The cost to rent a moving truck is a flat fee of $25 plus $0.60 per mile. The equatic
c, in dollars for the number of miles, m, traveled in the truck.
Identify the independent and dependent variables.
The
is the independent variable.
The
is the dependent variable.
$25 flat fee
cost
miles traveled?

Answer:

x = 10.8

Step-by-step explanation:

Cos∅ = adj/hyp

Cos26 = x/12

Multiply both sides by 12

12 * cos26 = x

Use calculator

10.785528555590004 = x

Round

x = 10.8

The probability of drawing a face card or a 5 is 4/13. Option a is correct.

A card is drawn at random from a well-shuffled deck of 52 cards. To find the probability of drawing a face card or a 5, we need to count the number of cards in a deck that are face cards or 5s and divide that by the total number of cards in a deck.

There are 16 such cards (12 face cards and 4 5s) in a deck and 52 total cards. So the probability of drawing a face card or a 5 is:

16/52 which can be simplified to 4/13.

The probability is 4/13. Option a is correct.

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Answer:

96π mm^3

Step-by-step explanation:

πr^2*h = formula

π4^2*6 = 16π(6) = 96π mm^3

Answer:

\(\Longrightarrow: \boxed{\sf{96\pi }}\)

Step-by-step explanation:

You must use the volume of this cylinder formula to solve the volume of this cylinder.

Volume of this cylinder formula:

\(\Longrightarrow: \sf{\pi r^2*h}\)

\(\Longrightarrow\sf{\pi 4^2*6}\)

Use the order of operations.

PEMDAS stands for:

First, solve exponents.

4²=4*4=16

16*6

Multiply.

16*6=96

\(\Longrightarrow: \boxed{\sf{96\pi}}\)

I hope this helps! Let me know if you have any questions.

Answer: 8n^2

Step-by-step explanation:

I did test and got 100

Answer:

the longest segment is between 14 and 9

Step-by-step explanation:

this is the best answer in my eyes

The length of the diagonal of the rectangular prism will be 19.95 centimeters.

A rectangle's longitudinal divides it into two equivalent right triangles. A rectangle's diagonal elements are all the same length. A rectangle is a rectangle whose diagonal elements bisect one another, cross at right angles, and are identical.

The length of the diagonal of the rectangular prism is given as,

D² = L² + W² + H²

The dimensions of the rectangular prism will be 14 cm long, 11 cm wide, and 9 cm tall.

The diagonal length is calculated as,

D² = 14² + 11² + 9²

D² = 196 + 121 + 81

D² = 398

D = 19.95 cm

The length of the diagonal of the rectangular prism will be 19.95 centimeters.

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Answer:

7/8

Step-by-step explanation:

because the are 8 pieces in the entire circle and Tara eats 7 out of 8 of them

Answer:

6

Step-by-step explanation:

you combine the a2 with 5a2 as they are the only ones with a squared, combine and you get 6a2 + 6a + 7

Answer:

6 and 7

Step-by-step explanation:

Performing a Chi-Square test is a statistical tool used to determine if there is a significant difference between observed and expected data. The test helps to analyze categorical data by comparing observed frequencies to the expected frequencies. The p-value in a Chi-Square test refers to the probability of obtaining the observed results by chance alone.

If a p-value lower than 0.01 is obtained in a Chi-Square test, it means that the results are statistically significant. In other words, there is strong evidence to reject the null hypothesis, which states that there is no significant difference between the observed and expected data. This means that the observed data is not due to chance alone, but rather to some other factor or factors.

The mean, or average, is not directly related to the Chi-Square test or the p-value. The Chi-Square test is specifically used to determine the significance of the observed data. However, the mean can be used as a measure of central tendency for continuous data, but it is not applicable to categorical data.

In conclusion, obtaining a p-value lower than 0.01 in a Chi-Square test means that there is strong evidence to reject the null hypothesis, and that the observed data is statistically significant.

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Answer:

11 cups

Step-by-step explanation:

11x5= 55

55+45

Answer:

9+10=90

Step-by-step explanation:

10x9=90

I hope it helps:)

Answer:

9+10=19

Step-by-step explanation:

9 added to 10 will be 19

example if you have 9 pens ,and your friend gives you 10 pens . how many pens do you have? you only going to do, is to count all the pens and the result will be 19 pens

The polygons are similar but not necessarily drawn to scale the value of x is 13.

We can set up a proportion between the corresponding sides of the two similar polygons:

Polygons are two-dimensional geometric shapes that are made up of straight lines and closed loops.

Polygons are characterized by the number of sides, angles, and vertices they have. The sides of a polygon are the straight lines that connect the vertices, while the vertices are the points where the sides meet. The angles of a polygon are formed by the intersection of two adjacent sides.

(x - 3) / 2.5 = 8 / 2

=> 16 / 4

Simplifying each side of the equation:

(x - 3) / 2.5 = 4

Multiplying both sides by 2.5 to isolate x:

x - 3 = 10

Adding 3 to both sides:

x = 13

Therefore, the value of x is 13.

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Note: The full question is

The polygons are similar but not necessarily drawn to scale, find the value of x.

Bigger polygon has x - 3, 8, and 16

Smaller has 2.5, 2, 4

Answer:  see below

Step-by-step explanation:

3 Red balls and 4 Blue balls makes a total of 9 balls

 1st Draw                        2nd Draw                Outcome     Probability    

 Red: P(R) =  3/7            Red: P(R₂/R₁) =1/3      Red, Red       (3/7) x (1/3) = 1/7

 Red: P(R) =  3/7            Blue: P(B₂/R₁) =2/3     Red, Blue     (3/7) x (2/3) = 2/7

 Blue: P(B) =  4/7           Red: P(R₂/B₁) =1/2      Blue, Red      (4/7) x (1/2) = 2/7

 Blue: P(B) =  3/7           Blue: P(B₂/B₁) =1/3     Blue, Blue     (4/7) x (1/2) = 2/7

                                                                                           Check: Total = 7/7  = 1

Notes:

P(R₂/R₁) means the probability that the 2nd ball is red given that the 1st ball was red. Since you started with 3 red balls out of 7 total balls but previously pulled one red ball out, you now have 2 remaining red balls out of 6 remaining total balls.

2 red / 6 total = 1/3    

P(B₂/R₁) means the probability that the 2nd ball is blue given that the 1st ball was red. Since you started with 4 blue balls out of 7 total balls but previously pulled one red ball out, you still have 4 blue balls but only 6 total remaining balls.

4 blue / 6 total = 2/3    

P(R₂/B₁) means the probability that the 2nd ball is red given that the 1st ball was blue. Since you started with 3 red balls out of 7 total balls but previously pulled one blue ball out, you still have 3 red balls but only 6 total remaining balls.

3 blue / 6 total = 1/2    

P(B₂/B₁) means the probability that the 2nd ball is blue given that the 1st ball was blue. Since you started with 4 red balls out of 7 total balls but previously pulled one blue ball out, now have 3 remaining red balls out of 6 total remaining balls.

3 blue / 6 total = 1/2    

See Tree Diagram below                                

Answer:

Step-by-step explanation:

You had the first part of the first question correct. The answer is 100:64

The sides of the squares

Area of e = 69% more than area of area of f

e^2: f^2 = ( 1 + 69/100 ) / 1

e^2 : f^2 = (1.69)/1            Take the square root of both sides

e:f  = 1.3:1

Answer:

Quadrant 4

Answer is D........

a) X'Y' + X'Y + XY simplifies to X' + Y.

b) A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the functions:

a) Complement is W' + X' + YZ.

b) Complement is (A' + B + C)(A'B' + C' + A'B).

a) To prove X'Y' + X'Y + XY = X' + Y, we can use Boolean algebra identities:

X'Y' + X'Y + XY

= Y'(X' + X) + XY(Distributive Law)

= Y' + XY(X + X' = 1)

= X' + Y(Commutative Law)

Therefore, X'Y' + X'Y + XY simplifies to X' + Y.

b) To prove A'BC' + ABC' + BC'D = BC', we can simplify the expression using Boolean algebra:

A'BC' + ABC' + BC'D

= BC'(A' + A) + BC'D   (Distributive Law)

= BC' + BC'D(A + A' = 1)

= BC'(BC' + BC'D = BC' + BC'(1) = BC')

Hence, A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the given functions:

a) The complement of WX(Y'Z + YZ') + W'X'(Y' + Z)(Y + Z') is W' + X' + YZ.

b) The complement of (A + B' + C')(A'B' + C)(A + B'C') is (A' + B + C)(A'B' + C' + A'B).

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Solution:

We know that:

Finding the radius of the cylindrical water tank:

\(\rightarrow Diameter = 2(Radius)\)

\(\rightarrow Radius = \frac{Diameter}{2} = \frac{12}{2} = 6 \ feet\)

Now, let's find the volume of the cylinder by substituting the radius.

Finding the volume of the cylinder:

\(\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = \pi r^{2} h\)

\(\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = (3.14)( 6^{2})( 17)\)

\(\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = (3.14)( 36)( 17)\)

\(\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = 1921.68 \ feet^{3}\)

Rounding to the nearest whole number:

\(\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = 1921.68 \ feet^{3}\)

\(\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = 1922 \ feet^{3} \ (Rounded \ to \ nearest \ whole \ number)\)  

Thus, the volume of the cylinder is 1922 feet³ (Rounded).

\(\\ \rm\rightarrowtail V=\pi r^2h\)

\(\\ \rm\rightarrowtail V=\pi (6)^2(17)\)

\(\\ \rm\rightarrowtail V=36(17)\pi \)

\(\\ \rm\rightarrowtail V=612\pi\)

\(\\ \rm\rightarrowtail V=1921.68ft^3\)

Answer:

0.22

Step-by-step explanation:

The total quantity demanded, q = q1 + q2, should be set such that the total cost is minimized and the price is maximized. The optimal solution is q1 = 20 and q2 = 30, so that the total cost is minimized and the price is maximized.

To maximize the company's profit, we must find the optimal quantity of q1 and q2 that minimizes the total cost and maximizes the price. We start by finding the total quantity demanded, q: q = q1 + q2. We can then use this equation to relate the price, p, and the total quantity, q, by substituting the equation for q into the equation for price: p = 50 - 0.04q. Next, we use the cost functions for each plant to find the total cost: C = C1 + C2. We can then use calculus to find the minimum total cost by taking the partial derivatives of C with respect to q1 and q2 and setting them equal to zero.Finally, we can use the equations for price and total cost together to find the optimal values for q1 and q2 that maximize the company's profit. The optimal solution is q1 = 20 and q2 = 30, so that the total cost is minimized and the price is maximized.

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Answer: 5 + 5w

Step-by-step explanation:

We can use the variable x to describe each additional hour, although the vairable can be substituted for any other vairable.

We know that the main cost for one hour is $5, and that each additional hour will cost $5.

Therefore, the equation to reflect this situation would be 5 + 5w, because the first 5 represents the first hour, and the 5w represents how much each hour costs. If you rent two extra hours, then the cost would end up being 15, because the equation would become: 5 + (5x2) = 15.

The equation is 5 + 5w. Hope this helps, and good luck!

Answer:

yes is correct 6/6 = 1 / 3*2=6 =1

Answer:

nonsense. what's the difference between 6/6 or 1 .

The solution to the differential equation dy/dx y^2 = 0, subject to the initial condition y(0) = 10 is y(x) = 10.

The solution to the differential equation dy/dx y^2 = 0, subject to the initial condition y(0) = 10 is:

y(x) = 10

To solve the given differential equation, we can first separate the variables by dividing both sides by y^2 to get:

1/y^2 dy/dx = 0

We can then integrate both sides with respect to x to obtain:

-1/y = C

where C is the constant of integration. Solving for y, we get:

y = -1/C

Since we have an initial condition of y(0) = 10, we can substitute this into the solution to solve for C:

10 = -1/C

C = -1/10

Substituting C back into the solution, we get:

y = -10

Therefore, the solution to the differential equation dy/dx y^2 = 0, subject to the initial condition y(0) = 10 is y(x) = 10.

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Let's begin by simplifying each of the terms in the expression on the left-hand side of the equation:

(x^m * x^n)^(m-n) = x^(m-n)*(m-n)

(x^p * x^(-n))^(n+p) = x^(n+p)*(p-n)

(x^p * x^(-m))^(p+m) = x^(p+m)*(p-m)

Now, let's substitute the given equation p^2 - n^2 = 1 into these expressions:

x^(m-n)*(p^2-n^2) = x^(m-n)

x^(n+p)*(p^2-n^2) = x^(n+p)

x^(p+m)*(p^2-n^2) = x^(p+m)

Simplifying each of these expressions using the given equation, we get:

x^(m-n) = x^(m-n)

x^(n+p) = x^(n+p)

x^(p+m) = x^(p+m)

Therefore, the left-hand side of the equation simplifies to:

x^(m-n) * x^(n+p) * x^(p+m) = x^(m-n + n+p + p+m) = x^(2m) = x^2^(m-n + n+p + p+m)

Thus, we have proved that:

(x^m * x^n)^(m-n) * (x^p * x^(-n))^(n+p) * (x^p * x^(-m))^(p+m) = x^2

which is the same as the given equation.

<EOG =90° AS INDICATED IN THE DIAGRAM

<EOF+<FOG=<EOG(THEY MAKE THE ANGLE)

\(27 + 3y = 90 \\ 3y = 90 - 27 \\ 3y = 63 \\ \frac{3y}{3} = \frac{63}{3} \\ y= 21\)

<AOB =180°( STRAIGHT LINE )

<AOE+EOF+<FOG+<GOB=<AOB(THWY MAKE THE ANGLE)

\(x + 27 + 3(21) + 8x + 18 = 180\)

\(x + 27 + 63 + 8x + 18 = 180 \\ x + 8x + 27 + 63 + 18 = 180 \\ 9x - + 108 = 180 \\ 9x = 180 - 108 \\ 9x =72 \\ \frac{9x}{9} = \frac{72}{8} \\ x = 9\)

ATTACHED IS THE SOLUTION

1) How many ways can 4 candy bars be chosen from a store that sells 30 candy bars?

In this case we can combine 30 types of candy bars in a set of 4 bars.

This can be calculated as a combination of 30 in 4 with no repetition:

Answer: 27,405 possible combinations (C).

2) How many ways can 13 students line up for lunch?

In this case we have a permutation of 13 in 13 with no repetition.

We can calculate this as:

Answer: 6,227,020,85)00 possible permutations (P).

3) How many ways can you make a 3-letter arrangements out of the letters in the word TRAPEZOID.

In the word we have 9 letters with no repetition, so we have to calculate a permutation (as order matters) of 9 letters in 3 places.

We can calculate this as:

Answer: 504 possible permutations (P).

4) How many ways can you choose 2 books from a shelf of 40 books.

In this case, the order does not matter, so it is a combination of 40 in 2.

This can be calculated as:

Answer: 780 possible combinations (C)

5) How many ways can 12 swimmers finish in first, second, and third place?

In this case, the order does matter, so we have a permutation of 12 in 3:

Answer: 1320 permutations (P)

6) How many ways can Mrs. Sullivan choose two students from 27 to help put away calculators at the end of class?

The order does not matter between the two students, so it is a combination of 27 in 2:

Answer: 351 combinations (C)

Answer:

Step-by-step explanation:

If the multiplication of two numbers has the zero at the end, one of them will have a factor of 2 and the other number will have the factor of 5.

Example: Multiplication of 25 and 8.

                Factors of 25 = 5 × 5 [5 is a factor of 25]

                Factors of 8 = 2 × 2 × 2 [2 is a factor of 8]

Multiplication of 8 × 25 = 200 [Zero at the end]

Two numbers are 459 and 885.

Factors of 459 = 3 × 3 × 3 × 17

Factors of 885 = 3 × 5 × 59

[Since, 2 is not a factor in both the numbers multiplication of the numbers will not have 0 at the end]

459 × 885 = 406215

Answer:

20° and  90°

Step-by-step explanation:

Let 2x = measure of 1st angle

then 9x =  measure of 2nd angle

The sum of the measures of the angles of a quad is 360

200 + 50 + 2x + 9x = 360

250 + 11x = 360

11x = 110

x = 10

2x = 20°

9x = 90°