Technician A says that all battery connections should be inspected for corrosion. Technician B says that battery cables should be checked for corrosion and replaced as needed. Who is right

Some of the things that can be done in the above scenario regarding issues with the LAN involving high broadcast frames are:

A network analyzer, also known as a network protocol analyzer or packet analyzer, is a software program, dedicated appliance, or feature set inside a network component that is used to diagnose network performance or to improve security within a corporate network.

A network analyzer is a tool for monitoring and analyzing network traffic in real time. Using a network analyzer, you may locate the source of the broadcast traffic and take appropriate action.

In the preceding example, your network architecture may not be optimum for the amount of switches and devices you have. To lower the amount of broadcast frames, you may need to install extra switches or reorganize your present switches.

Learn more about Network Analyzer:
https://brainly.com/question/29833406?
#SPJ1

In the life cycle way of thinking, maintenance and repair are treated differently from replacement and refurbishment in the following ways:Maintenance and repair are activities performed on existing equipment, structures, or systems to keep them in good working order.

They are done to prevent damage to the equipment and maintain the current performance level. These tasks are normally less expensive than replacement or refurbishment and they can extend the life of the asset. Maintenance and repair are considered to be an ongoing process that should be performed at regular intervals or when necessary.

Replacement, on the other hand, involves taking out an old or broken equipment and replacing it with a new one. Replacement typically occurs when an asset has reached the end of its useful life, is no longer repairable or maintainable, or when the cost of repairs is more expensive than the cost of replacement.

Refurbishment, on the other hand, involves restoring an asset to a like-new condition. It involves replacing parts and repairing damage to make an asset functional again. Refurbishment is typically less expensive than replacement and can extend the life of an asset beyond its original design life.

Refurbishment is usually done when the asset has some useful life remaining and when the cost of refurbishment is less than the cost of replacement.

For more such questions refurbishment,Click on

https://brainly.com/question/11222113

#SPJ8

For a dislocation density of 10^4 mm^-2, the chain would extend 1.24 miles. For a density of 10^10 mm^-2, the chain would extend 124,274 miles.

1. Calculate total dislocations: Dislocation density x Volume = 10^4 mm^-2 x 1000 mm^3 = 10^7 dislocations
2. Estimate the length of one dislocation: Consider 1 mm as an average dislocation length
3. Calculate total length of dislocations: 10^7 dislocations x 1 mm/dislocation = 10^7 mm
4. Convert length to miles: 10^7 mm x (1 m/1000 mm) x (1 km/1000 m) x (1 mile/1.609 km) ≈ 1.24 miles
5. Repeat steps 1-4 for a density of 10^10 mm^-2: 10^10 mm^-2 x 1000 mm^3 = 10^13 dislocations, total length ≈ 124,274 miles.

Therefore the chain would extend 1.24 miles.

To know more about dislocation density related problems visit:

brainly.com/question/15173600

#SPJ11

Answer:

Biochemistry

Explanation:

Hope this helps :)

Answer:

Biochemistry

Have an amazing day!

(a) The net flux of the toxicant to the sediment is 918 grams per year.

(b) A new load of 0.053 grams per year is necessary for the dissolved toxicant concentration to equal 0.5 micrograms per liter in the water column.

To solve this problem, we can use the following mass balance equation:

Mass in - Mass out + Mass generated or consumed = Accumulation

(a) We can start by calculating the total mass of the toxicant in the lake:

Mass in = loading rate = 106 g/yr

Mass out = effluent rate = 0 (assuming the lake has no outlet)

Next, we can calculate the mass of the toxicant in the water column and sediment separately:

Mass in water column = volume of water x water column concentration

= surface area x depth x solids concentration x partition coefficient

= 108 m² x 10 m x 10 mg/L x 10⁴ L/kg

= 1.08 kg

Mass in sediment = surface area x sediment concentration x depth

= 108 m² x 15 µg/g x 10 m x 10⁻⁶ kg/µg

= 0.162 kg

The net flux of the toxicant to the sediment can be calculated as:

Mass in water column - Mass in sediment = 1.08 kg - 0.162 kg = 0.918 kg = 918 g

Therefore, the net flux in grams/year of the toxicant to the sediment is 918 g/year.

(b) We can start by using the same mass balance equation, but this time solving for the loading rate:

Mass in - Mass out + Mass generated or consumed = Accumulation

Assuming the accumulation term is still zero, we can rearrange the equation to solve for the loading rate:

Loading rate = (Mass out - Mass generated or consumed) / Residence time

We can assume that the mass out is still zero, so we can simplify the equation further:

Loading rate = -Mass generated or consumed / Residence time

We want to find the new loading rate required to achieve a dissolved toxicant concentration of 0.5 µg/L in the water column. We can start by calculating the current concentration in the water column:

Dissolved toxicant concentration = Mass in water column / (volume of water x density of water)

= 1.08 kg / (108 m² x 10 m x 1000 kg/m³)

= 0.001 L/kg = 1 mg/L

We need to reduce this concentration to 0.5 µg/L, which is a 2000-fold reduction. Therefore, the new loading rate required to achieve this concentration can be calculated as:

New loading rate = Current loading rate / 2000

= 106 g/yr / 2000

= 0.053 g/yr

Therefore, a new load of 0.053 g/yr is necessary for the dissolved toxicant concentration to equal 0.5 µg/L in the water column.

To knowmore about net flux , visit: https://brainly.com/question/30652908

#SPJ4

a. The bandwidth occupied by a resource block depends on the specific cellular network technology and configuration. b. The bandwidth occupied by a resource element is typically a fraction of the resource block's bandwidth and varies based on the modulation and coding scheme employed.

a. ) The bandwidth occupied by a resource block varies depending on the cellular network technology being used. In Long Term Evolution (LTE) networks, a resource block typically occupies 180 kHz of bandwidth. However, it's important to note that different cellular network standards, such as 5G, may use different bandwidth allocations for resource blocks. Therefore, the specific bandwidth occupied by a resource block can vary based on the network configuration and deployment. b.) A resource block consists of multiple resource elements, and each resource element represents a smaller unit of bandwidth within the resource block. The bandwidth occupied by a resource element depends on the modulation and coding scheme (MCS) being used. Higher MCS values typically result in more bits being transmitted per resource element, effectively occupying a larger bandwidth. Conversely, lower MCS values result in fewer bits being transmitted per resource element, occupying a smaller bandwidth. The exact bandwidth occupied by a resource element can be calculated by dividing the overall bandwidth of the resource block by the number of resource elements it contains. In summary, the bandwidth occupied by a resource block depends on the specific cellular network technology, while the bandwidth occupied by a resource element varies based on the modulation and coding scheme employed within that resource block. The specific values for these bandwidth allocations may differ depending on the network technology and deployment scenario.

learn more about bandwidth here:

https://brainly.com/question/30337864

#SPJ11

According to the question, the stress developed in the rod and the tube is 64.68 N/mm³and the extension of the rod is 1.294 mm.

Change of any kind that strains a person physically, mentally, or emotionally is regarded as stressful. Stress is the body's response to anything that requires concentration or activity. Everyone goes through periods of stress.

Diameter of rod = 25 mm

Length of rod = 400 mm

External diameter of tube = 35 mm

Inside diameter of tube = 30 mm

E for steel = 200GN/m²

E for copper = 100GN/m²

A₁ = π/4 × (25)²

A₂ = 490.87 mm²

A₂ = π/4 (35² - 30²)

A₂ = 255.25 mm²

for equilibrium -

P₁A₁ + P₂A₂

= P

= 40 × 10³

so,

P₁²/E₁ = P₂²/E₂

P₁ = P₂ × (200/100)

P₁ = 2P₂

2P₂A₂ + P₂A₂ = 40 × 10³

P₂ = 32.34 N/mm³

P₁ = 2P₂ = 64.68 N/mm³

P₁ = 64.68 N/mm³

extension of rod = (64.88 × 4000) / (2×10³)

extension of rod = 1.294 mm

To learn more about stress visit:

https://brainly.com/question/12910262

#SPJ1

An airplane flying across the sky experience drag force determined by the factors including the speed of flight, coefficient of skin friction and the reference surface area

The boundary layer thickness is approximately 0.233 cm

The total skin friction drag, is approximately 265 N

Reason:

First part:

Given parameters are;

Chord length, L = 3 m

Velocity of the plane, V = 200 m/s

Density of the air, ρ = 1.225 kg/m³

Viscosity of the air, μ = 1.81 × 10⁻⁵ kg/(m·s)

The Reynolds number is given as follows;

\(R_{eL} = \dfrac{\rho \times V \times L}{\mu}\)

Therefore;

\(R_{eL} = \dfrac{1.255 \times 200 \times 3}{1.81 \times 10^{-5}} = 4.16022099448 \times 10^7 \approx 4.16 \times 10^7\)

Boundary layer thickness, \(\delta_L\), for laminar flow, is given as follows;

\(\dfrac{ \delta_L }{L}=\dfrac{5.0}{\sqrt{R_{eL} } }\)

\({ \delta_L }=\dfrac{5.0 \times L}{\sqrt{R_{eL} } }\)

Which gives;

\({ \delta_L }=\dfrac{5.0 \times 3}{\sqrt{4.16 \times 10^{7}} } \approx 2.33 \times 10^{-3 }\)

The boundary layer thickness, \(\delta_L\) ≈ 2.33 × 10⁻³ m = 0.233 cm

Second Part

The total skin friction is given as follows;

\(Dynamic \ pressure, q = \dfrac{1}{2} \cdot \rho \cdot V^2\)

Therefore;

\(q = \dfrac{1}{2} \times 1.225 \times 200^2 = 24,500\)

The dynamic pressure, q = 24,500 N/m²

Skin friction drag coefficient, \(C_D\), is given as follows;

\(C_D = \dfrac{1.328}{\sqrt{R_{eL} } }\)

Therefore;

\(C_D = \dfrac{1.328}{\sqrt{4.16 \times 10^7 } } \approx 2.06 \times 10^{-4}\)

Skin friction drag, \(D_f\), is given as follows;

\(D_f\) = q × \(C_D\) × A

Where;

A = The reference area

∴ \(D_f\) = 24,500 N/m² × 2.06 × 10⁻⁴ × 3 m × 17.5 m = 264.9675 N ≈ 265 N

The total skin friction drag, \(D_f\) ≈ 265 N

Learn more here:

https://brainly.com/question/12977939

Answer:

buter uwu heheheheh joke

The flow rate through the bend may be calculated using these equations to be 7.01 ft3/s, and the y-direction anchoring force needed to keep the bend in place is 674 pounds.

General solutions to the issue.

Step 1: Calculate the flow rate through the bend using Bernoulli's equation.

Step 2: Calculate the y-direction anchoring force necessary to hold the bend in place using the momentum equation.

Step 3: Hold the bend in place using the x-direction and y-direction anchoring forces.

The common equations that can be applied are:

Bernoulli's equation: P1 + 0.5 rhov 1 + rhogh 1 = P2 + 0.5 rhov 2 + rhogh 2 where P1 = pressure at inlet, v1 = velocity at inlet, h1 = height at inlet, P2 = pressure at outlet, v2 = velocity at outlet, h2 = height at outlet, rho = fluid density, and g = gas constant.

the speeding up caused by gravity.

FAY is the y-direction anchoring force, Q is the flow rate, v1 is the velocity at the inlet, and v2 is the velocity at the outlet. The momentum equation is FAY = rhoQ(v2 - v1).

It should be noted that the flow rate through the bend is calculated independently of the x-direction anchoring force.

The flow rate through the bend may be calculated using these equations to be 7.01 ft3/s, and the y-direction anchoring force needed to keep the bend in place is 674 pounds.

Learn more about y-direction anchoring force here:

https://brainly.com/question/31159713

#SPJ4

The flow rate through the bend is 7.01 ft^3/s, and the y-direction anchoring force, FAY required to hold the bend in place is 674 lbs. in.

To solve this problem, we can use the Bernoulli equation to relate the pressure and velocity of the water at different points along the bend. We can then use the conservation of mass equation to find the flow rate through the bend.

Using the given pressure gauge reading of 10 psi, we can determine the velocity of the water at point A using the Bernoulli equation. Solving for the velocity yields 34.77 ft/s. Using this velocity and the given geometry of the bend, we can determine the area of the flow at point A as 0.2019 ft^2.

Using the conservation of mass equation, we can relate the flow rate at point A to the flow rate at point B. Solving for the flow rate at point B yields 7.01 ft^3/s.

Find out more about Bernoulli's equation

brainly.com/question/13996213

#SPJ4

The work done on the gas during this process if the final pressure is 456 kPa is; -82.8 kJ

We are given;

The initial pressure; P₁ = 96 kPa

Final Pressure; P₂ = 456 kPa

The gas is compressed according to;

p = aV + b

where;

a = -1200 kPa/m³

b = 600 kPa

Thus, at initial pressure P₁ = 96 kPa;

96 = -1200V₁ + 600

1200V₁ = 600 - 95

1200V₁ = 505

V₁ = 505/1200

V₁ = 0.42 m³

At Final Pressure P₂ = 456 kPa;

456 = -1200V₂ + 600

1200V₂ = 600 - 456

1200V₂ = 144

V₂ = 144/1200

V₂ = 0.12 m³

Formula for the workdone during the process is;

W_out = ¹/₂(P₁ + P₂)(V₂ - V₁)

W_out = ¹/₂(96 + 456)(0.12 - 0.42)

W_out = -82.8 kJ

Read more about workdone in thermodynamics at; https://brainly.com/question/12641937

Drilling mud does all of the following EXCEPT keeps oil underground.

Drilling mud is a specialized fluid used in drilling operations to facilitate the drilling process and maintain the stability of the wellbore.

One of the functions of drilling mud is to cool the drill bit by circulating it through the bit and carrying away heat generated during drilling. This helps prevent the bit from overheating and prolongs its lifespan.

Drilling mud acts as a barrier, preventing the gas from entering the wellbore and causing blowouts. It helps control the pressure and allows for safe drilling operations.

Drilling mud has several important functions in drilling operations, including cooling the bit, allowing gas to escape, and flushing cuttings out of the hole. However, it is not intended to keep oil underground.

Learn more about drilling  https://brainly.com/question/29219391

#SPJ1

(1) The partial pressure of dry air is 89.9 kPa. (2) The specific humidity of the air is 0.0115 kg H20/kg dry air. (3) The enthalpy per unit mass of dry air is 45.4 kJ/kg dry air.

To determine the partial pressure of dry air, we need to calculate the vapor pressure of water at 18 °C, which is 2.88 kPa. Then, we can calculate the partial pressure of dry air by subtracting the vapor pressure from the total pressure:

Partial pressure of dry air = Total pressure - Vapor pressure

Partial pressure of dry air = 101 kPa - 2.88 kPa

Partial pressure of dry air = 89.9 kPa

To find the specific humidity of the air, we need to use the relative humidity and the vapor pressure. Specific humidity is the ratio of the mass of water vapor to the mass of dry air:

Specific humidity = Mass of water vapor / Mass of dry air

Specific humidity = (Relative humidity * Vapor pressure) / (Total pressure - Vapor pressure)

Specific humidity = (0.89 * 2.88 kPa) / (101 kPa - 2.88 kPa)

Specific humidity = 0.0115 kg H20/kg dry air

The enthalpy per unit mass of dry air can be determined using psychrometric properties and tables. At 18 °C, the enthalpy of dry air is 45.4 kJ/kg dry air.

Therefore, the partial pressure of dry air is 89.9 kPa, the specific humidity of the air is 0.0115 kg H20/kg dry air, and the enthalpy per unit mass of dry air is 45.4 kJ/kg dry air.

Learn more about partial pressure here :-

https://brainly.com/question/30114830

#SPJ11

Answer:

-Computer going blank .

-Mouse pointer freezing.

-Keyboard getting stuck.

Explanation:

Any problems with the computer related to its hardware will consist of issues directly related to the physical components of the PC or computer. So any problem involving the physical component of the computer, then it can be termed as a hardware problem.

Based on the problems given in the option, the hardware issues will be problems with the computer, mouse, and keyboard. These form the physical parts of the computer so they will be a hardware issue.

Thus, the correct answers are the third, fourth, and fifth options.

Answer:

c d e

Explanation:

Answer:

This is an asynchrnous 3-bit counter. Just note that this design is different and works differently than its synchronous counterpart. It's an easier design than its synchronous counterpart, and is not as reliable because it has delays.

The protocols used to auto negotiate trunk formation between two switches are Cisco's Dynamic Trunking Protocol (DTP) and the industry-standard IEEE 802.1Q protocol.

Dynamic Trunking Protocol (DTP) is a proprietary protocol developed by Cisco. It enables switches to automatically negotiate and establish trunk links between them. DTP allows switches to exchange information about their trunking capabilities, such as whether they support trunking or not, and if so, what type of trunking protocol to use.

IEEE 802.1Q is an industry-standard protocol used for trunking in Ethernet networks. It defines how VLAN information is carried within Ethernet frames, allowing switches to establish trunk links and transport multiple VLANs over a single physical connection. With 802.1Q, switches can negotiate and agree upon the trunking configuration, including the VLAN tags and the allowed VLANs on the trunk.

Both DTP and IEEE 802.1Q provide mechanisms for switches to automatically negotiate trunk formation, simplifying the configuration process and ensuring consistency in VLAN assignments across the network.

However, it's important to note that DTP only works between Cisco switches, while IEEE 802.1Q is an open standard that can be used across different vendors' switches.

In conclusion, the protocols used to auto negotiate trunk formation between two switches are Cisco's Dynamic Trunking Protocol (DTP) and the industry-standard IEEE 802.1Q protocol. DTP is specific to Cisco switches, while 802.1Q is an open standard that works across different vendor switches. These protocols enable switches to automatically establish trunk links and transport multiple VLANs over a single physical connection.

To know more about Protocol , visit:

brainly.com/question/13014114

#SPJ11

The worst way to show self-management is to ask your boss to set all your goals. Self-management is the act of managing one's own behavior, time, and resources effectively to reach a goal.

It is the ability to organize oneself and control impulses, emotions, and actions. It is a skill that requires discipline, self-awareness, and commitment. There are different ways to show self-management, but some ways are better than others.Asking your boss to set all your goals is the worst way to show self-management because it shows a lack of initiative and responsibility. It suggests that you are not willing to take ownership of your career or invest in your development. It also implies that you are not confident in your ability to set and achieve your own goals. By asking your boss to set all your goals, you are giving away your power and agency, and relying on someone else to define your success and progress. This approach can be limiting, disempowering, and demotivating.There are better ways to show self-management, such as planting a time to evaluate your progress, setting your own career goals, and asking for feedback on your progress. Planting a time to evaluate your progress is a proactive way to assess your performance and identify areas for improvement. Setting your own career goals demonstrates ambition, vision, and ownership of your future. Asking for feedback on your progress shows a willingness to learn, grow, and adapt to new challenges. These approaches are more empowering, engaging, and effective than relying on your boss to set all your goals.

To know more about self-management visit :

https://brainly.com/question/4574856

#SPJ11

Answer:

I think it is false!

Explanation:

Answer: I think it's true

Explanation:

Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.

The watercraft in the crossing are given with the responsibility to the starboard side to give the way and avoid collision.

The crossing rules are given as the safety rules that are mediated in order to avoid the collision accidents when the two vehicles are crossing the path.

In the sea, the rules are given with the watercraft at the starboard side or the giveaway side to make the way to the other watercraft and avoid collision.

Learn more about crossing rules, here:

https://brainly.com/question/4773184

#SPJ1

Answer:

The answer is below

Explanation:

The mining auxiliary operations in underground mining involve various activities that are important for a successful mining operation particularly in the areas of productive operating conditions.

The activities involved in the auxiliary operations in underground mining include the following: ventilation, haulage, drainage, power supply, lighting, delivery of compressed air, water, supplies to the working sections, and communications.

1. BRMLtoolbox Constructed Junction Tree:To construct the junction tree for the given distribution in the BRMLtoolbox, we use the following code:load diseaseNet.matp1=1.

The learned DAG is converted to the PDAG, and structure and data are provided to learn its structure with PC algorithm. Using the "jtree" function, a junction tree is constructed. Lastly, marginals of symptoms are computed using the "marginal" function, using the junction tree and symptoms 21-60 as input.2.

Efficient way to compute marginals p(si=1):Instead of computing all the marginals using the junction tree formalism, a faster and more efficient way to compute the marginals p(si=1) is to use the forward-backward algorithm. This algorithm is based on dynamic programming, and is used to compute all the marginals of a Hidden

evidence);fori=1:20belief{i}=marginal_nodes(engine, i);endThe above code is used to calculate the marginals of symptoms using the forward-backward algorithm.

To know more about construct visit:

https://brainly.com/question/791518

#SPJ11

Answer:

Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.

Explanation:

Answer:

cpct gvxjjxjhdfjokjdzfjiyddzzsjhxf

Answer:

Along the zero to measure an object on a ruler

Answer:

Coiled tubing is often used to carry out operations similar to wire lining.

Answer:

D. International distribution system

Identify the components: Determine the different elements or variables that make up the system. For example, if the system consists of masses, springs, and dampers, you would identify the masses, spring constants, damping coefficients, and displacements as the key components.

Define the relationships: Determine how the components interact with each other. This involves identifying the forces or torques acting on each component and understanding how they affect the system. For example, in a mass-spring-damper system, you would consider the forces exerted by the springs and the dampers on the masses.Apply Newton's laws or relevant principles: Use the fundamental principles governing the components to derive the equations of motion. For example, Newton's second law (F = ma) is commonly used to derive the equations of motion for mechanical systems.

Write the equations: Express the relationships obtained in  as differential equations. Depending on the complexity of the system, you may end up with a set of ordinary differential equations (ODEs) or partial differential equations (PDEs).It's important to note that the specific steps and equations involved in deriving the differential equations vary depending on the nature of the system.

To know more about Identify the components visit:

https://brainly.com/question/27866541

#SPJ11