The probability of a prison sentence greater than 18 years for a person convicted of second-degree murder is 0.1056 or about 10.56%.
We must normalize the variable using the following method in order to determine the likelihood that a person convicted of second-degree murder will serve a jail term longer than 18 years:
\(z = (x - μ) / σ\)
where: mean of the distribution (15 years), delta: standard deviation, and x: value of interest (18 years in this example) (2.4 years).
When we enter the values, we will get that:
z = (18 - 15) / 2.4 = 1.25
Then, we can use a calculator or table of the standard normal distribution to determine the probability associated with this z-score. The likelihood of a sentence longer than 18 years is represented by the region to the right of the value z = 1.25. We determine that the region to the right of 1.25 is roughly 0.1056 using a common normal distribution table.
Hence, the likelihood that a person convicted of second-degree murder will serve a sentence in jail longer than 18 years is 0.1056 or roughly 10.56%.
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Several years ago clarissa researched the number of telephones in several countries the data found rounded to the nearest whole number is shown in the table part 1: explain how to determine the scale to mark the vertical axis of your graph part 2: construct your graph to represent the number of telephones per thousand people for each country
Based on the number of telephones per people in the country given, the best scale would be a 100 telephones per 1 cm scale on the vertical axis.
What scale should be used?India has a small number of telephones per 1,000 people of 8 while the U.S. had a high number of 800.
Any scale used would have to cater for these two extremes while also catering for the numbers between.
The best scale would therefore be a 100 telephones per 1,000 people. The separation of each hundred would be 1 cm which every 0.1 cm representing 10 telephones per 1,000 people.
The graph is shown attached.
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Kyle competes in 100 m wheelchair races. Hel
calculates the information below using his last 4
race times.
His minimum race time was 19.8 s.
The range of his race times was 5.6 s.
The median of his race times was 23.8 s.
The mode of his race times was 25.4 s.
If Kyle includes a new race time of 25.7 s in his
calculations, how much will the mean change
by?
Answer:
0.5s
Step-by-step explanation:
His initial mean would be calculated by:
His minimum race time = 19.8s
The maximum race time = 19.8 + 5.6 = 25.4s
Since the mode is also 25.4, there are 2 25.4s races.
Since the median is 23.8s and the number of race times is even, the final race time can be calculated by:
25.4- 23.8s = 1.6s
23.8-1.6 = 22.2s
So the race times are 19.8s, 22.2s, 25.4s and 25.4s.
This means that his initial mean was (19.8+22.2+25.4+25.4)/4 = (42+50.8)/4= 92.8 /4 = 23.2s
With the new race time, the equation will change to (92.8+25.7)/(4+1)= 118.5/5= 23.7s
So the mean change would be 23.7 - 23.2 = 0.5 s.
Hope this helps!
The ratio of ages of kissi and esinam is 3:5 and esinam is 3:5 The sum of ages of all 3 is 147 years.whats the age difference between oldest and youngest ?
Answer:
48 years.
Step-by-step explanation:
Consider the complete question is "The ratio of ages of kissi and esinam is 3:5 and that of esinam and lariba is 3:5. The sum of ages of all 3 is 147 years. whats the age difference between oldest and youngest ?"
It is given that
Kissi : Esinam = 3:5 = 9:15
Esinam : Lariba = 3:5 = 15:25
So, the combined ratio is Kissi : Esinam : Lariba = 9:15:25
Let ages of Kissi, Esinam, Lariba are 9x, 15x and 25x.
Sum of ages of all 3 is 147 years.
\(9x+15x+25x=147\)
\(49x=147\)
\(x=3\)
The value of x is 3. So, the age of all three are
\(Kissi=9x=9(3)=27\)
\(Esinam=15x=15(3)=45\)
\(Lariba=25x=25(3)=75\)
Since Lariba is oldest and Kissi is youngest, therefore, the difference between their ages is
\(75-27=48\)
Hence, difference between oldest and youngest is 48 years.
Solution: The set of all elements in the universal set that is not in set A is called the complement of set A.
The complement of set A, denoted by ​ A`, is the collection of all elements that belong to the universal set but are not part of set A. It's not necessary to mention the universe (also known as U) if it's understood which set of elements is being referred to.
The complement of a set A is the collection of all elements that belong to the universal set but not to set A. It is denoted as ​ A` and does not include any elements that are already in set A. The universal set, also known as U, contains all possible elements and is assumed to be known. Therefore, when referring to the complement of a set, it is not necessary to mention the universal set explicitly. The complement of a set is useful in determining the set of elements that are not part of a particular set, and it can be used in various mathematical operations.
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A stadium has 80,000 seats. Seats sell for $40 in Section A, $20 in Section B, and $10 in Section C. The number of
seats in section Cequals the total number of seats in sections A and B. Suppose the stadium takes $1,500,000 from each
sold-out event. How many seats does each section hold?
Answer:
There are 26,000 seats in Section A, 14,100 in section B & 11,900 in section C
Step-by-step explanation:
Section B = x
Section C = y
Section A = x + y
Step 1-
Total number of seats = 52000
x + y + (x + y) = 52000
x + y + x + y = 52000
2x + 2y = 52000
x + y = 26000
x = 26000 - y
Step 2-
Total amount collected = $1,370,500
20x + 15y + 35(x + y) = 1,370,500
20x + 15y + 35x + 35y = 1,370,500
55x + 50y = 1,370,500
11x + 10y = 274,100
Step 3-
x = 26000 - y
11x + 10y = 274,100
Finding y
11 (26000 - y) + 10y = 274,100
286000 - 11y + 10y = 274,100
y = 11,900
Finding x
x = 26000 - y
x = 26000 - 11900
x = 14,100
Section B = 14,100
Section C = 11,900
Section A = 14,100 + 11,900 = 26,000
(d) at the 0.05 level of significance, is there evidence of a linear relationship between the number of cases delivered and the delivery time?
Yes, there is evidence that the level of significance is taken at 0.05 or 5% when the p-value is low.
Level of significance: The fixed probability of incorrectly eliminating the null hypothesis when it is actually true is what is meant by the term "level of significance." The probability of type I error is defined as the level of significance, which is set by the researcher using the results of the error. The statistical significance is measured by the level of significance. It specifies whether or not the null hypothesis is thought to be true. It is anticipated to determine whether the outcome is statistically significant enough to reject or prove the null hypothesis wrong.
The significance level is set at 0.05 or 5%. Low p-values indicate that the observed values differ significantly from the population value that was initially hypothesized. If the p-value is as small as possible, it is said to be more significant. Additionally, if the p-value is very low, the outcome would be highly significant. However, since obtaining a p-value below 0.05 is quite uncommon, p-values less than 0.05 are typically considered significant.
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16/25+8/5+4+10…+a10
what’s the sum of the series
Answer:
correct answer is 406/25+a10
Step-by-step explanation:
8. Use point-slope form to write the equation of a line that passes through the point (18, -3) with slope -1.
The equation of the line that passes through the point (18,-3) with slope -1 is y = -x+15.
According to the question,
We have the following information:
The line passes through the point (18,-3) with slope -1.
We know that the following formula is used to find the equation of the line passing through a point with the slope which is denoted by m:
(y-y') = m(x-x')
In this case, we have the following values:
m = -1
x' = 18 and y' = -3
Putting these values in the above formula:
y-(-3) = -1(x-18)
y+3 = -x+18
Subtracting 3 from both sides of the equation:
y = -x+18-3
y = -x+15
Hence, the equation of the line that passes through the point (18,-3) with slope -1 is y = -x+15.
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find the expected value of the proposition.round your answer to two decimal places. losses must be expressed as negative values.
To find the expected value of the question, we need to find the probability of having a card with a value less or equal to 5, and the probabilities greater than 5. We are told that the aces are considered the highest card in the deck. So, this card is not part of the group less or equal to 5.
Then, we have in a standard deck of cards 52 cards.
• Those cards that are equal or less than 5 are 16 cards.
,• Those cards that are greater than 5 are 36 cards.
The probability of having a card equal to or less than 5 is equal to:
\(P(C\leq5)=\frac{16}{52}\)The probability of having a card greater than 5 is equal to:
\(P(C>5)=\frac{36}{52}\)When we pay someone, we have a "loss" in a game. Then, if we pay $22, we need to write this value as -$22.
Therefore, the expected value of the proposition is as follows:
\(E(V)=\frac{16}{52}\cdot39-\frac{36}{52}\cdot22=-3.23076923077\)If we round the result to two decimal places, we have that the expected value is equal to E(V) = $ -3.23.
Learning Task 1: Solve and check. Write your answers on a separate sheet of paper.
1. X + 5 = 2
2. X – 10 = 22
3. 3n / 6= 7
4. 96 – 4x = -28
5. 2x/ 3= 10
6. 5y – 2 = 18
7. -32 = 15 + d
8. H/5 = 8
9. 2/4 – 7 = 35
10. 453 + 364 + d = 1000
Pasagot po pls
Answer:
hello
\(x + 5 = 2\\x = 2 - 5\\x = - 3 \\\\x - 10 = 22\\x = 22 + 10 \\x = 32 \\\\3 n /6 = 7 \\3 n = 42\\n = 14\\\\96 - 4 x = - 28\\- 4 x = - 28 - 96\\- 4 x = - 124\\x = 31\\\\2 x /3 = 10 \\2 x = 30\\x = 15 \\\\5 y - 2 = 18\\5 y = 18 + 2\\5 y = 20\\y = 20/5 = 4 \\\\- 32 = 15 + d \\- d = 15 + 32\\- d = 47\\d = - 47 \\\)
\(h /5 = 8 \\h = 40 \\\\453 + 364 + d = 1 000\\d = 1 000 - 817\\d = 183\\\\\)
Step-by-step explanation:
When the greatest common divisor and least common multiple of two integers are multiplied, the product is 180. How many different values could be the greatest common divisor of the two integers
The different values that could be be the greatest common divisor of the two integers are; 1, 2, 3, 4, 6
How to find the greatest common divisor?
Let the numbers be a, b. Thus, the product of the GCD(a, b) and the LCM(a, b) will be ab.
Now, for us to get something to be a factor of the GCD we need to make it be a factor of both a, b. Thus, its' square must be a factor of 180.
Therefore, the only numbers whose square is a factor of 1800 are 1, 2, 3, 4, 6 and as such they are the only GCDs possible.
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Let the polynomial p be the function of x. The graph of the polynomial has four zeros at
3, -4/3, -1, and 0. Select all the expressions that could represent p.
A. – 2x(x − 3)(x+3)(x + 1)^2
B. 2x(x + 3)(x + 3)(x+1)
C. - x(x − 3)(3x + 4)(2x + 2)
D. - *x(x − 3)(4x + 3)(x + 1)
E. 2x(x − 3)(3x + 4)(x - 1)^2
Find m/TRS if m/1 = 2x + 4 and
m/2= 3x - 3.
T
P
S
1
R
If the angles are ∠1 = 2x + 4 and ∠2 = 3x - 3, then m∠TRS = 36°.
What is an angle?
An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The Latin word "angulus," which meaning "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.
The measure of ∠1 = 2x + 4
The measure of ∠2 = 3x - 3
The measure of ∠TRS is -
∠TRS = ∠1 + ∠2
Since, PR is a bisector then ∠1 = ∠2.
The equation is -
2x + 4 = 3x - 3
2x - 3x = - 3 - 4
-x = -7
x = 7
Substitute the value of x in the angles -
∠1 = 2(7) + 4
∠1 = 14 + 4
∠1 = 18°
∠2 = 3(7) - 3
∠2 = 21 - 3
∠2 = 18°
So, the value of ∠TRS is -
∠1 + ∠2
18° + 18°
36°
Therefore, the measure of ∠TRS is 36°.
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Consider the function f(x) = x2 - 4x + 8 on the interval 0, 4. Verify that this function satisfies the three hypotheses of Rolle's Theorem on the inverval f(x) is f(x) is and f(0) on [0, 4] on (0, 4) f(4) Then by Rolle's theorem, there exists at least one value c such that f'(c) = 0. Find all such values c and enter them as a comma-separated list. Values of c =: (1 point) Consider the function graphed below. P n ? Does this function satisfy the hypotheses of the Mean Value Theorem on the interval a, b ? Does it satisfy the conclusion?? f(b) f(a)2 At what point c is f'(c) b - a
Verifying that this function satisfies the three hypotheses of Rolle's Theorem on the inverval f(x) is f(x) is and f(0) on [0, 4] on (0, 4) f(4) Then by Rolle's theorem, there exists at least one value c = 2 such that f'(c) = 0.
Given:
Consider the function f(x) = x2 - 4x + 8 on the interval 0, 4. Verify that this function satisfies the three hypotheses of Rolle's Theorem on the inverval f(x) is f(x) is and f(0) on [0, 4] on (0, 4) f(4) Then by Rolle's theorem, there exists at least one value c such that f'(c) = 0.
f(x)=x^2−4x+8, [0,4]
when, x = 0
f(x) = x^2 -4x +8
f(0) = y = 0 - 0 + 8 = 8
when, x=4
f(5) = y = 16 - 16+8 =
thus, we have 2 points (0, 8) ; (4, 8)
slope,m = {8-(8)} / {4-0} = 0
hence, we have to calculate all the points,x where 0<x<8 and slope=0
f '(x) = 2x - 4 = 0
or, f '(c) = 2c - 4 = 0
c = 4/2 =2 ( 0<x<4)
hence, the there is only one solution c=2 which satisfies Rolle's theorem.
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Given the function, f(x)= |x-1| -2, choose the correct transformation
Answer:
c
Step-by-step explanation:
I attached a desmos graph so you could get a better understanding but it's right 1, down 2
Where can the bisectors of the angles of an obtuse triangle intersect?
Answer: Hello! I'm JK!.....
B. I Only. (inside the triangle)
Step-by-step explanation:
I really hope this helps you. XoXoGoldenMaknae <3
Please find all stationary solutions using MATLAB. I get how to do this by hand, but I don't understand what I'm supposed to do in MATLAB. Thanks!dx = (1-4) (22-Y) Rady = (2+x)(x-2y) de - this Find all stationary Solutions of System of nonlinear differential equations using MATLAB.
The first two arguments of the "solve" function are the equations to solve, and the last two arguments are the variables to solve for.
To find all the stationary solutions of the given system of nonlinear differential equations using MATLAB, we need to solve for the values of x and y such that dx/dt = 0 and dy/dt = 0. Here's how to do it:
Define the symbolic variables x and y:
syms x y
Define the system of nonlinear differential equations:
dx = (1-4)(2-2y);
dy = (2+x)(x-2y);
Find the stationary solutions by solving the system of equations dx/dt = 0 and dy/dt = 0 simultaneously:
sol = solve(dx == 0, dy == 0, x, y)
sol =
x = 4/3
y = 1/3
x = -2
y = -1
x = 2
y = 1
The stationary solutions are (x,y) = (4/3,1/3), (-2,-1), and (2,1).
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The width of a rectangle measures (4v+3w) centimeters, and its length measures (6v−6w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?
The expression that represent the perimeter of the rectangle is 20v - 6w
How to find the perimeter of a rectangle?The perimeter of a rectangle is the sum of the whole side of the rectangle.
Therefore,
perimeter of a rectangle = 2l + 2w
where
l = lengthw = widthHence,
l = 6v - 6w
w = 4v + 3w
perimeter of a rectangle = 2(6v - 6w) + 2(4v + 3w)
perimeter of a rectangle = 12v - 12w + 8v + 6w
combine like terms
perimeter of a rectangle = 12v + 8v - 12w + 6w
perimeter of a rectangle = 20v - 6w
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A technical machinist is asked to build a cubical steel tank that will hold 60L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.01m.
Answer:
L= 7.75 mStep-by-step explanation:
This problem bothers on the mensuration of solids, cube
Step one:
The volume of the tanks will hold 60L of water
hence the volume of the tank is 60L
we know that the expression for the
volume of cube = L*L*L
Volume of cube = L^3
60= L^3
L= √60
L= 7.7459
To the nearest 0.01m we have L= 7.75 m
A pair of pants comes in 6 different choices of waist sizes, 6 different choices of lengths, and 6 different choices of colors. How many choices are there in total
Therefore, there are 216 different choices of combination in total.
To determine the total number of choices, you need to multiply the number of options for each category together. In this case, you have 6 choices for waist sizes, 6 choices for lengths, and 6 choices for colors.
The total number of choices can be calculated as follows:
Total choices = Number of waist sizes × Number of lengths × Number of colors
= 6 × 6 × 6
= 216
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ANSWER NOW AND YOU GET 20 and ill answer one of ur questions
Answer:
300 gallons per hour.
Step-by-step explanation:
It takes 4 of 1/4 hours to make 1 hour. Now multiply gallons per quarter hour by four.
75 x 4 = 300
Let E be the solid enclosed by the ellipsoid x^2/4+y^2/4+z^2/9 = 1 above the xy-plane.
Calculate the Jacobian using the change of variables x = 2u, y = 2v, and z = 3w.
J(u, v, w)= ∂(x, y, z)/ ∂(u, v, w) =______
So, the Jacobian matrix for the given change of variables is:
J(u, v, w) =
| 2 0 0 |
| 0 2 0 |
| 0 0 3 |
To calculate the Jacobian using the given change of variables, we need to compute the partial derivatives of the new variables (u, v, w) with respect to the original variables (x, y, z).
Let's start by expressing the original ellipsoid equation in terms of the new variables:
\(x^2/4 + y^2/4 + z^2/9 = 1\)
Substituting x = 2u, y = 2v, and z = 3w, we get:
\((2u)^2/4 + (2v)^2/4 + (3w)^2/9 = 1\\u^2 + v^2 + w^2/3 = 1\)
Now, we can express the Jacobian matrix as follows:
J(u, v, w) =
| ∂x/∂u ∂x/∂v ∂x/∂w |
| ∂y/∂u ∂y/∂v ∂y/∂w |
| ∂z/∂u ∂z/∂v ∂z/∂w |
Let's calculate each partial derivative individually:
∂x/∂u = 2
∂x/∂v = 0
∂x/∂w = 0
∂y/∂u = 0
∂y/∂v = 2
∂y/∂w = 0
∂z/∂u = 0
∂z/∂v = 0
∂z/∂w = 3
Now we can construct the Jacobian matrix:
J(u, v, w) =
| 2 0 0 |
| 0 2 0 |
| 0 0 3 |
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This is for a Geometry-H class
Applying the linear angles theorem, the measures of the larger angles are: 130 degrees.
The measures of the smaller angles are 50 degrees
How to Apply the Linear Angles Theorem?Based on the linear angles theorem, we have the following equation which we will use to find the value of y:
3y + 11 + 10y = 180
Add like terms
13y + 11 = 180
Subtract 11 from both sides
13y + 11 - 11 = 180 - 11
13y = 169
13y/13 = 169/13
y = 13
Plug in the value of y
3y + 11 = 3(13) + 11 = 50 degrees
10y = 10(13) = 130 degrees.
Therefore, applying the linear angles theorem, the measures of the larger angles are: 130 degrees.
The measures of the smaller angles are 50 degrees.
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Use Tools Find an object that you think has a mass greater
than 1 kilogram. Use a pan balance with kilogram and gram
weights to measure the mass of the object. Explain how you
measured the mass.
If the combined weight is 1.5 kilograms and the weight of the gram weights is 0.5 kilograms, then the mass of the object is 1 kilogram.
What is mass?Mass is describes the amount of matter it contains. It is usually measured in kilograms or pounds. Mass is distinct from weight, which measures the force of gravity on an object.
To measure the mass of an object that I think has a mass greater than 1 kilogram, I will use a pan balance and kilogram and gram weights.
First, I will set the pan balance to 0 by adjusting the counterweight.
Then, I will place the object on one of the pans and add weights to the other pan until the balance is equal.
I will first use 1 kilogram weights and then add smaller gram weights until the pan balance is equal.
Once the pan balance is equal, the combined weight of the object and the weights will be the mass of the object.
I can then calculate the mass in kilograms by subtracting the weight of the gram weights from the total mass.
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1. which is the product of these numbers, to the appropriate number of significant digits? 56.2 × 9.2057 = a. 517 b. 517.4 c. 517.36 d. 517.00
The product of 56.2 and 9.2057 to the appropriate number of significant digits is 517.00.
The significant digits in a number are the digits that contribute to its precision. When multiplying numbers, the result should be rounded to the same number of significant digits as the factor with the least number of significant digits.
In this case, 56.2 has three significant digits, and 9.2057 has five significant digits. The factor with the least number of significant digits is 56.2. Therefore, the product should be rounded to three significant digits.
Multiplying 56.2 by 9.2057 gives 517.38134. Rounding this result to three significant digits gives us 517.00. The trailing zeros after the decimal point are significant in this case as they indicate the precision of the result. Hence, the correct answer is 517.00.
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diameter ***BONUS + 5*** A 27 inch diameter tire is rolled down a hill. How far did it travel if it rolled three times from where it started. Convert your answer to feet. * (5 Points) O 254.35 ft 21.195 ft O 84.78 ft ONG
Diameter D= 27 inch
How far travel= 3 times X circumference
Then
Travel T = 3x π x Diameter = 81π = 254.47 inches
Now from 40 inches = 3 feet
we get as result
Travel T = (254.47 x 3/40 ) = 21.2 feet
THEN answer is O
calculate the iterated integral. 64 1 8 x y y x dy dx 1
The iterated integral is equal to \(\frac{29296}{63}\)
The iterated integral is: ∫ from x=1 to x=8 ∫ from \(\int\limits \, from y=\sqrt{x} to y=8 (xy)(yx) dy dx\)
We can simplify this expression by reversing the order of integration, which gives:
∫ from y=1 to y=8 ∫ from \(x=y^2 to x=8 (xy)(yx) dx dy\)
Now, we can evaluate the inner integral with respect to x:
∫ from y=1 to y=8 \([(\frac{1}{2} )x^3 y^2]\) evaluated at \(x=y^2\) and x=8 dy
= ∫ from y=1 to y=8 \([(\frac{1}{2} )(8^3 y^2 - y^6)] dy\)
= \([(\frac{4}{7} )y^7 - (\frac{1}{18} )y^9]\) evaluated at y=1 and y=8
= \((\frac{2048}{7} -\frac{2048}{63} ) - (\frac{4}{7} - \frac{1}{8} )\)
= \(\frac{29296}{63}\)
Therefore, the iterated integral is equal to \(\frac{29296}{63}\).
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How do you write 533,000, 327.5, and 0.0034 in scientific notation
Answer:
A: 5.33 x 10∧5 and B.3.4 × 10-3
Step-by-step explanation:
Answer:
533,000,327.5 and o.oo34
what is the domain of this relation? {(2,3),(-1,7),(-3,-4),(0,2)}
QUICKKK
Answer:
{2,-1,-3,0} im pretty sure domain is like all the x values
Step-by-step explanation:
2.29+2.59-0.50-0.30 please help me out
Answer: the answer is 4.08
Step-by-step explanation:
Answer:
4.08
Step-by-step explanation:
2.29+2.59-0.50-0.30 is equal to 4.08
it's just addition and subtraction haha