The balanced equation for the production of sugars by photosynthesis is shown below.
This equation demonstrates the law of conservation of mass because
A.
there are more oxygen atoms on the right side of the equation than on the left.
B.
there is the same number of compounds on the right side of the equation as the left.
C.
there is the same number of each type of atom on the right side of the equation as the left.
D.
the sugar molecule on the right has the same mass as the carbon dioxide molecules on the left.

One structural difference between oligosaccharides and polysaccharides is their respective chain lengths. Oligosaccharides are composed of a relatively small number of monosaccharide units (typically 3 to 10), whereas polysaccharides consist of a larger number of monosaccharide units, often hundreds or thousands. This difference in chain length gives rise to variations in their properties and functions.

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Answer:

The answer is D

Explanation:

Non metals are:

Hydrogen (H)

Sulphur (S)

Phosphorus (P)

Carbon (C)

Fluorine (F)

Oxygen (O)

Nitrogen (N)

Chlorine (Cl)

Bromine (Br)

Helium (He)

Argon (Ar)

Iodine (I)

Neon (Ne)

Krypton (Kr)

Radon (Rn)

Selenium (Se)

Xenon (Xe)

Answer:Temperature

Explanation:

Which chemical reaction is correctly balanced? *

a. CH4 +2O2 → CO2 +2H2O

b. 2CH4 +2O2 → CO2 +2H2O

c. CH4 +O2 → CO2 +H2O

d. None of the above

Explanation:

d none of the above

Answer:

The answer is a. CH4 + 2O2 --- CO2 + 2H2O

Explanation:

A balanced chemical reaction must have the same number of each type of atom on both sides according to the law of conservation of mass:

1 carbon 4 hydrogen + 4 oxygen ----- 1 carbon 2 oxygen + 4 hydrogen

2 oxygen  =

1 carbon 4 hydrogen 4 oxygen ---- 1 carbon 4 hydrogen 4 oxygen

Since each type of atom has the same amount on both sides, the chemical formula is balanced.

Answer:

no of moles=mass in gm÷molar mass so let x be the mass in gm

4.5=x÷35.5×2

x=4.5×35.5×2 grams

x=319.5 gm

Explanation:

formula

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

4Al +3O₂ → 2Al₂O₃

Explanation:

To balance the chemical equation, start by identifying the number of atoms of each element on both sides of the equation.

Al +O₂ → Al₂O₃

Reactants (right-hand side of the arrow)

Al➭ 1

O➭ 2

Products (left-hand side of the arrow)

Al➭ 2

O➭ 3

Balancing the equation means that we need to ensure the number of atoms of each element is the same on both sides of the equation.

Let's balance the number of O atoms.

Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 1

O➭ 3(2)= 6

Products

Al➭ 2(2)= 4

O➭ 2(3)= 6

Balancing the number of Al atoms:

4Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 4

O➭ 6

Products

Al➭ 4

O➭ 6

The equation is now balanced.

Additional:

For a similar question on balancing equations, do check out the following!

Answer:Chlorine:

It is an element that belongs to the p-block and non-metal.

It shows a variable oxidation state.

The oxidation number of chlorine can be - 1, 0, + 1, + 3, + 4, + 5, or + 7 which depends on the substance containing the chlorine.

Explanation:

Cl has a -1 oxidation number, except when bonded to a F or an O.

Answer:

NH4OH

Explanation:

NH4OH is a weak base because it partially dissociates into NH + and OH− ions in aqueous solutions and the amount of OH− ions produced is low.

Answer:

Explanation:

Here, we want to get the number of moles

Mathematically:

We have that as:

The copper itself can react with hydrogen

Here is the chemical reaction

2CuCl2(aq) + H2(g) -> 2CuCl(s) + 2HCl(g)

Answer:

1. Mass percent of ethanol = 28.02 %.

2. Mole fraction of ethanol = 0.13.

Explanation:

1. To find the mass percent we need to use the following equation:

\(\%_{m/m} = \frac{m_{e}}{m_{s}} \times 100\)

Where:

\(m_{e}\) is the mass of ethanol

\(m_{s}\) is the mass of the solution

We need to calculate the mass of ethanol and the mass of the solution:

\( d = \frac{m_{s}}{V} \)

Where:

d: is the density of the solution = 0.957 g/mL

V: is the volume = 1 L

\( m_{s} = d*V = 0.957 \frac{g}{mL}*\frac{1000 mL}{1 L}*1 L = 957 g \)

Now, from the concentration we can find the mass of ethanol:

\( C = \frac{n_{e}}{V} = \frac{m_{e}}{M_{e}*V} \)                      

Where:

\(M_{e}\): is the molar mass of ethanol = 46.07 g/mol

\(n_{e}\): is the number of moles of ethanol = m/M

\( m_{e} = C*M*V = 5.82 \frac{mol}{L}*46.07 \frac{g}{mol}*1 L = 268.13 g \)

Finally, the mass percent of ethanol is:

\(\%_{m/m} = \frac{268.13 g}{957 g} \times 100 = 28.02 \%\)

2. The mole fraction of ethanol is given by:

\( \chi_{e} = \frac{n_{e}}{n_{s}} \)

The number of moles of ethanol is:

\(n_{e} = \frac{m_{e}}{M_{e}} = \frac{268.13 g}{46.07 g/mol} = 5.82 moles\)

And the moles of the solution is:    

\( n_{s} = n_{e} + n_{w} \)

Where w is for water

\( n_{s} = n_{e} + \frac{m_{w}}{M_{w}} \)

\( n_{s} = n_{e} + \frac{m_{s} - m_{e}}{M_{w}} \)

\(n_{s} = 5.82 moles + \frac{957 g - 268.13 g}{18 g/mol} = 44.09 moles\)

Hence, the mole fraction of ethanol is:

\(\chi_{e} =\frac{5.82 moles}{44.09 moles}=0.13\)

I hope it helps you!                                                          

51.4 mL is the  volume in mL of 0.727 MCa(OH)₂  needed to neutralize 22.8 mL of 0.390 M H₃PO₄  in a titration.

A measurement of three-dimensional space is volume. It is frequently expressed in numerical form using SI-derived units or different imperial or US-standard units (such the gallon, quart, and cubic inch). Volume and length (cubed) have a symbiotic relationship.

The volume much a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the volume of fluid (liquid or gas) that the container may hold.

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

MaVa / MbVb = nA / nB

( 0.390  ×  22.8) / (0.727 × Vb) = 2/3

Vb = 51.4 mL

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The activation energy of this reaction is approximately -13.770 J/mol.

1. To graphically determine the activation energy, we need to plot two points. The given data points are:

  Point 1: (1, -1.275)

  Point 2: (2, 0.379725)

2. The rise is the change in the y-coordinate between the two points:

  Rise = y2 - y1 = 0.379725 - (-1.275) = 1.654725

3. The run is the change in the x-coordinate between the two points:

  Run = x2 - x1 = 2 - 1 = 1

4. The slope of the line formed by these two points can be calculated using the formula:

  Slope = rise / run = 1.654725 / 1 = 1.654725

5. The activation energy (Ea) can be determined using the equation:

  Ea = -R * slope

 Here, R is the ideal gas constant, which is approximately 8.314 J/(mol·K).

6. Plugging in the values:

  Ea = -8.314 * 1.654725 = -13.770 J/mol

Note that the activation energy is negative because it represents the energy difference between the reactants and the transition state (higher energy) in an exothermic reaction.

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Answer:

A mixture of ethane and ethene occupies 40 litre at 1.00 atm and at 400 K.The mixture reacts completely with 130 g of O2 to produce CO2 and H2O . Assuming ...

Missing: 32 ‎Br2

The balancing of chemical equations is based on the law of conservation of mass.

How could a chemical process be made to balance out? Which integers can be changed, and which cannot?

When an equation is balanced, the coefficients can only be changed (the numbers in front of molecules or atoms).

The coefficients are indicated by the numerals in front of the molecule. Subscripts are the smaller numerals found following atoms. These cannot be changed while balancing chemical equations!

How is a chemical equation brought to equilibrium?

the algebraic balancing technique. Chemical equations can be balanced by assigning algebraic variables as stoichiometric coefficients to each species in the unbalanced chemical equation.

Equations in mathematics are used to calculate the values of each of these variables

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We can actually deduce here that the purpose of this assignment is to teach students about decomposition reactions and allow them to determine the percent yield.

By performing the experiment, students will gain a better understanding of the concepts involved and how they relate to their overall learning.

The specific focus of this assignment is the decomposition of sodium bicarbonate (NaHCO3) to produce sodium carbonate (Na2CO3), water (H2O), and carbon dioxide (CO2). The unbalanced chemical equation for this reaction is:

NaHCO3 (s) + heat -> Na2CO3 (s) + H2O (g) + CO2 (g)

To understanding the reaction itself, students will also learn about the concept of percent yield. Percent yield is a measure of the efficiency of a chemical reaction and is calculated by dividing the actual yield of the desired product by the theoretical yield, then multiplying by 100.

This calculation allows students to assess how well the reaction proceeds in terms of producing the expected amount of sodium carbonate.

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Answer:

Copper (i) iodide

Cu is copper and I is iodine

Answer: 2

Explanation: Calcium has a +2 charge and PO4 has a -1 charge. When writing this expression, the charges are flipped; instead of Ca2(PO4), it's Ca(PO4)2.

Answer:

1H2 + O2 -> 2Н2O.

combination reaction.

Answer: looking for improvements

Explanation:

Answer:

B. Looking for improvements

Explanation:

took the quiz and got in right on a pex

Answer:

Thermal energy comes from heat sources that provide energy from it's temp.

Explanation:

Produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. The energy that comes from the temperature of the heated substance is called thermal energy. 6 min, 47 sec Heat Energy.

(If this doesn't help let me know in the comments, I'll try to explain better :> )

Answer:

C. 2,3,3,4-tetramethylhexane

Explanation:

Answer:

In a reactivity series, the most reactive element is placed at the top and the least reactive element at the bottom.

The simplified expression for the given expression is:40T^2 × T^98 × (4^181) / 4^67

Given expression : (4^-3)^-3 × (4^0)^-9 × (4^6)^-3 × (-4)^-49 × (2T)^2 × (T^2)^49 × (-4)^181 × 40To simplify the given expression, we use the following properties of exponents : For any real numbers a, b and n, we have ;a^-n = 1/a^n and a^n × a^m = a^(n+m)Let's simplify each term of the given expression one by one:(4^-3)^-3 = 4^(9) because when a negative exponent is raised to another negative exponent, it becomes positive. (4^-3)^-3 = 4^(-3×-3) = 4^(9)(4^0)^-9 = 4^0 = 1 because any number raised to the power of 0 is equal to 1(4^6)^-3 = 4^(-6×3) = 4^(-18) because when a negative exponent is multiplied by another negative exponent, it becomes positive.(-4)^-49 = -1/(4^49) because when a negative exponent is raised to another negative exponent, it becomes positive and also negative.(-4)^181 = (4^181) because when an odd negative power of a negative number is raised to another power, it becomes negative.40 = 40 as it is(2T)^2 = 4T^2(T^2)^49 = T^(2×49) = T^98(-49) = -49 as it is Now let's simplify the given expression:1 × 1/(4^49) × 4^(-18) × 40 × 4T^2 × T^98 × (4^181)40 and 4^-18 can be simplified and combined as follows:1/(4^49) × 4^(-18) × 40 = 40/(4^49 × 4^18) = 40/4^(49+18) = 40/4^67.

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Answer:10.71 g

Explanation:

The molar mass is 3230.8 g/mol

First, we need to know that the formula for the general gas law  is represented as;

PV = nRT

such that the parameters are;

Substitute the values

1 × 2.33 = n × 8.314 × 433.15

Multiply the values, we get;

n = 2.33/ 8.314 × 433.15

Divide the values

n = 6.5 × 10⁻⁴ moles

But, number of moles = mass/molar mass

Molar mass = 2.10/ 6.5 × 10⁻⁴

Molar mass = 3230.8 g/mol

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