the best graph to use for nominal or ordinal data is

Answer:

-1.25

Step-by-step explanation:

t÷3-1÷2 = t÷1+3÷9

2t-3÷6 = 9t+3=9

18t - 27 = 54 + 18

18t -54t = 18 + 27

-36t = 45

Divide through by -36

t = -1.25

Answer:

The probability that the mean of the sample would differ from the population mean by less than 36 points=0.9216

Step-by-step explanation:

We are given that

The variance of the scores on a skill evaluation test=143,641

Mean=1517 points

n=343

We have to find the probability that the mean of the sample would differ from the population mean by less than 36 points.

Standard deviation,\(\sigma=\sqrt{143641}\)

\(P(|x-\mu|<36)=P(|\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}|<\frac{36}{\frac{\sqrt{143641}}{\sqrt{343}}})\)

\(=P(|Z|<\frac{36}{\sqrt{\frac{143641}{343}}})\)

\(=P(|Z|<1.76)\)

\(=0.9216\)

Hence,  the probability that the mean of the sample would differ from the population mean by less than 36 points=0.9216

Answer:

678.24 cubic centimeters

Step-by-step explanation:

n = 25

=====================================================

Explanation:

The standard error formula for the mean is

\(\sigma_{M} = \frac{\sigma}{\sqrt{n}}\\\\\)

Since we want this 2.00 or less, this means,

\(\sigma_{M} \le 2.00\\\\\frac{10}{\sqrt{n}} \le 2.00\\\\10 \le 2.00\sqrt{n}\\\\2.00\sqrt{n} \ge 10\\\\\sqrt{n} \ge \frac{10}{2.00}\\\\\sqrt{n} \ge 5\\\\n \ge 5^2\\\\n \ge 25\\\\\)

The sample size needs to be n = 25 or larger.

In other words, the sample size needs to be at least 25.

The transformation T1 defined by T1(x1,x2,x3)=(x1,0,x3) is linear transformation among the five given questions.

A linear transformation satisfies two properties: additivity and homogeneity. That is, for any vectors u and v, and any scalars a and b:

T(u + v) = T(u) + T(v)

T(au) = aT(u)

Using these properties, we can determine which of the given transformations are linear transformations:

A. The transformation T1 defined by T1(x1,x2,x3)=(x1,0,x3)

T1(u+v) = (u1+v1, 0, u3+v3) = (u1, 0, u3) + (v1, 0, v3) = T1(u) + T1(v)

T1(au) = (au1, 0, au3) = a(u1, 0, u3) = a*T1(u)

Therefore, T1 is a linear transformation.

The transformation T2 defined by T2(x1,x2)=(2x1−3x2,x1+4,5x2)

T2(u+v) = (2(u1+v1)−3(u2+v2), u1+v1+4, 5(u2+v2))

= (2u1−3u2, u1+4, 5u2) + (2v1−3v2, v1+4, 5v2) = T2(u) + T2(v)

However, T2 does not satisfy homogeneity property. Consider a = -1 and u = (1, 1):

T2(-u) = (-2, 5, -5)

-1*T2(u) = (-2, -5, -5)

Therefore, T2 is not a linear transformation.

The transformation T3 defined by T3(x1,x2,x3)=(x1,x2,−x3)

T3(u+v) = (u1+v1, u2+v2, -(u3+v3)) = (u1, u2, -u3) + (v1, v2, -v3) = T3(u) + T3(v)

T3(au) = (au1, au2, -au3) = a*(u1, u2, -u3) = a*T3(u)

Therefore, T3 is a linear transformation.

The transformation T4 defined by T4(x1,x2,x3)=(1,x2,x3)

T4(u+v) = (1, u2+v2, u3+v3) ≠ (1, u2, u3) + (1, v2, v3) = T4(u) + T4(v)

T4(au) = (1, au2, au3) ≠ a(1, u2, u3) = a*T4(u)

Therefore, T4 is not a linear transformation.

The transformation T5 defined by T5(x1,x2)=(4x1−2x2,3|x2|)

T5(u+v) = (4(u1+v1)−2(u2+v2), 3|u2+v2|)

= (4u1−2u2, 3|u2|) + (4v1−2v2, 3|v2|) ≠ T5(u) + T5(v)

T5(au) = (4au1−2au2, 3|au2|) ≠ a*T5(u)

Therefore, T5 is not a linear transformation.

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According to the definition of triangle, the sum of 2 sides of a triangle is greater than the third side.

It means that for triangle ABC, it is true that:

For the given value 3, 36 and 39, it is assumed that the sum of 3 and 36 must be greater than 39:

The sum of 3 and 36 equals 39, is not greater than 39. It means the correct answer is Cannot be determined (Not a triangle)

Answer:

y= 0.5x + 8.2

$13.6 per hour

Step-by-step explanation:

(Is it weird that I had the same exact question? Maybe not. But I also found another person with the same question as me. It was a different question though. This is probably too late. But I'm just gonna try to answer it for anyone who needs it.

"Linear regression" is just a fancy word for scatter plots. Scatter plots take place in graphs. The dots or plots are scattered and the way they are scattered means something. If it's going down, it's negative, up it's positive, and if it's scattered, it has no corrolation.

Also, you should have learned this in 9th grade. So, check your notes.

If you don't have it, WRITE IT!!!

To find it in your calculator:

1. Go to "Lists and Spreadsheets"

2. Rename the first column "x" and the second on "y"

3. Write all of your numbers in the right column

1, 5, 3, 7 under the "x"

8.67, 10.50, 9.58, 11.41 under the "y"

4. Move your cursor to an empty cell

4. Click: "MENU" #4 #1 #3

5. Rename the correct rows "x" and "y" and press enter

6. Now you can find "m" and "b"

7. Then move your cursor to an empty cell and click "doc" "insert" #7

8. Find the x-axis and find "x"

9. Find the y-axis and find "y"

10. Now press "MENU" #4 #6 #1

And you found your y=mx+b: y=0.5x+8.2

Now, how much money per hour.

So you've found your m and b but now you have to:

1. Replace y with 15 and solve it

15=0.5x+8.2

-8.2       -8.2

6.8=0.5x

Divide 0.5 on both sides

6.8/0.5=13.6

13.6=x

$13.6 per hour

Answer:

1 torr = 760 atm

1 torr = 1 mmHg

Company A's revenue was $239 million whereas Company B's was $467 million as a result revenue for Company A was equal to 52% of that for Company B. ​

It shows the proportion between two integers when stated as a decimal fraction of 100 parts. It is a statistic used to compare two sets of data, and the sign % is used to represent it as a percentage.

It is given that, the revenue for Company A was ​$239 ​million, compared to ​$467 million for Company B.

We have to find the % by which A was revenue for Company B.

Suppose  x% by which A was revenue for Company B.

⇒$467 of x =$239

⇒467×x​=239

⇒x=239/467

⇒x=0.5177 ≈ 0.52

⇒x%=52%

Thus, the revenue for Company A was equal to 52% of that for Company B. ​

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Answer:

Step-by-step explanation:

Volume = Bh

Turn the shape so the trapezoid is on the bottom/base

h=18   for overall shape

B = area of base, trapezoid

B = 1/2 (b₁ + b₂) h  

b₁ = 11

b₂ = 25

h = 24   for trapezoid

B = 1/2 (11 + 25)(24)

B = 432

V = Bh

V = (432)(18)

V= 7776 in³

Answer:

tree C was planted first

Step-by-step explanation:

Since Tree c was 10 inches tall when it was first grown and Tree A was 5 at first and Tree B was 3 inches tall. 10>5 10>3

Answer: x=1, y=1, z=-1

Step-by-step explanation:

From the first and 3rd equation, 2x+9y=11.

The first equation is also 4x+16y-4z=24, so add that to the second equation, and you get 6x+27y=33.

Solving, we get x=1 and y=1, meaning that z=-1.

The calculated value of the probability of B is (c) 0.25

From the question, we have the following parameters that can be used in our computation:

P(A or B) = 0.3

P(A and B) = 0.2

P(A/B) =0.8

First, we have

P(A/B) = P(A and B)/P(B)

Substitute the known values in the above equation, so, we have the following representation

0.2/P(B) = 0.8

So, we have

P(B) = 0.2/0.8

Evaluate

P(B) = 0.25

Hence, the probability of B is 0.25

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10.......................

The resulting equation after multiplying the first equation by 2 and subtracting the second equation is:

-5y = -375

1. Given equations:

  - x + 3y = 350    (Equation 1)

  - 2x + 4y = 625   (Equation 2)

2. Multiply Equation 1 by 2:

  - 2(x + 3y) = 2(350)

  - 2x + 6y = 700    (Equation 3)

3. Subtract Equation 2 from Equation 3:

  - (2x + 6y) - (2x + 4y) = 700 - 625

  - 2x - 2x + 6y - 4y = 75

  - 2y = 75

4. Simplify Equation 4:

  -2y = 75

5. To isolate the variable y, divide both sides of Equation 5 by -2:

  y = 75 / -2

  y = -37.5

6. Therefore, the resulting equation is:

  -5y = -375

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To make the fractions equivalent, we need to find the missing numerators that would make them equal. Let's fill in the missing numerators:

1/2 and __/8

To make the fractions equivalent, we can multiply both the numerator and denominator of the first fraction by 4:

1/2 and 4/8

Now, the fractions are equivalent.

---

4/12 and __/60

To make the fractions equivalent, we can multiply both the numerator and denominator of the first fraction by 5:

4/12 and 20/60

Now, the fractions are equivalent.

---

2/3 and __/12

To make the fractions equivalent, we can multiply both the numerator and denominator of the first fraction by 4:

2/3 and 8/12

Now, the fractions are equivalent.

---

4/4 and __/8

To make the fractions equivalent, we can multiply both the numerator and denominator of the first fraction by 2:

4/4 and 8/8

Now, the fractions are equivalent.

Answer:

\(f(x) = {x}^{2} - 2x + 17 \\ completing \: squares \\ divide \: the \: sum \: by \: 2 \: and \: the \: result \: to \: the \: {x}^{2} and \: subtract \: it \: from \: the \: product \\ in \: this \: case. \: our \: sum \: is \: 2 \\ f(x) = ({x}^{2} \times \frac{2}{2} ) + (17 - \frac{2}{2} ) \\ f(x) = {(x + 1)}^{2} + (17 - 1) \\ f(x) = {(x + 1)}^{2} + 16\)

The point representing 0 on the real number line is the origin.

A number line is a visual representation of a set of real numbers. It is a straight line that is usually represented horizontally and it has a starting point, usually labeled as 0, which is called the origin.

Numbers to the right of the origin are positive, and numbers to the left of the origin are negative. The numbers on a number line are evenly spaced, and each point on the line represents a specific real number.

Number lines are useful in mathematics to represent numerical relationships, such as order, magnitude, and distance between numbers. They are also useful in teaching mathematical concepts, such as addition, subtraction, and fractions.

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Note: ^ is for Start of the line, $ is for end of the line ,* means 0 or more, + means 1 or more, [ab] means either a or b and {} is for specific number of times, () is for grouping.

A task in which it is necessary to create regular expressions to define five different languages. The alphabet used is A = {a, b}. The languages ​​are:

L1, which has exactly one "a" but any number of "bs".

L2, which has an odd number of "as" and an even number of "bs".

L3, which contains exactly two "as" or exactly two "bs", although not necessarily adjacent.

L4, which has all "bs" appearing before any "a" or all "as" appearing before any "b".

L5, where there can be any number of "as", but the number of "bs" must be even, although the "bs" need not be adjacent.

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The value of the function is a straight line graph

The given function is F(x)=-2cosx+4

we shall be plotting a table of values for the function

Let us chose the range of the function as follows 0≤x≤150 at 30⁰ interval

The table of values that will help us draw the graph is

f(x)                0         30           60            90         120          150

2cosx+4      6.0      5.73        5.00       4.00        3.00         2.27

The above table is best for the graph of the function

In conclusion, the graph of the function is a linear function because it shows a straight line

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(a) The value of the z-score for the 6.4 fluid ounce orange is -1.64

(b) The value of the z-score for the 3.11 fluid ounce orange is -4.63

From the question, we have the following parameters that can be used in our computation:

Mean = 8.2

Standard deviation = 1.1

The values of the z-scores is calculated as

z = (z - Mean)/Standard deviation

So, we have

z = (z - 8.2)/1.1

When the score is 6.4, we have

z = (6.4 - 8.2)/1.1

Evaluate

z = -1.64

Recall that

z = (z - Mean)/Standard deviation

So when the score is 3.11, we have

z = (3.11 - 8.2)/1.1

Evaluate the expression

z = -4.63

Hence, the values of the z-scores are -1.64 and -4.63

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Answer:

Paul earned 21 points and Jamie earned 39 points.

Step-by-step explanation:

So, you start off with 60-18=42. Now, you have how much they earned minus Jamie's bonus 18. So, now that they have earned the same amount, you divide 42/2=21. So, now you know how many points Paul earned, 21, and now you just have to add the points Jamie earned that Paul didn't back to their score. 21+18=39

Answer:

30*1.609=48.27

Hope This Helps!!!

The amounts to report at December 31, 2019 are:

Amount reported in Income

Sales revenue                   $1,000,000

Warranty expenses           $40,000

Amount reported on the balance sheet:

Unearned service revenue      $12,000

Cash                                         $1,012,000

($1,000,000 + $12,000)  

Warranty liability                       $40,000

Inconclusion the amounts to report at December 31, 2019 are: Sales revenue $1,000,000, Warranty expense $40,000, Unearned warranty revenue $12,000, Warranty liability $40,000 and Cash $1,012,000.

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Answer: To determine how much 5 inches of wire would cost at the same rate as 12 inches of wire, we can first determine the rate at which the wire is being sold by dividing the cost of the wire by the length of the wire:

36 cents / 12 inches = 3 cents/inch

We can then use this rate to determine the cost of 5 inches of wire by multiplying the rate by the length of the wire:

3 cents/inch * 5 inches = 15 cents

Therefore, 5 inches of wire would cost 15 cents at the same rate as 12 inches of wire.

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

\(t = 3.054\)

4

The p-value  is   \(p-value = P(Z > 3.054) = 0.0011291\)

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  \(n_1 = 51\)

    The first sample  mean is \(\mu_1 = 36\)

    The second sample size is  \(n_2 = 41\)

    The second sample  size is  \(\mu_2 = 25\)

     The first standard deviation is  \(\sigma _1 = 21.4 \ g\)

    The second standard deviation is  \(\sigma _2 = 12.8 \ g\)

  The  level of significance is  \(\alpha = 0.05\)

The  null hypothesis is  \(H_o : \mu_1 = \mu_ 2\)

The  alternative hypothesis is  \(H_a : \mu_1 > \mu_2\)

Generally the test statistics is mathematically represented as

    \(t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }\)

=>   \(t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }\)

=> \(t = 3.054\)

The  p-value is mathematically represented as

     \(p-value = P(Z > 3.054)\)

Generally from the z table  

             \(P(Z > 3.054) = 0.0011291\)

=>   \(p-value = P(Z > 3.054) = 0.0011291\)

From the values obtained  we see that \(p-value < \alpha\) so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The value of the difference in the mean number of chips eaten can be used to test the hypothesis.

The correct responses are;

Reasons:

The given parameters are;

The amount of Walker Crisps potato chips children ate, based on commercial watched.

Celebrity endorsed food snack commercial mean, \(\overline x_1\) = 36 g

Sample size that watched the celebrity endorsed commercial, n₁ = 51

Alternative food snack commercial mean, \(\overline x_2\) = 25 g

Sample size that watched the other commercial = 41

Standard deviation, SD,  of the samples;

Sample that watched the celebrity endorsed commercial, SD₁ = 21.4 g

Sample that watched the other commercial, SD₂ = 12.8 g

Reasons:

1. The claim from the question is; The mean amount of Walker Crisp eaten was significantly higher for the children who watched the sports celebrity - endorsed Walker Crisps commercial.

The null hypothesis is, H₀; \(\overline x_1 = \overline x_2\) (There is no difference in the mean)

The alternative hypothesis is, Hₐ; \(\overline x_1\) > \(\overline x_2\) (The mean of the amount of Walker Crisps eaten is significantly higher for the children that watched the sports celebrity-endorsed commercial)

2. Given that the aim of the study is to determine if the mean of the first

sample is higher than the mean of the second sample, the kind of test to

be performed is the test of the difference in the mean of the two samples

based on specified hypothesis, (one sample is higher), which is done using

a t-test, given that the population mean is not specified (unknown).

The kind of test to use is a t-test

3. The test statistic is given by Welch's Test for unequal variance as follows;

\(\displaystyle t = \mathbf{\frac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{s_1^2}{n_1} +\dfrac{s_2^2}{n_2} } }}\)

Which gives;

\(\displaystyle t = \frac{36- 25}{\sqrt{\dfrac{21.4^2}{51} +\dfrac{12.8^2}{41} } } = \frac{77500}{25379} \approx 3.054\)

The test statistic, t ≈ 3.054

4. From the above test statistic and by finding, degrees of freedom, df as follows, the p-value can be found.

\(\displaystyle df = \mathbf{\frac{\left(\dfrac{s_1^2}{n_1} +\dfrac{s_2^2 \righ}{n_2} \right)^2}{\dfrac{1}{n_1 - 1} \cdot \left( \dfrac{s_1^2}{n_1} \right)^2 + \dfrac{1}{n_2 - 1} \cdot \left( \dfrac{s_2^2}{n_2} \right)^2}}\)

Which gives;

\(\displaystyle df = \frac{\left(\dfrac{21.4^2}{51} +\dfrac{12.8^2 \righ}{41} \right)^2}{\dfrac{1}{51 - 1} \cdot \left( \dfrac{21.4^2}{51} \right)^2 + \dfrac{1}{41 - 1} \cdot \left( \dfrac{12.8^2}{41} \right)^2} \approx \mathbf{83.69}\)

From the t-test table, we have the p-value of the result as follows;

The p-value is; 0.001 < P(t > 3.054) < 0.0025.

5. The conclusion that can be made is; Given that the p-value of the test

statistic is less than the given alpha value of 0.05, we reject the null

hypothesis, given that there is significant statistical evidence to show that

the mean amount of Walker Crisp eaten was significantly higher for the

children that watch the celebrity-endorsed Walker Crisps commercial.

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Answer:

8.33% probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)

In which

P(B|A) is the probability of event B happening, given that A happened.

\(P(A \cap B)\) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Has the disease

Probability of a positive test:

10% of 100-1 = 99%

90% of 1%

So

\(P(A) = 0.1*0.99 + 0.9*0.01 = 0.108\)

Positive test and having the disease:

90% of 1%

\(P(A \cap B) = 0.9*0.01 = 0.009\)

What is the conditional probability that she does, in fact, have the disease

\(P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.009}{0.108} = 0.0833\)

8.33% probability that she does, in fact, have the disease

The answer is:

g(x + 1) = 6x + 1

g(4x) = 24x -5

Work/explanation:

To evaluate, I plug in x + 1 into the function:

\(\sf{g(x)=6x-5}\)

\(\sf{g(x+1)=6(x+1)-5}\)

Simplify

\(\sf{g(x+1)=6x+6-5}\)

\(\sf{g(x+1)=6x+1}\)

------------------

Do the same thing with g(4x)

\(\sf{g(4x)=6(4x)-5}\)

\(\sf{g(4x)=24x-5}\)

Hence, these are the answers.