The tiny space invader and the new space station will have equal orbital speed.
The orbital speed of satellite
The orbital speed of satellite on Earth surface is given as;
\(V = \sqrt{\frac{GM}{r} }\)
where;
V is the orbital speedG is universal gravitationM is mass of the Earthr is the radius of the circular pathSince the two objects are at the same height from Earth's surface, the distance from the central point (r) will be the same. Thus, the two objects will have equal orbital speed.
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a ball is thrown straight upward with an initial velocity of 8 m/s. the magnitude of the final velocity of the ball is
A. 0 m/s
B. 4 m/s
C. 8 m/s
D. 16 m/s
Assuming no air restance the speed when the ball comes back to the starting point will be again 8ms but directed DOWNWARDS; we can express this by saying that it will equal to −8ms adding a minus to indicate the downward direction.
To find the time of flight we use:
vf=vi+at
Where:
a is the acceleration of gravity (downwards, −9.8ms2);
vi=+8ms
vf=−8ms
So, we get:
−8=8−9.8t
−16=−9.8t
t=169.8≈1.6s
The answer is "B"
Answer link
In what direction will each of the wires below move?
Answer:
Explanation: ckeck this imagewhat is the work done on the box from x = 0m to 16m
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
Someone please help me!
Answer:
1,285 Risistance
Explanation:
The reason behind this is because of ohms law. You should use the formula r=v/i to find the resistance.
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
what instrument is used to measure volume by displacement
Identify the situation in which the kinematic equations under free fall are applicable.
To find:
The situation in which the kinematic equation under free fall is applicable.
Explanation:
The free fall is defined as the motion of an object under the influence of gravity.
The motion of the ball along the snooker board involves the applied force and the frictional force.
The motion of a bus along the road involves the applied force and the frictional force.
The motion of an airplane along the runway involves applied and frictional forces.
The raindrop moves towards the earth under the influence of gravity. Thus for this motion, the kinematic equations under the free fall are applicable.
Final answer:
The correct answer is option D.
A hollow ball weighs 40 newtons. In a water tank, it displaces 15 newtons of water. What is the buoyant force on the ball? Will the ball float or sink? Explain your reasoning.
Answer:
25N
it will float since the water displaced is less than the weight. buoyancy = 25n down
Explanation:
40 newtons - 25 newtons = 25 newtons
The buoyant force on the ball is 25 Newton and the ball will float.
From the information given, we're informed that a hollow ball weighs 40 newtons and a water tank displaces 15 newtons of water.
Therefore, the buoyant force on the ball will be:
= 40N - 15N = 25N
Since we got a positive value, it means that the ball will float on water.
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Which of the following measurement is most significant?
A. 66.000cm
B. 0.00066cm
C. 6.600cm
D. 6.6cm
Option C. The measurement with the most significant number is 6.600 cm.
What is significant number?
Significant numbers are numbers that have significance or meaning and give more precise details about the value of the entire numbers.
66.000 cm ------> 2 significant numbers0.00066 cm -------> 2 significant numbers6.600 cm ----------> 4 significant numbers6.6 cm ---------------> 2 significant numbersThus, the measurement with the most significant number is 6.600 cm.
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Part A
Playing in the street, a child accidentally tosses a ball (mass m) with a speed of v=18 m/s toward the front of a car (mass M) that is moving directly toward him with a speed of V=20 m/s . Treat this collision as a 1-dimensional elastic collision. After the collision, the ball is moving with speed v′ back toward the child and the car is moving with speed V′ in its original direction.
Part B
When we combine the equation from Part A with the conservation of momentum equation, we can solve for both final speeds. This relationship will involve the masses of the ball and the car, but we can apply a simplifying assumption: the car is so massive compared with the ball that its speed will not change at all as a result of this collision. Translate this sentence into an equation, what is V′ equal to? Now, having made this assumption, it becomes possible to solve the equation from Part A for the final speed of the ball, what is it?
Answer:
v' = -18 m/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved, as follows:\(p_{o} = p_{f} (1)\)
The initial momentum can be expressed as follows (taking as positive the initial direction of the ball):\(m_{b} * v_{b} -M_{c}*V_{c} = m_{b} * 18 m/s + (-M_{c}* 20 m/s) (2)\)
The final momentum can be expressed as follows (since we know that v'b is opposite to the initial vb):\(-(m_{b} * v'_{b}) + M_{c}*V'_{c} (3)\)
If we assume that Mc >> mb, we can assume that the car doesn't change its speed at all as a result of the collision, so we can replace V'c by Vc in (3).So, we can write again (3) as follows:\(-(m_{b} * v'_{b}) +(- M_{c}*V_{c}) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (4)\)
Replacing (2) and (4) in (1), we get:\(m_{b} * 18 m/s + (-M_{c}* 20 m/s) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (5)\)
Simplifying, and rearranging, we can solve for v'b, as follows:\(v'_{b} = -18 m/s (6)\), which is reasonable, because everything happens as if the ball had hit a wall, and the ball simply had inverted its speed after the collision.What is the rms speed of oxygen molecule at a pressure of 3.9x104
Pa if it has a
density of 1.3kg/m3
The root-mean-square speed of an oxygen molecule at a pressure of 3.9 x 10^4 Pa and a density of 1.3 kg/m^3 is approximately 6.13 x 10^-9 m/s.
What is the rms speed?The root-mean-square (rms) speed of an oxygen molecule can be calculated using the ideal gas law and the definition of density.
The ideal gas law states:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Rearranging the ideal gas law to solve for the rms speed (v) gives:
v = sqrt(3 * P / (density * N))
where P is the pressure, density is the density of the gas, and N is Avogadro's number (6.022 x 10^23 molecules/mol).
Given:
Pressure (P) = 3.9 x 10^4 Pa
Density = 1.3 kg/m^3
We can substitute these values into the formula to calculate the rms speed of an oxygen molecule.
v = sqrt(3 * (3.9 x 10^4) / (1.3 * (6.022 x 10^23)))
v = sqrt(3.77 x 10^-18 m^2/s^2)
v ≈ 6.13 x 10^-9 m/s
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Convert 1 x 10-3 nm to m. given: 1 m = 1,000,000,000 nm
Answer:
l m = 1000000000 nm
? = 0.001
= 0
1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
C=59(F−32)The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
A. temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 59 degree Celsius.
B. temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
C. temperature increase of 59 degree Fahrenheit is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
As a result, claim I is accurate. According to this formula, a temperature increase of 1 degree Celsius is comparable to a temperature increase of 9/5 degrees Fahrenheit.
0F and 0C stand for what?The Celsius scale, sometimes known as the centigrade scale, is a temperature scale based on the water's freezing point at 0°C and boiling point at 100°C. A temperature scale called the Fahrenheit scale is based on the fact that water freezes at 32°F and boils at 212°F.
Why convert 95 degrees Celsius to degrees Fahrenheit?The relationship between Celsius and Fahrenheit is inversely proportional. The temperature on the Fahrenheit scale rises as the temperature does on the Celsius scale, and vice versa. The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C.
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prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?
Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.
Why should cars be maintained and / or serviced ?First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.
The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.
This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.
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in a car lift in a service station, compressed air exerts a force on a small piston that has a circular cross section of radius 5.00cm. This pressure is transmitted by a liquid to a piston that has a radius of 15.0 cm. (b) What air pressure will produce a force of that magnitude?
The air pressure that will produce a force of the given magnitude is 135 times the pressure transmitted by the liquid. The value of P2, the pressure transmitted by the liquid, is not given in the problem, so we cannot determine the exact value of P1.
How is atmospheric pressure produced?The planet's gravitational pull on the gases above its surface produces atmospheric pressure, which depends on the planet's mass, the radius of its surface, the quantity, makeup, and vertical distribution of the gases in the atmosphere.
The following equations describe the force that compressed air exerts on a tiny piston:
F1 = P1 * A1
The larger piston, which has a larger area A2, receives the power via the liquid. The larger piston's power is determined by:
F2 = P2 * A2
Pascal's rule states that the larger piston receives the same amount of pressure P1 as the smaller piston, so we have:
P1 = P2
Since the forces F1 and F2 are equal, we have:
F1 = F2
Therefore:
P1 * A1 = P2 * A2
P1 * (pi * (5.00 cm)²) = P2 * (pi * (15.0 cm)²)
Simplifying and solving for P1, we get:
P1 = (P2 * A2 * (5.00 cm)²)/ (A1 * (15.0 cm)²)
Substituting A1 = pi * (5.00 cm)² and A2 = pi * (15.0 cm)², we get:
P1 = (P2 * 15.0²) / 5.00²
P1 = 135 * P2.
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Convert 25 meters per second (m/s) to feet per second (ft/s)
Answer: 82.021 Feet per second
Explanation:
Answer:
82.021 Feet per second
Explanation:
what is the velocity of a 0.145kg baseball if its kinetic energy is 109 j
Answer:
The velocity of the 0.145 kg baseball is 38.7743 m/s.
General Formulas and Concepts:
Energy
Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)
m is mass (in kg)v is velocity (in m/s)KE is kinetic energy (in J)Explanation:
Step 1: Define
Identify.
m = 0.145 kg
KE = 109 J
Step 2: Solve for v
Substitute in variables [Kinetic Energy Formula]: \(\displaystyle 109 \ \text{J} = \frac{1}{2}(0.145 \ \text{kg})v^2\)Simplify: \(\displaystyle 109 \ \text{J} = (0.0725 \ \text{kg})v^2\)Isolate variable term: \(\displaystyle 1503.45 \ \text{J/kg} = v^2\)Isolate v: \(\displaystyle v = 38.7743 \ \text{m/s}\)Topic: AP Physics 1/C
Unit: Energy
Imagine a 15 kg block moving with a velocity of 20 m/s to the left. Calculate the Kinetic Energy of this block. Formula: Work with Units: Variables with units: Final Answer with units:
Answer:
3000 J (joules)
Explanation:
Use the formula for kinetic energy which is:
\( k.e = \frac{1}{2} mv ^{2} \)
Where m is the mass and v is the velocity. If we put the values into the formula we get: 0.5 * 15 * (20)*(20) = 3000J
Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.
A fox getting its energy from a mouse and a mouse getting its energy from the grass shows evidence of the carbon cycle
What is the carbon cycle?The carbon cycle is a necessary component within the global interchange between living species and the environment.
Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.
Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.
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Which sling can the crane use to lift the 1000kg pipe?
A.
800kg rated sling
B. 1000kg rated sling
C. 2000kg rated sling
D. Band C
Answer:
C. 2000kg rated sling
Explanation:
ensures better safety and can carry twice more mass than current mass.
what is the frequency of a wave related to
Answer:
Frequency is the number of complete oscillations or cycles or revolutions made in one second.
if the mass of an object were doubled, its weight would be
Weight of a body is defined as the force with which it is attached to the earth.
mass is the total quantity of matter present.
the weight of something is given as mass * acceleration
weight of an object is directly proportional to the mass of the object. so, if mass doubles, weight will also double.
hope this helps :)
- jeron
1. Determine the potential energy of a 2kg rock at the top of a hill that is 20m high.
2. Determine the kinetic energy of a 2000 kg roller coaster car that is moving with a speed of 25 m/s.
3. A 80kg freezer is located in an office on the 59 floor of an office building 200 meters above the ground. What is the potential energy of the freezer?
Answer:
1) 392 joules
2) 625,000 joules
3) 156,800 joules
Explanation:
Gravitational potential energy = mgh. m = mass in kg, g = acceleration due to gravity and h = height in meters.
Kinetic energy = 1/2(m)(v)^2, m = mass in kg, v = velocity in meters per second
1) P.E = 2 x 9.8 x 20 = 392 joules
2) K.E = 1/2 x 2000 x (25)^2 = 625,000 joules
3) P.E = 80 x 9.8 x 200 = 156,800 joules
Answer:
\(1)\:392\:\text{J}\:(400\:\text{J with one significant figure)},\\2)\:625,000\:\text{J}\:(600,000\:\text{J with one significant figure)},\\3)\:156,800\:\text{J}\:(200,000\:\text{J with one significant figure)},\)
Explanation:
1. The potential energy of an object is given by \(PE=mgh\). Substituting given values, we have:
\(PE=2\cdot 9.8\cdot 20=\boxed{392\:\text{J}}\)
2. The kinetic energy of an object is given by \(KE=\frac{1}{2}mv^2\). Substituting given values, we have:
\(KE=\frac{1}{2}\cdot 2000\cdot 25^2 =\boxed{625,000\: \text{J}}\)
3. 1. The potential energy of an object is given by \(PE=mgh\). Substituting given values, we have:
\(PE=80\cdot 9.8\cdot 200=\boxed{156,800\:\text{J}}\)
A 900 kg car is beings coasting at 20 m/s along a level road . How large of a constant frictional force is required to stop it in a distance of 30m ?
Given data
*The given mass of the car is m = 900 kg
*The car is moving at a velocity is u = 20 m/s
*The given distance is s = 30 m
The formula for the acceleration of the car is given by the equation of motion as
\(\begin{gathered} v^2=u^2+2as \\ a=\frac{v^2-u^2}{2s} \end{gathered}\)*Here v = 0 m/s is the final velocity of the car
Substitute the known values in the above expression as
\(\begin{gathered} a=\frac{(0)^2-(20)^2}{2\times30} \\ =-6.67m/s^2 \end{gathered}\)The formula for the frictional force is required to stop it at a distance of 30 m is given as
\(f=ma\)Substitute the known values in the above expression as
\(\begin{gathered} f=(900)(-6.67) \\ =-6000\text{ N} \end{gathered}\)Hence, the frictional force is required to stop it at a distance of 30 m is f = -6000 N
a stone dropps 7,11m how long will it take it to fall
The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Heightu = Initial velocityt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/sH = 7.11 mg = 9.8 m/s²Substitute these values into equation 1 and solve for t.
7.11 = (0×t)+9.8×t²/27.11 = 4.9t²t² = 7.11/4.9t² = 1.451t = √1.451t = 1.2 secondsHence, the time it takes the stone to fall is 1.2 seconds.
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Assume a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will ________________ between Resistors R1 and R2 and then recombine at Point B
If a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will divide between Resistors R1 and R2 and then recombine at Point B
Parallel circuitA parallel circuit is a circuit with separate branches with a common endpoint. In a parallel circuit, the voltage across each branch is the same but the currents vary. The total current is the sum of the currents flowing through each component.
If a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will divide between Resistors R1 and R2 and then recombine at Point B.
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A baseball pitcher makes a big mistake and throws the ball straight up. If it reaches a maximum height of 15 m find the initial velocity he threw it up with
Answer:
17.15 m/s.
Explanation:
The following data were obtained from the question:
Maximum height (h) = 15 m
Final velocity (v) = 0 m/s
Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going again gravity)
Initial velocity (u) =.?
The initial velocity with which the baseball pitcher threw the ball can be obtained as follow:
v² = u² + 2gh
0² = u² + (2 × –9.8 × 15)
0 = u² + (–294)
0 = u² – 294
Collect like terms
0 + 294 = u²
294 = u²
Take the square root of both side
u = √294
u = 17.15 m/s
Therefore, the baseball pitcher threw the ball with an initial velocity of 17.15 m/s
Why do objects have specific colors?
Answer:
The color of an object is the wavelength of light that it reflects.
Now slowly begin to raise the temperature. At approximately what temperature would a heated material (metal, wood, etc.) begin to give off visible light at a deep red color?Note: This will be the temperature where your spectrum first begins to come off of the wavelength axis in the visible region, and so is giving off a small amount of red light.
A. 500 K (440 Fahrenheit)
B. 1050 K (1430 Fahrenheit)
C. 1800 K (2780 Fahrenheit)
D. 2500 K (4040 Fahrenheit)
Answer:
Explanation:
We shall apply Wien's displacement law which is as follows .
λ T = b where λ is wavelength of light that is coming out of hot body to maximum extent .
Putting the value of temperature given and b
λ x 500 = 2898 μmK
λ = 5.796 μm = 5796 nm
For temp 1050 K
λ = 2760 nm
For temp 1800 K
λ = 1610 nm
For temp 2500 K
λ = 1159.2 nm
The visible range starts from 740 nm .
Hence we can expect that some amount of visible light may emerge at the temperature of 2500K because the wavelength that we have calculated above gives the value of peak wavelength of a spectrum of light coming out of hot body .