T/F With large sample sizes, even small differences between the null value and the true value of the parameter, a difference often called the effect size, will be identified as statistically significant.

Answer:

b. (4,2)

Step-by-step explanation:

step one: isolate x in the first equation

substitute x=6-y: \(\begin{bmatrix}2\left(6-y\right)-2y=4\end{bmatrix}\)

\(\begin{bmatrix}12-4y=4\end{bmatrix}\)

\(-4y=-8\)

\(y=2\)

step two: isolate y in the second equation, substitute y=2

\(x=6-y\)

\(x=6-2\)

\(x=4\)

Answer:

b

Step-by-step explanation:

Given the 2 equations

3x + 3y = 18 → (2)

2x - 2y = 4 → (2)

Multiplying (1) by 2 and (2) by 3 and adding the result will eliminate the y- term

6x + 6y = 36 → (3)

6x - 6y = 12 → (4)

Add (3) and (4) term by term to eliminate y

12x + 0 = 48

12x = 48 ( divide both sides by 12 )

x = 4

Substitute x = 4 into either of the 2 equations and solve for y

Substituting into (1)

3(4) + 3y = 18

12 + 3y = 18 ( subtract 12 from both sides )

3y = 6 ( divide both sides by 3 )

y = 2

solution is (4, 2 ) → b

Answer:

y=-3x+1

Step-by-step explanation:

When oversampling a minority class, the positive rate increases, meaning that the model is more likely to correctly identify instances of that class. Under-sampling the majority class may decrease the false positive rate, as the model is less likely to incorrectly classify instances from the majority class as belonging to the minority class.

This may also decrease the positive rate, as there are fewer examples of the minority class to learn from. In general, both oversampling and under-sampling can have trade-offs and it is important to carefully consider the specific dataset and problem at hand before deciding which approach to use.

Oversampling, in which examples from the minority class are duplicated, can have the following effects:
1. False positive rate: Oversampling may lead to an increase in false positives, as the classifier becomes more sensitive to the minority class, causing it to potentially misclassify some majority class instances as minority class instances.
2. False negative rate: On the other hand, oversampling tends to reduce the false negative rate, since the classifier becomes better at identifying the minority class instances.

Undersampling, in which examples from the majority class are deleted, can have these effects:
1. False positive rate: Undersampling may lead to a decrease in false positives, as the classifier is less likely to misclassify majority class instances as minority class instances due to the reduced majority class representation.
2. False negative rate: However, undersampling can cause an increase in false negatives, as the classifier may not be as sensitive to the minority class instances and may misclassify them as majority class instances.

In summary, oversampling generally increases false positives and reduces false negatives, while undersampling tends to decrease false positives and increase false negatives. When choosing between these methods, it's important to consider the specific problem and the desired balance between false positive and false negative rates.

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Answer:

below

Step-by-step explanation:

that's is the solution above

Answer:

Step-by-step explanation: Using the formula:

distance = speed × time

where speed is in km/h and time is in hours

We have:

distance = 150 km/h × 2 h = 300 km

Therefore, the distance travelled for the journey is 300 km.

Answer:

Present value = $3,000

Step-by-step explanation:

Given:

Interest rate = 10%

Security pays = $1,100 next year, $1,210 the year after, and $1,331

Find:

Present value

Computation:

Present value = 1,100/(1 + 0.10) + 1,210/(1 + 0.10)² + $1,331/(1 + 0.10)³

Present value = 1,100/(1.10) + 1,210/1.21 + $1,331/1.331

Present value = $3,000

In this movie, the ratio of children to adults suggests that there are 27 children in attendance.

We have to give that,

There are 9 children for every 4 adults.

This means that if there were 13 people, 9 of them would be children and 4 would be adults.

Children would therefore be:

= 9 / 13

If there were 39 people, the number of children would be:

= 9/13 x 39

= 27 children

In conclusion, there are 27 children.

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The complete question is,

In the newest animated movie, for every 9 children, there are 4 adults. There are a total of 39 children and adults in the movie.

How many children are in the movie?

To find the displacement and total distance traveled by the object from t=0 to t=6, we need to integrate the velocity function over the given time interval.

The displacement can be found by integrating the velocity function v(t) with respect to t over the interval [0, 6]. The integral of v(t) represents the net change in position of the object during this time interval.

The total distance traveled can be determined by considering the absolute value of the velocity function over the interval [0, 6]. This accounts for both the forward and backward movements of the object.

Now, let's calculate the displacement and total distance traveled using the given velocity function v(t) = t^2 - (1/t) - 12 over the interval [0, 6].

To find the displacement, we integrate the velocity function as follows:

Displacement = ∫[0,6] (t^2 - (1/t) - 12) dt.

To find the total distance traveled, we integrate the absolute value of the velocity function as follows:

Total distance = ∫[0,6] |t^2 - (1/t) - 12| dt.

By evaluating these integrals, we can determine the displacement and total distance traveled by the object from t=0 to t=6.

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Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Halves it ?

I don't really get what he wants but I guess he wants me to know that is "Cuts it in a half" basically.

Answer:

Option B.

Step-by-step explanation:

We have to find the quotient of the expression \((3x^4+6x^3+2x^2+9x+10)\) when divided by (x + 2) by synthetic division.

-2 | 3     6     2     9     10

   | ↓    -6     0    -4    -10

     3     0     2     5     0

Solution of the synthetic division will be = (3x³ + 2x + 5)

Therefore, quotient after division will be, (3x³ + 2x + 5) and the remainder is 0.

Therefore, (3x³ + 2x + 5) will be the answer.

Option (B) will be the correct option.

Answer:

B

Step-by-step explanation:

I did the work and this one is very tough

Answer:

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f   brainliest ?

Answer:

C

Step-by-step explanation:

over the interval [-1,1], f(x) is greater than 0

Answer:

24

Step-by-step explanation:

(a) The Null-Hypotheses is H₀ : μ = 12, Alternate-Hypotheses is Hₐ : μ ≠ 12.

(b) The "test-statistic" is 10.36,

(c) The "p-value" is 0.0001,

(d) We make a decision to reject the "Null-Hypothesis",

(e) We conclude that the cans of "regular-Coke" have volumes with mean different from 12 ounces.

Part (a) : The "Null-Hypothesis" is that the mean volume of cans of regular Coke is 12 ounces, as stated on the label. The alternative-hypothesis is that the mean volume is different from 12 ounces.

So, H₀ : μ = 12

Hₐ : μ ≠ 12.

Part (b) : The "test-statistic" for a one-sample t-test is calculated as:

t = (x' - μ)/(s / √n),

where "s" = sample standard-deviation, μ = population mean, x' = sample mean, and n = sample size,

In this case, x' = 12.19, μ = 12, s = 0.11, and n = 36.

So, t = (12.19 - 12)/(0.11/√36) = 10.36,

Part (c) : We know that for "significance-level" of 0.01. The p-value is 0.0001.

Part (d) : Since the p-value is less than the significance-level of 0.01, we reject the null hypothesis.

Part (e) : Based on the results of the hypothesis test, we can conclude that there is sufficient evidence to suggest that cans of regular-Coke have volumes with a mean different from 12 ounces.

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Answer:

9. m∠v = 50°

10. m∠EFG = 60°

11. SU = 32

12. m∠G = 70°

13. m∠KMN = 37°

14. m∠CDE = 40°

Step-by-step explanation:

9.

36x - 1 + 29x + 1 + 50 = 180

36x + 29x = 65x

-1 + 1 = 0

65x + 50 = 180

65x + 50 - 50 = 180 - 50

65x = 130

65x/65 = 130/65

x = 2

m∠v = m∠x

m∠v = 50°

10.

x + 120 + 26 + 2x + 34 = 180

Step 1: Simplify both sides of the equation.

x+120+26+2x+34=180

(x+2x)+(120+26+34)=180(Combine Like Terms)

3x+180=180

3x+180=180

Step 2: Subtract 180 from both sides.

3x+180−180=180−180

3x=0

Step 3: Divide both sides by 3.

3x/3 = 0/3

x = 0

m∠EFG = 180 - m∠E

= 180 - (x + 120)

= 180 - (0 + 120)

= 180 - 120

= 60

m∠EFG = 60°

11.

2x − 2 = x + 7

Step 1: Subtract x from both sides.

2x−2−x=x+7−x

x−2=7

Step 2: Add 2 to both sides.

x−2+2=7+2

x=9

SU = 2(QU)

= 2(x + 7)

= 2(9 + 7)

= (2)(16)

= 32

SU = 32

12.

5x+10+44+4x+18=180

Step 1: Simplify both sides of the equation.

5x+10+44+4x+18=180

(5x+4x)+(10+44+18)=180(Combine Like Terms)

9x+72=180

9x+72=180

Step 2: Subtract 72 from both sides.

9x+72−72=180−72

9x=108

Step 3: Divide both sides by 9.

9x/9 = 108/9

x = 12

m∠G = m∠E

m∠G = 5x + 10

m∠G = 5(12) + 10

m∠G = 70°

13. 10x + 5 + 38 + 4x - 3 = 180

10x+5+38+4x−3=180

Step 1: Simplify both sides of the equation.

10x+5+38+4x−3=180

10x+5+38+4x+−3=180

(10x+4x)+(5+38+−3)=180(Combine Like Terms)

14x+40=180

14x+40=180

Step 2: Subtract 40 from both sides.

14x+40−40=180−40

14x=140

Step 3: Divide both sides by 14.

14x/14 = 140/14

x = 10

m∠KMN = 4x - 3

= 4(10) - 3

= 40 - 3

= 37

m∠KMN = 37°

14. 29x - 5 + 5x + 15 = 180

Step 1: Simplify both sides of the equation.

29x−5+5x+15=180

29x+−5+5x+15=180

(29x+5x)+(−5+15)=180(Combine Like Terms)

34x+10=180

34x+10=180

Step 2: Subtract 10 from both sides.

34x+10−10=180−10

34x=170

Step 3: Divide both sides by 34.

34x/34 = 170/34

x = 5

m∠CDE = 5x + 15

= 5(5) + 15

= 25 + 15

= 40

m∠CDE = 40°

Answer: E

Step-by-step explanation:

2 * 6 = 12

(45/360) *[(2)(6)(π)] = (3/2)π

The length is 1.5π +12 (16.71...)

This answer is not any of the suggested ones, so the answer is E.

The answer is option A, pet ownership is the independent variable.

In experimental research, an independent variable is the variable that is manipulated by the researcher to determine its effect on the dependent variable. In this case, the independent variable is pet ownership, which is being studied to determine its effect on the health and lifespan of pet owners.

The dependent variable, in turn, is the health and lifespan of pet owners, which is expected to be influenced by their pet ownership status.

It is important to note that the relationship between pet ownership and health/lifespan could be influenced by other factors, such as age, income, or lifestyle. These other factors are known as spurious variables and can confound the relationship between the independent and dependent variables.

Operational variables, on the other hand, refer to how the researcher measures or manipulates the independent and dependent variables.

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The answer is Series 1. It satisfies the given condition as it is a geometric series with a common ratio of 1/3. Each term in this series is obtained by multiplying the previous term by 1/3, which confirms that it is indeed a geometric series with the given condition.

We need to test each series to see if it is geometric with x = 1/3. Remember, a geometric series is one in which each term is obtained by multiplying the previous term by a constant value. In this case, that constant value is x = 1/3.  Let's test three series to see if they fit the given condition:  1) 3, 1, 1/3, 1/9, 1/27, ...
To see if this series is geometric with x = 1/3, we can check if each term is obtained by multiplying the previous term by 1/3.
1/3 ÷ 1 = 1/3
1/9 ÷ 1/3 = 1/3
1/27 ÷ 1/9 = 1/3
Since each term is obtained by multiplying the previous term by 1/3, this series is geometric with x = 1/3.

2) 1, 1/3, 3, 1/9, 9, ...
To test if this series is geometric with x = 1/3, we can check if each term is obtained by multiplying the previous term by 1/3.
1/3 ÷ 1 = 1/3
3 ÷ 1/3 = 9
1/9 ÷ 3 = 1/27
Since the terms are not consistently obtained by multiplying the previous term by 1/3, this series is not geometric with x = 1/3.
3) 1, 1/3, 1/9, 1/27, ...
To test if this series is geometric with x = 1/3, we can check if each term is obtained by multiplying the previous term by 1/3.
1/3 ÷ 1 = 1/3
1/9 ÷ 1/3 = 1/3
1/27 ÷ 1/9 = 1/3
Since each term is obtained by multiplying the previous term by 1/3, this series is geometric with x = 1/3.

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Step-by-step explanation:

plug in variables for x

x= 1:

-(1)-2

y= -3

x=2

-(2)-2

y= -4

x=3

-(3)-2

y= -5

x=4

-(4)-2

y= -6

The solutions of the equation are x = 2 and x = -2.Now, we can find the values of A, B, C and D as:\($$A^2 + B^2 + C^2 + D^2 = (-2)^2 + 2^2 + 0^2 + 0^2 = 8$$\)

Therefore, the value of A2 + B2 + C2 + D2 is 8.

The given equation is:\($$x^2(x^2 + 4x - 5) = 4(x^2 + 4x - 5)$$\)We can write this equation as \($x^2 = 4$ or $(x^2 + 4x - 5) = 4$.\)

When\($x^2 = 4$,\) then x = ±2. Now, we will check the second part of the equation\($(x^2 + 4x - 5) = 4$\) for both values of x.If x = 2, then \($$(2)^2 + 4(2) - 5 = 9$$If $x = -2$\), then \($$(-2)^2 + 4(-2) - 5 = -9$$\)

We know that a² + b² + c² + d² = (a+b+c+d)² - 2(ab+bc+cd+da)

Therefore, the solutions of the equation are x = 2 and x = -2.Now, we can find the values of A, B, C and D as:\($$A^2 + B^2 + C^2 + D^2 = (-2)^2 + 2^2 + 0^2 + 0^2 = 8$$\)

Therefore, the value of A2 + B2 + C2 + D2 is 8.

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Answer:

can you upload a bigger picture

Usando proporciones, se encuentra que:

---------------------------------

La regla de três es:

21000 - 1

x - 0.55

Aplicando multiplicación cruzada:

\(x = 21000(0.55) = 11550\)

El automóvil se vendió por 11,500.00.

21,000.00 - 11,500.00 = 9,500.00.

El monto de la pérdida total es de 9,500.00.

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Answer:

D

Step-by-step im not Shure but I think its D

The amounts for the other three partners are $25000, $100000, and $200000.

The amount that the other people will share will be:

= $400000 - $50000

= $350000

Therefore this will be divided as follows:

A = 2/(2+4+8) × $350000

= 2/14 × $350000

= $25000

B = 4/14 × $350000

= $100000

C = 8/14 × $350000

= $200000

Therefore, the amounts for the other three partners are $25000, $100000, and $200000.

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The transpose of A⁻¹ is the inverse of the transpose of A⁻¹, which implies that if A⁻¹ is orthogonal, then A is orthogonal. Therefore, we have shown that the matrix A is orthogonal if and only if its transpose A⁻¹ is orthogonal.

To find the orthogonal projection of vector w into the plane spanned by vectors u and v, we need to calculate the projection vector proj_w(uv).

First, we calculate the normal vector n of the plane. The normal vector is obtained by taking the cross product of vectors u and v:

n = u x v

= (1, 0, -1) x (4, 3, -2)

The cross product can be calculated as follows:

n = ((0)(-2) - (-1)(3), (-1)(4) - (1)(-2), (1)(3) - (0)(4))

= (-3, -6, 3)

Next, we normalize the normal vector n to obtain the unit normal vector n:

n = n / ||n||

= (-3, -6, 3) / √(9 + 36 + 9)

= (-3, -6, 3) / √54

= (-1/√6, -2/√6, 1/√6)

Now, we can calculate the projection of vector w onto the plane using the formula:

proj_w(uv) = w - ((w · n) / (n · n)) * n

The dot product of w and n is given by:

w · n = (2)(-1/√6) + (3)(-2/√6) + (-2)(1/√6)

= -2/√6 - 6/√6 - 2/√6

= -10/√6

The dot product of n and n is:

n · n = (-1/√6)(-1/√6) + (-2/√6)(-2/√6) + (1/√6)(1/√6)

= 1/6 + 4/6 + 1/6

= 6/6

= 1

Substituting these values into the projection formula, we have:

proj_w(uv) = (2, 3, -2) - ((-10/√6) / 1) * (-1/√6, -2/√6, 1/√6)

= (2, 3, -2) + (10/√6)(-1/√6, -2/√6, 1/√6)

= (2, 3, -2) + (-10/6, -20/6, 10/6)

= (2, 3, -2) + (-5/3, -10/3, 5/3)

= (2 - 5/3, 3 - 10/3, -2 + 5/3)

= (1/3, 1/3, -1/3)

Therefore, the orthogonal projection of vector w into the plane spanned by vectors u and v is (1/3, 1/3, -1/3).

Now, let's prove the statement that the matrix A is orthogonal if and only if its transpose A⁻¹ is orthogonal.

To prove this, we need to show two conditions:

If A is orthogonal, then A⁻¹ is orthogonal:

If A is orthogonal, it means that A · A⁻¹ = I, where I is the identity matrix.

Taking the transpose of both sides, we have (A · A⁻¹)ᵀ = Iᵀ, which simplifies to (A⁻¹)ᵀ · Aᵀ = I.

This shows that the transpose of A⁻¹ is the inverse of the transpose of A, which implies that if A is orthogonal, then A⁻¹ is orthogonal.

If A⁻¹ is orthogonal, then A is orthogonal:

If A⁻¹ is orthogonal, it means that (A⁻¹) · (A⁻¹)ᵀ = I, where I is the identity matrix.

Taking the transpose of both sides, we have ((A⁻¹) · (A⁻¹)ᵀ)ᵀ = Iᵀ, which simplifies to ((A⁻¹)ᵀ) · (A⁻¹) = I.

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Answer:

f(x) = -7(x-5)^2 +5

f(-1) = -7(-1-5)^2 +5

f(-1) = -7(-6)^2+5

f(-1) = -7(36)+5

f(-1) = -252+5

f(-1) = -247

Let me know if this helps!

Answer:

-247

Step-by-step explanation:

f(-1) = -7((-1)-5)^2

Given:

The equation is

\(\sin\left(x+\dfrac{7\pi}{2}\right)=-\dfrac{\sqrt{3}}{2}\)

To find:

The solutions of given equation over the interval \([0,2\pi]\).

Solution:

We have,

The equation is

\(\sin\left(x+\dfrac{7\pi}{2}\right)=-\dfrac{\sqrt{3}}{2}\)

\(\sin\left(x+\dfrac{7\pi}{2}\right)=-\sin \dfrac{\pi }{3}\)

\(\sin\left(x+\dfrac{7\pi}{2}\right)=\sin (-\dfrac{\pi }{3})\)

If \(\sin x=\sin y\), then \(x=n\pi +(-1)^ny\).

Over the interval \([0,2\pi]\).

\(x+\dfrac{7\pi}{2}=4\pi-\dfrac{\pi }{3}\) and \(x+\dfrac{7\pi}{2}=5\pi+\dfrac{\pi }{3}\)

\(x=\dfrac{11\pi }{3}-\dfrac{7\pi}{2}\) and \(x=\dfrac{16\pi}{3}-\dfrac{7\pi}{2}\)

\(x=\dfrac{22\pi-21\pi }{6}\) and \(x=\dfrac{32\pi-21\pi }{6}\)

\(x=\dfrac{\pi}{6}\) and \(x=\dfrac{11\pi }{6}\)

Therefore, the two solutions are tex]x=\dfrac{\pi}{6}\) and \(x=\dfrac{11\pi }{6}\).

Answer:

C. π/6 & 11π/6

Step-by-step explanation:

If you graph the equation ( Sin (x+7π/2)=-√3/2) and look between 0 & 2π, you'll see that the lines intersect the x-axis at π/6 & 11π/6.