Estimate the square root of the following imperfect square:
7.
a. 2.2
b. 2.4
C. 2.6
d. 2.8
This problem is just try and error.
First we try number 2.5 since its the average of all the answers.
2.5^2=6.25
This is smaller than 7 so the answer is either 2.6 or 2.8
Now let's try 2.7
2.7^2=7.29
Which is bigger than 7 and that means the correct answer is 2.6 :)
-5(x + 6) > 3 (x + 13) - 5
all possible solutions
Answer: x< -8
Step-by-step explanation:
-5(x + 6) > 3 (x + 13) - 5
-5x -30>(3x + 39)-5
-5x -30> 3x +34
i will put the rest in the comments
the fictional university called Sparkson, there are three schools (Engineering, Arts and Sciences, and Business). Aproximately 50% of incoming students are in Engineering, 30% are in Arts and Sciences, and 20% are in Business. In evaluating retention (those that return for the second year:
. About 85% of engineering students are retained.
. About 95% of arts and science students are retained.
• About 90% of business students are retained.
For a randomly selected incoming student, what is the probability that they will be retained one year later?
The probability that a randomly selected incoming student at Sparkson University will be retained one year later is approximately 88%.
To calculate the probability of retention for a randomly selected incoming student, we need to consider the number of students in each school and their respective retention rates. Let's assume there are 100 incoming students.
Out of these 100 students, 50% are in Engineering, which gives us 50 students. Since the retention rate for Engineering students is 85%, we can expect approximately 85% of these students to be retained, which is equal to 42.5 students. However, we cannot have a fraction of a student, so we round it down to 42.
Similarly, 30% of the incoming students are in Arts and Sciences, which gives us 30 students. With a retention rate of 95%, we can expect approximately 95% of these students to be retained, which is equal to 28.5 students. Rounding it down, we have 28 students.
Finally, 20% of the incoming students are in Business, which gives us 20 students. With a retention rate of 90%, we can expect approximately 90% of these students to be retained, which is equal to 18 students.
Adding up the number of students retained from each school, we have a total of 42 + 28 + 18 = 88 students retained out of the initial 100 incoming students.
Therefore, the probability that a randomly selected incoming student will be retained one year later is 88/100 = 0.88 or 88%.
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8 times what number equals 24?
\(8 \times x = 24 \\ x = \frac{24}{8} \\ x = 3\)
Solved8×3=24Answer:
3
Step-by-step explanation:
24 ÷ 8 = 3
8 × 3 = 24
....................
please help!!! will mark brainliest
Answer:
x = 15Step-by-step explanation:
Since the quadrilateral is inscribed into circle, its opposite angles are supplementary:
m∠H + m∠K = 180°Substitute the values and solve for x:
5x - 22 + 8x + 7 = 18013x - 15 = 18013x = 195x = 195/13x = 15Answer:
Solution ::According to the property of Cyclic Quadrilateral
5x - 22 + 8x + 7 = 180
(5x + 8x) - (22 - 7) = 180
13x - 15 = 180
13x = 180 + 15
13x = 195
x = 195/13
x = 15
\( \\ \)
What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x y - 1 = 0? 4x - y - 6 = 0 4x y 6 = 0 4x y - 6 = 0
The equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y - 1 = 0 is 4x+y-6=0.
What is meant by slope-intercept form?The line's equation is expressed in slope-intercept form: y = mx + b, where m represents the slope and b represents the y-intercept.
The slope intercept form is used to calculate the y-intercept and slope of a straight line.
We know that the equation of the line is, y= mx +b
4x+y-1=0 is the same as y= -4x+1
For this equation, b=1, but for a line with slope -4 passing through the point (1,2), the y-intercept changes.
y= -4x+b
The above line is passing through the point (1, 2)
2=-4(1)+b
Now, we have to solve for b value we get b=6.
The equation that we get is,
y= -4x+6 or 4x+y-6=0.
The equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y - 1 = 0 is 4x+y-6=0.
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a study wants to determine the average tuition that san jose state undergraduate students would pay per semester. each student in the following samples is asked how much tuition he or she paid for the fall semester. what is the type of sampling in each case?
The type of sampling used in each case of the students to pay tuition fee for the fall semester is simple random sampling.
Simple random sampling is the method that was applied in this instance. Each person in the population has an equal probability of being chosen for the sample when using simple random sampling. In this instance, the amount of tuition each participant in the sample paid for the autumn semester was questioned.
The type of sampling in the next case is stratified sampling. After classifying the students into freshmen, sophomores, juniors, or seniors, 25 students from each group are chosen. The sample will be representative of each group thanks to this technique.
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Complete question is:
A study wants to determine the average tuition that san jose state undergraduate students would pay per semester. each student in the following samples is asked how much tuition he or she paid for the fall semester. what is the type of sampling in each case?
A sample of 100 undergraduate San Jose State students is taken by organizing the students’ names by classification (freshman, sophomore, junior, or senior), and then selecting 25 students from each.
In a marathon, Peter ran 15 more kilometers than half of the number Juan ran. Peter ran at most 36 km
Answer: 42 km
Step-by-step explanation:
P=Peter. J=Juan
P=15+J/2
36=15+J/2
21=J/2
J=42 km
a biangle is a polygon with exactly 2 sides (like a triangle has 3 sides, and a quadrangle (i.e. quadrilateral) has 4). a biangle is non-degenerate if it has positive area (i.e. it is not contained entirely in a single line) (a) prove that a non-degenerate biangle cannot exist in euclidean geometry. (b) prove that a non-degenerate biangle cannot exist in hyperbolic geometry. (c) show how to construct a non-degenerate biangle in spherical geometry
a. a non-degenerate triangle cannot exist in Euclidean geometry. b. a non-degenerate triangle cannot exist in hyperbolic geometry. c. This forms a non-degenerate triangle with two sides and two angles of 0 radians.
(a) In Euclidean geometry, the sum of the interior angles of a polygon with n sides is (n-2)π radians. For a non-degenerate biangle, n=2, so the sum of the interior angles is (2-2)π = 0 radians. However, this is impossible in Euclidean geometry since the sum of the interior angles of any polygon must be greater than 0 radians. Therefore, a non-degenerate biangle cannot exist in Euclidean geometry.
(b) In hyperbolic geometry, the sum of the interior angles of a polygon with n sides is (n-2)π radians, where π is the constant known as the hyperbolic angle. For a non-degenerate biangle, n=2, so the sum of the interior angles is (2-2)π = 0 radians. However, this is possible in hyperbolic geometry since the hyperbolic angle is negative, so the sum of the interior angles of a polygon with fewer than 3 sides can be 0 radians. Therefore, a non-degenerate biangle cannot exist in hyperbolic geometry.
(c) In spherical geometry, the sum of the interior angles of a polygon with n sides is (n-2)π radians, where π is the constant known as the spherical angle. For a non-degenerate biangle, n=2, so the sum of the interior angles is (2-2)π = 0 radians. This is possible in spherical geometry since the spherical angle is positive, so the sum of the interior angles of a polygon with fewer than 3 sides can be 0 radians. To construct a non-degenerate biangle in spherical geometry, we can take two great circles on a sphere that intersect at two points, and take the two arcs connecting the points of intersection as the sides of the biangle. This forms a non-degenerate biangle with two sides and two angles of 0 radians.
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PLEASE HELP
A
B
C
D
???
It takes 1 ticket to ride the Ferris wheel at an amusement park. The amusement park earns $144 for each Ferris wheel ride if the cars are full. The Ferris wheel seats 48 people. Write an equation that can be used to determine the cost (c) for 1 ticket.
Answer:
It would cost 3 dollars.
Answer:
3 dollars
Step-by-step explanation:
Drag each expression to the box that describes the expression.
3-2 1-7
5-8 9-4
(4) (5) - (2)8
(11+5) (0-12)
5(2) (7) (8) (8)
Difference of Two Products
DRAG AND
Product of Two Quotients
DRAG AND
CLEAR
CHECK
Difference of Two Products has the expressions
(4)(5)-2(8)
and 5(2)(7)-8(8)
Product of Two Quotients
3-2/5-8 . 1-7/9-4
and (11÷5)(1-4/6-12)
The difference of two numbers is the result of subtracting these two numbers.
The product of two or more numbers is the result of multiplying two numbers
Difference of Two Products has the expressions
(4)(5)-2(8)
and 5(2)(7)-8(8)
Product of Two Quotients
3-2/5-8 . 1-7/9-4
and (11÷5)(1-4/6-12)
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What do you know to be true about the values of p and ?
/60"
459
458
A. p> 9
B. p
C. p = 9
D. Can't be determined
Answer:
B. p C. p = 9.
Step-by-step explanation:
Hope this helps!
Dawson simplifies the equation 4y-3=4(y + 1) and says it has no solution. Is dawson correct?
Let's start by substituting the right-hand side of the equation into the left-hand side:
What does the math equation mean?
Two expressions are combined by the equal sign to form a mathematical statement known as an equation. For instance, a formula might be 3x - 5 = 16. After solving this equation, we learn that the value of the variable x is 7.
4y - 3 = 4(y + 1)
4y - 3 = 4y + 4
Now, we can isolate y by subtracting 4y from both sides:
0 = y + 4
-4 = y
So, there is a solution to the equation: y = -4. This means that Dawson is incorrect in saying that the equation has no solution.
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The image of a parabolic lens is projected onto a graph. The image crosses the x-axis at –2 and 3. The point (–1, 2) is also on the parabola. Which equation can be used to model the image of the lens?
y = (x – 2)(x + 3)
y = (x – 2)(x + 3)
y = (x + 2)(x – 3)
y = (x + 2)(x – 3)
Given:
The image of a lens crosses the x-axis at –2 and 3.
The point (–1, 2) is also on the parabola.
To find:
The equation that can be used to model the image of the lens.
Solution:
If the graph of polynomial intersect the x-axis at c, then (x-c) is a factor of the polynomial.
It is given that the image of a lens crosses the x-axis at –2 and 3. It means (x+2) and (x-3) are factors of the function.
So, the equation of the parabola is:
\(y=k(x+2)(x-3)\) ...(i)
Where, k is a constant.
It is given that the point (–1, 2) is also on the parabola. It means the equation of the parabola must be satisfy by the point (-1,2).
Putting \(x=-1, y=2\) in (i), we get
\(2=k(-1+2)(-1-3)\)
\(2=k(1)(-4)\)
\(2=-4k\)
Divide both sides by -4.
\(\dfrac{2}{-4}=k\)
\(-\dfrac{1}{2}=k\)
Putting \(k=-\dfrac{1}{2}\) in (i), we get
\(y=-\dfrac{1}{2}(x+2)(x-3)\)
Therefore, the required equation of the parabola is \(y=-\dfrac{1}{2}(x+2)(x-3)\).
Note: All options are incorrect.
Chebyshev's theorem provides the proportion of observations that lie within k standard deviations of the mean. The value k must be ______.
The value of k in Chebyshev's theorem can be any positive real number.
Chebyshev's theorem, also known as Chebyshev's inequality, is a statistical theorem that provides an upper bound on the proportion of observations that lie within a certain number of standard deviations from the mean in any distribution.
The theorem states that for any distribution (regardless of its shape), at least \((1 - 1/k^2)\) proportion of the data falls within k standard deviations from the mean, where k is any positive number greater than 1.
Mathematically, Chebyshev's theorem can be expressed as:
P(|X - μ| < kσ) ≥ \(1 - 1/k^2\)
Where:
P(|X - μ| < kσ) represents the probability that a randomly selected observation from the distribution falls within k standard deviations from the mean.
μ represents the mean of the distribution.
σ represents the standard deviation of the distribution.
k is the number of standard deviations from the mean.
The value of k in Chebyshev's theorem can be any positive real number.
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If x = 6 and y = –2, evaluate the following expression:
7(2x – 3y)
Answer:
14x-21y
Step-by-step explanation:
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. This is:
7(2x – 3y)
= 7(2(6) – 3(-2))
= 7(12 + 6)
= 7(18)
= 126Which equation best describes a relationship between x and y in the table below?
Answer:
y = \(\frac{1}{3}\) x + 5
Step-by-step explanation:
Slope m = \(\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\)
y = mx + b , "b" is y-intercept with coordinates (0, b)
(0, 5)
(6, 7)
m = \(\frac{7-5}{6-0}\) = \(\frac{1}{3}\)
y = \(\frac{1}{3}\) x + 5
to calculate mad and summing up the forecasts errors, the value used for ||18−20|| in the calculation is? multiple choice question. either 2 or -2 2 -2 cannot be computed
The sum of forecast errors is also known as total forecast error. Therefore, the correct answer is option A, which is "2."
The absolute error of the given data is calculated by subtracting the actual value from the forecasted value, followed by the absolute value.
The errors are then summed up to get the mean absolute deviation. The value used for ||18−20|| in the calculation of MAD and summing up the forecast errors is 2.
Therefore, the correct answer is option A, which is "2."Formula for calculating MAD:MAD = Σ ( | A_i - F_i | ) / n
Where: MAD is the mean absolute deviation|A_i - F_i| represents the absolute error between the actual value (A) and the forecasted value (F)n is the total number of observations, Sum of forecast errors:Σ ( A_i - F_i )Where: A_i is the actual valueF_i is the forecasted value
The sum of forecast errors is also known as total forecast error.
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Calculate the future value of a three year uneven cash flow given below, using 11% discount rate:
Year 0 Year 1 Year 2 Year 3
0 $600 $500 $400
Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.
To calculate the future value of a three-year uneven cash flow given below, using an 11% discount rate, we need to use the formula;
Future value of uneven cash flow = cash flow at year 1/(1+discount rate)¹ + cash flow at year 2/(1+discount rate)² + cash flow at year 3/(1+discount rate)³ + cash flow at year 4/(1+discount rate)⁴
Given the cash flows;
Year 0: $0
Year 1: $600
Year 2: $500
Year 3: $400
Then the Future value of uneven cash flow
= $600/(1+0.11)¹ + $500/(1+0.11)² + $400/(1+0.11)³
= $600/1.11 + $500/1.23 + $400/1.36
=$540.54 + $405.28 + $293.00
=$1,238.82
Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.
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The slope of a line is -4, and the y-intercept is -3. What is the equation of the line written in slope-intercept form?
y = -4x - 3
y = 4x - 3
y = -4x + 3
Answer:
y= -4x+-3 = y=-4x-3
The rest are wrong.
Hi there! :)
We are given the slope of the line and its y-intercept.
So, we write the equation in slope-intercept form (y=mx+b)
m is the slope of the line, and b is the y-intercept.
y=mx+b
y=-4x-3
Hence, that's the equation (Option A)
Hope it helps. Use the comment section to clarify your doubts.
Answered by
~A cheerful gal who helps others and smiles
Good luck.
When Jonathan runs the 400 meter dash, his finishing times are normally distributed with a mean of 88 seconds and a standard deviation of 2.5 seconds. If Jonathan were to run 48 practice trials of the 400 meter dash, how many of those trials would be between 89 and 91 seconds, to the nearest whole number?
Answer:
3.18%
2 between 89 91
Step-by-step explanation:
*Probability-Between 3.18%
Z1=0.04 Z2=0.12
x-1 89
x-2 (not required) 91
µ 88
σ 25
a car was purchased last year for $28,500. now its value is $25,510. at what rate is the car's value depreciating each year?
Answer:
The car's value is depreciating by $2,990 per year.
Step-by-step explanation:
To solve this problem, we just need to subtract the cars value this year, or $25,510, from the car value of last year, or $28,500.
28,500 - 25,510 = $2,990
Since the car value was $2,990 more just last year, the car's value is depreciating by $2,990 per year.
Hope this helps! :D
negative 5 1 half plus 7 3 over 4
Answer:
\( 2 \dfrac{1}{4} \)
Step-by-step explanation:
\( -5 \dfrac{1}{2} + 7 \dfrac{3}{4} = \)
\( = -5 \dfrac{2}{4} + 7 \dfrac{3}{4} \)
\( = 7 \dfrac{3}{4} - 5 \dfrac{2}{4} \)
\( = 2 \dfrac{1}{4} \)
i need help, what’s the answer?
Answer:
-2x+8y-3 if im not wrong
the three perpendicular bisectors of a triangle intersect in one point called the
which would be an appropriate first step in solving the equation? 2(x+3)-5=9
Answer:
Distributing
Step-by-step explanation:
Order of opersations says to do parenthesis first so....
2(x+3)-5=9
we would distribute 2
2x+6-5=9
Answer: x=4
and wydm
Given the quantities a=3.7m, b=3.7s, c=80m/s, what is the value of the quantity d=a^3/cb^2?
The value of the quantity d is 0.0462 m^2/s.
Here,
The quantities a=3.7m, b=3.7s, c=80m/s.
We have to find the value of d = a^3/cb^2
What is quantity?
A quantity is an amount, number, or measurement that answers the question 'how much?' Quantities can be expressed in numbers or non-standard units.
Now,
The quantities a=3.7m, b=3.7s, c=80m/s.
The value of d;
\(d = \frac{a^{3} }{cb^{2} }\)
\(d = \frac{3.7*3.7*3.7 }{80 * 3.7^{2} }\)
\(d = \frac{3.7}{80}\)
\(d = 0.0462\)
Hence, The value of the quantity d is 0.0462 m^2/s.
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What condition has no solution?
A condition that is impossible to satisfy has no solution.
Mathematics can be a powerful tool for solving many problems, but there are some issues that can't be solved.
In particular, any condition that is impossible to satisfy, such as the logical statement ‘this statement is false’, has no solution in mathematics. This is because the statement can’t be proven true or false, and so it can’t be solved.
An unsolvable condition is one that cannot be solved using any combination of logical and mathematical steps.
This means that no matter how much time and effort is put in, a solution to the problem cannot be discovered.
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Round 6,258 to the nearest hundred
Answer:
6300
Step-by-step explanation:
Remember, we do not necessarily round up or down, but to the hundred that is nearest to 6258.
When rounding a number such as 6258 to the nearest hundred, we use the following rules:
A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above.
B) We round the number down to the nearest hundred if the last two digits in the number are 49 or below.
C) If the last two digits are 00, then we do not have to do any rounding, because it is already to the hundred.
In this case, Rule A applies and 6258 rounded to the nearest hundred is:
6300
Answer:
Step-by-step explanation:
it is 6300