The angle of elevation of a jet is 43° and 62° from two locations 28.5km apart. Calculate the height of the jet.​

The distance from the point directly below the edge of the table that the ball will land on is 106.132cm.

From the information, we are told that the small bill rolls at 16cm/s and falls off the edge of a table 80cm high.

The distance from the point directly below the edge of the table that the ball will land on will be:

Using h = 1/2gt²

The time will be:

= ✓(2 × 80/9.8)

= ✓160/9.8

= ✓16.66

= 4.082

The distance will now be:

= Speed × Time

= 26 × 4.082

= 106.132

Therefore, the distance from the point directly below the edge of the table that the ball will land on is 106.132cm.

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Step-by-step explanation:

Here ,

Length = 7 cm

breadth = 3 cm

height = 10 cm

Volume = ?

Now ,

Volume ( v ) = l × b × h

= 7 cm × 3 cm × 10 cm

\( = 210 {cm}^{3} \)

The correct conclusion is that the mean hemoglobin of pregnant women in the second and third trimester differs (p-value < 0.05).

Based on the comparison of Hemoglobin, Hematocrit, and HbA1c levels between pregnant women in the second and third trimester, the researchers found that there is a statistically significant difference in the mean hemoglobin levels. This conclusion is supported by a p-value that is less than the typical significance level of 0.05. The specific p-value is not provided in the question, but it is implied that it is smaller than 0.05. Therefore, the researchers can reject the null hypothesis and conclude that there is a significant difference in the mean hemoglobin levels between the second and third trimester of pregnancy.

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Answer:

B

Step-by-step explanation:

you would just divide 37 from 8659

 713   

1,000

Hope this helps!

Answer:

B

Step-by-step explanation:

3 5/5 = 4 because 5/5 is equal to 1, and 3+1 = 4.

1/4 is not equal to 4 because it is equal to 0.25

4/1 = 4 because it is an identity

3 4/4 = 4 because 4/4 is equal to 1, and 3+1 = 4

Answer:

Radius is 4.297

Step-by-step explanation:

Hieght=5

Surface Area=251

Answer:

Its r = 3.99898596 in

Step-by-step explanation:

It should be the answer if the volume is 251.2. But it confuses people like is it 251 2 or 251.2. Hope that helps

It represents a linear positive correlation between x and y −0. 999.

Given

The table shows Britney's distance, in miles, from her destination after different time intervals in hours:

Time (hours) (x) 2 4 1 3 6 5 7

Distance from destination (miles) (y) 1,000 880 1,060 940 760 820 690

A number between +1 and −1 is calculated so as to represent the linear interdependence of two variables or sets of data.

Then,

The correlation coefficient for the data, and what does it represent is;

It represents no correlation between x and y.

Hence, it represents a linear positive correlation between x and y −0. 999.

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Option c 15.8% is the required rate of return for Warp-O common stock.

Given,

The market price of share = $45

Beta = 1.4

The rate of return on Treasury bonds = 6%

Market rate of return = 13%

We have to find the required rate of return on Warp-O common stock;

Here,

Rate of return = The rate of return on Treasury bonds + beta × (market rate of return -The rate of return on Treasury bonds  )

= 6% + 1.4 × (13% - 6%)

= 6% + 1.4 ×7%

= 6% + 9.8%

= 15.8%

That is,

The required rate of return on Warp-O common stock is option c 15.8%

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The possible values for the given series, the interval notation will be calculated as follows:

Sn is the sum of a geometric series, and a1/(1-r).

R = x a1 = 4 in this mathematical sequence.

If you want the sum to be higher than 8, enter:.

r cannot equal 1 (the equation would have 0 in the denominator) and it cannot be GREATER than one. 8 1/2 Interval notation: (1/2, 1). We must limit it to 1. as the series becomes divergent and lacks a sum if it does.

Interval arithmetic is a general numerical computing technique that automatically generates guaranteed enclosures for arbitrary formulas, even in the presence of uncertainties, mathematical approximations, and arithmetic roundoff. Intervals are at the center of this technique.

The definition of intervals also applies to arbitrary totally ordered sets, such as integers or rational numbers. In the special section that follows, the notation of integer intervals is discussed.

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Note that the full question is:

The value of the series 4+4x+4x^2+4x^3... is a real number greater than 8. Find all possible values of x, giving your answer in interval notation.

Find  1+ 1/2+1/6+1/12 , where we alternately multiply by 1/2 and 1/3 to get the next term.

In a certain infinite geometric series, the first term is 1, and each term is equal to the sum of the two terms after it. (For example, the first term is equal to the sum of the second term and third term). If s is the sum of the series and r is the common ratio, find s - r.

Answer:

\(\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}\)

Step-by-step explanation:

We can use the following trigonometrical identity:

\(\sin (\alpha - \beta) = \sin \alpha \cdot \cos \beta - \cos \alpha \cdot \sin \beta\) (1)

Where \(\alpha\), \(\beta\) are angles, measured in sexagesimal degrees.

If we know that \(\alpha = 135^{\circ}\) and \(\beta = 30^{\circ}\), then the value of the given function is:

\(\sin 105^{\circ} = \sin 135^{\circ}\cdot \cos 30^{\circ} - \cos 135^{\circ}\cdot \sin 30^{\circ}\)

\(\sin 105^{\circ} = \left(\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{\sqrt{3}}{2}\right)-\left(-\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{1}{2}\right)\)

\(\sin 105^{\circ} = \frac{\sqrt{6}}{4}+\frac{\sqrt{2}}{4}\)

\(\sin 105^{\circ} = \sqrt{\frac{6}{16} }+\sqrt{\frac{2}{16} }\)

\(\sin 105^{\circ} = \sqrt{\frac{3}{8} }+\sqrt{\frac{1}{8} }\)

\(\sin 105^{\circ} = \frac{\sqrt{3}+1}{2\cdot \sqrt{2}}\)

\(\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}\)

Answer: D) sqrt(2 + sqrt3)/2

Step-by-step explanation: Nah

The measured signal could have a dynamic error of approximately 21.6% of the true value due to the limitations of the 1st order system with a time constant of 0.7 seconds.

The dynamic error that could result from measuring a 2 Hz periodic waveform using a 1st order system with a time constant of 0.7 seconds can be estimated using the following formula:

Dynamic error = 100% x (1 - exp(-T/τ)),

where T is the period of the input signal, τ is the time constant of the system, and exp(-T/τ) is the system's gain at the input frequency.

Substituting T = 0.5 s (since the period of a 2 Hz waveform is 0.5 seconds) and τ = 0.7 s, we get:

Dynamic error = 100% x (1 - exp(-0.5/0.7)) ≈ 21.6%

This means that the measured signal could have a dynamic error of approximately 21.6% of the true value due to the limitations of the 1st order system with a time constant of 0.7 seconds. This error is due to the fact that the system cannot respond fast enough to the rapid changes in the input signal, leading to an output that lags behind the input. The larger the time constant of the system relative to the period of the input signal, the larger the dynamic error will be.

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The experimental probability that the next time Audra rolls the number cube, she will roll a 2 is 3/22.

Experimental probability is the ratio of the number of times an event occurs to the total number of trials conducted. In this case, we want to find the experimental probability of rolling a 2.

Looking at the data provided, we can see that Audra rolled a 2 three times out of the total 22 rolls. So, the experimental probability of rolling a 2 can be calculated as:

Experimental probability = number of times the event occurred / total number of trials

Experimental probability of rolling a 2 = 3 / 22

Therefore, the correct option is (B) 3/22. This means that based on Audra's experiment, the probability of rolling a 2 is approximately 0.136 or 13.6%. It is important to note that this is the experimental probability based on a small sample size, and the actual probability of rolling a 2 in a large number of rolls may differ.

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The distance between the two points is 10 units

From the question, we have the following parameters that can be used in our computation:

A = (13, 2) and B =(7, 10)

The distance between the two points can be calculated using the following distance equation

distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Where

(x, y) = (13, 2) and (7, 10)

Substitute (x, y) = (13, 2) and (7, 10) in distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

distance = √[(13 - 7)² + (2 - 10)²]

Evaluate

distance = 10

Hence, the distance is 10 units

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Based on the given data, we can calculate the control limits using 3-sigma for the diameter of the auto pistons.

a) The value of x is 155.56 mm (rounded to two decimal places).

b) The value of R is 4.44 mm (rounded to two decimal places).

c) Using 3-sigma, the Upper Control Limit (UCL) for the diameter is calculated as:

UCL = x + 3R = 155.56 + 34.44 = 156.93 mm (rounded to two decimal places)

The Lower Control Limit (LCL) for the diameter is calculated as:

LCL = x - 3R = 155.56 - 34.44 = 154.19 mm (rounded to two decimal places)

d) Using 3-sigma, the Upper Control Limit for the Range (UCLR) is calculated as:

UCLR = D4 * R = 2.115 * 4.44 = 7.89 mm (rounded to two decimal places)

The Lower Control Limit for the Range (LCLR) is always 0 in this case since negative ranges are not possible.

e) If the true diameter mean should be 155 mm, the new centerline (nominal line) would be 155 mm. In this case, the UCL and LCL would be calculated using 3-sigma as follows:

UCL = Nominal + 3R = 155 + 34.44 = 156.37 mm (rounded to two decimal places)

LCL = Nominal - 3R = 155 - 34.44 = 153.63 mm (rounded to two decimal places)

Please note that the control limits calculated using 3-sigma assume a normal distribution and the data follows the same pattern in the future.

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The complete question is:

What is the value of x? = x= 155.56 mm (round your response to two decimal places). b) What is the value of R? R= 4.44 mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Upper Control Limit (UCL) = 156.93 mm (round your response to two decimal places). Lower Control Limit (LCL) = 154.19 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)= 7.89 mm (round your response to two decimal places). Lower Control Limit (LCLR)= 0.99 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want this as your center (nominal) line, what are the new UCL and LCL? Upper Control Limit (UCL)= 156.37 mm (round your response to two decimal places). Lower Control Limit (LCL;)= 153.63 mm (round your response to two decimal places). Refer to Table 56.1-Factors for Computing Control Chart Limits (3 sigma) for this problem Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day 1 2 3 4 5 Mean x (mm) 150.9 153.2 153.6 153.5 154.6 Range R (mm) 4.0 4.8 4.1 4.8 4.5

Answer:

e. 2x - 7y = 31.

Step-by-step explanation:

If you want a line parallel to the equation, the line must have the same slope.

2x - 7y = 9

-7y = -2x + 9

y = 2/7x - 9/7

You are looking for a line where the slope is 2/7.

a. Slope is 7/2.

b. Slope is -7/2.

c. Slope is 7/2.

d. Slope is...

y + 2 = 3/4x + 3

y = 3/4x + 1

Slope is 3/4.

e. Slope is -2/-7, which is 2/7. Just make sure to check whether it passes through (5, -3) by substituting those points into the equation.

2 * 5 - 7 * -3 = 31

10 --21 = 31

10 + 21 = 31

And there's your answer: e.

Hope this helps!

The explicit formula for f^-1 is (x-3)^(1/4) and this is obtained by switching the roles of x and y and solving for y in terms of x.

To find the inverse function of f(x)=x^4+3, we need to switch the roles of x and y, and solve for y.
Let y = x^4+3
Subtract 3 from both sides to get:
y - 3 = x^4
Take the fourth root of both sides to isolate x:
(x^4)^(1/4) = (y-3)^(1/4)
Simplify:
x = (y-3)^(1/4)
So the inverse function of f(x) is:
f^-1 (x) = (x-3)^(1/4)
This is the explicit formula for the inverse function of f(x).
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The lab should budget for the next year's rat orders be $63,700.00.

The lab orders 100 rats a week for each of the 52 weeks in the year for experiments that the lab conducts.

The prices for 100 rats follow the given distribution:

Price ($): 10.00, 12.50 , 15.00

Probability: 0.35 0.40 0.25

Mean price per 100 rats can be calculated using the expected value formula,

μx = ∑ [ xi × P(xi) ]

where

μx = mean value,

xi = price,

P(xi) = probability of xi

Mean price per 100 rats:

μx = (10.00 × 0.35) + (12.50 × 0.40) + (15.00 × 0.25)

μx = 3.50 + 5.00 + 3.75

μx = $12.25

The mean price per 100 rats is $12.25.

Hence, the cost of 100 rats is $12.25.

Therefore, the lab should budget for the next year's rat orders:

$12.25 × 100 × 52

= $63,700.00

The lab should budget for the next year's rat orders be $63,700.00.

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Explanation:

The figure shows us ...

  AB ≅ DB

  ∠ABC ≅ ∠DBC

  CB ≅ CB

In order, these are Side, Angle, Side in one triangle being shown congruent to corresponding Side, Angle, Side in the other triangle. This lets us conclude that ...

  ΔABC ≅ ΔDBC by SAS

The point in the form (1, y, z) that is equivalent to the given points is (1, 3/5, 3/5).

To find all the points in the form (1, y, z) that are equivalent to the points (2, -1, 0) and (0, -2, 1), we can use the concept of vector equivalence.

Let's consider the vector from (1, y, z) to (2, -1, 0). This vector is (2-1, -1-y, 0-z) = (1, -1-y, -z).

Similarly, the vector from (1, y, z) to (0, -2, 1) is (0-1, -2-y, 1-z) = (-1, -2-y, 1-z).

Since these two vectors are equivalent, we can set them equal to each other:

(1, -1-y, -z) = (-1, -2-y, 1-z)

Simplifying this equation, we get:

y - z = 0

2y + 3z = 3

Therefore, all points in the form (1, y, z) that are equivalent to the given points are given by the equations:

y = z

2y + 3z = 3

Solving this system of equations, we get:

y = 3/5

z = 3/5

So the point in the form (1, y, z) that is equivalent to the given points is (1, 3/5, 3/5).

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Answer:

k equals 8

Step-by-step explanation:

Answer: slope = 21, y-int = 15

Step-by-step explanation:

f(x) = -7x + 9

g(x) = -7(x + 2) + 9 = -7x - 5

h(x) = -3(-7x - 5) = 21x + 15

slope = 21

y-intercept = 15

hope this helps (not sure if my answer is correct)

Answer: 24

Step-by-step explanation:

Answer:

x= 7

Step-by-step explanation:

add (12x+1) and (5x-3) which becomes 17x-2 and then set that equal to 117 and solve. move the 2 to the right side of the equation which becomes 17x=119 and then divide 119 by 17 which x equals 7.

plug in 7 for x to make sure you get 117

If population grew by 5% from 2010 to 2015 and fell by 3% from 2015 to 2020 , then the population decrease from 2015 to 2020 is 6678    .

Let the population of the city in 2015 be = "p".

To find the population in year "2015" , we first find the growth from 2010 to 2015  ;

⇒ p = 212000×(1 + 0.05) = 212000 × 1.05 = 222600 ;

So, the population in 2015 was 222600 .

Next, we find the population in 2020 by applying the decrease of 3%:

⇒ p = 222600×(1 - 0.03) = 222600×0.97 = 215922

So, the population in 2020 was 215922.

To , find the decrease from 2015 to 2020, we subtract the population in 2020 from the population in 2015 ;

⇒ 215922 - 222600 = -6678

Therefore , the population of the city decreased by 6678 people from 2015 to 2020.

The given question is incomplete , the complete question is

In 2010, the population of a city was 212000. From 2010 to 2015, the population grew by 5%. From 2015 to 2020, it fell by 3%. How much did the population decrease from 2015 to 2020, to the nearest 100 people ?

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Answer:  

4 8/6

Step-by-step explanation:

That should be your answer

Answer:

58

Step-by-step explanation:

Put the numbers in chronological order and find the middle number

0, 0, 38, 47, 58, 65, 78, 99, 227

Helping in the name of Jesus.

Answ3r:

81x^2

Step-by-step explanation

I think

Answer:

x=0

Hope this helped!!!! :)

Answer:

Ummm

Step-by-step explanation:

This is confusing

Answer:

very confusing

Step-by-step explanation:

explainahh

A normal sampling distribution can be used for testing the claim. The hypotheses are stated as Hp: p ≤ 0.37, Ha: p > 0.37.

To determine whether a normal sampling distribution can be used to test the claim, we need to verify if the conditions for using a normal approximation are satisfied. The conditions are as follows:

Random Sample: The sample should be selected randomly from the population.

Independence: The sample observations should be independent of each other.

Sample Size: The sample size should be sufficiently large, typically requiring np ≥ 10 and n(1-p) ≥ 10, where n is the sample size and p is the estimated population proportion.

Given the information provided:

Claim: p > 0.45 - 0.08

Sample statistics: p = 0.40, n = 130

To determine if a normal sampling distribution can be used, we can check the sample size condition:

Calculate np and n(1-p):

np = 130 * 0.40 = 52

n(1-p) = 130 * (1 - 0.40) = 78

Since both np (52) and n(1-p) (78) are greater than 10, the sample size condition is satisfied.

Therefore, we can conclude that a normal sampling distribution can be used for testing the claim.

Next, we need to state the hypotheses for testing the claim.

H0: p ≤ 0.37 (Null hypothesis)

Ha: p > 0.37 (Alternative hypothesis)

Based on the claim, we are testing if the population proportion (p) is greater than 0.37.

Therefore, the correct choice for stating the hypotheses is:

OC. Hp: p ≤ 0.37, Ha: p > 0.37

To further analyze the data and test the claim, we can perform a hypothesis test using the sample proportion and significance level (α = 0.05).

We can calculate the test statistic, which in this case is a z-score:

z = (p - p0) / sqrt((p0 * (1 - p0)) / n)

= (0.40 - 0.37) / sqrt((0.37 * (1 - 0.37)) / 130)

= 0.03 / sqrt(0.2339 / 130)

≈ 1.437

Using a standard normal distribution table or calculator, we can find the critical value for a one-tailed test with a significance level of 0.05. The critical value corresponds to a z-score of approximately 1.645.

Since the calculated test statistic (1.437) does not exceed the critical value (1.645), we do not have sufficient evidence to reject the null hypothesis.

Therefore, based on the data provided, we do not have convincing statistical evidence to support Jenna's claim that the average texting time at her high school is greater than 94 minutes.

In summary, a normal sampling distribution can be used for testing the claim. The hypotheses are stated as Hp: p ≤ 0.37, Ha: p > 0.37. However, based on the hypothesis test, the data does not provide convincing statistical evidence to support Jenna's claim.

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