The amount of thermal energy transferred between objects depends only on their masses and initial and final temperatures.
Question 17 options:
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Four electrons are placed at the corner of a square

So we will first find the electrostatic potential at the center of the square

So here it is given as

here

r = distance of corner of the square from it center

now the net potential is given as

now potential energy of alpha particle at this position

Now at the mid point of one of the side

Electrostatic potential is given as

here we know that

now potential is given as

now final potential energy is given as

Now work done in this process is given as

We have that Work is done by the Coulomb force when the alpha particle moves to the midpoint of one of the sides of the square

From the question we are told

Four electrons are located at the corners of a square 10.0 nm on a side, with an alpha particle at its midpoint.  

How much work is done by the Coulomb force when the alpha particle moves to the midpoint of one of the sides of the square 

Generally the equation for the Work done  is mathematically given as

\(W=2kqQ\frac{2}{r1}-\frac{1}{r2}-\frac{1}{r3}\\\\\ W=2*8,99*10^9*-1.6*10^{-19}* -1.6*10^{-19} (\frac{2}{5*10^{-9}+5*10^{-9}}-\frac{1}{5*10^{-9}}-\frac{1}{10*10^{-9}+5*10^[-9]})\)

Therefore

Work is done by the Coulomb force when the alpha particle moves to the midpoint of one of the sides of the square

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Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question we have

force = 8.5 × 9.8

We have the final answer as

Hope this helps you

Answer:

The frequency of the coil is 7.07 Hz

Explanation:

Given;

number of turns of the coil, 200 turn

cross sectional area of the coil, A = 300 cm² = 0.03 m²

magnitude of the magnetic field, B = 30 mT = 0.03 T

Maximum value of the induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

Where;

ω is angular frequency = 2πf

E = NBA(2πf)

f = E / 2πNBA

f = (8) / (2π x 200 x 0.03 x 0.03)

f = 7.07 Hz

Therefore, the frequency of the coil is 7.07 Hz

Answer:

B = 0.025T

Explanation:

In order to calculate the strength of the magnetic field at the center of the solenoid, you use the following formula:

\(B=\frac{\mu N i}{L}\)         (1)

μ: magnetic permeability of vacuum = 4π*10^-7 T/A

N: turns of the solenoid = 500

i: current = 4.0A

L: length of the solenoid = 0.10m

You replace the values of the parameters in the equation (1):

\(B=\frac{(4\pi*10^{-7}T/A)(500)(4.0A)}{0.10m}=0.025T\)

The strength of the magnetic field at the center of the solenoid = 0.025T

Answer:

Magnetic field strength at the center is 2.51x10^-2T

Explanation:

Pls see attached file for step by step calculation

Answer:

kilogram

In the International System of Units (SI), the kilogram is the basic unit of mass, and the newton is the basic unit of force. The non-SI kilogram-force is also a unit of force typically used in the measure of weight.

False, their national space organization receives a significant amount of funding if they lead the mission.

The team typically sends about 30,000 remote control commands from the ground to the space station to manage the platform. Highly interactive, hands-on, tactile, and highly rewarding.

A mission control center (MCC, sometimes called a flight control center or operations center) is a facility that typically manages spaceflight from the launch point to landing or the end of the mission. This is part of the ground segment of spacecraft operations.

The station serves as a microgravity and space laboratory where scientific research in fields such as astrobiology, astronomy, meteorology, and physics is conducted.

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The average velocity of the car during this 20 sec interval is 1.5 m/s.

Given that,

A car travels 50 metres due north in 15 seconds then car turns around the and travels 20 metres due south in 5 second.

To find :

The magnitude of the average velocity of the car during this 20 seconds interval.

Initial velocity

u = 50 metres/15 = 3.33 m/s

Final velocity

v = 20 metres/5 = 4 m/s

Displacement of car is

Displacement = 50 - 20 = 30 metres

Let V is the velocity of the car during this 20 sec interval. We know that the average velocity is given by :

V = d/t

V = 30 metres/20 = 1.5 m/s

So, the average velocity of the car during this 20 sec interval is 1.5 m/s.

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Answer:

Explanation:

mass (m) = 65 kg

velocity (v) = 4.6 m/s

Kinetic energy (KE)

= 1/2 * m * v²

= 1/2 * 65 * 4.6²

=  687.7 J

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Answer:

Because they are denser.

Explanation:

Remember: the denser something depends on both its mass and volume. A higher mass will make a denser object. Likewise can be said for volume.

There is decreased pressure on the air molecules as one moves higher and the air is thinner

We know that the air pressure decreases with height. This implies that the air is thinner as you move up to higher altitude. This is the idea behind the use of the phrase; "Thin air".

Now, owing to the fact that there is decreased pressure on the air molecules as one moves higher and the air is thinner, it is much harder to breath until her aunt adjusts to the higher altitude.

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

The Great Pyramid of Giza (also known as the Pyramid of Khufu or the Pyramid of Cheops) is the oldest and largest of the pyramids in the Giza pyramid complex bordering present-day Giza in Greater Cairo, Egypt.It is the oldest of the Seven Wonders of the Ancient World, and the only one to remain largely intact.

Explanation:

Answer:

Explanation:

airspeed is speed with respect to air .

Let speed of airplane with respect to ground be V .

wind is blowing east at 55 km/h

airplane is heading north with speed V

Resultant of V and 55 km /h is 230 km/h

V² + 55² = 230²

V² = 52900 - 3025

V = 223.32 km/h

Let θ be the required angle

Tanθ = 55 / 223.32 = .246

θ = 14⁰ .

Answer:

v' = -18 m/s

Explanation:

       \(p_{o} = p_{f} (1)\)

       \(m_{b} * v_{b} -M_{c}*V_{c} = m_{b} * 18 m/s + (-M_{c}* 20 m/s) (2)\)

        \(-(m_{b} * v'_{b}) + M_{c}*V'_{c} (3)\)

       \(-(m_{b} * v'_{b}) +(- M_{c}*V_{c}) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (4)\)

       \(m_{b} * 18 m/s + (-M_{c}* 20 m/s) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (5)\)

Answer:

Momentum is a term used in physics to describe an object's resistance to change its motion. It is a measure of an object's mass and velocity and can be mathematically represented by the equation p = mv, where p is momentum, m is mass, and v is velocity.

Momentum is a vector quantity, meaning it has both magnitude and direction. It can be thought of as the amount of motion an object possesses in a particular direction. For example, a large truck traveling at a high speed has more momentum than a small car traveling at a slower speed, even though they both may have the same mass.

In physics, momentum plays a crucial role in determining how objects will react when they collide. If two objects collide and have equal and opposite momentum, they will typically bounce off each other. However, if one object has much more momentum than the other, it is likely to push the other object aside and continue on its original path.

It is also important to note that momentum is conserved in isolated systems. This means that if two or more objects collide or interact with each other, the total momentum before the collision is equal to the total momentum after the collision.

In conclusion, momentum is a fundamental concept in physics that helps to describe and understand the motion of objects. It is a combination of an object's mass and velocity, and it determines how objects will interact when they collide.

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Answer:

1.25 g/cm^3

Explanation:

mass-30.0g

volume- 4cm×2cm×3cm=24cm^3

density?

*to find density

Density=Mass/Volume

=30÷24

=1.25g/cm^3

Answer:

34.24 %

Explanation:

Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.

The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.

Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°

Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.

So,  I₄ = I₃cos²10°

I₄ = I₂cos²22°cos²10°

I₄ = I₁cos²25°cos²22°cos²10°

I₄ = (I₀/2)cos²25°cos²22°cos²10°

I₄/I₀ = cos²25°cos²22°cos²10°/2

I₄/I₀ = (cos25°cos22°cos10°)²/2

I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2

I₄/I₀ = 0.8275²/2

I₄/I₀ = 0.6848/2

I₄/I₀ = 0.3424

So, as a percentage,

I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %

Answer:

10-

Explanation:

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\(\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}\)

We would calculate the magnitude by applying pythagorean theorem:

\(\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}\)

\(\longrightarrow \sf{Magnitude = 33.12}\)

\(\longrightarrow \sf{The \: vector \: is \: (- 14, 30)}\)

The angle between two vectors is given by the formula:

\(\sf{\longrightarrow \small \cos \emptyset = \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }\)

In two dimensional, the x axis of vector form is:

\(\small\sf{\longrightarrow (b1, b2) = (1, 0) }\)

\(\sf{\longrightarrow \small \cos \: \emptyset = \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }\)

\(\small\longrightarrow \sf{ \dfrac{14}{33.12} }\)

\(\small\longrightarrow \sf{\emptyset \: = arcCos (\dfrac{ - 14}{33.12} )}\)

\(\small\longrightarrow \sf{\emptyset= 115^\circ}\)

\(\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}\)

\( \small\bm{The \: angle \: between \: the \: vector \: }\)

\(\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}\)

The speed of the ball rebounding from the plate is approximately 13.2 m/s.

According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.

The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.

The speed of the ball rebounding can be calculated using the formula:

(1/2)mv²= (1/2)mv_0²

where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).

Solving for v, we get:

v = sqrt(v_0² - (2F/m))

where F is the maximum force exerted on the force plate (1900 N).

Plugging in the values, we get:

v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s

Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.

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Kepler's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. ... The resulting shape will be an ellipse. An ellipse is a special curve in which the sum of the distances from every point on the curve to two other points is a constan

Answer:

Gravitational potential energy

kinetic energy

The total energy of all the particles makes up thermal energy. This implies that larger objects with slower-moving particles at low temperatures can have more energy than smaller ones with higher temperatures.

Thermal energy is the sum of the energies of all the particles. This implies that larger objects at low temperatures can have more energy than smaller ones at higher temperatures due to slower-moving particles.

These molecules and atoms move more quickly when something is heated, providing it with more thermal energy. Compared to cold water, hot water has more thermal energy.

Therefore, molecules and atoms in colder objects move more slowly and have less thermal energy than those in warmer ones. The ability of particles to transfer energy increases with speed.

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The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

First, we shall obtain the initial kinetic energy. Details below:

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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Answer: b

Explanation:

Answer:

For every action there is an opposite reaction.

Explanation: