The magnitude of the resistive force exerted by the air on the airplane is 9.60 N.
To determine the magnitude of the resistive force exerted by the air on the airplane, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
The net force acting on the airplane is the difference between the forward force exerted by the air on the propeller and the resistive force exerted by the air on the airplane.
Net force = Forward force - Resistive force
According to Newton's second law, this net force is also equal to the mass of the airplane multiplied by its acceleration:
Net force = Mass of airplane * Acceleration
Rearranging the equation to solve for the resistive force, we have:
Resistive force = Forward force - Mass of airplane * Acceleration
Plugging in the given values:
Forward force = 10 N
Mass of airplane = 0.20 kg
Acceleration = 2.0 m/s^2
Resistive force = 10 N - 0.20 kg * 2.0 m/s^2
Resistive force = 10 N - 0.40 N
Resistive force = 9.60 N
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3. According to the article, what is an effect
of migration from rural areas to cities?
a Colleges need to hire more faculty.
The country's infrastructure is burdened.
c Citizens are more likely to migrate to other countries.
The percentage of the population living in extreme
poverty goes down.
"The percentage of the population living in extreme poverty goes down." Therefore, option (D) is correct.
Migration from rural areas to cities can have a positive impact on poverty reduction. Urban areas often offer better access to job opportunities, education, healthcare, and social services, which can help individuals and families improve their living conditions.
As people migrate to cities and gain access to these resources, the percentage of the population living in extreme poverty tends to decrease.
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Which of the following equations illustrates the law of conservation of
matter?
A. 4A1 + 302 → 2A1203
B. 4A1 + O2 → 2A1203
C. 2A1 + 02 → A1203
D. 2A1 + 302 → Al2O3
The parent function `f\left(x\right)=\sqrt[3]{x}` is compressed vertically by a factor of `\frac{1}{3}` and then translated 3 units left and 7 units down. What is the transformed function `g\left(x\right)`?
Answer:
The answer is below
Explanation:
Given that f(x) = x√3.
A function can be vertically stretched or compressed by multiplying it by a positive constant. If the constant is greater than 1, it is vertically stretched and if the constant is less than 1 it is vertically compressed.
If a function f(x) = x is compressed or stretched by a constant a, then the new function g(x) = a f(x)
If a function f(x) = x is translated a units down, then the new function g(x) = f(x) - a
If a function f(x) = x is translated a units left, then the new function g(x) = f(x-a)
If f(x) = x√3 is compressed vertically by a factor of 1/3. The new function is
\(f(x)'=x\sqrt{3} *\frac{1}{3} \\\\f(x)'=\frac{x}{3} \sqrt{3}\)
If it is then translated 3 units left and 7 units down, the transformed function g(x) is:
\(g(x)=(\frac{x-3}{3}\sqrt{3} )-7\)
Use direct integration to determine the mass moment of inertia of the uniform thin parabolic plate of mass m about the x-axis and y-axis. Also state the corresponding radius of gyration.Ans:Ixx = (3/7)mh2kx = 0.655hIyy = (1/20)mb2ky = 0.224bYour answer must match the provided answer to receive a positive rating!
The mass moment of inertia of a uniform thin parabolic plate of mass m about the x-axis is given by Ixx = (3/7)m\(h^2\), with a corresponding radius of gyration kx = 0.655h. The mass moment of inertia about the y-axis is Iyy = (1/20)m\(b^2\), with a corresponding radius of gyration ky = 0.224b.
To determine the mass moment of inertia of the uniform thin parabolic plate about the x-axis and y-axis, direct integration can be used. The moment of inertia is a measure of an object's resistance to rotational motion and depends on its mass distribution and axis of rotation.
For the parabolic plate about the x-axis, integrating the mass element dm over the entire plate gives Ixx = ∫(\(y^2\)) dm. Assuming the mass per unit area is constant, dm = ρdA, where ρ is the mass per unit area and dA is an infinitesimal area element. By expressing y in terms of x and solving the integral, the resulting expression is Ixx = (3/7)m\(h^2\), where m is the mass of the plate and h is the height of the plate. The corresponding radius of gyration kx can be calculated as the square root of (Ixx / m).
Similarly, for the y-axis, integrating the mass element dm over the plate gives Iyy = ∫(\(x^2\)) dm. Solving the integral, the expression becomes Iyy = (1/20)m\(b^2\), where b is the base width of the plate. The corresponding radius of gyration ky is calculated as the square root of (Iyy / m).
Therefore, the mass moment of inertia and radius of gyration for the uniform thin parabolic plate about the x-axis and y-axis are as provided: Ixx = (3/7)m\(h^2\), kx = 0.655h, Iyy = (1/20)m\(b^2\), and ky = 0.224b.
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What Factor(s) determine the strength of an electric field between two objects?
A. The type of charge on the objects.
B. The amount of charge on the objects.
C. The distance between the objects.
D. B and C
Answer:
D. B and C
Explanation:
from the formular
\(E = \frac{kQ}{ {r}^{2} } \)
Q: is magnitude or amount of charge.
r: is the separation distance.
addition to acceleration, what do you need to know to calculate inertial mass?
Inertial mass is calculated by multiplying acceleration by the mass of the object. Therefore, to calculate inertial mass, you need to know the acceleration of the object, as well as its mass.
What is object ?
Objects are physical or conceptual entities that can be identified, represented, and manipulated. In computing, objects are pieces of data that have properties and associated behaviors that allow them to interact with other objects in the system.
Examples of objects include files, images, text, numbers, and people. Objects have unique identities and can be manipulated according to a set of rules or protocols. In object-oriented programming, objects are encapsulated collections of data and methods that interact with each other. Objects can be thought of as “black boxes” that contain both data and instructions on how to access and manipulate it. Objects are used to create applications and services that are efficient, scalable, and easy to maintain.
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A spring is stretched 5 cm from its equilibrium position. If this stretching requires 30 J of work,
what is the spring constant?
Answer:
Best answer will get Brainliest!!!
What is the volume scaled down by a factor of 1/10
Measurements:
Top: 7 in, both sides: 12 in, front: 12 in, back: 12 in, bottom: 7 in
Please help!
Explanation:
Wind, moving water, sunlight, and heat from earth's interior are sources of
Two sources emit waves that are in phase with each other. what is the largest wavelength that will give constructive interference at an observation point 141 m from one source and 295 m from the other source?
The largest wavelength that will give constructive interference at the observation point is 154 meters.
To determine the largest wavelength that will give constructive interference at an observation point equidistant from two sources, we can use the concept of path difference.
Constructive interference occurs when the path difference between the two sources is an integral multiple of the wavelength (λ) of the wave.
In this case, the observation point is equidistant from both sources, so the path difference (Δx) can be calculated as
Δx = |distance from source 1 - distance from source 2|
Given:
Distance from source 1, d1 = 141 m
Distance from source 2, d2 = 295 m
Δx = |141 m - 295 m|
Δx = 154 m
To achieve constructive interference, the path difference (Δx) must be an integer multiple of the wavelength (λ). Therefore
Δx = N * λ,
Where N is an integer.
The largest wavelength that will give constructive interference corresponds to the smallest value of N. In this case, N = 1
So, λ = Δx / N = 154 m / 1 = 154 m.
Therefore, the largest wavelength that will give constructive interference at the observation point is 154 meters.
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I'LL MARK U BRAINLIST!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A train travels 1000 m south for 100s what is the velocity of the train
Answer: 10m/s
Explanation:
Matter can undergo chemical reactions and nuclear reactions. Which property is conserved in nuclear reactions?
Answer:
Explanation:
In a chemical reaction, table sugar (sucrose) is mixed with sulfuric acid. The result of the reaction is a towering black structure of elemental carbon, water vapor, carbon dioxide, and sulfur dioxide gases.
Answer: total mass number
Explanation:
If you decide you want to meet someone you met online, what should you do first?
A. Tell your best friend.
B. Call the person you met online on the phone.
C. Tell your parents
D. Set up a meeting place.
c tell your parents it could be someone very dangerous and meeting people online can be very risky I would also tell my bsf just for fun tho
A set of charged plates have an
area of 8.22*10^-4 m^2 and
separation 2.42*10^-5 m. The
plates are charged with
5.24*10^-8 C. What is the
potential difference V between
the plates?
(Unit = V)
pls hurry <3
Answer:
175
Explanation:
its for Acellus
The potential difference is V=1.743*10^-7
The voltage is generally referred to as the electric potential difference and it can be measured using a voltmeter. The electrical potential difference between the two plates is expressed as q=CV.
CALCULATION
we know,
q=CV
q={EA/d}*V
here q= 5.24*10^-8C
A=8.22*10^-5m^2
d=2.42*10^-8m
therefore , C={( 8.85*10^-12)*(8.22*10^-5)}/(2.42*10^-8)
C=3.006*10^-1
q=CV
q/C=V
V=1.743*10^-7
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which of te following statmenst must be true for an object moving in constant velocity in a straight line
For an object moving in constant velocity in a straight line, the following statements must be true:
1. The object is not experiencing any acceleration.
2. The object's speed remains constant.
3. The object's direction of motion remains constant.
4. The net force acting on the object is zero.
5. The object's displacement is directly proportional to the time elapsed.
It is said that if an object is moving with constant velocity, then there is no force acting on it. If an object is moving with constant velocity, then a force has to act on the object to make the object move at constant velocity.
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the diagram shows a diver underwater.680N,600N
The resultant force that is acting on the diver is 80N.
What is the resultant?We know that the idea of the resultant force is that it is the kind of force that is the result of the action more than one force acting on an object. As such, the resultant force is the effective force that acts on an object that under the action of a given system of forces.
Now we can see that there is an upward and a downward force that is acting on the diver as we can see and the forces are in opposite direction thus the resultant of the forces can be obtained by subtraction. The resultant force is obtained as; 680 N - 600 N= 80N
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I need help in this please
Answer:the answer is b
I’m Sarah and I got bit by a vampire
ok? EXPLAIN PLS
Explanation:
how do the light-collecting area and best possible angular resolution of telescope with a 10-meter diameter mirror compare to that of a telescope with a 5-meter diameter mirror?
Angular resolution and light-collecting area:
The light-collecting area of a telescope is the amount of light that the mirror can collect. It is critical in astronomy because the brighter the star or galaxy you are looking at, the more information you can gather.
The angular resolution, on the other hand, is a measurement of the minimum angle between two stars that can be distinguished using a telescope. A high angular resolution means that you can see objects more clearly.
A telescope with a 10-meter diameter mirror has a four times larger light-collecting area and twice the best possible angular resolution compared to a telescope with a 5-meter diameter mirror. Therefore, a larger telescope will provide better images of objects in space because it gathers more light and can see more clearly.
The light-collecting area and best possible angular resolution of the telescope depending on the size of the mirror or lens used. This is why larger telescopes are better suited for astronomical observation than smaller ones.
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10 kg ball rolls off a 5 m high cliff traveling at 2 m/s. if it lands on a spring with a spring constant of 10,000 N/m, how far can it compress the spring? (assume the spring is pointed in the direction of the ball)
Answer:
Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)
Explanation:
In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.
Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).
Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).
Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:
\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).
With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:
\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).
Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).
All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.
It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:
\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).
Solve for the displacement of the spring, \(x\):
\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).
If an Isotope has a Half-life of minutes. How many Half-life's have occurred after 24 minutes?
Answer:12
Explanation:
show how three identical 6 resistors must be connected tho have the following effective resistance values 9 and 4 ohms
Answer:
connect two 9 ohms resistance in series now it becomes 18 ohm
A car that is standing still accelerates up a hill with a slope of 6.4% at an average acceleration of 2.93 ft/s^2. The hill is 12.42 miles long, and the final velocity of the car is 203 mph. How long does it take for the car to climb to the top of the hill?
Answer:
213 s
Explanation:
Slope is the ratio of change in vertical distance to change in horizontal distance.
Slope = vertical height / horizontal height
Therefore:
6.4% = vertical height / 12.42
vertical height = 6.4% * 12.42
vertical height = 0.8 miles
The distance travelled by the car (s) is:
s² = 0.8² + 12.42²
s² = 154.9
s = 12.45 miles
Acceleration (a) = 2.93 ft/s^2 = 0.00055 mile/s²
initial velocity (u) = 0, final velocity = 203 mph
Using:
s = ut + 0.5at²
12.45 = 0.5(0.00055)t²
t =213 s
what is the primary component of venus' atmosphere?
The primary component of Venus' atmosphere is carbon dioxide (CO2).
Carbon dioxide constitutes the majority of the planet's atmosphere, accounting for approximately 96% of its composition.
The thick atmosphere of Venus creates a strong greenhouse effect, trapping heat and leading to extreme surface temperatures that can exceed 450 degrees Celsius (870 degrees Fahrenheit).
The high concentration of carbon dioxide contributes to the intense greenhouse effect on Venus, making it the hottest planet in our solar system despite being farther from the Sun than Mercury.
In addition to carbon dioxide, Venus' atmosphere contains trace amounts of other gases such as nitrogen, sulfur dioxide, and water vapor.
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An air conditioner costs $13.50 to run for nine hours a day. If the thermostat temperature was adjusted so that the air conditioner would be on only five hours a day, how much money would be saved daily
Adjusting the thermostat to reduce the air conditioner usage to five hours a day would save $7.50 daily.
The cost to run the air conditioner for nine hours a day is $13.50. To find the cost per hour, we can divide the total cost by the number of hours: \(\frac{13.50}{9} = $1.50 per hour\).
If the air conditioner is only running for five hours a day, the daily cost would be 5 hours × $1.50 per hour = $7.50.
By adjusting the thermostat to reduce the air conditioner usage from nine hours to five hours, there would be a daily saving of $7.50. This reduction in operating time leads to decreased energy consumption, resulting in cost savings. It's important to note that these calculations assume a consistent electricity rate and do not consider other factors such as seasonal variations, maintenance costs, or the specific energy efficiency of the air conditioner.
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1. What happens to an atom when it gains electrons? *
Answer: An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion
Answer:
when an atom gains electrons, it gains a negative charge
Explanation:
hope I helped you
Please help
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Track and field champion changed his sport career not once but twice during his young life.
OA. Larry Bird
O B. Dwain Chambers
Oc. Bob Wiley
OD Darren Bornstop
Answer:
Darren Bornstop (real name is Darren Campbell)
how many atoms are in one mole of potassium
In the diagram, q1= -2.60*10^-9 C and
q2 = -8.30*10^-9 C. Find the magnitude
of the net electric field at point P.
Answer:
The magnitude of the net electric field is:
\(E_{net}=90.37\: N/c\)
Explanation:
The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).
On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).
Knowing this, the magnitude of the net electric field will be the E1 + E2.
Let's find first E1 and E2.
The electric field equation is given by:
\(|E_{1}|=k\frac{|q_{1}|}{d_{1}^{2}}\)
Where:
k is the Coulomb constant (k = 9*10^{9} Nm²/C²)q1 is the first charge d1 is the distance from q1 to P\(|E_{1}|=(9*10^{9})\frac{|-2.60*10^{-9}|}{0.538^{2}}\)
\(|E_{1}|=80.84\: N/C\)
And E2 will be:
\(|E_{2}|=k\frac{|q_{2}|}{d_{2}{2}}\)
\(|E_{2}|=(9*10^{9})\frac{|-8.30*10^{-9}|}{1.36^{2}}\)
\(|E_{2}|=40.39\: N/C\)
Finally, we need to use the Pythagoras theorem to find the magnitude of the net electric field.
\(E_{net}=\sqrt{E_{1}^{2}+E_{2}^{2}}\)
\(E_{net}=\sqrt{80.84^{2}+40.39^{2}}\)
\(E_{net}=90.37\: N/c\)
I hope it helps you!
Answer:
+90.3 N/C
Explanation:
acellus
An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?
The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,
F = kx
Therefore,
k = F/x
We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,
K = 50.174/0.25 N/m
K = 200.696 N/m
Therefore, The Spring Constant is 200.696 N/m
On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:
h = \(1/2 kx^{2}\)
We know that k=200.696 N/m and x=0.25 m. Therefore the height is:
h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)
h = 2.5087 m
Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
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