the critical resolved shear stress for copper (cu) is 0.48 mpa (70 psi). determine the maximum possible yield strength for a single crystal of cu pulled in tension.

Explanation:

most big airports. my father has the same degree and works for southwest airlines

Answer:

a

Explanation:

Answer:

c

Explanation:

:)

The average labour cost incurred per month in manpower budget is 12.69 Rs.

Budgeting is the process of creating a plan to spend your money. This spending plan is called a budget. Creating a budget allows you to determine in advance whether you will have enough money to do the things you need to do or would like to do.

Average labour cost incurred per month in manpower budget = (100 x 2 + 200 x 25 + 250 x 2) / (100 + 200 + 250)
= (200 + 5000 + 500) / (450)
= 5711 / 450
= 12.69 Rs.
Therefore, the average labour cost incurred per month in manpower budget is 12.69 Rs.

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The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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Answer:

16.2 cents

Explanation:

Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.

Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.

For the first 100 kWh:

16 cent × 100 = 1600 cents = 16 dollars

Since 1 dollar = 100 cents

For the remaining energy:

260 - 100 = 160 kwh

10 cents × 160 = 1600 cents = 16 dollars

The total cost = 10 + 16 + 16 = 42 dollars

Note that the base monthly of 10 dollars is added.

The cost of 260 kWh of energy consumption in July is 42 dollars

To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.

That is, 42 / 260 = 0.1615 dollars

Convert it to cents by multiplying the result by 100.

0.1615 × 100 = 16.15 cents

Approximately 16.2 cents

The maximum inventory of the part is limited to 3 units to match the demand rate of 12 units per hour.

To determine the maximum inventory of a part, we need to consider the processing time, maintenance time, and the demand rate. The processing time per part is given as 4 minutes, and after producing 190 units, a 34-minute maintenance process is required. The demand for the part is 12 units per hour.

First, let's calculate the total time required to produce 190 units:

Total production time = (Processing time per part) * (Number of units produced)

Total production time = 4 minutes * 190 units

Total production time = 760 minutes

Next, let's calculate the total time available for production:

Total time available = (Total production time) + (Maintenance time)

Total time available = 760 minutes + 34 minutes

Total time available = 794 minutes

Now, let's calculate the maximum inventory:

Maximum inventory = (Total time available) / (Time required to produce one unit)

Maximum inventory = 794 minutes / (4 minutes per unit)

Maximum inventory = 198.5 units

Since we cannot have fractional units of inventory, the maximum inventory of the part is rounded down to the nearest whole number, which is 198 units. However, since the demand for the part is 12 units per hour, we need to consider the time it takes to produce one unit. With a processing time of 4 minutes per unit, it takes 12 minutes to produce 3 units. Therefore, the maximum inventory of the part is limited to 3 units to match the demand rate of 12 units per hour.

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Answer:

No

Explanation:

In the early Aviation history men have always dominated the world of aviation and women are notoriously under-represented, particularly in technical and leadership roles. Therefore, women was treated unequal.

Answer:

Here's the MATLAB code to create the table:

% Create a vector of power values from 100 W to 10000 W

P = [100:100:1000, 2000:1000:10000];

% Convert power values from watts to horsepower

HP = P ./ 745.7;

% Create a table to display the results

T = table(P', HP', 'VariableNames', {'Power_W', 'Power_HP'})

This will create a table T with two columns: Power_W for power values in watts and Power_HP for power values in horsepower. The table will show the conversion of power values from 100 W to 10000 W in increments of 100 W up to 1000 W and increments of 1000 W all the way up to 10000 W.

Explanation:

Phishing, spear phishing, whaling, vishing, dumpster diving, and piggybacking are all types of social engineering attacks that are designed to manipulate people into divulging confidential information or taking actions that benefit the attacker.

Phishing is a type of social engineering attack where the attacker sends fraudulent emails or messages that appear to be from a legitimate source, in order to trick the victim into giving away sensitive information or clicking on a malicious link.

Spear phishing is a more targeted form of phishing where the attacker researches the victim and sends customized messages that appear to be from a trusted source, making it more likely for the victim to fall for the scam.

Whaling is a type of spear phishing that specifically targets high-level executives or individuals with access to sensitive information. The attacker uses social engineering tactics to convince the victim to take a specific action, such as wire transfer of funds or revealing confidential information.

Vishing (voice phishing) is a social engineering attack that uses voice calls or voice messages to trick the victim into giving away sensitive information. The attacker may impersonate a trusted source, such as a bank or government agency, to gain the victim's trust.

Dumpster diving involves searching through a person's trash or recycling to find confidential information, such as account numbers or passwords.

Piggybacking is a physical social engineering attack where the attacker gains unauthorized access to a restricted area by following closely behind an authorized individual, taking advantage of their access privileges.

Overall, social engineering attacks are a growing concern for individuals and organizations, as attackers continue to find new and creative ways to manipulate people into giving away sensitive information or taking actions that benefit them. It is important to be aware of these attack types and to take steps to protect yourself and your organization from these types of threats.

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Answer:

...

Explanation:

...

The question is incomplete. Here is the complete question.

Two kg of a two phase liquid vapor mixture of carbon dioxide (CO₂) exists at -40°C in a 0.05m³ tank. Determine the quality of the mixture, if the values of specific volume for saturated liquid and saturated vapor CO₂ at -40°C are \(v_{f}\) = 0.896 x 10⁻³m³/kg and \(v_{g}=\) 3.824 x 10⁻²m³/kg, respectively.

Answer: x = 1

Explanation: In a phase change of a pure substance, at determined pressure and temperature, the substance exists in two different phases: saturated liquid and saturated vapor.

Quality (x) is the ratio of saturated vapor in the mixture and can be written as:

\(x=\frac{m_{vapor}}{m_{liquid}+m_{vapor}}\)

It has value between 0 and 1: x = 0 for saturated liquid and x = 1 for saturated vapor.

When related with volumes, quality is rearranged as:

\(x=\frac{v-v_{f}}{v_{g}-v_{f}}\)

Solving for x:

\(x=\frac{0.05-0.896.10^{-3}}{3.824.10^{-2}-0.896.10^{-3}}\)

\(x=\frac{0.049104}{0.037344}\)

x = 1.3

Quality of mixture of carbon dioxide is x = 1, which means it's for saturated vapor.

The CIA triad and the Parkerian hex are the fundamental principles of information security.

Parkeriano, or Parkerian hexad: is a set of six elements of information security proposed by Donn B. Parker.

1. Confidentiality.

2. Ownership or Control.

3. Integrity.

4. Authenticity.

5. Availability.

6. Utility

The Parkerian hexagram adds three more attributes to the three classic security attributes of the CIA triangle

these are the fundamental principles of information security.

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The rate at which thermal energy is appearing in the resistor at time t can be found using the formula: P = I^2 * R, where P is the power, I is the current flowing through the circuit, and R is the resistance of the resistor. To find the current, we can use the equation for the charge on a capacitor as it charges up: Q = C * V, where Q is the charge on the capacitor, C is the capacitance, and V is the voltage across the capacitor.

Since the capacitor starts uncharged, the initial voltage across it is zero. As the capacitor charges up, the voltage across it will increase, but the voltage across the resistor will be equal to the battery's EMF E. Therefore, the current flowing through the circuit at time t can be found using Ohm's Law: I = E / (R + (1/C) * Q). Substituting Q = C * V, we get I = E / (R + (1/C) * C * V). Since V = Q/C, we get I = E / (R + V).

To find V, we can use the equation for the voltage across a charging capacitor: V = E * (1 - e^(-t / (R * C))). Substituting this into the expression for I, we get:

I = E / (R + E * (1 - e^(-t / (R * C))) / C)

Now we can find the power dissipated in the resistor at time t:

P = I^2 * R = (E^2 * R) / ((R + E * (1 - e^(-t / (R * C))) / C)^2)

So the rate at which thermal energy is appearing in the resistor at time t is (E^2 * R) / ((R + E * (1 - e^(-t / (R * C))) / C)^2), expressed in terms of the given variables resistance R, capacitance C, and EMF E.

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A binary temperature-composition phase diagram illustrates the relationship between temperature, the concentration of each component in a binary mixture, and the phase boundaries of the mixture.

At a eutectic point, two solid phases and a liquid phase are in equilibrium. In other words, three phases are present when the system is at equilibrium. Let's go into more detail about what a eutectic point is and why it's important on a phase diagram.A eutectic point is the lowest temperature at which a eutectic mixture melts. A eutectic mixture is a combination of two or more components that, when melted, results in a homogeneous liquid that solidifies into two or more solid phases.

In the case of a binary mixture, a eutectic mixture contains two components in specific proportions that produce a eutectic reaction.The eutectic point on a binary temperature-composition phase diagram is located at the intersection of the two solidus curves (which represent the temperatures at which solidification of one component occurs) and the liquidus curve (which represents the temperature at which melting of the solid occurs). At the eutectic point, the proportions of the two components are such that the solid phases are in equilibrium with the liquid phase, resulting in the formation of two solid phases and a liquid phase.

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Answer:

If your equipment is well maintained, it's less likely to breakdown, which leads to increased uptime, more working hours for the equipment, fewer repair costs, and therefore increased revenue.

Explanation:

Answer:what are you trying to say

Explanation:

The answer is analyze

Answer:

no idea

Explanation:

gvghvvvghhbbgggggggig gjgjg gjgbg gig gg bg GB g GB GB GB GB g GB GB GB of me and I am a diary and crewmate hide if you see a diary or not the other person is a non-electrolyte or no one vent the imposter win a diary or you can get any more confidently than you are in a spectacular place is the most important points to be mo to get skins and crewmate for a few days to be sure it will be the same for me it will take a while for a couple to get the right angle bu the other one is come to the end and then you have birds to get a lot more than a diary of a candle or no other one in a few weeks or no time to do it for me and my friend who has no idea how much time I have been to a new episodes and the best of all the time I am going sleep

Answer:

450.000 USD

Explanation:

Đây,

Cấu trúc hữu cơ 3/1 có nghĩa là ¾ một phần vốn được chuyển vào chi phí cố định và ¼ một phần đi vào chi phí biến đổi.

Tiền lương của người lao động là chi phí cố định và do đó, mức lương

= ¾ * 600.000 USD

= 450.000 USD

Answer:

the percentage of light that gets through this combination is 9.38

Explanation:

Given the data in the question;

Let us represent the incident unpolarized light with \(I_0\).

So, the amount of light intensity passing through the first polarizer will be;

\(I_1\) = \(I_0\) / 2 ------ let this be equation 1

An the amount of light intensity passing through the second polarizer will be;

\(I_2\) = \(I_1\)cos²θ

given that; the second one has its transmission axis at 30°

so, we substitute;

\(I_2\) = \(I_1\) × cos²( 30° )

\(I_2\) = \(I_1\) × 0.75

\(I_2\) = 0.75\(I_1\)

from equation; \(I_1\) = \(I_0\) / 2

\(I_2\) = 0.75( \(I_0\) / 2 )

\(I_2\) = 0.375\(I_0\) .

Now, the amount of light intensity passing through the third polarizer will be;

\(I_3\) = \(I_2\)cos² ( 90° - 30° )

\(I_3\) = \(I_2\) × cos²( 60° )

\(I_3\) = \(I_2\)  × 0.25

we substitute

\(I_3\) = 0.375\(I_0\)  × 0.25

\(I_3\) = 0.09375\(I_0\)

∴ \(I_3\)/\(I_0\) × 100 = 0.09375 × 100

⇒ 9.38%

Therefore, the percentage of light that gets through this combination is 9.38

Answer:

a) the minimum sampling rate is 6 kHz

b) the minimum numbers of required samples are 120

c) the minimum length of the analog signal is 0.02 s

Explanation:

Given the data in the question;

(a) the minimum sampling rate;

band width of analog signal xₐ(t) is;

bandwidth B = 3kHz

Now, according to sampling theorem, minimum sampling rate F\(_s\) must be twice the bandwidth of the signal.

so

F\(_s\) = 2B

F\(_s\) = 2( 3 kHz )

F\(_s\) = 6 kHz

Therefore, the minimum sampling rate is 6 kHz

(b) the minimum number of required samples;

Let L represent the minimum number of samples required,

given that; required resolution of the spectrum of the signal is less than or equal to 50 Hz

F\(_s\)/L ≤ 50

L ≥ F\(_s\)/50

L ≥ ( 6 × 1000 Hz ) / 50

L ≥ 6000 / 50

L ≥ 120

Therefore, the minimum numbers of required samples are 120

(c) the minimum length of the analog signal record(in seconds).

minimum number of samples required is 120

T = L /  F\(_s\)

T = 120 / ( 6 × 1000 Hz )

T = 120 / 6000

T = 0.02 s

Therefore, the minimum length of the analog signal is 0.02 s

The soil order which would be the least weathered and developed among the given soil orders is b. Entisols.

An entisol is a young soil that does not have a well-established soil profile. It is the least developed of all the soil orders. Entisols are often found in areas that are recently formed or where erosion is high. They are typically found in areas with recent geological processes, such as recently deposited sediment. They are also found in areas with high rates of erosion or weathering. Entisols are usually low in organic matter and nutrients. They are also often very shallow, with little or no soil horizons. The soil order has little weathering, and it has low development, making it the least developed of all the soil orders

Soils are complex systems that are critical for agriculture, biodiversity, and ecosystem function. They support plant growth by providing nutrients, water, and support for roots. Soil formation is a slow and complex process that can take thousands of years. Soil formation depends on several factors, including climate, geology, vegetation, and time.Soil orders are classifications of soils based on their properties. Each soil order has unique characteristics that reflect its formation and development. The United States Department of Agriculture (USDA) has developed a soil taxonomy system that categorizes soils into 12 soil orders. Each soil order has unique properties that reflect its formation and development.The least developed of all the soil orders is Entisols. It is a young soil that does not have a well-established soil profile. Entisols are typically found in areas with recent geological processes, such as recently deposited sediment. They are also found in areas with high rates of erosion or weathering. Entisols are usually low in organic matter and nutrients. They are also often very shallow, with little or no soil horizons. The soil order has little weathering, and it has low development, making it the least developed of all the soil orders.

The soil order that would be the least weathered and developed among the given soil orders is b. Entisols.

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Assembly is essentially binary code written in a way that people can read it. The assembler then converts the assembly code, line by line, to the corresponding bit code.

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Convolution is an important operation in DSP. MATLAB does provide a built-in function called conv that computes the convolution between two finite-duration sequences.(a) Suppose x(n) = {1, 1, 1, 1, 1}and h(n) = {1, 1, 1}, where the underline symbol " " indicates the time index 0.

Plot y(n) which is achieved by y(n) = x(n) ⋆ h(n).x(n) = {1, 1, 1, 1, 1}h(n) = {1, 1, 1}By applying convolution, we get y (n) = x(n) ⋆ h(n) = {1, 2, 3, 3, 3, 2, 1}(b) Solve the above problem analytically by hand and determine if the two outputs are the same.

x(n) = {1, 1, 1, 1, 1}h(n) = {1, 1, 1}y(n) = x(n) ⋆ h(n)So, $$y(n) = \sum_{k=-\infty}^{\infty} x(k)h(n-k)$$The non-zero terms in the summation will be when k = 0, 1, 2, 3, 4. Then,$$y(n) = \sum_{k=0}^{4} x(k)h(n-k)$$$$y(n) = \sum_{k=0}^{4} h(k) x(n-k)$$Substituting the given values of x(n) and h(n), we have $$y(n) = (1 * 1) + (1 * 1) + (1 * 1) + (1 * 1) + (1 * 1)$$$$y(n) = 1 + 1 + 1 + 1 + 1$$$$y(n) = 5$$The first and the last samples in y(n) occur when h(n) overlaps with the endpoints of x(n), which are 0 and 4. Hence, the duration of y(n) is 5 samples.

The convolution output of x(n) and h(n) matches with the result obtained in the above solution.

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(a)Suppose x(n) = {1, 1, 1, 1, 1} and h(n) = {1, 1, 1}, where the underline symbol indicates the time index 0. Plot y(n) which is achieved by y(n) = x(n) ⋆ h(n). To calculate the convolution between two signals, we utilize MATLAB's conv function.

Using the following code, we may easily plot the output clear all; close all; %clearing command window and work spa = [1 1 1 1 1] = [1 1 1] = conv(xn,hn);%convolution of x and h Solve the above problem analytically by hand and determine if the two outputs are the same.

The mathematical computation of convolution of x(n) and h(n) is represented by the following formula:\[y(n)=x(n)*h(n)=\sum (k)h(n-k)\]On substituting the given values of x(n) and h(n), we get,\[y(n)=x(n)*h(n)=\sum_{k=-\i}x(k)h(n-k)\]\[y(n)=(1)(1)+(1)(1)+(1)(1)+(1)(1)+(1)(1)\]\[y(n)=5\]Therefore, both the results are same.

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Answer:

1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.

2) The weakest point on cross section A is located at the point where the bending moment is maximum.

3) The von-Mises stress at the weakest point is given by:

σ = M/I

where M is the bending moment and I is the moment of inertia of the cross section.

4) The factor of safety n is given by:

n = Sy/σ

where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.

Explanation:

Hope this helps!

Answer:

1.4 mL

Explanation:

Given that:

volume of alcohol \(V_0\) = 500

Temperature change ΔT = (30° - 5°)C

=25° C

\(\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C\)

The increase in volume ΔV =  \(\alpha \times V_o \times \Delta T\)

\(= 500 \times 1.12 \times 10^{-4} / ^0 C\times 25^0 C\)

= 1.4 mL

The 'marking menu' opened up ways for me to access the most commonly used commands and tools with a flick of the wrist. What's more impressive is that its dependent on workspace, so you can use it in all parts of the design!

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