The electron configuration for the Magnesium ION is the same as the configuration for which noble gas?

Dilutions:

When a solution is diluted, the total number of moles of solute (n), does not change. Only the totel solution volume changes. As n=cV (molarity formula, where n = moles, c = concentration, V = volume), then the value of cV is a constant when diluting solutions. This can be expressed by the ratio:

c₁V₁ = c₂V₂, where subscripts 1 and 2 represent the concentrated and dilute solutions.

To prepare an 2.00 L aqueous solution of HCl (hydrochloric acid) of concentration 6.00 M from 12.1 M, we can use the dilution ratio:

C₁V₁ = C₂V₂.

Hence: 12.1×V₁ = 6.00×2.00

V₁ = 0.9917 L

therefore, the initial volume, the volume of HCl we start with, is 0.9917 L, or 991.7 mL

Answer: 4

Explanation:

When adding or subtracting numbers, you round your answer to the least amount of decimal places present in any of the numbers you add.

When multiplying or dividing numbers, you round your answer to the least amount of significant figures present in any of the number you multiply or divide.

Since we are adding 41.34, 1.561, and 0.1334, we will round our answer to 2 decimal places since that is the least amount present.

After rounding, our answer is 43.03, which is 4 significant figures.

Answer:

4

Explanation:

I got it right on the test.

Answer: Answer: How strong is the storm?

Explanation:

This alludes to the fact that the potential for ionization or the strength of the storm (being the strength of the base or acid) is not stated though is the determining factor if a base/acid will dissociate partially or completely. Reminder: weak acids and bases dissociate only partially while strong acids and bases dissociate completely, so the number of drowning Herberts will depend on the unspecified strength of the acid/base.

source: tite, basta may sagot

Answer:

734.0 grams

Explanation:

Because 16.0 and 855 mL it is 734.0 grams :) hope it helps

Neoclassical economics focuses on supply and demand as the driving forces behind the production and consumption of goods and services.

It should be noted that Neoclassical economics emphasizes the choices of consumers. Thus, in neoclassical economics, the value of products and services is above the costs of production.

Hubbert's peak theory states that the rise, peak, and decline of fossil fuel production with revolutions in new technology will be longer than originally predicted before the oil reserves run out

The tragedy of the commons is an economic problem of overconsumptio, and depletion of a common pool resource

One thing that puts tremendous pressure on our biodiversity and natural resources is an ever-growing demand for resources by a growing population.

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Answer:

1. Neoclassical economics focuses on supply and demand as the driving forces behind the production and consumption of goods and services.

2. It should be noted that Neoclassical economics emphasizes the choices of consumers. Thus, in neoclassical economics, the value of products and services is above the costs of production.

3. Hubbert's peak theory states that the rise, peak, and decline of fossil fuel production with revolutions in new technology will be longer than originally predicted before the oil reserves run out

4. The tragedy of the commons is an economic problem of overconsumptio, and depletion of a common pool resource

5. One thing that puts tremendous pressure on our biodiversity and natural resources is an ever-growing demand for resources by a growing population.

The spontaneity of a reaction is determined by the Gibbs free energy change (∆G), which is a measure of the system's ability to do work.

The equation that links ∆G, ∆H, and ∆S is: ∆G = ∆H - T∆S, where T is the temperature in Kelvin and ∆H and ∆S are the enthalpy and entropy changes, respectively. The signs of ∆H and ∆S determine whether the reaction is exothermic or endothermic and whether it is entropy-driven or enthalpy-driven, respectively.

If ∆G is negative, the reaction is spontaneous, meaning it occurs without the input of energy.The given reaction has a ∆H of 23.25 kJ and a ∆S of 161.26 J/mol∙K.

First, we need to convert the units of ∆S from J/mol∙K to kJ/mol∙K by dividing by 1000.∆S = 161.26 J/mol∙K ÷ 1000 = 0.16126 kJ/mol∙K Substitute the values into the equation to determine the spontaneity of the reaction:

∆G = ∆H - T∆S∆G = (23.25 kJ) - (298 K) x (0.16126 kJ/mol∙K)∆G = 23.25 kJ - 48.02 kJ∆G = -24.77 kJ Since ∆G is negative, the reaction is spontaneous.

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Answer:

Explanation:

H m sarav

The system must be structured to draw more energy to work.

Moreover, From second law of thermodynamics, The entropy is a thermodynamic property which represents unavailability of the internal energy of the system for conversion into mechanical energy. So, lower entropy is desirable to extract more internal energy as work done.

Entropy is parameter of orderliness. High entropy represents more chaos and low entropy represents more ordered state. So, ​​​​​​The system is orderly.

Structured system is more ordered than uniform system. Thus, structured system has lower entropy than uniform system. So, The system must be structured to draw more energy to work.

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The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.

NH3 can be calculated using the equation:

ΔG = ΔG° + RT ln(Q)

where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:

Q = (P(NH3))^2 / (P(N2) * P(H2)^3)

Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.

The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.

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The delocalization of electrons in the benzene ring leads to the absence of directionality for a substituent group. The substituent group is attached to the entire benzene ring, rather than a specific carbon atom, due to the delocalized nature of the pi bonds.

Benzene is a cyclic compound consisting of six carbon atoms and six hydrogen atoms. It has a planar structure, meaning that all the carbon atoms lie in the same plane. The reason there is no directionality for a substituent group coming off of benzene is because of the delocalization of electrons in the benzene ring.

In benzene, the electrons in the pi bonds are not localized between any two carbon atoms, but instead, they are delocalized over the entire ring. This delocalization creates a stable aromatic system. Each carbon atom in the benzene ring is sp2 hybridized, which allows for the formation of pi bonds above and below the plane of the ring.

When a substituent group is attached to a carbon atom in the benzene ring, the electrons in the pi bond are still delocalized. This means that the substituent group is not attached to a specific carbon atom, but rather, it is attached to the entire benzene ring. As a result, the substituent group does not have a specific directionality.

For example, if a methyl group (CH3) is attached to the benzene ring, it can be located in any of the six possible positions around the ring. The position of the methyl group does not affect the stability of the benzene ring or the delocalization of the electrons.

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Answer:the element is potassium

the proton and electron is 19 and the nuetron is 19

Explanation:

Answer:

The atomic number gives the number of protons 19

p = 19

The atomic mass is the sum of the protons and neutrons

p+n = 39 p = 19

Put p into the equation and solve for n the neutrons

19+n = 39

Subtract 19 from both sides

19-19+n = 39-19

n = 20

The number of electons equal the number of protons in a neutral atom. The positive charge equal to the negative charge. The negative charge is the number of electons. This ion has a charge of +1. So solve for the negative charge.

-19+1 = -18

The negative charge is -18 so

e = 18

Explanation:

Please find the Measures of Center and construct a histogram AND find the 5-number summary and construct a box-n-whisker plot for the numbers below.

Explanation:

Given :

Amount of solute - sucrose (C12H22O11) = 41 g

Amount of solvent -soda  = 355-mL

Molarity of the solution with respect to sucrose= ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

               Molarity =  

Amount of solvent is given in mL, let’s convert to L :

               1 L = 1000 mL

Therefore, 355 mL in L will be :

               = 0.355 L

We have the amount of solute in g, let’s calculate the number of moles first :

       Number of moles (n) =  

Molar mass of C12H22O11 = 342.29 g/mol.

Therefore, n =  

               = 0.119 moles.

Answer:

law of inertia

Explanation:

Answer: The \(K_{sp}\) of \(AgCrO_{4}\) is \(1.1 \times 10^{-12}\).

Explanation:

Given: \([Ag^{+}] = 1.3 \times 10^{-4} M\)

The reaction equation will be written as follows.

\(Ag_{2}CrO_{4} \rightleftharpoons 2Ag^{+} + CrO^{2-}_{4}\)

This shows that the concentration of \(CrO^{2-}_{4}\) is half the concentration of \(Ag^{+}\) ion. So,

\([CrO^{2-}_{4}] = \frac{1.3 \times 10^{-4}}{2}\\= 0.65 \times 10^{-4} M\)

The expression for \(K_{sp}\) of this reaction is as follows.

\(K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]\)

Substitute values into the above expression as follows.

\(K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]\\= (1.3 \times 10^{-4})^{2} \times 0.65 \times 10^{-4}\\= 1.1 \times 10^{-12}\)

Thus, we can conclude that the \(K_{sp}\) of \(AgCrO_{4}\) is \(1.1 \times 10^{-12}\).

Answer:

about 0.2 mL

Explanation:

To find the volume, you take the mass and divide it by the density

The new temperature (t2) required to increase the number of vacancies by 10 times from t1 is approximately 1609.1 Kelvin.

To increase the number of vacancies by 10 times from the starting temperature (t1) of 800°C, we need to calculate the new temperature (t2) required to achieve this.

Step 1: Convert the starting temperature (t1) from Celsius to Kelvin.
To convert from Celsius to Kelvin, we add 273 to the Celsius temperature. So, t1 in Kelvin = 800 + 273 = 1073 K.

Step 2: Use the formula for the relationship between the number of vacancies and temperature.
The number of vacancies (Nv) is given by the equation Nv = N0 * exp(-Q/RT), where N0 is the initial number of vacancies, Q is the activation energy (4.0 eV/atom), R is the gas constant (8.314 J/(mol*K)), and T is the temperature in Kelvin.

Step 3: Calculate the ratio of the final number of vacancies (Nv2) to the initial number of vacancies (Nv1).
Since we want to increase the number of vacancies by 10 times, the ratio Nv2/Nv1 = 10.

Step 4: Substitute the values into the equation and solve for the new temperature (t2).
10 = exp(-Q/(R*t2)) / exp(-Q/(R*t1))

Simplifying the equation, we have:
10 = exp((Q/R)*(1/t1 - 1/t2))

Taking the natural logarithm of both sides of the equation, we get:
ln(10) = (Q/R)*(1/t1 - 1/t2)

Rearranging the equation to solve for t2, we have:
t2 = 1 / ((1/t1) - (R/Q) * ln(10))

Substituting the values, t2 = 1 / ((1/1073) - (8.314/4.0) * ln(10))

Calculating t2 using a calculator, we find that t2 ≈ 1609.1 K.



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The amount, in grams, of \(CH_4\) needed to produce 44.2 g of \(CHCl_3\) would be 5.93 grams.

Chloroform, \(CHCl_3\), is formed from the reaction of methane with chlorine according to the following chemical equation:

\(CH_4+3Cl_2 --- > CH_3Cl +3HCl\)

From the equation, the mole ratio of methane to chloroform is 1:1.

Given 44.2 g of \(CHCl_3\), the equivalent mole would be:

Mole = mass/molar mass = 44.2/119.38 = 0.37 moles

From the mole ratio established from the balanced equation of the reaction, the equivalent mole of methane, \(CH_4\), needed will also be 0.37 moles.

Now, let's convert the mole to mass.

Mass = mole x molar mass

The molar mass of methane is 16.04 g/mol

Mass of 0.37 moles of methane = 0.37 x 16.04 = 5.93 grams

In other words, the amount of methane needed to produce 44.2 grams of chloroform would be 5.93 grams.

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The four polymers that can be used to give the same effect as xanthan gum are guar gum, locust bean gum, carrageenan, and carboxy methyl cellulose. Among these, guar gum could give high viscosity and lower flocculation.

Polymers are the macromolecules made up of monomers bonded together. These polymers are widely used in various applications due to their diverse properties such as high viscosity, high tensile strength, flexibility, transparency, and many more. Xanthan gum is one of the commonly used polymers that are used as a thickener, emulsifier, and stabilizer in various industries such as food, pharmaceuticals, cosmetics, and many more. Xanthan gum is derived from the bacterial fermentation process, but it is relatively expensive.

Carboxymethylcellulose: Carboxymethylcellulose is a synthetic polymer made by reacting cellulose with chloroacetic acid. It is used as a thickener and stabilizer in various food and cosmetic applications. It has high viscosity and excellent water-binding capacity, making it an ideal alternative to xanthan gum.Out of these four polymers, guar gum could give high viscosity and lower flocculation.

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Answer:

could occur at any temperature.

Explanation:

The spontaneity of a reaction is what determines whether the reaction will occur or not. A spontaneous reaction occurs easily.

The spontaneity of a reaction is predicted by the sign of ∆G.

When ∆G is positive, the reaction is not spontaneous. When ∆G is negative, the reaction is spontaneous.

Note that;

∆G= ∆H - T∆S

Where;

∆H = Change in enthalpy

∆S = Change in entropy

T= temperature

If ∆H is unfavourable and ∆S is favourable, the reaction can proceed at all temperatures because ∆G will always be negative.

It should be noted that a process that is unfavorable as regards to enthalpy, but favorable with respect to entropy could occur at any temperature.

Enthalpy(∆H) serves as amount of internal energy that a compound has, entropy( ∆S)  on the other hand serves as intrinsic disorder within the system.

However, spontaneity of a reaction determines likely hood of occurrence of a reaction, when the process is spontaneous, it makes the reaction to occurs easily.

We can conclude that whenever enthalpy is unfavourable and entropy of a system is favourable, then the spontaneity will be negative and the reaction will occur at any temperature.

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Answer:

Potassium Sulfide

Explanation:

K is more reactive than Fe which means K displaces Fe from the equation

Answer:Plasma is highest energy state of matter.It consists of electrons,protons and neutral particles.

Explanation:(1) Plasma has a very high electrical conductivity .

(2) The motion of electrons and ions in plasma produces it's own electric and magnetic field

(3)It is readily influenced by electric and magnetic fields .

(4)It produces it's on electromagnetic radiations.



somethingExplanation:

Answer:

True

Explanation:

Bones can be classified based on their shape. There are five classifications of bone based on shape. These categories are as follows: long bones, short bones, flat bones, irregular bones, and sesamoid bones.

In order to determine the classification of a bone, we need to identify its shape. Therefore, we cannot determine the classification of a bone unless we know its shape. The shape of a bone is important because it can tell us a lot about its function. For example, long bones are found in the limbs and are responsible for providing support and leverage. Short bones are found in the hands and feet and are responsible for providing stability and support. Flat bones are found in the skull and are responsible for protecting the brain. Irregular bones are found in the spine and are responsible for providing support and flexibility. Sesamoid bones are found in the knees and are responsible for protecting the tendons.

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If a resting axon increases its permeability to sodium ions, it will undergo depolarization.

The resting membrane potential of a neuron is maintained by the unequal distribution of ions across the cell membrane. At rest, the axon has a negative charge inside compared to the outside, primarily due to the higher concentration of sodium ions outside the cell and higher concentration of potassium ions inside the cell.

When the permeability of the axon membrane to sodium ions increases, more sodium ions can flow into the cell. This influx of positively charged sodium ions depolarizes the cell membrane, reducing the electrical potential difference across the membrane. As a result, the inside of the axon becomes less negative.

This increase in sodium permeability can be due to various factors such as the opening of voltage-gated sodium channels or the binding of specific molecules that increase sodium permeability. Depolarization plays a crucial role in initiating and propagating action potentials along the axon, allowing for the transmission of electrical signals in the nervous system.

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