The distribution of the mass of the milky way galaxy is determined by.

for example

1. drinking water at least after 1 hour beacuse if we immediately drink water just after meal it dilutes the HCL produced in our stomach which hinders the digestion process

2.picking up tomatoes for salads which contains oxalic acid

3.Cutting apples which contains malic acid with knife then after sometimes it will trun into brown due to oxidation of iron present in a apple.

A few examples of real science that demonstrate how scientific research and exploration contribute to our understanding of the world around us are the Human genome project, Mars exploration, and Climate Change Studies.

Human Genome Project:

The Human Genome Project (HGP) is a real scientific endeavor that aimed to map and sequence all the genes in the human genome. It involved an international collaboration of scientists and researchers to understand the genetic makeup of humans.

Mars Exploration:

Various space agencies, such as NASA and ESA, have conducted real scientific missions to explore Mars. Rovers like Curiosity and Perseverance have been sent to the Martian surface to study its geology, and atmosphere, and search for signs of past life.

Climate Change Studies:

Climate change research is an ongoing scientific field that investigates the causes and effects of global climate change. Scientists collect and analyze data from various sources, including satellite observations, weather stations, and ice core samples, to study trends and changes in Earth's climate over time.

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The energy required to heat 40.7 g of water (H2O) from -10°C to 70°C can be calculated as follows;Mass of water = 40.7 gTemperature change = 70 - (-10) = 80 °C Specific heat of ice = 2.06 J/g °CSpecific heat of water = 4.18 J/g °CHeat of fusion of water = 334 J/gAt first, we have to heat the ice from -10°C to 0°C using the formula;

q = mcΔTwhere m is the mass, c is the specific heat, and ΔT is the temperature change. For ice, c = 2.06 J/g °C, and the temperature change is 0 - (-10) = 10°C;

q1 = (40.7 g)(2.06 J/g °C)(10°C) = 839.42 J

This amount of heat energy is needed to bring the ice to its melting point. The amount of heat required to melt the ice at 0°C can be determined using the formula; q2 = mLfwhere Lf is the heat of fusion of ice, which is 334 J/g;

q2 = (40.7 g)(334 J/g) = 13590.8 J

Now, we have 40.7 g of water at 0°C.

To heat this water to 70°C, we use the formula;

q3 = mcΔT

where m is the mass, c is the specific heat, and ΔT is the temperature change. For water, c = 4.18 J/g °C, and the temperature change is 70 - 0 = 70°C;

q3 = (40.7 g)(4.18 J/g °C)(70°C) = 12123.94 J

The total energy required is;

\(q_total = q1 + q2 + q3 = 839.42 J + 13590.8 J + 12123.94 J = 26554.16 J\)

Thus, the energy required to heat 40.7 g of water (H2O) from −10∘C to \(70∘C is 2.66 x 10^4 J or 26.6 kJ\).

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After 20 s, the motorcycle attains a speed of

\(\left(4\dfrac{\rm m}{\mathrm s^2}\right)(20\,\mathrm s)=80\dfrac{\rm m}{\rm s}\)

and it continues at this speed for the next 40 s. So at 45 s, its speed is 80 m/s.

Explanation:

F = 40 N

d = 3 m

Work

W = Fd

where: W - work, J

F - force, N

d - distance, m

W = Fd

W = (40 N)(3 m)

W = 120 Nm or 120 J

According to the question the net force on particle q1 is \(1.45 * 10^-4 N.\)

Force is an influence that produces a change in the motion, direction, shape, or orientation of an object. It is a vector quantity, meaning it has both magnitude and direction. Force can be derived from different sources, including physical contact, gravity, magnetism, or even electrical fields. Force affects objects by producing acceleration, deceleration, or changes in direction.

The net force on particle q1 is the sum of the forces due to the two other particles. The force on particle q1 due to particle q2 is given by Coulomb's Law:

\(F12 = k(q1q2/r12^2)\)

Where k is the Coulomb's Constant, q1 and q2 are the charges of the two particles, and r12 is the distance between them, which is 0.220m.

Similarly, the force on particle q1 due to particle q3 is given by:

\(F13 = k(q1q3/r13^2)\)

Where q1 and q3 are the charges of the two particles, and r13 is the distance between them, which is 0.330m.

The net force on particle q1 is then the vector sum of these two forces:

Fnet = F12 + F13

Substituting the values for the charges and distances into Coulomb's Law gives:

\(Fnet = (9*10^9)(-(8.99*10^-6)(5.16*10^-6)/(0.22^2)) + (9*10^9)(-(8.99*10^-6)(-89.9*10^-6)/(0.33^2))\)

Simplifying, we get

\(Fnet = 1.45 * 10^-4 N\)

Therefore, the net force on particle q1 is\(1.45 * 10^-4 N.\)

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Answer:

At the point of dropping the object, by Newton's first law due to gravitational force \(F_g\) = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

Answer:

The ball was thrown from a height that can be calculated using the kinematic equation:

h = vi * t + 0.5 * a * t^2

Where:

h = height from which the ball was thrown

vi = initial vertical velocity = 0 m/s (thrown horizontally)

a = acceleration due to gravity = -9.8 m/s^2

t = time taken to hit the ground

We can use the horizontal distance traveled, d = 36.31 m, to calculate the time:

d = vi * t

t = d / vi

t = 36.31 / 29.59

Now we can use t to find h:

h = vi * t + 0.5 * a * t^2

h = 0 * t + 0.5 * (-9.8) * t^2

h = 4.8 * t^2

h = 4.8 * (36.31 / 29.59)^2

h = 10.76 m

So, the ball was thrown from a height of 10.76 m.

Explanation:

The spacecraft's acceleration can be found using the equation: a = (v-u)/t = 4.50 x 10^2 m / 4.0 s = 11.25 m/s^2.

Uniformly accelerating motion refers to an object that is moving at a constant rate of acceleration. This means that the velocity of the object is changing at a constant rate, but the acceleration remains the same throughout the motion. An example of this type of motion is an object that is accelerating from rest at a constant rate. The motion of the object can be described mathematically by the equations of motion, such as distance = initial velocity * time + 1/2 * acceleration * time^2. The graph of uniformly accelerating motion is a parabola, with velocity on the y-axis and time on the x-axis. This type of motion is different from non-uniform acceleration, where the acceleration changes during the motion.

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A spacecraft that is uniformly accelerating straight upward from rest reaches an altitude of 4. 50 X 102 m [up) with acceleration of 11.25 m/s².

The spacecraft's acceleration can be found using the equation:

                      a = (v-u)/t

             = 4.50 x 10² m / 4.0 s

                  = 11.25 m/s².

Uniformly accelerating motion refers to an object that is moving at a constant rate of acceleration. This means that the velocity of the object is changing at a constant rate, but the acceleration remains the same throughout the motion. An example of this type of motion is an object that is accelerating from rest at a constant rate.

The motion of the object can be described mathematically by the equations of motion, such as distance = initial velocity × time + 1/2 * acceleration × time². The graph of uniformly accelerating motion is a parabola, with velocity on the y-axis and time on the x-axis. This type of motion is different from non-uniform acceleration, where the acceleration changes during the motion.

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Answer:

\(-\frac{1}{2}\)

Diverging lens

Explanation:

Given parameters:

Power of lens  = -2.0D

Unknown:

Focal length  = ?

Solution:

The power of lens is the reciprocal of the focal length;

   P  = \(\frac{1}{f}\)

where  f is the focal length

 f  = \(\frac{1}{P}\)   = \(-\frac{1}{2}\)

The lens is a diverging lens

Answer: The force of gravity

The object was thrown horizontally, its horizontal velocity remains constant at 10 m/s. Therefore, the magnitude of the velocity when it hits the water is also 10 m/s.

When an object is thrown horizontally, its vertical velocity remains constant due to the absence of any vertical force.

Assuming the acceleration due to gravity is approximately 9.8 m/s², we can calculate the object's vertical displacement using the formula:

s = ut + 0.5 * g * t²

where

s = vertical displacement,

u = initial vertical velocity (0 m/s as the object is thrown horizontally),

t = time (5 seconds),

g = acceleration due to gravity (9.8 m/s²).

Substituting the values into the formula:

s = 0 * 5 + 0.5 * 9.8 * (5)²

s = 0 + 0.5 * 9.8 * 25

s = 0 + 122.5

s = 122.5 meters.

Thus, the object's vertical displacement when it hits the water is 122.5 meters.

Since the object was thrown horizontally, its horizontal velocity remains constant at 10 m/s. Therefore, the magnitude of the velocity when it hits the water is also 10 m/s.

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The correct answer is 378000 km.

The speed of light is the rate at which light waves move through distinct substances. In instance, it has now been established that the speed of light in a vacuum is 299,792,458 metres per second.

Using the equation

distance = speed × time,

the total distance travelled is calculated.

Consequently, the overall distance travelled is

Distance = ( 3.00 × 10^8 m/s ) ( 2.52 )

= 756000000 m

The total distance travelled divided by two determines the distance between the Earth and the Moon.

Distance between earth to moon = 756000000/2

= 378000000 meters

= 378000 km.

Approximately 384 thousand kilometres separate the Earth and the Moon.

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Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

Answer:

Modeling is used in science to simplify complex systems and phenomena, allowing scientists to make predictions and test hypotheses.

Explanation:

a) The vector field F =\(< 2xy^3z^4, 3x^2y^2z^4, 4x^2y^3z^3 >\) is conservative because it satisfies the condition of having a curl equal to zero. By taking the curl of F and simplifying, we can verify that the result is zero.

b) To find the potential function f such that F = ∇f, we need to determine the partial derivatives of f with respect to x, y, and z and equate them to the corresponding components of F. By integrating these partial derivatives, we can find the potential function f.

c) To calculate the work done in moving a particle from A(1, 1, 0) to B(3, 2, 1) under the force field F, we can use the formula for work done by a conservative force: W = ∫(B) - ∫(A) F · dr, where the integrals are taken along the path from A to B. By evaluating these integrals, we can find the work done.

a) To show that F is a conservative vector field, we need to calculate its curl. Taking the curl of F using the appropriate differential operators, we find that the curl of F is zero. This implies that F is conservative because conservative vector fields have zero curl.

b) To find the potential function f, we equate the partial derivatives of f with respect to x, y, and z to the corresponding components of F. Solving these equations and integrating with respect to the variables, we can obtain the potential function f such that F = ∇f, where ∇ is the gradient operator.

c) To calculate the work done, we use the formula W = ∫(B) - ∫(A) F · dr, where F · dr represents the dot product of the force field F and the infinitesimal displacement vector dr along the path from A to B. By evaluating the integrals along the given path, we can determine the work done by the force field.

In summary, we have shown that F is a conservative vector field by verifying that its curl is zero. We have found the potential function f by equating the partial derivatives of f to the components of F and integrating. Finally, we can calculate the work done by evaluating the appropriate integrals along the path from A to B.

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To maximize productivity on the project, a comprehensive plan will be implemented considering excavation, concrete placement, subcontractor costs, and efficient scheduling.

To maximize productivity on the project, several strategies can be implemented. Firstly, a detailed schedule should be created using appropriate project management software.

This will help allocate resources effectively, identify critical paths, and ensure that tasks are completed in a timely manner. By closely monitoring the schedule and progress, any delays or bottlenecks can be promptly addressed.

Coordination and communication among the various teams involved are crucial. Regular meetings should be held to ensure everyone is aware of their responsibilities and to address any potential conflicts or issues.

Efficient collaboration between the excavation crew, electrician, concrete team, and subcontractors will help streamline operations and minimize downtime.

To optimize productivity, experienced and skilled crews should be assigned to each task. Proper training and clear instructions should be provided to ensure work is done efficiently and accurately.

Additionally, utilizing the right equipment and machinery, such as excavators, concrete pumps, and saw-cutting tools, can significantly speed up the process.

Quality control measures should be implemented throughout the project to avoid rework and ensure compliance with specifications. Regular inspections and testing should be conducted to identify any deficiencies early on, allowing for timely corrections.

By considering these factors and closely monitoring progress, the project can achieve maximum productivity while maintaining high standards of quality and safety.

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The most important factor in determining if an area will be subject to mass movement is gravity. However, other factors such as relief, weather, and water content can also play a role in increasing the likelihood of mass movement occurring.

A crucial aspect of activities involving mass movement is gravity. Materials move because of the pulling power of gravity, which drags them downslope. It affects slope stability and controls whether or not there will be mass movement.

Additional elements like relief (a), which describes topographic variance or landscape steepness, and water content (d) can affect slope stability and influence mass movement. These things are important, but not as important as gravity itself.

Slope steepness is influenced by relief, and steeper slopes are typically more prone to mass movement. However, the force that causes the materials to slide or collapse is gravity.

In conclusion, while relief, water content, and weather conditions can all affect how much mass moves, gravity is by far the most crucial element since it acts as the motor that starts and regulates the movement of materials downslope. Therefore, b) gravity is the right response.

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Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

Answer:

\(\sf 0.192\:ms^{-2}\:\:(3\:s.f.)\)

Explanation:

Given:

First, convert the velocities into meters per second by dividing by 3.6:

\(\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}\)

\(\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}\)

To find the vehicle's acceleration, use one of the constant acceleration equations with the given values:

\(\implies \sf v=u+at\)

\(\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a\)

\(\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a\)

\(\implies \sf 19.5a=-3.75\)

\(\implies \sf a=-\dfrac{3.75}{19.5}\)

\(\implies \sf a=-0.1923076923...\:ms^{-2}\)

Therefore, the magnitude of acceleration is:

\(\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)\)

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The acceleration of the the object is 20m/s²

Force can be defined as the product of the mass of an object with it's acceleration. It is measured in Newton(N) and it is a vector quantity. This means that force has both magnitude and direction.

from the diagram two forces are acting on the object in opposite directions. Therefore the net force = 30-10 = 20N

force = mass × acceleration. This operational definition of force is obtained from Newton second law of motion.

where mass = 1kg

20N = 1× acceleration

acceleration = 20/1= 20m/s²

therefore the acceleration of the object = 20m/s²

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Answer:

A student becomes negatively charged because of the friction between his socks and the carpet. ... The electrons get rubbed and move towards the carpet so the carpets electrons move away and the student becomes negatively charged.

Answer:

Abiotic factors include water, sunlight, oxygen, soil and temperature. Water (H²0) is a very important abiotic factor - it is often said that "water is life." All living organisms need water. Plants must have water to grow.... Without the sun, plants could not live, and without plants, animals could not live!

Explanation:

*Hope this helps*

The stress function of the form Φ = C(x²- y²) provides the solution for torsion of the bar.

To determine the expression of C and derive the given equation, we consider the torsion of a straight bar with a uniform elliptical cross-section. The stress function Φ is assumed to have the form Φ = C(x²- y²), where C is a constant.

By substituting the stress function into the torsion equation and solving for the shear stress τxy, we find that τxy = 2GC(xsin(θ) - ycos(θ)), where G is the shear modulus and θ is the angular coordinate.

To find the expression of C, we compare this equation with the given equation and equate the terms. This leads us to C = Ty/(2G), where Ty is the applied torque.

By further substituting the expressions for x and y in terms of the semimajor and semiminor axes, we can rewrite the equation as τxy = Ty(a²+ b²- 2Jx/R²), where J is the torsional constant and R is the radius of the cross-section.

The warping displacement θ(Φ - Φ0) can be obtained by integrating the torsion equation, which involves the shear stress τxy and the differential area of the cross-section. This displacement can be expressed as θ(Φ - Φ0) = -G∫(τxy dA).

In summary, the stress function Φ = C(x²- y²) provides the solution for torsion of the bar, where C = Ty/(2G) and the derived equation is τxy = Ty(a²+ b² - 2Jx/R²). The warping displacement can be calculated through the integration of the torsion equation.

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Answer:

Explanation:

Electromagnetic waves are formed by the interference of both electric and magnetic fields. These include: Microwaves, Radio waves, Infrared, Visible, Ultraviolet, X-ray, and gamma rays. These waves can be arranged in a specific order (called spectrum) with respect to their wavelength or frequency. The higher the wavelength, the lower the frequency. And vice versa.

These waves are transverse, and travels at the same speed (speed of light - 3.0 x \(10^{8}\) m/s).

In the given question, the answers are:

1 - Magnetic

2 - Region

3 - Refractive indices

4 - Greater

5 - Higher

6 - Wavelength

The areas of physics involved in each of the following tests of lightweight metal alloy proposed for use in sailboat hulls are as follows:
a. Testing the effects of a collision on the alloy - The area of physics involved in this test is mechanics, specifically the study of forces and motion.
b. Testing the effects of extreme heat and cold on the alloy - The area of physics involved in this test is thermodynamics, specifically the study of heat and temperature and their relation to energy and work.
c. Testing whether the alloy can affect a magnetic compass needle - The area of physics involved in this test is electromagnetism, specifically the study of the relationship between electricity and magnetism.

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Time = (distance) / (speed)

Time = (0.25 km) / (65 km/hr)

Time = 0.00385 hour

(That's 13.85 seconds.)

Better way:

Distance = 0.25 km

Distance = 250 meters

Speed = (65 km/hr) x (1000 m/km) x (1 hr/3600 sec)

Speed = 18.06 m/sec

Time = (250 m) / (18.06 m/s)

Time = 13.85 seconds  

Answer:

1498962290

Explanation:

Explanation:

satellite A, because of its closest orbit.

The multiple of Earth's radius RE that the projectile reaches depends on its initial speed and kinetic energy


(a) If the initial speed of the projectile is 0.687 of the escape speed from Earth, then its initial speed can be calculated as:

v = 0.687 * sqrt(2GM/R)

where v is the initial speed, G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.

To find the radial distance that the projectile reaches, we can use the equation for the height of a projectile:

h = R + v^2/2g

where h is the height, v is the initial speed, and g is the acceleration due to gravity.

Since we want to find the multiple of Earth's radius RE, we can express the height in terms of RE:

h/RE = (R/RE) + (v^2/2g) * (1/RE)

Substituting the value of v and simplifying, we get:

h/RE = 1.374

Therefore, the projectile reaches a height that is 1.374 times the radius of the Earth.

(b) If the initial kinetic energy of the projectile is 0.687 of the kinetic energy required to escape Earth, then its initial speed can be calculated as:

v = sqrt(2KE/m)

where KE is the initial kinetic energy and m is the mass of the projectile.

To find the radial distance that the projectile reaches, we can use the same equation as in part (a):

h = R + v^2/2g

Substituting the value of v and simplifying, we get:

h/RE = sqrt(2KE/GM) / RE

Since KE is 0.687 of the kinetic energy required to escape Earth, we can write:

KE = 0.687 * (GMm/R)

Substituting this value and simplifying, we get:

h/RE = 1.333

Therefore, the projectile reaches a height that is 1.333 times the radius of the Earth.

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Answer:

a=40Km/hr^2

Explanation: