The bridge to cross the Neches River between Evadale and Silsbee is a toll bridge. It cost cars $3 to cross and trucks $5 to cross. Last Saturday a total of 76 cars and trucks crossed the bridge and the total tolls charged was $276. How many trucks crossed the bridge?

Answer:

d

Step-by-step explanation:

Answer:

Here's the answer

JUST correct me if I'm wrong

Step-by-step explanation:

Btw brainliest me plss

Answer:

4762

Step-by-step explanation:

0.21g x 10,000= 2100

0.21 x 5,000= 1050

0.21 x 4,000= 840

0.21 x 4700 =  987

0.21 x 4760 = 999.6

0.21 x 4762= 1000.02

( how much it's made from x the quantity = the grams or kg)

Euclid receives 20 shares of common stock as a nontaxable stock dividend.The basis of the common stock remains the same as in scenario a, which is $96.15 per share.

To calculate the per share basis, we divide the original purchase cost by the total number of shares (including the dividend shares).  In scenario b, Euclid receives a nontaxable preferred stock dividend of 20 shares. The preferred stock has a fair market value of $5,000, and the common stock, on which the preferred is distributed, has a fair market value of $75,000.

The tax consequences involve determining the new basis of the preferred stock and the common stock after the dividend. a. To find the per share basis of Euclid's common stock after receiving the stock dividend, we divide the original purchase cost by the total number of shares. The original purchase cost was $50,000 for 500 shares, which means the per share basis was $50,000/500 = $100. After receiving 20 additional shares as a dividend, the total number of shares becomes 500 + 20 = 520.

Therefore, the new per share basis is $50,000/520 = $96.15. b. In this scenario, Euclid receives a preferred stock dividend of 20 shares. The preferred stock has a fair market value of $5,000, and the common stock has a fair market value of $75,000. To determine the new basis of the preferred stock, we consider its fair market value.

Since the preferred stock dividend is nontaxable, its basis is equal to the fair market value, which is $5,000.

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The length of G’J’ is 3.5 units

Hence, the correct option is 3.5 units.

What is dilation?

In mathematics, dilation is a geometric transformation that changes the size of an object, but not its shape. Dilation involves stretching or shrinking an object by a certain scale factor while maintaining its proportions.

To find the length of G’J’, we first need to find the coordinates of G’, I’, and J’, which are the images of G, I, and J after dilation with a scale factor of 1/2.

The coordinates of G’ can be found by multiplying the x-coordinate and y-coordinate of G by 1/2:

G'(-41/2, 21/2) = (-2, 1)

Similarly, the coordinates of I' and J' can be found by multiplying the x-coordinate and y-coordinate of I and J by 1/2:

I'(61/2, 31/2) = (3, 1.5)

J'(31/2, 21/2) = (1.5, 1)

Now we can find the length of G’J’ by using the distance formula between G’ and J’:

d(G’J’) = √[(x2 - x1)² + (y2 - y1)²]

= √[(1.5 - (-2))² + (1 - 1)²]

= √[3.5²]

= √12.25

= 3.5

Therefore, the length of G’J’ is 3.5 units

Hence, the correct option is 3.5 units.

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The probability of of a random student having blue eyes and dark hair

 is 35% .

let consider the total students in the school be (U) = 100%

out of them ,

students having blue eyes (A) = 60%

students having  dark hair (B) = 55%

students with neither blue eyes nor dark hair (A∪B)' = 20%

let the students with blue eyes and dark hair be (A∩B) = x %

Then according to the set theorem

U = n(A∪B) + n(A∪B)'

U = n(A) + n(B) - n(A∩B) + n(A∪B)'

100 = 60 + 55 - x +20

∴ x = 60 + 55 +20 - 100

x = 35 %

So the probability of random student having blue eyes and dark hair is 35% .

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48 feet long (horizontally) would a ramp need to extend to elevate a person from a height of 2 feet to a height of 6 feet

The ratio between a distance on a map and its actual distance on the ground is known as the map's scale. Since scale must vary throughout a map due to the curvature of the Earth's surface, this straightforward idea is made more difficult. This change makes the idea of size significant in two different ways.

Given, ADA guidelines mandate a 1:12 ratio of rise to run for wheelchair ramps.

That means to raise a height of 1 foot we need to give a slope of 12 feet.

Since total height to elevate = 6-2

Since total height to elevate = 4 feet

Thus, an increase in elevation that could result in = 4 * 12

an increase in elevation that could result in = 48 feet

Also given, If a ramp extends 30 feet horizontally

The maximum increase in elevation that could result in = 30 /12

therefore, the maximum increase in elevation that could result is 2.5 feet.

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Answer:

the answer will be be 0.25 for decimal but for a fraction it would be 1/4

Answer:

0.25 is the answer :D

Many psychologists consider the distinguishing feature of adolescent thought to be the ability to think in terms of abstract concepts or hypothetical situations.

These cognitive abilities play a crucial role in adolescent development, facilitating problem-solving, decision-making, and the exploration of identity and future possibilities.

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Answer: get smart bro

you would know it if you was smart

Step-by-step explanation:

you wont do your work, you always cheat, and you don't listen to the teacher

you need to find the answer out on your own.

P.S. i hope you have a good day :)

Answer:

4.6 and 3.5 and 3.6.

Step-by-step explanation:

Because they have to be in a range between 3.7 and 4.3.

Answer: D

Step-by-step explanation:

9.6/2.1 ~ 4.571

30 - 28 = 2

10^2 = 100

4.571*100 = 457.1

Answer:

183

Step-by-step explanation:

-8(.75)-2(5+-4-4-4)+7(5)(5)

-8(.75) = -6

-6-2(5+-4-4-4)+7(5)(5)

(5+-4-4-4) = (-7)

-6-2(-7)+7(5)(5)

7(5)(5) = 175

-6-2(-7)+175

-2(-7) = 14

-6+14+175=183

Answer:

A 7.85 cm2 should be right

Answer:

-17

Step-by-step explanation:

Every number x goes up, the f(x) goes up by 9. -8+9=1 and 1+9=10. Therefore if the number goes down, you subtract. -8-9=-17

The correlation coefficient of

(a) X1 + X2 and X2 + X3  would be 1/2.

(b) X1 + X2 and X3 + X4 would be 0.

What is the correlation in statistics?

Correlation is a statistical measure (a number) that describes the magnitude and direction of a relationship between two or more variables. A correlation between variables, on the other hand, does not imply that a change in one variable is the cause of a change in the values of the other variable.

(a) X1 + X2 and X2 + X3.

We have

Cov(X1 + X2, X2 + X3) = Cov(X1, X2) + Cov(X1, X3) + Cov(X2, X2) + Cov(X2, X3)

                                    = 0 + 0 + Var(X2) + 0

                                    = 1.

We know that

Var(X1 + X2) = Var(X1) + Var(X2) + 2 Cov(X1, X2) = 1 + 1 + 2 · 0 = 2.

Similarly, Var(X2 + X3) = 0. So the correlation between X1 + X2 and X2 + X3 is

                        \(=\frac{Cov(X1+X2, X2+X3)}{\sqrt{Var(X1 + X2) Var(X2 + X3)} }\\\\=\frac{1}{\sqrt{2.2} }\\\\=\frac{1}{2}\)

(b) X1 + X2 and X3 + X4.

Since

Cov(X1 + X2, X3 + X4) = Cov(X1, X3) + Cov(X1, X4) + Cov(X2, X3) + Cov(X2, X4)

                                   = 0 + 0 + 0 + 0

                                   = 0,

the correlation between X1 + X2 and X3 + X4 is 0.

Hence, the correlation coefficient of X1 + X2 and X2 + X3  would be 1/2

and X1 + X2 and X3 + X4 would be 0.

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The answer is C: \(h = \frac{2A}{b}\)

Starting with the given formula for the area, A = 1/2hb, the first step is to isolate h by using the multiplicative inverse of b, which is \(\frac{1}{b}\) on both sides of the equation:

\(A(\frac{1}{b}) = \frac{1}{2}hb* (\frac{1}{b})\)

The result will be:

\(\frac{A}{b} = \frac{1}{2}h\)

The last step is to use the multiplicative inverse of \(\frac{1}{2}\), which is 2 or \(\frac{2}{1}\) to further isolate the variable h :

\(\frac{A}{b} (\frac{2}{1}) = (\frac{2}{1}) \frac{1}{2} h\)

The formula for h will be:

\(h = \frac{2A}{b}\)  which is the option C in your question.

Answer:

The value of n is 0.64

Step-by-step explanation:

10^3 = 1000

640 divided by 10^3 = 0.64

(a) If \($A$\) is a subset of B and B is a subset of C, then A is a subset of C.

(b) \(A\cup B\setminus A = B\setminus A$.\)

(c) \(A\cup\bigcup_{i=1}^n a_i = \bigcup_{i=1}^n a_i$, but equality may fail for $n=\infty$.\)

(a) If \(A\subseteq B$, then $C\cap A\subseteq C\cap B$.\)

Therefore, if \(A\subseteq B$, then $C\cap B\subseteq C\cap A$\) implies that\($C\cap A=C\cap B$.\)

Hence, if \(A\subseteq B$, then $C\cap A\subseteq C\cap B$\) and \(C\cap B\subseteq C\cap A$,\) which together imply that\($C\cap A=C\cap B$. So if $A\subseteq B$,\) then\($C\cap A=C\cap B$\)  implies that \(C\subseteq B$.\)

(b) We have \(A\cup B=A\cup (B\setminus A)$,\) so \($A\cup B\setminus A=(A\cup B)\setminus A=B$\) by the set-theoretic identity \(A\cup (B\setminus A)=(A\cup B)\setminus A$.\)

Therefore, \(A\cup B\setminus A=B$.\)

(c) Let \(X={1,2,3}$, $A={1}$, $a_1={1}$, $a_2={2}$, $a_3={3}$,\) and \(a_4={2,3}$.\)

Then\($A\subseteq\bigcup_{i=1}^4 a_i$ and $\bigcup_{i=1}^3 a_i\not\subseteq\bigcup_{i=1}^4 a_i$.\)

Therefore,\($A\cup\bigcup_{i=1}^3 a_i=\bigcup_{i=1}^4 a_i$\) and \(A\cup\bigcup_{i=1}^4 a_i\neq\bigcup_{i=1}^4 a_i.\)

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(a)If ACB, then CB  is a subset of C.

(b) AUB-AU is not a subset of AUB.

(c) UAa3υλα equality fails in this case.

(a) If ACB, then CB:
Let x be an element of C. If x is in A, then it is also in B (since ACB), and therefore in C (since B is a subset of C). If x is not in A, then it is still in C (since C is a superset of B), and therefore in B (since ACB). In either case, x is in CB, so CB is a subset of C.

(b) AUB-AU:
Let x be an element of AUB. If x is in A, then it is not in AU (since it is already in A), and therefore it is in AUB-AU. If x is not in A, then it must be in B (since it is in AUB), and therefore it is not in AU (since it is not in A), and therefore it is in AUB-AU. Thus, every element of AUB is also in AUB-AU, and therefore AUB-AU is a subset of AUB. On the other hand, if x is in AU but not in AUB, then it must be in U (since it is not in A or B), which contradicts the assumption that A and B are subsets of X. Therefore, AUB-AU is not a subset of AUB.

(c) UAa3υλα; give an example where equality fails:
Let X = {1,2,3}, A = {1}, B = {2}, and Αα = {1,3}. Then UAa3υλα = {1,2,3} = X, but AUB = {1,2} and AU = {1}, so AUB-AU = {2} is not equal to X. Therefore, equality fails in this case.
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To assess the correctness of the curved arrow notation in each case, specific examples or instances of the notation are needed. Without such examples, it is challenging to provide a meaningful analysis or explanation of whether the curved arrow notation is correct or incorrect.

Curved arrow notation is commonly used in organic chemistry to represent electron movement in chemical reactions and mechanisms. It indicates the flow of electrons, such as the movement of lone pairs, bonding electrons, or the formation/breakage of bonds. The notation is essential for understanding reaction mechanisms and the distribution of electron density in molecules.

To determine the correctness of curved arrow notation, one needs to evaluate whether it accurately represents the movement of electrons according to the established rules and principles of organic chemistry. This involves considering factors such as electron pair repulsion, formal charges, bond breaking/forming, and resonance structures.

Without specific examples or instances of the curved arrow notation in question, it is not possible to provide a comprehensive analysis or explanation. If you can provide specific examples or questions regarding the curved arrow notation, I would be glad to assist you further.

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the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

To write the system of ordinary differential equations (ODEs) for the transition probabilities Pᵢⱼ(t) of the given continuous-time Markov chain, we need to consider the rate at which the system transitions between different states.

Let Pᵢⱼ(t) represent the probability that the Markov chain is in state j at time t, given that it started in state i at time 0.

The ODEs for the transition probabilities can be written as follows:

dP₁₂(t)/dt = q₁₂ * P₁(t) - q₂₁ * P₂(t)

dP₁₃(t)/dt = q₁₃ * P₁(t) - q₃₁ * P₃(t)

dP₂₁(t)/dt = q₂₁ * P₂(t) - q₁₂ * P₁(t)

dP₂₃(t)/dt = q₂₃ * P₂(t) - q₃₂ * P₃(t)

dP₃₁(t)/dt = q₃₁ * P₃(t) - q₁₃ * P₁(t)

dP₃₂(t)/dt = q₃₂ * P₃(t) - q₂₃ * P₂(t)

where P₁(t), P₂(t), and P₃(t) represent the probabilities of being in states 1, 2, and 3 at time t, respectively.

Now, let's consider the second part of the question: Suppose that the initial state is 1. We want to find the probability that after the first transition, the process X(t) enters state 2.

To calculate this probability, we need to find the transition rate from state 1 to state 2 (q₁₂) and normalize it by the total rate of leaving state 1.

The total rate of leaving state 1 can be calculated as the sum of the rates to transition from state 1 to other states:

total_rate = q₁₂ + q₁₃

Therefore, the probability of transitioning from state 1 to state 2 after the first transition can be calculated as:

P(X(t) enters state 2 after the first transition | X(0) = 1) = q₁₂ / total_rate

In this case, the transition rate q₁₂ is 1, and the total rate q₁₂ + q₁₃ is 1 + 2 = 3.

Therefore, the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

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Answer: 4/3 or 1 & 1/3 cups of vinegar

Step-by-step explanation:

1. Set a proportion: 3/4 : 1/2

2. Divide 2 by 3/4 to get 2 & 2/3

3. Multiply 2 & 2/3 and 1/2 together to get 4/3 or 1 & 1/3

The number of unique numbers that can be made from creating a fraction with or in the numerator and/or in the denominator can be infinite if repetition is allowed, or depend on the range of numbers available if repetition is not allowed.

When creating a fraction, the numerator represents the number above the fraction line, while the denominator represents the number below it.

To determine the number of unique numbers that can be made, we need to consider two scenarios:
1. If we are allowed to repeat the numbers:

If we can use the same number more than once in both the numerator and denominator, the number of unique numbers that can be created is equal to the total number of possible numbers.

This would be infinite, as there is no limit to the numbers we can use.
2. If we cannot repeat the numbers: If each number can only be used once, the number of unique numbers that can be created depends on the range of numbers available.

For example, if we have the digits 1, 2, 3, and 4, we can create 24 unique fractions (4 factorial or 4!).

This is because we have 4 choices for the numerator, and once we choose a number, there are 3 choices left for the denominator, then 2 choices for the second numerator, and finally 1 choice for the second denominator.
In conclusion, the number of unique numbers that can be made from creating a fraction with or in the numerator and/or in the denominator can be infinite if repetition is allowed, or depend on the range of numbers available if repetition is not allowed.

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The solutions of the equation sec² x - 4 = 0 are x = π/3 + 2kπ, 2π/3 + 2kπ, 4π/3 + 2kπ, 5π/3 + 2kπ. Therefore, option d. is correct.

We start by solving for x in the equation sec² x - 4 = 0:

sec² x - 4 = 0
sec² x = 4
sec x = ±2

Recall that sec x = 1/cos x, so we can rewrite the equation as:

1/cos² x = 4
cos² x = 1/4
cos x = ±1/2

Now we need to find all values of x that satisfy cos x = ±1/2. These values are:

x = π/3 + 2kπ or x = 5π/3 + 2kπ (for cos x = 1/2)
x = 2π/3 + 2kπ or x = 4π/3 + 2kπ (for cos x = -1/2)

Combining these solutions, we get:
x = π/3 + 2kπ, 2π/3 + 2kπ, 4π/3 + 2kπ, 5π/3 + 2kπ

Therefore, the correct answer is d. pi/3 + 2k pi, 2pi/3 + 2k pi, 4pi/3 + 2k pi, 5pi/3 + 2k pi.

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The populations from which the samples are obtained must be normally distributed.

Sampling is done correctly. Observations for within and between groups must be independent.

The variances among populations must be equal (homoscedastic).

Data are interval or nominal.

If construction of many average quality homes began in an area that is known for having many high quality homes, it is likely that the overall property values of the homes in the neighborhood would decrease.

Explanation:

The presence of many high quality homes in a neighborhood tends to contribute to higher property values. These high quality homes often set a standard and attract buyers who are willing to pay a premium for the desirable location and quality of housing.

However, when a large number of average quality homes are constructed in the same area, it can lead to a dilution of the overall quality and desirability of the neighborhood. The increased supply of average quality homes may result in increased competition among sellers and a decreased demand from buyers who are seeking higher quality homes. As a result, property values in the neighborhood are likely to decrease.

Additionally, the introduction of average quality homes may also change the perception and reputation of the neighborhood. Buyers who were initially attracted to the area for its high quality homes may be less inclined to purchase in a neighborhood with a mixture of average and high quality homes, further impacting property values.

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Answer:

A y(y+10)

Step-by-step explanation:

Answer:

y(y+10y)

Step-by-step explanation:

u would do the second because u have y2 and and 10

Answer:

80/295 = 27%

Step-by-step explanation:

Answer:

30 % of the costumers where serve tea