therefore, we first need to find the partial derivatives of V with respect to x and y:

Vx = 400x V/m

Vy = -440y V/m

Next, we can calculate the electric field components:

Ex = -Vx = -400x V/m

Ey = -Vy = 440y V/m

At the point (2.0m, 3.0m), the electric field strength can be calculated as:

E = sqrt(Ex^2 + Ey^2) = sqrt((-400x)^2 + (440y)^2) = 880 V/m

The direction of the electric field can be determined as:

theta = arctan(Ey/Ex) = arctan(440y/(-400x)) = 116.6 degrees counterclockwise from the positive x-axis.

Therefore, the electric field strength at (2.0m, 3.0m) is 880 V/m and the direction of the electric field is 116.6 degrees counterclockwise from the positive x-axis.

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Answer:

Most certainly yes

Explanation: First you have to define what friction is "A force that resist motion" while Mechanical advantage " is simply a measure of the output force to the input force". Hence in a mechanical system if you increase friction in the system, it reduces the mechanical advantage and vice versa.

Answer:

The answer is (B). hot dry desert climate

Explanation:

Patrick's average velocity for the trip is 0.41 m/s along southeast.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Resultant displacement of Patrick = √(70² +20²) meter southeast

= 72.801 meter southeast.

Total time interval = 150 second + 30 second = 180 second

Hence, his average velocity for the trip is = resultant displacement/ Total time interval

= 72.801 meter ÷ 180 second

= 0.41 m/s along southeast

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The pressure difference needed to drain the shake in 3.0 minutes is approximately 346.67 cP cm^3/min / cm^2.

To find the pressure difference needed to drain the shake in 3.0 minutes, we can use the equation for flow rate:
Flow Rate = Volume / Time
Given that the volume is 520 ml and the time is 3.0 minutes, we can calculate the flow rate:
Flow Rate = 520 ml / 3.0 minutes = 173.33 ml/min

Now, to find the pressure difference, we can use the equation:
Pressure Difference = (Flow Rate * Viscosity) / Area
The viscosity of a shake is similar to that of water, which is about 1.0 cP (centipoise). The area of a typical straw is about 0.5 cm^2.
Plugging in the values:
Pressure Difference = (173.33 ml/min * 1.0 cP) / 0.5 cm^2
Converting ml to cm^3 (1 ml = 1 cm^3):
Pressure Difference = (173.33 cm^3/min * 1.0 cP) / 0.5 cm^2
Simplifying:
Pressure Difference = 346.67 cP cm^3/min / cm^2

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Answer:

On Bode's advice, Herschel named his newly discovered planet after: the Greek god Uranus.

Explanation:

Herschel named his newly discovered planet Uranus on Bode's advice for a couple of reasons:

Mythological Naming Convention: During that time, it was a common practice to name celestial objects after mythological figures, particularly gods from Greek and Roman mythology. Bode suggested following this convention and recommended that Herschel choose a name from Greek mythology for the newly discovered planet.

Connection to the Sky: Uranus was chosen as the name for the planet because it was the name of the Greek god of the sky. Given that Herschel had discovered a celestial object in the sky, naming it after the god associated with the sky seemed fitting.

By naming the planet Uranus, Herschel paid homage to the mythological tradition of naming celestial bodies while also establishing a connection between his discovery and the vastness of the sky.

Hope this helps!

Answer:

5.4mL

Explanation:

20.25g divided by 3.75g/mL= 5.4mL

The Second Law of Thermodynamics states that the total entropy of an isolated system can only increase over time.

Thermodynamics is the branch of physics that deals with the relationships between heat, work, temperature and energy. It is the study of how energy is converted from one form to another and how it is used to do work. Thermodynamics is concerned with the transfer of energy from one object or system to another and how that energy can be transformed or converted into different forms. It also explores the relationships between entropy, temperature, and energy. Thermodynamics can also be used to predict how systems will behave when exposed to a given amount of energy. Thermodynamics is a powerful tool used to understand the behavior of natural systems and to develop efficient technologies.

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Answer:

I don't know how it works, but I found this on the internet. image does not belong to me.

hope it helps!

Answer:

X-RAY

Explanation:

I took the test on study island

Answer:

Resultant horizontal force = 143 N

Explanation:

Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;

Resultant horizontal force = 165 * cos 30

Resultant horizontal force = 142.89

Approximating to a whole number gives;

Resultant horizontal force = 143 N

Answer:

a = 30 km / h²

Explanation:

Dado que

Velocidad inicial, u = 70 km / h

Velocidad final, v = 95 km / h

Tiempo, t = 30 s = 0.1 h

Lo sabemos

v = u + a t

a = aceleración

Ahora poniendo los valores en la ecuación anterior

\(95 = 70 + a \ times 0.1 \)

\(a = \ dfrac {95-70} {0.1} = 30 \ km / h ^ 2 \)

Por lo tanto, la aceleración será

a = 30 km / h²

GREETINGS!

lightening usually strikes the metal pole and cables above the building because they provide a safe low resistance pathway to the lightening to move from building from the concrete steel to the ground below, thats how building doesnt get any damage and high electric charge passes through it

HOPE IT HELPS YOU!

Answer:

The combined mass of the two stars is 2.9417 solar masses.

Explanation:

The mathematical expression for Kepler's third law is;

                        \(P^{2}\) = \(\frac{4\pi ^{2} }{k^{2} (M_{1} + M_{2} }a^{3}\)

Where: P is the period in days, a is the semimajor axis in AU, \(M_{1}\) is the mass of the first star, \(M_{2}\) is the mass of the second star and k is the Gaussian gravitational constant.

Given that;

P = 10 years = 3670 days (including two leap years)

a = 6.67 AU

k = 0.01720209895 rad

\(\pi\) = \(\frac{22}{7}\)

The sum of the masses of the two star can be determined by;

\((M_{1} + M_{2})\) = \(\frac{4\pi ^{2} }{P^{2}k^{2} } a^{3}\)

                = \(\frac{4*(\frac{22}{7}) ^{2} } {(3650)^{2} * (0.01720209895)^{2} } (6.67)^{3}\)

                = \(\frac{11724.29601}{3942.2904}\)

               = 2.9417 solar masses

Thus the combined mass of the two star is 2.9417 solar masses.

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Speed of scooter is 15 m/s . And, we have been asked to calculate the Distance , covered by the scooter in 45 seconds .

For calculating the Distance , we will use the Formula :-

\( \bigstar \: \: \boxed{ \sf{ \: Distance \: = \: Speed \: \times \: Time \: }} \)

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf { Distance \: = \: Speed \: \times \: Time \: } \)

\( \longmapsto \: \: \: \sf { Distance \: = \: 15 \: \times \: 45 \: } \)

\( \longmapsto \: \: \textbf {\textsf { Distance \: = \: 675 meter}} \)

\( \underline {\rule {180pt} {4pt}} \)