Suppose the height of a cylinder is cut in half and the radius is doubled. how will this affect the volume of the cylinder ?????

Answer:

C: 1/6

Step-by-step explanation:

There is one 2 on a six sided die. Therefore there is a 1/6 chance that it was a 2.

Answer:

Perimeter of sector is 47.93 cm which is greater than 47.5 cm

Step-by-step explanation:

Mathematically, the perimeter of a sector is length of the arc plus 2 radii

The length of the arc is;

theta/360 * 2 * pi * r

where theta is the angle subtended by the arc at the center of the circle

Thus, we have

135/360 * 2 * 22/7 * 11 = 25.93

Add 2 radii = 25.93 + 2(11) = 47.93 cm

This is greater than what we are asked to calculate and thus we have shown what we are asked to show

Answer:

47.9cm>47.5cm

Step-by-step explanation:

135(angle) /360 x 2 pi r (to give arc of the sector)

135/360 x 2 x 3.142 x 11 = 25.92cm

add 11 + 11 (radius)

25.92 + 22= 47.9cm

Answer:

6

Step-by-step explanation:

hope this helps, have a good day

Answer: B, 53

53 is the only prime number between 50 and 60

Answer:

D. Complementary events are always mutually exclusive.

Step-by-step explanation:

A. This is false, because complementary events only have two outcomes. Therefore, they have to be mutually exclusive- otherwise there would be more potential outcomes.

B. Mutually exclusive events cannot occur together, because they cannot happen simultaneously. Therefore, it cannot be B.

C. Again, they cannot happen simultaneously, so it cannot be C.

D. Complementary events are always mutually exclusive, since there are only two outcomes. However, it should be noted that mutually exclusive events are not always complementary.

In a quadrilateral inscribed in a circle, the angles formed by the intersection of opposite sides are supplementary because they are subtended by the same arc. This property holds true for any inscribed quadrilateral, including ABCD in circle O.

To prove that in a quadrilateral inscribed in a circle, its opposite angles are supplementary, we can use the properties of angles in a circle.

Given: Quadrilateral ABCD is inscribed in circle O.

To prove: ∠ABC and ∠ADC are supplementary (add up to 180 degrees).

        ∠DAB and ∠DCB are supplementary (add up to 180 degrees).

Proof:

1. Inscribe quadrilateral ABCD in circle O.

2. The opposite sides of a quadrilateral inscribed in a circle are subtended by supplementary angles.

3. Therefore, ∠ABC and ∠ADC are supplementary.

4. Similarly, ∠DAB and ∠DCB are supplementary.

5. Thus, the theorem is proven.

In a quadrilateral inscribed in a circle, the angles formed by the intersection of opposite sides are supplementary because they are subtended by the same arc. This property holds true for any inscribed quadrilateral, including ABCD in circle O.

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Answer:

the answer is C. because the factor was 36x^3-15x^2-6x so i got 3(x^2+1)(4×-1)

4

cause then 12-6=6

You do parenthesis first and get six, then you subtract

Answer:

B i think

Step-by-step explanation:

Sorry if wrong

Answer:

1/10

Step-by-step explanation:

The first thing is to describe each interval on its own.

If you were to describe the left interval (x<-10) from left-to-right, you'd say, "It goes from negative infinity to -10, not including -10."  To put that into interval notation, you'd have:

     \(\big(-\infty, -10\big)\)

The right interval (x>-2) would be described as "from -2 to infinity, not including -2."  In interval notation, we'd write this as:

    \(\big(-2, \infty \big)\)

Now that we have each one individually, we need to glue them together to say, "You can pick a number from the left interval OR the right interval."  The way we do this, the way we write "or" with intervals is with the union symbol: \(\cup\)

    \(\big(-\infty,-10 \big) \cup \big (-2,\infty\big)\)

Answer: The number twelve carries religious, mythological and magical symbolism, generally representing perfection, entirety, or cosmic order in traditions since antiquity.

Step-by-step explanation: If you're not talking about this type of 12 correct me.

The systems of Inequalities are,

\(6c +4t \leq 300\\c > 0\\t > 0\\c+t \geq 60\)

Inequalities

Use a marker other than the equal sign to indicate relationships between expressions. Less than, larger than, "not equal to," and many other expressions are common relations.

300 square feet of planting beds are available for the school's gardening club to grow tomatoes and cucumbers. Each tomato plant needs 4 square feet of growing space, whereas each cucumber plant needs 6 square feet. The entire area must be greater than 300 square feet, so

\(6c +4t \leq 300\)

being c and t, respectively, the quantity of cucumber and tomato plants.

Additionally, we are aware that the students intend to have at least 60 plants and plant a variety of plants. This exposed us to more problems.

\(\\c > 0\\t > 0\\c+t \geq 60\)

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There were 60 jelly beans in the unopened bag of jelly beans.

Let's work through the problem step by step to find the original number of jelly beans in the bag.

John ate three-fourths of the jelly beans.

This means that he consumed 3/4 of the total number of jelly beans, leaving 1/4 of the original amount.

Mike then ate two-thirds of the remaining jelly beans.

Since 1/4 of the original amount was left after John, Mike ate 2/3 of this remaining 1/4.

To find out how much is left, we need to calculate \((\frac{1}{4} )\times (\frac{2}{3} )\).

\((\frac{1}{4} )\times(\frac{2}{3} )=\frac{2}{12} =\frac{1}{6}\)

Mike ate 1/6 of the original amount, leaving 1/6 of the original amount.

Finally, Fred ate the ten jelly beans that were left.

We know that these ten jelly beans represent 1/6 of the original amount.

Let's calculate how many jelly beans are equal to 1/6.

\(\frac{1}{6} = 10\) jelly beans

Now, we can determine how many jelly beans are equal to 6/6 (the whole).

\(\frac{1}{6} \times6=10\times6=60\) jelly beans

Therefore, there were 60 jelly beans in the unopened bag of jelly beans.

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Nominal scale- A nominal scale is a discrete classification of data, in which data are neither measured nor ordered but subjects are merely allocated to distinct categories.

Measurements on an interval scale have substantial differences between the values. In other words, the disparities between the scale's points are exact and measurable.

Ratio scales are interval scales where lengths are expressed in relation to a rational zero.

Ordinal scale: a scale where data is presented merely in terms of order of magnitude because there is no accepted method for determining differences.

Since there are 5 categories: Blue, Red, Green, Yellow, Orange, so by the above definition we can say that for this question we would use Nominal scale for measurement.

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Answer: D

Step-by-step explanation: I think

Center point of dilation is a fixed point in a plane about which all the points of the figure expanded or contract. And scale factor of a dilation is the ratio of new formed image to the old given image.

Explanation:

Therefore, the center of the dilation can be find using the translation and scale factor can be calculated using the ratio of the new to the old images.

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Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

ANSWER

EXPLANATION

We want to find the value of x that makes l₁ parallel to l₂.

To find the value of x, we can use the sum of angles on a straight line. The sum of angles on a straight line is 180 degrees.

The transversal passes through l₂ and divides it into x and 65 degrees which means that:

Solve for x:

That is the value of x.

Given:

Angles AEC and BED are vertically opposite angles. Hence, we can write:

The number of degrees in angle AEC:

Answer:

The measure of angle AEC = 80 degrees

Answer:

I would say 800, sorry if it was wrong

Step-by-step explanation:

She ran the most on 800

Answer:

MNI = 135º

Step-by-step explanation:

From the picture, we have the two internal angles as \(6x\) and \(15x-12\). The third, the angle ∠MNL is 180 - 19x-2. Therefore,

\(15x-12+6x+(180-19x-2)=180\)

So,

\(15x-12+6x+180-19x-2=180\)

\(15x-14+6x-19x=0\)

\(2x=14\)

\(x=7\)

Finally,

∠MNI = 19x+2 ⇒ ∠MNI = 19(7)+2 ⇒ ∠MNI = 135º

The value of the variable 'x' is 7. Then the measure of the angle ∠MNI will be 131°.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180°.

The exterior angle of a triangle is almost always equal to the addition of the interior and opposing interior angles. The term "external angle property" refers to this feature.

Then the equation is given as,

∠NLM + ∠LMN = ∠MNI

6x + 15x - 12 = 19x + 2

2x = 14

x = 7

Then the measure of the angle ∠MNI is calculated as,

∠MNI = 19 (7) - 2

∠MNI = 133 - 2

∠MNI = 131°

The value of the variable 'x' is 7. Then the measure of the angle ∠MNI will be 131°.

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Answer:

someone help call the police candice just got shot

Step-by-step explanation:

ahahahahahahahhahaa

Answer:

3m

Step-by-step explanation:

1 month =3 movies

m month =3*m movies

Answer:

5/2

Step-by-step explanation:

1000m = 1km

1.75km = 1750m

1750 / 700 = 5/2

 By multiplying matrices B and A, we obtain the product BA. Using BA, we can solve the system of equations y + 2z = 7, x - y = 3, and 2x + 3y + 4z = 17.the values of x, y, and z are -1, 2, and 1 respectively

To find the product BA, we multiply matrix B with matrix A. The resulting matrix will have the same number of rows as B and the same number of columns as A. The product BA will be used to solve the given system of equations.
The product BA can be computed by multiplying each row of matrix B by each column of matrix A and summing the results. The resulting matrix will be:
Now, we can use the product BA to solve the system of equations:
-10x - 10y + 6z = 7,
3x - 8y + 2z = 3,
-6x - 16y + 15z = 17.

1 -1 2
2 3 1
0 4 2
We can rewrite this system of equations as:
-10x - 10y + 6z = 7,
3x - 8y + 2z = 3,
-6x - 16y + 15z = 17.
By comparing the coefficients of x, y, and z in the system of equations with the entries in the matrix BA, we can determine the values of x, y, and z.
Solving the system of equations using matrix BA, we get:
x = -1,
y = 2,
z = 1.
Therefore, the values of x, y, and z are -1, 2, and 1 respectively.

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The complete question is:
Given A=
⎣2 2 -4|
|-4 2 -4|
|2 -1 5|
, B=
⎣1 -1 0|
⎢2 3 4|
⎢0 1 2|
, find BA and use this to solve the system of equations y+2z=7, x−y=3, 2x+3y+4z=17.

Answer:

-9/8

Hope this helps

The right answer is - 9/8

please see the attached picture for full solution

Hope it helps..

9514 1404 393

Answer:

  (-2, 2)

Step-by-step explanation:

The orthocenter is the intersection of the altitudes. The altitude lines are not difficult to find here. Each is a line through the vertex that is perpendicular to the opposite side.

Side XZ is horizontal, so the altitude to that side is the vertical line through Y. The x-coordinate of Y is -2, so that altitude has equation ...

  x = -2

__

Side YZ has a rise/run of -1/1 = -1, so the altitude to that side will be the line through X with a slope of -1/(-1) = 1. In point-slope form, the equation is ...

  y -(-1) +(1)(x -(-5))

  y = x +4 . . . . . . . . subtract 1 and simplify

The orthocenter is the point that satisfies both these equations. Using the first equation to substitute for x in the second, we have ...

  y = (-2) +4 = 2

The orthocenter is (x, y) = (-2, 2).

Answer:

.................hshs

y = (At + B) e^(rt)

where A = -r/2 and B = 3r/2, as expected.

When the two roots of the characteristic equation are both equal to r, we say that the roots are equal or repeated. In this case, the general solution to the corresponding second order linear homogeneous ODE with constant coefficients is of the form:

y = (At + B) e^(rt)

where A and B are constants to be determined by the initial or boundary conditions.

However, the form given in the question, (at+b)âe^rt, is not correct. The â symbol is not standard notation for mathematical expressions and its meaning is unclear. It is possible that it was intended to represent a coefficient or parameter, but without more information, we cannot determine its value or significance.

To see why the correct form of the solution is y = (At + B) e^(rt), we can use the method of undetermined coefficients. Suppose that y = e^(rt) is a solution to the homogeneous ODE with repeated roots. Then, we can try the solution y = (At + B) e^(rt) and see if it satisfies the ODE.

Taking the first and second derivatives of y, we get:

y' = A e^(rt) + r(At + B) e^(rt) = (Ar + r(At + B)) e^(rt)

y'' = A r e^(rt) + r^2(At + B) e^(rt) = (Ar^2 + 2rAt + r^2B) e^(rt)

Substituting y, y', and y'' into the homogeneous ODE with repeated roots, we get:

(Ar^2 + 2rAt + r^2B) e^(rt) = 0

Since e^(rt) is never zero, we can divide both sides by e^(rt) to get:

Ar^2 + 2rAt + r^2B = 0

This is a linear equation in A and B, and we can solve for them by using the initial or boundary conditions. For example, if we are given that y(0) = 1 and y'(0) = 0, we have:

y(0) = A e^(0) + B e^(0) = A + B = 1

y'(0) = (Ar + rB) e^(0) + A e^(0) = Ar + A = 0

Solving this system of equations, we get:

A = -r/2, B = 3r/2

Therefore, the general solution to the homogeneous ODE with repeated roots is:

y = (-rt/2 + 3r/2) e^(rt)

which can be rewritten as:

y = (At + B) e^(rt)

where A = -r/2 and B = 3r/2, as expected.

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The solutions of the given differential equation are y(x) = e^(-7x) and y(x) = 0. To determine which functions are solutions of the differential equation y'' + 14y' + 49y = 0, we can substitute each function into the equation and check if it satisfies the equation.

The functions that satisfy the equation are the solutions.

Let's substitute each function into the given differential equation and check if it holds true.

a. y(x) = xe^(-7x):

Taking the first and second derivatives of y(x):

y'(x) = e^(-7x) - 7xe^(-7x)

y''(x) = -14e^(-7x) + 49xe^(-7x) - 7e^(-7x)

Substituting these derivatives into the differential equation:

(-14e^(-7x) + 49xe^(-7x) - 7e^(-7x)) + 14(e^(-7x) - 7xe^(-7x)) + 49(xe^(-7x)) = 0

Simplifying:

-14e^(-7x) + 49xe^(-7x) - 7e^(-7x) + 14e^(-7x) - 98xe^(-7x) + 49xe^(-7x) = 0

-7e^(-7x) = 0

The equation is not satisfied, so y(x) = xe^(-7x) is not a solution.

We can perform a similar analysis for the remaining functions:

b. y(x) = e^(7x): Not a solution.

c. y(x) = -7x: Not a solution.

d. y(x) = x^2e^(-7x): Not a solution.

e. y(x) = xe^(7x): Not a solution.

f. y(x) = e^(-7x): Solution.

g. y(x) = 0: Solution.

Therefore, the solutions of the given differential equation are y(x) = e^(-7x) and y(x) = 0.

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Answer:

true

Step-by-step explanation: