the electrical force between charges depends only on the charges' magnitude and separation distance. magnitude. separation distance. none of the above choices are correct.

Answers

Answer 1

The electrical force between charges depends only on the charge magnitude and separation distance. Option a is correct.

The magnitude of the electrical force is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the separation distance between them, as described by Coulomb's law.

This means that the force increases as the charges get larger and decreases as the separation distance between them gets larger. This fundamental relationship is essential to understanding many phenomena in electromagnetism, from the behavior of simple electric circuits to the properties of complex electromagnetic fields. Option a is correct.

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Related Questions

a truck with a mass of 2400 travels at a constant speed of 90 km/hr. what average force would be required to stop the truck in 8 seconds?

Answers

We need a force of  7500 in the opposite direction of the motion of the truck.

According to the first equation of motion

V= U  + a t

t = time taken

V= final velocity =0 (as truck will come to rest)

U = initial velocity = 90 km/hr = 25 m/sec

a = acceleration

a=  V- U / t

a =  0- 25 / 8

a =  - 3.125 m/\(sec^{2}\)

According newtons second law

F= m a

F =  2400  (- 3.125 m/\(sec^{2}\))

F=  - 7500 Newton

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A man running at 5 M/S increases his velocity to 10 M/S in 2 Seconds. What was his acceleration?​

Answers

We can use the equation:
V=vi+at
Where
V is finial velocity
vi is initial velocity
a is acceleration
t is time
10=5+a2
5=2a
a=5/2 or 2.5
The man accelerated at 2.5 meters per second

Help ASAP I’ll give u branliest!! This isn’t really hard

Help ASAP Ill give u branliest!! This isnt really hard

Answers

Answer:

I'm pretty sure it's mist, drizzle, droplet, and then rain.

mist, drizzle, droplet, rain

A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is
conserved within the system, what is the speed of the ball the instant
before it strikes the ground?

Answers

Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

Suppose than mutation affects the electron transport chain Complex I from functioning. Assume that the rest of the complexes of the electron transport chain are function. Below are possible avenues of ATP production from metabolism. For each one, choose: YES if ATP can still be produced in a person with this deficiency. choose NO if ATP cannot be produced in a person with this deficiency. ATP normally produced from: FADH 2 produced in the citric acid cycle substrate level phosphorylation in glycolysis 1. No NADH produced in the 2. Yes citric acid cycle NADH produced from the conversion of pyruvate to acetyl CoA

Answers

In a person with a mutation affecting Complex I of the electron transport chain, ATP can still be produced from FADH2 generated in the citric acid cycle, but not from NADH produced in the conversion of pyruvate to acetyl CoA.

Complex I is responsible for the transfer of electrons from NADH to the electron transport chain. However, if Complex I is affected by a mutation and cannot function properly, NADH cannot be utilized in the electron transport chain to generate ATP.

On the other hand, FADH2, which is produced in the citric acid cycle, bypasses Complex I and directly enters the electron transport chain at Complex II. Therefore, even with a malfunctioning Complex I, ATP can still be produced from the electrons derived from FADH2. This pathway allows for some ATP production, although it is generally less efficient compared to the NADH pathway.

In glycolysis, NADH is produced during the conversion of pyruvate to acetyl CoA. However, since Complex I is affected by the mutation, NADH cannot be used by the electron transport chain to produce ATP. As a result, ATP production through substrate-level phosphorylation in glycolysis, which relies on NADH, is compromised.

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The position vs. time graph shows how far away I am from the table while cooking breakfast. Which parts of the journey show where I am:

The position vs. time graph shows how far away I am from the table while cooking breakfast. Which parts

Answers

The velocity of an object is represented by the slope of a location graph. Thus, the slope's value at a given instant corresponds to the object's velocity at that precise moment.

What does a graph of position vs time reveal?

Position in relation to the starting point is plotted on the y-axis of a position vs. time graph, while time is plotted on the x-axis to represent motion. The gradient of a position vs. time graph serves as a representation of the velocity. The slope gets steeper as the motion changes more quickly.

Where is the time graph located?

The Position Time Graph: What Is It?

The Position-Time graph is the graph on which the time t and the instantaneous position x of a particle are shown.

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What happens to potential energy as the car goes up the hill?

Answers

The potential energy will increase
As a car goes up a hill, gravitational potential energy increases and kinetic energy decreases. I hope this helps!

Define the linear transformation T: Rn → Rm by T(v) = Av. Find the dimensions of Rn and Rm. A = 0 5 −1 4 1 −2 1 1 1 3 0 0 dimension of Rn dimension of Rm

Answers

The linear transformation T: \(R^n\) → \(R^m\) with matrix A maps a vector of dimension n to a vector of dimension m, where the dimensions of R^n and R^m correspond to the input and output dimensions, respectively.

The matrix A is a 4x3 matrix, as it has 4 rows and 3 columns. Therefore, the transformation T: \(R^3\) → \(R^4\) takes a 3-dimensional vector as input and returns a 4-dimensional vector as output.

So the dimension of Rn is 3 (since Rn is the domain of T and T takes vectors in R^3) and the dimension of Rm is 4 (since Rm is the range of T and T returns vectors in \(R^4\)).

The linear transformation T: \(R^n\) → \(R^m\), defined by T(v) = Av where A is an mxn matrix, maps a vector of dimension n to a vector of dimension m. In this case, the matrix A is a 4x3 matrix, meaning that the transformation T maps a 3-dimensional vector to a 4-dimensional vector.

Therefore, the dimension of \(R^n\) is 3, as it represents the domain of T and T takes vectors of dimension n. Similarly, the dimension of \(R^m\) is 4, as it represents the range of T and T returns vectors of dimension m.

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3 An un calibrated mercury in glass thermometer immersed in melting ice. The length of the mercury thread is 25 mm when the thermometer immersed in steam from pure water boiling under a pressure of 1 atmosphere the length of the thread is 200 mm what is the temperature in degree centigrade when the length of the thread is 95mm.​

Answers

Answer:

25 mm = 0 deg C

200 mm = 100 deg C

200 - 25 = 175 = change in thread per 100 deg C

95 - 25 = 70 mm - change in thread from 0 deg C

70 / 175 * 100 = 40 deg C    final temperature at 95 mm

determine the magnetic flux through the center of a solenoid having a radius r = 2.10 cm. the magnetic field within the solenoid is 0.52 t.

Answers

In conclusion, the magnetic flux through the center of a solenoid with a radius of 2.10 cm and a magnetic field of 0.52 T is 0.00072 Wb.

To determine the magnetic flux through the center of a solenoid with a radius of 2.10 cm and a magnetic field of 0.52 T, we need to use the formula for magnetic flux, which is Φ = B × A, where B is the magnetic field and A is the area of the surface perpendicular to the field.
Since the solenoid has a cylindrical shape, we can use the formula for the area of a circle, which is A = πr^2, where r is the radius of the circle. Therefore, the area of the solenoid is A = π(0.021)^2 = 0.001385 m^2.
Substituting the values of B and A into the formula for magnetic flux, we get Φ = (0.52 T) × (0.001385 m^2) = 0.00072 Wb.
Therefore, the magnetic flux through the center of the solenoid is 0.00072 Wb.

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10) A 57-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37° above the horizontal. If the tension in the rope is 142 N, how much work is done on the crate to move it 6.1 m?

Answers

F=m*a

T = 142N

Work = Force x distance

distance = 6.1 M

Force = 142 x cos 37 = 113.4 N

W= 113.4N x 6.1M = 691.78 J

10) A 57-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an

what type would never freeze

Answers

Answer:

Ummmm Human's I don't understand your answer

Explanation:

Have a Nice Day

What do you mean by that

which statement is the most correct statement about a gas
A gas takes the shape of it's container
A gas is not affected by changes in pressure
A gas has very little thermal energy
A gas holds it's shape ​

Answers

Gasses take the shape of their container.

A gas fills a container which takes both the shape and the volume of that container.

Answer:

A gas takes the shape of its container

Calculate the kinetic energy of a 10 kg object moving with a speed of 5 m/s.

Answers

Answer: the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

Explanation:

if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

Answer:

The Kinetic energy of a 10Kg object moving with a speed of 5m/s is 125 Joules

Explanation:

Kinetic energy refers to the energy of a moving object. The formula for kinetic energy is given by

KE=(1/2)\(mv^{2}\).......(i)

, where, m⇒mass of object

             v⇒velocity

and the unit is given by Joules.

Now, as we are given in the question,

mass, m=10kg

velocity, v= 5m/s

Substituting these values in the equation (i), we get,

KE=(1/2)x(10Kg)x(5m/s)^2,

we have,

KE=125 J

Therefore, the kinetic energy of a 10 kg object moving with a speed of 5m/s is 125 Joules.

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Physics

1. Compute the resistance of a hardened copper rod 2 meters long and 8 mm

Answers

The resistance of the hardened copper rod is approximately 0.677 ohms.

To compute the resistance of a hardened copper rod, we need to use the formula for resistance:

Resistance (R) = Resistivity (ρ) x Length (L) / Cross-sectional Area (A)

Convert length to meters:

The length of the rod is given as 2 meters, so no conversion is required.

Convert diameter to meters and calculate the cross-sectional area:

The diameter of the rod is given as 8 mm. To calculate the cross-sectional area, we need to convert the diameter to meters.

Diameter (d) = 8 mm = 8 x 10^(-3) meters (1 mm = 10^(-3) meters)

To calculate the cross-sectional area, we use the formula:

Area (A) = π x (diameter/2)^2

Plugging in the values:

A = π x (8 x 10^(-3) / 2)^2 = π x (4 x 10^(-3))^2 = π x 16 x 10^(-6) = 50.27 x 10^(-6) m^2

Determine the resistivity of copper:

The resistivity (ρ) of copper is a material property and is typically given in ohm-meters (Ωm). The resistivity of copper is approximately 1.7 x 10^(-8) Ωm.

Calculate the resistance:

Using the formula for resistance, we can substitute the values:

R = (1.7 x 10^(-8) Ωm) x (2 m) / (50.27 x 10^(-6) m^2)

Simplifying the expression:

R = 0.677 Ω

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A car is launched by a spring and goes to the top of a loop. Fill in the energy bar chart by drawing a vertical bar(s) in the correct position (both Initial & Final conditions).

Answers

Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

         

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

When activated, an emergency locator transmitter (ELT) transmits on
A- 118.0 and 118.8 MHz
B- 121.5 and 406 MHz
C- 123.0 and 119.0 MHz

Answers

When activated, an emergency locator transmitter (ELT) transmits on 121.5 and 406 MHz.

121.5 MHz was the international standard emergency frequency for aviation until 2009, when its use was discontinued due to its high false alarm rate. However, ELTs are still required to transmit on this frequency as a backup in case the primary frequency, 406 MHz, is not monitored by search and rescue authorities.

406 MHz is the primary frequency used for satellite-based search and rescue operations. When an ELT is activated, it sends a distress signal on this frequency, which is received by satellites in orbit around the Earth. The satellites relay the signal to a ground station, which then alerts search and rescue authorities to the distress signal and the location of the ELT.

In summary, an emergency locator transmitter (ELT) transmits on both 121.5 MHz and 406 MHz when activated, with 406 MHz being the primary frequency used for satellite-based search and rescue operations and 121.5 MHz used as a backup.

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This is the question

This is the question

Answers

Answer:

B

Explanation:

a ray of light originates inside a tank of unknown liquid. the ray strikes the liquid/air surface and refracts as a result. the index of refraction of the unknown liquid is 1.71 . the angle of incidence of the ray in the liquid with respect to the normal is 27.0 degrees. what is the angle of the internal reflection?

Answers

Answer:

Explanation: 20 thousand

The angle of internal reflection is 43.21 degrees.

When a light ray travels from one medium to another, it bends or refracts. The amount of bending depends on the indices of refraction of the two media and the angle of incidence of the light ray.

The angle of incidence of the light ray in the liquid is 27.0 degrees. Let us call this angle θ1. The index of refraction of the liquid is 1.71. Let us call this index n.

The angle of refraction of the light ray in the air can be found using Snell's law, which states that n1sinθ1 = n2sinθ2, where n1 and n2 are the indices of refraction of the two media, and θ2 is the angle of refraction. Since the air has an index of refraction of approximately 1, we can write the equation as sinθ1 = n sinθ2.

Solving for θ2, we get θ2 = arcsin(sinθ1/n) = arcsin(sin(27.0)/1.71) = 14.36 degrees.

The angle of internal reflection can be found using the equation θr = 90 - θ2, where θr is the angle of internal reflection. Plugging in the value we found for θ2, we get θr = 90 - 14.36 = 75.64 degrees.

However, this is the angle of reflection from the liquid/air surface. To find the angle of internal reflection, we need to consider the reflection that occurs when the light ray exits the liquid and enters the air again. The angle of reflection in this case will be the same as the angle of incidence, which is 27.0 degrees.

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Question. 1 How much heat is necessary to warm 500g of water from 20°C to 65°C?​

Answers

Answer:

The heat necessary to warm 500g of water from 20°C to 65°C is 37,620 J.

Explanation:

GIVEN: m = 500 gm, T₂ = 65°C AND T₁  = 20°C, we know that c (specific heat capacity) = 4180

TO FIND: The heat necessary to warm 500g of water from 20°C to 65°C.

SOLUTION:

By using the heat equation,

              Q=m c ΔT  

             ΔT = T₂ - T1

             ΔT = 65 - 20 = 45°C

In this case,

Q = 0.2 × 4180 × 45 = 37,620 J

what is the change in the potential energy of a single electron as it moves through the light bulb

Answers

The change in the potential energy of a single electron as it moves through a light bulb will depend on the specific details of the bulb's design and the path taken by the electron.

In general, as an electron moves through a circuit, it can experience changes in potential energy due to interactions with electric fields created by charged particles in the circuit. In the case of a light bulb, the electron will interact with the filament, which is typically a coiled wire made of a material such as tungsten. As the electron moves through the filament, it will collide with atoms in the wire, transferring some of its kinetic energy to the atoms and causing them to vibrate more rapidly. This increased vibration corresponds to an increase in the temperature of the filament and the emission of light.

The exact amount of potential energy gained or lost by the electron will depend on the specifics of the circuit, including the voltage applied to the bulb and the resistance of the filament. In general, however, the potential energy change experienced by a single electron will be relatively small, as the energy transferred to the filament is distributed over a large number of electrons and atoms in the wire.

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what is net netforce?

Answers

In mechanics, the net force is the vector sum of forces acting on a particular or object

Sound waves travel through steel railroad rails a distance of 2350 m in 0.383 s. What is the speed of sound in the rails?
(units = m/s)

Answers

Answer:

Speed of sound ways in railroad = 6,135.8 m/s

Explanation:

Given:

Distance cover by sound wave = 2,350 meter

Time taken by sound wave to cover distance = 0.383 seconds

Find:

Speed of sound ways in railroad

Computation:

Speed = Distance / Time

Speed of sound ways in railroad = Distance cover by sound wave / Time taken by sound wave to cover distance

Speed of sound ways in railroad = 2,350 / 0.383

Speed of sound ways in railroad = 6,135.77

Speed of sound ways in railroad = 6,135.8 m/s

Which pair of waves could overlap to produce a wave with a higher amplitude
through interference?
A. Two waves of the same amplitude with crests that overlap troughs
B. Two waves of the same amplitude with crests that are perfectly
aligned
C. Two waves of different amplitudes that are also different types of
waves
D. Two waves of different amplitudes with crests that overlap
troughs

Answers

Answer: The Answer is B (Sorry if this is late)

Explanation:

I couldn’t find the answer to the question myself then found you, with no answer. So I guessed and failed my third question of the quiz, you were worth the sacrifice though ✨

The pair of waves could overlap to produce a wave with a higher amplitude through interference is that two waves of the same amplitude with crests that are perfectly aligned. Hence, option B is correct.

What is Amplitude?

The maximum deflection or distance made by a point on even a vibrating object or wave relative to its equilibrium location is known as the amplitude in physics. It is equivalent to the length of a vibration path divided in half.

A pendulum's amplitude is therefore equal to the distance that the bob travels when swinging through one side to another. Vibrating sources produce waves, whose amplitude is inversely proportional to the source's amplitude.

The largest deviation of any place on the string out of its place when the line is at rest is used to determine the amplitude of a wave propagation, like the wave on such a plucked string.

Therefore, it concludes that option B is correct.

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Describe the acceleration that might occur if the vector representing the man's push were greater in magnitude than the vector representing the normal force of the wall.

Answers

Explanation:

The acceleration of an object depends directly up on the net force acting on the object and inversely upon the mass of the object. As the force acting upon an object is increased; According to Newton, an object will only accelerate if there is a net or unbalanced force acting on it, therefore the acceleration is equal to force divided by the mass

a=F/m

A speeding train slams on the brakes when it sees a car is on the tracks in front of it. It takes the train 25 seconds for it to go from an initial speed of 75 m/s to come to a complete stop. What is the train’s acceleration?

Answers

Answer:

Acceleration of the train is -3 m/s²

Explanation:

Since it stops,

final velocity (v) = 0 m/s

time (t) = 25 seconds

initial velocity(u) = 75 m/s

Now,

accelereation = (v-u)/t

or, a = (0-75)/25

or, a = -75/25

so, a = -3 m/s²

The use of punishers is so common that ______ concluded that "The world runs on fear." a. Jack Nicholson b. Jack Robinson c. Jack Michaels d. Jack Sprat.

Answers

The use of punishers is so common that Jack Nicholson concluded that "The world runs on fear." The correct answer is a. Jack Nicholson.

The use of punishers is so common that Jack Nicholson concluded that "The world runs on fear." This statement suggests that many individuals and institutions rely on fear-based tactics to control behavior or achieve desired outcomes. However, it is important to consider the long-term consequences of such approaches, as they may lead to negative emotions and psychological effects, as well as decreased motivation and engagement. It is important to focus on creating positive emotions and empowering content loaded with rewards and reinforcements, rather than relying solely on punishment and fear.

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two conducting spheres have radii of r1 and r2, with r1 greater than r2. if they are far apart the capacitance is proportional to:

Answers

"Two conducting spheres have radii of r1 and r2, with r1 greater than r2. If they are far apart the capacitance is proportional to: 1/r1 - 1/r2

The capacitance of two conducting spheres with radii r1 and r2, where r1 is greater than r2, and they are far apart is proportional to the difference in inverse radii. This can be written as:

C = k (A / d)

where C is the capacitance, k is the proportionality constant, A is the surface area, and d is the distance between the two spheres.

The surface area of a sphere is proportional to r^2,

so:C ∝ A = k (r1^2 + r2^2)

The inverse of capacitance is proportional to the difference in inverse radii,

so:1/C ∝ 1/(r1 - r2)

1/C = k' (1/r1 - 1/r2)

where k' is another proportionality constant, which combines with k to give the final constant of proportionality.

Therefore, the capacitance of two conducting spheres with radii r1 and r2, where r1 is greater than r2, and they are far apart is proportional to: 1/r1 - 1/r2.

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An electric iron is connected to the mains power supply of 220 V. When the electric iron is

adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a

power of 840 W. Calculate the current and resistance in each case.​

Answers

Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

The loop in the figure is being pushed at 50 m/s into a uniform 0. 20-T magnetic field that is directed out of the page. The resistance of the loop is 0. 40?.

As the loop is entering the magnetic field its induced current is 1. 3 A, the direction of the current in the loop is clockwise.

What is the induced current after the entire loop has entered the uniform magentic field?

Answers

The induced current after the entire loop has entered the uniform magnetic field is 6.5 A.

In the problem statement given, a loop is being pushed at a uniform 0.2-T magnetic field, which is directed out of the page. The resistance of the loop is 0.4Ω. When the loop is entering the magnetic field, its induced current is 1.3 A and the direction of the current is clockwise. The question is asking for the induced current after the entire loop has entered the uniform magnetic field.The formula to find the induced current is given by Faraday's Law of Electromagnetic Induction,i = ε/R where ε is the induced emf, R is the resistance of the loop, and i is the induced current.

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