the density of mercury is 13.6 gram per centimetre cubic find the volume of 2720 grams of mercury in metres cubic​

Answers

Answer 1

Answer:

2×10^-4m^3/0.002m^3

Explanation:

first know the formula of getting density which is

density=mass/volume

substitute with values given in the problem

{before beginning convert all the values to SI units}

13600m/cm^3=2.27kg/x

calculate to solve for x=volume


Related Questions

Hello please just answer question one for me!

Hello please just answer question one for me!

Answers

Answer:

See below

Explanation:

No energy has been added to the system to make it swing higher than from where it was released....actually....some energy has been LOST in the system due to air friction, so the balloon will not swing QUITE as high as from where it was released.

what feature of sound distinguishes between noise and music?

Answers

The feature of sound that distinguishes between noise and music is the presence of regular and organized patterns in the sound waves. Music typically exhibits rhythmic patterns, melodic structures, and harmonious arrangements, whereas noise lacks these organized patterns.

Here are a few key distinctions:

1. Pitch: Music often consists of discernible pitches, where specific frequencies or combinations of frequencies create melodic and harmonic elements. In contrast, noise tends to lack a distinct pitch and may contain a random mixture of frequencies.

2. Rhythm: Music typically follows a rhythmic pattern with a regular beat and timing, providing a sense of structure and synchronization. Noise, on the other hand, lacks a consistent or intentional rhythmic pattern and may appear random or chaotic in terms of timing.

3. Melody and Harmony: Music commonly features melodic lines and harmonies created by intentional arrangements of tones and chords. These melodic and harmonic elements contribute to the aesthetic quality and organized structure of music. Noise generally lacks intentional melodic or harmonic patterns.

4. Subjective Perception: The subjective perception and interpretation of sound can also play a role in distinguishing between noise and music. Different individuals may have varying preferences or cultural contexts that influence their perception of what is considered noise or music.

It is important to note that the distinction between noise and music can be subjective to some extent, as certain genres or styles of music may incorporate unconventional or experimental elements that challenge traditional notions of musicality.

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A marksman holds a 3.00 kg rifle loosely, so that we can ignore any horizontal external forces acting on the rifle–bullet system. He fires a bullet of mass 5.00 g horizontally with a speed vbullet=300m/s.
The same rifle fires a bullet with mass 10.5 g at the same speed as before. For the same idealized model, find the ratio of the final kinetic energies of the bullet and rifle.

Answers

The final kinetic energy of the rifle is about 3.48 times greater when firing the heavier bullet.

We can use the conservation of momentum to find the velocity of the rifle after the bullet is fired. Since the rifle is initially at rest, the total momentum before the bullet is fired is zero. After the bullet is fired, the total momentum is:

\(p = mvbullet + MVrifle\)

where m is the mass of the bullet, vbullet is its velocity, M is the mass of the rifle, and Vrifle is the velocity of the rifle after the bullet is fired. Since there are no horizontal external forces acting on the rifle-bullet system, the total momentum is conserved, so we have:

0 = mvbullet + MVrifle

Solving for Vrifle, we get:

\(Vrifle = -mvbullet/M\)

Note that the negative sign indicates that the rifle moves in the opposite direction of the bullet.

The kinetic energy of an object is given by:

\(K = (1/2)mv^2\)

where m is the mass of the object and v is its velocity. The ratio of the final kinetic energies of the bullet and rifle is:

\(Kbullet/Krifle = (1/2)mvbullet^2 / (1/2)MVrifle^2\)

Substituting the expression for Vrifle that we found above, we get:

\(Kbullet/Krifle = (m/M)(vbullet/Vrifle)^2\)

For the first bullet, we have m = 5.00 g = 0.005 kg and vbullet = 300 m/s. Substituting these values, we get:

Kbullet/Krifle = (0.005 kg / 3.00 kg) (300 m/s / (-0.005 kg / 3.00 kg))^2

Simplifying, we get:

Kbullet/Krifle = 0.0025

For the second bullet, we have m = 10.5 g = 0.0105 kg and vbullet = 300 m/s. Substituting these values, we get:

Kbullet/Krifle = (0.0105 kg / 3.00 kg) (300 m/s / (-0.0105 kg / 3.00 kg))^2

Simplifying, we get:

Kbullet/Krifle = 0.0087

Therefore, the ratio of the final kinetic energies of the bullet and rifle for the two cases is:

0.0087 / 0.0025 = 3.48

So the final kinetic energy of the rifle is about 3.48 times greater when firing the heavier bullet.

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Which of the following types of microscopes reveals the surface features of small molecules? - a confocal microscope - a fluorescent microscope - a transmission electron microscope (TEM) - an atomic force microscope

Answers

The types of microscopes that reveals the surface features of small molecules is an atomic force microscope.

The Atomic Force Microscope (AFM) is useful for imaging the surface topography of living, soft materials in their natural settings. It can be used to examine the inherent elastic modulus and receptor-ligand interactions of cells and extracellular matrix, among other mechanical properties. SEM pictures can investigate surface features that are several tenths of a nanometer in size, but AFM resolution is less than 0.1 nm. As a result, AFM can discern objects on flat surfaces with molecular dimensions.

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the connects all the points that have the highest annual mean temperatures compared to other locations at their longitude.

Answers

The thermal equator connects all the points that have the highest annual mean temperatures compared to other locations at their longitude.

The thermal equator is an imaginary line that connects all the points that have the highest annual mean temperatures compared to other locations at their longitude. It is a product of the Earth's solar heating and the resulting global atmospheric circulation patterns.

The thermal equator generally lies slightly north of the geographical equator and shifts slightly north or south depending on the seasonal changes in solar heating. The thermal equator has implications for agriculture, as it defines the regions where crops that require high temperatures can be grown successfully.

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Which term best describes the basic unit that makes up all matter?
O A. Atomic nuclei
O B. Protons
O C. Atoms
O D. Molecules

Answers

Answer:

C. Atoms

Explanation:

The basic unit of matter and the smallest, indivisible unit of a chemical element. It comprises a nucleus (neutrons + protons) that is surrounded by a cloud of electrons.

A student driving home for the holidays starts at 7:00 AM to make the 700km trip, practically all of which is on nonurban interstate highways. If she wants to arrive home no later than 5:00 PM, what must be her minimum average speed?

Answers

The student must maintain a minimum average speed of 70 km/h to arrive home no later than 5:00 PM.

To determine the minimum average speed the student must maintain to arrive home no later than 5:00 PM, we need to consider the total time available for the trip and the distance to be covered.

The student starts at 7:00 AM and wants to arrive home by 5:00 PM. This means she has a total of 10 hours available for the trip (from 7:00 AM to 5:00 PM).

The distance to be covered is 700 km.

To find the minimum average speed, we divide the total distance by the total time:

Minimum average speed = Total distance / Total time

Minimum average speed = 700 km / 10 hours

Minimum average speed = 70 km/h

Therefore, the student must maintain a minimum average speed of 70 km/h to arrive home no later than 5:00 PM.

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In 1–2 sentences, explain how you could find the kinetic energy of a baseball when it hits a window.(2 points)

Answers

Answer: You could measure the baseball's mass, the distance the ball traveled to hit the window, and finally find the time it took for it to reach the window. With this information, we can calculate the velocity of the baseball, and then the kinetic energy using the formula KE=1/2mv^2.

When a basketball player jumps to make a shot, _____.

Answers

Answer:

i would like some more explanation i dont understand the question enough

Explanation:

Answer:

Its D.

Explanation:

"When a basketball player jumps to make a shot, _____.""A:the forces on the player’s feet and on the floor are both in the upward direction B:the action-reaction forces are unequal because they act on different objects C:the force with which he jumps is equal to the force with which he shoots the ball D:the downward force on the floor is equal to the upward force on his feet "the floor is flat so it wont be a bc the shoes or not flat and its not b bc how u saypost to jump up uk and its not c bc u need to jump u cant just hit your shot when u jump up u gotta make sure u aimed for the shot so

Oh no! The Hulk just fell off the Empire State Building! Calculate how long it took him to fall straight down from the top of the Empire State Building, which is 380 m high.

If you can provide some, explanation I will greatly appreciate it.

Answers

Answer:

8.803 s

(but this is only if it's a free fall, which we assume since we didn't get the mass of the hulk)

Carl runs one complete lap around an outdoor track with a length of 400 meters in 100 seconds. His average speed is _____, and his average velocity is _____.

Carl runs one complete lap around an outdoor track with a length of 400 meters in 100 seconds. His average

Answers

Given:

The length of the outdoor track is: l = 400 m

The time taken to complete one complete lap around the track is: t = 100 s

To find:

The average speed and the average velocity

Explanation:

The average speed of an object is defined as the total distance covered by an object divided by the total time it took to complete that distance. It is given as:

\(v=\frac{d}{t}\)

Here, d is the total distance covered by Carl and t is the total time he took to complete the total distance d.

Substituting the values in the above equation, we get:

\(\begin{gathered} v=\frac{400\text{ m}}{100\text{ s}} \\ \\ v=4\text{ m/s} \end{gathered}\)

Now, the average velocity of an object is defined as the displacement of an object divided by the total time it took to displace from its initial position.

As Carl runs one complete lap around an outdoor track, after one round he returns to his original initial position from where he had started running. Thus, the displacement D of the Carl will be zero.

Thus, D = 0 m

The average velocity V is calculated as:

\(V=\frac{D}{t}\)

Substituting the values in the above equation, we get:

\(\begin{gathered} V=\frac{0\text{ m}}{100\text{ s}} \\ \\ V=0\text{ m/s} \end{gathered}\)

Final answer:

Thus, the average speed of Carl is 4 m/s and his average velocity is 0 m/s.

(ii) a wet bar of soap slides down a ramp 18.8 m long inclined at 8.0°. a) what is the height of the inclined plane at the extreme left b) how long does it take to reach the bottom? assume 0.0550

Answers

The the time required to reach the bottom of the incline is calculated to be 6.77 s.

Displacement of the bar = 18.8 m

Angle of inclination θ = 8°

Coefficient of friction factor μk = 0.055

We have to find the time taken to reach the bottom.

We know that the formula for weight of the soap bar is given as,

Fg = mg sinθ

The frictional force acting on this soap bar is determined by,

Ff = μ mg cosθ

Let us determine the constant acceleration of the bar,

F = Fg - Ff

Fg - Ff = ma(mg sinθ) - μ mg cosθ = m a

a = g sinθ - μg cosθ

where,

Fg is force imparted due to weight

Ff is frictional force

m is mass of the bar

g is acceleration due to gravity

a is acceleration of the bar

If the bar starts from rest, equations of motion involved are,

s = 1/2 a t²

t = √(2s/a)

where,

s is the distance moved by the bar

t is the time taken to reach the bottom

Putting in the known values, we have,

t = √(2× 18.8/a)

a = g sinθ - μg cosθ = 9.8 sin8° - 0.055× 9.8 cos8° = 1.364 - 0.543 = 0.821 m/s²

t = √(2× 18.8/a) = t = √(2× 18.8/0.821) = 6.77 s

Thus, the time required to reach the bottom of the incline is calculated to be 6.77 s.

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Kathy and Cheryl are walking in a fundraiser. Kathy completes the course in 3.6 hours and Cheryl completes the course in 6 Kathy walks two miles per hour faster than Cheryl. FiFind Kathy’s speed and Cheryl’s speed.

Answers

Kathy’s speed is 5 miles per hour and Cheryl’s speed is 3 miles per hour.

Kathy and Cheryl are walking in a fundraiser. Kathy completes the course in 3.6 hours and Cheryl completes the course in 6 hours. Kathy walks two miles per hour faster than Cheryl.

Let the speed of Kathy be x Then the speed of Cheryl will be (x - 2)

Distance covered by both of them will be the same.

Therefore,(x)(3.6) = (x - 2)(6)3.6x = 6x - 12(3.6)12 = 2.4x

x = 5

Thus, the speed of Kathy = 5 miles per hour and the speed of Cheryl = 3 miles per hour.

So, the  Kathy’s speed and Cheryl’s speed is: Kathy’s speed is 5 miles per hour and Cheryl’s speed is 3 miles per hour.

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[HELPPPPP HELP ME HELP ] Current carrying conductor AB is placed in a magnetic field shown below. If the conductor AB moves away from the magnet, what will be the direction of the current in the conductor?​

[HELPPPPP HELP ME HELP ] Current carrying conductor AB is placed in a magnetic field shown below. If

Answers

Answer:

B is directed from N to S     (upwards at the open end)

Let the magnet be oriented with the open end at the north

F = q * v X B

A positive charge would be deflected towards the East using v X B

This is the direction of the "conventional" current which is B to A

Actual charges flow from A to B but the sign of the charge is -q

convert 5.7 kilometers decameters

Answers

570 decameters

To convert 5.7 kilometers into decameters, you can divide 5.7 by 0.1.

1 kilometer = 1000 meters

1 decameter = 10 meters

So,

1 kilometer = 100 decameters

Therefore,

5.7 kilometers = (5.7 x 100) decameters = 570 decameters.

Star meaning plz :) I need help

Answers


a fixed luminous point in the night sky which is a large, remote incandescent body like the sun. or a conventional or stylized representation of a star, typically one having five or more points.

21. A toy car starts from rest and accelerates at 1.50 m/s’ [E] for 5.25 s. What is the final
velocity, V, of the car? Show your work.

21. A toy car starts from rest and accelerates at 1.50 m/s [E] for 5.25 s. What is the finalvelocity,

Answers

Answer: The final Velocity, V, of the car is 7.9m/s

Explanation:

Given the following :

Toy car starts from rest, therefore,

Initial Velocity (u) = 0

Acceleration (a) = 1.5m/s^2 E for time, t = 5.25s

Final velocity (V) of the car =?

Using the motion equation:

v = u + at

Where v = final Velocity

u = Initial Velocity

a = acceleration

t = time

v = 0 + 1.5(5.25)

v = 0 + 7.875

v = 7.875m/s

v = 7.9m/s

The amount of a radioactive isotope present in a certain sample at time t is given by A(t) = 500e^-0. 02828t grams, where t years is the since the initial amount was measured. How long will it take for the amount of the isotope to equal 317 grams

Answers

It will take approximately 22.037 years for the amount of the radioactive isotope to equal 317 grams.

To determine how long it will take for the amount of the radioactive isotope to equal 317 grams, we can set up an equation using the given formula:

A(t) = 500e^(-0.02828t)

In this case:

Initial amount (A₀) = 500 grams

Target amount (A(t)) = 317 grams

We need to find the time (t) when the amount of the isotope is equal to 317 grams. We can rearrange the equation and solve for time:

A(t) = A₀e^(-0.02828t)

317 = 500e^(-0.02828t)

317/500 = e^(-0.02828t)

Taking the natural logarithm (ln) of both sides to isolate the exponent:

ln(317/500) = -0.02828t

t = ln(317/500) / -0.02828

t ≈ 22.037 years

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when a nucleus of 235u undergoes fission, it breaks into two smaller, more tightly bound fragments. t or f

Answers

The fragments reaction is 7.59 MeV/nucleon and  8.39 MeV/nucleon

What is nucleus ?

Neutrons and protons, which have opposite electric charges, make up atomic nuclei. The strongest basic force now understood, known as the strong force, is what holds these things together. A normal atom's nucleus generally holds more than 99.9% of the atom's mass yet takes up considerably less than.01 percent of its volume.

What is fission ?

When a neutron collides with a bigger atom, it excites it and causes it to split into two smaller atoms, which are known as fission products. This process is known as fission. A chain reaction might start as a result of additional neutrons that are also emitted. Huge amounts of energy are produced during the splitting of each atom.

1) m_proton + m_netron + m_electron - m_U

= 92*1.007276466812 + 92*5.4857990943e-4 + 143*1.008664916 - (235.0439299)

= 1.9151 u

= 931.494061 * 1.9151 MeV

= 1784 MeV

= 1784/235 = 7.59 MeV/nucleon

2) m_proton + m_netron + m_electron - m_Cs

= 55*1.007276466812 + 55*5.4857990943e-4 + 82*1.008664916 - (136.9070895)

= 1.2338 u

= 931.494061 * 1.2338 MeV

= 1149 MeV

= 1145/137 = 8.39 MeV/nucleon

Therefore, the fragments reaction is 7.59 MeV/nucleon and  8.39 MeV/nucleon.

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The coetticient of friction between a block and the surface it slides across is 0.360. The block has a mass of 150 kg

What force is required to accelerate the block 0.5 m/a^2.

Answers

The friction between the b;ock and surface is given by mass and accelerartion.

Force = mass * acceleration

Defination wheel and axle​

Answers

a simple lifting machine consisting of a rope which unwinds from a wheel on to a cylindrical drum or shaft joined to the wheel to provide mechanical advantage. reeeeeeeeeeeeeeeeeeeeeeeeee

As you know, the earth has an orbital period of 1.0 year at an orbital radius of 1.0 AU (astronomical unit, the average distance between the earth and the sun). If a new "minor planet" were to be found in a circular orbit with radius 13 AU, what would be its orbital period?

Answers

If a new "minor planet" were to be found in a circular orbit with a radius of 13 AU, 47 years would be its orbital period.

What is the Orbital Period?

The amount of time it takes for an astronomical object to complete one orbit around another object is known as the orbital period (also called the revolution period). It typically refers to planets or asteroids that orbit the Sun, moons that orbit planets, exoplanets that orbit other stars, and binary stars in astronomy.

The relationship between an object's average distance from its object of orbit and its period is depicted by Kepler's third law. In its most basic form, this can be applied to anything naturally orbiting around other things. Formula: Where: P2=ka3 The orbit's time-based period is called P.

A year is a time it takes for a planet to circle the Sun once, which for Earth is just over 365 days.

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What is weight??????????????????

Answers

Answer:

Weight is a body's relative mass, or the quantity of matter contained by it.

Explanation:

Hope this helps

What is the relationship between the frequency and the wavelength of a wave?

Answers

Answer: The wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.

Explanation:

what happens the first time dr. hewitt lifts the bowling ball near his teeth and lets go?

Answers

Dr. Hewitt's experiment using the bowling ball to showcase the relationship between momentum, energy and speed of a body in motion. In his first attempt, the ball returns and stops almost exactly at the point it was launched.

In Dr.Hewitt's first trial with the bowling ball, the ball was launched without any additional force applied, hence, the initial energy during the launch was converted to same amount of potential energy on the ball's return. Hence, stopping at the same point where the ball was launched.

In subsequent trials, when extra force was applied, the ball went past the initial launch position as the potential energy as the ball returned was higher.

Therefore, the ball stopped at the position of initial launch during the first trial.

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You don't need to push off with a foot against the ground to start

a skateboard rolling down a bank. Does this violate Newton's

first law of motion? Why or why not?

Answers

Answer:

No, it does not violate Newton's first law

Explanation:

Newton's first law of motion states that, "A body will continue in its state of rest or uniform motion in a straight unless acted up by a force to make it act otherwise" This means a force is required to initiate movement and also required to halt it.

For a skate positioned to roll down a bank, Here, the force of gravity acting on the skate acting downward will make the skate roll without having to push off the skate with a foot. Because the position of the skate doesn't balance the Gravitational force acting on it. Hence. The Gravitational force is enough to set the skate in motion.

with what tension must a rope with length 2.80 m and mass 0.125 kg be stretched for transverse waves of frequency 39.0 hz to have a wavelength of 0.740 m ?

Answers

The tension in the string for waves of frequency of 39 Hz to have a wavelength of 0.740 m is 1166 N.

The velocity(v) of a wave in a string is given by the following formula

V = 1/2L x √(T/μ) .........(i)

Here, L is the length of rope

T is the tension

μ is the mass per unit length i.e, M/L

We know that v = f x λ

Where f is the frequency and λ is the wavelength

So, the equation becomes

f x λ =  1/2L x √(T/μ)

Putting f = 39 Hz, lambda = 0.740 m, L= 2.80 m and m = 0.125 kg

39 x 0.740 = 1/2(2.80) root T/(0.125/2.80)

On solving the above equation

T = 1166 N.

Hence, the tension in the string for waves of frequency of 39 Hz to have a wavelength of 0.740 m is 1166 N.

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A man with a mass of 60 kg rides a bike with a mass of 13 kg. What is the force needed to accelerate the bike at 0.90 m/s2?

A. 65.7
B.657
C.75.6
D.756

Answers

The total mass of the things on the road is 60 + 13, which is 73kg.

mass • acceleration = F

73 x 0.9m/s^2 = 65.7N

F = 65.7 N

What is the formula for density?

(A) D= m x V
(B) D= d-(m+v)
(C) D= d/v
(D) D= m/v

Answers

Answer:

D: D= m/v

Explanation:

That is the right formula. I like to remember that finding density takes a lot of HEART because it is shaped like a heart

E) Would you expect the temperature of the water to continue rising above 20°C? Explain your answer.​

Answers

Answer:

No, when water converts to steam on heating, the temperature remains constant at the boiling point and the heat supplied to the water is used for the vaporisation of water, rather than increasing the temperature of water.

This energy used for the vaporisation is termed as the latent heat of vaporisation.

You’ll find similar observations if you try heating ice - the temperature remains at 0∘ Celsius. Here, it’s the latent heat of fusion.

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O drops (Unable to buffer 10 drops acid 20 drops acid Buffer capacity was not reached Beaker #2 4.29 4.12 3.88 3.57 OM Choose 469 4.51 4.79 462 Beaker 23 4.46 Choose 5.15 503 Beaker #4 489 5.52 542 531 Choose 5.64 Beaker 85 Cha 6.29 0.00 0:00 Choose 7.84 Beaker 36 Table view List view Buffer capacities in drops of base Initial 10 drops 20 drops 30 drops Beaker 1 280 3.50 0.00 000 Base Buffer capacity Choose... Odrops (Unable to buffer) 10 drops base 20 drops base Buffer capacity was not reached Beaker #2 4.20 4.42 4.40 451 Cho 4.62 4.86 Beaker N3 4.77 49 Choose 5.00 5.15 5.22 Beaker 4 5:31 Choose Doo Choose 5.44 5.64 5.73 5.91 Beaker 5 Choose Choose 0.00 0.00 1230 8.53 Beaker 86 What was the test or tests that made you decide if you compound was an aldehyde or a ketone and why? If, on average, a person smokes 10 cigarettes a day, on average how many days would you expect him to be absent from work?What is the correlation coefficient between the number of cigarettes and the number of days absent from work?What percentage of variation in number of days absent from work is explained by the number of cigarettes each smoker smokes?What is the standard deviation of prediction errors for this model?Cigarettes Days43 1941 1847 2246 1846 2045 1845 1544 1842 1242 1542 940 1349 1948 2248 2047 1847 1447 2246 1845 2145 1345 2045 1544 1744 1444 2544 1443 1543 1343 2043 1442 2442 1442 1442 1841 1741 1541 1241 1241 941 1641 1640 1440 1240 2440 1540 1439 1739 1738 1537 1937 1837 1937 2037 1437 1336 1036 1736 1236 1435 1435 935 1835 1034 1434 1434 1534 933 1332 1232 1032 1531 1431 1131 830 1130 1230 930 1429 929 1529 1428 1428 1528 1427 1427 826 626 1125 1425 324 1522 920 819 917 717 1217 1016 515 7 Which of the following equations are first-order, second-order, linear, non-linear? (No ex- Slanation needed.) 12xy- 7ry' = 4e* y 17xy=-yx dy -3y = 5y +6 da +(z + sin Use the law of Cosines to find the values of X and YX=Y=