The combustion of octane, C8H18, proceeds according to the reaction shown.

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)

If 354 mol of octane combusts, what volume of carbon dioxide is produced at 15.0 ∘C
and 0.995 atm?

Answer:

4.35 mL

Explanation:

The water line falls halfway inbetween the 4.4 and 4.3 mark.

The number halfway between 4.3 and 4.4 is 4.35.

Therefore, the volume of the liquid in the graduated cylinder is 4.35 mL.

Answer:

B

Explanation:

B is the only answer choice that provides a rate

(like 3ºC/ hr meaning 3ºC per hour)

all the other answer choices don't have a /hr

so best answer choice is B

The properties of hard and soft materials refer to their physical characteristics and behaviors.

These properties are related to factors such as the arrangement of molecules, bonding strength, and response to external forces. Here, we will discuss the general properties of hard and soft materials.

Hard materials:

Rigidity: Hard materials exhibit high stiffness and resist deformation under applied forces. They tend to maintain their shape and structure.

High strength: Hard materials have strong intermolecular or intramolecular forces, allowing them to withstand high stress and pressure without breaking or deforming.

High melting and boiling points: Hard materials often have high melting and boiling points due to the strong bonds between their atoms or molecules.

Brittle: Hard materials are often brittle, meaning they have low tolerance to tensile or bending forces and are prone to fracturing or shattering instead of deforming.

Low compressibility: Hard materials have low compressibility, meaning they do not easily compress or change volume under pressure.

Soft materials:

Flexibility: Soft materials are pliable and easily deformable under applied forces. They can be bent, stretched, or compressed without breaking.

Low strength: Soft materials have weak intermolecular or intramolecular forces, making them more susceptible to deformation or damage under stress.

Low melting and boiling points: Soft materials generally have lower melting and boiling points compared to hard materials.

Ductile: Soft materials are often ductile, meaning they can be drawn into thin wires or stretched into thin sheets without fracturing.

High compressibility: Soft materials can be easily compressed or change volume under pressure due to their loosely packed molecular structures.

It's important to note that these properties are generalizations, and there can be variations within each category. Some materials may exhibit properties that fall between hard and soft, or they may have unique combinations of properties. Materials' properties play a crucial role in various applications, as they determine their suitability for specific uses such as construction, manufacturing, and design.

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Answer:

Argon

Explanation:

It has more electron than chlorine

Answer:

Im bad at math sorry

Explanation:

Answer:

1. went on the first manned launch during the Apollo mission

2. responsible for all spacecraft systems

3. 4500 hour

4. published All-American Boys

5. Joined back in space organization as a consultant to inspire next generation for mars

It can harm birds and species nearby.

Wind mills, also known as wind turbines, are devices that generate electricity from wind energy. While wind energy is a renewable and clean source of energy, the installation and operation of wind turbines can have both positive and negative consequences on the environment and society.

The consequences of wind mills depend on many factors, such as their location, size, design, and the management practices used to mitigate their impacts. Careful planning and management can help to maximize the positive consequences of wind mills while minimizing their negative impacts.

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Explanation:

To calculate the heat gained by nickel, we can use the formula:

q = m * c * ΔT

where q is the heat gained, m is the mass of the nickel, c is the specific heat of nickel, and ΔT is the change in temperature.

Given:

- Mass of nickel, m = 31.4 g

- Specific heat of nickel, c = 0.443 J/g · °C

- Change in temperature, ΔT = 64.2 °C - 27.2 °C = 37.0 °C

Substituting the values into the formula, we get:

q = (31.4 g) * (0.443 J/g · °C) * (37.0 °C)

Simplifying the calculation, we get:

q = 584 J

Therefore, the heat gained by nickel when 31.4 g of nickel is warmed from 27.2 °C to 64.2 °C is 584 J.

Answer:

answer is d Combining

Explanation:

I did the test and got it correct

As a chemical change takes place when binders are added to a paint mixture combining part of the manufacturing process occurs.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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The heat of combustion per gram of quinone is -25.43 KJ/g.

Given,

mass of sample = 2.300g

total heat capacity = 7.854 kJ/∘C

Temperature change = 32.09 - 24.64 = 7.45

we have to find out heat of combustion per gram of quinone.

- Q(rxn) = Q(cal) = C(cal)ΔT

Q(rxn) = -(7.854kJ/⁰C)(32.09 - 24.64)

= -58.5 KJ

Now, we will calculate heat of combustion per gram.

Q(rxn) = -58.5/2.3g = -25.43 KJ/g

negative sign denote exothermic reaction.

Thus, heat of combustion per gram of quinone is -25.43 KJ/g.

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Answer:

For many solids dissolved in liquid water, the solubility increases with temperature. The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.

Answer:

i do k12 too!

Explanation:

lol

When the concentration of the HCl is varied, the color of the solution is changed as the equilibrium position moves to the left or right.

The term equilibrium in a chemical reaction connotes that the forward and the revers reactions proceed at the same rate. Let us note that Co(H2O)6^2+ is pink in color while  CoCl4^2– is blue in color.

As such, when the concentration of the HCl is varied, the color of the solution is changed as the equilibrium position moves to the left or right.

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The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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HNO2 nitrous acid whose Ka value is 4.5×10−4 is strongest among all the given acids, as its dissociation constant (Ka) is highest of all.

The difference between strong and weak acids is determined by the acid dissociation constant (Ka). As Ka rises, the acid dissociates more. Therefore, strong acids must dissociate more in water. On the other hand, a weak acid has a lower propensity to ionise and release a hydrogen ion, resulting in a less acidic solution.

The equilibrium constant of an acid's dissociation reaction is known as the acid dissociation constant, or Ka. The strength of an acid in a solution is numerically represented by this equilibrium constant. Ka is frequently expressed in mol/L units. Strong acids have Ka values that are extraordinarily high. By examining the equilibrium constant for the acid's dissociation, the Ka value can be determined. The more the acid dissociates, the higher the Ka.

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Answer:

a

Explanation:

sugar is composed of different elements combined in a manner form

Answer:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction.

For example, when wood burns, the mass of the soot, ashes, and gases equals the original mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant.

Another example, solar panels don't create solar energy. They harness energy from the sun and transform it into another type of energy (electricity).

Answer:

I don't know what the hell is going on with the this.

Answer:

a. Molecular equation: AgNO₃(aq) + NaI(aq) ----> NaNO₃(aq) + AgI(s)

Net ionic equation: Ag⁺(aq) + I⁻ ---> AgI(s)

b. Molecular equation: Ba(NO₃)₂(aq) + K₂SO₄(aq) ----> 2KNO₃(aq) + BaSO₄(s)

Net ionic equation: Ba²⁺(aq) + SO₄²⁻(aq) ---> BaSO₄(s)

c. Mg(NO₃)₂ + K₂SO₄  ------> No reaction

d. CaCl₂ + AI(NO₃)₃ ----> No reaction

Note: The question is incomplete. A complete similar question is given below:

Write the molecular equation and the net ionic equation for each of the following aqueous reactions. If a reaction is not carried out, write NR after the arrow.

a. AgNO₃ + NaI⁻

b. Ba(NO₃)₂ + K₂SO₄

c. Mg(NO₃)₂ + K₂SO₄

d. CaCl₂ + AI(NO₃)₃

Explanation:

a. A double displacement reaction occur between aqueous solutions of silver nitrate and sodium iodide to give a precipitate of silver iodide.

Molecular equation: AgNO₃(aq) + NaI(aq) ----> NaNO₃(aq) + AgI(s)

Net ionic equation: Ag⁺(aq) + I⁻ ---> AgI(s)

b. A double displacement reaction occurs between aqueous solutions of barium nitrate and potassium sulfate to produce a precipitate of barium sulfate

Molecular equation: Ba(NO₃)₂(aq) + K₂SO₄(aq) -----> 2KNO₃(aq) + BaSO₄(s)

Net ionic equation: Ba²⁺(aq) + SO₄²⁻(aq) ---> BaSO₄(s)

c. Since no precipitate is formed when aqueous solutions of magnesium nitrate and potassium sulfate are mixed together, no reaction occurs

Mg(NO₃)₂ + K₂SO₄  ------> No reaction

d. Since no precipitate is formed when aqueous solutions of calcium chloride and aluminum nitrate are mixed together, no reaction occurs

CaCl₂ + AI(NO₃)₃ ----> No reaction

Explanation:

In fact, a good way to remember radiation is that it is how you can feel heat without touching it. Heat passes through the empty space until it reaches your hand. That's radiation! A fire is another example of radiation.

The given answer statement  "there is no aluminum left" and " limiting reactants is aluminum" are correct.

In the analysis of Trial 2, it was found that there was no aluminum left after the reaction had taken place. This indicates that all of the aluminum had reacted with the copper (II) chloride and that it was the limiting reactant in the reaction.

To confirm this, the mass of each reactant was converted to moles using their respective molar masses. It was found that the aluminum had a smaller number of moles than the copper (II) chloride, indicating that it would be used up first and thus be the limiting reactant.

Therefore, the limiting reactant in Trial 2 was aluminum.

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Answer:

part 1

3) 5.47 molecules

4) 11.15 moles

5) 2.95 × 10^23 molecules

6) 7670.9g

part2

1) 216000g

2) 5.71 molecules

3) 0.18 moles

4) 737.40g

5) 2.89×10^23 molecules

Explanation:

part 1

3) number of moles = (6.02 × 10^23)/11.0

=5.47molecules.

4) moles= (6.02 × 10^23)/(5.40×10^23)

= 11.15 moles

5) molar mass of NH3= 14+(3×1)= 14+3=17

number of molecules= (6.02 × 10^23) × 17/35

= (6.02 × 10^23)× 0.49 =2.95 × 10^23 molecules

6) molar mass of N2I6= (2×14) + (6×127)

= 28+762= 790g/mol

mass= 790 × (6.02 × 10^23)/(6.20×10^22)

=790× 9.71= 7670.9g

part 2

1) molar mass of CuBr= 64+80= 144g/mol

mass= 1500 × 144= 216000g

2) molecules = (6.02 × 10^23)/1.055

= 5.71 molecules

3) moles = (6.02 × 10^23)/(3.35×10^24)

= 0.18 moles

4) molar mass of SiO2= 28+ (2×16)= 28+32

=60gmol

mass= 60 × (6.02 × 10^23)/(4.90×10^22)

= 60× 12.29= 737.40g

5) molar mass of CH4= 12+(4×1)= 12+4=16g/mol

number of molecules= (6.02 × 10^23) × 16/33.6

= (6.02 × 10^23)× 0.48

= 2.89×10^23 molecules

Answer:

1. Oxygen Nitrogen

2. silicon Nitrogen

3. Carbon dioxide

Not sure about the 2nd one

Explanation:

prove me wrong

Answer:

1.6 L CH3OH

Explanation:

3.20 L H2 x (1 mol H2/22.4 L H2) x (1 mol CH3OH/2 mol H2) x (22.4 L CH3OH/1 mol CH3OH) = 1.60 LCH3OH

1.602 liters of CH₃OH gas are formed when 3.20 L of H₂ gas are completely reacted at STP according to the following chemical reaction:

CO(g) + 2 H₂(g) → CH₃OH(g)

Remember 1 mol of an ideal gas has a volume of 22.4 L at STP

To find the volume of CH₃OH gas formed when 3.20 L of H₂ gas is completely reacted, we need to use stoichiometry and the given balanced chemical equation.

The balanced equation is:

CO(g) + 2 H₂(g) → CH₃OH(g)

From the balanced equation, we can see that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.

Step 1: Convert the given volume of H₂ gas to moles at STP.

Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.

Number of moles of H₂ gas = Volume of H2 gas at STP / Volume of 1 mol of H₂ gas at STP

Number of moles of H₂ gas = 3.20 L / 22.4 L/mol

Number of moles of H₂ gas = 0.14286 moles (rounded to 5 decimal places)

Step 2: Use stoichiometry to find the moles of CH₃OH formed.

From the balanced equation, we know that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.

Since the ratio of H₂ to CH₃OH is 2:1, the number of moles of CH₃OH formed will be half of the moles of H₂ used in the reaction.

Number of moles of CH₃OH = (1/2) * Number of moles of H₂

Number of moles of CH₃OH = (1/2) * 0.14286

Number of moles of CH₃OH = 0.07143 moles (rounded to 5 decimal places)

Step 3: Convert the moles of CH₃OH to volume at STP.

Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.

Volume of CH₃OH gas at STP = Number of moles of CH₃OH * Volume of 1 mol of CH₃OH gas at STP

Volume of CH₃OH gas at STP = 0.07143 moles * 22.4 L/mol

Volume of CH₃OH gas at STP = 1.602 L (rounded to 3 decimal places)

Therefore, approximately 1.602 liters of CH₃OH gas are formed when 3.20 liters of H₂ gas are completely reacted at STP.

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Answer:

the relation between Kp and Kc is

\( \colorbox{red}Kp=Kc{[RT]}^{∆n}\)

where

∆n=no.of moles of gaseous product - no.of moles of gaseous reactant in the balanced chemical equation.

R=universal gas constant

T=temperature.

Sinve CH3NH2 is weak base and its salt is CH3NH3Cl, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

A buffer is a solution which resists changes to its pH when a small quantity of strong acid or base is added to it..

A buffer is made from a weak acid and its salt or a weak base and its salt.

From the given options, CH3NH2 is weak base and its salt is CH3NH3Cl.

Therefore, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

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Explanation:

Depositional landforms are the visible evidence of processes that have deposited sediments or rocks after they were transported by flowing ice or water, wind or gravity. Examples include beaches, deltas, glacial moraines, sand dunes and salt domes.

hope it helps!

Sulphur  is a main-group nonmetal element in period number 3 of the periodic table.

Elements can be classified as metals, non-metals, or metalloids. Metals are excellent conductors of heat and electricity, and are malleable (can be swaged into sheets) and ductile (can be stretched into wires). Most metals are solid at room temperature and have a characteristic silvery luster (except mercury, which is liquid). Nonmetals are (usually) poor thermal and electrical conductors and are not malleable or ductile. Many of the elemental nonmetals are gases at room temperature, others are liquids, and others are solids. Semimetals are intermediate in their properties. Their physical properties are similar to non-metals, but some can be made conductive under certain circumstances. These semiconductors are very important in computers and other electronic devices.

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