The centers of two slits of width a are a distance d apart. if the fourth minimum of the interference pattern occurs at the location of the first minimum of the diffraction pattern for light of wavelength λ, the ratio a/d is equal to?

The required mechanical energy used to move this book is calculated by the summation of kinetic energy and potential energy.

Mechanical energy M.E is constant in a system that has only gravitational forces or in an otherwise idealised system.

Given that, the method for calculating kinetic energy K.E is,

K.E = 1/2 × m × v²

where,

m is mass

v is velocity

Potential energy P.E is given as mass times g times height, with g as a constant 9.8 m/s².

P.E = m × g × h

where,

m is mass

g is gravity

h is height

Potential and kinetic energies combine to form mechanical energy.

So, mathematically,

M.E = K.E + P.E

"M.E = 1/2 × m × v² + m × g × h"

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Answer:

control group and experimental group

Answer:

0.45  [m/s²].

Explanation:

1) formula of the required acceleration is (V-final velocity, V₀-initial velocity, t-elapsed time):

\(a=\frac{V-V_0}{t};\)

2) according to the formula above:

a=(12-3)/20=0.45 [m/s²].

Answer:

The final velocity is 5.24 m/s

The initial speed is 65.5 m/s

Explanation:

Horizontal Motion

When an object is launched horizontally with an initial speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

\(v_x=v_o\)

The vertical component of the velocity changes in time t because gravity makes the object fall at increasing speed given by:

\(v_y=g.t\)

The maximum horizontal distance traveled by the object can be calculated as follows:

\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)

Another useful formula allows us to calculate the distance traveled by the object in terms of time t:

\(\displaystyle y=\frac{g.t^2}{2}\)

a.

The time taken for the arrow to reach the ground can be calculated by solving the above equation for t:

\(\displaystyle t=\sqrt{\frac{2y}{g}}\)

Since y=1.40 m:

\(\displaystyle t=\sqrt{0.2857}\)

t = 0.53 s

The final vertical speed is:

\(v_y=9.8.(0.53)=5.24\ m/s\)

The final velocity is 5.24 m/s

b)

The initial speed can be calculated by solving the following equation for v:

\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)

\(\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}\)

\(\displaystyle v=35\cdot\sqrt{\frac {9.8}{2(1.40)}}\)

v = 65.5 m/s

The initial speed is 65.5 m/s

The question is asking whether it is possible to find a magnetic vector potential for a given uniform surface current flowing in the xy plane and generating a magnetic field for different regions of space.

To determine whether it is possible to find a magnetic vector potential for the given scenario, we need to consider the conditions that must be satisfied. In general, a magnetic vector potential A can be found if the magnetic field B satisfies the condition ∇ × A = B. This is known as the magnetic vector potential equation.

In the given situation, the magnetic field is different for the regions above and below the xy plane. For z > 0, the magnetic field is described as B = MoK -î, and for z < 0, it is described as B = -MoK -î. To find the magnetic vector potential, we need to determine if there exists a vector potential A that satisfies the equation ∇ × A = B in each region.

By calculating the curl of A, we can check if it matches the given magnetic field expressions. If the curl of A matches the magnetic field expressions for both regions, then it is possible to find a magnetic vector potential for the given scenario. However, if the curl of A does not match the magnetic field expressions, then it is not possible to find a magnetic vector potential that satisfies the conditions.

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u= coefficient of friction = 0.77

g= gravity = 10 m/s^2

m= mass = 38.4 kg

v= speed = 0.77 m/s

Apply Newton's second law:

Sum of forces = mass x acceleration

Net Force = f - umg

a = 0 (constant speed)

F = umg = 0.77 x 38.4 x 10 = 295.68 N

Answer:

6

Explanation:

Average velocity = (change in position) / (change in time)

Therefore, (18-3) / 2.5 = 6

The average velocity of the shopping cart is 8.4 meters per second, directed towards the east.

To find the average velocity of the shopping cart, we'll use the formula for average velocity:

Average velocity = (change in displacement) / (change in time)

The change in displacement is the difference between the final position and the initial position of the shopping cart. Since the cart moves from 3.0m west of the flagpole to 18.0m east of the flagpole, the change in displacement will be:

Change in displacement = 18.0m - (-3.0m) = 18.0m + 3.0m = 21.0m

Now, we'll calculate the average velocity:

Average velocity = (21.0m) / (2.5s) = 8.4 m/s

Hence, the average velocity of the shopping cart is 8.4 meters per second, directed towards the east.

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Answer:(B) 25.0 N

Explanation:

This is what makes most since. You are wanting to look at the stress of the first wire. 25 *3 for the amount of balls handing of the string you get 75.0 N which is the max the top wire can hold without breaking! Hope this helps!

Answer:

easeaseaseas

Explanation:

Answer:

5.93 m/s (2 d.p.)

Explanation:

When a body is projected through the air with initial speed u, at an angle of θ to the horizontal, it will move along a curved path.

Therefore, trigonometry can be used to resolve the body's initial velocity into its vertical and horizontal components:

As the projectile is modeled as moving only under the influence of gravity, the only acceleration the projectile will experience will be acceleration due to gravity.

Constant Acceleration Equations (SUVAT)

\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

If the salmon jumps at an angle of 36.2° then:

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

\(s=3.02 \quad u=u \cos 36.2^{\circ} \quad v=u \cos 36.2^{\circ} \quad a=0\)

\(\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac{1}{2}at^2\\\\3.02 & = (u \cos 36.2^{\circ})t+\dfrac{1}{2}(0)t^2\\3.02 & = (u \cos 36.2^{\circ})t\\\implies t&=\dfrac{3.02}{u \cos 36.2^{\circ}}\end{aligned}\)

Acceleration due to gravity = 9.81 ms⁻²

Resolving vertically, taking ↑ as positive and using the found expression for t:

\(s=0.258 \quad u=u \sin 36.2^{\circ} \quad a=-9.81 \quad t=\dfrac{3.02}{u \cos 36.2^{\circ}}\)

\(\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac{1}{2}at^2\\\\0.258 & = (u \sin 36.2^{\circ})\left(\dfrac{3.02}{u \cos 36.2^{\circ}}\right)+\dfrac{1}{2}(-9.81)\left(\dfrac{3.02}{u \cos 36.2^{\circ}}\right)^2\\0.258&=3.02 \tan36.2^{\circ}-4.905\left(\dfrac{9.1204}{u^2 \cos^2 36.2^{\circ}}\right)\\0.258-3.02 \tan36.2^{\circ}&=-\dfrac{44.735562}{u^2 \cos^2 36.2^{\circ}}\\u^2&=-\dfrac{44.735562}{(0.258-3.02 \tan36.2^{\circ})(\cos^2 36.2^{\circ})}\\u^2&=35.18849443\\ u&=5.931989079\end{aligned}\)

Therefore, the minimum speed at which the salmon should leave the water is 5.93 m/s (2 d.p.).

Answer:

Explanation:

The answer is Temperature difference

Answer:

C

Explanation:

is the answer ,..........................

At 7 AM (13 hours after 6 PM), the temperature would be close to the average temperature of 59°F, which can be approximated to 65.9°F.

The temperature over a 24-hour period can be modeled using a sinusoidal function, given that the high temperature of 77°F occurs at 6 PM and the average temperature is 59°F.

To find the temperature at 7 AM, we need to consider the characteristics of a sinusoidal function. In this case, the function represents a single day, with the peak temperature at 6 PM and the average temperature over the 24-hour period.

Since a sinusoidal function repeats itself every 24 hours, we can infer that the low temperature would occur 12 hours after the high temperature. Therefore, at 7 AM (13 hours after 6 PM), the temperature would be close to the average temperature of 59°F, which can be approximated to 65.9°F.

To gain a deeper understanding of sinusoidal functions and their applications in modeling temperature variations over time, it would be beneficial to explore topics such as periodic functions, trigonometry, and mathematical modeling.

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Far does the jet go while accelerating = 95.2m and force catapult have to exert on jet is 4.42*105 N.

(measured in metres)

Use the formula xf = xi + v0*t+(1/2)*a*t2 The initial velocity and location are both zero! xf = 0+0+(1/2) xf = (1/2)*(68 m/s - 0 m/s)*(1/2.8s)*(2.8s)2 = 95.2 m

How much force does the catapult have to exert on the jet?

(N) Because F = m*a and Force = mass*acceleration, F = (18,200 kg)*(68 m/s - 0 m/s)*(1/2.8s) = 4.42*105 N.

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White phosphorous (p4) is used in military incendiary devices because it ignites spontaneously in air. 19.33 grams of P4 will react with 25.0 grams of O2.

To determine how many grams of P4 will react with 25.0 grams of O2, we need to use the balanced chemical equation. According to the equation, 1 mole of P4 reacts with 5 moles of O2. From the molar masses of P4 (123.89 g/mol) and O2 (32.00 g/mol), we can calculate the grams of P4 that will react with 25.0 grams of O2.

1. Write the balanced chemical equation: P4 + 5O2 -> P4O10
2. Calculate the molar mass of P4: 4 * 30.97 g/mol = 123.89 g/mol

3. Calculate the moles of O2: 25.0 g / 32.00 g/mol = 0.78125 mol
4. According to the balanced equation, 1 mole of P4 reacts with 5 moles of O2.

Therefore, we need 0.78125 mol * (1 mol P4 / 5 mol O2) = 0.15625 mol of P4.
5. Convert moles of P4 to grams: 0.15625 mol * 123.89 g/mol = 19.33 grams.
Therefore, 19.33 grams of P4 will react with 25.0 grams of O2.

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Answer:

when a force is applied by one object to a second object, an equal and opposite force is applied back on the first object

Explanation:

The two carts' total linear momentum will be zero in the end.

Linear momentum is a vector quantity and is defined as the sum of an object's mass, m, and velocity, v. Informally, the letter "p" is used to denote it and to refer to momentum. The momentum of a body always points in the same direction as the velocity vector, as you should be aware of.

Collision is the phrase used to describe how two items interact. Both elastic and inelastic collisions are possible types of collisions.

In this instance, two identical carts approach one another at the same speed, and a collision results. The kinetic energy of an inelastic collision is wasted, while the momentum before and after the contact remains unchanged.

When two objects collide, they stick to one another and move at the same speed.

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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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Answer:

15.0 N

Explanation:

see pic

Answer:

Speed.

Their speeds are different; Have you ever heard the metaphor the speed of light? For this case, we must turn that into a reality. So, people refer to light speed as the fastest travelling thing in the world, and that is right, unless there is a thing faster than light that was never classified. Unlikely the case. The speed of sound through air travels a lot slower than light. Look at the diagrams below to see what I mean by that.

                                                             • • •

As shown in the diagrams, sound speed is WAY slower than light speed!

Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

They cannot be divided and still keep the properties of the element true about all of these atoms. Option D is corect.

The atom consists of matter that may be split without releasing electrical charges.

It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.

In the nucleus proton and the neutron is exists. The condition of the atom to be electrically neutral is that the number of the proton and electron should be the same.

They cannot be separated while still maintaining the element's characteristics for each and every one of these atoms.

Hence, option D is corect.

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Answer:

The correct answer is d, they cannot be divided and still keep the properties of the element.

Explanation:

You're welcome :)

Answer:

B. they must be intrinsically far more luminous than the brightest galaxies.

Explanation:

Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.

Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."

This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.

Answer:

Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

\(t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})}\) where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

\(16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)}\) and

\(16.0=\frac{83640x+2928}{4182x+292.8}\) and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

Answer: a=3946.35m/s2 for the centripetal acceleration at the tip of a helicopter blade with a length of 4.90 m and a rotational speed of 310 rev/min.

The helicopter's blade measures 4.9 meters long overall.

w=300rev/min =31.41rad/s, the blade's angular velocity

The three different categories of accelerated motions are uniform acceleration, non-uniform acceleration, and average acceleration. When an object moves in a straight path while experiencing equal-interval increases in velocity, this motion is referred to as having uniform acceleration.

The change in displacement is measured in terms of velocity. The amount of change in speed is known as acceleration. Given that it has both a magnitude and a direction, velocity is a vector quantity.

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(1) The rock came to be in a various position than you thought it was by way of the wonder of refraction. The rock's position seemed different due to light refraction as it travels at varying speeds through different mediums.

2. Rock looks red as it absorbs all colors of sunlight except red.

2b.  When white light enters water, it refracts and splits into various colors.

This causes the object to perform at a different position than it literally is. In this case, the light indications coming from the rock were bent when they entered the water, making the rock to appear at a more ignorant wisdom than it actually was.

Therefore, in response to question 2, rock appears red by way of the selective assimilation and reflection of light. The rock absorbs all of the banner of silvery light except for flaming, which is mirrored back to our eyes. This is because the microscopic structure of the rock absorbs all the banner except that red, that is reflected back.

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The concepts required to solve the problem are Amperes law and Biot-savart law.

According to Amperes law, "the sum of the length elements times the magnetic field is permeability times the electric current enclosed in the loop".

\($$\oint \vec{B} \cdot \overrightarrow{d s}=\mu_{0} I$$\)

Here,

is the magnetic field,

\(\vec{B}$$\)

is the length element,

\($$\overrightarrow{d s}$$\)

is the permeability of free space and

is the current.

\($$B=\int \frac{\mu_{0} I d \vec{l} \times \hat{r}}{4 \pi r^{2}}$$\)

Here,

is the length element,

is the unit vector, and

is the distance of the point from the wire.

Amperes law equation is as follows:

\($$\oint \vec{B} \cdot \overrightarrow{d s}=\mu_{0} I$$\)

If the loop has

\($N$\)

turns and

\($2 \pi r$\)

is substituted for

\($\overrightarrow{d s}$\)

the magnetic field can be calculated below:

\($$\begin{gathered}\oint \vec{B} \cdot \overrightarrow{d s}=\mu_{0} N I \\B(2 \pi r)=\mu_{0} N I \\B=\frac{\mu_{0} N I}{2 \pi r}\end{gathered}$$\)

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Answer:

Hey there!

Inclined planes are used to lift heavy objects to higher places.

Hope this helps :)

Answer:

Inclined planes are used to lift heavy objects to higher places.

Explanation:

Answer:

try this

Explanation:

The energy of a falling object when it hits the ground is equaled to the energy it starts with because the potential energy is converted into kinetic energy entirely with the height at 0. This means the energy would be 200 J.

RESULT

83.33ms-² is the rocket's acceleration

a = 10,000–5,000/(60)

a=5,000/60

a=83.33ms-²

Fuel and an oxygen supply, known as an oxidizer, are combined and blasted in a combustion chamber of a rocket engine. The combustion process generates hot exhaust, which is directed through a nozzle to accelerate the flow and generate thrust.

Propulsion is the application of a force to modify the velocity of a vehicle, influencing both its speed and direction. This force is commonly referred to as thrust in aeronautical vehicles.

Today, liquid hydrogen is the American space program's hallmark fuel, and it is employed by other countries in the satellite launch sector. Boeing's Delta III and Delta IV now include liquid-oxygen/liquid-hydrogen upper stages, in addition to the Atlas.

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A galaxy in the local group  is most likely to be the oldest.

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We can conclude that the force exerted on each wand is repulsive, as the charges are both of the same sign.

Magnitude is a measure of the size of a physical quantity usually explain it as a numerical value of the octane used to compare the relative size of different object or phenomena it is typically used to measure the intensity soldiers trained the something magnitude is a concept applicable how many different physical quantities of the light sound and its speed and force.

The magnitude of the force exerted by each wand can be calculated using Coulomb’s Law, which states that the force is equal to the product of the two charges, divided by the square of the distance between them. Since we know the charge on the white-faced wand, we can calculate the force:

F = (1.38 x 10-10 C)2 / (1.35 cm x 10-2 m)2

F = 0.0012 N

The force between the two wands is repulsive, as the charges are both of the same sign.

Assuming that the wands are not charged before they are rubbed together and that the distance between them remains constant, we can conclude that the force exerted on each wand is repulsive, as the charges are both of the same sign.

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