The assignment is to create a MIPS assembly language program that corrects bad data using Hamming codes. The program is to request the user to enter a 12-bit Hamming code and determine if it is correct or not. If correct, it is to display a message to that effect. If incorrect, it is to display a message saying it was incorrect and what the correct data is (the 12-bit Hamming code) again in hex. I will be testing only with single bit errors, so the program should be able to correct my tests just fine. You do not need to worry about multiple bit errors. Make certain that you have lots of comments in your code as this is in MIPS assembly language. For this assignment, turn in your MIPS assembly language code and a screenshot of a test run.
Answers
To fulfill the assignment, a MIPS assembly language program needs to be created that utilizes Hamming codes to correct bad data.
The program will prompt the user to input a 12-bit Hamming code and determine if it is correct or not. In the case of a correct code, it will display a corresponding message. However, if the code is incorrect, the program will notify the user of the error and provide the correct data, represented as the 12-bit Hamming code in hexadecimal format. The program will specifically handle single bit errors and is not required to handle multiple bit errors. Hamming codes are a set of error-correcting codes used to detect and correct single bit errors in data. These codes add additional parity bits to the original data bits to form a codeword. The parity bits are calculated based on the position of the set bits in the codeword. During error detection, the program checks if the received codeword has any errors by recalculating the parity bits and comparing them with the received parity bits. If there is an error, the program identifies the erroneous bit and corrects it based on the parity bits. Finally, the program displays the result, indicating whether the code is correct or incorrect, and if incorrect, it provides the corrected data in hexadecimal format.
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Related Questions
Determine the bare module cost of a 1-shell-pass, 2-tube-pass(1 - 2) heat exchanger designed for the following operating conditions: Maximum operating pressure (tube side) = 30 barg Maximum operating pressure (shell side) = 5 barg Process fluid in tubes requires stainless steel MOC Shell-side utility (cooling water) requires carbon steel MOC Heat exchange area = 160 m^2
Answers
The heat exchanger's estimated bare module price is $199,101.
How much does a bare module cost, exactly?The pricing of a bare module includes all necessary hardware and installation labour within a 3-meter radius. Investment = above plus royalties plus real estate plus supplies + legal + working capital plus construction-related interest Working capital is equal to 10%+ of invested fixed capital. This could differ greatly.
Bare module cost = (Cost of tubes + Cost of shell + Cost of bundle) x (Cost factor)
Tube length = \(160 / (2 x 1.3) = 61.54 m\)
Cost of tubes = \(61.54 x $50 = $3,077\)
Shell length = \(1.25 x 61.54 = 76.92 m\)
Cost of shell = \(1.5 x 76.92 x $500 = $57,690\)
Number of tubes = \(61.54 x 10 = 615\)
Assuming a cost per tube of $10, we get:
Cost of bundle =\(615 x $10 = $6,150\)
Bare module cost = \(($3,077 + $57,690 + $6,150) x 3 = $199,101\)
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what are some examples of the structural and aerodynamic research conducted by naca?
Answers
The National Advisory Committee for Aeronautics (NACA), which was the predecessor of NASA, conducted a significant amount of research in the fields of structural and aerodynamic design.
What are some examples of research done by NACA?
Some examples of their work include:
Structural research: NACA conducted studies on the strength and behavior of materials used in aircraft construction, including metal alloys and composite materials. They also developed methods for testing and analyzing the structural integrity of aircraft components and developed new construction techniques.Aerodynamic research: NACA conducted extensive studies on the aerodynamics of aircraft, including lift, drag, and stability. They made important contributions to our understanding of wing design, including the development of the NACA airfoil, which remains widely used in aircraft design. NACA also conducted wind tunnel tests on full-scale aircraft models to study airflow patterns and identify ways to improve performance.These and other NACA research efforts laid the foundation for many of the advances in aircraft design and aeronautical engineering that we see today, and helped to make air travel safer, more efficient, and more reliable.
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1) In a system with virtual memory, process virtual address space must be larger than the size of physical memory. Is this statement true or false?
2) In a system with paging as the address translation mechanism, the virtual page size must be the same as the physical page size. Is this statement true or false?
3) In a system with virtual memory, the number of bits of a virtual address must be the same as the number of bits of a physical address. Is this statement true or false?
4) Using multi-level paging will increase time needed for TLB lookups when comparing to using linear paging. Is this statement true or false?
5) In a system with paging as the address translation mechanism, using multi-level paging always causes less memory usage for storing address translation info (i.e., the page directories and page tables) than using linear paging. Is this statement true or false?
Answers
As per the statements mentioned, the correct answer of validation is:
1) True. In a system with virtual memory, the process virtual address space can be larger than the size of physical memory, as it allows for the efficient use of memory resources by swapping data between disk storage and physical memory when needed.
2) True. In a system with paging as the address translation mechanism, the virtual page size must be the same as the physical page size to ensure proper mapping of virtual addresses to physical addresses.
3) False. In a system with virtual memory, the number of bits of a virtual address does not have to be the same as the number of bits of a physical address. Virtual addresses usually have a larger bit size to accommodate larger address spaces.
4) True. Using multi-level paging can increase the time needed for TLB lookups when compared to linear paging, as multiple levels of address translation require additional memory accesses.
5) False. In a system with paging as the address translation mechanism, using multi-level paging does not always cause less memory usage for storing address translation info. The efficiency of memory usage depends on the system's implementation and the specific workloads it encounters.
Thus, the answers to the statements are mentioned.
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the equijoin takes its name from the comparison operator ____ used in the condition.
Answers
The equijoin operation in database management systems is a type of join operation where two tables are joined based on an equality condition on one or more matching columns.
The name "equijoin" is derived from the comparison operator "=". In other words, an equijoin is performed when a query involves the matching of columns between two tables, and the comparison is based on the equality operator.
The equijoin operation is an essential tool in database management systems and is widely used in many applications. It is particularly useful when retrieving information from multiple tables, such as in a data warehouse or in a business intelligence system. The equijoin operation is also a fundamental operation in the SQL language, which is the standard language used for managing relational databases.
In summary, the name "equijoin" comes from the comparison operator "=" used in the condition to join two tables. This operation is critical in database management systems, and it is commonly used in various applications.
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The temperature distribution across a wall 0.3 m thick at a certain instant of time is T(x) a bx cx2 , where T is in degrees Celsius and x is in meters, a 200 C, b 200 C/m, and c 30 C/m2 . The wall has a thermal conductivity of 1 W/mK. (a) On a unit surface area basis, determine the rate of heat transfer into and out of the wall and the rate of change of energy stored by the wall. (b) If the cold surface is exposed to a fluid at 100 C, what is the convection coefficient
Answers
Answer:
the rate of heat transfer into the wall is \(\mathbf{q__{in}} \mathbf{ = 200 W/m^2}\)
the rate of heat output is \(\mathbf{q_{out} =182 \ W/m^2}\)
the rate of change of energy stored by the wall is \(\mathbf{ \Delta E_{stored} = 18 \ W/m^2 }\)
the convection coefficient is h = 4.26 W/m².K
Explanation:
From the question:
The temperature distribution across the wall is given by :
\(T(x) = ax+bx+cx^2\)
where;
T = temperature in ° C
and a, b, & c are constants.
replacing 200° C for a, - 200° C/m for b and 30° C/m² for c ; we have :
\(T(x) = 200x-200x+30x^2\)
According to the application of Fourier's Law of heat conduction.
\(q_x = -k \dfrac{dT}{dx}\)
where the rate of heat input \(q_{in} = q_k\) ; Then x= 0
So:
\(q_{in}= -k (\dfrac{d( 200x-200x+30x^2)}{dx})_{x=0}\)
\(q_{in}= -1 (-200+60x)_{x=0}\)
\(\mathbf{q__{in}} \mathbf{ = 200 W/m^2}\)
Thus , the rate of heat transfer into the wall is \(\mathbf{q__{in}} \mathbf{ = 200 W/m^2}\)
The rate of heat output is:
\(q_{out} = q_{x=L}\); where x = 0.3
\(q_{out} = -k (\dfrac{dT}{dx})_{x=0.3}\)
replacing T with \(200x-200x+30x^2\) and k with 1 W/m.K
\(q_{out} = -1 (\dfrac{d(200x-200x+30x^2)}{dx})_{x=0.3}\)
\(q_{out} = -1 (-200+60x)_{x=0.3}\)
\(q_{out} = 200-60*0.3\)
\(\mathbf{q_{out} =182 \ W/m^2}\)
Therefore , the rate of heat output is \(\mathbf{q_{out} =182 \ W/m^2}\)
Using energy balance to determine the change of energy(internal energy) stored by the wall.
\(\Delta E_{stored} = E_{in}-E_{out} \\ \\ \Delta E_{stored} = q_{in}- q_{out} \\ \\ \Delta E_{stored} = (200 - 182 ) W/m^2 \\ \\\)
\(\mathbf{ \Delta E_{stored} = 18 \ W/m^2 }\)
Thus; the rate of change of energy stored by the wall is \(\mathbf{ \Delta E_{stored} = 18 \ W/m^2 }\)
We all know that for a steady state, the heat conducted to the end of the plate must be convected to the surrounding fluid.
So:
\(q_{x=L} = q_{convected}\)
\(q_{x=L} = h(T(L) - T _ \infty)\)
where;
h is the convective heat transfer coefficient.
Then:
\(Replacing \ 182 W/m^2 \ for \ q_{x=L} , (200-200x +30x \ for \ T(x) \ , 0.3 m \ for \ x \ and \ 100^0 C for \ T\) We have:
182 = h(200-200×0.3 + 30 ×0.3² - 100 )
182 = h (42.7)
h = 4.26 W/m².K
Thus, the convection coefficient is h = 4.26 W/m².K
four working ladies a,b c,d are sitting around a table
1) a sits opposite to cook
2.b sits on the right side of the beautician
3.teacher is on the left side of an accountant
4.d sits opposite to c
5.c is to the right of the accountant
Answers
Answer:
A accountant
D teacher
B cook
C beautician
Explanation:
C is on the right of the accountant, so D (opposite C) is the teacher. The accountant is to the right of the teacher, so cannot be B, and must be A. Then B (opposite A) is the cook, and C (left of B) is the beautician.
__
Clockwise from A:
A accountant
D teacher
B cook
C beautician
Identify several areas in which a risk manager should be knowledgeable?
Answers
At least five fundamental components must be considered when creating a framework for risk management. They are risk governance, risk reporting and monitoring, risk reporting and assessment, risk mitigation, and risk identification.
What are the risk manager should be knowledgeable?They are aware of the potential effects those risks could have on the company and what preventative measures or backup plans should be put in place.
In order to set objectives or budgets, it is essential to analyze your growth and performance, which analytics help you do.
Risk managers find it challenging to reflect on the past or plan for the future without analytics. They make it straightforward to raise any company's productivity and effectiveness.
Therefore, risk managers are aware of all potential risks in their domain and, if feasible, beyond.
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A home with 8’ ceilings measure 42"" x 30"" the areas of the window and the door openings are approximately 125 ft. ². What’s the total wall area that needs to be insulated
Answers
The total wall area that needs to be insulated of the home with 8’ ceilings measuring 42" x 30" and window and door openings approximately 125 ft² can be found out as follows:First, we need to convert 8 feet into inches as follows: 8 feet x 12 inches/foot = 96 inches.
Therefore, the area of one wall can be calculated as follows:Area of one wall = Length x Height= 42 inches x 96 inches= 4,032 square inches= 28 square feetSince there are four walls in a room, the total area of the walls can be calculated by multiplying the area of one wall by.
Therefore:Total wall area that needs to be insulated = Total area of the walls – Area of the window and door openings= 112 square feet – 125 square feet= -13 square feetSince the total wall area can't be negative, there might be a mistake in the given values. Please check the given values and question and provide them if any of them are wrong.
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If you are creating an artificial cell and you want this cell to be capable of the greatest sensitivity to an applied signal, which would be the most useful?.
Answers
The most popular technique for creating artificial cells is cell encapsulation.
What is artificial cell?Artificial cell is defined as a manufactured particle that replicates one or more biological cells' functions. A type of artificial structures with physiologically active components is referred to as "artificial cells."
In order to create encapsulated cells, liquid cell suspensions are often divided into controlled-size droplets, which are quickly hardened or gelled to offer additional stability. They can be utilized as biomimetic systems to analyze the dynamics of cells with little interference from cellular complexity, to study and comprehend the characteristics of biological cells,
Thus, the most popular technique for creating artificial cells is cell encapsulation.
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a three-bend saddle is a saddle consisting of a center bend and two side bends with the center bend having twice the angle of the side bends.a. trueb. false
Answers
A three-bend saddle is a saddle consisting of a center bend and two side bends with the center bend having twice the angle of the side bends is a true statement.
What is a three-bend saddle?The most common 3-point saddle bends have a 45-degree bend in the center and a 22.5-degree bend on either side. Add the shrinking amount and distance measurement together to determine where to place the center bend along the conduit. Make a note of the number as your center line measurement.
What is the definition of bend length?When we bend a steel bar, its length increases slightly due to stretching in the bending area. The degree of bend and the grade of steel influence length expansion. The length increases as the bending degree increases and decreases as the steel grade increases.
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a current amplifier supplies i rna to a load resistance of i k.o. when the load resistance is increased to 12 kn, the output current decreases to 0.5 ma. what are the values of the short-circuit output current and the output resistance of the amplifier?
Answers
We can use the voltage divider rule to calculate the output current from the amplifier:
\(Vout = iRNA * RL/(RA + RL)\)
When RL is i kΩ,
\(Vout = iRNA * i kΩ/(RA + i kΩ)\)
When RL is 12 kΩ,
\(Vout = 0.5 mA * 12 kΩ/(RA + 12 kΩ)\)
Since the voltage gain of the amplifier is infinite, the output voltage is equal to the input voltage.
we can equate the two values of Vout as follows:
\(iRNA * i kΩ/(RA + i kΩ)\)
\(= 0.5 mA * 12 kΩ/(RA + 12 kΩ)\)
Simplifying this equation and solving for RA, we get:
RA = 4 kΩ
The short-circuit output current is the current flowing through RA and is given by:
ISC = Vinput/RA
Where Vinput is the voltage applied to the input of the amplifier.
Vinput = iRNA * RA
ISC = iRNA/RA
\(= iRNA/4 kΩ\)
\(= (iRNA/1000) / 4 A\)
\(= 0.25 iRNA mA\)
The short-circuit output current is 0.25 iRNA mA. the output resistance of the amplifier is 4 kΩ and the short-circuit output current is 0.25 iRNA mA.
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Calculate the power required for heating a 1.5 kg sample of water for 10 minutes in a thermal system. What is the amount of energy required to raise the temperature of the water from 25°C to 60°C ? How much minimum amount of power does the heater have to supply per unit time? Why does the actual power rating of the heater need to be higher than this minimum amount? (The specific heat of water is 4.18 J/g°C .)
*60 points to anyone who can help*
Answers
Answer:
Power= Heat energy\ time
heat energy= mc∆T
specific heat of water = 4180
1.5*4180*(60-25)
=219450
time = 10× 60= 600 secs
power = 219450/600
Power= 365.75 Watt
=0.37 KW
Explanation:
the actual has to be bigger because the heater might be required to handle more ...also to accommodate extra energy.
A room has a width of 14.1 feet, a length of 15.5 feet, and a ceiling height of 12.0 ft. The average flow rate for this room's air conditioning unit is
Answers
Answer:
Your question lacks the time required hence i will calculate the Average flow rate using a general concept and an assumed time value of 25 seconds
ANSWER : 104.904 ft^3/sec
Explanation:
General concept : Average flow rate is the volume of fluid per unit time through an area
Hence the average flow rate of the air conditioning unit of this room
Volume of the room / time taken for the air to cycle the room = v / t
assuming the time taken = 25 seconds
volume of room = width * length * height
= 14.1 * 15.5 * 12 = 2622.6 ft^3
Average flow rate = V/ t
= 2622.6 / 25 = 104.904 ft^3/sec
Limpies are best used for
o creating landscape topiaries.
o removing shrub structural branch defects.
o selectively thin delicate shrubs like roses.
o pruning flowers.
Answers
Limpies are best used for removing shrub structural branch defects.
Limpies are specialized pruning tools commonly used in horticulture and arboriculture. They are specifically designed for the precise and careful removal of shrub structural branch defects. These defects can include broken, dead, diseased, or crossing branches that affect the overall health and aesthetics of the shrub. Limpies are equipped with sharp blades and a scissor-like action, allowing for clean and accurate cuts to be made close to the main stem or branch collar. This helps promote proper healing and reduces the risk of disease or insect infestation. While limpies can be used for general pruning tasks, they excel in addressing structural branch defects and maintaining the overall health and integrity of shrubs.
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Example 12: Write an algorithm and draw a flowchart to calculate
the factorial of a number(N). Verify your result by a trace table by
assuming N = 5.
Hint: The factorial of N is the product of numbers from 1 to N)
Answers
Answer:
An algotherum is a finite set of sequential instructions to accomplish a task where instructions are written in a simple English language
Realice un analisis tecnologico de un frasco de vidrio.Teniendo en cuenta todos los niveles de analisis: analisis morfologico estructural,analisis de ls funcion y del funcionamiento,analisis tecnologico economico y analisis historico,por favor ayudenmen necesito entregarlo hoy
Answers
Answer:
b
Explanation:
device that illuminates the front of a stage floor is called___
Answers
A device that illuminates the front of a stage floor is called a footlight.
Footlights are typically placed around the front of the stage floor and help to illuminate the performers. This allows the audience to see the performers’ movements and facial expressions. Footlights are usually composed of several different lamps and they can produce a variety of lighting effects, such as spotlighting or accenting. This helps to create the desired atmosphere and mood for the performance. Footlights can also be used to draw attention to specific areas or objects on the stage. The light that is created by footlights is usually quite soft, which helps to make the performers appear more visible and lifelike.
In addition to providing illumination for the performers, footlights are also important for safety. They make it easier for performers to see the stage and help them to avoid any potential obstacles. Additionally, it helps the audience to better see the stage, as well as any props or scenery that might be present. Footlights also provide more visibility for those who might be operating sound and lighting equipment, making the process much safer for everyone.
Footlights are an essential part of any theatrical performance, helping to provide the necessary lighting to create an inviting and enjoyable atmosphere for both the performers and the audience.
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When choosing a respirator for your job, you must conduct a
test.
Answers
I hope this helps.
A double-threaded Acme stub screw of known major diameter is used in ajack having a plain thrust collar of known mean diameter. Coefficients of running friction are estimated as 0.10 for the collar and 0.11 for the screw. Assume (1) the starting friction is about 1/3 higher than running friction and (2) the screw is not exposed to vibration.
Required:
a. Determine the pitch, lead, thread depth, mean pitch diameter, and helix angle of the screw.
b. Estimate the starting torque for raising and for lowering a 5000 lb load.
c. If the screw is lifting a 5000 lb load at the rate of 4 ft/min, what is the screw rpm? What is the efficiency of the jack under this steady-state condition?
d. Would the screw overhaul if a ball thrust bearing (of negligible friction) were used in place of the plain thrust collar.
Answers
Answer:
I'm pretty sure it's c but i may be wrong
A noisy transmission channel has a per-digit error probability p = 0.01.
(a) Calculate the probability of more than one error in 10 received digits?
Answers
Answer:
The appropriate answer is "0.0043".
Explanation:
The given values is:
Error probability,
p = 0.01
Received digits,
n = 10
and,
\(x\sim Binomial\)
As we know,
⇒ \(P(x)=\binom{n}{x}p^xq^{n-x}\)
Now,
⇒ \(P(x >1) =1- \left \{ P(x=0)+P(x=1) \right \}\)
⇒ \(=1-\left \{\binom{10}{0}(0.01)^0(0.99)^{10-0}+\binom{10}{0}(0.01)^1(0.99)^{10-1} \right \}\)
⇒ \(=1-0.9957\)
⇒ \(=0.0043\)
What is code in Arduino to turn led on and off
Answers
here's your answer..
Reason for IEE regulations in electrical installation
Answers
Because doing electrical installations without regulations can lead to substandard work that can kill people and destroy property.
Explanation:
Prior to leaving Ohio, I was, for many years, a Certified Fire Safety Inspector. The prevention side of my job involved inspecting structures - houses, churches, schools, commercial, industrial, etc. - for compliance with fire safety regulations. I was required to have a working knowledge of the National Electrical Code, as well as most other building codes, so that I could identify conditions that could cause people to get hurt or buildings to catch fire.
The electrical code was considered to be a compilation of “best practices” for the installation of electrical systems in a structure. In many instances these “practices” were developed as a result of prior unsafe practices leading to fires and/or loss of life. Sort of - opps, we mustn’t do that again! The standards published concerning a wide range of electrical systems and devices, if followed, will make the installation as safe as the current state-of-the-art permits. Failure to follow the relevant codes can destroy a builder’s or an electrician’s defense in court if something bad happens.
As an example: 165 people died at the Beverly Hills Supper Club in Soulgate, KY, on May 28th 1977. The fire appeared to have started by improper electrical wiring. After the fire, numerous electrical code violations, as well as numerous building code violations were found. You wouldn’t want to be the owner of something like that.
Several new laws were passed as a result of this fire -no more aluminum wiring in commercial buildings, exit lighting required, automatic fire alarm systems, automatic sprinkler systems required, etc. The updates made to electrical and building codes made later buildings much safer.
As written, the IEEE codes are not law - after all the IEEE is an association, not a legislature; however, many of the standards they set forth are referenced specifically or by inclusion in formal codes approved by legislative bodies and made into law - The Ohio Fire Code, for example references the National Electrical Code. An inspector noting violations of such codes when they are given legal recognition by the State can issue orders to have violations corrected and can also issue citations which can lead to court appearances and monetary fines levied against the building’s management.
Codes are updated with regularity. In general, a change to the code does not require a change to an existing structure. However, if a structure undergoes renovation then there is a point at which the building must be brought up to meet the present code standards. There are exceptions. Much time, effort , and money has been expended to remove asbestos from existing structures even where no renovation to the structure was even being planned. Exit doors opening to the public way now need automatic EXIT lighting and many older buildings were retrofit with exit lighting as a result in code updates.
Codes are for a reason. They are devised by the collective thinking and experience of people who are experts - or at least experienced - in their field. And they are intended to protect YOU!
The largest class of errors in software engineering can be attributed to _______.
Answers
Answer:
improper imput validation
Explanation:
Saturated water vapor at 1 bar enters a direct-contact heat exchanger operating at steady state and
mixes with a stream of liquid water entering at 250C, 1 bar. A two-phase liquid-vapor mixture exits at 1 bar. The entering streams have equal mass flow rates. Neglecting heat transfer with the surroundings and the effects of motion and gravity, determine for the heat exchanger
a) The rate of exergy destruction, in kJ per kg of mixture exiting
.b) The exergetic efficiency given by equation : ε = (ṁ2 (e3 – e2)) / (ṁ1 (e1−e3))
Let T0 = 200 C, p0 = 1 bar.
Answers
gyucucugbyguhg8yiuhj7uuh/Answer:
Select the correct answer.
What is the output of P.P( theres three lines over the second P) ?
A. P.P
B. P
C. P.P(one line over the second P)
D. P.P(one line over both ps)
Answers
What field provides traffic marking for a QoS system at layer 3?
Answers
The field that provides traffic marking for a QoS system at layer 3 is the Differentiated Services Code Point (DSCP) field. This field is used to classify and prioritize traffic based on its type and importance within the network system. By using DSCP values, network administrators can ensure that critical traffic receives preferential treatment and that the system can effectively manage and prioritize network traffic.
What is the QoS system?
QoS stands for Quality of Service, and it refers to a system or set of technologies that are used to manage and prioritize network traffic. QoS systems are designed to ensure that important data, such as voice or video streams, is delivered with the highest priority, while less critical data, such as file downloads or emails, receives a lower priority.
A QoS system typically involves setting up policies and rules that govern how different types of network traffic are handled. For example, a policy might be created that prioritizes video conferencing traffic over file downloads, so that the video stream is not interrupted by slower downloads.
QoS systems are commonly used in enterprise networks to ensure that business-critical applications have the necessary bandwidth and priority to operate effectively. They are also used by internet service providers (ISPs) to manage traffic on their networks and prevent congestion during peak usage times.
Overall, QoS systems are an important tool for ensuring reliable and efficient network performance, particularly in environments where network traffic is high or where certain types of data are especially important.
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A standard 20° pressure angle, 20 tooth pinion with a diametral pitch of 12 rotates at 1776 rpm driving a mating gear at 740 rpm.a) How many teeth are there on the gear?b) What are the pitch diameters of the pinion and gear?c) What are the standard addendum and dedendum diameters of the pinion and gear?d) What is the theoretically correct center distance?e) What are the radial, tangential and normal tooth loads when contact between the pinion and the gear occurs at the pitch point and the gearset is transmitting ½ hp?
Answers
Answer:
A) 48
B) Pitch diameters : pinion = 42.164 mm, Gear = 101.19 mm
C) standard addendum : pinion = 46.3804, Gear = 105.406
standard dedendum : pinion = 37.265 mm, Gear = 96.312 mm
D) 71.672 mm
E) 94.989 N , 101.0858 N, 34.573 N
Explanation:
Given Data :
∅ = 20⁰ , Tp = 20 ( tooth pinion ),
diameter pitch = 12, Np = 1776 rpm ,
Ng = 740 rpm,
attached below is the detailed solution of the given problems
Definition of permanent, semi permanent and temporary heat setting
Answers
Where a screen is installed at a combustion air opening, the mesh size shall not be smaller than ___________ inch.
a. 1/8
b. 1/2
c. 3/8
d. 1/4
Answers
When a screen is installed at a combustion air opening, the mesh size shall not be smaller than 1/4 inch.
What is the screen?
A screen is used in many outdoor or indoor structures, such as homes or commercial buildings, to protect windows, doors, outdoor spaces, or ventilation and air conditioning systems from insect, weather, or environmental damage.
Screens are also used in various industries, such as agriculture and mining, to protect the safety of the personnel working in those industries. The screens are made from various materials, including aluminum, steel, copper, bronze, fiberglass, nylon, and other synthetic materials.
CombustionCombustion is the process of burning, which is an exothermic chemical reaction between a fuel and an oxidizing agent that releases energy in the form of heat, light, and other byproducts. Combustion is vital to many energy production, transportation, and heating systems, including internal combustion engines, turbines, boilers, and furnaces.
Mesha mesh is a type of screen that is made of interlocking or interwoven strands of metal, plastic or other materials that form a grid or network with holes or gaps of various sizes. Meshes are used for many purposes, including filtering, sifting, separating, or reinforcing materials in various industries, including construction, mining, and agriculture.
Hence the mesh size shall not be smaller than 1/4 inch. option D is correct.
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One of the testing equipments used for inspection is? Test tubes Measuring jar Strain gauges None of the mentioned
Answers
Answer:
The answer is the strain gauges.
Explanation:
Inspection systems work or are performed to measure the characteristics of a product, to verify if it meets specified requirements, all using benchmarks and test equipment.
The strain gauges are part of the test equipment used for inspection. These are sensors that measure deformation, pressure and load in resistance tests of materials.