technician a says that you should always use thick leather gloves when attempting to trace a blind leak in hydraulic hose. technician b says that hydraulic pinhole injection can take place in flesh without the knowledge of the injured person. who is correct?

The energy production of a 10m/s wind turbine is  produces more during the night than during the day.

Energy production = k x V³ (where V is the wind speed, k is the proportionality constant)

Since the energy production is proportional to the cube of the wind speed, the energy produced is directly proportional to the wind speed cubed.

Thus, the energy produced by a 10m/s wind turbine is proportional to (10m/s)³ = 1000m³/s³.

On average, the wind speeds at night are higher than during the day.

Hence, a wind turbine produces more energy during the night than during the day. Therefore, the energy produced by a 10m/s wind turbine will be more during the night than during the day.

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Answer:

ok the answer is 0

Explanation:

Answer:

An architect will help you determine exactly what you need and come up with inventive ideas to solve even the most complex design problems. Think of us as professional 3D problem solvers! An architect can and should lift your project out of the ordinary.

Explanation:

What are the 3 main functions of an architect?

Design: Architects must design, plan, and develop concepts to create construction plans and technical documents. These are based on client requirements and ideas. Research: Architects must learn about the different building codes, safety regulations, construction innovations and city laws that affect their designs

What are the 7 types of architecture?

There are several main types of architects who focus on different types of structures and designs.

...

Commercial Architects

Office buildings / skyscrapers.

Hotels.

Bridges.

Schools.

Museums.

Government buildings.

Multi-unit residential buildings.

Pretty much any type of building that's not a residential home.

Answer:

Explanation:

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The credit building options that I think  is the easiest method that you can see yourself doing is Secured credit cards.

Secured credit cards are known to be a type of card that are said to be backed by a specific refundable security deposit.

This kind of deposit is known to limit or lower the lender's risk and thus makes it better for people who do not have credit or when they do not  qualify for that type of credit. This credit option is easier to get when compared to unsecured cards, as it does not need a lot of requirement.

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Answer:

R = 20Ω

L = 0.1 H

C = 1 × 10⁻⁵ F

Explanation:

Given the data in the question;

Vs = 10∠30°V   { peak value }

V"s\(_{rms\) = 10/√2 ∠30° V

resonance freq w₀ = 10³ rad/s

Average Power at resonance Power\(_{avg\)  = 2.5 W

Q = 5

values of R, L, and C = ?

We know that;

Power\(_{avg\) = |V"s\(_{rms\)|² / R

{ resonance circuit is purely resistive }

we substitute

2.5 = (10/√2)² × 1/R

2.5 = 50 × 1/R

R = 50 / 2.5

R = 20Ω

We also know that;

Q = w₀L / R

we substitute

5 = ( 10³ × L ) / 20

5 × 20 = 10³ × L

100 = 10³ × L

L = 100 / 10³

L = 0.1 H

Also;

w₀ = 1 / √LC

square both side

w₀² = 1 / LC

w₀²LC = 1

C = 1 / w₀²L

we substitute

C = 1 / [ (10³)² × 0.1 ]

C = 1 / [ 1000000 × 0.1 ]

C = 1 / [ 100000 ]

C = 0.00001 ≈ 1 × 10⁻⁵ F

Therefore;

R = 20Ω

L = 0.1 H

C = 1 × 10⁻⁵ F

Answer:

electric circuit, a conduit for moving current. A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.

network in series

circuit parallel

There are various categories in which to place electric circuits. Only one direction of current can flow through a direct-current circuit. As in most residential circuits, an alternating-current circuit transports current that pulses back and forth repeatedly every second. (To learn more about direct and alternating current circuits, visit electricity: Direct electric

Explanation:

is this good? please mark brainliest

3837 kip-ft / 7560 kip-ft = 1.97 for Mn / Mx. Member AB is regarded as suitable for LRFD because this ratio is bigger than 1.0.

The force that will cause a member to yield is typically between 1.3 and 1.4 times the member strength (the maximum load that the member will support). These load factors, whose size varies depending on the type of load, are used in the load combination formulae.

Kx = Effective length factor for x-axis bending

= Lx / rx

\(Lx = AC = √(13^2 + 25^2) = 28.8 ft\)

\(rx = √(Ix / A)\)

\(A = 28.5 in^2\)

\(Ix = 1630 in^4\)

\(rx = √(1630 / 28.5) = 9.07 in\)

Now we can calculate Kx:

Kx = Lx / rx = (28.8 ft) / (9.07 in / 12 in/ft) = 11.5

\(Mx = (1.2D + 1.6L) * (Lx / Kx)\)

\(= (1.2 * 204 kips + 1.6 * 408 kips) * (28.8 ft / 11.5)\)

= 3837 kip-ft

\(Mn = Fy * Zx\)

\(Zx = 168 in^3\)

\(Mn = Fy * Zx = 50 ksi * 168 in^3 = 8400 kip-ft\)

The LRFD design strength of member AB is then:

\(φMn = 0.9 * Mn = 0.9 * 8400 kip-ft = 7560 kip-ft\)

\(φMn / Mx = 7560 kip-ft / 3837 kip-ft = 1.97\)

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The LP model to determine how much of mixes 1 and 2 the company should produce will be:

Maximize : 1.0905X1 + 1.25X2

Subject to -

0.67X1 + 0.6X2 ≤ 30000

0.33X1 + 0.25X2 ≤ 12000

0.15X2 ≤ 10000

X1, X2 ≥ 0

Let's Assume, X1 pound mix 1 to be produced.

X2 pound mix 2 to be produced.

Therefore, total peanuts will be used = 0.67X1 + 0.6X2

Total cashew will be used = 0.33X1 + 0.25X2

Total almond will be used = 0.15X2

Total cost of peanuts = 0.35(0.67X1 + 0.6X2)

= 0.2345X1 + 0.21X2

Total cost of cashew =

0.5(0.33X1 + 0.25X2)

= 0.165X1 + 0.125X2

Total cost of almond =

0.7 x 0.15X2

= 0.105X2

Therefore, total cost =

0.3995X1 + 0.44X2

Selling price of mix 1 = $1.49

Selling price of mix 2 = $1.69

Therefore, total revenue =  1.49X1 + 1.69X2

Hence, total profit =

(1.49X1 + 1.69X2) - (0.3995X1 + 0.44X2)

1.0905X1 + 1.25X2

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Containers transporting more than 1000 pounds of non-bulk packages are required to be placarded on all four sides of the vehicle.

Containers transporting more than 1000 pounds of non-bulk packages are required to be placarded on all four sides of the vehicle.

Placards are large, diamond-shaped signs that communicate the type of hazardous material being transported.

They are used to alert emergency responders, other drivers, and the public about the potential hazards associated with the cargo. Placarding helps ensure safety and proper handling of the materials during transportation.

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Answer:

  d. 2.3 ohms (5.3 amperes)

Explanation:

The calculator's 1/x key makes it convenient to calculate parallel resistance.

  Req = 1/(1/4 +1/8 +1/16) = 1/(7/16) = 16/7 ≈ 2.3 ohms

This corresponds to answer choice D.

__

Additional comment

This problem statement does not tell the applied voltage. The answer choices suggest that it is 12 V. If so, the current is 12/(16/7) = 21/4 = 5.25 amperes.

An environmental hazard is a substance, state or event which has the potential to threaten the surrounding natural environment and/or adversely affect human's health. This term incorporates topics like pollution, natural disasters and human-made hazards. Health studies investigate the human health effects of exposure to environmental hazards ranging from chemical pollutants to natural, technological or terrorist disasters. The environment in which we live can be considered as having three fundamental sets of components, physical, chemical, biological. Associations between an exposure and an adverse health effect do not, on their own, prove that the former is the cause of the latter. Many other non-causal associations could explain the findings. Physical hazards involve environmental hazards that can cause harm with or without contact. Examples are earthquakes, electromagnetic fields, floods, light pollution, noise pollution, vibration, x-rays etc. Radioactivity is associated with an exposure dependent risk of some cancers notably leukaemia. The scientific evidence of adverse health effects from general environmental exposure to these fields is "not proven". If there are adverse effects yet to be proven, the risk is probably likely to be small. Chemical substances cause significant damage to the environment. Tobacco smoke is the single biggest known airborne chemical risk to health, whether measured in terms of death rates or ill-health. To a much lesser degree of risk, these adverse effects apply to non-smokers exposed passively to sidestream tobacco smoke. Health effects of concern are asthma, bronchitis, lung cancer and similar lung diseases, and there is good evidence relating an increased risk of symptoms of these diseases with increasing concentration of Sulphur dioxide, ozone and other pollutants. Biohazards generally fall into two broad categories: those which produce adverse health effects through infection (microorganisms, viruses or toxins) and those which produce adverse effects in non-infective (allergic) ways.

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Multi-stage distillation without reflux is equivalent to a single-stage flash operation, and the streams leaving the unit are in equilibrium. These statements hold true for both flash and multi-stage distillation processes.

Distillation is a separation method used in various industries to separate components in a mixture based on their boiling points. It involves heating a feedstock and passing it through a series of distillation columns. In multi-stage distillation, the feedstock is introduced into a pre-flash column operating at lower pressure, causing volatile components to vaporize and rise. The vapor is then condensed and partially vaporized in subsequent columns, with separation occurring at each stage until desired separation levels are achieved.

In multi-stage distillation, the streams leaving the unit are in equilibrium, meaning the compositions of the vapor and liquid phases are balanced. This equilibrium is maintained throughout each stage of the process. Additionally, multi-stage distillation without reflux can be considered as a single-stage flash operation, where the design assumes adiabatic conditions and the overall mass balance determines the operating line. However, the feed temperature is typically higher than the product temperature in this process.

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Answer:

C. WordArt

Explanation:

WordArt feature of MS word is used for styling the text n order to make it look neater or more noticeable. These features are found in the top home menu. They feature text size, text style, text color, and options to make text bold, italic, underlined, etc. There are also many features to make text flashy, colorful, and add special effects. It can be shaded, neon, have shadows, etc.

It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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Answer:

1. Two or One

2. False- offered twice a year

3. Must pass an ASE test and have relevant hands-on work experience

4. Certified

5. In addition to passing an ASE certification test, automotive technicians must have two years of on-the-job-training or one year of on-the-job-training and a two-year degree in automotive repair to qualify for certification.

Explanation:

D. Draw in or press in. This method is used to install new wheel studs because it is the most secure and reliable way to install them. The stud is inserted into the wheel hub and then pressed in with a press or hammer.

There are several methods that may be used to install new wheel studs. The most common method is to draw in or press in the stud. This involves inserting the stud into the wheel hub and then pressing it in with a press or hammer. This ensures that the stud is securely in place and will not come loose or move. Another method is to draw out or slide in the stud. This involves inserting the stud into the wheel hub and then sliding it in until it is flush with the hub. This method is less secure than the press-in method, but it is still effective. Finally, the draw out or push in method involves inserting the stud into the wheel hub and then pushing it in until it is flush with the hub. This method is the least secure of the three, but it is still effective.

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Answer: A leak in the system

Explanation:

The new discharge may remain roughly the same or could even increase slightly, depending on the exact values of width, depth, and velocity.

The discharge of a river is the volume of water that passes through a given cross-section of the river per unit of time. It is calculated as the product of the cross-sectional area of the river channel (width times depth) and the flow velocity.

Discharge (Q) = Width (W) × Depth (D) × Velocity (V)

Given the following changes:

Channel depth (D) decreased to 1 ft

Width (W) stayed at 10 ft

Flow velocity (V) increased to 9 ft/sec

The new discharge (Q') can be calculated as:

Q' = W × D' × V'

Where D' is the new channel depth of 1 ft, and V' is the new flow velocity of 9 ft/sec.

An incompressible fluid, like the water in a river, has a constant mass flow rate along a streamline according to the fluid mechanics principle of continuity. This means that, in the absence of external forces, the product of the cross-sectional area and the flow velocity is constant. Here, we make the assumption that the river is in a stable state and that no outside factors are changing its flow.

When the channel depth (D) decreases to 1 ft, but the width (W) stays the same at 10 ft, the cross-sectional area (W × D') of the river decreases. However, the flow velocity (V') increases to 9 ft/sec.

As a result, if the continuity principle is valid, the decline in channel depth is balanced by the rise in flow velocity. This indicates that depending on the precise values of breadth, depth, and velocity, the new discharge (Q') may either stay nearly the same or perhaps significantly rise.

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As per the details given, the total entropy generated during this process is approximately 1.2792 Btu/lb·°R.

We may use the entropy balance equation to calculate the overall entropy produced throughout the process:

ΔS = Q/T

In this instance, both the heating process and the phase change process require entropy changes to be calculated.

ΔS1 = Q1 / T1

Q1 = 700 Btu (heat transferred)

T1 = 1000°F (temperature of the source)

T1 = (1000 + 459.67) °R = 1459.67 °R

ΔS1 = 700 Btu / 1459.67 °R

Phase change process:

ΔS2 = S_vapor - S_liquid

S_liquid = 1.0 Btu/lb·°R (specific entropy of saturated liquid water)

S_vapor = 1.8 Btu/lb·°R (specific entropy of saturated vapor water)

ΔS2 = 1.8 Btu/lb·°R - 1.0 Btu/lb·°R = 0.8 Btu/lb·°R

So, the total entropy is:

ΔS_total = ΔS1 + ΔS2

ΔS_total = (700 Btu / 1459.67 °R) + 0.8 Btu/lb·°R

Calculating the sum:

ΔS_total ≈ 0.4792 + 0.8 Btu/lb·°R

ΔS_total ≈ 1.2792 Btu/lb·°R

Thus, the total entropy generated during this process is approximately 1.2792 Btu/lb·°R.

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To determine the reactions at points A, B, and C, we will first need to analyze the forces and moments acting on the beam. Given that F1 = 450 N and F2 = 720 N, we can use the following steps:

1. Calculate the sum of the vertical forces, which should be equal to zero for static equilibrium:

ΣFy = Ay + By + Cy - F1 - F2 = 0

2. Calculate the sum of the moments about point A, which should also be equal to zero for static equilibrium:

ΣMA = (F1 * d1) + (F2 * d2) - (Cy * d3) = 0

Here, d1, d2, and d3 are the distances from point A to the points where the forces F1, F2, and Cy are applied.

3. Solve for the unknown reactions Ay, By, and Cy using the above equations.

Note that without the distances (d1, d2, and d3) or a diagram (Figure 1), it is not possible to provide specific numerical values for the reactions at A, B, and C.

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The reference OSHA standard requires several important characteristics of a PFAS. The employer must ensure that personal fall arrest systems (PFAs) must:

a. Limit the maximum arresting force on the employee to 1,800 pounds (8 kN). The figure used above must be based on the use of a full body harness.

From the above, we can therefore say that The reference OSHA standard requires several important characteristics of personal fall arrest systems (PFAs) as employers must reduce the maximum arresting force on the employee to 1,800 pounds (8 kN) using full body harness.

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Answer:

Explanation:

The first successful engine working on this cycle was built by

A. Otto.

These days, many gas, petroland many of the oil engines run on this cycle. It is also known as constant volume cycle, as the heatis received and rejected at a constant volume

This cycle is taken as a standard of comparisonfor internal combustion engines. For the purposeof comparison with other cycles, the air isassumed to be the working substance.•

The ideal Otto cycle consists of two constantvolume and two reversible adiabatic orisentropic processes as shown fig:Otto Cycle•

Processes of Otto Cycle:•

Process 1-2: Isentropic compression•

Process 2-3: Constant-volume heat additiont

Process 3-4: Isentropic expansion• Process 4-1: Constant-volume heat rejection

According to the Otto Cycle, heat engines use gasoline to propel themselves. This cycle also converts chemical energy into thermal energy, which is ultimately converted into motion. The Otto cycle explains the operation of internal combustion engines (which use gasoline), such as those found in cars and lawnmowers.

The Otto Cycle was crucial to the development of the modern world and supplies the energy for the majority of transportation. Specifically, the Otto Cycle is used by the great majority of vehicles on the road today to turn gasoline into motion.

Explain the Internal Combustion Engine.

An internal combustion engine is a type of heat engine in which fuel and an oxidizer burn together in a combustion chamber which is a crucial component of the working fluid flow circuit. The power-generating technologies that are currently most commonly utilized and used are internal combustion engines. An example is diesel and gasoline engine.

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Answer:

performance bonuses

Explanation:

Answer:

winter viscosity grades

Explanation:

The “W”/winter viscosity grades describe the oil's viscosity under cold temperature engine starting conditions. There's a Low Temperature Cranking Viscosity which sets a viscosity requirement at various low temperatures to ensure that the oil isn't too thick so that the starter motor can't crank the engine over.

In a relation schema, the name and structure of the relation are specified. A relational database is made up of various relation schemas.

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The magnitude of the load necessary to produce the given change in length is approximately 21.95 kN.

Yes, it is possible to compute the magnitude of the load necessary to produce the given change in length.

To calculate the load, we can use the formula:

Load = Cross-sectional area ₓ Stress

The cross-sectional area of a cylindrical specimen can be calculated using the formula:

A = π × (d/2)ⁿ2

Where:

A = Cross-sectional area

d = Diameter of the specimen

Given:

d = 12.7 mm (or 0.0127 m)

Substituting the values into the equation, we can calculate the cross-sectional area:

A = π × (0.0127/2)ⁿ2

A = 3.14159 × (0.00635)ⁿ2

A ≈ 7.98 × 10ⁿ-5 mⁿ2

Now, let's calculate the stress on the specimen

Stress = Force / Area

Since we want to find the load (force), rearranging the equation gives us:

Force = Stress ×Area

Given:

Stress = Yield Strength = 275 MPa = 275 × 10ⁿ6 Pa

Area ≈ 7.98 × 10ⁿ-5 mⁿ2

Calculating the load:

Force = 275 × 10ⁿ6 Pa × 7.98 × 10ⁿ-5 mⁿ2

Force ≈ 21.95 kN

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Answer:

What must a subclass do to modify a private superclass instance variable?

a) The subclass must simply use the name of the superclass instance variable.

b) The subclass must declare its own instance variable with the same name as the superclass instance variable.

c) The subclass must use a public method of the superclass (if it exists) to update the superclass's private instance variable.

d) The subclass must have its own public method to update the superclass's private instance variable.

Option c) The subclass must use a public method of the superclass (if it exists) to update the superclass's private instance variable is the correct answer.

Private instance variables of a superclass are not directly accessible by subclasses. However, if the superclass provides a public method to modify the variable, the subclass can use this method to indirectly modify the private instance variable.

For example, consider the following superclass with a private instance variable and a public method to modify it:

public class Superclass {

   private int value;

   public void setValue(int newValue) {

       this.value = newValue;

   }

}

If a subclass wants to modify the value of the private instance variable value, it can do so by calling the public method setValue() of the superclass:

public class Subclass extends Superclass {

   public void updateValue(int newValue) {

       setValue(newValue); //call to public method of superclass to update private instance variable

   }

}

In this example, the updateValue() method of the subclass uses the public setValue() method of the superclass to modify the private instance variable value.

Explanation: