The effect of a catalyst is to: change the stoichiometry of the reaction. lower the activation energy of a reaction whereby making it easier for the reactants to get over the energy hump. change the position of the equilibrium. increase the number of collisions between reactants. increase the temperature of the reactants whereby more products are forme

The theoretical yield of Fe is 335.1 g.

54.0 g of C is needed.

The volume of CO2 produced is 0.992 L.

198.05 g of CO2 was produced.

The percent yield of the reaction is 75.2%.

The balanced chemical equation for the reaction is:

2Fe2O3 + 3C → 4Fe + 3CO2

Using the equation, we can calculate the theoretical yield of Fe and the amount of C needed.

To calculate the theoretical yield of Fe:

Convert the given mass of Fe2O3 to moles:

480 g Fe2O3 x (1 mol Fe2O3/ 160 g Fe2O3) = 3.0 mol Fe2O3

Use stoichiometry to find the moles of Fe produced:

2 mol Fe2O3 → 4 mol Fe

3.0 mol Fe2O3 x (4 mol Fe / 2 mol Fe2O3) = 6.0 mol Fe

Convert moles of Fe to grams:

6.0 mol Fe x (55.85 g Fe / 1 mol Fe) = 335.1 g Fe

To calculate the amount of C needed:

Use stoichiometry to find the moles of C needed:

2 mol Fe2O3 → 3 mol C

3.0 mol Fe2O3 x (3 mol C / 2 mol Fe2O3) = 4.5 mol C

Convert moles of C to grams:

4.5 mol C x (12.01 g C / 1 mol C) = 54.0 g C

To find the volume of CO2 produced, we need to calculate the number of moles of CO2 produced using stoichiometry.

Use stoichiometry to find the moles of CO2 produced:

2 mol Fe2O3 → 3 mol CO2

3.0 mol Fe2O3 x (3 mol CO2 / 2 mol Fe2O3) = 4.5 mol CO2

Convert moles of CO2 to volume using the ideal gas law:

PV = nRT

V = nRT/P

V = (4.5 mol) (0.0821 L atm mol^-1 K^-1) (298 K) / (1 atm)

V = 0.992 L

To find the mass of CO2 produced:

Use the molar mass of CO2 to convert from moles to grams:

4.5 mol CO2 x (44.01 g CO2 / 1 mol CO2) = 198.05 g CO2

To calculate the percent yield of the reaction:

Use the given mass of Fe (252 g) and the theoretical yield of Fe (335.1 g) to calculate the percent yield:

Percent yield = (actual yield / theoretical yield) x 100%

Percent yield = (252 g / 335.1 g) x 100%

Percent yield = 75.2%

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Yes, the benefits of using nuclear energy outweigh the risks as  nuclear energy has help to solve electricity issues in the United states and other countries.

The benefits of nuclear energy  is that it is one of the cleanest forms of energy. Its carbon footprint is also among the smallest. It is among the solutions to the energy gap. It is crucial to how we respond to greenhouse gas emissions and climate change.

Note that A clean energy source with no emissions is nuclear. It produces energy by fission, which is the splitting of uranium atoms to release energy. With no toxic byproducts created from fossil fuels, the heat from fission is used to create steam that powers a turbine and produces electricity.

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Answer:

D) Repeating units.

Explanation:

Polymers are large macromolecules which are made up of many repeating structural units called monomers :)

Answer:

102.807 kPa

Explanation:

There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.

Using the combined ideal gas equation.

P= absolute pressure of the air inside the balloon.

V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)

n= moles of gas(air). (0.250 mol)

R= Universal gas constant ( 8.314 J / mol·K)

T= Temperature in Kelvin

T= 35 + 273.15 = 308.15 K

P= 102.807 * 10³ Pa

P= 102.807 kPa

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Answer:

Yes, they are same

Explanation:

Glycosphingolipids are a subtype of glycolipids containing the amino alcohol sphingosine. They may be considered as sphingolipids with an attached carbohydrate. Glycosphingolipids are a group of lipids (more specifically, sphingolipids) and are a part of the cell membrane.

Answer:

glycosphingolipid is an example of sphingomyelin

Answer:

To convert 675000 to scientific notation, we need to express it in the form a × 10^n, where a is a number between 1 and 10 (but not 10 itself), and n is an integer.

Starting with 675000, we can divide by 10 repeatedly until we get a number between 1 and 10.

675000 ÷ 10 = 67500 (one division by 10)

67500 ÷ 10 = 6750 (two divisions by 10)

6750 ÷ 10 = 675 (three divisions by 10)

Now we have a number between 1 and 10 (namely, 6.75), and we know that we divided by 10 three times, so the exponent is -3.

Therefore, we can express 675000 in scientific notation as:

6.75 × 10^5

(Note that we could also express it as 6.75 × 10^2 × 10^3, but this is not in standard scientific notation, which requires the coefficient to be between 1 and 10.)

Answer:

10 neutrons

Explanation:

The mass of is made up of the total protons and neutrons in an atom.

Each particle has a mass of 1 amu (atomic mass unit).

All fluorine atoms have 9 protons.

If each proton is 1 amu, the protons must contribute 9 amu to the total mass of the atom (9 x 1 amu = 9 amu).

This means the neutrons must contribute a total mass of 10 amu (18.998 amu - 9 amu = ~10 amu).

If each neutron has a mass of 1 amu, there must be 10 neutrons in a fluorine atom (10 amu / 1 amu = 10 amu).

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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The balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia is:

N2(g) + 3H2(g) ⟶ 2NH3(g)

Using the given initial moles of nitrogen and hydrogen, we can calculate the limiting reactant and the amount of ammonia produced.

Number of moles of N2 = 0.100 mol

Number of moles of H2 = 0.321 mol

To determine the limiting reactant, we need to compare the moles of each reactant to their stoichiometric ratio in the balanced equation. The stoichiometric ratio of N2 to H2 is 1:3, which means that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.

Moles of H2 required = 3 x moles of N2 = 3 x 0.100 = 0.300 mol

Since we have more moles of H2 than required (0.321 mol), H2 is in excess and N2 is the limiting reactant.

The amount of NH3 produced is determined by the moles of the limiting reactant. Since 1 mole of N2 reacts with 2 moles of NH3, the number of moles of NH3 produced is:

Moles of NH3 = 2 x moles of N2 = 2 x 0.100 = 0.200 mol

Therefore, 0.200 mol of NH3 are produced.

To calculate the moles of H2 and N2 remaining, we need to determine how much of each was not consumed in the reaction. Since N2 is the limiting reactant, all of the H2 would not be consumed, but only a portion of the N2 would react.

Moles of H2 remaining = Initial moles of H2 - Moles of H2 consumed

Moles of H2 remaining = 0.321 mol - (3 x moles of N2 consumed)

Moles of H2 remaining = 0.321 mol - (3 x 0.100 mol)

Moles of H2 remaining = 0.021 mol

Therefore, 0.021 mol of H2 remains.

Moles of N2 remaining = Initial moles of N2 - Moles of N2 consumed

Moles of N2 remaining = 0.100 mol - moles of N2 consumed

Moles of N2 remaining = 0.100 mol - 0.100 mol

Moles of N2 remaining = 0 mol

Therefore, all of the N2 is consumed and 0 moles of N2 remains.

In summary:

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Proper cleaning and sanitizing practices are critical in preventing bacteria that can cause foodborne illness.

Benefits of sanitizing:

Eliminates Pathogens.

Sanitizing Improves Home Odor.

Reduces Respiratory issues.

Decreases Allergy Flare-Ups.

Easy to Use.

Reduces Stress.

Helps the Immune System.

When and how to clean surfaces in your home.

Important to clean and sanitize kitchen premises

Cleaning your kitchen premises and equipment ensures that clean food preparation is carried out in order to improve kitchen efficiency and reduce environmental impacts.

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Answer:

dog 2 because it is running 1m faster a second than dog 1. Dog 2 can run 1 meter farther in a second than the other dog.

Hamilton explained the choice on the On Purpose show, admitting that the pair's work connection from karting to F1 had placed a burden on an otherwise strong friendship.

Lewis Hamilton now has a close connection with his father Anthony, but this was not always the case during his Formula One tenure. Anthony had a significant influence on his son's career, notably working multiple jobs to finance Hamilton's early foray into racing until he was signed by McLaren at the age of 11.

However, his earnings outside of Formula One rose from $8 million in 2021 to $12 million in 2022. Hamilton was the highest-paid Formula One racer. He has profitable agreements with companies such as Monster energy drinks.

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1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer

Explanations:

The formula for calculating the percent impurity of oxygen is expressed as:

Given the following parameter

Mass of water = 36.8 grams

Determine the moles of water

According to the ideal gas equation, PV = nRT

Determine the mass of oxygen

Mass of O2 = moles * molar mass

Mass of O2 = 2.857 * 16

Mass of O2 =

Refer to the attachment

Answer:0.1g

Explanation:

Answer: The smallest scale division is a tenth of a centimeter or 1 mm.

Explanation: I got this from a website but I hope it helps!

Answer:

A: arrive early or on time

Explanation:

The empirical formula is KCO2

Explanation:

As with all these problems, we assume a

100

⋅

g

mass of unknown compound, and then we work out the molar quantity:

Moles of potassium

=

47.0

⋅

g

39.10

⋅

g

⋅

m

o

l

−

1

=

1.20

⋅

m

o

l

Moles of carbon

=

14.5

⋅

g

12.011

⋅

g

⋅

m

o

l

−

1

=

1.21

⋅

m

o

l

Moles of oxygen

=

38.5

⋅

g

16.0

⋅

g

⋅

m

o

l

−

1

=

2.41

⋅

m

o

l

We divide thru by the smallest molar quantity to give the empirical formula:

K

C

O

2

.

Now the molecular formula is always a whole number of the empirical formula:

i.e.

molecular formula

=

n

×

empirical formula

And thus with the molecular mass, we can solve for

n

.

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

39.1

+

12.011

+

2

×

16.00

)

⋅

g

⋅

m

o

l

−

1

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

83.1

)

⋅

g

⋅

m

o

l

−

1

Clearly,

n

=

2

, and the

molecular formula

=

K

2

C

2

O

4

The compound is LIKELY the potassium salt of oxalic acid,

K

+

−

O

(

O

=

)

C

−

C

(

=

O

)

O

−

K

+

, i.e.

potassium oxalate.

Answer linkExplanation:

As with all these problems, we assume a

100

⋅

g

mass of unknown compound, and then we work out the molar quantity:

Moles of potassium

=

47.0

⋅

g

39.10

⋅

g

⋅

m

o

l

−

1

=

1.20

⋅

m

o

l

Moles of carbon

=

14.5

⋅

g

12.011

⋅

g

⋅

m

o

l

−

1

=

1.21

⋅

m

o

l

Moles of oxygen

=

38.5

⋅

g

16.0

⋅

g

⋅

m

o

l

−

1

=

2.41

⋅

m

o

l

We divide thru by the smallest molar quantity to give the empirical formula:

K

C

O

2

.

Now the molecular formula is always a whole number of the empirical formula:

i.e.

molecular formula

=

n

×

empirical formula

And thus with the molecular mass, we can solve for

n

.

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

39.1

+

12.011

+

2

×

16.00

)

⋅

g

⋅

m

o

l

−

1

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

83.1

)

⋅

g

⋅

m

o

l

−

1

Clearly,

n

=

2

, and the

molecular formula

=

K

2

C

2

O

4

The compound is LIKELY the potassium salt of oxalic acid,

K

+

−

O

(

O

=

)

C

−

C

(

=

O

)

O

−

K

+

, i.e.

potassium oxalate.

Answer

A) atom

Explanation

An atom is the smallest unit of a pure substance or element that can exist and still retain the properties of the original substance or element.

Therefore, a/an atom is the smallest unit of matter that has the characteristics of a chemical element.

The correct answer is option A) atom

Answer:

1.5×1024 molecules

Explanation:

Answer:

Explanation:

abything that is both mass and volume

Answer:

anything that has both mass and volume

Answer:

Given the reaction:

Fe+H

2

O→Fe

3

O

4

+H

2

If the number of electrons lost or gained during the changes is x. Then, the value of x is 8.

The balanced chemical equation is as follows:

3Fe+4H

2

O→Fe

3

O

4

+4H

2

The oxidation number of hydrogen changes from +1 (in water) to 0 (in hydrogen molecule).

Thus, net change in the oxidation number of hydrogen per atom is 1.

There are 8 H atoms.

Hence, the total change in the oxidation number of 8 hydrogen atoms is 8.

Hence, 8 electrons are involved in the redox reaction.

Hence, x=8.

The  third quantum number of a 2p\(^{3}\) electron in phosphorus is ml= -1.

Quantum numbers are the set of numbers describe the position of electron and energy of electron in an atom.there are four types of quantum numbers.

Electronic configuration of phosphorus is 1s\(^{2}\) 2s\(^{2}\) 2p\(^{6}\) 3s\(^{2}\) 3p\(^{6}\)

Quantum numbers for 2p\(^{3}\)

1) Principal quantum number (n) = 2

2) Azimuthal quantum number (l) = (n-1) = 1

3) magnetic quantum number (ml) = -l to +l = -1 , 0 , +1

form the given option , ml = -1  for n= 2 , l = 1

Thus,The third quantum number of a 2p\(^{3}\) electron in phosphorus is m= -1

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Answer: A. m/= -1

Explanation:

Answer:

For a: The IUPAC name of the compound is N-ethylethaneamide.

For b: The IUPAC name of the compound is N,N-diethylmethaneamide.

For c: The IUPAC name of the compound is ethyl pentanoate

Explanation:

To name a compound, first look for the longest possible carbon chain.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is \(R-CO-NH_2\), where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is \(R-CO-NH_2\), where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

Esters are a kind of organic molecules having functional groups, \(R-COO-R'\) where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

Answer

b) 1 mole of atoms

Explanation

Avogadro;s Constant says a mole of any substance contains the same number of atoms (6.022 × 10²³).

Therefore, 1 mole of atoms is correct.

The molar concentration of the salt is  0.600 M. Option B

We know that the term molar concentration has to do with the number of moles of the salt that is present in one liter of the solution. We have been given the mass of the salt that is formed, we need to obtain the number of moles of the salt that has been formed and use the volume of the solution that have been given in the question to find the molar concentration of the salt.

Mass of the salt = 8.24 g

Molar mass of the salt = 58.5 g/mol

Number of moles of the salt = mass/molar mass

=  8.24 g/ 58.5 g/mol

= 0.14 moles

Volume of the solution = 235.0 mL or 0.235 L

Molar concentration =  0.14 moles/ 0.235 L

= 0.595 M or  0.600 M

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Answer:

See Explanation

Explanation:

Both oxygen and dinitrogen (1) oxide are known to rekindle a glowing splint. However, oxygen is an odorless gas while dinitrogen (1) oxide has a faint smell and has an effect on the central nervous system.

Also, the combustion of dinitrogen (1) oxide produces brown fumes of nitrogen IV oxide.

Finally, when dinitrogen (1) oxide and oxgen are both heated with copper, residual nitrogen gas is left with dinitrogen (1) oxide while no residual gas is left with oxygen.

The redox reactions is balanced as by adding coefficients as follows:2 H+ +ClO²⁻+I⁻⟶2 Cl⁻+H₂O+I₂.

Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.

While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.These too are balanced by adding coefficients.

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