If the universe were completely empty except for one object- a solid sphere moving through space at a speed of 100km/s, then the object would be moving in a straight path. Since there are no other objects in space, there is no gravitational force to affect the path of the object.
Therefore, it will continue to move in a straight path, in accordance with Newton's first law of motion. The first law of motion states that an object will remain at rest or in uniform motion in a straight line unless acted upon by a net external force.
In this case, since there are no other objects or forces in the universe, the object will continue to move in a straight path at a constant velocity of 100 km/s. This path would not be altered by gravity or any other force.
Hence, the solid sphere moving through space at a speed of 100km/s would move in a straight line.
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You drive a bumper car into another bumper car whose driver has a much larger body mass than you do. Who experiences more of a jolt, you or the other driver?
Answer:
both drivers experience the same force. just with different "results"
Explanation:
Answer:
You do
Explanation:
Momentum is mass*velocity. So Newton's 3rd law equal and opposite reaction. Because you weigh less you will have more force act on you than the driver who weighs more.
A circuit with a 25 V battery a 7 Ω resistor and 5 Ω resistor in series. What is the current throughout the circuit?
First, let's calculate the total resistance in the circuit.
Since the two resistors are in series, the total resistance is the sum of each resistance:
\(R=7+5=12\)Now, to calculate the current, we can divide the voltage by the total resistance:
\(\begin{gathered} I=\frac{V}{R} \\ I=\frac{25}{12} \\ I=2.083\text{ A} \end{gathered}\)Therefore the current is 2.083 A.
The Current throughout the circuit is 2.083 A.
To calculate the current, we will use the formula:
I = V / R
Where,
I = current,
V = Voltage of Battery.
R = Total Resistance.
Now, we will use the given values in the question,
V = 25 V
R = 7Ω + 5Ω
Now, we have to find total Resistance,
Total Resistance = 7Ω + 5Ω
= 12Ω.
Now, we will calculate the current using the above formula,
Putting all the values,
I = 25 / 12
I = 2.083 A.
Therefore, the Current running throughout the circuit is 2.083 A.
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Juan draws a free-body diagram of an object that is in dynamic equilibrium moving to the left. A free body diagram with 4 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = Y. The second vector is pointing right, labeled F Subscript t Baseline = X. The third vector is pointing upward, labeled F Subscript N Baseline = 45 N. The fourth vector is pointing left, labeled F Subscript f Baseline = negative 30 N. The up and down vectors are the same length. The right and left vectors are the same length. Which labels correctly complete the diagram? X: 45 N Y: –45 N X: –45 N Y: 30 N X: 30 N Y: –45 N X: 30 N Y: –30 N
Answer:
see below
Explanation:
∑F at x = 0
-30 + Ft = 0
Ft = 30
∑F at y = 0
Fn + Fg = 0
45 - Fg = 0
Fg = - 45
The labels correctly complete the vector diagram is X = 30 and Y = -45.
What is vector diagram?
The velocity of such an item in motion could be represented in vector diagrams.
For vector X
It is known that, ∑F = 0 when x will be 0(x=0)
Hence,
\(F_{t}+F_{f} =0\\F_{t} +(-30) = 0\\F_{t} = 30\)
For vector Y
And, ∑F = 0 when y will be 0(y=0)
\(F_{n}+F_{g} =0\\F_{g} +(-45) = 0\\F_{g} = -45\)
Therefore, the value will be X = 30 and Y = -45.
The correct answer will be option (c).
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Express 48 m/s in terms of
1.km/h
2.m/min
3.km/s
4.km/minutes
48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.
To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.
1 km (kilometer) = 1000 meter
1 h (hour) = 3600 seconds
1 minutes = 60 seconds
To convert m/s into km/h,
48 m/s * 3600/1000 = 172.8 km/h
To convert m/s into m/min,
48 m/s * 60 = 2880 m/min
To convert m/s into km/s,
48 m/s ÷ 1000 = 0.048 km/s
To convert m/s into km/minutes,
48 m/s * 60 / 1000 = 2.88 km/min
Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.
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48 m/s is equivalent to 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
To express 48 m/s in different units of velocity:
km/h (kilometers per hour):
To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.
48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h
Therefore, 48 m/s is equivalent to 172.8 km/h.
m/min (meters per minute):
To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.
48 m/s * (60 m/min / 1 s) = 2880 m/min
Therefore, 48 m/s is equivalent to 2880 m/min.
km/s (kilometers per second):
Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.
48 m/s / 1000 = 0.048 km/s
Therefore, 48 m/s is equivalent to 0.048 km/s.
km/minute (kilometers per minute):
To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.
0.048 km/s * 60 = 2.88 km/minute
So, 48 m/s is equivalent to 2.88 km/minute.
Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
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show that the minimum period for a satellite in orbit around a spherical planet of uniform density is
The minimum period for a satellite in orbit around a spherical planet of uniform density can be derived by considering the gravitational force and the centripetal force acting on the satellite. By equating these forces, the minimum period can be determined.
The gravitational force acting on the satellite is given by the equation F_grav = (G * M * m) / r^2, where G is the gravitational constant, M is the mass of the planet, m is the mass of the satellite, and r is the distance between the center of the planet and the satellite.
The centripetal force required to keep the satellite in orbit is given by F_centripetal = (m * v^2) / r, where v is the velocity of the satellite.
By equating the gravitational force and the centripetal force, we have (G * M * m) / r^2 = (m * v^2) / r.
Simplifying the equation, we can solve for the velocity of the satellite, v, in terms of the gravitational constant, the mass of the planet, and the distance between the satellite and the planet.
The period of the satellite is given by the equation T = (2 * pi * r) / v, where T is the period and r is the distance between the center of the planet and the satellite.
By substituting the expression for v into the period equation, we can derive the minimum period for a satellite in orbit around a spherical planet of uniform density.
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Suppose a 60-kg boy and a 41-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration of the girl toward the boy is 3.0 m/s2, find the magnitude of the acceleration of the boy toward the girl.
A.
2.05 m/s2
B.
2 m/s2
C.
2.1 m/s2
Answer:
Approximately \(2.05\; {\rm m\cdot s^{-2}}\).
Explanation:
The net force on the girl would be:
\(\begin{aligned}m(\text{girl}) \, a(\text{girl}) &= 41\; {\rm kg} \times 3.0\; {\rm m\cdot s^{-2}} \\ &= 123.0\; {\rm N} \end{aligned}\).
Under the assumptions, the net force on this girl would be equal to the tension force in the rope. All other forces on the girl would be balanced.
In other words, the tension force that the rope exerted on the girl would be \(123.0\; {\rm N}\). The girl would exert a reaction force on the rope at the same magnitude (\(123.0\; {\rm N}\!\)) in the opposite direction. This force would translate to a \(123.0\; {\rm N}\!\!\) force on the boy towards the girl.
Under similar assumptions, the net force on the boy would also be \(123.0\; {\rm N}\). Since the mass of the boy is \(m(\text{boy}) = 60\; {\rm kg}\), the acceleration of the boy would be:
\(\begin{aligned}a(\text{boy}) &= \frac{(\text{net force})}{m(\text{boy})} \\ &= \frac{123.0\; {\rm N}}{60\; {\rm kg}} \\ &= 2.05\; {\rm m\cdot s^{-2}}\end{aligned}\).
a density of lead is just over 10 the power of 4 kg/m3 find the mass of a cylinderical rod of length 0.5m and radius 0.020m
The mass of a cylindrical rod is 6.29 kg.
What is density?The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition.
Density of lead = 10⁴ kg/m³.
Volume of a cylindrical rod of length 0.5m and radius 0.020m = πr²l
= (22/7)(0.020)²(0.5) m³
=6.29×10⁻⁴ m³.
Hence, mass of the cylindrical rod = volume × density
= 6.29×10⁻⁴ m³ × 10⁴ kg/m³.
= 6.29 kg.
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The human capacity for storing long-term memories is Group of answer choices A) essentially limitless. B) roughly equal to seven units of information. C) typically much greater in young children than in adults. D) greatly reduced after people reach the age of 65.
The human capacity for storing long-term memories is A) essentially limitless.
The human capacity for storing long-term memories is generally considered to be essentially limitless. Unlike short-term memory, which has limited capacity and duration, long-term memory has the potential to store an enormous amount of information for extended periods.
Research suggests that the brain has an incredible capacity to form and store memories, and this capacity is not fixed or finite. The exact capacity of long-term memory is difficult to quantify precisely, as it can vary greatly among individuals and is influenced by various factors such as age, cognitive abilities, and expertise in specific domains.
While it is true that short-term memory has a limited capacity, long-term memory has the ability to store a vast amount of information over a lifetime. Studies have shown that individuals can retain an extensive range of memories, including personal experiences, factual knowledge, and learned skills, without any predetermined upper limit on storage capacity.
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An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.
The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.
To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.
Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.
Using the formula, we can calculate the distance traveled as follows:
d = rt
d = 130 mph × 2.5 hours
Multiplying the rate (130 mph) by the time (2.5 hours) gives us:
d = 325 miles
Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.
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with the use of the hubble space telescope, scientists recently discovered a giant runaway star. it is 90 times larger than the sun and is very hot and blue-white in color. why does the sun appear to be brighter than this runaway star when viewed from earth?
The runaway star is farther away from Earth than the sun. the sun is closer to Earth than the runaway star if it seems brighter than the star and the star is 90 times bigger than the sun.
What is a runaway star?An exceptionally high proper motion, known as a runaway star, is a star that was supposed to have been ejected from a nearby binary system when its companion star exploded supernova. Beyond the Milky Way, these runaway stars seem to be widespread, especially in massive galaxy clusters.
Astronomers have found hundreds of billions of runaway stars in the Virgo cluster. The Milky Way's sun and all of its stars are revolving around its nucleus. Although there are some little local motions within this broader stream of stars, it is largely orderly. Compared to the sun, the runaway star is closer to Earth.
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. Why are the Jovian planets formed from materials different from the terrestrial planets?
a. Terrestrial planets were protected by the asteroid belt between Mars and Jupiter.
b. The composition of elements in a planet was a random process after the big bang.
c. When the solar system first formed, the heaviest elements sank toward the center of the nebulae and the lightest elements floated out.
d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
e. Only the terrestrial planets formed from planetesimals.
The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.
Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
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help please !!! determine the voltage
The voltage of given circuit is 5 volts.
What is Ohm's law?Explanation of Ohm's Law, the relationship between current, voltage and resistance. The amount of continuous current flowing through many materials is directly proportional to the potential difference or voltage between them. Therefore, if the voltage V (in volts) across a wire made of one of these materials is tripled, the current I (in amperes) is also tripled. The quotient V/I remains constant. The quotient V/I for a particular piece of material is called the resistance R and is measured in units called ohms. The resistance of materials that obey Ohm's law does not change over vast voltage and current ranges. Ohm's law can be expressed mathematically as V/I = R.
Given,
I = 0.5 Amp
As all the four resistors are connected in series, total resistance of the circuit is:
R = 1 + 2 + 3 + 4
R = 10 Ω
Using Ohm's law:
V = IR
V = 0.5 × 10
V = 5 volts
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A plank 3.8 m long and weighing 124 N has its left end resting on a block and the other end supported by a rope. The plank is in the horizontal position. If the greatest tension the rope can withstand is 414 N, how far from the block can a 63.2 kg girl walk out on the plank before the rope breaks
Using the concept of torque, the girl can walk out 1.52 m on the plank before the rope breaks.
The rotating force or moment of a force around a particular axis or pivot point is measured by torque. The tendency of a force to cause an object to spin along an axis is described as a vector quantity, torque.
We need to consider the torque exerted by the girl's weight and the tension in the rope.
The torque equation is given by:
τ = F × d where:τ is the torque, F is the force, and d is the distance from the pivot point.
In this case, the torque due to the girl's weight is balanced by the torque due to the tension in the rope.
The weight of the girl is
Weight = 63.2 kg * 9.8 = 619.36 N
Assuming the girl walks out on the plank at a distance of x m from the block.
The torque due to her weight is τ₁ = Weight × x
The maximum tension the rope can withstand is 414 N, so the torque due to the tension in the rope is: τ₂ = Tension * (3.8 - x)
To find the maximum distance the girl can walk out on the plank before the rope breaks, we need to set the torques equal to each other:
τ₂ = τ₁
Weight × x = Tension × (3.8 - x)
putting all the values in the above equation
619.36 × x = 414 × (3.8 - x)
x = 1.52 m
Therefore, The girl can walk out 1.52 m on the plank before the rope breaks.
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formulas in the solutions.
1. The Hulk leaps upward, pushing the Earth down (and the Earth
pushes him up). Which of Newton's Laws is the Hulk most closely
demonstrating? Why this law?
Type here
Answer:
1) The Newton's law the Hulk is most closely demonstrating is the Third Law of motion
Newton's third law of motion states that action and reaction are equal and opposite.
2) The reason why the Newton's Law the Hulk is most closely demonstrating is the Newton's Third Law of Motion is that according to Newton's Third Law of motion, forces exist in pairs, the action of the Hulk when he leaps upward by pushing against the the Earth (which can be assumed stationary in relation to the Hulk), is equal to the reaction of the Earth, which moves down slightly, away from its initial position.
However, due to the large mass of the Earth, compared to the mass of the Hulk, the downward motion of the Earth due to the reaction force (equal to the force with which the Hulk leaps) is negligibly small, such that the Earth can absorb the Hulk's leap force by reacting mainly locally, at the leap point by forming a crater, while the Earth in general, remains in the same place
Explanation:
A motor car is traveling at a steady speed of 30m/s. The engine provides the force needed to oppose the force of air resistance, 1600N
(Calculate the work done by the car each second against the force of air resistance)
If a motor car is traveling at a steady speed of 30m/s then the work done by the car each second against the force of air resistance is 48,000 J.
To calculate the work done by the car each second against the force of air resistance, we need to use the formula for work, which is:
work = force x distance
In this case, the distance is not given, but we know that the car is traveling at a steady speed of 30m/s. We can use this information to calculate the distance traveled in one second:
distance = speed x time
distance = 30m/s x 1s
distance = 30m
Now we can calculate the work done by the car against the force of air resistance:
work = force x distance
work = 1600N x 30m
work = 48,000 J
Therefore, the work done by the car each second against the force of air resistance is 48,000 J.
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in a two coil system the mutual inductance depends on
The mutual inductance (M) in a two-coil system depends on the number of turns in each coil (N₁ and N₂), the permeability of the medium between the coils (µ), and the geometry of the coils.
Mutual inductance is a measure of the ability of one coil to induce an electromotive force (emf) in the other coil when a current changes in one of them. It depends on several factors.
First, the number of turns in each coil plays a role. The greater the number of turns, the stronger the magnetic field produced by the coil, resulting in a higher mutual inductance.
Second, the permeability of the medium between the coils is important. The permeability determines how easily magnetic flux lines pass through the medium. A higher permeability leads to stronger coupling between the coils and, consequently, higher mutual inductance.
Lastly, the physical arrangement and geometry of the coils affect the mutual inductance. The proximity and alignment of the coils influence the amount of magnetic flux linking them, thereby impacting the mutual inductance.
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what would happen if the louisiana purchase did not double the United States?
Answer:
The Louisiana Purchase eventually doubled the size of the United States, greatly strengthened the country materially and strategically, provided a powerful impetus to westward expansion, and confirmed the doctrine of implied powers of the federal Constitution.
A sound wave has a frequency of 745 Hz in air and a wavelength of 0.55 m. What is the temperature of the air? Relate the speed of sound in air to temperature in units of Kelvin, but answer in units of Celsius. Assume the velocity of sound at 0 ◦C is 332 m/s. Answer in units of degC
The temperature of the air at the given speed of sound wave is 142.8 ⁰C.
Temperature of air
The temperature of the air at the given speed of sound and frequency is calculated as follows;
\(v = 332\sqrt{1 + \frac{T}{273} }\)
Velocity of the sound wavev = fλ
v = 745 x 0.55
v = 409.75 m/s
Now, solve for the temperature;
\(409.75 = 332 \sqrt{1 + \frac{T}{273} } \\\\1.234 = \sqrt{1 + \frac{T}{273} }\\\\1.234^2 = 1 + \frac{T}{273}\\\\0.523 = \frac{T}{273} \\\\T = 142.8 \ ^0C\)
Thus, the temperature of the air at the given speed of sound wave is 142.8 ⁰C.
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What simple machine did you find the most useful in everyday life? Explain why.
Simple machines are advantageous because they lessen labor requirements or enable people to undertake things that would otherwise be beyond their capacity.
What six simple machines can you recall?The airplane, wedge, screw, lever, pulley, and wheel-and-axle are the six most typical simple machines. They are made to change the direction or strength of the force (remember that work is equal to force times distance), which makes the task easier to complete.
Which basic machines are the most popular ones?Simple machines including the axle, wheel and axle, pulleys, inclined plane, screw, wedge, and lever are frequently utilized. Although simple machines may increase or decrease the forces which can be applied on them, they have no effect on the overall amount of work required to complete the activity.
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express the first law of thermodynamics for the following processes: a. isothermal b. adiabatic c. isovolumetric
The first law of thermodynamics states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W): ΔU = Q - W.
a. Isothermal process: In an isothermal process, the temperature remains constant, so there is no change in internal energy (ΔU = 0). Therefore, the first law of thermodynamics for an isothermal process is expressed as:
Q = W
b. Adiabatic process: In an adiabatic process, no heat is exchanged between the system and its surroundings (Q = 0). Therefore, the first law of thermodynamics for an adiabatic process is expressed as:
ΔU = -W
c. Isovolumetric process: In an isovolumetric process, the volume remains constant, so no work is done by the system (W = 0). Therefore, the first law of thermodynamics for an isovolumetric process is expressed as:
ΔU = Q
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Which quantity is a vector quantity?A. displacementB. distanceC. massD. temperatureE. volume
In order to be a vector quantity, the quantity needs to have a direction, besides its magnitude.
For example, temperature has no direction, only magnitude, but velocity has direction and magnitude.
From these options, the only one that is a vector quantity is displacement, therefore the correct option is A.
Khaled said the North star is special because it appears all over the world and its changes position.
a. false
b.true
A hemispherical tank is full of oil (density = 50 pc). It has a diameter of 10 ft. Find the work done in Ib-ft in pumping all the liquid out of the tank
The work done in pumping all the liquid out of the tank is 2500π lb-ft.
Work done calculationThe potential energy of an object is given by the formula:
PE = mgh
Given:
Density of oil = 50 lb/ft^3
Diameter of the tank = 10 ft ( r = 5 ft)
To calculate the work done, we need to find the mass of the oil and the height it is lifted. Let's start by finding the mass:
Volume of oil in the tank:
The volume of a hemisphere = (2/3) * π * (r^3)
Volume = (2/3) * π * (5^3) = (2/3) * π * 125 = 250π/3 ft^3
Mass of the oil:
Mass = Volume * Density = (250π/3) * 50 lb
Now, we need to find the height of the tank. For a hemisphere, the height is equal to the radius (5 ft).
Finally, we can calculate the work done:
Work = PE = mgh = (250π/3) * 50 lb * 5 ft
Work = (250π/3) * 50 * 5 lb-ft
= 2500π lb-ft
So, the work done in pumping all the liquid out of the tank is approximately 2500π lb-ft.
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A baseball player dives head-first into
second base and slows down while sliding on the infield dirt.
Of the forces listed, identify which act upon the player.
1.Normal
2.Gravity
3.Applied
4.Friction
5.Tension
6. Air Resistance
Answer:
Explanation:
Discussion
The ones that are certain are
Normal GravityFrictionIf you have a normal, and the player slides into 2nd, and stops (which he must before he is tagged), then there must be friction involved. There must be gravity, or he would keep going up.
I don't think there is tension. There might be some Air Resistance, but that force is very tiny. Don't be surprised if you answer includes Air Resistance, but I won't try it to begin with.
burns that extend through the entire outer layer and into the inner skin layer are considered:
Burns that extend through the entire outer layer of the skin, known as the epidermis, and into the inner skin layer, known as the dermis, are considered second-degree burns.
These burns are more serious than first-degree burns, which only affect the outer layer of the skin, and can result in blistering, swelling, and pain. Second-degree burns can also cause damage to hair follicles, sweat glands, and nerve endings, which can lead to scarring and long-term changes in skin texture and color. Treatment for second-degree burns may include cleaning the affected area, applying topical ointments, and in some cases, skin grafting. It is important to seek medical attention for any burn that extends beyond the outer layer of the skin, as these burns can have serious complications if left untreated.
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Ali kicks a soccer ball upward at 45° angle
with an initial speed of 32 m/s. What
expression should Ahmed use to calculate
the magnitude of the ball's initial velocity
the horizontal direction?
Select one:
a. 32 sin(45°) m/s
b. 32 cos(45°) m/s
c. 32 tan(45°) m/s
d. 45 m/s
Answer:
the answer is 32sin(45°)m/s
Si: A + B = C – D es una ecuación física donde A, B, C y D son magnitudes físicas entonces [ A ] = [ B ] = [ C ] = [ D ]
Answer:
\([A] = [B] = [C] = [D]\) por el Principio de Homogeneidad Dimensional y el uso de operaciones de adición y sustracción.
Explanation:
Por el Principio de Homogeneidad Dimensional, A, B, C y D deben tener las mismas magnitudes físicas para la realización de operaciones de adición y sustracción. Es decir:
\([A] + [B] = [C] - [D]\), donde \([A] = [B] = [C] = [D]\)
The kinetic energy of an object can sometimes be greater than a potential energy a originally possessed, true or false?
Answer:
true
Explanation:
Energy stored in the nuclei of atoms can be used to generate electricity. ... Most of the energy of food is converted to heat.
what do you mean by supplementary quantities and its unit?
$ \large\boxed{ \sf \red{More ~Info :}}$
The units of supplementary quantities are dimensionless units.
\( \\ \)
There is an elephant shaped weather vane at the top of a corn dryer tower that is 45 m high. If the weather vane weighs 190 N, what is the Potential Energy that the weather vane has?Potential Energy = Weight x HeightWeight = Potential Energy / HeightHeight = Potential Energy / WeightWeight = Mass x 10Mass = Weight / 10
Given,
The weight, W = 190 N
The height, H = 45 m
The potential energy is calculated by the formula,
\(PE=\text{Weight}\times Height\)Calculate the potential energy by substituting the given values.
\(\begin{gathered} PE=190\text{ N}\times45\text{ m} \\ PE=8,550\text{ J} \end{gathered}\)Thus, the potential energy is 8,550 Joules.