Answer:
Mechanical energy
Explanation:
The chemical energy in the food gets changed into the mechanical energy of moving muscles.
How to calculate the friction force when a ball travel through a loop (like in a roaller-coater) at a point omewhere between the top and the bottom of the loop?
To calculate the friction force when a ball travel through a loop , we should use ½ mv^2 + mgh.
Physical friction is all around us. Static friction is the resistance to an object moving along a path. Finally, explain it with a simple example. Consider the common activity we all engage in: walking. While working, we are constantly in contact with the floor. As we advance our feet, motion pushes against the ground as we move backward. The fact that friction operates in the opposite direction from relative motion is one important concept to be aware of in order to minimize friction. This phenomenon might be helpful for slowing down the action until it eventually stops.
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An airline tracks each of its airplanes' stops for the day. A particular airplane can travel to one of the following cities for each of its stops:
What is the probability that the stops include Boston and Chicago?
The probability of the stops including Boston and Chicago is 1/100 when an airline tracks each of its airplanes' stops for the day.
To calculate the probability of an airplane making stops in both Boston and Chicago, we need to know the total number of possible cities that the airplane can stop in. Let's say there are 10 possible cities.
The probability of the airplane stopping in Boston on any given stop is 1/10 (since there are 10 possible cities). The same goes for Chicago.
To calculate the probability of the airplane stopping in both Boston and Chicago, we need to multiply the probabilities of each stop. So, the probability of the airplane stopping in both Boston and Chicago on any given day is:
1/10 * 1/10 = 1/100
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SI UNIT OF GRAVITY is the
Answer:
G
Explanation:
6. The engine of the car drives the car with a force of 700 N
with a speed of 40 m/s
If thrust, calculate the engine power.
ok
Here work done by the car against the force of air in each second denotes the power needed to overcome air resistance at that particular speed. The power of engine is 28 kW.
What is power?The power of an object denotes the rate of performing the work. It is defined as the work done in unit time. The SI unit of power is Watt (W) which is also called joules per second.
Power = Resistance × Speed of vehicle
Here the air resistance is found to be 700 N. Then,
Power = 700 × 40 = 28000 N m/s = 28 kW
Thus the engine power is 28 kW.
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You kick a soccer ball across a field the ball travels across the field and slowly comes to a stop. Since the ball slowly comes to a stop what does that mean about the acceleration of the ball?
Answer:
the acceleration is negative which means it is going in the opposite direction of the actual motion which concludes the reason why the ball is slowing down. However, when the ball is stopped, there is no acceleration as the ball is in equilibrium
Explanation:
An airplane flies on a level path. There is a pressure difference of 587 Pa between the lower and upper surfaces of the wings. The area of each wing surface is about 100 m2. The air moves below the wings at a speed of 80.5 m/s.Estimate the air speed above the wings. Density of air is 1.29 kg/m3.
ANSWER:
85.97 m/s
STEP-BY-STEP EXPLANATION:
Bernoulli’s theorem is written as:
\(P_1+\frac{1}{2}\cdot\rho\cdot v^2_1+\rho\cdot g\cdot h_1=P_2+\frac{1}{2}\cdot\rho\cdot v^2_2+\rho\cdot g\cdot h_2\)The potential energy is zero as the height is same, therefore:
\(\begin{gathered} \rho\cdot g\cdot h=0 \\ P_1+\frac{1}{2}\cdot\rho\cdot v^2_1+0=P_2+\frac{1}{2}\cdot\rho\cdot v^2_2+0 \\ P_1+\frac{1}{2}\cdot\rho\cdot v^2_1=P_2+\frac{1}{2}\cdot\rho\cdot v^2_2 \\ \text{ we solve for }v_1\colon \\ \frac{1}{2}\cdot\rho\cdot v^2_1=P_2-P_1+\frac{1}{2}\cdot\rho\cdot v^2_2 \\ v^2_1=\frac{2}{\rho}\cdot(P_2-P_1)+\frac{2}{\rho}\cdot\frac{1}{2}\cdot\rho\cdot v^2_2 \\ v^2_1=\frac{\Delta P}{\rho}+v^2_2 \\ v_1=\sqrt[]{\frac{2\Delta P}{\rho}+v^2_2} \\ \text{ replacing the values:} \\ v_1=\sqrt[]{\frac{2\cdot587}{1.29}+80.5^2} \\ v_1=85.97\text{ m/s} \end{gathered}\)The air speed above the wings is 85.97 m/s
seafloor topography can be mapped by satellite sensors that use: group of answer choices electromagnetic waves that pass through ocean water and bounce back to the satellite from the seafloor. extremely sensitive cameras that sense electromagnetic radiation being emitted by the seafloor. sound waves that pass through ocean water and bounce back to the satellite from the seafloor. electromagnetic waves that bounce back to the satellite from the sea surface.
Answer:wet wet
Explanation:
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Include a picture, video, or diagram of your model of lunar phases or eclipses.
Provide a description of how you made your model and how it demonstrates eclipses or lunar phases.
Include a one-paragraph reflection on the success of your model in explaining your event.
Include the name of the person you taught about your event and that person's description of what they learned from your model.
The lunar phases are caused by the relative positions of the Earth, Moon, and Sun. The Moon orbits the Earth once every 29.5 days, and as it does so, we see different portions of the illuminated side of the Moon. These different portions of the Moon are called phases. There are eight primary phases of the Moon: New Moon, Waxing Crescent, First Quarter, Waxing Gibbous, Full Moon, Waning Gibbous, Third Quarter, and Waning Crescent.
An eclipse occurs when one celestial object moves into the shadow of another. There are two types of eclipses: solar and lunar. A solar eclipse occurs when the Moon passes between the Earth and the Sun, blocking the Sun's light and casting a shadow on the Earth. A lunar eclipse occurs when the Earth passes between the Sun and the Moon, casting a shadow on the Moon.
To explain these phenomena, teachers can use different methods such as diagrams, animations or models. For example, teachers can use a lamp to represent the Sun, a small ball to represent the Moon and a larger ball to represent the Earth. By moving the Moon around the Earth, the phases of the Moon can be demonstrated. To show eclipses, the Moon can be moved between the Earth and the Sun, or the Earth can be moved between the Sun and the Moon.
Using these methods can be an effective way of demonstrating the phases and eclipses to students. Teachers can also use animations and videos to help students visualize these events. It is important to note that these models and demonstrations are not perfect representations of the actual events, as they simplify the complex motions and distances involved in the interactions between celestial bodies.
Name of person taught: John
John said: "I learned a lot from the model that my teacher showed me. It was very helpful to see how the phases of the Moon and eclipses occur. The demonstration with the lamp and the balls really helped me understand the concepts. I also appreciated the videos that my teacher showed me, as they helped me see the events from different perspectives."
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Include a picture, video, or diagram of your model of lunar phases or eclipses.
Provide a description of how you made your model and how it demonstrates eclipses or lunar phases.
Include a one-paragraph reflection on the success of your model in explaining your event.
Include the name of the person you taught about your event and that person's description of what they learned from your model.
Explanation:
wawa wawa
How does a pendulum model an energy conversion system?
NO LINKS!
Answer:As a pendulum swings, its potential energy converts to kinetic and back to potential. ... A swinging pendulum.
Explanation:During the course of a swing from left to right, potential energy is converted into kinetic energy and back.
i took my football with 5.4 liters of air at 1.9 atm, and went deep sea diving with it. at 40 meters, the intense water pressure crushed my ball, and now there are only 2.16 liters in the ball. what is the pressure at my new depth
When went deep sea diving with it. at 40 meters. The pressure at new depth is 4.75 atm.
PRESSURE - It is the force applied perpendicularly to an object's surface divided by the surface area that it is applied to.
The new pressure that crushed ball is calculated as:
we use Boyle's Law;
P₁V₁ = P₂V₂
where P₁,P₂,V₁,V₂ are the pressure and volume for respective values.
P₂ = P₁V₁/V₂
P₁ = 1.9 atm
V₁ = 5.4 liters
V₂ = 2.16 liters
P₂ = ?
P₂ = P₁V₁/V₂
P₂ = (1.9 atm x 5.4 liters) / 2.16 liters
P₂ = 10.26 / 2.16
P₂ = 4.75 atm
When went deep sea diving with it. at 40 meters. The pressure at new depth is 4.75 atm.
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Most of the galaxies in the universe are observed to be moving away from Earth. Suppose a particular galaxy emits orange light with a frequency of 5.000 x 10 Hz. Part A If the galaxy is receding from Earth with a speed of 4500 km/s, what is the frequency of the light when it reaches Earth? Express your answer to four significant figures and include appropriate units.
The frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.
Explanation:-
Given:
Emitted frequency of light, f = 5.000 x 10^14 Hz,
Speed of the galaxy receding from Earth, v_src = 4500 km/s.
We need to convert the speed of the galaxy from km/s to m/s:
v_src = 4500 km/s * (1000 m/km)
v_src = 4.5 x 10^6 m/s
Plugging the given values into the Doppler effect formula:
f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s + 0 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)
Simplifying the expression:
f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)
f' ≈ 4.988 x 10^14 Hz
Therefore, the frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.
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A source of strong electric and magnetic fields will produce light with higher
a. amplitude
b. frequency
c. wavelength
d. wave speed
e. period
How much energy was released if rocket hydrogen fuel was burnt ?
Answer:
In layman's terms, burning hydrogen results in water: H2 + 1 2 O2 −→ H2O + 286, 000 joules. This combustion reaction also releases 286,000 joules of energy per mole of hydrogen gas burned.
Explanation:
.Two wooden blocks A and B have respective masses of 3.0 kg and 4.0 kg and are connected with an
inextensible cord. If the blocks are placed on a horizontal frictionless surface and a force of 8.0 N is
applied to A, find the tension in the connecting cord.
The tension in the connecting cord is 4.72 N.
What is tension?Tension is defined in physics as the pulling force transmitted axially by a string, rope, chain, or similar object, or by each end of a rod, truss member, or similar three-dimensional object; tension can also be defined as the action-reaction pair of forces acting at each end of said elements.
Given that:
Mass of block A (mₐ) = 3.0Kg
Mass of block B (mb) = 4.0 kg
Force (F)= 8.0N
Assume a = acceleration of the blocks.
mₐ(a) + mb(a) = 8
3a + 4a = 8
7a = 8
a = 8/7
a = 1.142 m/s²
Suppose T to be the tension in the string.
If we take a look at the forces acting on the first block, then:
F - T = (a)
T = F - (a)
T = 8- 3(1.142)
T = 8-3.428
T =4.72 N
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If a line has a slope of 2 and a
rise of 12 what was the run
A grey hound can run about 40/mph is it velocity,acceleration, or speed
Answer: Speed
Explanation:
Speed is the time it takes something to travel a certain distance. Accelaration is the rate at which an object's speed changes. Velocity is a vector of the object's speed and direction.
why is unit of force called derived unit
Answer:
because these units are derived from combinations of two or more of the seven base units
A spring oscillates with a period of
0.228 S. What is its frequency?
(Unit = Hz)
Answer:4.39
Explanation:For acellus students the answer is 4.39
Hey. :)
Which combination of resistors has the smallest equivalent resistance?
Concepts:
For resistors in series we know the following,
\(1. \ I_{tot.}=I_1=I_2=I_3=...\\2. V_{tot.}=V_1+V_2+V_3+... \\3. R_{eq.}=R_1+R_2+R_3+...\)
For parallel resistors we know the following,
\(1. \ V_{tot.}=V_1=V_2=V_3=...\\2. \ I_{tot.}=I_1+I_+I_3+...\\3. \frac{1}{R_{eq.}}=\frac{1}{R_1} + \frac{1}{R_2} +\frac{1}{R_3}+...\)
What is a resistor?
Resistors are used in electrical circuits. Resistors take energy and convert it into another form such as thermal energy which in turn can limit the amount of current through a wire.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#1:
We are given a circuit with series resistors.
Using the following equation to find an equivalent resistor.
\(\Rightarrow R_{eq.}=R_1+R_2+R_3+...\)
\(\Longrightarrow R_{eq.}=2+2 \Longrightarrow \boxed{R_{eq.}=4 \Omega}\)
#2:
We are given a circuit with parallel resistors.
Using the following equation to find an equivalent resistor.
\(\Rightarrow \ \frac{1} {R_{eq.}}=\frac{1}{R_1} + \frac{1}{R_2} +\frac{1}{R_3}+...\)
\(\Longrightarrow \ \frac{1} {R_{eq.}}=\frac{1}{2} + \frac{1}{2} \Longrightarrow \ \frac{1} {R_{eq.}}=1 \Longrightarrow (\ \frac{1} {R_{eq.}})^{-1}=(1)^{-1} \Longrightarrow \boxed {R_{eq.}=1 \ \Omega}\)
#3:
We are given a circuit with parallel resistors.
Using the following equation to find an equivalent resistor.
\(\Rightarrow \ \frac{1} {R_{eq.}}=\frac{1}{R_1} + \frac{1}{R_2} +\frac{1}{R_3}+...\)
\(\Longrightarrow \ \frac{1} {R_{eq.}}=\frac{1}{1} + \frac{1}{1} \Longrightarrow \ \frac{1} {R_{eq.}}=2 \Longrightarrow (\ \frac{1} {R_{eq.}})^{-1}=(2)^{-1} \Longrightarrow \boxed {R_{eq.}=\frac{1}{2} \ \Omega}\)
#4:
We are given a circuit with series resistors.
Using the following equation to find an equivalent resistor.
\(\Rightarrow R_{eq.}=R_1+R_2+R_3+...\)
\(\Longrightarrow R_{eq.}=1+1 \Longrightarrow \boxed{R_{eq.}=2\ \Omega}\)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Thus, the combination with smallest equivalent resistance is option #3.
Problem Three. In the circuit shown, the battery EMF is 10.0 V, the inductance L is 12.0mH, and the resistance R is 2.00Ω 11. If the switch is connected to point a, find the time (in ms) it takes for the current to reach 80.0% of its maximum value? (A) 3.21 (B) 4.22 (C) 2.56 (D) 8.67 (E) 9.66 12. After the inductor is fully charged, the switch is connected to point b. Find the current (in amps) after two time constants have passed. (A) 0.321 (B) 0.235 (C) 0.586 (D) 0.972 (E) 0.677
For Problem Three:
11. The time constant for this circuit is given by τ = L/R = 12.0mH / 2.00Ω = 6.00ms. To find the time it takes for the current to reach 80% of its maximum value, we can use the equation I = Imax * (1 - e^(-t/τ)), where Imax = EMF/R is the maximum current that the circuit will reach. Solving for t, we get t = -τ * ln(1 - 0.80 * R/EMF) = -6.00ms * ln(1 - 0.80 * 2.00Ω/10.0V) ≈ 3.21ms. Therefore, the answer is (A) 3.21ms.
12. After the switch is connected to point b, the circuit behaves like a simple RL circuit. The current in an RL circuit at any time t is given by I = Imax * e^(-t/τ), where Imax = EMF/R is the maximum current that the circuit will reach and τ = L/R is the time constant. After two time constants have passed (i.e. t = 2τ), the current in the circuit will have decayed to I = Imax * e^(-2) ≈ 0.135 * Imax. Therefore, we need to find Imax first: Imax = EMF/R = 10.0V/2.00Ω = 5.00A. Then, the current after two time constants have passed is I = 0.135 * Imax = 0.135 * 5.00A ≈ 0.677A. Therefore, the answer is (E) 0.677A.
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An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the floor of the elevator on a(n) 62 kg passenger? answer in units of n.
Answer:
Explanation:
Fr= Fn-P
ma=Fn-mg
Fn= m(a+g)
Fn=62(1.2+9.8)
Fn= 682N
A bowling ball is dropped off of the side of a building. Ignore the effects of air resistance. As the ball continues to fall freely, the kinetic energy of the ball.
The ball continues to fall, its kinetic energy will increase.
What is kinetic energy?Kinetic energy is the energy an object possesses due to its motion. It is the energy associated with an object’s speed and mass, and is the energy that an object has because of its movement. Kinetic energy can be converted into other forms of energy, such as heat, light, or sound. It can also be used to do work, such as moving objects or powering machines. Kinetic energy is a form of mechanical energy, which is energy that is associated with the motion or position of an object. Kinetic energy is related to the work done on an object, and it increases as the object’s speed increases. Kinetic energy can be calculated using the formula KE = ½mv2, where m is the mass of the object and v is the velocity of the object.
The kinetic energy of the ball will increase as it falls, because it is gaining speed due to gravity.
As it falls, it accelerates at a rate of 9.8 m/s^2, and its kinetic energy is equal to its mass multiplied by the square of its velocity.
Therefore, as the ball continues to fall, its kinetic energy will increase.
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A bus travelling at 80km/h accelerates for 12 s to a speed of 100km/h. What was the acceleration
Answer:
0.463 m/s^2
Explanation:
I calculated the answer using my
A man who has type B blood (genotype: BB) is married to a woman with type O blood. What blood type will their children have? blood typing
The Tacoma narrows bridge collapsed due to?
A. Refraction
B. Reflection
C. Diffraction
D. Resonance
Answer:
i think its resonance but if im wrong its my fault
Explanation:
Which of the following statements DOES NOT explicitly describe a transfer of energy,
A. A ball dropped from a height hits the ground with a high speed.
B. The collisions produced in a nuclear reaction heat up the surroundings.
C. A plane increases its air speed from 150 mi/hr to 200 mi/hr.
D.The electricity from the power socket causes the fan to turn
Answer:
Option A
Explanation:
A. A ball is dropped from a height and hits the ground with a high speed. As this is a ball, it has elastic energy, so upon impact on the ground the kinetic energy can 1. go into making sound upon impact, or 2. go into making the ball bounce upward again. There may by more possible energy transfers, but this is what should occur in like conditions. Now it didn't mention that the ball transfers energy as such, only that the ball hits the ground at high speed. Thus, this statement does not explicitly describe a transfer of energy.
_______________________________________________________
Just to confirm that this is the correct answer, take a look at the other options. Option B states that the energy from the collision is transferred to heat, not in those exact words but still is given. Option C states that the plane increases speed, most likely transferring energy to the atmosphere, in the form sound. In option d the electricity causes the fan to turn, an explicit statement of the transfer of energy.
Hope that helps!
A person holds a 25 kg (250 newton) bag of cement over his head and moves it a distance of 10 m, taking 2 minutes, while another person carries it on a wheelbarrow that same distance, taking 1 minute.Who does more work ? What is the power of each person?
Explanation:
Assuming the 10 m distance is the vertical displacement, the work done by both people is the same.
Work = force × distance
W = (250 N) (10 m)
W = 2500 J
The power of the first person is:
Power = work / time
P = 2500 J / 120 s
P = 20.83 W
The power of the second person is:
P = 2500 J / 60 s
P = 41.67 W
Find the surface area of the solid shape below ( please help !!!!!!)))))))
The change of any element of the project, must not essentially be passed through a change control process? Select one: True False
The change of any element of the project, must not essentially be passed through a change control process.
False
Any modifications to a project component must go through the change control process in order to ensure that the change request is properly evaluated and either authorized, postponed, or denied. Therefore, it is crucial to follow the change control procedure when submitting a change request since it enables the business to make decisions that are effective.
The aforementioned claim cannot be true since the change control process allows for the correct review and approval of modifications before they are implemented in a project. This makes it easier and more accurate for the organization to achieve its objectives.
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A locomotive's "adhesion" is the locomotive's pulling force as a multiple of its weight. This is an important performance measure of a locomotive. A diesel locomotive model has adhesion which varies in actual use according to a Normal distribution with mean 0.37 and standard deviation 0.04.
A) The percent of adhesions measured in use that are higher than 0.40 is closest to
22.66%
The percentage of adhesions measured in use that are higher than 0.40 is approximately 22.66%.
For finding the percentage of adhesions that are higher than 0.40, need to calculate the area under the normal distribution curve to the right of 0.40. First, need to standardize the value of 0.40 using the Z-score formula:
Z = (X - μ) / σ
Where X is the value (0.40), μ is the mean (0.37), and σ is the standard deviation (0.04).
Z = (0.40 - 0.37) / 0.04 = 0.03 / 0.04 = 0.75
Next, look up the Z-score of 0.75 in the standard normal distribution table for finding the corresponding cumulative probability. The Z-table tells that the cumulative probability to the left of 0.75 is approximately 0.7734.
Since want the percentage to the right of 0.40, subtract the cumulative probability from 1:
1 - 0.7734 = 0.2266
Therefore, the percentage of adhesions measured in use that are higher than 0.40 is approximately 22.66%.
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